Please go fast i only have 20 minutes left
Which statements are true about the rectangular pyramid below? Select three options. A rectangular pyramid. The rectangular base has a length of 6 centimeters and width of 4 centimeters. 2 triangular sides have a base of 6 centimeters and height of 6 centimeters. 2 triangular sides have a base of 4 centimeters and height of 4.6 centimeters. The area of the base is 24 cm2. There are four lateral faces. All the lateral faces are congruent. The total surface area of the figure is 66.4 cm2. At least one of the lateral faces has an area equal to 24 cm2.
the image isnt here, but if u use ed then u will know i hope. anything helps

Answer:

  12+√74 ≈ 20.60

Step-by-step explanation:

The side lengths of this right triangle are 5 and 7 units, so the length of the hypotenuse is ...

  b² = a² +c² = 5² +7² = 74

  b = √74

The perimeter is ...

  P = a + b + c = 5 + √74 + 7

  P = 12+√74 ≈ 20.60

Answer:

x = -8

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 12 from both sides:

3x + 12 (-12) = -12 (-12)

3x = -12 - 12

3x = -24

Next, divide 3 from both sides:

(3x)/3 = (-24)/3

x = -24/3

x = -8

x = -8 is your answer.

~

Answer:

x = -8

Step-by-step explanation:

3x + 12= -12

3x = -24

x = -24/3

x = -8

Answer:

The area of the rectangular prism is 40cm²

Step-by-step explanation:

To calculate the volume of a rectangular prism we have to use the following formula:

a = area

v = volume  = 800 cm³

h = height  = 20 cm

v = a * h

we replace the values that ​​we know        

800cm³  = a * 20cm

800cm³  / 20cm = a

40cm² = a

v = 70ft³

The area of the rectangular prism is 40cm²

Answer:

(a)

Reflexivity

Is not reflexive

Symmetry

Is symmetric

Anti-Symmetry  

is not antisymmetric.

Transitivity

It is transitive

[tex]R = \begin{pmatrix} 1 & 0 & 0 & 0 & 1 \\0 & 1 & 0 & 0 & 0 \\0 & 0& 1 & 0 & 0 \\0 & 0& 0 & 1 & 0 \\0 & 0& 0& 0 & 1 \end{pmatrix}[/tex]

(b)

Reflexivity

Is not reflexive  

Symmetry

Is not symmetric

Anti-Symmetry  

It is antisymmetric

Transitivity

So is NOT transitive.

[tex]R = \begin{pmatrix} 0 & 1 & 1 & 1 & 1 \\0 & 0 & 1 & 0 & 0 \\0 & 0& 0 & 1 & 0 \\0 & 1& 0 & 0& 0 \\0 & 1& 0& 0 & 0 \end{pmatrix}[/tex]

Step-by-step explanation:

(a)  

Reflexivity

Is not reflexive because 5 is not related to 5.

Symmetry

Is symmetric because 1R5 .and 5R1

Anti-Symmetry  

If it is symmetric then it is not antisymmetric.

Transitivity

It is transitive because  1R5 5R1 and 1R1.

[tex]R = \begin{pmatrix} 1 & 0 & 0 & 0 & 1 \\0 & 1 & 0 & 0 & 0 \\0 & 0& 1 & 0 & 0 \\0 & 0& 0 & 1 & 0 \\0 & 0& 0& 0 & 1 \end{pmatrix}[/tex]

(b)

Reflexivity

Is not reflexive no element of the set is related to itself.

Symmetry

Is not symmetric because (1,4) belongs to the relation but (4,1) does not belong to the relation . And similarly you can do the same with all pairs and none of them will satisfy the condition.

Anti-Symmetry  

It is symmetric because for every element if aRb then "b" is NOT related to "a"

Transitivity

A relation can't be antisymmetric and transitive. So is NOT transitive.

[tex]R = \begin{pmatrix} 0 & 1 & 1 & 1 & 1 \\0 & 0 & 1 & 0 & 0 \\0 & 0& 0 & 1 & 0 \\0 & 1& 0 & 0& 0 \\0 & 1& 0& 0 & 0 \end{pmatrix}[/tex]

Find the given attachment for the solution

A model relating a CEO's annual salary to firm's sales, market value, and profits is proposed. The equation takes a logarithmic form of sales and market value for the elasticity. Profits cannot take a logarithmic form due to the possibility of negative values.

The objective of this question is to build a model relating CEO's annual salary to firm sales, market value, and profits, using the data from CEOSAL2.RAW. The model would be a constant elasticity variety for the sales and market variables. The standard form of a constant elasticity model is ln(Y) = a + b1*ln(X1) + b2*ln(X2) + u, where Y represents the dependent variable (CEO's annual salary), X1 and X2 represent independent variables (firm sales and market value).

Now adding profits to the model, your equation would be: ln(Y) = a + b1*ln(X1) + b2*ln(X2) + b3*X3 + u, where X3 denotes the firm's profits. It is not in logarithmic form because profits can be negative, and the natural log of a negative number is undefined in real numbers.

https://brainly.com/question/16483963

#SPJ12

Answer:

The equation of the circle is

(x + 2)² + (y + 2)² = 9

Centered at (-2, -2), with radius of 3 units.

Step-by-step explanation:

The general equation of a circle is given as

(x - h)² + (y - k)² = r²

Where (h, k) is the center of the circle, and r is the radius.

Looking at the graph, the center is the red dot. It corresponds to -2 on the y-axis, and -2 on the x-axis. So, the center (h, k) is (-2, -2).

The radius is the distance from the center of the circle to the edge of the circle. The red dot is the edge of the circle, there are 3 lines that represent 3 units, so we have a radius of 3 units.

Using these in the general equation, we have

[x - (-2)]² + [y - (-2)]² = 3²

(x + 2)² + (y + 2)² = 9

And this is the equation.

Answer:

(x+2)^2 + (y+2)^2= 0.5625

Step-by-step explanation:

Answer:

b = 3

Step-by-step explanation:

the area of the parallelogram is 7*b, since we know it is 21, b = 3.

Answer:

90% confidence interval for the proportion of all US adults ages 55 to 64 to use online dating is [0.095 , 0.148].

Step-by-step explanation:

We are given that a survey conducted in July 2015 asked a random sample of American adults whether they had ever used online dating.

The survey included 411 adults between the ages of 55 and 64, and 50 of them said that they had used online dating.

Firstly, the pivotal quantity for 90% confidence interval for the population proportion is given by;

                                P.Q. =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of adults who said that they had used online dating =  [tex]\frac{50}{411}[/tex]  = 0.122

n = sample of adults between the ages of 55 and 64 = 411

p = population proportion of all US adults ages 55 to 64 to use online dating

Here for constructing 90% confidence interval we have used One-sample z proportion statistics.

So, 90% confidence interval for the population proportion, p is ;

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                  of significance are -1.645 & 1.645}  

P(-1.645 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.645) = 0.90

P( [tex]-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.90

P( [tex]\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.90

90% confidence interval for p = [[tex]\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex], [tex]\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]]

= [ [tex]0.122-1.645 \times {\sqrt{\frac{0.122(1-0.122)}{411} } }[/tex] , [tex]0.122+1.645 \times {\sqrt{\frac{0.122(1-0.122)}{411} } }[/tex] ]

 = [0.095 , 0.148]

Therefore, 90% confidence interval for the proportion of all US adults ages 55 to 64 to use online dating is [0.095 , 0.148].

Answer: 36x^2

Step-by-step explanation:

just took eg quiz

The expression represents the volume of the prism, in cubic units is

39x². (Option D) This is because the formula for the volume of a prism is: V = Bh

Any 3-dimensional shape with two identical shapes facing each other is called a Prism.

Recall that the oblique prism is described as having a base area of 3x², If the height is 13 (that is the distance between the top of the quadrilateral and the bottom) hence,

V = 3x² * 13

→ V = 39x², therefore, Option D is the correct answer.

Learn more about Prisms at:
https://brainly.com/question/23963432
#SPJ2

Answer:

Check the explanation

Step-by-step explanation:

Key Differences Between Descriptive and Inferential Statistics:

The difference between descriptive and inferential statistics can be drawn clearly on the following grounds:

Descriptive Statistics is a discipline which is concerned with describing the population under study. Inferential Statistics is a type of statistics; that focuses on drawing conclusions about the population, on the basis of sample analysis and observation.

Descriptive Statistics collects, organised, analyzes and presents data in a meaningful way. On the contrary, Inferential Statistics, compares data, test hypothesis and make predictions of the future outcomes.

There is a diagrammatic or tabular representation of final result in descriptive statistics whereas the final result is displayed in the form of probability.

Descriptive statistics describes a situation while inferential statistics explains the likelihood of the occurrence of an event.

Descriptive statistics explains the data, which is already known, to summaries sample. Conversely, inferential statistics attempts to reach the conclusion to learn about the population; that extends beyond the data available.

Ex. Of 350 randomly selected people in the town of Luserna, Italy, 280 people had the last name Nicolussi. An example of descriptive statistics is the following statement :

"80% of these people have the last name Nicolussi."

Ex. Of 350 randomly selected people in the town of Luserna, Italy, 280 people had the last name Nicolussi. An example of inferential statistics is the following statement :

"80% of all people living in Italy have the last name Nicolussi."

We have no information about all people living in Italy, just about the 350 living in Luserna. We have taken that information and generalized it to talk about all people living in Italy. The easiest way to tell that this statement is not descriptive is by trying to verify it based upon the information provided.

Answer:

The question is incomplete, the complementary part is left on the graph and the requested ones are answered

Differences between inferential and descriptive statistics:

1. We know that in descriptive statistics the main objective is only to describe data from the population, in inferential what is sought is to analyze data to draw conclusions from them

2. In descriptive statistics, the process involves collecting information, organizing it, and displaying data that are relevant or significant. In inferential statistics, the data is taken and processed to evaluate hypotheses and draw conclusions regarding future results.

3. the representation in the descriptive statistics is made by means of diagrams or tabulations and the result in the inferential one is given in probability

4. When we have a situation, descriptive statistics allows us to describe it and, in inferential, we obtain the probability that the event will occur.

descriptive statistics is based on known data, inferential it is intended to project future situations, which allows with all the previous answers to generate an important panorama for the development of engineering and its true application in a real field

-. an example is the following

Of 350 people taken at random in Madrid, Spain, 280 had the surname Martinez, we can take this situation to the descriptive statistic as follows:

80% of people carry the surname Martinez

We have, then, the result of a small sample of a city, not of the entire population of Spain, so the result has been generalized and we refer to a country from a small sample, however we must verify it and take it to a statistic inferential

Answer:

A, C are true .  B is not true.

Step-by-step explanation:

Mean of a discrete random variable can be interpreted as the average outcome if the experiment is repeated many times. Expected value or average of the distribution is analogous to mean of the distribution.

The mean can be found using summation from nothing to nothing x times Upper P (x) , i.e ∑x•P(x).

Example : If two outcomes 100 & 50 occur with probabilities 0.5 each. Expected value (Average) (Mean) : ∑x•P(x) = (0.5)(100) + (0.5)(50) = 50 + 25 = 75

The mean may not be a possible value of the random variable.

Example : Mean of possible no.s on a die = ( 1 + 2 + 3 + 4 + 5 + 6 ) / 6 = 21/6 = 3.5, which is not a possible value of the random variable 'no. on a die'

The correct answer is statement B, 'The mean must be a possible value of the random variable'. This claim is incorrect because the mean of a discrete random variable, calculated as the expected value, does not necessarily have to be a possible value of the variable.

In the given options, the only statement about the mean of a discrete random variable that is not true is 'B. The mean must be a possible value of the random variable.' The mean or expected value of a discrete random variable is calculated as the sum of all possible values each multiplied by their respective probabilities (Statement C). The expected value or mean can indeed be interpreted as the average outcome if the experiment is repeated many times (Statement A), but it does not necessarily need to be an exact outcome or possible value of the random variable.

This is especially true for distributions such as the binomial and Poisson distributions, where the calculation of the mean relies on the probability of events and does not have to align with specific outcomes. Hence, the statement 'B. The mean must be a possible value of the random variable' is incorrect.

https://brainly.com/question/17238189

#SPJ3

according to the model, the black bear population at the national park after 25 years will be approximately 2,973.

To find the black bear population at the national park after 25 years using the given function [tex]\( B(t) = 2,500 \times 2^{0.01t} \)[/tex], we substitute [tex]\( t = 25 \)[/tex] into the function:

[tex]\[ B(25) = 2,500 \times 2^{0.01 \times 25} \][/tex]

[tex]\[ B(25) = 2,500 \times 2^{0.25} \][/tex]

[tex]\[ B(25) = 2,500 \times 2^{1/4} \][/tex]

[tex]\[ B(25) = 2,500 \times \sqrt[4]{2} \][/tex]

Now, let's compute the value:

[tex]\[ B(25) = 2,500 \times 1.1892 \][/tex]

[tex]\[ B(25) \approx 2,973 \][/tex]

Therefore, according to the model, the black bear population at the national park after 25 years will be approximately 2,973.

Answer:

Step-by-step explanation:

[tex]12(3g - 9) = 99 \\ 36g - 108 = 99 \\ 36g = 99 + 108 \\ 36g = 207 \\ \frac{36g}{36} = \frac{207}{36} \\ g = 5.75[/tex]

A. 8.5.

55.25 feet / 6.5 feet = 8.5 miles.

A telescope is an optical tool using lenses, curved mirrors, or a combination of both to look at distant objects, or various devices used to look at distant objects by means of their emission, absorption, or reflection of electromagnetic radiation.

There are three main types of telescope. These are

Learn more about telescope here

https://brainly.com/question/18300677

#SPJ2

Answer:

IV

Step-by-step explanation:

Since x is positive, the two possible quadrants are I and IV.

Since y is negative, the two possible quadrants are III and IV.

The point lies in quadrant IV.

To estimate the true mean weight of the cream filling within 0.25 grams with 99% confidence, the quality control inspectors should sample approximately 384 donuts. This is calculated using statistical techniques for sample size determination.

In order to find out how many donuts the quality control inspectors should sample, we need to utilize the formula for sample size in statistics, which is n = (Z^2 * σ^2 * N) / E^2 . In this case, 'Z' is the Z-score which corresponds to the desired confidence level, σ is the standard deviation of the sample data, E is the desired margin of error, and N is the population size.

For a 99% confidence level, the Z-score is 2.58. Given the standard deviation(σ) is 1.5 grams, and the desired margin of error(E) is 0.25 grams, we can substitute these values into the equation to calculate the sample size(n).

Substituting these values: n = (2.58^2 * 1.5^2) / 0.25^2. n becomes approximately 384.

Therefore, the quality control inspectors should sample approximately 384 donuts to be 99% confident that their estimate of the true mean weight of cream filling is within 0.25 grams of the true mean.

https://brainly.com/question/34288377

#SPJ2

9514 1404 393

Answer:

  (a)  k = –2.5

Step-by-step explanation:

When the function f(x) is transformed to f(x -h) +k, the graph is translated h units right and k units up.

If the absolute value function has its original vertex of (0, 0) moved to (1, -2.5), then (h, k) = (1, -2.5).

The value of k is -2.5.

_____

Additional comment

The above answer applies to the given problem statement. The question asked in the comment has a vertex of (0, 2.5), so (h, k) = (0, 2.5) for that question.

If you're going to copy the answer, make sure it is the answer to the question you're looking at.

In an absolute value function expressed as f(x) = |x – h| + k, the value of k corresponds to the y-coordinate of the function's vertex. In this case, as the vertex is at the point (1, -2.5), the value of k is -2.5.

The student's question relates to the concepts of Two-Dimensional (x-y). Graphing and the graphing of the absolute value function. It is vital to remember that the vertex of an absolute value graph in the form f(x) = |x – h| + k corresponds to the point (h, k) on the Cartesian coordinate plane. The student states that the vertex is at the point (1, -2.5), so based on our function analysis, the value of k, which represents the y-coordinate of the vertex, is -2.5. Therefore, the correct answer is k = -2.5.

For more about Absolute Value Graph here:

https://brainly.com/question/19848212

#SPJ3

Answer:

The probability that a randomly selected score on the  verbal section is higher than 165 is 0.0392

Step-by-step explanation:

We are given that The scores on the verbal section of the Graduate Records Examination (GRE)  are approximately normally distributed with a mean of 150 and a standard  deviation of 8.5.

Mean = [tex]\mu = 150[/tex]

Standard deviation =[tex]\sigma = 8.5[/tex]

We are supposed to find the probability that a randomly selected score on the  verbal section is higher than 165 i.e.P(x>165)

Formula :[tex]Z=\frac{x-\mu}{\sigma}[/tex]

[tex]Z=\frac{165-150}{8.5}[/tex]

Z=1.76

Refer the z table for p value

P(x<165)=0.9608

P(x>165)=1-P(x<165)=1-0.9608=0.0392

Hence the probability that a randomly selected score on the  verbal section is higher than 165 is 0.0392

Answer:

slope of orange Line = -1

slope of other line = -1 (also)

would be parallel

no solution

Step-by-step explanation:

how do i know. I did the assignment. Can i get brainlyest. I need it please.

This question is based on system of linear equation. thus, there is no solution of equations.

Given:

y = - x + 3                                                                        ...(1)

y = -x - 3                                                                          ...(2)                          

We know that ,

Equation of line  is y = mx+c                                        ...(3)

Now, calculate the slope of equation (1) is m= -1 (by comparing equation (1) and (3).

Now, calculate the slope of equation (2) is m= -1 (by comparing equation (2) and (3).

Therefore, both lines are parallel to each other.Thus, never meet ech other so, the equation has no solution.

For further details, prefer this link:

https://brainly.com/question/21404414

Answer: I think the answer is 11.9% , because I had this on a quiz and this was the same question.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The function's graph is not symmetrical about the origin, so it is not an odd function. It is not symmetrical about the y-axis, so is not an even function.

The function is neither even nor odd.

There are 5 zero-crossings and no places where y=0 and the graph does not cross. This means the function is of degree 5, at least.

The general shape of the function is down and to the right, so the sign of the function for large values of x is opposite the sign of x. The leading coefficient must be negative.

As we noted, there are 5 zero-crossings. These are the real roots. They are found at x-values in the set {-6, -4, 0, 2, 3}.

Answer:

cos (A)  =5/13

tan (C) =5/12

Step-by-step explanation:

The triangle for the problem is produced and attached.

cos (A)=Adjacent/Hypotenuse

cos (A) = 10/26 =5/13

Similarly,

tan (C)=Opposite/Adjacent

tan (C)=10/24 =5/12

Answer:

Cos(A) = 5/13 or 10/26

Tan(C) = 5/12 or 10/24

Step-by-step explanation:

I did it on edge :)

Answer: yes reptiles have no teeth at all while mammals have two sets of teeth

Step-by-step explanation:

Answer:

dot plot

Step-by-step explanation:

gay gay

Answer:

X=4

for the graph, the point would be (4,0)

Answer:

12

Step-by-step explanation:

x^2 -bx +36

A perfect square trinomial is of the form

a^2 -2abx +b^2

x^2 -bx +6^2

a =1 and b = 6

2ab = 2*1*6 = 12

Answer:

i thinl it would be 200 or 1000

Answer:

9

Step-by-step explanation:

range is the range from the lowest # through the biggest # in other words subtract the smaller number from the bigger number

Answer:

95​% confidence interval for the mean length of sentencing for this crime is [47.53 months , 54.47 months].

Step-by-step explanation:

We are given that in a random sample of 41 criminals convicted of a certain​ crime, it was determined that the mean length of sentencing was 51 ​months, with a standard deviation of 11 months.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                               P.Q. =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean length of sentencing = 51 months

             [tex]s[/tex] = sample standard deviation = 11 months

             n = sample of criminals = 41

             [tex]\mu[/tex] = population mean length of sentencing

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.021 < [tex]t_4_0[/tex] < 2.021) = 0.95  {As the critical value of t at 40 degree of

                                               freedom are -2.021 & 2.021 with P = 2.5%}  

P(-2.021 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.021) = 0.95

P( [tex]-2.021 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]-2.021 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-2.021 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.021 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.021 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.021 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                               = [ [tex]51-2.021 \times {\frac{11}{\sqrt{41} } }[/tex] , [tex]51+2.021 \times {\frac{11}{\sqrt{41} } }[/tex] ]

                                              = [47.53 , 54.47]

Therefore, 95​% confidence interval for the mean length of sentencing for this crime is [47.53 months , 54.47 months].