PLEASE HELP HELPPPPPPO HELPPPPPPO

b=-7

Please look at the attached picture to see what I did

The value of b=-7.

y=3x+b

point(2,-1)

x=2, y=-1

subtract into equation

-1 = 3(2) +b

-1 = 6+b

-1-6 = b

b= -7

Coordinates are a couple of numbers that describe the precise function of a factor on a cartesian aircraft through the use of the horizontal and vertical lines known as the coordinates. commonly represented by (x, y) the x cost and y price of the point on a graph. Each factor or an ordered pair consists of two coordinates.

A factor-to-factor graph also referred to as a line graph, is a pictorial rendition of records wherein specific values of a feature are plotted as dots on a coordinate aircraft.

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Answer:

16/29

Step-by-step explanation:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(basketball or baseball) = P(basketball) + P(baseball) - P(both)

= (13/29) + (7/29) - (4/29)

= 16/29

The probability that a randomly chosen student plays either sport is 16/29.

Answer:

A

Step-by-step explanation:

The bottles are cylindrical.  The volume of a cylinder is:

V = πr²h

where r is the radius (half the diameter) and h is the height.

The bottles are similar, so we can write a proportion to find the height of the smaller bottle:

3/10 = 1.5/h

h = 5

The volume of the big bottle is:

V = π(3/2)²(10)

V ≈ 70.7

The volume of the small bottle is:

V = π(1.5/2)²(5)

V ≈ 8.8

So the difference in volume is:

V = 70.7 - 8.8

V = 61.9

Answer:

A

Step-by-step explanation:

got it right

Answer:

  (a) max P(A∩B) = 1/3; min P(A∩B) = 1/12

  (b) max P(A∪B) = 1; min P(A∪B) = 3/4

Step-by-step explanation:

Let the universal set be the numbers 1–12, U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}, each with probability 1/12.

Let event A be any of the numbers 1–9, {1, 2, 3, 4, 5, 6, 7, 8, 9}. If a number is chosen at random from U, the probability of event A is 9/12 = 3/4.

a1) Let event B be any of the numbers 1–4, {1, 2, 3, 4}. If a number is chosen at random from U, the probability of event B is 4/12 = 1/3.

The set A∩B is the numbers 1–4, {1, 2, 3, 4}, so the probability of that event is also 4/12 = 1/3.

In general the maximum value of P(A∩B) will be min(P(A), P(B)). Here, that is min(3/4, 1/3) = 1/3.

__

a2) Let event B be any of the numbers 9–12, {9, 10, 11, 12}. If a number is chosen at random from U, the probability of event B is 4/12 = 1/3. The set A∩B is the number {9}, so the probability of that event is 1/12.

In general, the minimum value of P(A∩B) is max(0, P(A) +P(B) -1). Here, that is max(0, 3/4 +1/3 -1) = 1/12.

__

b1) Let event B be defined as in (a2), the numbers 9–12. Then A∪B is the set {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}, which is equal to the universal set, U. That is, the probability of event A∪B when drawing a number from U is 1.

In general, the maximum value of P(A∪B) is min(1, P(A)+P(B)). Here, that is min(1, 3/4+1/3) = 1.

__

b2) Let event B be defined as in (a1), the numbers 1–4. Then A∪B is the set {1, 2, 3, 4, 5, 6, 7, 8, 9}. If a number is chosen at random from U, the probability of event A∪B is 9/12 = 3/4.

In general, the minimum value of P(A∪B) is max(P(A), P(B)). Here, that is max(3/4, 1/3) = 3/4.

Answer:

theoretical is 15 each

experimental is Red: 13 Blue: 14 Yellow:18 Green:15

Step-by-step explanation:

the theoretical probability is what should statisticly happen when you do it so if there are for outcomes with an equal chance of occurring then 1 out of every 4 or 1/4 of the time each one should happen so divide 60 by 4 and you get 15

the experimental probability is what happens when someone actually spins it 60 times and in your scenario

RESULTS HERE

Red: 13 Blue: 14 Yellow:18 Green:15

is what happened so that is the experimental probability

Answer: 28x + 8y + 2

Answer:

28x +8y +2

Step-by-step explanation:

It can work well to simplify the contents of the parentheses, then apply the overall multiplier.

= -2(x(3-17) +y(12-16) +(-5+4)) . . . . collect terms

= -2(-14x -4y -1)

= 28x +8y +2 . . . . use the distributive property

Answer:

309 ft

Step-by-step explanation:

In order to solve this I have to assume that the sling shot is ground level.  Since you did not provide an initial height, without making the assumption that it is 0, we cannot solve the problem at all.

The standard form of a quadratic function is

[tex]f(x)=ax^2+bx+c[/tex]

c is the initial height for which we are going to sub in a 0.  Given 2 points, we are going to plug in the y and the x, one point each into 2 quadratic functions, to find the model.  The first coordinate is (1, 121):

[tex]121=a(1)^2+b(1)+0[/tex] and 121 = a + b

The second coordinate is (2, 224):

[tex]224=a(2)^2+b(2)+0[/tex] and 224 = 4a + 2b

Solve the first equation for a:

a = 121 - b

and sub it in for a in the second equation:

224 = 4(121 - b) + 2b and

224 = 484 - 4b + 2b and

-260 = -2b so b = 130.

Now we can sub that in for b and solve for a:

a = 121 - 130 so a = -9.

The equation then that models the motion is

[tex]f(x)=-9x^2+130x[/tex]

Now that we know that, all we have to do now is to find f(3):

[tex]f(3)=-9(3)^2+130(3)[/tex] and

f(3) = 309 ft

Answer:

12

Step-by-step explanation:

SOH CAH TOA reminds you that ...

Sin = Opposite/Hypotenuse

so ...

sin(45°) = (6√2)/x

Your memory of trig functions tells you sin(45°) = 1/√2, so we have ...

1/√2 = (6√2)/x

Multiplying by (√2)x gives ...

x = 6(√2)^2 = 6·2

x = 12

_____

You can simply recognize that this is an isosceles right triangle, so the hypotenuse (x) is √2 times the leg length:

x = (6√2)·√2 = 6·2 = 12

Answer:

No.

Step-by-step explanation:

First, subtract 32-5= 27

Then multiply 5 * 4=20

since 20 is less than 27, she will not have enough.

Answer:

No

Step-by-step explanation:

She already has 5 and the total is 32 so she has to make 28 friendship bracelets.

Bracelets in packages of 4 and she buys 5 packages which is 20 so no, she doesn't have enough bracelets if she buys 5 packages.

Answer:

see below

Step-by-step explanation:

Choose a couple of values for x. Figure out the corresponding values for y. Plot those points and draw a line through them.

Let's choose x=0 and x=4. Then the corresponding y-values are ...

y = 2·0 = 0 . . . . . point (x, y) = (0, 0)

y = 2·4 = 8 . . . . . point (x, y) = (4, 8)

These are graphed below.

Answer:

reflective and slide the y is -1

Step-by-step explanation:

refect over the -1 x axis and the translate x-1 and y-1

Answer:

Equation 1: r = -5 * cos theta

Equation 2: r = 1 – ( 4 * sin theta  )

Step-by-step explanation:

Graph 1:

This graph is a circle along negative x- axis.

General equation for graph:

R = a cos theta          ∴ a =  diameter of circle

From given graph, it is included that:

a = -5  

a/2 = -2.5 (center of circle)

Equation 1: r = -5 cos theta

Graph 2:

This graph is an inner-loop limacon.

The inner-loop limacon is in the downward direction along the negative y-axis

The general equation for the graph will be :

r = a – b sin theta  

a will represent x – intercept, from graph it is included that:

a = { +1, -1  }

For inner-loop on y-axis, b - a = 3     ………….1  

For outer-loop on y-axis, a + b = 5    …………2

Adding both 1 and 2 to find values of a and b

b – a = 3

a + b = 5

2b     = 8     ⇒      b = 4

Putting value of b in 2

a + 4 = 5       ⇒       a = 1

substituting values of a and b in general equation:

Equation 2: r = 1 – 4 sin theta

Answer:

(36,000,000 / 573) - (38,000,000 / 845) = 17856.8 ≈ 17857 people per square mile

Answer:

17857 people per mile²

Step-by-step explanation:

Area of Tokyo, Japan = 845 square miles

Population Tokyo = 38 million

Area of Delhi, India = 573 square miles

Population of Deli = 36 million

Population density of Tokyo = [tex]\frac{38}{845}[/tex] = 0.04497 millions/miles²

Population density of Delhi = [tex]\frac{36}{573}[/tex] = 0.062827 millions/miles²

Difference in population density of Delhi and Tokyo = 0.062827 - 0.04497

                      = 0.17857 million per mile²

or 17857 people per mile² is the answer.

For this case we have the following system of equations:

[tex]8x-9y = -122\\-8x-6y = -28[/tex]

To solve, we add both equations:

[tex]8x-8x-9y-6y = -122-28\\-15y = -150\\y = \frac {-150} {- 15}\\y = 10[/tex]

We find the value of "x":

[tex]8x = -122 + 9y\\x = \frac {-122 + 9y} {8}\\x = \frac {-122 + 9 (10)} {8}\\x = \frac {-122 + 90} {8}\\x = \frac {-32} {8}\\x = -4[/tex]

The solution is (-4,10)

ANswer:

Option C

Answer:

[tex]A = 144\ ft[/tex]

Step-by-step explanation:

The area of a triangle is:

[tex]A = 0.5b*h[/tex]

Where b is the base of the triangle and h is the height

In this case we know the hypotenuse of the triangle and the angle B.

Then we can use the sine of the angle to find the side opposite the angle

By definition we know that

[tex]sin (\theta) = \frac{opposite}{hypotenuse}[/tex]

In this case hypotenuse = 24

opposite = b

Then:

[tex]sin (45) = \frac{b}{24}[/tex]

[tex]b= 24*sin(45)[/tex]

[tex]b=12\sqrt{2}[/tex]

Now

[tex]cos(\theta) = \frac{adjacent}{hypotenuse}[/tex]

adjacent = a = h

[tex]cos(45) = \frac{h}{24}[/tex]

[tex]h = 24*cos(45)\\\\h=12\sqrt{2}[/tex]

Then the area is:

[tex]A = 0.5*12\sqrt{2}(12\sqrt{2})\\\\A=144\ ft[/tex]

ANSWER

[tex]Area = 144 {ft}^{2} [/tex]

EXPLANATION

We use the sine ratio to find the missing side.

[tex] \sin(45 \degree) = \frac{AC}{24} [/tex]

[tex]24\sin(45 \degree) = AC[/tex]

[tex]AC = 24 \times \frac{ \sqrt{2} }{2} [/tex]

[tex]AC = 12 \sqrt{2} ft[/tex]

The triangle is a right isosceles triangle.

This implies that,

AC=BC=12√2 ft.

The area of the triangle is:

[tex]Area = \frac{1}{2} bh[/tex]

We substitute the values to get,

[tex]Area = \frac{1}{2} \times 12 \sqrt{2} \times 12 \sqrt{2} [/tex]

[tex]Area = 144 {ft}^{2} [/tex]

The volume of 1 cube is s^3 where S is the side length.

Volume of one cube = 18^3 = 5832 cubic inches.

Now multiply the volume of one cube by the total number of cubes:

5832 x 10 = 58,320 cubic inches.

To find the volume of the stack of cubes, we need to find the volume of one cube and then multiply it by the number of cubes in the stack.

To find the volume of the stack of cubes, we need to find the volume of one cube and then multiply it by the number of cubes in the stack. The side length of each cube is given as 18 inches. The formula to find the volume of a cube is side length cubed, so the volume of one cube is 18³ cubic inches.

To find the volume of the stack, we multiply the volume of one cube by the number of cubes, which is 10. So the volume of the stack of cubes is 18³ * 10 cubic inches.

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Answer:

A) 525,500

B) decreasing by 0.995% per year

C) 430,243

D) After 20 years, the population can be expected to be about 20% smaller.

E) 2009

Step-by-step explanation:

A) t=0 represents the year 2000, so put 0 where t is in the expression and evaluate it. Of course, e^0 = 1, so the y-value is 525.5 thousand, or 525,500.

__

B) Each year, the population is multiplied by e^-0.01 ≈ 0.99004983, or about 1 - 0.995%. That is, the population is decreasing by 0.995% per year.

__

C) t represents the number of years since 2000, so the year 2020 is represented by t=20. Put that value in the equation and do the arithmetic.

y = 525.5·e^(-0.01·20) = 525.5·e^-0.2 ≈ 430.243 . . . . thousands

The population in 2020 is predicted to be 430,243.

__

D) The decrease is about 1% per year, so a rough estimate of the decrease over 20 years is 20%. The population of about 500,000 will decrease by about 100,000 in that time period, so will be about 400,000. The value we calculated is in that ballpark. (The actual decrease is about 18.13%; or about 95.2 thousand.)

__

E) Your working shows the general idea, but you need to remember the numbers in the equation are thousands:

480 = 525.5·e^(-0.01t)

0.913416 = e^(-0.01t) . . . . divide by 525.5

ln(0.913416) = -0.01·t . . . . take the natural log

-100ln(0.913416) = t ≈ 9.06

The population will be 480 thousand after 9 .06 years, in the year 2009.

Answer:

20. OPTION D.

12. OPTION B.

Step-by-step explanation:

20. An inverse variaton equation has this form:

[tex]y=\frac{k}{x}[/tex]

Where "k" is the constant of variation.

If  Q varies inversely as the square of p, then the equation is:

[tex]Q=\frac{k}{p^2}[/tex]

Knowing that [tex]Q = 36[/tex] when [tex]p = 7[/tex], you can solve for "k" and caculate its value:

[tex]k=Qp^2\\k=(36)(7^2)\\k=1,764[/tex]

Then, to find the value of "Q" when [tex]p = 6[/tex], substitute the known  values into  [tex]Q=\frac{k}{p^2}[/tex]:

[tex]Q=\frac{1,764}{6^2}\\\\Q=49[/tex]

12. Given [tex](ab)^n[/tex], you get:

[tex](ab)^n=(a^1b^1)^n=a^{(1*n)}b^{(1*n)}=a^nb^n[/tex]

Then:

 [tex](ab)^n=a^nb^n[/tex]

This matches with the option B.

To solve this problem, we need to use the z-score formula to standardize the values and then look up the corresponding probabilities in the standard normal distribution table.

To solve this problem, we need to use the z-score formula to standardize the values and then look up the corresponding probabilities in the standard normal distribution table. The z-score formula is given by (X - μ) / σ, where X is the given value, μ is the mean, and σ is the standard deviation. Here are the calculations for each question:

First, we need to calculate the z-score for 61 hours:

z = (61 - 56) / 3.3 = 1.52

Next, we can look up the probability corresponding to a z-score of 1.52 in the standard normal distribution table. The probability of getting a value greater than 1.52 is approximately 0.0655, or 6.55%.

First, we need to calculate the z-score for 53 hours:

z = (53 - 56) / 3.3 = -0.9091

Next, we can look up the probability corresponding to a z-score of -0.9091 in the standard normal distribution table. The probability of getting a value less than or equal to -0.9091 is approximately 0.1814, or 18.14%.

First, we need to calculate the z-scores for 57 hours and 62 hours:

z1 = (57 - 56) / 3.3 = 0.303

z2 = (62 - 56) / 3.3 = 1.82

Next, we can look up the probabilities corresponding to z1 and z2 in the standard normal distribution table. The probability of getting a value between z1 and z2 is approximately 0.1988, or 19.88%.

First, we need to calculate the z-score for 46 hours:

z = (46 - 56) / 3.3 = -3.03

Next, we can look up the probability corresponding to a z-score of -3.03 in the standard normal distribution table. The probability of getting a value less than -3.03 is approximately 0.00123, or 0.123%.

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The question involves the computation and interpretation of Z-scores in a normally distributed data, which in this case is the lifetime of light bulbs. The probabilities are found by calculating the Z-scores and then looking up these scores in a Z-table or using a calculator. About 6.4% of bulbs will last more than 61 hours, 18.1% will last 53 hours or less, approximately 34.1% will last between 57 and 62 hours, and only about 0.1% will last less than 46 hours.

The question is about using the properties of a normal distribution to find probabilities related to the lifetime of light bulbs. To do this, we use the mean and standard deviation to compute Z-scores, which give us the number of standard deviations away from the mean a certain value is.

(a) To find the proportion of light bulbs that will last more than 61 hours, we calculate the Z-score for 61 hours: Z = (61 - 56)/3.3 = 1.52. We look this Z-score up in a Z-score table or use a calculator to find that the probability of getting a Z-score of 1.52 is about 0.064. Therefore, about 6.4% of light bulbs will last more than 61 hours.

(b) For finding the proportion of light bulbs that will last 53 hours or less, we calculate the Z-score for 53 hours: Z = (53 - 56)/3.3 = -0.91. Looking this up, we find that about 18.1% of light bulbs will last less than or equal to 53 hours.

(c) To find the proportion of light bulbs that will last between 57 and 62 hours, we calculate the Z-scores and find the probabilities for both, then subtract the smaller from the larger. The Z-score for 57 hours is 0.30 (probability about 37.5%) and for 62 hours is 1.82 (probability about 3.4%). Thus, about 34.1% of all light bulbs will last between 57 and 62 hours.

(d) Finally, to find the probability that a light bulb lasts less than 46 hours, we again calculate the Z-score: Z = (46 - 56)/3.3 = -3.03. This Z-score is quite small, suggesting this is unlikely: indeed, only about 0.1% of all light bulbs last less than 46 hours.

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she went down the slope 10.2 meters, -10.2

then she jumped down to the lake 1.5 meters, -1.5

-10.2 - 1.5 = -11.7 meters.

so she pretty much went 11.7 meters down from her original location.

Answer:

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Sin = Opposite/Hypotenuse

In ΔAHD, the side opposite angle DAH is DH, and the hypotenuse is AD, so we have ...

  sin(∠DAH) = DH/AD = 4/8

  ∠DAH = arcsin(4/8) = 30°

That makes ΔAHD a 30°-60°-90° triangle, so the side lengths have the ratios 1 : √3 : 2.

∠CAB = 2·30° = 60°, so ΔABC is also a 30°-60°-90° triangle having the same ratios of side lengths.

In short, ...

  AH = √3·DH = 4√3

  AC = 2·AH = 8√3

  AB = 2·AC = 16√3

  BC = √3·AC = 8·(√3)² = 24

[tex]5\frac{3}{7}[/tex] Kilometers of thread.

The key to solve this problem is using the rule of three.

We have to change mixed number to improper fraction in order to solve the problem.

A mixed number is a number formed by an integer and a proper fraction (one whose quotient is less than 1).

An improper fraction  is one whose denominator is less than its numerator.

To change a mixed number to an improper fraction:

1. Multiply the whole number by the denominator and add to the numerator.

2. The denominator of the mixed number is unchanged.

It takes [tex]2\frac{1}{4}[/tex] kilometers of thread to make [tex]3\frac{1}{2}[/tex] boxes of shirts. How many kilometers of thread would it take to make 8 boxes?

We need to change [tex]2\frac{1}{4}[/tex] and [tex]3\frac{1}{2}[/tex] to an improper franctions:

[tex]2\frac{1}{4}=\frac{(2)(4)+1}{4}=\frac{9}{4}[/tex]

[tex]3\frac{1}{2}=\frac{(3)(2)+1}{2}=\frac{7}{2}[/tex]

To calculate how many kilometers of thread would it take to make 8 boxes, we use the rule of three:

9/4 Km of thread -------------> 7/2 boxes of shirts

                    x     <-------------  8 boxes of shirts

[tex]x = \frac{(\frac{9}{4})(8)}{\frac{7}{2}}= \frac{19}{\frac{7}{2}}\\x=\frac{38}{7}[/tex]

Convert the improper fraction 38/7 to a mixed number:

1. Divide the numerator by the denominator.

38÷7 = 5 and a remainder of 3

2.  5 become the whole number, the remainder is the numerator, and the denominator is unchanged.

38/7 = 5 3/7

It would take 5 3/7 kilometers of thread make 8 boxes of shirts.

Answer:

D

Step-by-step explanation:

(cos t) (sec t − cos t)

1 − cos² t

sin² t

The expression cos t(sec t - cos t) simplifies to sin² t, which matches option D.

The student has asked to simplify the expression cos t(sec t − cos t).

To simplify this expression, we start by distributing cos t across the parentheses:

cos t × sec t − cos t ×cos t

1 − cos² t (since cos t × sec t = 1)

1 − (1 − sin² t) (using the Pythagorean identity cos² t + sin² t = 1)

sin² t

Thus, the expression simplifies to sin² t, which corresponds to option D.

Answer:

35 years

Step-by-step explanation:

We have been given an exponential decay function that models the weight of the bones of an extinct dinosaur;

[tex]f(x)=10e^{-0.02x}[/tex]

The initial weight of the bones is;

substitute x with 0 in the function, f(0) = 10 grams

We are required to determine the number of years it will take for the bones to be less than 5 grams. The solution can be achieved either analytically or graphically. I obtained the graph of the function from desmos graphing tool as shown in the attachment below.

From the graph, the bones will weigh 5 grams after approximately 34.65 years. This implies that it will take 35 years for the bones to be less than 5 grams.

Answer:

  88.49 units²

Step-by-step explanation:

Use the formula for the area of a sector.

  A = (1/2)r²·θ

where θ is the central angle of the sector in radians, and r is the radius.

Here, the central angle of the sector is 360°-300° = 60° = π/3 radians. Then the area is ...

  A = (1/2)(13)²(π/3) = 169π/6 ≈ 88.49 . . . . units²

To find the area of a sector, use the formula A = (θ/360) × πr². Plug in the provided values for the central angle and the radius. The final answer should carry the same number of significant figures as the radius provided.

To find the area of the sector (A), we will use the formula: A = (θ/360) × πr², where θ represents the sector's central angle in degrees and r the radius of the circle. Suppose you are given that the central angle (θ) is 90° (or π/2 in radians) and the radius (r) is 0.0500 m, as suggested in the provided information.

Plugging these values into the formula, we get A = (90/360) × 3.14(0.0500 m)² = 7.85 × 10-3 m² rounded to two decimal places. Even though the output from the calculator is a number with more digits, [1.11] , we need to make sure our final answer is limited to two significant figures to match the given radius value.

If the radius of the circle was given as 0.800 m (or 80.0 cm), then going through the same process produces an area of 1.26 m² for a one meter length along the curve of the mirror, for instance.

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Answer:

  24%

Step-by-step explanation:

2610 of the 10730 students are graduates. The probability of choosing a graduate at random from all students is ...

  2610/10730 × 100% ≈ 24.324% ≈ 24%

Answer:

D, y = cos(x -π/2)

Step-by-step explanation:

When the cosine function is shifted right by π/2 units, it looks like the sine function. That is what we have here. To shift f(x) to the right, replace x by x-(amount of shift). Here, this means the graph is described by ...

y = 2cos(x -π/2)

_____

The vertical scale factor is 2 on the graph and in all answer choices.

Answer:

  6 is in the "hundreds" place

Step-by-step explanation:

The value of the 6 can be found by setting the other digits to zero:

  00,600.00 = 600

The 6 represents six hundred, hence is in the hundreds place.

Answer:

Part 1) The statement is false

Part 2) The statement is false

Part 3) The statement is true

Step-by-step explanation:

Let

h(t)-----> the height of an object launched to the air

t ----> the time in seconds after the object is launched

we have

[tex]h(t)=-16t^{2} +72t[/tex]

Verify each statement

case 1) The factored form of the equation is h(t)=-16(t-4.5)

The statement is false

Because

The factored form is equal to

[tex]h(t)=-16t(t-4.5)[/tex]  

case 2) The object will hit the ground at t=72 seconds

The statement is false

Because

we know that

The object will hit the ground when h(t)=0

substitute in the equation and solve for t

[tex]0=-16t(t-4.5)[/tex]  

so

[tex](t-4.5)=0[/tex]  

[tex]t=4.5\ sec[/tex]  

case 3) The t-value for the maximum of the function is 2.25

The statement is true

Because

Convert the quadratic equation in vertex form

[tex]h(t)=-16t^{2} +72t[/tex]

[tex]h(t)=-16(t^{2} -4.5t)[/tex]

[tex]h(t)-81=-16(t^{2} -4.5t+2.25^{2})[/tex]

[tex]h(t)-81=-16(t-2.25)^{2}[/tex]

[tex]h(t)=-16(t-2.25)^{2}+81[/tex] ---> quadratic equation in vertex form

The vertex is a maximum

The vertex is the point (2.25,81)

____________________________________________________

Answer:

Your answer would be x + y = 1

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Step-by-step explanation:

In this scenario, we know that the line of CD passes through the coordinates (0,1), and would also be parallel to the equation x + y = 3.

When two lines are parallel, that means that their slopes are equal.

The slope of the line must be:

[tex]x + y = 3[/tex]

Move the x to the other side by subtracting

[tex]y= -x + 3[/tex]

The slope for the equation would be -1, since there is a invisible one after the equal sign. When there's no other number there, it would be 1.

The slope of the line CD would be -1.

Now, we would need to plug in -1 into the equation, to find the standard form.

[tex](y - 1) = m(x - 0)\\\\(y-1)=-1(x)\\\\x+y=1[/tex]

[tex]x + y = 1[/tex] should be your FINAL answer.

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