Please help me out!!!!!

Answer:

Step-by-step explanation:

Surely the units of time: minut, hour, second.

Answer:

The unit of time - seconds

Step-by-step explanation:

The metric system uses units such as meter, liter, and gram to measure length, liquid volume, and mass.

Whereas in the US system of units, units like feet, quarts, and ounces to measure these.

But 'seconds' the base unit of time, is the unit that is used in both the system of units.

Answer:

i think the answer is c.) which is square root

Step-by-step explanation:

Answer:

C. Square root.

Step-by-step explanation:

We have been given 4 choices. We are asked to determine, which of the given functions has a domain of x ≥ 0.

A. linear.

We know that linear function is in form [tex]y=mx+b[/tex], which is defined for all values of x, therefore, option A is not a correct choice.

B. Square

We know that a square function is in form [tex]y=x^2[/tex], which is defined for all values of x, therefore, option B is not a correct choice.

C. Square root.

We know that a square root function is in form [tex]y=\sqrt{x}[/tex]. We also know that a square root function is not defined for negative values of x, so a square root function is defined for all values of [tex]x\geq 0[/tex]. Therefore, option C is the correct choice.

D. Cube

We know that a cube function is in form [tex]y=x^3[/tex], which is defined for all values of x, therefore, option D is not a correct choice.

To find the original price, divide the sale price by 1 minus the discount rate:

4160 / (1- 0.35) =  4160 / 0.65 = 6400

The original price was $6,400

Answer:

It is the second graph.

Step-by-step explanation:

One zero is x = -1 so the graph will be curved (as it has degree 3) and will  pass through the x axis at x = -1  and only at -1 because the other 2 zeroes are complex numbers.

Answer:

Step-by-step explanation:

The expected value is the sum of products of payoff and probability of that payoff:

  -$8(37/38) +$288·(1/38) = $(-296 +288)/38 = -$8/38 ≈ -$0.21

In 1000 plays, the expected loss is ...

  -$8000/38 ≈ $210.53

The expected loss per roulette game, when betting $8 on number 33, is approximately $.0526, which equates to an expected loss of about $52.63 after 1000 games.

In the game of roulette, the player takes a risk by placing a bet on a specific outcome, in this case, the metal ball landing on the number 33. For this situation, we need to calculate the Expected Value, which is the long-term average of a random variable.

The player will either win $280 plus the original $8 bet, amounting to $288 or lose the $8 bet. The chance of winning is 1/38 and the chance of losing is 37/38. The expected value can be calculated as follows: (1/38) * $288 + (37/38) * -$8. This calculates to -$.0526. Therefore, each game, on average, the player loses about $.0526.

If you then multiply this average loss per game by the number of games played, in this case, 1000 games, you would find the total expected loss. So, -$. 0526 * 1000 = -$52.63. Therefore, if a player played this game 1000 times, they would expect to lose about $52.63.

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Answer:

the answer is:

b. x=10^2

ANSWER

b. x=10²

EXPLANATION

The logarithmic equation is:

[tex] log(x) = 2[/tex]

Note that this is the common logarithm, so it has a base of 10.

[tex] log_{10}(x) = 2[/tex]

Take antilogarithm of both sides to base 10.

[tex] {10}^{ log_{10}(x) } = {10}^{2} [/tex]

This implies that,

[tex]x = {10}^{2} [/tex]

the answer is "a" because If it was proportional out of 50 there would be 15 english majors.

Using stratified proportionate sampling out of 50 students, 15 English majors should have been chosen, fewer than the 20 selected in the simple random sample.

To answer the question, we need to determine how many English majors would have been chosen if the sample was created using stratified proportionate sampling. In stratified proportionate sampling, the number of students selected from each group is proportional to their representation in the overall population.

Since there are 150 English majors out of 500 students, English majors make up 30% of the student body. When creating a sample of 50 students, 30% of this sample size should be English majors, which would be:

30% of 50 students = 0.3 x 50 = 15 English majors.

Since the simple random sample selected 20 English majors, and a stratified proportionate sample would have included only 15, the answer is:

A.) There should be fewer English majors in the stratified proportionate sample.

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Answer:

(0,-5)

Step-by-step explanation:

The vertex form of the equation of a circle is [tex](x-h)^2 + (y-k)^2 = r^2[/tex] where (h,k) is the center of the circle and r is the radius. This means that for the equation [tex]x^2 + (y+5)^2 = 25[/tex] the center is (0,-5).

Answer:

Center:  ( − 5 , 2 )

Radius:  5

Step-by-step explanation:

on edge

Answer:

a) The increasing intervals would be from -4 to 0 and 4 to infinity. The decreasing interval would just be from negative infinity to -4 and 0 to 4.

b) The local maximum comes at x = 0. The local minimums would be x = -4 and x = 4

c) The inflection points are x= +/-√16/3

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

f(x) = x^4 - 32x^2 + 2

f'(x) = 4x^3 - 64x

Now we take the derivative and solve for zero to find the local max and mins.

f'(x) = 4x^3 - 64x

0 = 4x^3 - 64x

0 = 4x(x + 4)(x - 4)

x = -4 OR x = 4 OR 0

Given the shape of a positive 4th power function function, we know that the first and last  would be a minimums and the second would be a maximum.

As for the increasing, we know that a 4th power, positive function starts up and decreases to the local minimum. It also decreases after the local max. The rest of the time it would be increasing.

In order to find the inflection point, we take a derivative of the derivative and then solve for zero.

f'(x) = 4x^3 - 64x

f''(x) = 12x^2 - 64

0 = 12x^2 - 64

64 = 12x^2

16/3 = x^2

+/- √16/3 = x

-3/2 = x

Answer:

This is a problem where we need to analyse the function. To do so, we can recur to the applications of derivatives.

So, we have to derive the function first:

[tex]f(x)=x^{4}-32x^{2}  +3\\f'(x)= 4x^{4-1} -32(2)x^{2-1} + 0\\f'(x) = 4x^{3} -64x[/tex]

To analyse the function, we need to determinate the intervals using critic points, which can be found making the function equal to zero and then factorize:

[tex]f'(x) = 4x^{3} -64x=0\\x(4x^{2} -64)=0\\[/tex]

Applying the null factor property, we can equal to zero both factors:

[tex]x = 0\\4x^{2} -64=0\\4x^{2} =64\\x^{2} = \frac{64}{4}  =16\\x = ± 4[/tex].

So, there are three critic points: -4; 0 ; 4, which give us four intervals.

[tex](- \infty; -4], (-4;0],(0;4],(4;+\infty)\\[/tex].

Now, we have to evaluate each intervals, to know if they are increasing or decreasing. If the result of each evaluation results more than zero, then it's increasing, if results less than zero, it's decreasing.

So, the test values are -5 (1st interval), -1 (2nd interval), 1 (3rd interval), 5 (4th interval). As you can see, each value is included in one interval. The evaluation can be done just by replacing each value:

[tex]f'(-5) = 4(-5)^{3} -64(-5) = -180 <0\\f'(-1) = 4(-1)^{3} -64(-1) = 60>0\\f'(5) = 180>0\\f'(1) = -60<0[/tex]

Therefore, the increasing intervals of the function are [tex](-4;0],(4;+\infty)\\[/tex]. On the other hand, the decreasing intervals are [tex](- \infty; -4],(0;4],\\[/tex].

On the other hand, if the function change from negative to positive in c, then the function has a minimum located in (c ; f(c)). So, in -4 and 4, the function change from negative to positive (from decreasing to increasing), so the are minimums located in (-4;-253) and (4;-253). However, if the function change from positive to negative in c, then the functions has a maximum locate in (c ; f(c)). In this case, 0 changes from positive to negative. So, the maximum is located in (0; 3).

At last, the inflection points can be find using the second derivative criteria. First, we derive again the function, to find the second derivative, and then equal to zero to find inflexion points:

[tex]f"(x) = 12x^{2} -64=0\\12x^{2} =64\\x^{2} =\frac{64}{12} \\x=\sqrt{\frac{64}{12} } =±2.3[/tex]

Therefore, the inflexion points are located in -2.3 and +2.3. Next, we do the same process, we determine the intervals, then we evaluate each of them to find which interval is concave up and which is concave down.

Intervals: [tex](- \infty;-2.3);(-2.3;2.3);(2.3:+\infty)[/tex]

We can use -3, 0 and 3 to evaluate each interval:

Replacing this values in the second derivative expression ([tex]f"(x) = 12x^{2} -64[/tex]), we have:

[tex]f"(-3) = 12(-3)^{2} -64=44>0\\f"(0)=-64<0\\f"(3) = 12(3)^{2} -64=44>0[/tex]

So, positive results mean concave up, negative results mean concave down. Therefore,  [tex](- \infty;-2.3);(2.3:+\infty)[/tex] are concave up, and (-2.3;2.3) is concave down.

Answer:

[tex]-7.3[/tex]

Step-by-step explanation:

We want to evaluate the line integral:

[tex]\int\limits^{(4,6)}_{(0,3)} {x\sin y} \, ds[/tex]

where [tex]ds=\sqrt{(\frac{dx}{dt})^2+(\frac{dy}{dt})^2 }dt[/tex]

The parametric equation of the straight line joining (0,3) and (4,6) is

[tex]x=4t[/tex] and [tex]y=3t+3[/tex]

This implies that;

[tex]ds=\sqrt{(4)^2+(3)^2 }dt[/tex]

[tex]ds=\sqrt{25}dt[/tex]

[tex]ds=5dt[/tex]

Our line integral then becomes;

[tex]\int\limits^{1}_{0} {4t\sin (3t+3)} \, 5dt[/tex]

Using, using integration by parts, we obtain;

[tex]20\int\limits^{1}_{0} {t\sin (3t+3)} \, dt=-7.3[/tex] to the nearest tenth.

The solution to the line integral for the equation [tex]\mathbf{\int ^{(4,6)}_{(0,3)} \ x \ sin y \ ds}[/tex] where c is the line segment from (0,3) to (4,6) is -7.3

A line integral is a type of integral in mathematics in which the variable function to be integrated is measured across a curve.

From the given information, we are to evaluate the line integral:

[tex]\mathbf{\int ^{(4,6)}_{(0,3)} \ x \ sin y \ ds}[/tex]

where;

[tex]\mathbf{ds = \sqrt{(\dfrac{dx}{dt})^2 + (\dfrac{dy}{dt})^2}}[/tex]

Using the parametric function to determine the straight line joining (0,3) and (4,6), we have:

Then, we can now have ds to be:

[tex]\mathbf{ds = \sqrt{(\dfrac{4}{1})^2 + (\dfrac{3}{1})^2} \ dt}[/tex]

[tex]\mathbf{ds = \sqrt{(16 + 9} \ dt}[/tex]

[tex]\mathbf{ds = \sqrt{25} \ dt}[/tex]

ds = 5dt

Now, the line integral can be written as:

[tex]\mathbf{=\int^1_0 4t sin (3t + 3) \ 5 dt}[/tex]

By applying integration by parts, we have:

[tex]\mathbf{= 20 \int^1_0 t sin (3t + 3) \ dt}[/tex]

= -7.3

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The area of the triangle with points Q(-1,1),R(2,-3), and S(-1,-3) is equal to 6 square units.

In Mathematics and Geometry, the area of a triangle can be calculated by using the following mathematical equation (formula):

Area of triangle, A = 1/2 × b × h

Where:

By substituting the given vertices into the formula for the area of a triangle with coordinates, we have the following;

[tex]A=\frac{1}{2} \times |x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|\\\\A=\frac{1}{2} \times |-1(-3 + 3) + 2(-3 - 1) + (-1)(1 +3)|\\\\A=\frac{1}{2} \times |0 -8 - 4|\\\\A=\frac{1}{2} \times |-12|[/tex]

Area of triangle = 1/2 × 12

Area of triangle = 6 square units.

In the context of this horse racing problem, the weights assigned to horses can range from 53 kg - 4 kg to 53 kg + 4 kg, or 49 kg to 57 kg, thus option a (49 kg–57 kg) is the correct answer.

The question involves the concept of range in mathematics. In this horse racing scenario, we are given that the standard weight carried is 53 kg, and that the weight carried by each horse cannot differ by more than 4 kg from the standard. To find the maximum weight, we need to add 4 kg to the standard weight. So, the maximum weight a horse can carry is 53 kg + 4 kg = 57 kg. Likewise, to find the minimum weight, we subtract 4 kg from the standard. As a result, the minimum weight a horse can carry is 53 kg - 4 kg = 49 kg. Therefore, the maximum and minimum acceptable weights for a horse to carry are 57 kg and 49 kg, respectively, making option a the correct answer.

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Answer:

Option D. [tex]904.32\ in^{3}[/tex]

Step-by-step explanation:

we know that

The volume of the sphere (a baseball-shaped piñata ) is equal to

[tex]V=\frac{4}{3}\pi r^{3}[/tex]

we have

[tex]r=12/2=6\ in[/tex] -----> the radius is half the diameter

[tex]\pi=3.14[/tex]

substitute the values

[tex]V=\frac{4}{3}(3.14)(6)^{3}=904.32\ in^{3}[/tex]

Answer:

the answer is b

Step-by-step explanation:

There is no negative sign therefore d and a are not an option and yep ito b

Answer:

They are the same weight

Step-by-step explanation:

Haha! A classic riddle! They are both 100 pounds, so they weigh the same.

Hello there!

They are both the same. In the question, it states that you have 100 lbs of each item, so you have the same amount. There are probably waaaaay more flowers since they are very light, but nonetheless you still have 100 lbs so they will weigh the same :)

I hope this helps, have a great day!

Answer:

  C.  132

Step-by-step explanation:

We assume all angle measures are in degrees. The vertical angles are equal in measure, so ...

  4x = x +36

  3x = 36

  x = 12

  x +36 = 48

  y = 180 -48 = 132

The value of y is 132.

Answer:

more than: how much cups? 80 cups

Step-by-step explanation:

a little story to remember better:

there is a island called gallon island. there are 4 queens(quarts) and each queen has two prince's or princesses(pint). and each princess/prince has two childeren(cup)

if you draw it out you see:

one gallon

4 quarts

8 pins

and 16 cups

one gallon has 16 cups which is wayy more than 5 cups so the answer is more than 5 cups

now how much cups do you exactly need?

16 cups x 5 gallons = 80 cups

plz give brainliesttt

Answer:

The best estimate of the area of the irregular shape is [tex]19.5\ units^{2}[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

To know an estimate of the area of the figure calculate the area of the rectangle minus the squares marked with x

so

[tex]A=(8*6)-29=19\ units^{2}[/tex]

therefore

The best estimate of the area of the irregular shape is [tex]19.5\ units^{2}[/tex]

Answer:ITS NOT 19.5!!! ITS 15.5

Step-by-step explanation:

Answer:

Option c

Step-by-step explanation:

The general polar form of the conic with cosine in the denominator is:

[tex]r=\frac{ep}{1+ecos(\theta)}[/tex]

Comparing the given equation (Denominator) with the general equation, we can write:

e = 2

This means eccentricity = 2. Since eccentricity is greater than 1, the given conic is a hyperbola.

The equation of directrix is x = p

Comparing the numerators of general and given equation, we can write:

ep = 6

Using the value of e, we get p = 3

Therefore, equation of directrix is x =3

Hence option c is the correct answer.

The expression to compute the quartic root of a number x is sqrt(sqrt(x)).

To compute the quartic root of a number x, you can use the sqrt() function twice. The first call to sqrt() will find the square root of x, and the second call will find the square root of the result from the first call. This can be expressed as sqrt(sqrt(x)). This expression will return the quartic root of x if x is a positive number.

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Answer:

3xy^4+y-2/x

Step-by-step explanation:

12x^3y^4 + 4x^2y -8x

-----------------------------------

4x^2

We can break this fraction into pieces

12x^3y^4      4x^2y        8x

-------------- +    ---------   -  ------------

4x^2                4x^2          4x^2

Taking the first piece

12/4 =3

x^3/x^2 =x

y^4/1 =y^4

3xy^4

Taking the second fractions

4/4=1

x^2/x^2 =1

y=y

y

Taking the third fraction

8/4=2

x/x^2 = 1/x

2/x

Adding them back together

3xy^4+y-2/x

Final answer:

To solve for q in the equation k = 4pq², divide both sides of the equation by 4p and take the square root of both sides. Simplify to get q = ±(√k)/(2√p).

Explanation:

To solve for q in the equation k = 4pq², we need to isolate the variable q. Here are the steps:

Divide both sides of the equation by 4p to get q² = k/(4p).

Take the square root of both sides to get q = ±√(k/(4p)).

Simplify the square root to q = ±(√k)/(√(4p)).

Simplify further to q = ±(√k)/(2√p).

Therefore, the correct answer is q = ±(√k)/(2√p). This corresponds to option C.

Answer:

the correct answer is 77°

Step-by-step explanation:

Angle GHJ and IHJ form supplementary angles which add up to 180°

therefore angle IHJ=180-154

angle IHJ=26°

Triangle IHJ is an isosceles triangle whose base angles HIJand IJH are equal. Lets assign them the same value, x° each

since the sum of all interior angles of a triangle add up to 180°, then x°+x°+26°=180°

2x+26=180

2x=154°

x=77°

Therefore both HIJ and IJH measure 77°

Answer:

1,250 lbs

Step-by-step explanation:

There are 2,000 in 1 ton, so 5 * 2,000 = 10,000 lbs weight limit for the bridge.

10,000-8750 = 1,250 lbs can be added to the truck  before they reach the bridge weight limit.

Answer: 1250 pounds

There are 2000 pounds in one ton

Multiple 5 by 2000 and get 10000

Subtract that for 8570

Step-by-step explanation:

Answer:

y = 10

Step-by-step explanation:

The opposite sides of a parallelogram are congruent, hence

x + 10 = 110 - 4x ( add 4x to both sides )

5x + 10 = 110 ( subtract 10 from both sides )

5x = 100 ( divide both sides by 5 )

x = 20

Using the other pair of congruent sides, then

3y - 10 = 2x - 20 = (2 × 20) - 20 = 40 - 20 = 20, thus

3y - 10 = 20 ( add 10 to both sides )

3y = 30 ( divide both sides by 3 )

y = 10

Answer:

[tex]119.7\ miles[/tex]

Step-by-step explanation:

step 1

Find the total distance Jeremy rode in one day

[tex]2.2+11.1=13.3\ miles[/tex]

step 2

Find the total distance Jeremy rode in 9 days

Multiply the distance Jeremy rode in one  day by the total days

so

[tex]13.3(9)=119.7\ miles[/tex]

Answer:

Sean's collection was 250 times greater than Jeremy's.

Step-by-step explanation:

1.0 x 10^7 is the same as 10,000,000

4.0 x 10^4 is the same as 40,000

Divide 10,000,000 by 40,000 to get the answer. 10,000,000/40,000 = 250

Answer:

In the first account was invested [tex]\$3,000[/tex]  at 3%

In the second account was invested [tex]\$4,000[/tex]  at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]I=P(rt)[/tex]

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

First account

[tex]t=1 years\\ P=\$x\\ r=0.03[/tex]

substitute in the formula above

[tex]I=x(0.03*1)[/tex]

[tex]I=0.03x[/tex]

Second account

[tex]t=1 years\\ P=\$(7,000-x)\\ r=0.05[/tex]

substitute in the formula above

[tex]I=(7,000-x)(0.05*1)[/tex]

[tex]I=350-0.05x[/tex]

Remember that

The interest is equal to [tex]\$290[/tex]

so

Adds the interest of both accounts

[tex]0.03x+350-0.05x=\$290[/tex]

[tex]0.05x-0.03x=350-290[/tex]

[tex]0.02x=60[/tex]

[tex]x=\$3,000[/tex]

therefore

In the first account was invested [tex]\$3,000[/tex]  at 3%

In the second account was invested [tex]\$7,000-\$3,000=\$4,000[/tex]  at 5%

$3000 was invested at 3% and $4000 was invested at 5%.

To determine how much was invested in each account, follow these steps:

1. Define variables:

  - Let [tex]\( x \)[/tex] be the amount invested at 3% interest.

  - Let [tex]\( y \)[/tex] be the amount invested at 5% interest.

2. Set up the equations:

  - The total amount invested is $7000:

    [tex]\[ x + y = 7000 \][/tex]

  - The total interest earned is $290. The interest from each account is [tex]\( 0.03x \)[/tex] and [tex]\( 0.05y \),[/tex] respectively:

   [tex]\[ 0.03x + 0.05y = 290 \][/tex]

3. Solve the system of equations:

  From the first equation:

  [tex]\[ y = 7000 - x \][/tex]

  Substitute [tex]\( y \)[/tex] into the second equation:

  [tex]\[ 0.03x + 0.05(7000 - x) = 290 \][/tex]

  Distribute and simplify:

  [tex]\[ 0.03x + 350 - 0.05x = 290 \][/tex]

  [tex]\[ -0.02x + 350 = 290 \][/tex]

  [tex]\[ -0.02x = 290 - 350 \][/tex]

  [tex]\[ -0.02x = -60 \][/tex]

  [tex]\[ x = \frac{-60}{-0.02} \][/tex]

  [tex]\[ x = 3000 \][/tex]

  Now find [tex]\( y \)[/tex]:

  [tex]\[ y = 7000 - x \][/tex]

 [tex]\[ y = 7000 - 3000 \][/tex]

  [tex]\[ y = 4000 \][/tex]

Answer:

The number b is bigger than the number a by [tex]\dfrac{1}{4}[/tex] of a.

Step-by-step explanation:

1. If the number a is smaller than the number b by 1/5 of b, then

[tex]a+\dfrac{1}{5}b=b.[/tex]

Thus,

[tex]a=b-\dfrac{1}{5}b=\dfrac{4}{5}b,\\ \\b=\dfrac{5}{4}a.[/tex]

2. Consider the expression [tex]b=\dfrac{5}{4}a:[/tex]

[tex]b=\dfrac{5}{4}a=\dfrac{4}{4}a+\dfrac{1}{4}a=a+\dfrac{1}{4}a.[/tex]

This gives you that the number b is bigger than the number a by [tex]\dfrac{1}{4}[/tex] of a.

It is found that A is smaller by 1/5 of b.

To analyze the function or expression to make the function uncomplicated or more coherent is called simplifying and the process is called simplification.

We are given that the number a is smaller than the number b by 1/5 of b.

So if we add a and 1/5 of b, we would have b:

a + 1/5b = b

Solving for a we have:

A = b - 1/5b = 4/5b

A = 4/5b

Solving for b divide both sides by 4/5,

B = 5/4a

Since 4/4 = 1, this means b would be bigger than a by 1/4

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