Answer:
The program using do-while loop defined as follows:
Program:
#include <stdio.h> //include header file
int main() //defining main method
{
int i = 0; //defining integer variable i and assign value.
//defining do-while loop
do
{
printf("%d", ++i); //print value
}while (i<5); //check condition
return 0;
}
Output:
12345
Explanation:
Output of given program:
In the given program, it will not print any value because in while loop semi colon is used which is not valid.
Program Explanation:
In the above C language program header file is included, which provides features to use basic function then the main method is defined inside this method an integer variable "i" declare, that holds a value which is "0". In this method, the do-while loop is defined. In the do section, we print value and in the while block checks the condition which is i is less than 5.
Answer:
#include <stdio.h>
void main()
{
int i = 0;
do{
printf("%d ", ++i);
}
while (i < 5);
i=i+1;
}
}
Explanation
The #include needs to include something and that's the standard input and output which is coded has stdio.h
In the do while loop what it does is print the value of I while I is less than 5 and you increment I value so as to prevent infinite looping
Create a C++ program that consists of the following: In main create the following three variables: A char named theChar A double named theDouble An int named theInt Fill each of these variables with data taken as input from the keyboard using a single cin statement. Perform the following task on each variable: Increment theChar by one Decrement theDouble by two Square theInt This should be done on separate lines. Note, outputting theChar + 1 is not modifying the variable. It is simply outputting it. Output the value of each variable to the screen on separate lines using cout statements. Your program should also output the name of the variable followed by a colon.
Answer:
The source code and output is attached.
I hope it will help you!
Explanation:
Write an SQL statement to display from the Products table the CategoryID, CategoryName, and the sum of Units In Stock grouped by CategoryID, CategoryName and name the sum Total Products OnHand.Only include products that have 100 or lessin stock(Hint: use aWHERE clause). Only show categories having more than 200 total products in stock(Hint: use a GROUP BY and HAVING clause). Display the results in descending order by Total Products OnHand.
Answer:
Select CategoryID, CategoryName, sum(Units_in_stock) as "Total Products On hand"
from Products
where Units_in_stock <= 100
group by CategoryID, CategoryName
having count(Units_in_stock) > 200
order by count(Units_in_stock) desc;
Explanation:
First thing to do is to select the required columns from the Products table. We have used an alias for the "Units_in_stock" column.
Next, is to have the where clause, followed by grouping the results by category Id and name.
And after that, only showing grouped results with more than 200 as the sum value. And finishing it off with the descending order command.
Database management systems are expected to handle binary relationships but not unary and ternary relationships.'
True or false
Answer:
False
Database management systems are expected to handle binary, unary and ternary relationships.
Explanation:
Unary Relationship: It is a recursive relationship which includes one entity in a relationship which means that there is a relationship between the instances of the same entity. Primary key and foreign key are both the same here. For example a Person is married to only one Person. In this example there is a one-to-one relationship between the same entity i.e. Person.
Binary Relationships: It is a relationship involving two different entities. These two entities identified using two relations and another relation to show relationship between two entities and this relation holds primary keys of both entities and its own primary key is the combination of primary keys of the both relations of the two entities. For example Many Students can read a Book and many Books can be obtained by a Student.
Ternary Relationships: is a relationship involving three entities and can have three tables. For example a Supplier can supply a specific Part of many Mobiles. Or many Suppliers may supply several Parts of many Mobile models.
Final answer:
The claim that database management systems cannot handle unary and ternary relationships is false; they can manage unary, binary, and ternary relationships as well as other complex relationships.
Explanation:
The statement 'Database management systems are expected to handle binary relationships but not unary and ternary relationships.' is false. Modern database management systems (DBMS) are equipped to handle a variety of relationship types, including unary (or recursive), binary, and ternary relationships, among others. A unary relationship is an association between two instances of the same entity. For example, an employee entity might have a manager relationship that relates an employee to another employee who is the manager. A binary relationship exists between two different entities, such as an 'Employee' entity and a 'Department' entity where an employee works in a department. A ternary relationship involves three different entities at the same time, such as a 'Supplier', 'Product', and 'Consumer' entities, where a supplier provides products to a consumer.
Which of the following can be used to copy a file into OneDrive from the File Explorer window? Select all that apply.
A. select the file or folder
B. on the home tab in the clipboard group, click the copy button
C. navigate to the folder you want to move the file to and click the paste button
Final answer:
To copy a file to OneDrive from File Explorer, select the file, click the 'Copy' button in the Clipboard group under the Home tab, navigate to the OneDrive folder, and click 'Paste'. All the options are correct.
Explanation:
To copy a file into OneDrive from the File Explorer window, you would typically follow these steps:
Select the file or folder you wish to copy.On the Home tab in the Clipboard group, click the Copy button.Navigate to the OneDrive folder where you want to place the file.Click the Paste button to copy the file into the selected OneDrive folder.All of the actions listed - selecting the file or folder (A), clicking the copy button on the home tab in the clipboard group (B), and navigating to the folder you want to move the file to and clicking the paste button (C) - are steps in the process of copying a file to OneDrive.
Violations of security policies are considered to be a(n) __________ issue upon which proper disciplinary actions must be taken.
law enforcement
employer-employee
executive-staff
implementation
Answer:
Violations of security policies are considered to be a(n) law enforcement issue upon which proper disciplinary actions must be taken.
Explanation:
The security policies are considered as law enforcement issue, which may include the rules and regulations of the society decided by the government. These rules and regulations are necessary to maintain the norms of society.
The issue comes under the law enforcement are cyber crime, women rights security in working environment of the organization, use of technology that may cause threats for the society.
To enforce these law to maintain the security in the society, department of law and enforcement has been established such as Police department, Some intelligence agencies. They takes proper disciplinary action under the law enforcement to maintain the security in society against violation of rules.
The running time of Algorithm A is (1/4) n2+ 1300, and the running time of another Algorithm B for solving the same problem is 112n − 8. Assuming all other factors equal, at what input size(s) would we prefer one algorithm to the other?
Answer:
Answer is explained below
Explanation:
The running time is measured in terms of complexity classes generally expressed in an upper bound notation called the big-Oh ( "O" ) notation. We need to find the upper bound to the running time of both the algorithms and then we may compare the worst case complexities, it is also important to note that the complexity analysis holds true (and valid) for large input sizes, so, for inputs with smaller sizes, an algorithm with higher complexity class may outperform the one with lower complexity class i.e, efficiency of an algorithm may vary in cases where input sizes are smaller & more efficient algorithm might be outperformed by the lesser efficient algorithms in those cases.
That's the reason why we consider inputs of larger sizes when comparing the complexity classes of the respective algorithms under consideration.
Now coming to our question for algorithm A, we have,
let F(n) = 1/4x² + 1300
So, we can tell the upper bound to the function O(F(x)) = g(x) = x2
Also for algorithm B, we have,
let F(x) = 112x - 8
So, we can tell the upper bound to the function O(F(x)) = g(x) = x
Clearly, algorithmic complexity of algorithm A > algorithmic complexity of algorithm B
Hence we can say that for sufficiently large inputs , algorithm B will be a better choice.
Now to find the exact location of the graph in which algorithmic complexity for algorithm B becomes lesser than
algorithm A.
We need to find the intersection point of the given two equations by solving them:
We have the 2 equations as follows:
y = F(x) = 1/4x² + 1300 __(1)
y = F(X) = 112x - 8 __(2)
Let's put the value of from (2) in (1)
=> 112x - 8 = 1/4x² + 1300
=> 112x - 0.25x² = 1308
=> 0.25x² - 112x + 1308 = 0
Solving, we have
=> x = (112 ± 106) / 0.5
=> x = 436, 12
We can obtain the value for y by putting x in any of the equation:
At x=12 , y= 1336
At x = 436 , y = 48824
So we have two intersections at point (12,1336) & (436, 48824)
So before first intersection, the
Function F(x) = 112x - 8 takes lower value before x=12
& F(x) = 1/4x² + 1300 takes lower value between (12, 436)
& F(x) = 112x - 8 again takes lower value after (436,∞)
Hence,
We should choose Algorithm B for input sizes lesser than 12
& Algorithm A for input sizes between (12,436)
& Algorithm B for input sizes greater than (436,∞)
To determine at which input size one would prefer Algorithm A over B, their running times must be set equal and the resulting quadratic equation solved for 'n'. Algorithm A is quadratic (O(n^2)), while Algorithm B is linear (O(n)), indicating Algorithm B is better for large inputs. The exact crossover point is found by solving the quadratic equation formed by equating the two running times.
The question asks at what input size one would prefer Algorithm A ((1/4)n2 + 1300) over Algorithm B (112n
- 8) or vice versa, assuming all other factors equal. When analyzing the running time of algorithms, we focus on the highest-order terms, also known as Big-O notation. The running time of Algorithm A, in Big-O notation, is O(n2), while the running time for Algorithm B is O(n). Therefore, Algorithm B is more efficient for large input sizes due to its linear time complexity compared to Algorithm A's quadratic time complexity.
To determine the exact point where one algorithm becomes preferable over the other, we have to set their running times equal to each other and solve for n:
First, equate the two expressions: (1/4)n2 + 1300 = 112n - 8.Rearrange the terms: (1/4)n2 - 112n + 1308 = 0.Solve the quadratic equation for n.After solving the quadratic equation, we will get the values of n at which the running time of both algorithms is the same. For values lower than this n, Algorithm A would be preferred, and for values higher, Algorithm B would be more efficient.
To determine at which input size one would prefer Algorithm A over B, their running times must be set equal and the resulting quadratic equation solved for 'n'. Algorithm A is quadratic (O(n^2)), while Algorithm B is linear (O(n)), indicating Algorithm B is better for large inputs. The exact crossover point is found by solving the quadratic equation formed by equating the two running times.
The question asks at what input size one would prefer Algorithm A ((1/4)n2 + 1300) over Algorithm B (112n
- 8) or vice versa, assuming all other factors equal. When analyzing the running time of algorithms, we focus on the highest-order terms, also known as Big-O notation. The running time of Algorithm A, in Big-O notation, is O(n2), while the running time for Algorithm B is O(n). Therefore, Algorithm B is more efficient for large input sizes due to its linear time complexity compared to Algorithm A's quadratic time complexity.
To determine the exact point where one algorithm becomes preferable over the other, we have to set their running times equal to each other and solve for n:
First, equate the two expressions: (1/4)n2 + 1300 = 112n - 8.Rearrange the terms: (1/4)n2 - 112n + 1308 = 0.Solve the quadratic equation for n.After solving the quadratic equation, we will get the values of n at which the running time of both algorithms is the same. For values lower than this n, Algorithm A would be preferred, and for values higher, Algorithm B would be more efficient.
To determine at which input size one would prefer Algorithm A over B, their running times must be set equal and the resulting quadratic equation solved for 'n'. Algorithm A is quadratic (O(n^2)), while Algorithm B is linear (O(n)), indicating Algorithm B is better for large inputs. The exact crossover point is found by solving the quadratic equation formed by equating the two running times.
The question asks at what input size one would prefer Algorithm A ((1/4)n2 + 1300) over Algorithm B (112n
- 8) or vice versa, assuming all other factors equal. When analyzing the running time of algorithms, we focus on the highest-order terms, also known as Big-O notation. The running time of Algorithm A, in Big-O notation, is O(n2), while the running time for Algorithm B is O(n). Therefore, Algorithm B is more efficient for large input sizes due to its linear time complexity compared to Algorithm A's quadratic time complexity.
To determine the exact point where one algorithm becomes preferable over the other, we have to set their running times equal to each other and solve for n:
First, equate the two expressions: (1/4)n2 + 1300 = 112n - 8.Rearrange the terms: (1/4)n2 - 112n + 1308 = 0.Solve the quadratic equation for n.After solving the quadratic equation, we will get the values of n at which the running time of both algorithms is the same. For values lower than this n, Algorithm A would be preferred, and for values higher, Algorithm B would be more efficient.
Write a while loop that prints
A. All squares less than n. For example, if n is 100, print 0 1 4 9 16 25 36 49 64 81.
B. All positive numbers that are divisible by 10 and less than n. For example, if n is 100, print 10 20 30 40 50 60 70 80 90
C. All powers of two less than n. For example, if n is 100, print 1 2 4 8 16 32 64.
Following are the program to the given question:
Program Explanation:
Including the header file.Defining the main method inside this, two integer variables, "squ and n", are defined, then three while loops are declared.The loop is used to calculate different values, which can be described as follows: In the first, while loop, both "n" and "squ" variables are used, in which n is used for checking range and "squ" is used to calculate the square between 1 and 100. The second is that while it is used to calculate the positive number, which is divisible by 10, in this case only the n variable is used, which calculates the value and checks its range. In the last while, the loop is used, which is used to calculate the double of the number, which is in the 1 to 100 range.Program:
#include <iostream> //defining header file
using namespace std;
int main() //defining main method
{
int squ=0,n=0; //defining variable
cout<<"Square between 0 to 100 :"; //message
while(n<100) //loop for calculate Square
{
n=squ*squ; //holing value in n variable
cout<<n<<" "; //print Square
squ++; //increment value by 1
}
cout<<endl; //for new line
n=1; //change the value of n
cout<<"A Positive number, which is divisible by 10: "; //message
while (n< 100) //loop for check condition
{
if(n%10==0) //check value is divisible by 10
{
cout<<n<<" ";//print value
}
n++; //increment value of n by 1
}
cout<<endl; //for new line
cout<<"A Powers of two less than n: "; //message
n=1; //holing value in n
while (n< 100) //loop for check condition
{
cout<<n<<" ";//print value
n=n*2; //calculate value
}
return 0;
}
Output:
Please find the attached file.
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The problem involves writing while loops to print: (A) squares less than n, (B) numbers divisible by 10 less than n, and (C) powers of two less than n. Python code for each part is provided with examples.
Let's write a series of while loops to address each of the sections of the student's question.
A. All squares less than n
Here's the Python code to print all squares less than n:
n = 100For example, if n is 100, the output will be: 0 1 4 9 16 25 36 49 64 81
B. All positive numbers that are divisible by 10 and less than n
Here's the Python code to print all positive numbers divisible by 10 and less than n:
n = 100For example, if n is 100, the output will be: 10 20 30 40 50 60 70 80 90
C. All powers of two less than n
Here's the Python code to print all powers of two less than n:
n = 100For example, if n is 100, the output will be: 1 2 4 8 16 32 64
CTIVITY 2.2.2: Method call in expression. Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call findMax() twice in an expression.
Answer:
The one statement is:
maxSum = maxFinder.findMax(numA, numB) + maxFinder.findMax(numY, numZ);
Explanation:
The given code in the Activity contains a method named findMax() in class SumOfMax which has two parameters num1 and num2. The method returns the maximum value after comparing the values of num1 and num2.In the main() function, 4 variables numA, numB, numY and numZ of type double are declared and assigned the values numA=5.0, numB=10.0, numY=3.0 and numZ=7.0. Also a variable maxSum is declared and initialized by 0. After that an object named maxfinder of SumOfMax class is created using keyword new.SumOfMax maxFinder = new SumOfMax();
We can invoke the method findMax() by using reference operator (.) with the object name. So the task is to assign to maxSum the maximum of numA, numB plus maximum of numY, numZ in one statement. Using findMax() method we can find the maximum of numA and numB and also can find the maximum numY and numZ. The other requirement is add (PLUS) the maximum of numA, numB to maximum of numY, numZ. The statement used for this is given below:maxSum = maxFinder.findMax(numA, numB) + maxFinder.findMax(numY, numZ);
So as per the hint given in the question statement, findMax() function is being called twice, at first to find the maximum between the values of variables numA and numB and then to find the maximum between the values of numY and numZ. According to the given values of each of these variables:numA=5.0, numB=10.0,
So numB>numA
Hence findMax returns numB whose value is greater than numA Now findMax() is being called again for these variables:numY=3.0 and numZ=7.0
So numZ>numY as 7.0>3.0
Hence findMax() returns numZ whose value is 7.0Finally according to the statement maximum will be added and the result of this addition will be assigned to variable maxSum10.0 is added to 7.0 which makes 17.0 System.out.print("maxSum is: " + maxSum);This statement displays the value of maxSum which is 17.0
___________ is the term used to describe the time taken from when a packet is sent to when the packet arrives at the destination. This is commonly referred to as "ping time" in various places such as online gaming.
Answer:
Packet delay
Explanation:
In measuring the efficiency of a network, one of the many factors to consider is packet delay. Packet delay is the total time taken for a data packet to travel from its source network to its destination. It is sometimes called latency.
High packet delay or latency are caused by, but not limited to, the following:
(i) The distance between the source network and the destination network
(ii) The size of the packet being transferred
(iii) The time taken to forward data - packet switching delay.
what is the maximum number of charters of symbols that can be represented by UNicode?
Answer: 16 bit
Explanation:
Write a series of conditional tests. Print a statement describing each test and your prediction for the results of each test. For example, your code may look something like this:car = 'subaru'print("Is car == 'subaru'? I predict True.")print(car == 'subaru')print("\nIs car == 'audi'? I predict False.")print(car == 'audi')Create at least 4 tests. Have at least 2 tests evaluate to True and another 2 tests evaluate to False.
Answer:
this:name = 'John'
print("Is name == 'John'? I predict True.")
print(name == 'John')
print("\nIs name == 'Joy'? I predict False.")
print(car == 'Joy')
this:age = '28'
print("Is age == '28'? I predict True.")
print(age == '28')
print("\nIs age == '27'? I predict False.")
print(age == '27')
this:sex = 'Male'
print("Is sex == 'Female'? I predict True.")
print(sex == 'Female')
print("\nIs sex == 'Female'? I predict False.")
print(sex == 'Joy')
this:level = 'College'
print("Is level == 'High School'? I predict True.")
print(level == 'High School')
print("\nIs level == 'College'? I predict False.")
print(age == 'College')
Conditions 1 and 2 test for name and age
Both conditions are true
Hence, true values are returned
Conditions 3 and 4 tests for sex and level
Both conditions are false
Hence, false values are returned.
Conditional tests in Python allow you to check if a certain condition is True or False. Here are four examples of conditional tests with predictions and code outputs.
Explanation:Conditional Tests in PythonConditional tests in Python allow you to check if a certain condition is True or False. They are often used in decision-making structures like if statements. Here are four examples of conditional tests:
age = 16
print('Is age greater than 18? I predict False.')
print(age > 18)
temperature = 25
print('Is temperature between 20 and 30? I predict True.')
print(20 < temperature < 30)
is_raining = False
print('Is it not raining? I predict True.')
print(not is_raining)
name = 'John'
print('Does name start with J? I predict True.')
print(name.startswith('J'))
These examples demonstrate how to use conditional statements in Python to check if certain conditions are True or False, and then execute different code based on the results.
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For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively.
sll $t0, $s0, 2 # $t0 = f * 4
add $t0, $s6, $t0 # $t0 = &A[f]
sll $t1, $s1, 2 # $t1 = g * 4
add $t1, $s7, $t1 # $t1 = &B[g]
lw $s0, 0($t0) # f = A[f]
addi $t2, $t0, 4
lw $t0, 0($t2)
add $t0, $t0, $s0
sw $t0, 0($t1)
Answer:
Explanation:
The MIPS (Microprocessor without Interlocked Pipeline Stages) Assembly language is designed to work with the MIPS microprocessor. These RISC processors are used in embedded systems such as gateways and routers.
The C statement for given MIPS instruction set is below:
f = A[f];
f = A [f+1] + A[f];
B[g] = f;
Here, f, g, h and i are variables used in program.
A and B are arrays used in program.
Hope this helps!
Final answer:
The C statement corresponding to the given MIPS assembly instructions is 'f = A[f]; B[g] = f + A[f + 1];'.
Explanation:
The MIPS assembly instructions can be translated to the following C statement:
f = A[f]; B[g] = f + A[f + 1];
The explanation is as follows:
sll $t0, $s0, 2 and add $t0, $s6, $t0 calculate the address of A[f].sll $t1, $s1, 2 and add $t1, $s7, $t1 calculate the address of B[g].lw $s0, 0($t0) loads the value from A[f] into f.addi $t2, $t0, 4 and lw $t0, 0($t2) load the value from A[f + 1] into a temporary register.Finally, the value of f (A[f]) is added to the value at A[f + 1] and stored into B[g].
The U.S. National Institute of Standards and Technology defines the incident response life cycle as having four main processes: 1) Preparation 2) Detection and analysis 3) Containment, eradication, and recovery; and 4) ____. Select one: a. incident report b. triage c. post-incident activity d. resolution
Answer:
C. Post-incident activity.
Explanation:
An incident is a event of intrusion or attack or violation of an attempt of an attack. An incident response is an opposing response to an attack or violation.
An incident response life cycle are stages followed to mitigate a current attack or violation. The stages of the incident response life cycle are, preparation, detection and analysis, containing and eradicating and recovery, and post incident activity.
One example of a Microsoft Store app is Select one: a. Photos. b. Paint. c. File Explorer. d. Notepad.
Answer:
b. Paint
Explanation:
Paint was one of Microsoft's application that allowed users to draw basic diagrams and visual representation of objects. Microsoft Paint was discontinued as an addition in the latest versions of Windows, however the app is available for download from Microsoft Store App. Photos is an application of Apple, whereas File Explorer and Notepad are default applications of Windows operating system.
One example of a Microsoft Store app is Paint. Therefore, the correct answer is option B.
Paint was one of Microsoft's application that allowed users to draw basic diagrams and visual representation of objects. Microsoft Paint was discontinued as an addition in the latest versions of Windows, however the app is available for download from Microsoft Store App. Photos is an application of Apple, whereas File Explorer and Notepad are default applications of Windows operating system.
Therefore, the correct answer is option B.
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The basic parts of an instruction, in order from left to right, are:
a. label, mnemonic, operand(s), comment
b. comment, label, mnemonic, operand(s)
c. label, mnemonic, comment
d. mnemonic, operand(s), comment
Answer:
A. label, mnemonic, operand(s), comment.
Explanation:
Assembly language is a low level programming language. There are four parts of the assembly language syntax, they are, from left to right, label, mnemonic, operands, comments.
The label points to a specific location in the program, it is used to segment codes and ends with a colon. The mnemonic is also called an opcode, it is the operation carried out on the operands. The operands are the values in memory being resolved. A comment is a statement that describes a line of code, it is not executed by the assembler.
According to the text, is it possible to develop Internet applications without understanding the architecture of the Internet and the technologies?
Answer:
The correct answer to the following question will be "Yes".
Explanation:
Sure, you can write code of the program that interacts over a server without recognizing the technology of software and hardware that are used to transmit data through one program to another. Knowledge of the existing network system does, however, allow a developer to produce better code.Which command would rename the file cows.txt to cheezburger.txt? Select one: a. mv cows.txt cheezburger.txt b. I can haz cheezburger! c. rename cows.txt d. rn cows.txt cheezburger.txt e. rm cows.txt
Answer:
Option A i.e., mv cows.txt cheezburger.txt is the correct option.
Explanation:
In Linux, mv means move that is used to move a file from one destination to other but the user also used the mv command for renaming the file because it is the easiest way to rename any file to others.
Syntax:
mv first_file.ext new_file.ext
In the above syntax, mv is the command and first_file is the name of that file whose name wants to be change and .ext is the file extension, new_file.ext is that file that name wants to be applied on first one.
In this new file write a function called swapInts that swaps (interchanges) the values of two integers that it is given access to via pointer parameters. Write a mainfunction that asks the user for two integer values, stores them in variables num1 and num2, calls the swap function to swap the values of num1 & num2, and then prints the resultant (swapped) values of the same variables num1 and num2.
Here is the C++ program to swap the values of two integers. However, let me know if you require the program in some other programming language.
Program:#include <iostream>
/*include is preprocessor directive that directs preprocessor to iostream header file that contains input output functions */
using namespace std;
// namespace is used by computer to identify cout endl cin
void swapInts(int* no1, int* no2) {
/*function swapInts definition which swaps two integer values having pointer type parameters */
int temp; //temporary variable to hold the integer values
temp = *no1; // holds the value at address of no1
*no1 = *no2; //places no2 to no1
*no2 = temp; } //places no2 to temp variable which is holding no1
int main() // enters body of the main function
{ int num1; //declares variable num1 of integer type
int num2; //declares variable num2 of integer type
cout << "Enter two integer values:" << endl;
// prompts the user to input two integer values
cin>>num1; // reads input value of num1
cin>>num2; // reads input value of num2
cout<<"The original value of num1 before swapping is = "<<num1<<endl;
/*displays the original value of integer in num1 variable before calling swapInts function*/
cout<<"The original value of num2 before swapping is = "<<num2<<endl;
/*displays the original value of integer in num2 variable before calling swapInts function*/
swapInts(&num1, &num2);
/*function call to swapInts()) function and here &num1 is address of num1 variable and &num2 is address of num2 variable */
cout << "The swapped value of num1 is = " << num1 << endl;
//displays the value of num1 after swapping
cout << "The swapped value of num2 is = " << num2 << endl; }
//displays the value of num2 integer after swapping/
Output:Enter two integer values:
3
5
The original value of num1 before swapping is = 3
The original value of num2 before swapping is = 5
The swapped value of num1 is = 5
The swapped value of num2 is = 3
Explanation:This swapInts(&num1, &num2); statement calls the function swapInts() by passing the addresses of variables num1 and num2 in function call instead of the values of variables. In simple words the function is called by passing values by pointer. For this purpose the symbol & is used which is called reference operator which is used to assign address of the variables.So this method is called passing by pointer, which means that address of an actual argument in call to the function is copied to the formal parameters of the called function. The passed argument also gets changed with the change made to the formal parameter.In void swapInts(int* no1, int* no2) statement no1 holds the address of num1 and no2 holds the address of num2. Also *no1 and *no2 give value stored at addresses num1 and num2. So to obtain the value which is stored in these addresses, dereference operator "*" is being used with pointer variables *no1 and *no2.The address of num1 and num2 is passed to this function instead of the values of num1 and num2 Now if any changes are made to *no1 and *no2 this will affect the value of num1 and num2 and their value will be changed too.Implement a java program to find the smallest distance between two neighbouring numbers in an array.
Here is the JAVA program to find smallest distance between 2 neighboring numbers in an array.
import java.lang.Math; // for importing Math class functions
import java.util.Scanner; // for importing Scanner class
public class CalSmallestDistance // class to calculate smallest distance
{public static void main(String[] args) { // to enter java program
Scanner s = new Scanner(System.in); //creating scanner object
int size; // size of the array
System.out.print("Enter size of the array:"); //prompts to enter array size
size = s.nextInt(); // reads input
int arr[] = new int[size]; // array named arr[]
//line below prompts to enter elements in the array System.out.println("Enter numbers in the array:");
for(int j = 0; j < size; j++) //loops through the array
{arr[j] = s.nextInt(); } //reads the input elements
int smallest_distance = Math.abs(arr[0]-arr[1]);
int position= 0; //index of the array
for(int i=1; i<arr.length-1; i++){
int distance= Math.abs(arr[i]-arr[i+1]);
if(distance< smallest_distance){
smallest_distance= distance;
position = i; } }
System.out.println("Smallest distance is :"+smallest_distance);
System.out.println("The numbers are :"+arr[position]+ " and " +arr[position+1]); } }
Explanation:I have stated the minor explanation of some basic lines of code as comments in the code given above.
Now i will give the detailed explanation about the working of the main part of the code.
Lets start from here
int smallest_distance = Math.abs(arr[0]-arr[1]);
In this statement the array element at 0 index (1st position) and the array element at 1 index (2nd position) of the array are subtracted.
Then i used the math.abs() method here which gives absolute value
Lets say the distance between 3 and 5 is -2 as 3-5 equals to -2. But the math.abs() method will return 2 instead of -2.
Now the subtraction of two array elements and absolute value (if subtraction result is negative) will be assigned to variable smallest_distance.
for(int i=1; i<arr.length-1; i++)
This is for loop. Variable i is positioned to the 1 index of the array (arr) (it is pointing to the second element of the array). It will move through the array until the end of the array is reached i.e. the loop will continue till value of i remains less than the length of the array.
Now at the start of the loop body the following statement is encountered
int distance= Math.abs(arr[i]-arr[i+1]);
This subtracts the array element at i th position and array element at i th +1 position (means one position ahead of array element at i th position). In simple words two neighboring numbers in an array are being subtracted and Math.abs() method is used to give absolute value. The result of this operation is assigned to distance variable.
if(distance< smallest_distance)
This if statement checks if the value in distance variable is smallest than the value of smallest_distance variable which was previously calculated before calculating the value for distance variable.
If this condition is true then the following statements are executed:
smallest_distance= distance;
if distance value is less than value in smallest_distance, then the value of distance is assigned to smallest_distance.
this means the smallest_distance will keep on storing the smallest distance between two neighboring numbers.
Next the value of variable i that is pointing to the 1st index of the array is now assigned to the position variable.
position = i;
It will keep assigning the value of i to position variable so at the end of the program we can get the positions of the two neighboring numbers that have the smallest distance between them.
Then the value of i is incremented and moves one place ahead in the array.
Then the 2nd iteration takes place and again checks if i pointer variable has reached the end of the array. If not the loop body will continue to execute in which the distance between the two neighboring numbers is calculated and shortest distance is stored in smallest_distance.
When i reaches the end of the array the loop will break and the smallest distance between two neighboring numbers in the array have been stored in the smallest_distance variable.
Finally the statement System.out.println("Smallest distance is :"+smallest_distance); displays the shortest distance and the statement System.out.println("The numbers are :"+arr[position]+ " and " +arr[position+1]); displays the array index positions at which the two neighboring numbers have the smallest distance.
What is the value of vals[4][1]? double[][] vals = {{1.1, 1.3, 1.5}, {3.1, 3.3, 3.5}, {5.1, 5.3, 5.5}, {7.1, 7.3, 7.5}};
Answer:
When the user concludes the value of "vals[4][1]", then it will give an exception of "ArrayIndexOutOfBoundsException".
Explanation:
It is because the size of the above array is [4*3] which takes the starting index at [0][0] and ending index at [3][2]. It is because the array index value starts from 0 and ends in (s-1). When the double dimension array size is [5][5], then it will conclude the value of [4][1].The above array have following index which value can be calculated :-- [0][0],[0][1],[0][2],[1][0], [1][1],[1][2], [2][0], [2][1], [2][2],[3][0],[3][1] and [3][2].A ______________ is a specialized VM that contains an operating system and is preloaded and preconfigured with an application.
Answer:
The correct answer to the following question will be "Virtual Appliance ".
Explanation:
A virtual appliance is a virtual server picture file comprising an environment and a single software that has been preconfigured. The goal of a virtual system is to simplify application production and activity. Towards this end, only critical elements of the OS are included.It is a professional VM with an operating system and a preconfigured program. It is preconfigured.Therefore, Virtual Appliance is the right answer.
Answer:
Virtual Appliance
Explanation:
A virtual appliance (VA) is a virtual machine (VM) image file consisting of a pre-configured operating system (OS) environment and a single application. ... A virtual appliance can be deployed as a VM or a subset of a virtual machine running on virtualization technology, such as VMware Workstation.
A virtual appliance is a pre-configured virtual machine image, ready to run on a hypervisor; virtual appliances are a subset of the broader class of software appliances. Installation of a software appliance on a virtual machine and packaging that into an image creates a virtual appliance.
How will you ensure that all of the network's applications and tcp/ip services also support ipv6?
Answer:
Configure the Extended BSD API socket.
Explanation:
There are two types of logical network address, they are IP version 4 and up version 6. They are used to route packets to various destinations from various sources.
A network application must configure this IP addresses protocol. The IP version4 is the default address applications use. To enable IP version 6 the extended BSD API is configured on the network.
What is the output of the following query? SELECT INSERT ('Knowledgeable', 5, 6, 'SUPER');
Answer:
The above query gives an error.
Explanation:
The query gives an error because is not the correct syntax of the select or inserts query.The syntax of the select query is as follows: "select Attributes_1_name, Attributes_2_name,...., Attributes_n_name from table_name;".The syntax of the insert query is : "insert into table_name (column_1_name, column_2_name,...,column_n_name) values (column_1_value, column_2_value,...,column_n_value);".The syntax of the insert and select query is : "insert into table_name (select Attributes_1_name, Attributes_2_name,...., Attributes_n_name from table_name);".But the above query does not satisfy any property which is defined above. Hence it gives a compile-time error.A developer is asked to write negative tests as part of the unit testing for a method that calculates a person's age based on birth date. What should the negative tests include
Answer:
"Verify that the method rejects the future dates" is the correct answer.
Explanation:
In the given statement some information is missing, that is options of the question:
A) Taking the unit test with a custom exception.
B) Verify that the system accepts a null value.
C) Verify that the method accepts the past dates
D) Verify that the method rejects the future dates
Negative tests also stands for validation that check software can accommodate incorrect feedback on user actions gracefully. This testing indicates the program properly treats erroneous user behavior. It does not accepts unexpected input, and other options are wrong that can be described as follows:
In option A, It is not correct because this process does not verify the method.Option B and Option C are wrong because both options do not test negative input.Final answer:
Negative tests for calculating a person's age should include testing with future birth dates, non-date values, incorrect date formats, exceptionally high age results, and null or empty inputs to ensure the robustness of the application.
Explanation:
A developer asked to write negative tests for a method that calculates a person's age based on their birth date should consider scenarios where the input is incorrect, incomplete, or unexpected. Negative testing is essential for ensuring that the method can handle invalid input gracefully without crashing or giving incorrect output.
Here are some examples of inputs that could be used for negative tests:
Providing a birth date that is in the future
Using non-date values, such as strings or special characters
Entering a date format that the method is not designed to handle
Inputting birth dates that would result in ages that are exceptionally high and unrealistic
Submitting a null or empty input for the birth date
To prevent users of the application from changing the size of the form. you must set the FormBorderStyle property to ____
Answer:
The answer is "Fixed-single".
Explanation:
A FormBorderStyle property is a part of the C# language, which is used to displays the form's border style for viewing an application form. This property uses the fixed-single attribute, which will be used to determine, if the template or form can be resized by the end-user, it can be dragged or resized by no border or a title bar. A fixed, single-line border.
Courts are struggling with the privacy implications of GPStracking. In 2009, New York’s highest court held that policeofficers must have a ______________ in order to place a GPStracking device on a suspect’s car.
a. warrant
b. injunction
c. RFID tagtor
d. warrant
Answer:
warrant
Explanation:
New York State's highest court ruled in 2009 that tracking a person via the global positioning system (GPS) without a warrant violated his right to privacy.
A(n) __________ is a set of technologies used for exchanging data between applications and for connecting processes with other systems across the organization, and with business partners. Select one:
a. ERP
b. mashup
c. SOA
d. Web service
Answer:
The answer is "Option ".
Explanation:
The SOA stands for "Service-Oriented Architecture", which is primarily known as a service set and these services enable you to communicate with each other. In the communication, it may require simple data to transfer to two or more services, which can be organized by those operations, and other options were incorrect, that can be explained as follows:
In option a, It is a business software, which is used to organized data, that's why it is wrong.Option b and Option d both are wrong because the mashup process is used only on web services, which is not a part of SOA , that's why it is wrong.Answer:
The correct answer is letter "C": SOA.
Explanation:
Service-oriented architecture (SOA) is a type of software structure oriented to the integration of applications that share the same network or between different software systems that are part of different domains. SOA has the objective of aligning users with all the Information Technology (IT) of their organization.
A map file is produced by which of the following utility programs?
a. assembler
b. linker
c. loader
d. text editor
Answer:
b. Linker
Explanation:
Linker is a program which performs the process of linking.
Object modules of program are linked into a single object file using the linker.
It is also called link editors.
It is a process in which data and piece of code is collected and maintained into a single file.
It also links a specific module into system library.
All of the following are benefits of hosted data warehouses EXCEPT: a. Frees up in-house systems b. Smaller upfront investment c. Better quality hardware d. Greater control of data
Answer:
The answer is "Option d"
Explanation:
In networking, the data centers and cloud deployments are a micro-segmentation method, which is used to create security zones, that enables the company and isolates working loads and protect them individually. The main purpose to use, this process to increase the level of safety of the network and this process is also known as greater control of data, and other choices are not correct, that can be described as follows:
In option a, It is used to clean drive, that's why it incorrect. In option b, It is also known as share the amount of entrepreneur that can buy in a particular securities, fund or opportunity, that's why it is wrong. In option c, It is incorrect because it is used on the internet, that can't be part of this process.
Which of the following is a best practice for a strong password policy?
O Users must reuse one of the last five passwords.
O Passwords may be reset only after 30 days.
O Passwords must meet basic complexity requirements.
O Organizational Unit policy should be enforced over Domain policy.
Answer:
Passwords must meet basic complexity requirements.
Explanation:
Password should contain:
Uppercase lettersLowercase lettersdigits (0 through 9)special characters like @#$%^&*minimum length of 8Passwords should not contain:
user's name or surnamebirth year/datenot similar to previous passwordaccount/identity number