Reaction has a theoretical yield of 56.9 g. when the reaction is carried out, 36.6 g of the product is obtained.

The formation of BF3(g) from its elements in their standard states is described by the equation B(s) + 3F2(g) -> BF3(g). The reaction involves the solid boron reacting with three moles of fluorine gas to form boron trifluoride gas.

The formation of BF3(g) from its elements in their standard states is represented by the following equation:

B(s) + 3F2(g) -> BF3(g)

This equation represents the formation of one mole of boron trifluoride (BF3) gas from boron in its standard state (solid) and fluorine in its standard state (gaseous). In this reaction, solid boron reacts with three moles of fluorine gas to form one mole of boron trifluoride gas. This type of equation is typically used in calculations involving energetics, for example when calculating the standard enthalpy change of formation.

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The formation of boron trifluoride (BF3) from its elements boron (B) and fluorine (F2) in their standard states is represented by the equation: B(s) + 3/2 F2(g) -> BF3(g).

Boron trifluoride (BF3) is formed from its elements boron (B) and fluorine (F2) in their standard states. The equation for the formation of BF3 from its elements in their standard states can be written as:

B(s) + 3/2 F2(g) -> BF3(g).

Here, solid boron (B) reacts with fluorine gas (F2) to form boron trifluoride gas (BF3). This process involves the breaking of F-F bonds in F2 and the formation of new B-F bonds in BF3. The total energy involved in this conversion is equal to the experimentally determined enthalpy of formation of the compound from its elements.

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The chemical reaction involving Mg(OH)2 and HCl is:

Mg(OH)2  +  2HCl  -->  MgCl2  +  2H2O

So we see that for every 2 moles of HCl, 1 mole of Mg is reacted.

Calculating for moles HCl:

moles HCl = 0.300 M * 0.215 L

moles HCl = 0.0645 mol

The moles Mg then is:

moles Mg = 0.0645 mol * (1 / 2)

moles Mg = 0.03225 mol

0.03255 moles of Mg is used for neutralizing 0.3 M 245 ml [tex]\rm Mg(OH)_2[/tex].

The chemical reaction of the reaction of Mg with water yields Magnesium hydroxide.

The neutralization reaction of [tex]\rm Mg(OH)_2[/tex] with HCl will be:

[tex]\rm Mg(OH)_2\;+\;2\;HCl\;\rightarrow\;MgCl_2\;+2\;H_2O[/tex]

For neutralizing 1 mole of magnesium hydroxide 2 moles of HCl are required.

The moles  of HCl in the question are:

moles = [tex]\rm molarity\;\times\;\dfrac{1000}{Volume\;(ml)}[/tex]

moles of HCl = 0.3 [tex]\rm \times\;\dfrac{1000}{215}[/tex]

moles of HCl = 0.0645 moles.

The moles of Mg required are half of HCl.

Moles of Mg = [tex]\rm \dfrac{0.0645}{2}[/tex]

Moles of Mg = 0.03225.

0.03255 moles of Mg is used for neutralizing 0.3 M 245 ml [tex]\rm Mg(OH)_2[/tex].

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When titanium undergoes elctron capture

22Ti + e-  21Sc + Ve

so on electron capture of titanium produces Scandium

so your answer is Sc

Explanation:

It is known that when working with an electrical appliance then your hands must be dry because otherwise an electrical shock might occur.

Water is a good solvent and electrons can flow through it easily. Also, your work station must be dry also as it might also lead to an electrical shock.

Your plug must be pull on because otherwise some amount of electric current will still flow into the circuit. And, there are chances of getting an electric shock.

Hence, we can conclude that actions which are appropriate and safe when working with electrical equipment are as follows.

Whether CO or CO₂ is produced when a fuel burns depends on the availability of oxygen; ample oxygen leads to CO₂, limited oxygen to CO. Stoichiometry and bond energies are also important factors in combustion reactions, which release energy used in power and electricity, while also impacting the environment.

The production of either carbon monoxide (CO) or carbon dioxide (CO₂) when a fuel burns is largely determined by the availability of oxygen during the combustion process. In a reaction where there is ample oxygen, such as 2C₈H₁₈ (l) + 25O₂(g) → 16CO₂(g) + 18H₂O(g) + heat, the carbon in the fuel is fully oxidized to CO₂. However, with a limited oxygen supply, incomplete combustion occurs, leading to the production of carbon monoxide. For instance, 2 C (s) + O₂(g) → 2 CO(g) demonstrates how limited oxygen creates a predominance of CO. The precise stoichiometry of reactants and the strength of chemical bonds involved in the reaction play a critical role in the energy released during the combustion process. When we burn fuels such as paraffin, coal, propane, and butane, these chemical changes release huge amounts of energy that we utilize for power and electricity. At the same time, carbon dioxide (a greenhouse gas) is released, impacting the environment negatively.

Answer : The formula for an alkane which contained 42 hydrogen atoms is, [tex]C_{20}H_{42}[/tex]

Explanation :

The general representation of alkane is, [tex]C_nH_{2n+2}[/tex]

As we are given the number hydrogen atoms which is equal to 42. Now we have to determine the number of carbon atoms.

As,

[tex]2n+2=42\\\\2n=42-2\\\\2n=40\\\\n=\frac{40}{2}\\\\n=20[/tex]

Thus, the number of carbon atoms is, 20

Therefore, the formula for an alkane which contained 42 hydrogen atoms is, [tex]C_{20}H_{42}[/tex]

The answer is the water will boil. The water boils because of a reduction in the air pressure due to the reduced weight of air column above. This also reduces the collision of water molecules with air molecules at the surface hence allowing the water molecules to easily escape into the atmosphere. This means that the boiling point of the water is easily reached under low air pressure.

The water was at 20°C and when it was subjected to experience reduced pressure in a vacuum chamber where there was no exchange of energy was possible. The system was isolated from the surrounding and when the system was brought to low pressure of less than 18 mmhg the molecules of water expanded and the collision rate between the molecules increased which brought early boiling of the water molecules than normal conditions.

Final answer:

The molarity of acetic acid in the vinegar sample is determined by calculating the moles of NaOH used in the titration, which are equivalent to the moles of acetic acid, and then dividing by the volume of the vinegar sample.

Explanation:

The student's question pertains to the calculation of the molarity of acetic acid (HOAc) in a vinegar sample based on a titration experiment with sodium hydroxide (NaOH). To determine the molarity, we use the volume of NaOH added and the molarity of NaOH to calculate the moles of NaOH, which equals the moles of acetic acid due to the 1:1 stoichiometry in the reaction. The equation is:

Given that the volume of NaOH used is (19.35 mL - 0.15 mL) and the molarity of NaOH is 0.317 M, the calculation is as follows:

Moles of NaOH = (19.35 mL - 0.15 mL) × 0.317 M × (1 L / 1000 mL)

Moles of HOAc = Moles of NaOH

Molarity of HOAc = Moles of HOAc / 0.025 L

NaOH = 19.35 - 0.15 = 19.2 mL 19.2 mL x 0.317 M = 6.086 millimoles NaOH 6.086 mmol NaOH neutralized 6.086 mmol acetic acid 6.086 mmol acetic acid / 25.0 mL = 0.2435 mmol/mL = 0.2435 mol/L Acetic acid was 0.2435 M

Sodium benzoate, with the formula C₆H₅COONa, is an effective food preservative that functions by reducing intracellular pH. It is found in various food items and is quite soluble in water, with about 62.69 g dissolving in 100 mL of water.

Sodium benzoate is a commonly used food preservative, with the chemical formula C₆H₅COONa. It works to preserve food by reducing the intracellular pH, thus inhibiting the growth of bacteria and fungi.Sodium benzoate is generally considered nontoxic and is found in several food items including jams, soft drinks, pastries, and chewing gum.

When coming to its solubility in water, it is quite soluble: approximately 62.69 g can dissolve in 100 mL of water at 25 °C. Therefore, it can be dissolved in water quite easily, making it an effective option for food preservation.

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The pH of Marco's saliva indicates its acidity, and with a pH of 6.1, the hydrogen ion concentration, [H3O+], is approximately 0.0000008 M.

The subject of your question is related to the concentration of hydrogen ions in a solution, which comes under the field of chemistry. The pH of a solution is a way to measure the acidity or alkalinity of a liquid and is calculated by the formula pH = -log[H3O+]. If Marco's saliva has a pH of 6.1, we can use this formula to calculate the concentration of hydrogen ions, or [H3O+], in his saliva.

To find [H3O+], simply reverse the formula: [H3O+] = 10^-pH. So for Marco's saliva with a pH of 6.1, [H3O+] = 10^-6.1. This gives a hydrogen ion concentration of approximately 0.0000001 M or to seven decimal places, 0.0000008 M.

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The hydrogen ion concentration of Marco's saliva, determined from its pH of 6.1 using the formula [H+] = 10^(-pH), is approximately 7.943 × 10^(-7) Molar. This implies a relatively low concentration of hydrogen ions, indicative of a slightly acidic environment.

The pH of a solution is a measure of its acidity or alkalinity and is defined as the negative logarithm (base 10) of the hydrogen ion concentration. The formula for pH is given by pH = -log[H+], where [H+] is the hydrogen ion concentration.

In the case of Marco's saliva with a pH of 6.1, we can use the formula to find the hydrogen ion concentration.

pH = -log[H+]

6.1 = -log[H+]

To find [H+], we can rewrite the equation as:

[H+] = 10^(-pH)

Substituting the pH value:

[H+] = 10^(-6.1)

Calculating this gives the hydrogen ion concentration:

[H+] = 7.943 × 10^(-7)

Rounded to seven decimal places, the hydrogen ion concentration of Marco's saliva is approximately 0.0000008. Therefore, the hydrogen ion concentration is 7.943 × 10^(-7).

To learn more about hydrogen ion

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The solubility of M(OH)2 in a 0.202 M solution of M(NO3)2 is approximately 0.202 M.

To determine the solubility of M(OH)2 in a 0.202 M solution of M(NO3)2, we need to use the solubility product constant (Ksp) and solve for the molar solubility (M) of M(OH)2.

The equation for the dissolution of M(OH)2 is:

M(OH)2 → M²⁺ + 2OH⁻

Using the given Ksp value of 9.05 x 10-18, we can set up the expression for Ksp:

Ksp = [M²⁺] * [OH⁻]2

Since the molarity of M(NO3)2 is 0.202 M, the concentration of M²⁺ ions is also 0.202 M.

Let's assume the molar solubility of M(OH)2 is M. Therefore, the concentration of OH⁻ ions would be 2M (because of the 2:1 stoichiometric ratio).

Substituting the values into the expression for Ksp and solving for M, we get:

Ksp = (0.202)(2M)2

9.05 x 10-18 = 0.404 M²

Taking the square root of both sides:

M = 0.202 M

Therefore, the solubility of M(OH)2 in a 0.202 M solution of M(NO3)2 is approximately 0.202 M.

Evaporation and capillary action are required to work together to move water to the top of tall plants. Evaporation is a kind of condensation that happens in the form of a liquid as it transforms into the gas state when it approaches its boiling point.

Temperature, surface area and intermolecular forces are the factors which affect evaporation. Capillary action is the capacity of a liquid to move in confined areas without the help of forces, which are provided by outside like gravitational force which is due to earth.

These two phenomena are required to flow water or liquid to the top of tall plants.

You need evaporation and capillary action to move water to the top of tall plants.

I hope this helps :D

Explanation:

A molecule is a substance that contains atoms of either different or same elements.

For example, [tex]Cl_{2}[/tex] molecule and NaCl is also a molecule.

On the other hand, a compound always consists atoms of different elements. For example, NaCl is also a compound but [tex]Cl_{2}[/tex] is not a compound.

Whereas it is known that gases exist as diatomic molecules. For example, [tex]Cl_{2}[/tex], [tex]N_{2}[/tex], [tex]Br_{2}[/tex] are all gases.

Therefore, we can conclude that the particles of a gas are molecules.

Answer: The particles of a gas are ATOMS OR MOLECULES.

Hope this helps

The limiting reactant is substance a because we need 8.85 mol based on the stoichiometry of the reaction, but only have 3.5 mol. Substances b and c have more than needed to react completely with a. Therefore, a is the reactant that will run out first, limiting the amount of product d that can be formed.

To determine the limiting reactant in the chemical reaction 3a+2b+c→2d, we first calculate the number of moles of each substance. We were given 3.5 mol of a, 5.9 mol of b, and 2.2 mol of c. Using the stoichiometric ratios from the balanced chemical equation, we calculate the amount of each reactant needed:

Since 8.85 mol of a is needed but only 3.5 mol is present, a is the limiting reactant. To find the excess reactants, we identify the amount of b and c that would react with the 3.5 mol of a:

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For the reaction shown here, 5.7 mol A is mixed with 3.2 mol B and 2.5 mol C. The limiting reactant is . B

By comparing the mole ratios of reactants A, B, and C to their stoichiometric coefficients, we find that B has the smallest mole ratio, making it the limiting reactant.

For the reaction 3A + 2B + C → 2D, we begin by comparing the mole ratios of the reactants given: 5.7 mol A, 3.2 mol B, and 2.5 mol C.

The limiting reactant is the one with the smallest mole ratio compared to the stoichiometric coefficients.

Since B has the smallest mole ratio (1.60), it is the limiting reactant.

Correct question is: For the reaction shown here, 5.7 mol A is mixed with 3.2 mol B and 2.5 mol C. What is the limiting reactant?
3A+2B+C→2D
a. A.
b. B.
c. C.
d. D

 the answer is that high energy photons are what gamma rays consist of

Answer:

[tex]2.46x10^{22}atoms[/tex]

Explanation:

Hello,

In this case, we need to compute the atoms of both phosphorous and oxygen, taking into account the following mass-mole-atoms relationship:

[tex]Molar,mass=31*2+16*5=142g/mol\\atomsP=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{2molP}{1molP_2O_5} *\frac{6.022x10^{23}atomsP}{1molP}=7.04x10^{21}atomsP\\atomsO=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{5molO}{1molP_2O_5} *\frac{6.022x10^{23}atomsO}{1molO}=1.76x10^{22}atomsO[/tex]

Now, by adding each result, we've got:

[tex]atoms=1.76x10^{22}atomsP+7.04x10^{21}atomsO=2.46x10^{22}atoms[/tex]

Best regards.

Final answer:

To find the total atoms in 0.830 g of P2O5, calculate its moles, then multiply by Avogadro's number and atoms per molecule, resulting in approximately 2.46×1022 atoms.

Explanation:

To determine the total number of atoms in 0.830 g of P2O5, we first need to calculate the number of moles of P2O5.The molar mass of P2O5 can be calculated by adding the molar masses of phosphorus (P) and oxygen (O) in the compound. The molar mass of phosphorus is 30.973761 g/mol, and the molar mass of oxygen is 15.9994 g/mol. Therefore, for P2O5:2P: (2 atoms)(30.973761 g/mol) = 61.947522 g/mol5O: (5 atoms)(15.9994 g/mol) = 79.9970 g/mol The molar mass of P2O5 = 61.947522 g/mol + 79.9970 g/mol = 141.944522 g/mol. Now, to find the number of moles of P2O5 in 0.830 g:Number of moles = mass / molar mass = 0.830 g / 141.944522 g/mol = 0.005846 mol. Since one molecule of P2O5 contains 2 atoms of phosphorus and 5 atoms of oxygen, totalling 7 atoms, the total number of atoms in the sample is calculated by multiplying the number of moles by Avogadro's number (6.022×1023 atoms/mol) and then by the number of atoms per molecule: Total number of atoms = 0.005846 mol × 6.022×1023 atoms/mol × 7 atoms/molecule = 2.46×1022 atoms.

Answer: The equation is written below.

Explanation:

Copper is the 29th element of the periodic table having electronic configuration of [tex][Ar]3d^{10}4s^1[/tex]

When an atom looses an electron to form positive ion, it is called an oxidation reaction.

Copper will loose 1 electron to form +1 ion. The equation for the formation of copper (I) ion from neutral copper atom follows:

[tex]Cu\rightarrow Cu^++1e^-[/tex]

Hence, the equation is written above.

First let us calculate for the rate constant k from the formula:

k = ln(2) / t0.5

where t0.5 is the half life

k = ln(2) / 1.3x10^9 years

k = 5.33x10^-10 years-1

Then we use the formula:

A/Ao = e^-kt

where A/Ao is the amount remaining = 25% = 0.25, t is time

Rearranging to get t:

t = ln(A/Ao) / -k

t = ln(0.25) / (-5.33x10^-10 years-1)

t = 2.6x10^9 years

Answer : The age of the sample of granite is, 2.6 billion years

Solution : Given,

As we know that the radioactive decays follow the first order kinetics.

First we have to calculate the rate constant.

Formula used : [tex]t_{1/2}=\frac{0.693}{k}[/tex]

[tex]1.3\text{ billion years}=\frac{0.693}{k}[/tex]

[tex]k=0.533(\text{billion years})^{-1}[/tex]

Now we have to calculate the age of the sample of granite.

The expression for rate law for first order kinetics is given by :

[tex]k=\frac{2.303}{t}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  = [tex]0.533[/tex]

t = time taken for decay process  = ?

a = initial amount of the reactant  = 100 g

a - x = amount left after decay process  = 100 - 75 = 25 g

Putting values in above equation, we get the age of the sample of granite.

[tex]0.533=\frac{2.303}{t}\log\frac{100}{25}[/tex]

[tex]t=2.6\text{ billion years}[/tex]

Therefore, the age of the sample of granite is, 2.6 billion years

To calculate the ∆H of the reaction per mole of KOH, we use the thermal energy absorbed by the water (q), obtained from the mass, specific heat, and temperature change, and then divide by the moles of KOH present in the solution.

When 25.0 mL of 0.500 M H2SO4 is mixed with 25.0 mL of 1.00 M KOH in a coffee-cup calorimeter, and the temperature changes from 23.50°C to 30.17°C, we can calculate the enthalpy change (∆H) of the neutralization reaction per mole of KOH. Assuming no heat loss to the calorimeter, and that the solution's density and specific heat capacity are the same as water's, we find the heat absorbed by the solution (q) using the formula:

q = m × C × ∆T

Where m is the mass of the solution, C is the specific heat capacity, and ∆T is the change in temperature. The total volume of the solution is 50.0 mL, which we can convert to grams (density of water = 1.00 g/mL). The specific heat capacity of water (C) is typically 4.184 J/g°C, and ∆T is the temperature change (30.17°C - 23.50°C).

Answer:

vinegar is made from the most basic ingredient

Explanation:

Answer:

The answer on Ed is C :

VI /n1 = V2 / n2.

Explanation:

Final answer:

Heat can indeed travel through a vacuum, as it does not require a medium, contrasting with the false statement that heat and temperature are the same or that heat has shorter wavelengths than visible light.

Explanation:

The statement that heat can travel through a vacuum is true. Heat, in the form of infrared radiation, does not require a medium to travel. This is why we can feel the heat from the Sun, despite the vacuum of space. It's important to note that heat and temperature are not the same; temperature is a measure of the average kinetic energy of particles in a substance, while heat refers to the transfer of this energy between bodies or systems. Furthermore, electromagnetic radiation, which includes heat, has a wide range of wavelengths, with heat generally having longer wavelengths than visible light. Therefore, the statement that heat has shorter wavelengths than visible light is incorrect.