Reduce the rate 210 miles per 3 hours to it's unit rate and write the miles portion of your answer

Using the Pythagorean theorem, we find that the sum of the squares of the two shorter sides of the triangle (6 cm and 10 cm) is less than the square of the longest side (12 cm). Hence, the triangle is obtuse because 6² + 10² < 12².

To classify a triangle whose sides measure 6 cm, 10 cm, and 12 cm, we can use the Pythagorean theorem which relates the lengths of a right triangle's legs (a and b) to its hypotenuse (c), by the formula a² + b² = c². In our case, we need to check if the squares of the two shorter sides add up to the square of the longest side. We calculate:

Since 136 is less than 144, 62 + 102 < 122 is true, and the triangle is obtuse because the sum of the squares of the lengths of the two shorter sides is less than the square of the length of the longest side.

area = 1/2 b*h

1/2 *10 *015 =

1/2 * 150 =75

 area = 75 square feet

[tex]\displaystyle \boxed{y = \frac{6}{25}cos\:(1\frac{1}{2}\pi{x} - \frac{\pi}{2})} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{3}} \hookrightarrow \frac{\frac{\pi}{2}}{1\frac{1}{2}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}} \hookrightarrow \frac{2}{1\frac{1}{2}\pi}\pi \\ Amplitude \hookrightarrow \frac{6}{25}[/tex]

OR

[tex]\displaystyle \boxed{y = \frac{6}{25}sin\:1\frac{1}{2}\pi{x}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}} \hookrightarrow \frac{2}{1\frac{1}{2}\pi}\pi \\ Amplitude \hookrightarrow \frac{6}{25}[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = \frac{6}{25}cos\:1\frac{1}{2}\pi{x},[/tex] in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is approximately shifted [tex]\displaystyle \frac{1}{3}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{3}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{1}{3}} = \frac{\frac{\pi}{2}}{1\frac{1}{2}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = \frac{6}{25}cos\:(1\frac{1}{2}\pi{x} - \frac{\pi}{2}).[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-2\frac{2}{3}, 0],[/tex]from there to [tex]\displaystyle [-1\frac{1}{3}, 0],[/tex]they are obviously [tex]\displaystyle 1\frac{1}{3}\:unit[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 1\frac{1}{3}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended six-twenty-fifths unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**Now, it really does not matter which function you use because the result will always be the same, but IF the system only wants one function as an answer, then it would be the sine function sinse it intersects the origin. Other than that, it does not matter which one is chosen.

I am delighted to assist you at any time.

To satisfy his grandmother's request, Dave needs to mix [tex]\( \frac{1}{5} \)[/tex] cup of fruit for every [tex]\( \frac{1}{3} \)[/tex] cup of nuts.

To find out how many cups of fruit Dave needs to mix for a single cup of nuts, we need to find a common denominator for [tex]\( \frac{1}{5} \)[/tex]  and [tex]\( \frac{1}{3} \)[/tex], which is 15.

[tex]\[ \frac{1}{5} \times \frac{3}{3} = \frac{3}{15} \][/tex]

[tex]\[ \frac{1}{3} \times \frac{5}{5} = \frac{5}{15} \][/tex]

So, Dave needs to mix [tex]\( \frac{3}{15} \)[/tex] cup of fruit for every [tex]\( \frac{5}{15} \)[/tex] cup of nuts.

Therefore, to satisfy his grandmother's request, Dave must mix [tex]\( \frac{3}{15} \)[/tex] cup of fruit for a single cup of nuts.

The complete Question is given below:

dave is helping his grandmother make trail mix his grandmother asks him to add 1/5 cup of fruit for every 1/3 cup of nuts. To satisfy his grandmother's request, drave must mix ___ cups of fruit for a single cup of nuts

Answer:

m= 6/5, n= √2

Step-by-step explanation:

This is just a simple version of the answer.

3x-5 =10

 add 5 to both sides

3x=15

 divide both sides by 3

x=5

check:

3(5)-5 = 15-5 = 10

5 2/3 = 17/3 = 34/6

8 5/6 = 53/6

34/6 - 53/6 = -19/6 = -3 1/6

the answer is  20,21,29 because  

20 times 20 is 400

21 times 21 is 441

and 29 times 29 is 841

the formula to ge tthe answer is a^2 + b^2 = c^2

20^2 + 21^2= 29^2

then plug the rest in

400+441= 841

Answer:

[tex]\frac{r^{15}}{512}[/tex]

Step-by-step explanation:

(8r^-5)^ -3

[tex](8r^{-5})^{-3)[/tex]

Apply exponential property

(ab^m) ^n = a^m b^mn

Multiply the outside exponent with the exponents insde

[tex](8r^{-5})^{-3)= 8^{-3}r^{-5*-3}=8^{-3}r^{15}[/tex]

Appy property a^-m = 1/a^m to make the exponent positive

[tex]8^{-3}r^{15}= \frac{r^{15}}{8^3} =\frac{r^{15}}{512}[/tex]

Answer:

[tex]3\frac{5}{8}[/tex] pizzas were there at the start of the party.

Step-by-step explanation:

At the party let number of pizzas were = x

Aisha and her friends ate [tex]2\frac{1}{2}[/tex] pizzas after which [tex]1\frac{1}{8}[/tex] pizzas were left.

Therefore the equation formed will be

[tex]x-2\frac{1}{2}=1\frac{1}{8}[/tex]

x - (5/2) = 9/8

x = 9/8 + 5/2

x = 29/8 = [tex]3\frac{5}{8}[/tex]

Therefore [tex]3\frac{5}{8}[/tex] pizzas were there at the start of the party.

585/9 = 65 miles per hour

65 x 5 = 325 miles

 she would drive 325 miles in 5 hours

Answer: on e2020 it’s b

Step-by-step explanation:

Answer: [tex]1.25=1+0.2+0.005[/tex]

Step-by-step explanation:

Given : When measuring board footage for some exotic woods, a carpenter must use 1.25 inches for thickness rather than 1 inch in her calculations.

To write : 1.25 in expanded form.

When we write a decimal number in expanded form, we are showing the place value of each digit.

Now, 1.25 can be written as :

[tex]1.25=1+0.2+0.005[/tex]

Hence, the expanded form of [tex]1.25=1+0.2+0.005[/tex]

Answer:

As shown in the image....

Step-by-step explanation:

This equation follows with the distance formula which is (x2-x1)+(y2-y1) squared.

Final answer:

The weight of the solids in the fruit remains constant at 10 kg. When the water content changes to 80%, the total weight of the fruit is 50 kg, since the solids make up 20% of the fruit's weight.

Explanation:

Initially, we have 100 kg of fruit with 90% water content. This means that there are 90 kg of water and 10 kg of solids (since water plus solids equals the total weight of the fruit).

After some time, the fruit dehydrates to where it now contains 80% water. However, the amount of solids in the fruit has not changed; it remains constant at 10 kg. To find the new total weight of the fruit with 80% water, we can set up the equation where 80% of the new weight is equal to the weight of the solids subtracted from the new total weight (since solids comprise the remaining 20% of the weight).

Let's denote the new total weight of the fruit as 'x'. According to the given information, 20% of x is the weight of the solids, which is 10 kg. Therefore, the equation is:

0.20x = 10 kg

Now we solve for 'x':

x = 10 kg / 0.20 x = 50 kg

The result is that there are 50 kg of the fruit with 80% water content now.

The approximate length of the leg of a right triangle is 17.

Use the concept of a triangle defined as:

A triangle is a three-sided polygon, which has three vertices and three angles which has a sum of 180 degrees.

And the Pythagoras theorem for a right-angled triangle:

(Hypotenuse)²= (Perpendicular)² + (Base)²

Given that,

One leg = 8 say it is the base of a triangle.

Hypotenuse = 19

Applying the Pythagorean theorem,

(19)²= (Perpendicular)² + (8)²

(Perpendicular)² = 297

Taking square root on both sides,

Perpendicular ≈ 17.2

Hence,

The required length of leg is approximately 17.

To learn more about triangles visit;

brainly.com/question/1058720

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