Reese went cycling in the morning .The ratio of her distance in miles to the length of time in minutes was 15:60 tease concluded that she rode at an average speed of 4 miles per minute is she correct or not ?

Answer:

(3) Jonah's graph has a steeper slope than Rowan's

Step-by-step explanation:

First we are going to write the equations for the amount of money that each one save

y = a+bx

 Where y: Amount of money in the jar

             a: Initial saving

             b: Money saved every week ( graph's slope )

             x: Number of week

Then, for Rowan

y = 50 + 5x

and for Jonah

y = 10 + 15x

Initially Rowan's graph lies above Jonah's graph but this situation change with time.

It is always true that Jonah's graph has a steeper slope than Rowan's, because for Rowan's graph the slope is 5 and for Jonah's graph the slope is 15

Then the answer is:  

(3) Jonah's graph has a steeper slope than Rowan's

3) Jonah's curve has a steeper slope than Rowan's is True, All others are false

Rowan Savings Equation = 50 + 5t , where t is weekly time

Rowan Savings = 10 + 15t , where t is weekly time

        1             50 + 5 (1) = 55           10 + 15 (1) = 25

        2            50 + 5 (2) = 60          10 + 15 (2) = 40

        3            50 + 5 (3) = 65          10 + 15 (3) =  55

        4            50 + 5 (4) = 70           10 + 15 (4) = 70

        5            50 + 5 (5) = 75           10 + 15 (5) = 85

At t weeks < 3 , Rowan savings > Jonah savings. At t weeks > 4, Jonah savings > Rowan savings. At t = 4 units, their savings are equal. So, none savings curve is above the other 'always'.

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The exponential growth function that models the data is: A(t) = 6.27 million * e^(0.0173t)

We can use the given information to solve for the parameters in the exponential growth model:

1. Set up the equation:

We know the initial population (A_0) is 6.27 million and the projected population after 40 years (t = 40) is 9 million. Therefore:

A(t) = 6.27 million * e^(kt)

2. Solve for k:

Substitute the final population value and time into the equation and solve for k:

9 million = 6.27 million * e^(40k)

e^(40k) = 9 million / 6.27 million

e^(40k) ≈ 1.433

Take the natural logarithm of both sides to isolate k:

40k ≈ ln(1.433)

k ≈ ln(1.433) / 40

k ≈ 0.0173

3. Write the complete function:

Now that we know k, we can substitute it back into the original equation to find the complete function:

A(t) = 6.27 million * e^(0.0173t)

Therefore, the exponential growth function that models the data is: A(t) = 6.27 million * e^(0.0173t)

Answer:

$28,600

Step-by-step explanation:

Probably of 0.7 = 46000

Probability of 0.3 = 12000

The average profit = Sum of (x*Pr(x)

=0.7(46000) + 0.3(-12000)

= 32200 - 3600

= $28,600

The contractor should expect to earn $28,600 on the average

Answer:

a. 53.20; 94.30

Step-by-step explanation:

Data given  

[tex]\mu =73.75[/tex] reprsent the population mean

[tex]\sigma=6.5[/tex] represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: [tex] 1-\frac{1}{k^2}"[/tex]

We want the limits that have at least 90% of the population is include. And using the theorem we have this:

[tex]0.9 =1-\frac{1}{k^2}[/tex]

And solving for k we have this:

[tex]\frac{1}{k^2}=0.1[/tex]

[tex]k^2 =\frac{1}{0.1}=10[/tex]

[tex]k=\pm 3.162[/tex]

So then we need the limits between two deviations from the mean in order to have at least 90% of the data will reside.

Lower bound:

[tex]\mu -3.162\sigma=73.75-3.162(6.5)=53.195 \apporx 53.20[/tex]

Upper bound:

[tex]\mu +3.192\sigma=73.75+3.162(6.5)=94.304 \approx 94.30[/tex]

So the final answer would be between (53.20;94.30)

Using Chebyshev's theorem to find the range of life expectancy for Canadian women that includes at least 90% of the population, the lower and upper bounds are approximately 53.21 years and 94.29 years, respectively.

The question pertains to calculating bounds on life expectancy using Chebyshev's theorem, which is a statistical rule that applies to different types of distributions, regardless of their shape. To calculate the bounds that include at least 90% of the data for the life expectancy of Canadian women, where the mean is 73.75 years, and the standard deviation is 6.5 years, we need to use the formula k = 1/√(1-(1/p)), where p is the proportion of the population. In this case, since we want to include at least 90% of the population, p=0.9.

First, we solve for k:

k = 1/√(1-(1/0.9))
k ≈ 3.16

Then, we multiply k by the standard deviation and subtract it from and add it to the mean to find the bounds:

Lower Bound = Mean - k * Standard Deviation
Lower Bound = 73.75 - (3.16 * 6.5) ≈ 53.21

Upper Bound = Mean + k * Standard Deviation
Upper Bound = 73.75 + (3.16 * 6.5) ≈ 94.29

Therefore, the bounds are approximately 53.21 years and 94.29 years, which corresponds to option a. 53.20; 94.30.

Answer: the 55th stripe is white

Step-by-step explanation:

The first four stripes on a wall with 100 stripes are red , blue, white, and purple. The four colors repeat in the same order. This means that Red always follow blue which is followed by white and then purple. This means that red would always start each new and consecutive set of four stripes and purple will always end it

We want to determine the 55th stripe. The last four stripes that include 55 ends with the 56th stripe. This means that the 56th stripe is purple. Therefore, the 55th stripe would be white because it follows purple.

The color of the 55th stripe on the wall is white. The colors repeat every four stripes implying that the 55th, as per our calculation, falls on the third color in the pattern, white.

This is a repetition pattern problem in Mathematics. The pattern of colors (red, blue, white, purple) on the wall repeats every four stripes. To determine the 55th stripe color, we divide 55 by 4, getting a quotient of 13 and a remainder of 3. The remainder indicates that the 55th stripe is the third color in our repeating pattern which is white.

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Answer:

  2

Step-by-step explanation:

A is on the line QA', which is 1.25+1.25 = 2.50 units long*. Thus the scale factor is ...

  QA'/QA = 2.50/1.25 = 2

The scale factor is 2.

_____

* There are two points on the line QA that are 1.25 units from A. One of them is point Q. If A' is coincident with Q, then the scale factor is 0, and line segment A'B' is the single point Q. We don't believe that is intended to be the case, so we assume that point A' is farther along AQ, hence 2.5 units from Q.

Answer:

Step-by-step explanation:

Let B divides AB in the ratio K:1

[tex]x=\frac{nx1+mx2}{m+n} \\y=\frac{ny1+my2}{m+n} \\\frac{-4}{5} =\frac{1*\frac{2}{3}+k*4}{k+1} \\-4k-4=\frac{10}{3} +20k\\-12 k-12=10+60k\\72k=-22\\36k=-11\\k=-\frac{11}{36} \\[/tex]

so B divides AB in the ratio 11:-36

[tex]x=\frac{-36*1+11 *\frac{-1}{2} }{11-36} \\x=\frac{83}{50}[/tex]

Answer:

[tex]\large \boxed{1.66}[/tex]

Step-by-step explanation:

1. Calculate the equation of the straight line joining A and C.

The equation for a straight line is

y = mx + b

where m is the slope of the line and b is the y-intercept.

The line passes through the points (-½, 4) and (1, ⅔)

(a) Calculate the slope of the line

[tex]\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = & \dfrac{\frac{2}{3} - 4}{1 - (-\frac{1}{2})}\\\\& = & \dfrac{-\frac{10}{3}}{\frac{3}{2}}\\\\& = & \dfrac{-10}{3}\times{\dfrac{2}{3}}\\\\& = & \dfrac{-20}{9}\\\\\end{array}[/tex]

(b) Find the y-intercept

Insert the coordinates of one of the points into the equation

[tex]\begin{array}{rcl}y & = & mx + b\\4 & = & \dfrac{-20}{9}\left(-\dfrac{1}{2}\right) + b \\\\4 & = & \dfrac{10}{9} + b\\\\b & = & \dfrac{36}{9} - \dfrac{10}{9}\\\\b & = & \dfrac{26}{9}\\\\\end{array}[/tex]

(c) Write the equation for the line

[tex]y = -\dfrac{20}{9}x + \dfrac{26}{9}[/tex]

2. Calculate the value of x when y = -⅘

[tex]\begin{array}{rcl}y & = & -\dfrac{20}{9}x + \dfrac{26}{9}\\\\-\dfrac{4}{5} & = & -\dfrac{20}{9}x+ \dfrac{26}{9}\\\\36 & = & 100x -130\\100x & = & 166\\x & = & 1.66\\\end{array}\\\text{The value of x is $\large \boxed{\mathbf{1.66}}$}[/tex]

The graph below shows your three collinear points.

Answer: Expected value is -4.48.

Step-by-step explanation:

Since we have given that

Cost of ticket for a raffle = $7

Number of tickets sold = 640

Amount winner wins = $1600

So, we need to find the expected value.

So, it becomes,

[tex]E[x]=\sum xp(x)\\E[x]=-7\times \dfrac{639}{640}+(1600+7)\times \dfrac{1}{640}\\\\E[x]=\dfrac{-4473+1607}{640}\\\\E[x]=\dfrac{-2866}{640}\\\\E[x]=-4.48[/tex]

Hence, Expected value is -4.48.

Answer:  a. 0.04

Step-by-step explanation:

Given : Number of multiple choice questions  = 2

Choices given in each question = 5

Since only one choice is correct out of 5.

So, the probability of selecting the correct answer = [tex]\dfrac{1}{5}[/tex]

Also, both questions are independent of each other.

It means , The probability of answering the two multiple choice questions correctly if random guesses are made

=( Probability of selecting the correct answer in question 1 ) x ( Probability of selecting the correct answer in question 2 )

= [tex]\dfrac{1}{5}\times\dfrac{1}{5}= 0.04[/tex]

Hence, the required probability =0.04

Answer:

"≥"

Step-by-step explanation:

1) Well, for the sake of clarity we'll use a circle on a number line to represent the point solution of each inequality.

2) Writing the system:

[tex]\left\{\begin{matrix}y\geqslant 3x&\\x\geqslant-2&\end{matrix}\right.[/tex]

3) We'll shade the circles and use "≥"

Final answer:

The correct inequality symbols that could be written in both circles for the system 'y 3x x –2' are '<=' and '>=', representing the relationships 'y <= 3x' and 'x >= -2' respectively.

Explanation:

To represent the given system of inequalities algebraically, one needs to identify the correct inequality symbols that could be used between the variables x and y. These symbols articulate the ordering and relationship between these variables.

Given the statement of the system 'y 3x x –2', the inequality symbols that could fit in the circles to complete the system algebraically could be '<=' for 'y <= 3x' and '>=' for 'x >= -2'. This means '<=' and '>=' are both inequality symbols that could be written in the circles to represent the relationship between the variables according to the rules of inequalities which define x is less than or equal to y (x <= y), and x is greater than or equal to y (x >= y).

Inequalities allow us to compare relative sizes or orders of numbers and to solve various algebraic problems dealing with quantity and relationships.

Answer:

384 lamps

Step-by-step explanation:

This is simply a multiplication problem. From the question, we know that each fixture needs 4 lamps with a single room needing 16 fixtures.

The number of lamps required by each room is thus 16 * 4 = 64 lamps

Now, the total number of lamps required by 6 rooms is thus 64 * 6 = 384 lamps

To find the total number of lamps required for 6 rooms, multiply the number of fixtures per room by the number of rooms, then multiply the result by the number of lamps per fixture.

To find the total number of lamps required for 6 rooms, we need to first determine the number of fixtures in 6 rooms. Since each room requires 16 fixtures, the total number of fixtures in 6 rooms would be 16 x 6 = 96 fixtures.

Each fixture requires 4 lamps, so to find the total number of lamps required for 96 fixtures, we multiply 96 x 4 = 384 lamps.

Therefore, 384 lamps will be required for 6 rooms.

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Answer:

The farmer will need 7 crates.

Step-by-step explanation:

It is given that there are 71 pumpkins in total.

And each crate holds 19 pumpkins.

Let the number of crates required be "n".

The total number of pumpkins can be calculated by multiplying number of pumpkins in each crate with total number of crates.

Thus, the equation is

[tex]19(n) = 71[/tex]

[tex]n = \frac{71}{19} = 7[/tex]

Thus, the farmer needs 7 crates to hold total of 71 pumpkins.

Answer:

  x = -4

Step-by-step explanation:

Vertical asymptotes are found where the denominator has a zero that is not cancelled by a numerator zero. Here, the expression simplifies to ...

  [tex]f(x)=\dfrac{x^2+7x+10}{x^2+9x+20}=\dfrac{(x+5)(x+2)}{(x+5)(x+4)}=\dfrac{x+2}{x+4} \qquad x\ne -5[/tex]

The function is undefined at x=-5, but has a vertical asymptote at x=-4.

Answer:

Size C can is the best buy.

Step-by-step explanation:

The given question is incomplete; here is the complete question.

One brand of canned salmon is sold in four different sizes.

Size A The 7 1/5 -ounce can costs $3.49.

Size B The 16 1/2 -ounce can costs $6.49.

Size C The 24 3/4 -ounce can costs $8.49.

Size D The 30 2/3 -ounce can costs $10.99. What is the unit rate for each size to the nearest cent? If the cost is less than a dollar, put a zero to the left of the decimal point.

Size Unit rate

A (Blank)

B (Blank)

C (Blank)

D (Blank)

What size is best to buy? explain how you know.

For Size A - [tex]7\frac{1}{5}[/tex] ounce or [tex]\frac{36}{5}[/tex] ounce can costs $3.49

Therefore, per ounce cost = [tex]\frac{\text{Total cost}}{\text{Size of can}}[/tex]

= [tex]\frac{3.49}{\frac{36}{5}}[/tex]

= [tex]\frac{3.49\times 5}{36}[/tex]

= $0.48

For Size B - [tex]16\frac{1}{2}[/tex] or [tex]\frac{33}{2}[/tex] ounce can costs $6.49

Per ounce cost = [tex]\frac{6.49}{\frac{33}{2}}[/tex]

= [tex]\frac{6.49\times 2}{33}[/tex]

= 0.39

For size C - [tex]24\frac{3}{4}[/tex] ounce or [tex]\frac{99}{4}[/tex] ounce can costs $8.49

Per ounce cost = [tex]\frac{8.49}{\frac{99}{4}}[/tex]

                         = [tex]\frac{8.49\times 4}{99}[/tex]

                         = $0.34

For size D - [tex]30\frac{2}{3}[/tex] or [tex]\frac{92}{3}[/tex] ounce can for $10.99                                                              

Per ounce cost = [tex]\frac{10.99}{\frac{92}{3} }[/tex]

                         = [tex]\frac{10.99\times 3}{92}[/tex]

                         = $0.36

For size C, per ounce cost of the can is the least. Therefore, size C can is the best buy.

There are 4 numbers possible 156, 257, 358 and 459.

The value a digit in a number represents based on where it is in the number is known as place value.

Let 25 is a number, then the place value of 2 is 20.

Let the three-digit number is x5y,

Then the number whose digits are switched is y5x,

The number x5y can be written according to its place value = 100x + 50 + y

Similarly, y5x can be written according to its place value = 100 y + 50 + x

The number y5x is 495 more than the number x5y

Implies that,

100 y + 50 + x - (100x + 50 + y) = 495

99y-99x - 495

99(y-x) = 495

y-x = 5

The numbers can be 156, 257, 358 and 459.

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Final answer:

To find the three-digit number with the tens digit being 5 and the number increasing by 495 when the hundreds and ones digits are switched, set up an equation using placeholders for the hundreds and ones digits, solve the equation to find these digits, and deduce the original number, which is 459.

Explanation:

The question involves finding a three-digit number based on given conditions about digits and their positions. We know that the tens digit is 5. If we switch the hundreds and the ones digits, the number increases by 495. This implies that the ones digit must be less than the hundreds digit, as switching them results in a larger number. Let's denote the hundreds digit by 'a' and the ones digit by 'c'.

The original number can be represented as 100a + 50 + c, and after switching, the number becomes 100c + 50 + a. The problem states that the latter is 495 units larger than the original number. So, we can set up the following equation:

100c + 50 + a = (100a + 50 + c) + 495

Simplifying the equation gives us:

99c - 99a = 495

This simplifies to:

c - a = 5

Since 'a' and 'c' are digits, the only possibility is that a = 4 and c = 9. Therefore, the original number is 459.

Answer:

Yamal can move the ice to 82 km in approximately 15 hrs.

Step-by-step explanation:

Given:

Speed  = 5.5 km/hr

Distance = 82 km

Let time be represented as 'x'.

We need to find the number of hours required to travel 82 km.

We know that Distance can be calculated by the product of Speed and time.

Framing above sentence in equation form we get;

Distance = Speed × Time

Substituting the given value we get;

[tex]82 = 5.5x[/tex]

Hence The expression for number of hours is [tex]82 = 5.5x[/tex]

Solving the equation to find the value of x we get;

[tex]82 = 5.5x\\\\x=\frac{82}{5.5} = 14.90 \approx 15\ hrs[/tex]

Hence Yamal can move the ice to 82 km in approximately 15 hrs.

Answer:

The answer is: [tex]\frac{1}{8}[/tex]

Step-by-step explanation:

The sample space when tossing a coin three times is [HHH, HHT, HTH, HTT, THH, THT, TTH, TTT]  and the total number of occurrence is 8.

Getting Head on first toss, tail on second and third is: HTT and it occurs just once in our sample space.

Therefore, the probability of getting Head on first toss, tails on second and third tosses is: [tex]\frac{1}{8}[/tex]

Note probability = [tex]\frac{number of possible occurrence}{number of total occurrence}[/tex]

Answer:

[tex]z=\frac{0.21 -0.2}{\sqrt{\frac{0.2(1-0.2)}{400}}}=0.5[/tex]  

[tex]p_v =2*P(Z>0.5)=0.617[/tex]  

So the p value obtained was a very high value and using the significance level given [tex]\alpha=0.1[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the true proportion of defectives it's not significant different from 0.2.  

Step-by-step explanation:

1) Data given and notation

n=400 represent the random sample taken

X=84 represent the number of items defective

[tex]\hat p=\frac{84}{400}=0.21[/tex] estimated proportion of defectives

[tex]p_o=0.2[/tex] is the value that we want to test

[tex]\alpha=0.1[/tex] represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

[tex]p_v[/tex] represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.2 or 20%:  

Null hypothesis:[tex]p=0.2[/tex]  

Alternative hypothesis:[tex]p \neq 0.2[/tex]  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

The One-Sample Proportion Test is used to assess whether a population proportion [tex]\hat p[/tex] is significantly different from a hypothesized value [tex]p_o[/tex].

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

[tex]z=\frac{0.21 -0.2}{\sqrt{\frac{0.2(1-0.2)}{400}}}=0.5[/tex]  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided [tex]\alpha=0.1[/tex]. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

[tex]p_v =2*P(Z>0.5)=0.617[/tex]  

So the p value obtained was a very high value and using the significance level given [tex]\alpha=0.1[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the true proportion of defectives it's not significant different from 0.2.  

Answer:

The independent variable in the relationship is the Number of Months and should be placed on the x-axis .

The dependent variable in the relationship is the Number of Fish and should be placed on the y-axis .

Step-by-step explanation:

Independent variable is the variable that is being changed or controlled. It's the value that you would graph on the x-axis. Intuitively you would graph the months on the x-axis. I don't really know how to explain it other than that.

Dependent variable is the variable that is being measured. It's the value that is being graphed on the y-axis. You're measuring the amount of fish so that's your dependent variable.

Answer:

C

Step-by-step explanation:

since the camper gets old we will choose decay factor over the years and since t is in years in the explanation so t in the expression means years as well

The expression describes the initial value of the camper multiplied by its annual decay factor raised to the power of the number of years since purchase, corresponding to option C.

The expression 22,475(0.81)^t best describes the product of the initial value of the camper and its decay factor raised to the number of years since it was purchased. The correct choice that describes the expression is C. The initial value of the camper is given as $22,475. The factor 0.81 represents the annual depreciation rate, meaning that the camper loses 19% of its value each year (100% - 81% = 19% decay). The variable t stands for the number of years since the purchase. Therefore, each year, the value is multiplied by 0.81, repeatedly, to reflect the continuous decrease in value.

The 500th digit from 1 to 500 in a row will be;

A: 0 or 1

The double digit numbers are; 10 to 99 = 90 numbers × 2 = 180 digits

This is a total of 180 + 9 = 189 digits

Thus, after 99, we are looking for the;

500 - 189 digit = 311th digit

(100 + x)3 = 312

100 + x = 312/3

100 + x = 104

x = 104 - 100

x = 4

The 104th term after 99 is;

104 + 99 = 203

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As per the question, the 500th digit would be:

a). 0 or 1

To write,

Numbers from [tex]1 to 500[/tex]

The numbers containing 1 digit [tex]= 9[/tex] digits  (1 to 9)

The numbers containing 2 digits [tex]= 90[/tex] × [tex]2 = 180[/tex]   (from 10 to 99)

To find,

[tex]500th[/tex] digit

Remaining [tex]= 500 - (180 + 9)[/tex]

[tex]= 311th[/tex]

As we know, 311 can not be divided by 3, and therefore, we will look for the nearest number that is divisible by 3 i.e. 312

So, assuming the x as 100 + nth digit

[tex](100 + x)3 = 312[/tex]

[tex]100 + x = 312/3[/tex]

[tex]100 + x = 104[/tex]

[tex]x = 104 - 100[/tex]

∵[tex]x = 4[/tex]

Now,

[tex]100 + 4 = 104th digit[/tex]

∵ [tex]104 + 99 = 203[/tex]

Since the [tex]312th[/tex] term is employed rather than the [tex]311th[/tex], it implies that[tex]203 - 3 = 200[/tex]. Thus, 0 would be the [tex]500th[/tex] digit.

Thus, option a is the correct answer.

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Answer:

Step-by-step explanation:

a) Steps to prove that two triangles are similar are

1) AA(angle angle)if two angles of each triangle is congruent to two angles of another triangle, then the third angles of both triangles must be congruent since the sum of angles in the triangle is 180 degrees

2) SSS(side side side) if the three sides of both triangles are proportional to each other, then the triangles are similar.

3) SAS(side angle side) if two sides of a triangle are proportional to two sides of another triangle and and the angle formed by both lines in the two triangles are equal, then the third sides of both triangles are proportional. Therefore, the triangles are similar.

b) triangle ABC would be similar to triangle QRS if

1) angle A is congruent to angle Q and angle B is congruent to angle R

2)if the ratio of AB to QR is proportional to the ratio of AC to QS, and to BC to RS

3) if AC is proportional to QS, AB is proportional to QR and angle A = angle Q

c) AC/AB = QS/QR

60/50 = 6/QR

6/5 = 6/QR

6QR = 6×5 = 30

QR = 30/6 = 5 cm

Answer:

B) [tex]j=32m[/tex]

Step-by-step explanation:

Given:

Ayanna jumps at the rate of = 32 times/minute

To find the algebraic equation to express the function of the total number of time Ayanna jumped the rope.

Solution:

Let [tex]j[/tex] represent the total jumps made by Ayanna.

Let Ayanna jump for [tex]m[/tex] minutes.

Using unitary method to calculate total number of jumps made by Ayanna in [tex]m[/tex] minutes.

In 1 minute, Ayanna jumps = 32 times

Thus, in [tex]m[/tex] minutes Ayanna will jump = [tex]32\times m=32m[/tex] times

Thus, the function can be represented as;

[tex]j=32m[/tex]  (Answer)

Answer: b

Step-by-step explanation:

Answer:

Cannot give answer until Mile (x) is given

Step-by-step explanation:

The function that represents the number of math problems solved in a class is given by ????(x, y) = (15/7)* x / y, where x represents time and y represents the number of student questions. The constant of variation 'k' is 15/7.

Given that the number of math problems solved (????) in class is influenced by time duration (x) and the number of student questions (y), we can infer a relationship. We can define a constant of variation (k), which stands for the number of problems solved per time unit and per question. Based on the provided situation where 5 problems were solved in 6 minutes with 14 questions, we calculate k as k = ????(x/y) = 5(6/14) = 30/14 = 15/7.

Therefore, the function that represents this scenario is ????(x, y) = (15/7)* x / y, where x is the length of time and y is the number of student questions.

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Answer:

Step-by-step explanation:

You just need the distance formula here.  It's very simple to follow:

[tex]d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }[/tex]

which, for us, looks like this:

[tex]d=\sqrt{(13-4)^2+(19-7)^2}[/tex] and

[tex]d=\sqrt{9^2+12^2}[/tex] and

[tex]d=\sqrt{81+144}[/tex] and

[tex]d=\sqrt{225}[/tex] so

d = 15

[I'm still thinking sorry]

I'm assuming 2x-12 is the angle measure of DAC in degrees.

Let p=AB=AD, q=AC

By the Law of Cosines,

22² = p² + q² - 2pq cos 48°

q² - 2pq cos 48° + p² - 22² = 0

We also require by the triangle inequality

CD+AD < AC

16 + p < q

Let's set them equal and see where we are.

q=p+16

(p+16)² - 2p(p+16) cos 48° + p² - 22² = 0

p≈12.2125,

q≈28.2125

16² = p² + q² - 2 pq cos DAC

16² = 12.2125² + 28.2125² - 2 (12.2125)(28.2125) cos DAC

cos DAC = (12.2125² + 28.2125²  - 16²)/(2 (12.2125)(28.2125) ) = 1

That's a surprise, DAC maxes out at a right angle

90 = 2x - 12

102 = 2x

x = 51

Answer: 6 < x < 51

Answer: The bond has to go down.

Step-by-step explanation: A bond is a loan usually given by an issuer to an investor that pays back a fixed rate of return.

Although bonds have a fixed rate of return, bonds itself are not fixed which means when bond price can rise or fall. When bond rises, interest falls and when bond price falls, interest rises. A vice versa relationship.

What this means is that the investor has to pay more, take for example.

-If a bond of $100 has a return rate of 10%, this means investor will pay back $10.

-If bond price increases $120, investor will have to pay $12. Investor pays more

-However, if bond price decreases to $80, investor will pay $8. Investor pays less

Therefore, for an existing bond to compete with a new bond which has a higher interest rate, the existing bond price has to go down so that interest can go up.

Answer:

(x + 4) x 2

Step-by-step explanation:

x represents number of cookies Alice ate.

x + 4 represents the number of cookies Tim ate.

As Bob had eaten twice the number of cookies that Alice ate the expression should be

(x + 4) x 2

Answer:

-2L² + 50L − 300 ≥ 0

Step-by-step explanation:

View Image

Perimeter is the sum of all the sides. She got 50 feet of fence work with. So our equation right now is:

y + y + x + x = 50

However, she used her house for one of the side, so we can remove one of the side. Our new equation is now:

y + y + x = 50

Solve for one of the side. I solved for x because it's easier to work with and substitute later. I got x = 50 - 2y.

Now I solve for area. Area of a rectangle is Length * Width.

A = LW

I used x and y for my sides so my area is this instead:

A = yx

Substitute in x.

A = y(50 - 2y)

A = 50y - 2y²

Area must be a minimum of 300ft², so

50y - 2y² ≥ 300

50y - 2y² - 300 ≥ 0

replace y with L because that's what they used in the answer choice

-2L² + 50L − 300 ≥ 0

Answer:

-2l^2+50l-300 ≥ 0

l(50 − 2l) ≥ 300

(l − 15)(l − 10) ≤ 0

Step-by-step explanation: