Regroup to express the number in a different way , please help

Regroup To Express The Number In A Different Way , Please Help

Answers

Answer 1
25.3 = 1 ten + 15 ones + 3 tenths

hope it helps

Related Questions

Find the value of c, rounded to the nearest tenth. Please help me!!

Answers

When two secant lines intersect each other outside a circle, the products of their segments are equal.

14(с + 14) = 10(10 + 20)
14с + 196 = 10 * 30
14с +196 = 300
14с = 300 - 196
14с = 104
с = 104/14
с ≈ 7.4

Question 1(Multiple Choice Worth 5 points) (04.03 MC) Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet deep. What is the function that best represents the depth of the pond each week and how deep is the pond after 8 weeks? Round your answer to the nearest foot. Hint: Use the formula, f(x) = P(1 + r)x. f(x) = 10(0.03)x, 36 feet f(x) = 10(1.03)x, 14 feet f(x) = 10(1.3)x, 37 feet f(x) = 10(1.03)x, 13 feet

Answers

In this problem, you are to create an algrebraic formula to describe the progression of the depth of the pond with respect to time. In fact, you are already given with the general formula: f(x) = P(1 + r)x. All you have to do is find the value of P, r and x, to determine f(x) which stands for the depth.

I think P is the principal amount of depth. This is the base depth before the experiment has even started. Hence, P=10 feet. Then, r is the rate of change. Since it was mentioned that the depth increases by 3% each week, r = 3% or 0.03. Lastly, you want to find the depth after 8 weeks, so x=8. Therefore, the formula becomes:

f(x) = 10(1+0.03)*8 = 82.4

However, this is not one of the choices. There must be some typographical error. The equation must be f(x) = P(1+r)^x. Using this equation instead,

f(x) = 10(1+0.03)^8 = 13 ft 


Cuál es el número que agregado a 3 suma 8,hacer una ecuacion

Answers

x + 3 = 8
x = 8 - 3
x = 5 <=

Express the limit as a definite integral on the given interval. lim nââ n xi ln(1 + xi2) δx, [0, 3] i = 1

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I'm guessing the sum is

[tex]\displaystyle\lim_{n\to\infty}\sum_{i=1}^nx_i\ln(1+{x_i}^2)\Delta x[/tex]

Comparing to the definition of the definite integral, this limit quite clearly corresponds to the definite integral

[tex]\displaystyle\int_0^3x\ln(1+x^2)\,\mathrm dx[/tex]

Pensils are sold in packages of 10 and erasers are sold in packages of 6. What is the least number of pensils and erasers you can buy so that there is one pencil for each eraser with none left over.

Answers

To understand the problem consider the following cases.

i)

If we buy 1 packet of pencils, and 2 packet of erasers, 

we have 1*10=10 pencils and 2*6=12 erasers.

ii)

If we buy 3 packet of pencils, and 4 packet of erasers, 

we have 3*10=30 pencils and 4*6=24 erasers.


So let and b be the correct number of packets of pencils and erasers respectively.

That is the least numbers and b, such that 10a=6b.

10a=6b

divide both sides by 10:

[tex]a= \frac{6b}{10}= \frac{3b}{5}[/tex]

divide both sides by b:

[tex] \frac{a}{b} = \frac{3}{5} [/tex]

the ratio a:b cannot be simplified any further. This means that the smallest (natural) numbers a and b such that [tex] \frac{a}{b} = \frac{3}{5} [/tex] are a=3 and b=5


Answer:


3 packages of pencils, 5 packages of erasers.

What is 61 ones times 1/10? Choices are: 61 hundreths 61 tenths or 61 tens.

Answers

I believe 61 tenths

Answer: Second option is correct.

Step-by-step explanation:

Since we have given that

61 ones times [tex]\frac{1}{10}[/tex]

which will be equal to

[tex]61\times \frac{1}{10}\\\\=6.1[/tex]

So, 6.1 will read as six point one

and

after decimal it is read as tenths.

So, it becomes,

61 tenths.

Hence, Second option is correct.

If I had 6 yellow fish and 7 blue fish, how many times can I make a pair?

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You can only make 6 pairs of blue and yellow fish since the yellow fish is a limiting reagent since it has the fewer amount of fishes

Which is true?


A
5.4793 < 5.4812

B
5.2189 = 5.219

C
5.0359 > 5.0923

D
5.0167 < 5.0121


Answers

c because it makes the most sence
A is correct, while the other answers are not.

Given that lim x→1 (5x − 3) = 2, illustrate definition 2 by finding values of δ that correspond to ε = 0.1, ε = 0.05, and ε = 0.01.

Answers

[tex]\displaystyle\lim_{x\to1}(5x-3)=2[/tex]

is to say that for any [tex]\varepsilon>0[/tex], we can find [tex]\delta>0[/tex] such that [tex]0<|x-1|<\delta[/tex] implies [tex]|(5x-3)-2|<\varepsilon[/tex].

To that end, we have

[tex]|(5x-3)-2|=|5x-5|=5|x-1|<\varepsilon\implies|x-1|<\dfrac\varepsilon5=\delta[/tex]

which means that if [tex]\varepsilon=0.1[/tex] is given, then we can choose [tex]\delta=\dfrac{0.1}5=0.02[/tex]; if [tex]\varepsilon=0.05[/tex], then [tex]\delta=\dfrac{0.05}5=0.01[/tex]; if [tex]\varepsilon=0.01[/tex], then [tex]\delta=\dfrac{0.01}5=0.002[/tex].
Final answer:

To illustrate the definition of a limit, we need to find values of δ for different values of ε. We can solve inequalities involving the expression (5x − 3) - 2 to find suitable values of δ for ε = 0.1, ε = 0.05, and ε = 0.01.

Explanation:

Limits are an important concept in calculus. In this case, we are given that the limit as x approaches 1 of the expression (5x − 3) is 2. To illustrate the definition, we need to find values of δ that correspond to different values of ε. We can start by setting ε to 0.1 and then solve for δ.

When ε = 0.1, we want to find δ such that |(5x − 3) - 2| < 0.1 whenever 0 < |x - 1| < δ. We can solve this inequality by manipulating it and simplifying it to find a suitable value of δ. Similarly, we can find values of δ corresponding to ε = 0.05 and ε = 0.01 by solving the inequalities |(5x − 3) - 2| < 0.05 and |(5x − 3) - 2| < 0.01, respectively.

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Find the polar coordinates of the points with cartesian coordinates (−x, y).

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The relationship to go from Cartesian coordinates to polar coordinates is given by the following equations:

x = r * cos(theta)
y = r * sin(theta)

Since the coordinates we are given are just variables that can take any value, we'll have to work with that. Thankfully, that means we can just plug in these equations to get polar coordinates!

(-x, y) becomes
(-(r * cos(theta)), r * sin(theta))

Prove that if x is irrational, then 1/x is irrational

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Proof by contradiction.

Let assume that when [tex]x[/tex] is an irrational number, then [tex]\dfrac{1}{x}[/tex] is a rational number.

If [tex]\dfrac{1}{x}[/tex] is a rational number, then it can be expressed as a fraction [tex]\dfrac{a}{b}[/tex] where [tex]a,b\in\mathbb{Z}[/tex].

[tex]\dfrac{1}{x}=\dfrac{a}{b} \Rightarrow x=\dfrac{b}{a}[/tex]

Since [tex]a,b\in\mathbb{Z}[/tex], the number [tex]x=\dfrac{b}{a}[/tex] is also a rational number. But this contardicts our initial assumption that [tex]x[/tex] is an irrational number. Therefore [tex]\dfrac{1}{x}[/tex] must be an irrational number.

Below are grades in a course and how many students earned each grade:
5 students earned an A,
8 students earned a B,
10 students earned a C,
3 students earned a D
and 2 students earned a F.

What percent passed the course with a C or better? (Round your answer to one decimal place.)

Answers

Final answer:

The percentage of students who passed the class with a C or better is 82.1%. This is found by adding the number of students who earned A, B, or C grades, dividing by the total number of students, and multiplying by 100.

Explanation:

The subject is Mathematics, specifically a problem in percentages. First, we need to find the total number of students in the class. We add the number of students that earned each grade: 5 (A) + 8 (B) + 10 (C) + 3 (D) + 2 (F) = 28 students in total.  

Next, we need to identify the number of students who passed the class with a C or better. This includes the students who earned an A, B, or C. Adding these numbers together gets us 5 (A) + 8 (B) + 10 (C) = 23 students.  

Then, to find the percentage of students who passed the class, we divide the number of students who passed (23) by the total number of students (28) and then multiply by 100 to convert the result to a percentage. So the calculation is as follows: (23/28)*100 = 82.14. Rounded to one decimal place, that is 82.1%. Therefore, 82.1% of students passed the class with a grade of C or better.

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The percent of students who passed the course with a C or better is: 82.14%

To find the percent of students who passed the course with a C or better, we need to divide the number of students who passed by the total number of students and multiply by 100%.

The number of students who passed is 5 + 8 + 10 = 23.

The total number of students is 5 + 8 + 10 + 3 + 2 = 28.

Therefore, the percent of students who passed the course with a C or better is:

(23 / 28) * 100% = 82.14%

Rounding to one decimal place, the answer is 82.1%.

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If Sue wants to plant a triangular garden that has a perimeter of 45 feet, and her neighbor Jill wants to create a congruent triangular garden, then what would the perimeter be for Jill’s garden?

45 feet
90 feet
22.5 feet
None of the choices are correct.

Answers

Jill's garden would have a perimeter of 45 feet since congruent shapes have the same dimensions.

What is the algebraic rule for a figure that is rotated 270 degrees clockwise

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The algebraic rule for rotating a point [tex]\( 270^\circ \)[/tex] clockwise about the origin is:

[tex]\[ (x, y) \rightarrow (y, -x) \][/tex]

Rotations in the coordinate plane can be performed using rotation matrices or by following specific rules based on the degree of rotation and the direction (clockwise or counterclockwise). For a rotation of [tex]\( 270^\circ \) or \( -90^\circ \) (since \( 270^\circ \)[/tex]  clockwise is equivalent to [tex]\( -90^\circ \)[/tex] counterclockwise), the rule can be derived as follows:

1.Starting Point:Consider a point [tex]\( (x, y) \)[/tex] in the coordinate plane.

2. 90° Rotation Counterclockwise (or 270° Clockwise):

  When you rotate a point [tex]\( 90^\circ \)[/tex] counterclockwise about the origin, the new position is [tex]\( (-y, x) \)[/tex].

3. 80° Rotation (second 90° Counterclockwise):**

  If you rotate [tex]\( (-y, x) \)[/tex] another [tex]\( 90^\circ \)[/tex] counterclockwise (making a total of 180°), the new position is [tex]\( (-x, -y) \)[/tex].

4.270° Rotation (third 90° Counterclockwise or 90° Clockwise):

Finally, rotating [tex]\( (-x, -y) \)[/tex] another [tex]\( 90^\circ \)[/tex] counterclockwise (or the original point [tex]\( (x, y) \) \( 90^\circ \)[/tex] clockwise), the new position is [tex]\( (y, -x) \).[/tex]

Therefore, the algebraic rule for rotating a point [tex]\( 270^\circ \)[/tex] clockwise about the origin is:

[tex]\[ (x, y) \rightarrow (y, -x) \][/tex]

This rule effectively swaps the x and y coordinates and negates the new x-coordinate, which corresponds to a [tex]\( 270^\circ \)[/tex] clockwise rotation.

The length of a rectangle is 5 cm longer than twice the length of the width. If the perimeter of the rectangle is 88 centimeters, what is the width?

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L= 31 feet
W= 13 feet

G prove that limx→∞(x 2 + 1)/x2 = 1 using the definition of limit at ∞.

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[tex]\displaystyle\lim_{x\to\infty}\frac{x^2+1}{x^2}=1[/tex]

means to say there is some number [tex]M[/tex] for which any choice of [tex]\varepsilon>0[/tex] such that

[tex]x>M\implies\left|\dfrac{x^2+1}{x^2}-1\right|<\varepsilon[/tex]

Working backwards, we have

[tex]\left|\dfrac{x^2+1}{x^2}-1\right|=\left|1+\dfrac1{x^2}-1\right|=\dfrac1{x^2}<\varepsilon[/tex]
[tex]\implies\sqrt{\dfrac1{x^2}}<\sqrt\varepsilon\implies\dfrac1{\sqrt\varepsilon}<|x|[/tex]

So, whenever [tex]x>M=\dfrac1{\sqrt\varepsilon}[/tex], we can always guarantee that [tex]\left|\dfrac{x^2+1}{x^2}-1\right|<\varepsilon[/tex].

circle with a radius of 4.5 cm? Round your answer to the nearest tenth. Use 3.14 for mc018-2.jpg.

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The Answer is 7.1 centimeters

complete this statement 45ax^2+27 ax+18a=9a

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Final answer:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 45, b = 27, and c = 18. By substituting these values into the quadratic formula, we find that the equation has no real solutions.

Explanation:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 45, b = 27, and c = 18. To complete the statement, we need to find the values of x for which the equation is satisfied:

45ax² + 27ax + 18a = 9a

Simplifying the equation:

45ax² + 27ax + 18a - 9a = 0

45ax² + 27ax + 9a = 0

Dividing the equation by 9a:

5ax² + 3ax + 1 = 0

Now, we have a quadratic equation that we can solve using the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values of a = 5, b = 3, and c = 1 into the formula:

x = (-3 ± √(3² - 4(5)(1))) / (2(5))

x = (-3 ± √(9 - 20)) / (10)

x = (-3 ± √(-11)) / (10)

Since the discriminant (b² - 4ac) is negative, the equation has no real solutions. Therefore, the statement cannot be completed with real values of x.

Is 3+9=12 9+3=12 a sentence for commutative property of addition

Answers

yes, it is.

The commutative property means the numbers can " commute ", they can move.....3 + 9 = 12 : 9 + 3 = 12....does not matter the order of the numbers, they still equal the same

A sample of 20 observations has a standard deviation of 4. the sum of the squared deviations from the sample mean is:

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Answer: 304.

Step-by-step explanation:

The formula to calculate the sample standard deviation is given by :-

[tex]s=\sqrt{\dfrac{\sum(x-\overline{x})^2}{n-1}}[/tex]

, where x = sample element.

[tex]\overline{x}[/tex] = Sample mean

s=sample standard deviation.

n= Number of observations.

[tex]\sum(x-\overline{x})^2[/tex] = sum of the squared deviations from the sample mean

As per given , we have

s=4

n= 20

Substitute theses values in the above formula , we get

[tex]4=\sqrt{\dfrac{\sum(x-\overline{x})^2}{20-1}}[/tex]

[tex]4=\sqrt{\dfrac{\sum(x-\overline{x})^2}{19}}[/tex]

Square root on both sides , we get

[tex]\Righatrrow\ 16=\dfrac{\sum(x-\overline{x})^2}{19}\\\\\Righatrrow\ \sum(x-\overline{x})^2=16\times19=304[/tex]

Hence, the sum of the squared deviations from the sample mean is 304.

Sum of squared deviations: [tex]\( 16 \times (20 - 1) = 304 \),[/tex]  given a standard deviation of 4 and sample size of 20.

To find the sum of the squared deviations from the sample mean, we'll use the formula for variance. Since the standard deviation is the square root of the variance, we'll square the standard deviation to get the variance. Then, we'll multiply by the sample size minus 1 to get the sum of the squared deviations.

Given:

Standard deviation (σ) = 4

Sample size (n) = 20

First, let's find the variance:

[tex]\[ \text{Variance} = \sigma^2 = 4^2 = 16 \][/tex]

Now, we'll use the formula for the sum of squared deviations:

[tex]\[ \text{Sum of squared deviations} = \text{Variance} \times (n - 1) \]\[ \text{Sum of squared deviations} = 16 \times (20 - 1) \]\[ \text{Sum of squared deviations} = 16 \times 19 = 304 \][/tex]

So, the sum of the squared deviations from the sample mean is 304.

Lateisha shaw deposits $12000 for 8 years in an account paying 5% compounded quarterly. She then leaves the money alone, with no further deposits, at 6% compounded annually for an additional 6 years. Approximate the total amount on deposit after the entire 14-year period.

Answers

The formula is
A=p (1+r/k)^kt
A future value?
P present value 12000
R interest rate
T time
K compounding periods

The future value of 8 years in an account paying 5% compounded quarterly
A=12,000×(1+0.05÷4)^(4×8)
A=17,857.566103137 use it as a present value for the second period

at 6% compounded annually for an additional 6 years.
A=17,857.566103137×(1+0.06)^(6)
A=25,331.30....answer


what is this equation 41 > 6m - 7

Answers

Think of the greater than sign as an equals sign. Then, you solve for m

If gasoline costs
2.50
2.50 euros per​ liter, it will cost ​$

how much
to drive
220 kilometers

Answers

We have 2.50 euro = ​$ 2.91;
220 x 2.50 = 550 euros or 220 x 2.91 =$ 640.20;

Brainliest to whoever is correct 30pts...!!!!!!!!!

Answers

angle between 16 and 18 = 90 + 55 = 145°

[tex]d= \sqrt{16^2+18^2-2*16*18*cos(145^o)}= \\ \\ \sqrt{256+324+471.83}= \sqrt{1051.83} \approx 32[/tex]

Answer: y=(yx−16x)x+16

Step-by-step explanation:

You have two exponential functions. One has the formula h(x) = 2 x + 3. The other function, g(x), has the graph shown below.
PICK:
g(2) = h(2) = 7g(7) = h(7) = 2g(2) > h(2)g(2) < h(2)

Answers

To answer, we substitute each of the numbers in parentheses to x of h(x) and get the value of g(x).

A. h(2) = 2(2) + 3 = 7  ;   g(2) < 4               (neither is equal to 7)

B. h(7) = 2(7) + 3 = 17;    g(7) is not shown in the graph          (not true)

C. h(2) = 7   ; g(2) < 4   Thus, g(2) < h(2)   (choice is not true)

D. From C, g(2) < h(2)   (TRUE)

Thus, the answer to this item is letter D. 

Answer:

answer is C.g(2)>h(2)

Step-by-step explanation:

What is the probability of rolling a sum of 12 on a standard pair of six-sided dice? express your answer as a fraction or a decimal number rounded to?

Answers

Answer:

1/36

Step-by-step explanation:

Each dice can take 6 values and if we roll two dices the values are independent from each another. All the possible combinations are 6 × 6 = 36.

There is only one way of rolling a sum of 12, which is that each dice takes the value 6.

The probability of rolling a sum of 12 is:

[tex]P(12)=\frac{favorable\ cases }{possible\ cases} =\frac{1}{36}[/tex]

The probability of rolling a sum of 12 on two six-sided dice is [tex]\( \frac{1}{36} \) or approximately 0.028.[/tex]

To find the probability of rolling a sum of 12 on a standard pair of six-sided dice, we first need to determine the number of favorable outcomes (rolling a sum of 12) and the total number of possible outcomes when rolling two six-sided dice.

Step 1 :

**Total Number of Possible Outcomes**:

  When rolling two six-sided dice, each die has 6 faces, so the total number of possible outcomes is [tex]\(6 \times 6 = 36\)[/tex].

Step 2 :

**Number of Favorable Outcomes**:

  To get a sum of 12, we need one die to show a 6 and the other die to show a 6 as well. There is only one way to get each die to show a 6.

Step 3 :

**Probability**:

  Probability is the ratio of favorable outcomes to total outcomes.

  [tex]\[ \text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \][/tex]

  [tex]\[ \text{Probability} = \frac{1}{36} \][/tex]

So, the probability of rolling a sum of 12 on a standard pair of six-sided dice is [tex]\( \frac{1}{36} \)[/tex].

This can also be expressed as a decimal rounded to three decimal places: [tex]\[ \text{Probability} \approx 0.028 \][/tex]

Hannah wants to rewrite 18+12 using the greatest common factor and the distributive property. Which expression should she write?

1. 6(3+2)
2. 6(18)+6(12)
3. 3(18+2)
4. 6(3+12)

Answers

your answer would be a because 6 times 3 is 18 and 6 times 2 is 12 all your doing is distributing the 6 into 3 and 2 meaning multiplying

The expression for 18+12 is  6(3+2)

What is Expression?

A mathematical operation such as subtraction, addition, multiplication, or division is used to combine terms into an expression. In a mathematical expression, the following terms are used:

An absolute numerical number is referred to as a constant.Variable: A symbol without a set value is referred to as a variable.Term: A term can be made up of a single constant, a single variable, or a mix of variables and constants multiplied or divided.Coefficient: In an expression, a coefficient is a number that is multiplied by a variable.

Given:

18+12

Now, prime factorize

18 = 2 x 3 x 3

12= 2 x 2 x 3

So,  18+12 = 2 x 3 x 3 + 2 x 2 x 3

= 2 x 3( 3 + 2)

=6 (3+ 2)

Hence, the expression is 6 (3+ 2).

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Eliminate the parameter t to find a cartesian equation for x=t^2 y=2+10t

Answers

hello :
[tex] \left \{ {{x= t^{2} }...(1) \atop {y=2+ 10t }...(2)} \right. [/tex]
by(1) : 
[tex]t = \frac{y-2}{10} [/tex]
subsct in (2) : 
 [tex]x = ( \frac{y-2}{10} )^{2} [/tex]....(cartesian equation )

To eliminate the parameter t in the equations x=t^2 and y=2+10t, solve [tex]t = \sqrt(x)[/tex] and substitute into the second equation to get [tex]y = 2 + 10\sqrt(x)[/tex]. This results in the cartesian equation [tex]y = 2 + 10\sqrt(x).[/tex]

To eliminate the parameter t and find the cartesian equation, follow these steps:

Start with the given parametric equations: x=t^2 and y=2+10t

Solve the first equation for t:

[tex]t = \sqrt(x)[/tex]

Substitute this expression for t into the second equation:

[tex]y = 2 + 10(\sqrt(x))[/tex]

Thus, the cartesian equation is [tex]y = 2 + 10 \sqrt(x).[/tex]

.   A medical plan requires a patient to pay a $25.00 copay plus 20% of all charges incurred for a medical procedure. If the average bill for a patient is between $200 and $800, find the range of the original bill

Answers

Patient's payment = $25.00 + 20% * charges

Final payment = $200 => $ 200 = $25  +  0.2 * charges

=> charges = [$200- $ 25 ] / 0.2 = $875.

Final payment = $800 => $800 = $25 + 0.2 * charges

=> harges = [$800 - $25] / 0.2 = $3875

=> The range of the original bill is [$875, $3875]

Choose if the following function is even, odd or neither. f(x) = x^3

Answers

its neither but i will go with odd
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