Resistance is a measure of how well a material conducts an electric charge. Would you expect to find a high or low, level of resistance in a copper wire and why

Answers

Answer 1
Resistance is a measure of how a material conducts an electric charge. It is a quantity that measures how well a material would reduce the current that flow through it. So, for a copper wire, you would expect it to have a low resistance since it conducts electric charge very well. It is known to be a good conductor. It has a high electrical conductivity and low resistance.

Related Questions

Investigators are most likely to use the case history method when they study

Answers

Investigators are most likely to use the case history method when they study a rare behavior or an unusual person.
They do this to obtain some sort of basis that they could use as a pointer to make their decision regarding the similar case (after figuring out the difference in situation between each period)

The famous leaning tower of pisa doesn't topple over because its center of gravity is

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Vertical line from the centre of mass is inside the base of the tower.

A cyclist does work at the rate of 500 w while riding. how much force does her foot push with when she is traveling at 8.0 m/s?

Answers

P=F*V
F=P/V
F=500W/8=62.5N

Answer:

The foot push of the cyclist exerted a force of 63 Newton.

Explanation:

Given data

Power (P): 500 WattVelocity (v): 8.0 m/sForce (F): ?

We can find the force exerted by the foot push of the cyclist using the following expression.

P = F × v

v = P/F = 500 W/ (8.0 m/s) = 63 N

The foot push of the cyclist exerted a force of 63 Newton.

Which transmits the most light?

A. Tinted glass

B. Opaque glass

C. Clear glass

D. All types transmit light equally

Answers

That would be Clear glass because tinted glass is made to have less light travel through it and opaque glass is not able to be seen through.

How many ohms of resistance are in a 120–volt hair dryer that draws 7.6 amps of current?

A. 16 ohms
B. 910 ohms
C. 0.063 ohms
D. 6,900 ohms

Answers

Resistance = Volt/Amps

R = 120/7.6=15.789 Ohm ~ 16 ohm.

So, (A) is the answer

The concept Ohm's law is used here to determine the resistance. The resistance is found to be 16 ohm .The correct option is A.

What is Ohm's law?

The relationship between the electric current and the potential difference is given by the Ohm's law. The current which flows through the conductors is directly proportional to the voltage applied. Mathematically the relationship is given as:

V = IR

V - Potential difference

R - Resistance

I - Current

R = V / I

R = 120 / 7.6

R = 15.7 ohm ≈ 16 ohm

The ohm's law holds true if the provided temperature and the other physical factors remain constant. In certain components, increasing the current raises the temperature. In this case Ohm's law is violated.

It is the Ohm's law which maintains the desired voltage drop across the electronic components. It helps to determine the voltage, resistance or current of an electric circuit.

Thus the correct option is A.

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A certain string on a piano is tuned to produce middle c (f = 261.63 hz) by carefully adjusting the tension in the string. for a fixed wavelength, what is the frequency when this tension is tripled?

Answers

The final frequency is 453.16 Hz when the tension is tripled.

We know that:

f = v / λ

Where,

f = frequency   of sound wave.

v= speed of sound wave

λ = wavelength of sound wave

So, for a fixed wavelength ( let it be λ), frequency is directly proportional to velocity of the sound wave.

Again for a certain tension T, velocity of sound wave in a string is given by, v = √(T/μ) where, μ is mass per unit length of the string.

So, when this tension is tripled; velocity of sound wave becomes √3 times of its initial value and as frequency is directly proportional to the velocity,  final frequency becomes = √3 × initial frequency

= √3 × 261.63 Hz. ( as given in the question, initial frequency = 261.63 Hz)

= 453.16 Hz.

Hence,  when this tension is tripled, the frequency will be 453.16 Hz.

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If three devices are plugged into one port on a switch and two devices are plugged into a different port, how many collision domains are on the switch?

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Collision domain is a portion in the network where there is a possibility of formation of packets. This occurs when two or more devices are able to send a packet to a single switch or port on the network that is shared, on the same time. It was noted that this collision domain reduces the efficiency of the network. 

For this item, the first packet is the whole switch with the three devices. Next one would be first of the three devices that is connected to the other port. Similarly, the third one would be the second of the three devices that is also connected to the switch. Therefore, the answer is 3. 

What conditions are required for a solar eclipse?

Answers

The phase of the Moon must be new, and the nodes of the Moon's orbit must be nearly aligned with Earth and the Sun.
Final answer:

A solar eclipse occurs when the Moon blocks the Sun from the Earth's viewpoint during a New Moon phase. The Moon also needs to be crossing the line of nodes, the intersection of the Earth's and Moon's orbit plain.

Explanation:

A solar eclipse occurs when the Moon moves between the Sun and the Earth, casting a shadow on the Earth. This event happens only during a New Moonphase, which is one of the conditions needed. Not all New Moon phases result in a solar eclipse because the Moon's orbit is tilted relative to the Earth's orbit around the Sun. Therefore, for a solar eclipse to take place, the Moon must be in the New Moon phase, and it must also be at a position in its orbit where it crosses the plane of the Earth's orbit around the Sun. This place is known as the line of nodes.

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Koi is climbing through a crevice and places her feet so that her body is perpendicular as shown below she then rest in this spot for twenty minutes

Answers

the type of force that Koi is demonstrating in this position would be: static friction
static friction is a type of force that created when a stationary object is placed on the surface where it's resting. It also defined the amount of force you need to overcome before you could move the object

Answer:

static friction

Explanation:

she's not moving so she has static friction

What number does a bit that is turned on represent? what number does a bit that is turned off represent?

Answers

In digital electronics, only two numbers are used to represent the state of the bit. These two numbers are "0" and "1" where:

- The bit that is turned on is represented by the number "1" 
- The bit that is turned off is represented by the number "0" 

The _________ specifies the station that sent the frame.

Answers

Ans: The source Address field specifies the station that sends the frame. 

The format of an Ethernet frame includes a destination address at the beginning which contains the address of the device which is sending the frame. And, the source address tells us which station the information is received from. 

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, how far would it have fallen (in m) after 2 s? (g = 10 m/s2) 20.0

Answers

t=2s
g=10m/s2
h=?
free fall: h=gt2/2
              h= 10*4/2
               h=40/2
              h=20m








Neglecting air resistance, the rock would have fallen a distance of 20 meters after 2 seconds, calculated using the formula d = gt²/2 with g as the acceleration due to gravity (10 m/s²).

If you drop a rock from a tall building neglecting air resistance, the distance it has fallen after 2 seconds can be calculated using the formula for the distance fallen under constant acceleration, which is d = gt²/2, where g is the acceleration due to gravity (approximately 10 m/s²) and t is the time in seconds the object has been falling.

Plugging in the values, we get:

d = 10 m/s² × (2 s)² / 2 = 20 m

Therefore, the rock would have fallen 20 meters after 2 seconds.

If the atomic radius of lead is 0.175 nm, calculate the volume of its unit cell in cubic meters.

Answers

Before any calculations, we need to determine first the crystal structure of the lead metal. From literature, the lead metal assumes an FCC structure. So, it would have 4 atoms per units cell where the three atoms is the sum of all the portion of an atoms in each face of the cell and the 1 atom is the sum of all the portion of the corner atoms. The volume of the unit cell is equal to the edge length raise to the power three or V = a^3. The edge length can be calculated from the radius of the atoms by the pythagorean theorem. We do as follows:

V = a^3
   a^2 + a^2 = (4r)^2
  2a^2 = (4r)^2
    a = 2r
V = (2r)^3
V = 16r^3
V = 16 (0.175x10^-9)^3
V = 1.21 x 10^-28 m^3
Final answer:

The volume of a unit cell of lead, which is a face-centered cubic, can be determined by calculating the edge length of the cell using its atomic radius and then cubing the edge length. The volume of a lead unit cell with an atomic radius of 0.175 nm is 1.205 * 10^-29 m^3.

Explanation:

To calculate the volume of a unit cell of lead, we need to understand that lead crystalizes in a face-centered cubic lattice, where the edge length of the unit cell equals the square root of 2 times the atomic radius, doubled (since the diameter is 2 times the radius). So we first calculate the edge length, a = 2 * atomic radius * sqrt(2), and then calculate the volume of the unit cell, which is a cubic volume, V = a^3.

Given the atomic radius of lead is 0.175 nm or 0.175 * 10^-9 meters, we calculate:

Edge length, a = 2 * 0.175 * 10^-9 meters * sqrt(2) = 0.494 * 10^-9 meters.

The volume V = (0.494 * 10^-9 meters)^3 = 0.1205 * 10^-27 m^3 or 1.205 * 10^-29 m^3.

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If you observe an angular unconformity, you could infer that the region had experienced ________.

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old pain thats reacting until now

The point of origin of an epileptic seizure is called the ____.â

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The point of origin of an epileptic seizure is called the focus. It is the part of the brain that is affected by epilepsy. This is a term used for people with partial epilepsy. The focus can be the frontal lobe, occipital lobe, mesial temporal lobe or the parietal lobe. During seizures, it is the that specific part of the brain that is being effected.  Seizures happen when a surge in the electrical activities happen on certain parts. Symptoms are contractions of the muscles, blackouts and visual disturbances. Seizures can be cured and, for partial epilepsy, they are treated with AEDs or antiepileptic drugs.

___ cables are continually being improved to increase speed. the fastest cables under development today use multiple cores and/or multiple wavelengths to transmit data as fast as 255 tbps.

Answers

Fiber Optic Cables are continually being improved to increase speed. the fastest cables under development today use multiple cores and/or multiple wavelengths to transmit data as fast as 255 tbps.
A fiber optic cable consists of a bundle of glass threads, each of which is capable of transmitting messages modulated onto light waves. it is a technology used to transmit data. 

Different units used to describe average velocity can be changed from one to another by the use of

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Average velocity can be calculated by determining the total displacement divided by the total time of travel. The average velocity of an object does not tell us anything about what happens to it between the starting point and ending point. Average velocity is different from average speed because it considers the direction of travel and the overall change in position.

Although the class has no water, the students want to know if the cube will float or sink in water. Explain, in detail, the steps that must be taken to determine if the cube will float or sink. Be sure to use the following key terms: triple beam balance, metric ruler ,and density.

Answers

Okay, so the density of water is 1g/cm3. In order for the cube to float, it has to be less than 1, and it will sink if it is more than 1 g/cm3. Use a triple beam balance to weigh the cube, looking at the metric ruler on the balance. Then, if the cube's density is more than 1, then you know it will float. If the density is less than 1, you know it will sink.
hope this helps, and I didn't know how to use the word "metric ruler"

Imagine that you're standing in a large room when a loud noise is made. You begin hearing a series of echoes. Which characteristic of sound best explains what just happened?

Answers

The characteristic of sound that would best explain the series of echoes you are hearing would be reverberation. It is created when a sound wave is being reflected to the surfaces causing it to have a many reflection building up and decaying as these waves are being absorbed bu the surfaces in the area which could be tables, chairs, people or the air. Reverberation is the group of the reflected sounds in an enclosed area. 

Imagine that you're standing in a large room when a loud noise is made. You begin hearing a series of echoes. The characteristic of sound that best explains what just happened is: Reverberation.

You stand by the railroad tracks as a train passes by. you hear a 1 000-hz frequency when the train approaches, which changes to 800 hz as it goes away. how fast is the train moving? the speed of sound in air is 340 m/s.

Answers

This is a concrete example of the Doppler effect. This effect is the change of frequency experienced by the listener or the observer with respect to their relative distance to the source of the sound. There can be two equations to be applied: to the approaching source, and to the receding source.

Approaching source:
frequency observed = [v/(v-v,source)]*frequency of source, where v is the velocity of sound . Substituting,
1000 =  [340/(340-v,source)]*frequency of source  <---- equation 1

Receding source:
frequency observed = [v/(v+v,source)]*frequency of source, where v is the velocity of sound . Substituting,
800 =  [340/(340+v,source)]*frequency of source  <---- equation 2

Rearranging equation 1: [1000(340-v,source)]/340 = frequency of source
Equation 2: 800 = [340/(340+v,source)]*frequency of source

Substituting equation 1 to equation 2:
800 = [340/(340+v,source)]*[1000(340-v,source)]/340 

Solving using the scientific calculator under shift-solve feature,
v,source = 37.78 m/s

Therefore, the train is moving at 37.78 m/s.



Answer:

[tex]v_s= 37.8 m/s[/tex]

Explanation:

As per Doppler's effect when source and observer moves relative to each other then the frequency of the sound observed is different from the real frequency

When source is moving towards the stationary observer then we have

[tex]f_1 = f_o(\frac{v}{v - v_s})[/tex]

now when source of sound moving away from stationary observer then we have

[tex]f_2 = f_o(\frac{v}{v + v_s}[/tex]

now from above two equations

[tex]\frac{f_1}{f_2} = \frac{v + v_s}{v - v_s}[/tex]

here we know that

[tex]f_1 = 1000 hz[/tex]

[tex]f_2 = 800 hz[/tex]

v = 340 m/s

now we have

[tex]\frac{1000}{800} = \frac{340 + v_s}{340 - v_s}[/tex]

[tex]5(340 - v_s) = 4(340 + v_s)[/tex]

[tex]340 = 9 v_s[/tex]

[tex]v_s = 37.8 m/s[/tex]

Which expression is equivalent to 3m+1-m

Answers

2m+1

You would simplify the expression by subtracting the 3m by the m.

Answer:

Th equivalent of [tex]3m+1-m[/tex] is [tex]2m+1[/tex]

Explanation:

We need to write the equivalent expression of [tex]3m+1-m[/tex]

first, combine the like terms,

[tex]3m-m+1[/tex]

take out the common variable,

[tex](3-1)m+1[/tex]

[tex]2m+1[/tex]

Therefore, the equivalent of [tex]3m+1-m[/tex] is [tex]2m+1[/tex]

When you measure the current and voltage in a ac circuit with a multimeter, is your result the peak value or the rms value?

Answers

Ac voltmeters and ammeters usually give rms readings.

In general, the rate of evaporation increases with ___________. in general, the rate of evaporation increases with ___________. decreasing intermolecular forces decreasing volatility decreasing temperature decreasing surface area

Answers

In general, the rate of evaporation of liquid increases with increase in temperature and increases with increase in surface area of the liquid exposed to air. The rate of evaporation decreases with increasing of the intermolecular forces. The bigger intermolecular forces , the harder the molecules can escape from the liquid and become gas.

A howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 4.6 km. assume the acoustic output of a howler to be uniform in all directions and that the threshold of hearing is 1.0 × 10-12 w/m2. what is the acoustic power emitted by the howler?

Answers

The acoustic power of a specific sound is determine by multiplying the square of the distance and the threshold of hearing. We have to convert the distance first from kilometers to meters.

              distance = (4.6 km) x (1000 meters/ 1 km) = 4600 meters

Performing the required operation,

               Acoustic power = (1.0 x 10^-12 W/m²)(4600 m)²
                Acoustic power = 2.116 x 10^-5 W

Thus, the acoustic power is approximately 2.12 x 10^-5 W. 

The ____ button on the rehearsal toolbar clears the slide time box and resets the timer to 0:00:00.

Answers

The Rehearsal toolbar is used in Microsoft Power Point. It has buttons that allow the user to start, pause and repeat viewing the slides in the slide show. The buttons are: next, pause recording, slide time, repeat and elapsed time. The slide time button on the rehearsal toolbar clears the slide time box and resets the timer to 0:00:00.

Find the number of certifications held by people grouped by planet. this should have two columns the first, "name" will be the names of planets that have at least one certification. the second column should be "certcount" an

Answers

The tables are the following:

 

CREATE TABLE `bsg_cert` (

  `id` int(11) NOT NULL AUTO_INCREMENT,

  `title` varchar(255) NOT NULL,

  PRIMARY KEY (`id`)

) ENGINE=InnoDB

 

CREATE TABLE `bsg_cert_people` (

  `cid` int(11) NOT NULL DEFAULT '0',

  `pid` int(11) NOT NULL DEFAULT '0',

  PRIMARY KEY (`cid`,`pid`),

  KEY `pid` (`pid`),

  CONSTRAINT `bsg_cert_people_ibfk_1` FOREIGN KEY (`cid`) REFERENCES `bsg_cert` (`id`),

  CONSTRAINT `bsg_cert_people_ibfk_2` FOREIGN KEY (`pid`) REFERENCES `bsg_people` (`id`)

) ENGINE=InnoDB

 

CREATE TABLE `bsg_people` (

  `id` int(11) NOT NULL AUTO_INCREMENT,

  `fname` varchar(255) NOT NULL,

  `lname` varchar(255) DEFAULT NULL,

  `homeworld` int(11) DEFAULT NULL,

  `age` int(11) DEFAULT NULL,

  PRIMARY KEY (`id`),

  KEY `homeworld` (`homeworld`),

  CONSTRAINT `bsg_people_ibfk_1` FOREIGN KEY (`homeworld`) REFERENCES `bsg_planets` (`id`) ON DELETE SET NULL ON UPDATE CASCADE

) ENGINE=InnoDB

 

CREATE TABLE `bsg_planets` (

  `id` int(11) NOT NULL AUTO_INCREMENT,

  `name` varchar(255) NOT NULL,

  `population` bigint(20) DEFAULT NULL,

  `language` varchar(255) DEFAULT NULL,

  `capital` varchar(255) DEFAULT NULL,

  PRIMARY KEY (`id`),

  UNIQUE KEY `name` (`name`)

) ENGINE=InnoDB

 

 

Joining them all up doing a count with a group by should do the trick:

SELECT  planet.name ,

    COUNT(*) AS cert_count

FROM    bsg_cert_people people_cert

    JOIN bsg_people people ON people.id = people_cert.pid

    JOIN bsg_planet planet ON people.homeworld = planet.id

GROUP BY planet.name

 

Or we can also use this syntax to get the same result:

SELECT pl.name, count(cert) AS "CertCount"

FROM bsg_planets pl

JOIN bsg_people pe ON pl.id = pe.homeworld

JOIN bsg_cert_people cp ON cp.pid = pe.id

GROUP BY pl.id

Calculate the work energy, w, gained or lost by the system when a gas expands from 15 l to 35 l against a constant external pressure of 1.5 atm

Answers

The work done by the gas is about 30 L.atm

[tex]\texttt{ }[/tex]

Further explanation

The Ideal Gas Law and Work formula that needs to be recalled is:

[tex]\boxed {PV = nRT}[/tex]

[tex]\boxed { W = P \Delta V }[/tex]

where:

W = Work ( J )

P = Pressure ( Pa )

V = Volume ( m³ )

n = number of moles ( moles )

R = Gas Constant ( 8.314 J/mol K )

T = Absolute Temperature ( K )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial volume = Vo = 15 L

final volume = V = 35 L

constant pressure = P = 1.5 atm

Asked:

word done by the gas = W = ?

Solution:

[tex]W = P \Delta V[/tex]

[tex]W = P \times ( V - Vo )[/tex]

[tex]W = 1.5 \times ( 35 - 15 )[/tex]

[tex]W = 1.5 \times 20[/tex]

[tex]W = 30 \texttt{ L.atm }[/tex]

[tex]\texttt{ }[/tex]

Conclusion:

The work done by the gas is about 30 L.atm

[tex]\texttt{ }[/tex]

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[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

The work energy, w, gained or lost by the system when the gas expands is 30 Joules.

Given the following data:

Pressure = 1.5 atmInitial volume = 15 litersFinal volume = 35 liters

To find the work energy, w, gained or lost by the system when the gas expands:

Mathematically, the work energy by a system is given by the formula:

[tex]Work = P \delta V[/tex]

Where:

P is the pressure.V is the volume.

Substituting the given parameters into the formula, we have;

[tex]Work\;energy = 1.5(35-15)\\\\Work\;energy = 1.5(20)[/tex]

Work energy = 30 Joules.

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the length of a pipe will weigh the most when

Answers

When fluid is flowing through the pipe. 

Why?

No fluid results in the following:

Sum forces in y-direction: sum F = ma, W_pipe + W_fluid = ma, however if there was no fluid it be W_pipe = ma. 

The rotating nozzle sprays a large circular area and turns with the constant angular rate theta overscript dot endscripts = 2.2 rad/s. particles of water move along the tube at the constant rate l overscript dot endscripts = 1.8 m/s relative to the tube. find the magnitudes of the velocity v and acceleration a of a water particle p when the distance l = 0.85 m if the angle beta = 64°.

Answers

Final answer:

The magnitude of the velocity of the water particle is approximately 2.6 m/s, and the magnitude of the acceleration of the water particle is approximately 7.5 m/s^2.

Explanation:

The magnitudes of the velocity v and acceleration a of a water particle can be calculated using the concepts of angular velocity, and the relationships between linear and angular motion.

The velocity of the water particle v has two components: a tangential component due to the rotation (equal to the angular velocity times the distance from the center of rotation), and a radial component due to the flow of water along the tube.

The tangential velocity Vt = ωr, where r = 0.85 m is the distance of the water particle from the center of rotation and ω = 2.2 rad/s is the angular velocity. Substituting these values we find that Vt = 2.2 rad/s * 0.85 m = 1.87 m/s. The radial velocity Vr = l_dot = 1.8 m/s is given in the problem.

The total velocity is obtained by combining the radial and tangential velocities. Its magnitude is given by v = sqrt(Vr^2 + Vt^2). Substituting the known values, we find that the magnitude of the velocity v of the water particle is approximately 2.6 m/s.

The acceleration of the particle also has two components: a radial component equal to the square of the tangential velocity divided by the radius, and a tangential component equal to the product of the angular velocity and the radial velocity. Therefore, the magnitude of the acceleration a is given by a = sqrt((Vt^2 / r)^2 + (ωVr)^2), which gives us a value of approximately 7.5 m/s^2.

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The magnitude of the velocity [tex]v[/tex] of the water particle is approximately 2.6 m/s. The magnitude of the acceleration [tex]a[/tex] of the water particle is 4.114 m/s².

Velocity due to rotation (tangential velocity):

The tangential velocity [tex]v_{tangential}[/tex] is given by

[tex]v_{tangential} = l \cdot \dot{\theta}[/tex]

Substituting the values:

[tex]v_{tangential} = 0.85 \text{ m} \cdot 2.2 \text{ rad/s} = 1.87 \text{ m/s}[/tex]

Velocity along the tube:

The velocity along the tube [tex]v_{tube}[/tex] is given by [tex]\dot{l}[/tex], which is already provided as 1.8 m/s.

Resultant velocity:

The total velocity of the particle [tex]v[/tex] is the vector sum of the tangential and tube velocities. Since the angle [tex]\beta[/tex] between these two components is given, we can use the Pythagorean theorem:

[tex]v = \sqrt{( v_{tangential} )^2 + ( v_{tube} )^2}[/tex]

Substituting the values:

[tex]v = \sqrt{(1.87 \text{ m/s})^2 + (1.8 \text{ m/s})^2} \approx 2.6 \text{ m/s}[/tex]

Acceleration

Centripetal acceleration:

The centripetal (radial) acceleration [tex]a_c[/tex] is given by:

[tex]a_c = l \cdot \dot{\theta}^2[/tex]

Substituting the values:

[tex]a_c = 0.85 \text{ m} \cdot (2.2 \text{ rad/s})^2 = 4.114 \text{ m/s}^2[/tex]

Tangential acceleration:

The tangential acceleration [tex]a_t[/tex] will be zero because the angular velocity is constant (no angular acceleration).

Total acceleration:

The total acceleration [tex]a[/tex] is due to the centripetal acceleration alone, as there is no tangential component. Hence:

[tex]a = a_c = 4.114 \text{ m/s}^2[/tex]

how does bare soil surface type affect the amount of runoff?

Answers

The bare soil surface affects runoff because it has no nutrients or real resistants. Run-off rate increases because there is nothing there to absorb the rain water. A porous surface type will absorb a little runoff. A non-porous surface will not absorb much at all. It increases it since there is less plant material to slow down the water.
 Run-off rate increases because there is nothing there to absorb the rain water. If the bare soil is comprised of porous-type, then it can absorb a little runoff. But if the soil is non-porous surface, then it will not absorb much at all. 
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