Answer:
the last one is linear
the throwing a baseball in the air is quadratic
half life of a pesticide is exponential
thats all i know
Step-by-step explanation:
HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing. Check all that apply.
Answer:
A, B, and D.
Step-by-step explanation:
The absolute value function is V shaped, goes through the origin, and never dips below the x axis, meaning that it is in the 1st and 2nd quadrants. The left side resembles a line with slope -1, which means that choice C is incorrect. Hope this helps!
A grocery store has an average sales of $8000 per day. The store introduced several advertising campaigns in order to increase sales. To determine whether or not the advertising campaigns have been effective in increasing sales, a sample of 64 days of sales was selected. It was found that the average was $8300 per day. From past information, it is known that the standard deviation of the population is $1200. The p-value is a. .9772. b. .5475. c. 2.000. d. .0228.
Answer:
Step-by-step explanation:
Given data
Average sales = 8000
n = 64
standard deviation = 1200
8300
The solution is attached in the picture below
6 - 8x = 22 whats the answer?
Answer:
x = -2
Step-by-step explanation:
subtract the 6 from 22
then divide -8x and 16 by -8
then you get your anser
The solution to the equation 6 - 8x = 22 is x = -2. The equation was solved by rearranging and isolating 'x', and then dividing by the coefficient -8.
Explanation:The question is a simple linear equation. Let's solve it step by step:
First, let's rearrange 6 - 8x = 22 to find the value of 'x'. We can do this by subtracting 6 from both sides, which gives us -8x = 22 - 6.So, -8x = 16.Next, we solve for 'x' by dividing both sides of the equation by -8. This gives us x = 16 / -8.x = -2 is the solution to the equation 6 - 8x = 22.Learn more about Solving linear equationshttps://brainly.com/question/2030026
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A company produces fruit juice in 10 different flavors. a local supermarket sells the product, but has only sufficient shelf space to display 3 of the company's 10 fruit juice flavors at a time. How many possible combinations of 3 flavors can the fruit juice company display on the local supermarket shelf?
Answer:
120.
Step-by-step explanation:
This is the number of combinations of 3 from 10.
This = 10C3
= 10! / 3! (10-3)!
= 10*9*8 / 3*2*1
= 120 combinations.
Answer:
120
Step-by-step explanation:
One study on managers’ satisfaction with management tools reveals that 58% of all managers use self-directed work teams as a management tool. Suppose 70 managers selected randomly in the United States are interviewed. What is the probability that fewer than 35 use self-directed work teams as a management tool?
Answer:
6.94% probability that fewer than 35 use self-directed work teams as a management tool
Step-by-step explanation:
I am going to use the normal approximation to the binomial to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].
In this problem, we have that:
[tex]n = 70, p = 0.58[/tex]
So
[tex]\mu = E(X) = np = 70*0.58 = 40.6[/tex]
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.58*0.42} = 4.13[/tex]
What is the probability that fewer than 35 use self-directed work teams as a management tool?
Using continuity correction, this is P(X < 35 - 0.5) = P(X < 34.5), which is the pvalue of Z when X = 34.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{34.5 - 40.6}{4.13}[/tex]
[tex]Z = -1.48[/tex]
[tex]Z = -1.48[/tex] has a pvalue of 0.0694.
6.94% probability that fewer than 35 use self-directed work teams as a management tool
The question requires calculation of binomial probability. Given that the rate of success is 58% (or 0.58) and we're trying to find the likelihood of fewer than 35 successes out of 70 trials, one must sum the binomial probabilities from k=0 to 34.
Explanation:This problem is about calculation of binomial probability, which is a specific type of probability that deals with experiments that have two possible outcomes: success (in this case, using self-directed work teams) or failure (not using self-directed work teams). Given that the rate of success is 58% (or 0.58 as a decimal), and we're looking for the probability of fewer than 35 successes out of 70 trials (or managers), we can solve using the formula for binomial probability.
The basic form of the binomial formula is: [tex]P(X=k) = C(n, k) * (p^k) * ((1-p)^{(n-k)})[/tex], where n is the number of trials, k is the number of successful trials, p is the probability of success, and C(n, k) is a combination which calculates the number of possible combinations of n items taken k at a time.
To find P(X<35), we sum from k=0 to 34. Thus, this involves a fair amount of calculation, and you may want to use software or a calculator that has binomial probability functionality.
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What is the area of the wall that will be painted
Answer:
B. 104
Step-by-step explanation:
Just find the area of the wall and subtract the area of the window. The area of the wall is 10 times 11 which is 110. The area of the window is 2 times 3 which is 6. 110 minus 6 is 104.
Can anyone pls help me to solve question 2 f and g and pls provide me a explanation I’m with that questions for three days
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
__
f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
__
g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
Harry is trying to solve the equation y = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps below. Find the step where Harry went wrong. (1 point)
Step 1: x equals the negative of negative 1 plus or minus the square root of the quantity negative one squared minus 4 times 2 times negative six, end quantity, all over 2 times 2.
Step 2: x equals the negative of negative 1 plus or minus the square root of negative one plus forty-eight all over two times 2.
Step 3: x equals the negative of negative 1 plus or minus the square root of forty-seven all over two times 2.
Step 4: x equals 1 plus or minus the square root of forty-seven all over 4.
Answer:
Step 2
Step-by-step explanation:
The quadratic formula is given by [tex]x=-b+-\frac{\sqrt{b^{2}-4ac } }{2a}[/tex]
Our equation is y = 2x²-x-6
So here our a = 2, b = -1, and c = -6
We can now plug these numbers into our formula
[tex]x= -(-1) +-\frac{\sqrt{(-1)^{2}-4(2)(-6) } }{2(2)} = 1 +-\frac{\sqrt{1+24} }{4} = 1+-\frac{\sqrt{25} }{4}[/tex]
Step 2 is incorrect because it states that "x equals the negative of negative 1 plus or minus the square root of negative one plus forty-eight all over two times 2."
The correct statement would be "x equals the negative of negative 1 plus or minus the square root of positive one plus forty-eight all over two times 2.", because the square of a negative is positive, resulting in a positive one.
Since this step is incorrect, the steps after are also incorrect, but Harry went wrong at Step 2
Answer:
The above answer is correct.
Step-by-step explanation:
I got it right on the test
Nana Akosua Owusu – Ansah, a financial manageress for a company is considering two competing investment proposals. For each of these proposals, she has carried out an analysis in which she has determined various net profit figures and has assigned subjective probabilities to the realization of these returns. For proposal A, her analysis shows net profits of GHȼ 20,000.00, GHȼ 30,000.00 or GHȼ 50,000.00 with respective probabilities 0.2, 0.4 and 0.4. For proposal B, she concludes that there is a 50% chance of successful investment, estimated as producing net profits of GHȼ 100,000.00, and of an unsuccessful investment, estimated as a break – even situation involving GHȼ 0.00 of net profit. Assuming that each proposal requires the same Ghana cedi investment, which of the two proposals is preferable solely from the standpoint of expected monetary return?
Answer:
Proposal B
Step-by-step explanation:
This problem can be solved by comparing the expected returns on both options.
The expected return is the sum of the possible outcomes multiplied by its probabilities of occurrence.
For proposal A, the net profits are $20,000, $30,000 and $50,000, with respective probabilities 0.2, 0.4 and 0.4. Then, the expected return can be calculated as:
[tex]E(A)=\sum_{i=1}^3p_iR_i\\\\E(A)=p_1R_1+p_2R_2+p_3R_3\\\\E(A)=0.2*20,000+0.4*30,000+0.4*50,000\\\\E(A)=4,000+12,000+20,000\\\\E(A)=36,000[/tex]
The proposal A has a expected net profit of $36,000.
The proposal B has a 50% chance of having a net profit of $100,000 and a 50% of break even (zero net profit). We applied the same calculation for the expected profit and we have:
[tex]E(B)=\sum_{i=1}^2p_iR_i\\\\E(B)=p_1R_1+p_2R_2\\\\E(B)=0.5*100,000+0.5*0\\\\E(B)=50,000[/tex]
The proposal B has a expected net profit of $50,000.
Assuming that each proposal requires the same investment, the proposal B has more expected monetary return (GHȼ 50,000) than proposal A (GHȼ 36,000).
The head of institutional research at a university believed that the mean age of full-time students was declining. In 1995, the mean age of a full-time student was known to be 27.4 years. After looking at the enrollment records of all 4934 full-time students in the current semester, he found that the mean age was 27.1 years, with a standard deviation of 7.3 years. He conducted a hypothesis of Upper H 0: muequals27.4 years versus Upper H 1: muless than27.4 years and obtained a P-value of 0.0020. He concluded that the mean age of full-time students did decline. Is there anything wrong with his research?
Answer:
[tex]t=\frac{27.1-27.4}{\frac{7.3}{\sqrt{4934}}}=-2.887[/tex]
The degrees of freedom are given by:
[tex] df= n-1 = 4934-1= 4933[/tex]
Then the p value for this case calculated as:
[tex]p_v =P(t_{4933}<-2.887) =0.002[/tex]
Since the p value is a very lower value using any significance level for example 1% or 5% we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significanctly less than 27.4. So then is not anything wrong with the conclusion
Step-by-step explanation:
Information provided
[tex]\bar X=27.1[/tex] represent the sample mean
[tex]s=7.3[/tex] represent the sample standard deviation
[tex]n=4934[/tex] sample size
[tex]\mu_o =27.4[/tex] represent the value to test
t would represent the statistic
[tex]p_v[/tex] represent the p value
System of hypothesis
We want to verify if the mean age of full-time students did decline (less than 27.4), the system of hypothesis would be:
Null hypothesis:[tex]\mu \geq 27.4[/tex]
Alternative hypothesis:[tex]\mu < 27.4[/tex]
The statistic for this case is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
Replacing the info we got:
[tex]t=\frac{27.1-27.4}{\frac{7.3}{\sqrt{4934}}}=-2.887[/tex]
The degrees of freedom are given by:
[tex] df= n-1 = 4934-1= 4933[/tex]
Then the p value for this case calculated as:
[tex]p_v =P(t_{4933}<-2.887) =0.002[/tex]
Since the p value is a very lower value using any significance level for example 1% or 5% we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significanctly less than 27.4. So then is not anything wrong with the conclusion
A marble is selected at random from a jar containing 4 red marbles, 2 yellow marbles, and 3 green marbles.
Home
What is the probability that the marble is red?
Answer:
4 / 9 probability of getting a red
Step-by-step explanation:
How many marbles are there total?
4 red + 2 yellow + 3 green = 9 marbles total
P( red marble) = 4 red / 9 total = 4/9
Answer:
Step-by-step explanation:
Red marbles- 4
Yellow marbles-2
Green marbles-3
Total marbles=9
Probability= 4/9
=0.4444
The combined math and verbal scores for students taking a national standardized examination for college admission, is normally distributed with a mean of 820 and a standard deviation of 200. If a college requires a student to be in the top 15 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college calculator
Answer: 1007.28
Step-by-step explanation:
Given : The combined math and verbal scores for students taking a national standardized examination for college admission, is normally distributed with
[tex]\mu=820\ \ \ ,\ \sigma=200[/tex]
If a college requires a student to be in the top 15 % of students taking this test, it means that they want the students that score 85 percentile or above.
Let X be the scores of any random student, we require
[tex]P(X<x)=0.85[/tex], where x is minimum score that such a student can obtain and still qualify for admission at the college.
Formula for z-score = [tex]z=\frac{x-\mu}{\sigma}=\frac{x-820}{200}[/tex] ...(i)
From normal z-value table , [tex]P(z<1.036)=0.85[/tex]...(ii)
From (i) and (ii) , we get
[tex]\frac{x-820}{200}=1.0364\\\\\Rightarrow\ x-820=207.28\\\\\Rightarrow\ x=207.28+820=1007.28[/tex]
Hence, the minimum score that such a student can obtain and still qualify for admission at the college is 1007.28.
a new play premieres on saturday, october 1, and 420 people attend. attendance then decreases by 30% each day. find the attendance on tuesday , october 4
Answer:
The attendance on tuesday, october 4, is of 144 people.
Step-by-step explanation:
The attendance after t days is given by the following equation:
[tex]A(t) = A(0)(1-r)^{t}[/tex]
In which A(0) is the attendance on the first day and r is the daily decrease rate.
Premieres on saturday, october 1, and 420 people attend.
This means that [tex]A(0) = 420[/tex]
Attendance then decreases by 30% each day.
This means that [tex]r = 0.3[/tex]
So
[tex]A(t) = A(0)(1-r)^{t}[/tex]
[tex]A(t) = 420(1-0.3)^{t}[/tex]
[tex]A(t) = 420(0.7)^{t}[/tex]
Find the attendance on tuesday , october 4
This is 4-1 = 3 days after saturday. So this is A(3).
[tex]A(3) = 420(0.7)^{3} = 144[/tex]
The attendance on tuesday, october 4, is of 144 people.
To find the attendance on Tuesday, October 4, after a 30% daily decrease from an initial attendance of 420 people on Saturday, October 1, we calculate the exponential decay for three days to get approximately 144 attendees.
The student's question involves an exponential decay math problem where the attendance of a play decreases by a percentage each day. To calculate the attendance on Tuesday, October 4, we begin with the initial attendance of 420 people on Saturday, October 1. We then apply a 30% decrease for each subsequent day:
Sunday, October 2: 420 - (0.30 × 420) = 294 peopleMonday, October 3: 294 - (0.30 × 294) = 205.8 peopleTuesday, October 4: 205.8 - (0.30 × 205.8) = approximately 144.06 peopleSince we cannot have a fraction of a person attending, we would generally round to the nearest whole number, which means about 144 people attended the play on Tuesday, October 4.
Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an unabraded (U) condition and an abraded (A) condition. Use the paired t test to test: H0: μD = 0 versus Ha: μD > 0 at significance level 0.01. (Use μD = μU-A.) Note: The data below is formatted such that you can copy and paste it into R. Fabric 1 2 3 4 5 6 7 8 U = c( 36.3, 55.0, 51.1, 38.8, 43.2, 48.8, 25.6, 49.5) A = c( 28.5, 20.0, 46.0, 34.5, 36.5, 52.5, 26.5, 46.5) Calculate the mean difference and standard deviation. d = sd = Compute the test statistic value. (Round your answer to three decimal places.) t = p-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions. Reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions. Fail to reject H0. The data suggests a significant mean difference in breaking load for the two fabric load conditions. Reject H0. The data suggests a significant mean difference in breaking load for the two fabric load conditions.
Rejection region(s)
t > 2.998
Test statistic value
t = 2.89
Fail to reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions. Option B is the right choice.
State the hypotheses
H0: μD = 0
Ha: μD > 0
State the rejection region
Since the alternative hypothesis is one-sided, we use a one-tailed test. The rejection region for a one-tailed t-test with significance level 0.01 and 7 degrees of freedom is:
t > 2.998
Compute the test statistic
The test statistic for a paired t-test is calculated as follows:
t = ([tex]\bar x[/tex]D - μD) / (sdD / √n)
where:
[tex]\bar x[/tex]Dis the mean difference between the unabraded and abraded breaking loads
sdD is the standard deviation of the difference between the unabraded and abraded breaking loads
n is the sample size
Calculating the mean difference:
[tex]\bar x[/tex]D = (36.3 - 28.5) + (55.0 - 20.0) + (51.2 - 46.0) + (38.6 - 34.0) + (43.2 - 36.5) + (48.8 - 52.5) + (25.6 - 26.5) + (49.6 - 46.5) = 6.85
Calculating the standard deviation of the difference:
sdD = √[((36.3 - 28.5)^2 + (55.0 - 20.0)^2 + (51.2 - 46.0)^2 + (38.6 - 34.0)^2 + (43.2 - 36.5)^2 + (48.8 - 52.5)^2 + (25.6 - 26.5)^2 + (49.6 - 46.5)^2) / 7] = 10.87
Calculating the test statistic:
t = (6.85 - 0) / (10.87 / √8) = 2.89
Make a decision
Since the test statistic (2.89) is less than the critical value (2.998), we fail to reject the null hypothesis.
The correct choice is option d. Fail to reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
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Question:-
Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an unabraded condition and an abraded condition. Use the paired t test to test H0: ?D = 0 versus Ha: ?D > 0 at significance level 0.01. (Use ?D = ?U ? ?A.)
State the rejection region(s). (If the critical region is one-sided, enter NONE for the unused region. Round your answers to three decimal places.)
t ? _______
t ? ________
Compute the test statistic value. (Round your answer to three decimal places.)
t = _____
State the conclusion in the problem context.
a.Reject H0. The data suggests a significant mean difference in breaking load for the two fabric load conditions.Fail to b.reject H0. The data suggests a significant mean difference in breaking load for the two fabric load conditions. c.Reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
d.Fail to reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions
f(x) = x4 - 50x2 + 3 (a) Find the intervals on which f is increasing. (Enter the interval that contains smaller numbers first.) ( , ) ∪ ( , ) Find the intervals on which f is decreasing. (Enter the interval that contains smaller numbers first.) ( , ) ∪ ( , ) (b) Find the local minimum and maximum values of f. (min) (max) (c) Find the inflection points. ( , ) (smaller x value) ( , ) (larger x value) Find the intervals on which f is concave up. (Enter the interval that contains smaller numbers first.) ( , ) ∪ ( , ) Find the interval on which f is concave down. ( ,
Answer:
(-5, 0) ∪ (5, ∞)
Step-by-step explanation:
I find a graph convenient for this purpose. (See below)
__
When you want to find where a function is increasing or decreasing, you want to look at the sign of the derivative. Here, the derivative is ...
f'(x) = 4x^3 -100x = 4x(x^2 -25) = 4x(x +5)(x -5)
This has zeros at x=-5, x=0, and x=5. The sign of the derivative will be positive when 0 or 2 factors have negative signs. The signs change at the zeros. So, the intervals of f' having a positive sign are (-5, 0) and (5, ∞).
The details provided do not correspond to a coherent mathematics problem regarding the function [tex]f(x) = x^4 - 50x^2 + 3[/tex]. Therefore, an accurate response cannot be provided without further information or correct context.
Explanation:To address the question about the function [tex]f(x) = x^4 - 50x^2 + 3[/tex], we need to analyze its intervals of increase and decrease, as well as find any local extrema and points of concavity. However, the question as posed does not provide enough context or coherent detail for the actions requested, such as finding the inflection points or intervals of concavity, since no specific function was clearly defined. Instead, various unrelated Mathematics problems are listed, each of which is missing comprehensive details needed to provide an accurate answer.
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Adrian earns $16000 per month. He spends 1/4 of his income on food; 3/10 of the remainder on house rent . How much money does he have left?
Answer:
8000
Step-by-step explanation:
1/4 of 16000 is 4000
16000-4000=12000 1/3 of 12000 is also 4000
12000-4000=8000
One kitty weighs 2 pounds 4 ounces. Another kitten weighs 2 ounces less. What is the combined weight of the two kittens in ounces
The combined weight of the two kittens is 70 ounces.
To find the combined weight of the two kittens, we'll start by converting the weight of the first kitten to ounces.
1 pound is equal to 16 ounces, so 2 pounds is equal to 2 x 16 = 32 ounces.
Therefore, the first kitten weighs 32 + 4 = 36 ounces.
The weight of the second kitten is 2 ounces less, so we subtract 2 from the weight of the first kitten: 36 - 2 = 34 ounces.
Finally, we can find the combined weight by adding the weights of the two kittens together: 36 + 34 = 70 ounces.
Therefore, the combined weight of the two kittens is 70 ounces.
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Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the night shift than on the day shift. A sample of 60 day-shift workers showed that the mean number of units produced was 334, with a population standard deviation of 23. A sample of 68 night-shift workers showed that the mean number of units produced was 341, with a population standard deviation of 28 units.At the .10 significance level, is the number of units produced on the night shift larger?1. This is a (Click to select)twoone-tailed test.2. The decision rule is to reject H0: μd ≥ μn if z < . (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)3. The test statistic is z = . (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)4. What is your decision regarding H0?
Answer:
Step-by-step explanation:
Let the subscripts d and n represent day and night respectively
The null hypothesis is
H0 : μd ≥ μn
The alternative hypothesis is
H1 : μd < μn
it is a one-tailed and also a right left test because of the greater than symbol in the alternative hypothesis.
The decision rule is to reject H0: μd ≥ μn If 0.10 > p value
Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)
z = (xd - xn)/√σd²/nd + σn²/nn
Where
xd and xn represents sample means for day and night respectively.
σd and σn represents population standard deviations for day and night respectively.
nd and nn represents number of samples
From the information given,
xd = 334
xn = 341
σd = 23
σ2 = 28
nd = 60
nn = 68
z = (334 - 341)/√23²/60 + 28²/68
= - 7/√20.34607843138
z = - 1.55
From the normal distribution table, the probability value corresponding to the z score is 0.061
Since the level of significance, 0.1 > 0.061, we would reject H0
Therefore, there is enough evidence to conclude that there are more units produced on the night shift than on the day shift.
Final answer:
Clark Heter is conducting a one-tailed test to compare the mean production of day and night shifts. The decision to reject the null hypothesis that day shift production is greater or equal to night shift production is based on a critical value of -1.28 linked to a significance level of 0.10. The test statistic is computed from the given means and standard deviations for both samples.
Explanation:
Conducting a Two-Sample Z-Test
Clark Heter wants to determine if more units are produced on the night shift than on the day shift. Given the samples:
- Day-shift (n=60): mean = 334, population standard deviation = 23.
- Night-shift (n=68): mean = 341, population standard deviation = 28.
The significance level is 0.10.
Let A= | 1 1 1,1 4 5, 1 5 6 | and D= | 7 0 0 ,0 4 0, 0 0 2 | .
Compute AD and DA.
Explain how the columns or rows of A change when A is multiplied by D on the right or on the 1 5 6 0 0 2 left.
Find a 3x3 matrix B, not the identity matrix or zero matrix, such that AB -BA.
Compute AD AD- Compute DA. DA Explain how the columns or rows of A change when A is multiplied by D on the right or on the left.
Choose the correct answer below
A. Right multiplication that is, multiplication on the right by the diagonal matrix D multiplies each row of A by the corresponding diagonal entry of D
B. Both right multiplication that is, multiplication on the right and left multiplication by the diagonal matrix D multiplies each row entry of A by the 0
C. Both right multiplication that is, multiplication on the right and left multiplication by the diagonal matrix D multiplies each column entry of A by the ?
D. Right multiplication that is, multiplication on the right by the diagonal matrix D multiplies each column of A by the corresponding diagonal entry of D Left-multiplication by D multiplies each column of A by the corresponding diagonal entry of D corresponding diagonal entry of D corresponding diagonal entry of D Left-multiplication by D multiplies each row of A by the corresponding diagonal entry of D Find a 3x3 matrix B, not the identity matrix or zero matrix, such that AB BA. Choose the correct answer below There is only one unique solution. B= ?
A. Simplitfy your answers.)
B. There are infinitely many solutions. Any multiple of 13 will satisfy the expression °
C. There does not exist a matrix, B, that will satisfy the expression
Answer:
Check the explanation
Step-by-step explanation:
Kindly check the attached images below to see the step by step explanation to the question above.
After performing the calculations, the right matrix multiplication by D changes each column of A and the left matrix multiplication by D changes each row of A. Also, there are an infinite number of 3x3 matrices that satisfy the condition AB ≠ BA
Explanation:To compute the products AD and DA, we first need to understand how matrix multiplication works. Given matrices A and D as presented, it is important to understand that when A is multiplied by D on the right side (AD), each column of A is multiplied by the corresponding diagonal entry of D. Conversely, when A is multiplied by D on the left side (DA), each row of A is multiplied by the corresponding diagonal entry of D. This is true for any two matrices you want to multiply. Therefore, the correct answer to the first part of the question is statement D.
For the second part of the question, we're seeking a non-identity, non-zero 3x3 matrix B such that AB is not equal to BA. This is generally quite difficult and requires some trial and error. There are an infinite number of matrices B that satisfy the condition AB ≠ BA. The exact form of B depends on A and can be quite complex, but B isn't necessarily unique. Therefore, the correct answer to this question is B: There are infinitely many solutions.
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An experiment consists of randomly selecting a marble from a bag, replacing it, and then selecting another marble. The bag contains 3 yellow marbles and 2 white marbles? What is the probability of selecting a white marble and then a yellow marble?
Answer:
6/25 probability
Step-by-step explanation:
We have 5 marbles total, 3 + 2 = 5
Find P( white marble, yellow marble with replacement)
= P(white, yellow) = (2/5)*(3/5) = 6 / 25
What is the equation of the following graph?
Enter our answer
help me please !!
A circular dining room table can seat 11 people. Each person has about 2 feet of space along the edge of the table. What is the radius of the table, rounded to the nearest half-foot?
Answer:bruh
Step-by-step explana
The radius of the table, rounded to the nearest half-foot, is 3.5 feet.
To determine the radius of the circular dining room table, we can use the formula for the circumference of a circle, which is:
C = 2 π r
where:
C - circumference
r - radius
Given that each person has about 2 feet of space along the edge of the table, the circumference of the table must be able to accommodate the seating for 11 people. Each person occupies 2 feet of space, so the total space needed around the edge of the table is:
11 × 2 = 22 feet
We can set up an equation using the circumference formula:
C = 2 π r = 22
To find the radius (r), we divide both sides of the equation by 2π:
r = [tex]\frac{22}{2 \pi}[/tex]
Now, let's calculate the value:
r = [tex]\frac{22}{2 \pi}[/tex] = [tex]\frac{22}{2 \times 3.14}[/tex] = [tex]\frac{22}{6.28}[/tex] = 3.503
Rounding to the nearest half-foot, we get:
r = 3.5 feet
Find the solution for system of equations
2x-3y=2 x=6y-5
Answer and how to do it
Answer:
[tex] (x - 9)^2 + y^2 = 36 [/tex]
Step-by-step explanation:
The equation of a circle in standard form is
[tex](x - h)^2 + (y - k)^2 = r^2[/tex]
You are given
[tex] x^2 + y^2 - 18x + 45 = 0 [/tex]
In order to put the equation in standard from, we need to complete the square. Since there is no y term, the y part is simply y^2, and there is no need to complete the square for y. For x, we do have an x term, so we must complete the square in x.
Start by grouping the x terms and subtracting 45 from both sides.
[tex] x^2 - 18x + y^2 = -45 [/tex]
Now we need to complete the square for x.
[tex] x^2 - 18x ~~~~~~+ y^2 = -45 [/tex]
The number that completes the square will go in the blank above, and it will also be added to the right side of the equation.
To find the number you need to add to complete the square, take the coefficient of the x term. It is -18. Divide it by 2. You get -9. Now square -9 to get 81. The number that completes the square in x is 81. Now you add it to both sides of the equation.
[tex] x^2 - 18x + 81 + y^2 = -45 + 81 [/tex]
[tex] (x - 9)^2 + y^2 = 36 [/tex]
Answer: [tex] (x - 9)^2 + y^2 = 36 [/tex]
At the post office, Tiffany paid, $11.04. for 2 stamps. At this rate, how much would it cost for Tiffany yo buy 18 stamps?
Answer: $$$99.36
Step-by-step explanation:
It's 11.04 for 2 stamps
U have to buy 18 stamps
18÷2=9
9×11.04=99.36
Answer:
It costs $5.52 to Sam to buy 12 stamps.now multiply
Step-by-step explanation:
Square M N O P is shown. Angle M is (4 t + 20) degrees and angle N is (7 f + 6) degrees.
MNOP is a square. What are the values of t and f?
t =
f =
Answer:
t = 17.5°
f = 12°
Step-by-step explanation:
MNOP is a square and the angle M is (4t + 20)° and the angle N is (7f + 6)°. The value of t and f can be calculated below.
A square is a quadrilateral and all the sides are equal. Opposite sides are parallel to each other . Each angle of a square is equal to 90°.
Since ∠M = 4t + 20
This means ∠M
4t + 20 = 90
4t = 90 - 20
4t = 70
t = 70/4
t = 17.5°
∠N = 7 f + 6
7 f + 6 = 90
7f = 90 -6
7f = 84
f = 84/7
f = 12°
Answer:
t=17.5
f=12
Step-by-step explanation:
Apply the Pythagorean Theorem to find the distance between points A and B. A) 6 units B) 18 units C) 27 units D) 81 units
Answer:
A: 6 Units
Step-by-step explanation:
simplify the expression below. (-3x2 + 2x - 4) + (4x2 + 5x +9)
Answer: =x2+7x+5
Step-by-step explanation:
−3x2+2x−4+4x2+5x+9
=−3x2+2x+−4+4x2+5x+9
Combine Like Terms:
=−3x2+2x+−4+4x2+5x+9
=(−3x2+4x2)+(2x+5x)+(−4+9)
=x2+7x+5
Answer:
=x2+7x+5
Answer:
x^2+7x+5
Step-by-step explanation:
Remove parentheses: -3x^2+2x-4+4x^2+5x+9
Group like terms: -3x^2+4x^2+2x+5x-4+9
Add similar elements: x^2+2x+5x-4+9
Add/subtract the numbers: x^2+7x+5
Question 1 (1 point)
in a local raffle, first prize is $100, second prize is $75, third prize is $50 and fourth prize is $25. If 15 people enter the raffle, how many ways
can 4 be selected to win the prizes?
There are 32,760 ways to select 4 winners from 15 participants in a local raffle where the order of prizes matters according to permutation.
Explanation:To find out how many ways 4 winners can be selected from 15 participants in a local raffle with given prizes, we can use the concept of permutation because the order in which the prizes are awarded matters (i.e., the prizes are not identical).
The total number of different ways to select 4 winners from 15 participants is represented by the permutation of 15 things taken 4 at a time (since the order of selection matters for different prizes).
The formula for permutation is: P(n, k) = n! / (n-k)! where n is the total number of items, k is the number of items to choose, and '!' represents a factorial.
For this problem, we calculate P(15, 4):
Therefore, there are 32,760 ways to select 4 winners from 15 participants.
a scientist counted 11 crows to every 3 hawks. if this data holds true, how many hawks would he expect to see if there were 363 crows?
Answer:
99
Step-by-step explanation:
11 crows : 3 hawks
363 crows: X hawks
X/363 = 3/11
X = 363 × 3/11
X = 99