Solve 16 1/2 ÷ 2 1/4

A:7 1/3

B:5 3/7

C:133/8

Answers

Answer 1
(16 1/2) / (2 1/4) =
(33/2) / (9/4) =
33/2 * 4/9 =
132/18 =
7 1/3 <==

Related Questions

Which fraction is NOT equivalent to 4/12?
A. 1/3 B. 12/30 C. 8/24 D. 16/48

Answers

The answer is B
4 times 3 is equal to 12 but 12 times 3 equal 36 so it would have to be
12/36 to be equivalent to 4/12
First, you need to simplify these fractions:
4/12 = 1/3
A. is definitely the same as 4/12.
B: 12/30 = 2/5
C: 8/24 = 1/3 - this is also the same as 4/12
D: 16/48 = 1/3 this is also the same as 4/12

This means that the fraction not equivalent to 4/12 is B. 12/30

What is the first step to writing an equation of a line when given two points?

Answers

Find the slope of the line using the two points by plugging them into this formula: m = y2 - y1 / x2 - x1 where the two points are x1, y1 and x2, y2 and m is the slope. 

I'm in high school and need help with this problem. 2x +y = -13 x= 3x+y

Answers

First input the variables in to the equation.
2(3x+y)+y=-13
We will now distribute.
6x+3y=-13
This is the furthest we could get because we have no more variables we can combine. 

Hi! Please help... a woman drops a front door key to her husband from their apartment window several stories above the ground. the function h=-16t^2 +64 gives the height h of the key in feet, t seconds after she releases it.
A/ how long does it take the key to reach the ground?
B/ what are the reasonable domain and range for the function h? ...?

Answers

A. When the key reaches the ground, h = 0.

   0 = -16t^2 + 64
   16t^2 = 64
   t^2 = 4
   t = 2 seconds.

B. The reasonable domain of the function is [0, 2], since the function does not hold when the key reaches the ground. The range of the function is [0, 64] which corresponds to the domain.

Answer:

It would take 2 seconds to the key to reach the ground.

The domain the function is: 0≤t≤2 or in interval notation [0,2].

The range of the function is: 0≤h≤64 or in interval notation [0,64].

Step-by-step explanation:

The provided function is: [tex]h=-16t^2 +64[/tex]

Where h represents the height and t represents the time.

Part(A) how long does it take the key to reach the ground?

When key will be at ground, the height will be 0.

Substitute the value of h=0 in above equation and solve for t.

[tex]-16t^2 +64=0[/tex]

[tex]-16(t^2 -4)=0[/tex]

[tex](t^2 -2^2)=0[/tex]

[tex](t+2)(t-2)=0[/tex]

[tex]t+2=0\ or\ t-2=0[/tex]

[tex]t=-2\ or\ t=2[/tex]

Ignore the negative value of t.

Hence, it would take 2 seconds to the key to reach the ground.

Part (B) what are the reasonable domain and range for the function h?

Time and Distance should be a positive number.

Thus, the value of t and h should be greater or equal to 0.

From the part (a) we know that the after 2 second the key will hit the ground so the value of t can be greater or equal to 0 but should be less or equal to 2.

Thus, the domain the function is: 0≤t≤2 or in interval notation [0,2].

The maximum height of the key will be at t=0.

Thus the maximum value of h can be 64 and minimum value can be 0.

The range of the function is: 0≤h≤64 or in interval notation [0,64].

Name the property of 11xn=1

Answers

Is it 11x or 11 time n = 1?

. To change the shape of a function, you need to _____ or compress it.

A. compress
B. stretch
C. shift
D. flip

Answers

Answer – B. Stretch
 Transformations are said to be rigid if they maintain the same size and shape, so by inference, a change in shape can only be accomplished by a non-rigid transformation. A form of non-rigid transformation is a stretch or compression therefore, in order to change the shape of a function, you need to stretch or compress it.

Answer:

B. Strech

Step-by-step explanation:

Stretching can change the shape of something such as a function.

Slope is - 3 And (0,-4) is on the line

Answers

I hope this helps you



x'=0 y'= -4



slope (x'-x)=y'-y



-3. (0-x)= -4-y


-3.-x= -4-y


3x= -4-y


y= -3x-4
the equation of a line that has slope m and passes through the point (x1,y1) is
y-y1=m(x-x1)

given
slope=-3
point=(0,-4)
x1=0
y1=-4

equaton is
y-(-4)=-3(x-0)
y+4=-3(x)
y+4=-3x

The Sugar Sweet Company is going to transport its sugar to market. It will cost
$4500 to rent trucks, and it will cost an additional $175 for each ton of sugar transported. Let C represent the total cost (in dollars), and let S represent the amount of sugar (in tons) transported. Write an equation relating C to S. Then use this equation to find the total cost to transport 19 tons of sugar.

Answers

C= 4500+(S×175)

19×175 = 3325

4500+3325= 7825

C= $7825

The des moines register recently reported the ratings of high school sportsmanship as complied by the iowo high school athletic association. For each school, the participants and coaches were rated by referees, where 1= superior, and 5= unsatisfactory. A regression analysis of the averages scores given to football players and coaches is shown below.

interpret the value of the correlation between the ratings of coaches and participants.

Answers

The correlation coefficient "r" is square root of of the "R^2" .... square root (.45) which yields 0.67

Which graph represents a reflection of f(x) = 2(0.4)x across the y-axis?




Answers

Answer: The correct option is A.

Explanation:

The given function is,

[tex]f(x)=2(0.4)^x[/tex]

To find the graph of this function after the reflecting across y-axis, first we have to find the graph of the equation.

The value of the function is 2 when x=0, so, the graph of given equation intersect the y-axis at 2.

In the equation [tex](0.4)^x[/tex]. Since [tex]0<0.4<1[/tex], so the given function is decreasing function.

[tex]f(x)\rightarrow 0 \text{ as }\rightarrow \infty[/tex]

[tex]f(x)\rightarrow \infty \text{ as }\rightarrow -\infty[/tex]

The value of f(x) is always positive, so the graph of f(x) is always above the x-axis. Thus, the graph must be above the x-axis after reflection across y-axis.

So, the option (2) and (4) and incorrect.

When we reflect the graph across the y-axis then,

[tex]f(x)\rightarrow \infty \text{ as }\rightarrow \infty[/tex]

[tex]f(x)\rightarrow 0 \text{ as }\rightarrow -\infty[/tex]

It means when x approaches to large negative number the f(x) approaches to 0 and when x approaches to large positive number the f(x) approaches to infinite.

Therefore, the correct option is show in first graph.

Answer:

a

Step-by-step explanation:

Which of the following is not a valid postulate or theorem for proving triangles congruent?
A. SSA
B. ASA
C. AAS
D. SAS

Answers

Final answer:

The valid postulates and theorems for proving triangles congruent are ASA, AAS, and SAS. The SSA postulate is not a valid postulate.

Explanation:

The valid postulates and theorems for proving triangles congruent are ASA (Angle-Side-Angle), AAS (Angle-Angle-Side), and SAS (Side-Angle-Side).

The SSA (Side-Side-Angle) postulate, also known as the ambiguous case of the Law of Sines, is not a valid postulate for proving triangles congruent because it can result in two different triangles or no triangle at all.

Thus, the correct answer is A. SSA.

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Solve the differential equation using the method of undetermined coefficients

a) 4y"- 4y'-3y= cos2x

Answers

First: the homogeneous solutions: the characteristic equation is4r^2 - 4r - 3 = 0which has roots r = 3/2, -1/2 hence the homogeneous solution isy = c1.exp(-x/2) + c2.exp(3x/2)

next you need the general form for the guess for yp and that isyp = A1cos(2x) + A2sin(2x)
Now substitute that into the equation and solve for A1, A2.

help please?
solve for Y
a(y+c)=b(y-c)
solve for W
A=lw+wh+lh
...?

Answers

I am pretty sure that the solution I attach below is the correct one :[tex]ay+ac=by-bc ay-by=-ac-bc y(a-b)=c(a-b)[/tex]
[tex]y=c(a-b)/(a-b) y=c[/tex]
And what about the next part of your task, the answer is : 
[tex]A=lw+wh+lh w=(A-Ih)/(l+h)[/tex]
Do hope you will find it useful!

**!!!STUCK ON 2 QUESTIONS!!!!

The time is takes to mow the lawn at a large park m(x) varies inversely with the numbers of workers assigned to the job x. It takes 90 minutes to complete the job when 3 workers are assigned to it.


which equation can be used to find the time to complete the job when x workers are assigned to it?

A.) m(x)= 270/x
B.) m(x) = 270x
C.) m(x) = 30/x
D.) m(x) = 30x

2. Suppose that H(x) varies inversely with x and H(x)=50 when x =0.25

What is H(x) when x =2?

A.) 0.5
B.) 6.25
C.) 12.5
D.) 24

Can you also provide how you got the answer as well :)

Answers

The first one is A 
270/3=90 thus proving the equation right 

oh and the second one is B

Answer:

1. Which equation can be used to find the time to complete the job when x workers are assigned to it?

A.) m(x) = 270/x

2. Suppose that H(x) varies inversely with x and H(x)=50 when x =0.25

What is H(x) when x =2?

B.) 6.25

Step-by-step explanation:

1. We know when x=3 (workers), m(x)= 90 min (time is takes to mow the lawn at a large park) and we know m(x) varies inversely with x, this means when m(x) increases so x decreases. This is obtained with a division over x.

Now, we can replace to know what is the correct answer:

[tex]m(x)=\frac{y}{x} (1) \\90=\frac{y}{3} \\90*3=y[/tex]

[tex]y=270[/tex]

The answer is A.

[tex]m(x)=\frac{270}{x}[/tex]

We can confirm if we replace x=3 in the equation before. Our answer should be 90.

[tex]m(x)=\frac{270}{3}=90[/tex]

2.  Suppose that H(x) varies inversely with x and H(x)=50 when x =0.25

We know H(x) varies inversely with x, this means when H(x) increases so x decreases. This is obtained with a division over x. Now, we need to find the constant in the numerator.

Now, we can replace in the eq (1) to know the constant in the numerator:

[tex]H(x)=\frac{y}{x}\\50=\frac{y}{0.25} \\50*0.25=y[/tex]

[tex]y=12.5[/tex]

Now, we can replace in the eq (1) to find H(x) when x=2

[tex]m(x)=\frac{y}{x}[/tex]

[tex]m(x)=\frac{12.5}{2}[/tex]

[tex]m(x)=6.25[/tex]  

The answer is B.) 6.25

Which answer shows these decimals written in order from greatest to least?   46.95
48.1
46.581

Answers

48,1 > 46.95 >46.581            

What is the midpoint of 0.7 0.8?

Answers

Midpoint = 0.7+0.8/2 = 1.5/2 = 0.75
So, their mid-point is 0.75

Hope this helps!
its 0.75

hope this helps you

Two particles are fixed to an x axis: particle 1 of charge -1.00 x 10-7 C is at the origin and particle 2 of charge +1.00 x 10-7 C is at x = 17.1 cm. Midway between the particles, what is the magnitude of the net electric field?

...?

Answers

The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint. 

The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = -7.041 N/C

Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*7.041 N/C = 14.082 N/C

The following data values represent a population. What is the variance of the values?

8, 10, 14, 12

A.22
B.11
C.5
D.10

Answers

Answer:

It’s actually 5

Step-by-step explanation:

Ape x

The product of 9 and a number is 12 less than three times that number.

What is the number?

Answers

So let me give you the answer with procedure so that you can understand it better:
Let x = Number 

Product of 9 and Number:
9x 
is 12 less than 3 times that number. So: 
3x - 12 
Set them equal and solve for x like this:
9x = 3x - 12 
6x = -12 
x = -2
I hope this is very useful for you

Which of the following options is an equivalent function to f(x) = 3(2)3x?

f(x) = 3(8)x
f(x) = 24x
f(x) = 27(8)x
f(x) = 3(8x)

Answers

So based on the given function above, the one that is equivalent to it would be the first option. So as you see, there might be a slight difference because the actual function should be written like this: f(x) = 3(2)^3x. Therefore, basing on this, the answer would be the first option: f(x) = 3(8)^x. Hope this answer helps.

The correct option is A: [tex]\( \boxed{f(x) = 3(8)^x} \).[/tex]

To determine which option is equivalent to the given function f(x) = [tex]3(2)^{3x} \),[/tex] we will simplify the given function and compare it to each option.

The given function is:

[tex]\[ f(x) = 3(2)^{3x} \][/tex]

We can rewrite the exponent part using properties of exponents:

[tex]\[ (2)^{3x} = (2^3)^x = 8^x \][/tex]

So the function becomes:

[tex]\[ f(x) = 3 \cdot 8^x \][/tex]

Now, let's compare this to each of the given options:

Option A: [tex]\( f(x) = 3(8)^x \)[/tex]

This is exactly the same as our simplified function. Therefore, Option A is equivalent to [tex]\( f(x) = 3(2)^{3x} \).[/tex]

Option B: [tex]\( f(x) = 24^x \)[/tex]

This is not equivalent because it implies a different base raised to the power of x.

Option C:[tex]\( f(x) = 3(8x) \)[/tex]

This is not equivalent because it multiplies by 27 instead of 3.

Option D: [tex]\( f(x) = 3(8x) \)[/tex]

This is not equivalent because it implies multiplying 8 by x, not raising 8 to the power of x.

Therefore, the correct answer is:

[tex]\( \boxed{f(x) = 3(8)^x} \).[/tex]

The complete question is here:

Which of the following options is an equivalent function to f(x) = 3(2)3x?

A. f(x) = 3(8)x

B. f(x) = 24x

C. f(x) = 27(8)x

D. f(x) = 3(8x)

-1.4n + 2.1 = 6.58

what is n

Answers

-1.4n + 2.1 = 6.58
-1.4n = 6.58 - 2.1
-1.4n = 4.48
n = -4.48/1.4
n = -3.2

So, your final answer is -3.2

Hope this helps!



Solve the system of equations and choose the correct ordered pair.

3x + 2y = 12
6x + 3y = 21

A. (4, 3)
B. (4, 0)
C. (2, 3)
D. (3, 2)

Answers

I hope this helps you

Answer:

C.

Step-by-step explanation:

We are going to solve it with substitution, that is, we are going to clear one variable and then replace it in the other equation. Then,

[tex]3x + 2y = 12[/tex]

[tex]3x = 12-2y[/tex]

[tex]x = \frac{12-2y}{3}[/tex]

[tex]x = \frac{12}{3}-\frac{2y}{3}[/tex]

[tex]x = 4-\frac{2y}{3}.[/tex]

Now, we replace that x value in the equation 6x + 3y = 21:

[tex]6(4-\frac{2y}{3}) + 3y = 21[/tex]

[tex]24-\frac{12y}{3} + 3y = 21[/tex]

[tex]24-4y + 3y = 21[/tex]

[tex]24-y = 21[/tex]

[tex]-y = 21-24[/tex]

[tex]-y = -3[/tex]

[tex]y = 3.[/tex]

Finally, we replace the y value found to find x.

[tex]x = 4-\frac{2*3}{3}[/tex]

[tex]x = 4-2[/tex]

[tex]x = 2.[/tex]

So, the solution is (x,y)=(2,3). Then, the answer is C.

a factory makes 1200 pounds of potato chips in four hours at this rate how many pounds of potato chips will a factory make in 10 hours

Answers

1200/4 = x/10 ,,,,4x=12000,,,x=3000
Final answer:

A factory producing 1200 pounds of chips in four hours will yield 3000 pounds when operating for 10 hours, assuming a consistent production rate.

Explanation:

The given problem pertains to rate, which allows the determination of how much of something can be done in a specific amount of time. In this case, the rate of potato chip production is 1200 pounds every four hours. To find out how many pounds of potato chips can be produced in 10 hours, we first need to determine the hourly rate of production.

Firstly, we determine the hourly production rate of the factory by dividing the total produce by the time spent. That is 1200 pounds / 4 hours = 300 pounds/hour.

At this hourly rate, the amount of potato chips that can be produced in 10 hours can be calculated by multiplying the hourly rate by the number of hours, which is 300 pounds/hour * 10 hours = 3000 pounds.

So, a factory that produces 1200 pounds of potato chips in four hours will make 3000 pounds of potato chips in 10 hours.

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keisha is reading a 325 page book at a rate of 25 pages per day. use a point slipe equation to determine whether she will finish reading the book in 10 days.

Answers

Final answer:

Using the point slope equation, it is determined that Keisha will not finish reading the 325 pages book in 10 days if she is reading at a rate of 25 pages per day.

Explanation:

The subject of this question is Mathematics and it involves solving a problem using a point slope equation.

Let's denote the total number of pages in the book as 'y' and the number of pages that Keisha can read per day as 'm'. We know that y=325 and m=25. The point slope equation in this case would be y=mx, where 'x' represents the number of days. In this case, we are trying to find out whether x=10.

Substituting the known values into the equation we get: 325=25*10. This simplifies to 325=250.

Since 325 does not equal 250, we can conclude that Keisha will not complete reading the book in 10 days.

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The formula for an object's final velocity is f=i−gt f=i−gt . Solve for t.

Answers

f=i-gt
subtract i
f-i=-gt
divide by -g
(f-i)/-g=t

answer: (f-i)/-g=t


I hope it helps~

which correctly describes the root of the following cubic equation? x^3-3x^2+4x-12=0

Answers

Answer:

The equation has one real root and two complex roots.

Step-by-step explanation:

The given equation is

[tex]x^3-3x^2+4x-12=0[/tex]

The above equation is true form x=3, therefore (x-3) is a factor of above equation.

Use long division or synthetic division method to divide the equation by (x-3).

[tex](x-3)(x^2+4)=0[/tex]

Equate each factor equal to zero.

[tex]x-3=0[/tex]

[tex]x=3[/tex]

Therefore 3 is a real root of the equation.

[tex]x^2+4=0[/tex]

[tex]x^2=-4[/tex]

[tex]x=\sqrt{-4}[/tex]

[tex]x=\pm 2i[/tex]

2i and -2i are complex roots of the equation.

Therefore the equation has one real root and two complex roots.

4 questions that I don't understand how to do. Help please?

Answers

In the first problem, you are subtracting fractions.
To subtract fractions, you need a common denominator.
Do the two fractions have a common denominator?
The first one is B
the second one is, 4x+8/5x-5
the third one i think is c (im not sure)
the fourth one is x+2/8x^3+24x^2


page 128 slopes and intercepts

Answers

How on earth is anyone suppose to answer this !!

Mark all of the statements that are true.
(will attach graph shortly)

a. The range for this function is the set {3}.

b. This graph is not a function because the value of y is the same for every value of x.

c. The domain for this function is all real numbers.

d. The domain for this function is the set {3}.

e. All real numbers are in the range of this function.

***CHOOSE ALL THAT APPLY!! And please explain!! :)

Answers

The statements that are true are:

a. The range for this function is the set {3}.      [range is the value of y, here the value of y is 3 for all value of x]

c. The domain for this function is all real numbers.      [the domain is the value of x, as you can see, the graph span all the x axis]

i am the only number between 41 and 49 that has 5 as a factor. what number am i?

Answers

it is 45 becuase 9 times 5 is 45 
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