Solve the equation, and check the answer
5g+4(-5+3)=1-g

Answers

Answer 1
the answer is 5g - 8 is your answer
Answer 2
1- 4=-3
(-5+3)=-2
-3/-2=1.5
1.5 times 5=7.5
g=7.5

Related Questions

The ratio of a number and 6 written as an algebraic expression is

Answers

The answer to your question is:
x/6

The required algebraic expression is x / 6.

Given that,
In the question, was asked to determine the ratio of the number 6 in the form of algebraic expression.

What is an algebraic expression?

The algebraic expression consists of constant and variable. eg x, y, z, etc.

What is a polynomial function?

A polynomial function is a function that applies only integer dominions or only positive integer powers of a value in an equation such as the quadratic equation, cubic equation, etc. ax+b is a polynomial.

Let the number be x,
The ratio of numbers x and 6,
= x / 6
Here above expression is an algebraic expression, because the x is a variable in the equation.

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What number is greater 87 or 13.688?

Answers

87 is greater of course
87, if it's easier to see, you can round 13.688 and get 14. 87 > 14

In 448,244, how is the relationship between the first pair of 4's the same as the relationship between the second pair of 4's?

Answers

They are all whole numbers , Judy in different spaces and positions
Final answer:

The similar relationship between the two pairs of '4's in the number 448,244 is based on their order of magnitude or place value each pair differing by one order of magnitude.

Explanation:

In the number 448,244, the relationship between the first pair of 4's is the same as the relationship between the second pair of 4's in terms of their place value or order of magnitude.

The first '4' is in the hundred thousands place and the second '4' is in the ten thousands place, a difference of one order of magnitude (105 vs 104). Similarly, the third '4' is in the hundreds place and the second '4' is in the units place, also a difference of one order of magnitude (102 vs 100). So, despite the fact they are located in different parts of the number, the relationship between each pair of '4's is consistent based on their order of magnitude.

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It is estimated that each guest at a party will eat
9/10 pounds of chocolates. How many guests can be served with 45 pounds of chocolate?

Answers

[tex]\bf \begin{array}{ccll} guests&\stackrel{lbs}{chocolate}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&\frac{9}{10}\\\\ g&45 \end{array}\implies \cfrac{1}{g}=\cfrac{\frac{9}{10}}{45}\implies \cfrac{1}{g}=\cfrac{\frac{9}{10}}{\frac{45}{1}}\implies \cfrac{1}{g}=\cfrac{9}{10}\cdot \cfrac{1}{45} \\\\\\ \cfrac{1}{g}=\cfrac{9}{450}\implies \cfrac{1\cdot 450}{9}=g[/tex]

and pretty sure you know how much that is.

how to solve -x+4=-2x-6

Answers

Regroup terms

Add 2x to both sides 

Simplify 4 - x + 2x to 4 + x

subtract 4 from both sides

subtract -6 - 4.

Answer: x = -10

-x+4 = -2x-6

add 6 to each side:

-x+10 = -2x

add 1x to each side

10 = -x

divide each side by -1

x = -10

The population of a town grows at a rate proportional to the population present at time t. the initial population of 500 increases by 15% in 10 years. what will be the population in 50 years? (round your answer to the nearest person.)

Answers

This is a case of exponential growth.  The appropriate equation, with the given data inserted, is     P(t) = 500 ( 1+0.15)^50

or                                   = 500 (1.15)^50

Evaluate this on your calculator.

3. You are looking into two long distance telephone plans offered by GT&T. The “One Rate 5 cents” plan has a monthly fee of $7.95 and all calls are 5 cents per minute. The “One Rate 7 cents” plan has a monthly fee of $4.95 and all calls are 7 cents per minute. Under what circumstances is one plan less expensive than the other?

a. The "One Rate 5 cents" plan is less expensive for calls lasting less than 1.5 minutes. The "One Rate 7 cents" plan is less expensive for calls lasting more than 1.5 minutes.

b. The "One Rate 7 cents" plan is less expensive for calls lasting less than 1.5 minutes. The "One Rate 5 cents" plan is less expensive for calls lasting more than 1.5 minutes.

c. The "One Rate 5 cents" plan is less expensive for calls lasting less than 150 minutes. The "One Rate 7 cents" plan is less expensive for calls lasting more than 150 minutes.

d. The "One Rate 7 cents" plan is less expensive for calls lasting less than 150 minutes. The "One Rate 5 cents" plan is less expensive for calls lasting more than 150 minutes.

Answers

 D. After 150 minutes, the 5 cent one is more.

Hope this helps!

Answer:

D.The "One Rate 7 cents" plan is less expensive for calls lasting less than 150 minutes. The "One Rate 5 cents" plan is less expensive for calls lasting more than 150 minutes.

Step-by-step explanation:

let the total number of minutes of calls be x minutes.

Now let us find the total cost incurred in both plan for x mins.

Plan 5 cent : 7.95+0.05x

Plan 7 cent : 4.95+0.07x

Let us find the time at which both the plans will give you same Bill.

Hence

7.95+0.05x=4.95+0.07x

7.95-4.95=0.07x-0.05x

3=0.02x

x=150

Hence at 150th min, both the plan will charge you same cost. Hence the plan giving you less Bill for 100 mins will give you high Bill in 200 mins. Let us calculate the bill incurred by both plan at 100th min.

Plan 5 cent : 7.95+0.05×100=12.95

Plan 7 cent: 4.95+0.07×100=11.95

Hence plan 7 cent is lesser than 5 cent for calls more than 150 mins

Let find which plan cost you cheaper

Build the fraction to an equivalent fraction with the specified denominator. State the numerator. 5/12 = ?/60

Answers

The answer is 5/12 = 25/60

The difference between 29 and a number

Answers

The word "difference" means subtract (-)

29 equals 29

A number equals w

So, your answer would be: 29 - w

There are two pizzas. Conor ate 1⁄4 of a pizza, Brandon 2⁄8, Tyler 3⁄4, and Audrey4⁄8. Who ate the most of the two pizzas? 

       A. Audrey   B. Tyler   C. Brandon   D. Conor

Answers

B. Tyler ate the most of the two pizzas. 
First, get them all to have the same denominator.
Conor- 1/4
Brandon- 2/8 = 1/4
Tyler- 3/4
Audrey- 4/8 = 2/4

Out of all these, the person who ate the most was Tyler, at 3/4 of the pizzas.
B. Tyler

Jimmy’s new cell phone cost him $49.99 when he signed a 2 year plan, which was 75% off the original place. What was the original price?

Answers

If Jimmy's new cell cost him $49.99 with a 75% discount, then $49.99 is 100%−75%=25% of the original price.

The original price of the cell phone was $199.96.

Item 10 A restaurant earns $1240 on Friday and $921 on Saturday. Write and solve an equation to find the amount xx (in dollars) the restaurant needs to earn on Sunday to average $1000 per day over the three-day period. Write your equation so that the units on each side of the equation are dollars per day.

Answers

Let the restaurant need to earn x dollars on Sunday, to average 1000$/day .

The average earning over the 3 days is [tex] \frac{1240+921+x}{3}= \frac{2161+x}{3} [/tex] dollars.

we equalize this expression to $1000:

[tex]\frac{2161+x}{3} =1000\\\\ 2161+x=3000\\\\x=3000-2161\\\\x=839[/tex] dollars


Thus the equation is : [tex]\frac{1240+921+x}{3}(\$/day)=1000(\$/day) [/tex]

Which graph represents the function f(x)=8 1/3x

Answers

The second one. Try plotting the points by plugging in a few values for x. 

f(x=0) = 8^0 = 1
f(x=2) = 8^(1/3)*2 = 4
f(x=4) = 8^(1/3)*4 = 16

Answer:

The correct option is 2.

Step-by-step explanation:

The given function is

[tex]f(x)=8^{\frac{1}{3}x}[/tex]

At x=0,

[tex]f(0)=8^{\frac{1}{3}(0)}=8^0=1[/tex]

At x=1,

[tex]f(1)=8^{\frac{1}{3}(1)}=8^{\frac{1}{3}}=2[/tex]

At x=2,

[tex]f(2)=8^{\frac{1}{3}(2)}=8^{\frac{2}{3}}=4[/tex]

At x=3,

[tex]f(3)=8^{\frac{1}{3}(3)}=8^{1}=8[/tex]

The graph of f(x) passing through the points (0,1), (1,2), (2,4),(3,8).

According to these coordinates we can say that the graph of f(x) is represented by option 2.

Therefore correct option is 2.

A school party visit the gift shop. They all want to buy a badge. Your friend needs to get 37 badges from the stock room. The badges come in packs of 10. How many packs does she need?

Answers

She needs 4 packs and she will then have a spare 3

Answer:

She will need 4 packs.

Step-by-step explanation:

The badges come in packs of 10 but this person only needs 37 badges.

If she buys two packs, she will get 20 badges.

If she buys three packs, she will get 30 badges.

Is she buys four packs, she will get 40 badges.

She will need four packs so she can have 37 badges and there will be 3 remaining badges.

Find the value of $ 15,000 at the end of one year if it is invested in an account that has an interest rate of 4.95 % and is compounded in accordance with the rules below. a. compounded monthly b. compounded daily​ (assuming a​ 365-day year) c. compounded quarterly

Answers

a)

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$15000\\ r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{twelve months, thus} \end{array}\to &12\\ t=years\to &1 \end{cases} \\\\\\ A=15000\left(1+\frac{0.0495}{12}\right)^{12\cdot 1}[/tex]

b)

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$15000\\ r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{365 days, thus} \end{array}\to &365\\ t=years\to &1 \end{cases} \\\\\\ A=15000\left(1+\frac{0.0495}{365}\right)^{365\cdot 1}[/tex]

c)

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$15000\\ r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{four quarters, thus} \end{array}\to &4\\ t=years\to &1 \end{cases} \\\\\\ A=15000\left(1+\frac{0.0495}{4}\right)^{4\cdot 1}[/tex]

A) compounded monthly; A = $15,759.579

B)  compounded quarterly; A = $15,756.396

What is Compound interest?

Compound interest, also known as interest on principle and interest, is the practise of adding interest to the principal amount of a loan or deposit.

We have,

P = $15,000

R= 4.95%

a) Using A = P(1+ r/n[tex])^{nt[/tex]

A = 15,000 (1 + 0.0495 /12[tex])^{12[/tex]

A= 15,000 x 1.0506386172

A = $15,759.579

b) Again, A = P(1+ r/n[tex])^{nt[/tex]

A = 15,000 (1 + 0.0495 /365[tex])^{365[/tex]

c) Again, A = P(1+ r/n[tex])^{nt[/tex]

A = 15,000 (1 + 0.0495 /4.1[tex])^{4.1[/tex]

A = 15, 000 x 1.05042644766

A = $15,756.396

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Jackson has 50 megabytes (MB) of space left on his smartphone. He can download songs that each use 3.5 MB or videos that each use 7 MB. He wants to download at least 10 new media files. Which pair of inequalities specifies the number of song files, x, and the number of video files, y, that Jackson can download

Answers

The number of song files Jackson can download: x

The number of video files Jackson can download: y



x song files occupy a space of 3.5MB per file, times x files = 3.5x MB

y media files occupy a space of 7MB per file, times y files = 7yMB


(3.5x + 7y) MB must be at most 50 MB, since there is 50 MB left,

this can be represented by the inequality: [tex]i) \ \ 3.5x+7y \leq 50[/tex]


Jackson wants to download at least 10 media files, so y must be at least 10

this means that [tex]ii) \ \ \ y \geq 10[/tex]


Answer: [tex]i) \ \ 3.5x+7y \leq 50\\\\ii) \ \ \ y \geq 10[/tex]


Answer:

[tex]3.5x+7y\leq 50[/tex]

[tex]x+y\geq 10[/tex]

Step-by-step explanation:

Given : Jackson has 50 megabytes (MB) of space left on his smartphone. He can download songs that each use 3.5 MB or videos that each use 7 MB. He wants to download at least 10 new media files.

To find : The pair of inequalities specifies the number of song files, x, and the number of video files, y, that Jackson can download.

Solution :

The number of song files Jackson can download is x

The number of video files Jackson can download is y

→ x song files occupy a space of 3.5 MB per file,

So, number of space occupy by songs files = 3.5x MB

→ y media files occupy a space of 7 MB per file,

So, number of space occupy by video files = 7y MB

→ The total amount of MB used is [tex]3.5x+7y[/tex]

Jackson has 50 megabytes (MB) of space left on his smartphone.

The total amount must be less than or equal to 50 MB,

which can be represented as [tex]3.5x+7y\leq 50[/tex]

Jackson wants to download at least 10 media files,

which means [tex]x+y\geq 10[/tex]

Therefore, The two inequality form is

[tex]3.5x+7y\leq 50[/tex]

[tex]x+y\geq 10[/tex]                                                      

Sylvia bought 8 tickets to a concert. Each ticket costs $18. To find the total cost in dollars, she added the product 8×10 to the product 8×8, for a total of 144. Which property did Sylvia use?

Answers

Sylvia wanted to find the total cost in easier way.
8 x 10 + 8 x 8 = 80 + 64 = 144
She used the Distributive property:
a x ( b + c ) = a x b + a x c
8 x 18 = 8 x ( 10 + 8 ) = 8 x 10 + 8 x 8 = 80 + 64 = 144
Answer:
Distributive property.

Answer:

distributive property

Step-by-step explanation:

im tired i just solved the problem good bye

Explain how u would use repeated subtraction to find 8÷2

Answers

If you are dividing by 2, you subtract 2 times. 8-2-2=4. It is the same as 8/2=4.
8 divided by 2 is four...
8-2=6-2=4-2=2-2=0

If (x)=x/2-2 and g(x)=2x2+x-3, find (f+g)(x)

Answers

(f+g)(x)=f(x)+g(x)=
[tex]\frac{x}{2}-2+2x^2+x-3=2x^2+\frac{2}{2}x+\frac{1}{2}x-2-3=[/tex]
[tex]2x^2+\frac{3}{2}x-5[/tex]


[tex](f+g)(x)=2x^2+\frac{3}{2}x-5[/tex]

Add 1/7+7/10 as a fraction in simplest form

Answers

1/7 = 10/70 ; 7/10 = 49/70

10/70 + 49/70 = 59/70

59/70 is your answer.

First, we need to find the least common denominator in order to add these fractions together. The lowest common denominator is 70.

[tex]\frac{10}{70}[/tex] + [tex]\frac{49}{70}[/tex] = [tex]\frac{59}{70}[/tex]

Whats 12 divided by 3 1/2

Answers

3 1/2 = 7/2

12 / 7/2 = 12*2 =24/7 = 3 3/7

If two circles have the same circumference what do you know about their area

Answers

If the circumference is half of the perimeter than the area for both circles would be half of them find one circles area and half it

The sum of three numbers is 104. The first number is 6 less than the second. The third number is 3 times the second. What are the numbers

Answers

We can write this in math as x+y+z=104, x=y-6, and z=3y

Because we already know what x and z are in terms of y, we can substitute our values for x and z into the first equation. This now looks like (y-6) + y + (3y) = 104. Now we can simplify our equation to find our value for y.

y-6 + y + 3y = 104 simplifies to 5y - 6 = 104, then 5y=110, and finally y=22.

Now that we know our value for y we can find our values for x and z by substituting our value for y into the other two equations.

The second equation x = y-6 can be simplified as x = 22 - 6 and further simplified as x = 16.

The third equation z = 3y can be written as z = 3(22) or z = 66.

Our three numbers are 16, 22, and 66. Hope this helps you!

A man in a rowboat that is a = 2 miles from the nearest point A on a straight shoreline wishes to reach a house located at a point B that is b = 8 miles farther down the shoreline (see the figure). He plans to row to a point P that is between A and B and is x miles from the house, and then he will walk the remainder of the distance. Suppose he can row at a rate of 2 mi/hr and can walk at a rate of 4 mi/hr. If T is the total time required to reach the house, express T as a function of x.

Answers

Alright, so by creating a right triangle with side a, point A, and point P,we can get that a^2+A^2 (if A is the distance from A to P) = P^2 (if P is the distance from P to the rowboat) using the Pythagorean Theorem. After that, we know that he will walk x miles to point B. Since b is A+x, we know that b=A+x and
b-x=A by subtracting x from both sides. Therefore, a^2+(b-x)^2=P^2 and by plugging a=2 and b=8 in, we get 2^2+(8-x)^2=P^2. To find out P, we square root both sides, getting P= sqrt(4+(8-x)^2). Since the man rows 2 miles per hour, we can divide P by 2 to get how much time it takes for him to travel to point P, resulting in sqrt(4+(8-x)^2)/2. In addition, we can divide x by 4 as the man walks 4 miles per hour, getting x/4. Adding them up, we get
sqrt(4+(8-x)^2)/2+x/4 as the amount of time it will take to get to point B

How many pair of socks a person has to take out from the drawer to be sure to have at least 4 pairs of blue socks?

Answers

I suspect you have more info than you have shared here.  How many pair of socks, total, are in that drawer, and of what colors are they?

q(a+y)=67y+93 help me answer this

Answers

The answer your looking for is q-67

What is the area of a square deck, if one side is 10 feet long?

Answers

Since we know the length of one side, and it's a square, we simply multiply 10 by 10 to get 100. The final answer is 100 square feet.

Answer:100 square feet

Step-by-step explanation: since we know that a square has all equal sides, and we know one length of one side is 10, we know all sides are ten then. We then multiply 10 x 10 which will equal, 100

Alisa says it is easier to compare the numbers in Set A (45,760 and 1,025,680) than the numbers in Set B (492,111 and 409,867). What is one way you could construct an argument justifying whether Alisa's conjecture is true?

Answers

To construct the argument, one could look at the value of the largest digit. In Set A, the largest-valued digit (1) has a value of one million, while the 4 in the other value is only valued at 40,000. Set B has two 4 values that are both worth 400,000, which will end up requiring a second comparison to tease out the larger value.

If R is the midpoint of QS, QR= 8x-51 and RS=3x-6, find QS.

Answers

QS = 11x - 57 

since r is the midpoint, QR + RS = QS

Answer:  The required length of QS is 42 units.

Step-by-step explanation:  Given that R is the midpoint of QS, where

[tex]QS=8x-51,~~RS=3x-6.[/tex]

We are to find the length of QS.

Since R is the midpoint of the segment QS, so we must have

[tex]QR=RS\\\\\Rightarrow 8x-51=3x-6\\\\\Rightarrow 8x-3x=51-6\\\\\Rightarrow 5x=45\\\\\Rightarrow x=\dfrac{45}{5}\\\\\Rightarrow x=9.[/tex]

Therefore, the length of QS is given by

[tex]QS\\\\=QR+RS\\\\=8x-51+3x-6\\\\=11x-57\\\\=11\times9-57\\\\=99-57\\\\=42.[/tex]

Thus, the required length of QS is 42 units.

What multiplies to 14 and adds to -15?

Answers

This would be -14 and -1 (I'm assuming you're trying to factor a quadratic equation).

Check:
-14*-1=14
-14-1=-15
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