Solve the quadratic equation by factoring 9x2+24+20=4

let's take a peek

we really have a rectangular prism below a square pyramid.

the prism has a front, back, left and right of a rectangle 2x11 .

its bottom or base is an 11x11 square.

the pyramid 4 triangles, each one has a base of 11 and a height of 7.

[tex]\bf \stackrel{\textit{front, back, left, right}}{4(2\cdot 11)}~~+~~\stackrel{\textit{base}}{(11\cdot 11)}~~+~~\stackrel{\textit{four triangles}}{4\left[ \cfrac{1}{2}(11)(7) \right]} \\\\\\ 88+121+154\implies 363[/tex]

Answer:

The surface area of composite solid = 363 ft²

Step-by-step explanation:

Points to remember

Area of rectangle = Length * Breadth

Area of triangle = bh/2

Where b - Base and h - Height

To find the surface area of composite solid

Surface area = Base area  + side area  + area of 4 triangles

 = (11 * 11) + 4(11 * 2) + 4(11 * 7)/2

 = 121 + 88 + 154

 = 363 ft²

Therefore the surface area of composite solid = 363 ft²

Answer:

-3

Step-by-step explanation:

The x-intercept is the plot point where y = 0.

Answer:

-3

Step-by-step explanation:

the x-intercept is the point on the graph where the ploted line crosses the x axes  

Answer: This is some information I have gathered to help you since I cannot answer this directly sin θ + (cot θ)(cos θ)  

= sin θ + (cos θ / sin θ)(cos θ)  

= sin θ + cos² θ / sin θ  

Since cos² θ = 1 - sin² θ,  

= sin θ + (1 - sin² θ) / sin θ  

= sin θ + 1 / sin θ - sin θ  

= 1 / sin θ  

= csc θ ∎ Sin(x) = tan(x) / [sqrt(1 + tan^2(x)]  

Sin(theta) =3/4 / sqrt[1 + .75^2]

Sin(theta) =0.75 / sqrt[ 1.5625 ]

Sin(theta) =0.75 / 1.25

Sin(theta) = 0.60

Answer:

a) 3,6,9,12,15,..

b) Common Ratio is 3

c) Recursive Formula : aₙ= aₙ₋₁ + d where a₁=3 and d= 3

Step-by-step explanation:

a) Create your own arithmetic sequence. Write out the first 3 terms.

Consider the sequence: 3,6,9,12,15,..

a₁ = 3

a₂ = 6

a₃ = 9

b) What is the common difference of your sequence?

6-3 = 3

9-6 = 3

12 -9 =3

So, common difference is 3

c) Write the recursive formula representing your sequence.

a₁ = 3

a₂ = aₙ₋₁ + d

   = a₁ + d

   = 3+ 3 = 6

a₃ = aₙ₋₁ + d

    = a₂ + d

   = 6+3 = 9

so, recursive formula is aₙ = aₙ₋₁ + d where a₁ = 3 and d= 3

An example of an arithmetic sequence can be created with a starting value (a1) of 2 and a common difference (d) of 3. The sequence's terms would be 2, 5, 8, etc. Its recursive formula would be a1 = 2; a_n = a_(n–1) + 3.

Let's create an arithmetic sequence, starting with the first term (a1) of 2 and a common difference (d) of 3. So, the first three terms of the sequence would be 2, 2+3=5, and 5+3=8.

The common difference of this arithmetic sequence is 3 as each term is 3 greater than the previous term.

The recursive formula for this sequence is a1 = 2; a_n = a_(n–1) + 3. What this formula means is that the first term is 2, and each subsequent term (an) is the previous term (an-1) added to the common difference (3).

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ANSWER

(C) d=1

EXPLANATION

The given equation is

[tex] \frac{ - 3d}{ {d}^{2} - 2d - 8} + \frac{3}{d - 4} = \frac{ - 2}{d + 2} [/tex]

Factor the first fraction to get,

[tex] \frac{ - 3d}{(d + 2)(d - 4)} + \frac{3}{d - 4} = \frac{ - 2}{d + 2} [/tex]

Multiply through by (d+2)(d-4)

[tex] - 3d + 3(d + 2) = - 2(d - 4)[/tex]

Expand:

[tex] - 3d + 3d + 6 = - 2d + 8[/tex]

[tex] 6 = - 2d + 8[/tex]

[tex]6 - 8= - 2d[/tex]

[tex] - 2 = - 2d[/tex]

divide both sides by -2

[tex]d = 1[/tex]

The correct answer is (B) [tex]\( d = -2 \)[/tex] and [tex]\( d = 4 \)[/tex].

To find the solution to the given quadratic equation, we can factor it or use the quadratic formula. The equation is not provided in the conversation, but based on the options given, it seems that the equation could be in the form [tex]\( (d - a)(d - b) = 0 \)[/tex], where [tex]a[/tex] and [tex]b[/tex]are the roots of the equation.

The quadratic equation can be written as [tex]\( d^2 - (a+b)d + ab = 0 \)[/tex]. To have the sum of the roots [tex]\( a + b \)[/tex] equal to 0 and the product of the roots [tex]\( ab \)[/tex] equal to -8, we can set up the following system of equations:

1. [tex]\( a + b = 0 \)[/tex]

2. [tex]\( ab = -8 \)[/tex]

From equation 1, we can express [tex]\( b \)[/tex] in terms of [tex]\( a \): \( b = -a \).[/tex]

Substituting [tex]\( b \)[/tex] into equation 2, we get:

[tex]\( a(-a) = -8 \)[/tex]

[tex]\( -a^2 = -8 \)[/tex]

[tex]\( a^2 = 8 \)[/tex]

Taking the square root of both sides, we find:

[tex]\( a = \pm\sqrt{8} \)[/tex]

[tex]\( a = \pm2\sqrt{2} \)[/tex]

Since [tex]\( b = -a \),[/tex] we have:

[tex]\( a = 2\sqrt{2} \) and \( b = -2\sqrt{2} \)[/tex]

[tex]\( a = -2\sqrt{2} \) and \( b = 2\sqrt{2} \)[/tex]

However, these are not the exact values given in the options. We need to find the exact integer values for [tex]a[/tex] and [tex]b[/tex]. Since the product [tex]\( ab \)[/tex] is -8, we can look for two numbers that multiply to -8 and add up to 0. These numbers are -2 and 4.

Therefore, the solutions to the equation are [tex]\( d = -2 \)[/tex] and [tex]\( d = 4 \)[/tex], which corresponds to option (B).

Answer:

0

Step-by-step explanation:

Between -6 and 9 are 15 units.

2/5 of 15 units is 6 units.  Add this to -6 to obtain 0.

0 is the answer to this question

Step-by-step explanation:

I'm not sure but I think its like the distance between -6 and 9 is 15 or something and 15 divided by 5 is 3 and 2/5 is 6 so 6-6 is 0 and that's that point.

Depending on the country, most democracies use taxes for:

-public programs (any governmentally run or funded services)

-infrastructure (roads, bridges, etc)

-the military

-schools

-governmental departments (EPA, Department of Homeland Security, etc)

-government employee paychecks

And SOMETIMES:

-universal healthcare

-college/university

-etc.

Taxes are used to fund government services, reduce income inequalities, and support state and local government activities.

Taxes are used for a variety of purposes. They are primarily used to fund government services such as military, police, education, infrastructure, and social security. Taxes are also used to reduce income and wealth inequalities by transferring income to lower income groups. Additionally, taxes are used to support state and local government activities and services.

For example, in the United States, the federal government raises revenue through income taxes, corporate earnings taxes, and sales taxes on goods such as gasoline, alcohol, and tobacco. State and local governments also collect taxes, including income, property, and sales taxes, which fund activities like maintaining public parks and providing a police force.

Overall, taxes play a crucial role in financing government operations and essential public services that benefit communities.

500/4 = x/1

125 = x

125 miles per inch.

That would be week 2 and 4 (B). They are both at 12 students attending

Hope this helped!

Answer:

The correct option is B.  weeks 2 and 4.

Step-by-step explanation:

Consider the provided histogram.

The histogram shows the weekly attendance of participants in a school's study skills program.

Now, consider the Histogram.

In week 1 the Student attendance was 8.

In week 2 the Student attendance was 12.

In week 3 the Student attendance was 15.

In week 4 the Student attendance was 12.

In week 5 the Student attendance was 18.

In week 6 the Student attendance was 16.

Hence the Student attendance numbers were the same during week 2 and week 4 of the workshop.

Therefore, the correct option is B.  weeks 2 and 4

Answer:

48

Step-by-step explanation:

48 heads =48sheep. .i guess. .......

Something's odd with this question: each sheep has one head, so if you see 48 heads there are 48 sheeps.

But each sheep has also 4 legs, so if you have 48 sheeps you should see

[tex]48\cdot 4 = 192\text{ legs}[/tex]

So, unless you have some sheeps with missing legs, there must be a mistake in the question.

Answer:

x = ± 2[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Given

16 - 2x² = - 64 ( subtract 16 from both sides )

- 2x² = - 80 ( divide both sides by - 2 )

x² = 40 ( take the square root of both sides )

x = ± [tex]\sqrt{40}[/tex] = ± [tex]\sqrt{4(10)}[/tex] = ± 2[tex]\sqrt{10}[/tex]

Answer:

the answer on e2020 is 12.

The required answer is,

f(x) + f(x) + f(x) = 3ax² + 3bx + 3c

3f(x) = 3ax² + 3bx + 3c

3f(2) = 12a  + 6b + 3c

A function is defined as a relation between a set of inputs having one output each. In simple words, a function is a relationship between inputs where each input is related to exactly one output.

Now let the function be,

f(x) = ax² + bx + c

To find,

f(x) + f(x) + f(x)

we have,

f(x) + f(x) + f(x) = (ax² + bx + c) +  (ax² + bx + c) +  (ax² + bx + c)

⇒ f(x) + f(x) + f(x) = 3(ax² + bx + c)

or, f(x) + f(x) + f(x) = 3ax² + 3bx + 3c

Similarly,

3f(x) = 3(ax² + bx + c)

or, 3f(x) = 3ax² + 3bx + 3c

now to find f(2), put x =  2 in f(x). we get,

f(2) = a2² + b2 + c

or, f(2) = 4a + 2b + c

Therefore,

3f(2) = 3(4a + 2b + c)

or, 3f(2) = 12a  + 6b + 3c

hence, the required answer is,

f(x) + f(x) + f(x) = 3ax² + 3bx + 3c

3f(x) = 3ax² + 3bx + 3c

3f(2) = 12a  + 6b + 3c

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Answer:

(1,2)

Step-by-step explanation:

I just used a graphing calculator

Answer:

18x-30-10x-35=25

8x-65=25

8x-65+65=25+65

8x=90

Divide by 8 for 8x and 90

x=90/8 or 45/4 or 11 1/4 ( Answers)

Answer:

[tex]\left(s\cdot t\right)\left(x\right)=2x^2+12x+16[/tex]

[tex]\left(s-t\right)\left(x\right)=-x[/tex]

[tex]\left(s+t\right)\left(4\right)=20[/tex]

Step-by-step explanation:

Given functions are:

[tex]s\left(x\right)=x+4[/tex]

[tex]t\left(x\right)=2x+4[/tex]

Then [tex]\left(s\cdot t\right)\left(x\right)=s\left(x\right)\cdot t\left(x\right)[/tex]

or [tex]\left(s\cdot t\right)\left(x\right)=\left(x+4\right)\left(2x+4\right)[/tex]

or [tex]\left(s\cdot t\right)\left(x\right)=2x^2+4x+8x+16[/tex]

or [tex]\left(s\cdot t\right)\left(x\right)=2x^2+12x+16[/tex]

---------

Similarly

[tex]\left(s-t\right)\left(x\right)=s\left(x\right)-t\left(x\right)[/tex]

or [tex]\left(s-t\right)\left(x\right)=\left(x+4\right)-\left(2x+4\right)=x+4-2x-4[/tex]

or [tex]\left(s-t\right)\left(x\right)=-x[/tex]

---------

Similarly

[tex]\left(s+t\right)\left(4\right)=s\left(4\right)+t\left(4\right)=\left(4+4\right)+\left(2\left(4\right)+4\right)=\left(8\right)+\left(12\right)=20[/tex]

[tex]\left(s+t\right)\left(4\right)=20[/tex]

Answer:

(b)

5 cm

5 cm

108

cm

1080

1080

5 cm

5 cm

108°

1089

5 cm​

Step-by-step explanation:

Ummmmm. :)

well hope it helped you!

Answer:

Given that ΔJKL ≅ ΔUVW and ΔUVW ≅ ΔABC, complete the following statements.

Triangle JKL is congruent to triangle .

Side LK corresponds to sides .

Angle JLK corresponds to angles .

Step-by-step explanation:

Answer:

8y^50

Step-by-step explanation:

Answer:

8y^50

Step-by-step explanation:

The answer is:

The correct options are:

A)  [tex]y-2=-0.75(x-3)[/tex]

and

D) [tex]y-5=-0.75(x+1)[/tex]

To find the correct answers, we need to find a equation that meet the following charactheristics:

From the graph we can se that the function:

- Has a negative slope (is decreasing)

- Pass throught the points: (-1,5) and (3,2)

Now, discarding from the given options, we have:

[tex]y-2=-0.75(x-3)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-2=-0.75(-1-3)[/tex]

[tex]3=-0.75(-4)[/tex]

[tex]3=3[/tex]

Evaluating (3,2):

[tex]2-2=-0.75(3-3)[/tex]

[tex]0=-0.75(0)[/tex]

[tex]0=0[/tex]

We have that the equation is satisfied, so,  the line pass  through the given points.

Hence, we have that the equation A is an equation of the line shown.

[tex]y-5=-0.75(x-1)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-5=-0.75(-1-1)[/tex]

[tex]0=-3.5[/tex]

Hence, we have that since the equation is not satisfied, the line shown is not passing  through the point (-1,5) meaning that the equation is not an equation of the line shown.

So,  we have that the equation B is not equation of the line shown.

[tex]y-3=-0.75(x-2)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-3=-0.75(-1-2)[/tex]

[tex]2=-0.75(-3)[/tex]

[tex]2=2.25[/tex]

Hence, we have that since the equation is not satisfied, the line shown is not passing  through the point (-1,5) meaning that the equation is not an equation of the line shown.

So, we have that the equation B is not equation of the line shown.

(assuming you committed a mistake writing the options and the equality sign is missing)

[tex]y-5=-0.75(x+1)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-5=-0.75(-1+1)[/tex]

[tex]0=-0.75(0)[/tex]

[tex]0=0[/tex]

Evaluating (3,2)

[tex]2-5=-0.75(3+1)[/tex]

[tex]-3=-0.75(4)[/tex]

[tex]-3=-3[/tex]

We have that the equation is satisfied, so,  the line pass  through the given points.

Hence, we have that the equation B is an equation of the line shown.

Finally, we have that the correct options are:

A)  [tex]y-2=-0.75(x-3)[/tex]

and

D) [tex]y-5=-0.75(x+1)[/tex]

Have a nice day!

Answer:

[tex]P = 0.201[/tex]

Step-by-step explanation:

If the discrete random variable X represents the number of correct Colin responses then X can be represented by a binomial distribution with parameters p, n, x.

In this case p represents the probability that colin gets a correct answer, n represents the number of questions.

So the probability that Colin receives x correct questions is:

[tex]P(x) = \frac{n!}{x!(n-x)!}*p^x*(1-p)^{n-x}[/tex]

Where:

[tex]p=\frac{1}{5}[/tex]

[tex]n=10[/tex]

[tex]x=3[/tex]

[tex]P(x=3) = \frac{10!}{3!(10-3)!}*(\frac{1}{5})^3*(1-\frac{1}{5})^{10-3}[/tex]

[tex]P(x=3) = \frac{10!}{3!*7!}*\frac{1}{125}*(\frac{4}{5})^{7}[/tex]

[tex]P = 0.201[/tex]

Answer:

[tex]-\sqrt{11}[/tex]

Step-by-step explanation:

As square root value is written with both + and - signs

In Given case:

A polynomial has root [tex]\sqrt{11}[/tex]

= ±3.316

Also [tex]-\sqrt{11}[/tex]

= ±3.316

Hence [tex]-\sqrt{11}[/tex] is also root of the polynomial!

The ratio is 5:8 campers

Answer:

50

--- Ratio: 50:80

80

Step-by-step explanation:

50 would be how many girls were that the summer camp. And the 80 is how many students all together at the summer camp.

Hoped This Helped You

Have A Wonderful day

The final answer is 16

The act or process of taking one number away from another is called subtraction.

According to the problem,

This can be written as (5 x 3) + 10- 9

 =  16

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x=1/4 because, 1/4 will multiply with 4 to cancel out to have an exponent of 1

[tex]\bf (9^4)^{?}=9^1\implies 9^{4\cdot ?}=9^1\implies \stackrel{\textit{same base, the exponents must also be the same}}{4?=1\implies ?=\cfrac{1}{4}}[/tex]

Hello There!

All of the areas are indeed perfect squares.

4x4 is 16

5x5 is 25

3x3 is 9

B is the correct answer

The x - determinant of the equation is [tex]\left[\begin{array}{cc}0&-1\\-3&1\\\end{array}\right][/tex]

The y - determinant of the equation is [tex]\left[\begin{array}{cc}2&0\\1&-3\\\end{array}\right][/tex]

The system determinant is [tex]\left[\begin{array}{cc}2&-1\\1&1\\\end{array}\right][/tex]

How to find the determinants of x, y and the entire system?

The given system of equation include the following;

2x - y = 0

x + y = - 3

The x - determinant of the equation will be obtained by replacing coefficient of x with the constant terms.

[tex]\Delta x = \left[\begin{array}{cc}0&-1\\-3&1\\\end{array}\right][/tex]

The y - determinant of the equation will be obtained by replacing coefficient of y with the constant terms.

[tex]\Delta y = \left[\begin{array}{cc}2&0\\1&-3\\\end{array}\right][/tex]

The system determinant is obtained by removing the constant term and writing only the x and y coefficient in the matrix;

[tex]\Delta = \left[\begin{array}{cc}2&-1\\1&1\\\end{array}\right][/tex]

Answer:

C

Step-by-step explanation:

Answer:

The correct option is 3.

Step-by-step explanation:

The difference of squares is defined as

[tex]a^2-b^2=(a-b)(a+b)[/tex]

In option 1,

[tex](-7x+4)(-7x+4)=(-7x+4)^2[/tex]

This expression is a perfect square, therefore this is not the difference of squares. Option 1 is incorrect.

In option 2,

[tex](-7x+4)(4-7x)=(-7x+4)(-7x+4)=(-7x+4)^2[/tex]

This expression is a perfect square, therefore this is not the difference of squares. Option 2 is incorrect.

In option 3,

[tex](-7x+4)(-7x-4)=(-7x)^2-(4)^2[/tex]

This expression is the difference of squares., therefore Option 3 is correct.

In option 4,

[tex](-7x+4)(7x-4)=-(-7x+4)(-7x+4)=-(-7x+4)^2[/tex]

This expression is a perfect square, therefore this is not the difference of squares. Option 4 is incorrect.

Answer:

-30x+35

Step-by-step explanation:

Add 11 and 24

Answer:

the correct answer is BCA

Answer:

The correct option is 2.

Step-by-step explanation:

Given information: [tex]m\angle 1=110^{\circ}[/tex].

It is given that [tex]m\angle 1=110^{\circ}[/tex], so arc(BA)=110° and the central angle of arc BCA is

[tex]Arc(BCA)=360^{\circ}-Arc(BA)[/tex]

[tex]Arc(BCA)=360^{\circ}-110^{\circ}[/tex]

[tex]Arc(BCA)=250^{\circ}[/tex]

The measure of arc BC is

[tex]180^{\circ}-110^{\circ}=70^{\circ}[/tex]

The measure of arc CTA is 180° because AC is the diameter.

It means options 1 and 3 are incorrect.

The measure of arc BCA is 250°. Therefore the correct option is 2.

Step-by-step explanation:

If you lost "y" in the first equation.

[tex]\underline{+\left\{\begin{array}{ccc}2x-3y=14\\-x+3y=-6\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad x=8\\\\\text{Put the value of x to the first equation:}\\\\2(8)-3y=14\\16-3y=14\qquad\text{subtract 16 from both sides}\\-3y=-2\qquad\text{divide both sides by (-3)}\\y=\dfrac{2}{3}\\\boxed{x=8,\ y=\dfrac{2}{3}}[/tex]

If first equation is correct.

[tex]2x-3=14\qquad\text{add 3 to both sides}\\2x=17\qquad\text{divide both sides by 2}\\x=8.5\\\\\text{Put the value of x to the second equation:}\\-8.5+3y=-6\qquad\text{add 8.5 to both sides}\\3y=2.5\qquad\text{divide both sides by 3}\\y=\dfrac{2.5}{3}\\y=\dfrac{25}{30}\\y=\dfrac{5}{6}\\\\\boxed{x=8.5,\ y=\dfrac{5}{6}}[/tex]