Some plant seeds are adapted to sprout with a limited amount of water. For what environmental change are these seeds most likely adapted? earthquake tsunami drought global warming

Answer:

The most concentrated solution is the one with the highest molarity. Molarity is calculated by taking the moles of solute/ liters of solution. The already gave you the molarity, so you do not need to calculate it. The most concentrated solution is the 0.25 M KCl.

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Answer:

B. covers all body surfaces

Explanation:

epi=upper (outside of skin)

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Answer:

it is B 168 It is 100% sure

Explanation:

Answer:

B) When the urea dissolves it absorbs heat and the cold pack gets colder.

Explanation:

Cold packs usually contains two bags, one contains a water and the other inside is a form of ammonium nitrate  as the solid (s) or urea.

Breaking the inner portion activates the instant cold pack thereby releasing the solid urea into the surrounding water makes the urea to react with the water and makes it cold. This is because the reaction that takes place then undergoes an endothermic reaction, Hence heat is absorbed from the surroundings and the cold pack gets colder

The cold pack gets colder as a result of an endothermic reaction where urea dissolves in water and absorbs heat from the surroundings.

When Holly activates her instant ice pack by breaking the inner compartment, she initiates an endothermic reaction in which the solid urea dissolves in water. During this endothermic dissolution, the urea absorbs heat energy from the surrounding environment, which includes Holly's injured shoulder. This absorption of heat causes the temperature of the pack and the surrounding area to decrease, thus the pack feels cold to the touch. Therefore, the process that Holly observes as she uses the cold pack is B) When the urea dissolves it absorbs heat and the cold pack gets colder.

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Answer: d

Explanation: i got it right on acellus

Answer:

12.64 cm^3 to the nearest hundredth

Explanation:

1 L of 0.25M of HCl contains 0.25 * (1.008 * 35.45) g of HCl

= 9.1145 g HCl.

So 2 litres contain 18.229 g HCl.

So we need the volume of concentrated acid which contains 18.229 g HCl.

1.46 * 0.98 = 1.4308 g are in  1 cm^3

So 18.229 g are in  18.229/1.4308

= 12.6404 cm^3 (answer).

Answer:

the first is 5

the second is  3

The third is 5

the last one is  4:)

Explanation:

J.J. Thomson's experiments with cathode ray tubes showed that electrons are many thousand times smaller than the nucleus and negatively charged.

J.J. Thomson's experiments with cathode ray tubes implied that electrons are many thousand times smaller than the nucleus and negatively charged. Thomson discovered that cathode rays, which were later identified as streams of electrons, were deflected by electric and magnetic fields in a way that indicated they had a negative charge. Furthermore, based on the amount of deflection, Thomson was able to deduce that electrons had far less mass than atoms, leading to the conclusion that electrons are much smaller than the nucleus.

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J.J. Thomson's experiments with cathode ray tubes showed that option C) electrons are many thousand times smaller than the nucleus and negatively charged.

J.J. Thomson's experiments with cathode ray tubes implied that electrons are many thousand times smaller than the nucleus and negatively charged. He noticed that the rays in the tube were deflected towards the positive plate, indicating that they possessed a negative charge. By measuring the deflection and applying known magnetic and electric fields, Thomson was able to determine the mass-to-charge ratio of the electron and estimate its mass.

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Answer: The [tex][OH-][/tex] concentration of the aluminum hydroxide solution is [tex]1.41\times 10^{-10}[/tex]

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pOH is calculated by taking negative logarithm of hydroxide ion concentration.

[tex]pOH=-\log [OH^-][/tex]

Putting in the values:

[tex]9.85=-\log[OH^-][/tex]

[tex][OH^-]=10^{-9.85}=1.41\times 10^{-10}[/tex]

Thus the [tex][OH-][/tex] concentration of the aluminum hydroxide solution is [tex]1.41\times 10^{-10}[/tex]

Answer: [tex][OH^{-}][/tex] of the aluminium hydroxide solution is [tex]1.41 \times 10^{-6}[/tex].

Explanation:

It is given that pH is 9.85 and the relation between pH and concentration of ions is as follows.

                 pH = [tex]-log [H^{+}][/tex]

                9.85 = [tex]-log [H^{+}][/tex]

          antilog (9.85) = [tex][H^{+}][/tex]

           [tex][H^{+}] = 7.1 \times10^{-9}[/tex]

We also know that,

               [tex][H^{+}][OH^{-}] = 10^{-14}[/tex]

        [tex][OH^{-}] = \frac{10^{-14}}{7.1 \times 10^{-9}}[/tex]

                      = [tex]1.41 \times 10^{-6}[/tex]

Therefore, we can conclude that [tex][OH^{-}][/tex] of the aluminium hydroxide solution is [tex]1.41 \times 10^{-6}[/tex].

Answer:

B

Explanation:

Answer:

The two isotopes have the same number of protons within the nucleus.

Explanation:

Answer:

Protons

Explanation:

Odyssey ware

Answer:

V = 7.8 L

Explanation:

Message

The volume of gas of 0.323 mole sample of a gas at 265 K and 0.900 atm is 7.798L.

Ideal gas equation gives idea about the behavior of gas at different condition & represented as:

PV = nRT, where

On putting all these values on the above equation, we get

V = (0.323)(0.082)(265) / (0.9) = 7.798 L

Hence required volume of gas is 7.79L.

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Answer:

a

Explanation:

Answer:

0.0679

Explanation:

Answer:

answer is point no 9.o6×10-5

Answer:

A

Explanation:

Did it on edge 2020

88.98 %

The Balance Chemical Equation is as follow,

                                  2 HCl + Pb(NO₃)₂     →    2 HNO₃ + PbCl₂

According to equation,

          331.2 g (1 mole) Pb(NO₃)₂ produces  =  278.1 g (1 mole) PbCl₂

So,

                 870 g of Pb(NO₃)₂ will produce  =  X g of PbCl₂

Solving for X,

                     X  =  (870 g × 278.1 g) ÷ 331.2 g

                     X  =  730.5 g of PbCl₂

Therefore,

               Theoretical Yield =  730.5 g

Also as given,

                Actual Yield =  650 g

So using following formula for percentage yield,

                        %age Yield  =  (Actual Yield / Theoretical Yield) × 100

Putting values,

                        %age Yield  =  (650 g / 730.5 g) × 100

                        %age Yield  =  88.98 %

Brianliest please and thank you.

Final answer:

To find the percent yield of lead(II) chloride, calculate the theoretical yield based on the balanced chemical equation and the given amount of lead(II) nitrate. Then, divide the actual yield by the theoretical yield and multiply by 100% to find the percent yield.

Explanation:

To find the percent yield of lead(II) chloride, we need to compare the actual yield to the theoretical yield. The theoretical yield is the amount of lead(II) chloride that would be formed if the reaction went to completion. The actual yield is the amount of lead(II) chloride that was actually obtained in the experiment. To calculate the theoretical yield, we can use the stoichiometry of the balanced chemical equation.

From the equation, we can see that 1 mole of lead(II) nitrate reacts with 2 moles of hydrochloric acid to produce 1 mole of lead(II) chloride. Therefore, the amount of lead(II) chloride that would be formed from 870 grams of lead(II) nitrate can be calculated as follows:

Calculate the number of moles of lead(II) nitrate:

Use the mole ratio from the balanced equation to calculate the number of moles of lead(II) chloride that would be formed:

Convert moles of lead(II) chloride to grams:

The actual yield of lead(II) chloride is given as 650 grams. To calculate the percent yield, we use the formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

Substituting in the values we found:

Percent Yield = (650 / 748) x 100% = 86.77%

Answer:

82

Explanation:

Atomic number of the isotope is 26 and it has a mass number of 56

X = ⁵⁶₂₆Fe

The three main subatomic particles in an atom are

1. Proton

2. Neutron

3. Electron

The number of protons and electrons are usually equal so as to maintain electrical neutrality in the atom except in cases where it's a charged particles hence the number of proton and electrons will differ.

In this case, the atomic number is 26 and atomic numbers are also known as the number of protons (positively charged particle).

Proton = 26

Electrons = 26 (since it's a naturally charged particle)

Neutron = ?

Mass number = sum of proton and neutrons. This variation in the mass number usually leads to isotopes of an atom and this is mainly caused by variation in the number of neutrons eg. Carbon-12 and Carbon-13 have different number of neutrons.

Mass number = protons + neutrons

Neutrons = mass number - protons

Neutrons = 56 - 26

Neutrons = 30

Subatomic particles present are

Protons = 26

Electrons = 26

Neutrons = 30

Total number = (26 + 26 + 30) = 82

The total number of subatomic particles is 82.

The total number of subatomic particles in the nucleus of this common isotope of iron (with an atomic number of 26 and a mass number of 56) is the sum of protons and neutrons, which is 56.

An isotope is a variant of an element that has the same number of protons (which is the atomic number) but differs in the number of neutrons. The atomic number of iron (Fe) is 26, which reflects the number of protons in the nucleus. The mass number (56) is the combined total of protons and neutrons in the nucleus. Since we know there are 26 protons (from the atomic number), the remainder must be neutrons. So, 56 (mass number) minus 26 (atomic number) gives us 30 neutrons.

Therefore, the total number of subatomic particles in the nucleus of this isotope of iron is 26 (protons) + 30 (neutrons) = 56 particles in total.

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Answer:

1.55g of propane, C3H8

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

C3H8 +5O2 —> 3CO2 + 4H2O

Step 2:

Data obtained from the question. This include the following:

Volume (V) of O2 = 3.29L

Pressure (P) = 1.05 atm

Temperature (T) = –34°C = –34°C +273 = 239K

Number of mole O2 =...?

Gas constant (R) = 0.082atm.L/Kmol

Step 3:

Determination of the number of mole of O2 that reacted.

The number of mole of O2 that reacted can be obtained by using the ideal gas equation as follow:

PV = nRT

Divide both side by RT

n = PV /RT

n = (1.05 x 3.29)/(0.082 x239)

n = 0.176 mole

Therefore, 0.176 mole of O2 was used in the reaction.

Step 4:

Determination of the number of mole of C3H8 needed to react with 0.176 mole of O2.

This can be obtained as follow:

From the balanced equation above,

1 mole of C3H8 reacted with 5 moles of O2.

Therefore, Xmol of C3H8 will react with 0.176 mole of O2 i.e

Xmol of C3H8 = 0.176/5

Xmol of C3H8 = 0.0352 mole

Step 5:

Conversion of 0.0352 mole of C3H8 to grams.

This is illustrated below:

Mole of C3H8 = 0.0352 mole

Molar mass of C3H8 = (3x12) + (8x1) = 44g/mol

Mass of C3H8 =...?

Mass = mole x molar Mass

Mass of C3H8 = 0.0352 x 44

Mass of C3H8 = 1.55g.

Therefore, 1.55g of propane, C3H8 were used in the reaction.

Final answer:

To find out how many grams of propane will react with 3.29 L of O₂ at 1.05 atm and -34° C, we use the Ideal Gas Law to calculate moles of O₂ and then use the stoichiometry of the balanced combustion equation to determine the moles of propane. The final step is to convert the moles of propane to grams, resulting in 1.614 grams of propane required.

Explanation:

The balanced chemical equation for the complete combustion of propane (C₃H₈) is:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Calculating Grams of Propane:

First, we need to use the Ideal Gas Law PV = nRT to determine the moles of O₂. Given that P = 1.05 atm, V = 3.29 L, R = 0.0821 L·atm/mol·K, and T = 239 K (-34 °C + 273 = 239 K), we can solve for n (the number of moles of O₂).

n = PV / RT

n = (1.05 atm * 3.29 L) / (0.0821 L·atm/mol·K * 239 K)

n = 0.183 moles of O₂

From the balanced equation, we see that 1 mole of C₃H₈ reacts with 5 moles of O₂. So, we need to find out how many moles of C₃H₈ will react with 0.183 moles of O₂ by dividing by the stoichiometric coefficient of O₂:

moles of C₃H₈ = 0.183 moles of O₂ / 5 = 0.0366 moles of C₃H₈

Now, we calculate the mass of propane by multiplying the moles of C₃H₈ by its molar mass (C₃H₈ = 44.09 g/mol):

mass of C₃H₈ = 0.0366 moles * 44.09 g/mol = 1.614 grams

Therefore, 1.614 grams of propane will react with 3.29 L of O₂ at 1.05 atm and -34° C.

Answer:

Honey is   ------ A mixture and a solution

Grape Juice is ------ A mixture and a solution

Sand on the beach is ----- A mixture but not a solution

A mixture of Carbon Dioxide and nitrogen gases is ----- A mixture and a solution

Rubbing Alcohol is ----- A mixture and a solution

Explanation:

Please put 5.0 stars so other ppl know its corrrect :D

They're correct^^^

The next question:

Question:

Select the term that completes each statement.

When acetic acid is dissolved in water to make vinegar, acetic acid is the

When a small amount of carbon is dissolved in iron to make steel, the iron is the

When a small amount of hydrogen gas mixes with nitrogen gas, hydrogen is the

When carbon dioxide gas dissolves in water, water is the

When a small amount of solid iodine is mixed with ethanol, ethanol is the

Answer:

solute

solvent

solute

solvent

solvent

Explanation:

edge :) have a lovely day!

and thank you for the answers to the first one lovely person above me <3

Answer:

he can by checking up each person particle and make beyond any doubt the atom numbers are the same within the reactants and the products

Explanation:

i hope this helps

counting up each individual atom and make sure the atom numbers are the same in the reactants and the products

Explanation:

just found it on quizzlet

The elements on the periodic table that form cations in ionic compounds are primarily found in the alkali metals (group 1), alkaline earth metals (group 2), transition metals  and the representative metals. These elements lose electrons to achieve a stable electron configuration and form cations with positive charges.

The areas of the periodic table that contain elements which form cations in ionic compounds are primarily the groups that contain metals. These are the alkali metals (group 1), alkaline earth metals (group 2) and transition metals (groups 3-12). These elements lose electrons and form cations with positive charges. For example, an atom of an alkali metal like sodium (Na) loses one electron and forms a cation with a 1+ charge.

Transition elements and post-transition metals can also form cations in ionic compounds. Although their charges can vary, they often lose electrons to achieve a stable electron configuration.

These are termed as representative metals, including aluminum, zinc, and tin, which can exhibit different positive charge magnitudes based on their group and period. For instance, aluminum (Al) from group 13, and zinc (Zn) from group 12, commonly lose 3 and 2 electrons respectively to form cations.

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Answer:

pollution and habitat destruction

Explanation:

Brainliest plzz. to help a sister out

Aluminum (Al) loses three electrons to form an Al³+ cation while sulfur (S) gains two electrons to form an S²- anion. These cations and anions combine in a 2:3 ratio to form the compound Al2S3.

The electron-dot notation, also known as Lewis symbols, can be used to demonstrate the formation of an ionic compound involving the elements aluminum (Al) and sulfur (S). The aluminum atom loses three electrons to achieve a stable electron configuration, resulting in an aluminum cation with a charge of +3 (Al³+). On the other hand, sulfur gains two electrons to complete its octet, forming a sulfide anion with a charge of -2 (S²-). However, to balance the charges, we need two sulfide ions for every aluminum ion, leading to the formation of the compound Al2S3.

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Answer:

If the temperature was increased to 404 K, its volume would be 3.68 L.

Explanation:

Charles' Law gives a relationship between the volume and the temperature of the gas at constant temperature. This law states that the volume of a given amount of gas held at constant pressure is directly proportional to the temperature.

[tex]V\propto T[/tex]

[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}[/tex]

Let

[tex]V_1=2.76\ L\\\\T_1=303\ K\\\\T_2=404\ K[/tex]

Let [tex]V_2[/tex] is new volume. Using above formula we get :

[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{2.76\times 404}{303}\\\\V_2=3.68\ L[/tex]

If the temperature was increased to 404 K, its volume would be 3.68 L.

Final answer:

Potassium hydroxide is a strong base because it fully dissociates in water, A. easily releasing hydroxide ions. Potassium hydroxide (KOH) is a strong base because it easily releases hydroxide ions (OH-). When dissolved in water, KOH dissociates completely into K+ and OH- ions, increasing the concentration of hydroxide ions in the solution.

Explanation:

Potassium hydroxide (KOH) is considered a strong base because when it dissolves in water, it completely dissociates into potassium ions (K+) and hydroxide ions (OH-). This complete ionization in solution is characteristic of a strong base. Wrapping up, the correct answer to why KOH is a strong base is that it easily releases hydroxide ions into the solution.

Final answer:

Potassium hydroxide (KOH) is a strong base because it completely dissociates into potassium ions (K+) and hydroxide ions (OH-) in water, easily releasing hydroxide ions. This complete ionization defines its strength as a base and sets it apart from weak bases, which do not fully ionize.

Explanation:

Potassium hydroxide (KOH) is characterized as a strong base because it easily releases hydroxide ions when dissolved in water. The dissolution of KOH in water is a highly exothermic process where it dissociates completely into potassium (K+) and hydroxide (OH-) ions. This characteristic of complete ionization in solution is what defines a strong base, in contrast to weak bases that only partially ionize.

Unlike substances that do not dissolve well or do not conduct electricity, KOH is very soluble in water and is a good electrical conductor due to the movement of ions. Strong bases like KOH are important in various industrial processes due to their reactivity toward acids and their corrosive nature.

Understanding the behavior of strong bases can be crucial in areas such as acid-base chemistry, titrations, and pH calculations. Potassium hydroxide's complete dissociation into ions is typical of soluble metal hydroxides and is an indicator of its strength as a base.