. Store E offers a book that Karen wants for 20% off its regular price of $15.00. Store F sells the same book for $15, before a $3.00 mail-in rebate. Where should Karen purchase the book? Explain your reasoning.

Jennifer has 27 nickels and 56 dimes.

Let's use the variables n and d to represent the number of nickels and dimes Jennifer has, respectively.

We can set up two equations based on the given information:

Now, we can solve this system of equations.

We can rewrite equation 1 as n = 83 - d and substitute it into equation 2:

0.05(83 - d) + 0.10d = 6.95

4.15 - 0.05d + 0.10d = 6.95

0.05d = 6.95 - 4.15

0.05d = 2.80

d = 2.80 / 0.05

d = 56

Substituting the value of d back into equation 1, we find n = 83 - 56 = 27.

Therefore, Jennifer has 27 nickels and 56 dimes.

Answer:

The answer is C "The values of h(t) when t = 4 and 5 should be 0."

The first option is correct:

1.) if to rays are opposite.

Answer:

B. 29%

Step-by-step explanation:

if there is a 30% chance of sun tomorrow and a 20% chance of wind and no sun.

what is the probability that it is windy, given that it is not sunny.

A: it is not sunny

P(A)=0.7    (since, chance of being sunny=30% then chance of not being sunny=70%)

B:it is windy

A∩B:it is windy and not sunny

P(A∩B)=0.2  (chance=20%)

B/A:it is windy given that it is not sunny

Baye's theorem states that:

P(A∩B)=P(B/A)×P(A)

0.2=P(B/A)×0.7

⇒ P(B/A)= 2/7=0.286

             ≈ 29%

Hence, probability that it is windy, given that it is not sunny is:

 B.  29%

In part (a), the expression for cost as a single fraction is (6x^2 + 900000x) / x. In part (b), we substitute x = 240 and simplify the expression to find the cost for ordering and storing 240 units of the product.

(a) To write the expression for cost as a single fraction, we need to combine the terms in the numerator. The numerator is 6x + 900000 and the denominator is x. To combine the terms, we multiply 6x by x to get 6x^2, and then add 6x^2 + 900000x in the numerator. Therefore, the expression for cost is (6x^2 + 900000x) / x.

(b) To determine the cost for ordering and storing x = 240 units of this product, we substitute x = 240 into the expression for cost. Plugging in x = 240, we have (6(240)^2 + 900000(240)) / 240. Simplifying this expression gives us the cost for ordering and storing 240 units of the product.

The cost function C = 6x + 900000/x can be written as a single fraction as C = (6x² + 900000) / x. When x = 240, the cost for ordering and storing the units is calculated to be $5190.

The cost C of ordering and storing x units of a product is given by the formula C = 6x + 900000/x. To write this expression as a single fraction, we can find a common denominator and combine the two terms:

C = (6x²+ 900000) / x

For part (b), to determine the cost for ordering and storing x = 240 units of this product, we substitute 240 for x in the expression:
C = (6(240)² + 900000) / 240

Which simplifies to:
C = (6(57600) + 900000) / 240

C = (345600 + 900000) / 240

C = 1245600 / 240

C = 5190

Therefore, the cost for ordering and storing 240 units of this product is $5190.

To convert 2x = 2y into polar form, replace x with r cos(theta) and y with r sin(theta), then simplify, resulting in the polar equation cos(theta) = sin(theta) or theta = pi/4 + kpi, where k is an integer.

To convert the equation 2x = 2y to polar form, we need to use the relationship between Cartesian coordinates (x, y) and polar coordinates (r, (theta)). The transformations are given by x = r cos(theta) and y = r sin(theta).

Starting with our original equation 2x = 2y, we can substitute the transformations into the equation, which gives us 2(r cos(theta)) = 2(r sin(theta)). We can divide both sides by 2 to simplify, which results in r cos(theta) = r sin(theta). Since r cannot be 0 (because then both x and y would be 0, which does not satisfy the original equation), we can divide both sides by r, leading to cos(theta) = sin(theta). This equation implies that tan(theta) = 1. When tan(theta) equals 1, theta can be written as theta = arctan(1) or theta = pi/4 + kpi, where k is an integer representing the multiple full rotations around the circle.

Answer:

x=4

Step-by-step explanation:

The value of x that  makes the triangle equilateral is 4

For an equilateral triangle, all three sides must be equal in length. In this case, the sides are represented by 3x, 2x + 4, and 5x - 8.

To find the value of x that makes the triangle equilateral, set up an equation:

3x = 2x + 4 = 5x - 8

Now, solve for x:

3x = 2x + 4.

Subtract 2x from both sides:

x = 4

Now, check if x = 4 satisfies the other two parts: 2x + 4 and 5x - 8.

For 2x + 4:

2(4) + 4 = 8 + 4 = 12

For 5x - 8:

5(4) - 8 = 20 - 8 = 12

Since all three expressions are equal to 12, the value of x = 4 makes the triangle equilateral.

Learn about triangles at: https://brainly.com/question/1058720

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Answer:

Kelli's height = [tex]\frac{3}{4}x[/tex]

Step-by-step explanation:

Here, x represents the Ted's height .

As per the statement:

Kelli is [tex]\frac{3}{4}[/tex] as tall as her brother Ted.

We have to find an expression to describe Kelli's height.

then;

[tex]\frac{3}{4}[/tex] as tall as her brother Ted means [tex]\frac{3}{4}x[/tex]

⇒Kelli's height =  [tex]\frac{3}{4}x[/tex]

Therefore, an expression to describe Kelli's height is, [tex]\frac{3}{4}x[/tex]

To solve the equation cos2x - sqrt 2 sinx = 1, rewrite cos2x as 2cos^2x - 1. Use the quadratic formula to solve for cosx. Substitute the values back into the equation cos2x - sqrt 2 sinx = 1 and solve for x.

To solve the equation cos2x - √2 sinx = 1, we can use trigonometric identities and equations. First, we can rewrite cos2x as 2cos^2x - 1. So, the equation becomes 2cos^2x - √2 sinx - 1 = 0. To solve this quadratic equation, let's set 2cos^2x - √2 sinx - 1 = 0 and solve for cosx.

Next, we can use the quadratic formula to solve for cosx. The quadratic formula states that x = (-b ± √(b^2 - 4ac)) / 2a. In this case, a = 2, b = -√2 sinx, and c = -1. Plugging in these values, we can solve for cosx.

After solving for cosx, we can substitute the values back into the equation cos2x - √2 sinx = 1 and solve for x. The student's question is about solving the equation cos(2x) - √2 sin(x) = 1 for all solutions. We can use the trigonometric identities cos(2x) = 1 - 2sin2(x) or cos(2x) = 2cos2(x) - 1 to rewrite the equation. Since we have a sine term in the original equation, let's use the former identity:

cos(2x) - √2 sin(x) = 1

(1 - 2sin2(x)) - √2 sin(x) = 1

2sin2(x) + √2 sin(x) - 1 = 0

This is a quadratic equation in sin(x).

We can solve this quadratic equation for sin(x), then find x using inverse trigonometric functions. By factoring the quadratic or using the quadratic formula, we get solutions for sin(x). Then, we solve for x by considering all possible angles in the unit circle that correspond to the found sine values.

The equation cos(2x) - √2 sin(x) = 1 can be solved by using trigonometric identities to simplify and factor the equation, leading to solving for sin(x) using inverse operations.

The original equation given is cos(2x) - √2 sin(x) = 1. To solve this equation, we can use trigonometric identities to simplify the cosine term. One such identity is cos(2x) = 1 - 2sin²(x), which allows us to rewrite the equation as 1 - 2sin²(x) - √2 sin(x) = 1. From there, we subtract 1 from both sides, thus isolating the sine terms on the left: - 2sin²(x) - √2 sin(x) = 0. Factoring out the common term sin(x), we get sin(x)(-2sin(x) - √2) = 0. Setting each factor equal to zero gives us two possible solutions: sin(x) = 0 and sin(x) = -√2/2. In the context of a right triangle, these solutions correspond to specific angles where the sine value is 0 and -√2/2, respectively. The solutions can be found using standard trigonometric unit circle values or by calculating the inverse sine for -√2/2.

The probability that a dessert chosen at random contains nuts given that it contains chocolate is approximately 0.34.

To find the probability that a dessert chosen at random contains nuts given that it contains chocolate, we can use the formula for conditional probability:

P(N|C) = P(C and N) / P(C)

We are given that the probability that a dessert contains chocolate is 73% or 0.73, and the probability that a dessert containing chocolate also contains nuts is 25% or 0.25. Therefore, P(N|C) = 0.25 / 0.73 ≈ 0.34, rounded to the nearest tenth of a percent.

The probability that a dessert contains nuts given it contains chocolate is approximately 34.3%.

Probability of a dessert containing chocolate = 73% (0.73)
Probability of a dessert containing nuts given it contains chocolate = 25% (0.25)
Probability that a dessert contains nuts given it contains chocolate
Let C be the event that the dessert contains chocolate and N be the event that it contains nuts.

Therefore, the probability that a dessert chosen at random contains nuts given that it contains chocolate is approximately 34.3%.

Answer:  [tex]\overline{WX}\cong \overline{WV},\ \overline{VA}\cong\overline{AZ}[/tex]

[tex]\overline{XY}\cong\overline{YZ}[/tex]

[tex]\overline{UV}\cong \overline{UZ}\cong \overline{UX}[/tex]

Step-by-step explanation:

In the given figure we have a triangle , in which U is the circumcenter of triangle XVZ.

We know that the circumcenter is equidistant from each vertex of the triangle.

Since , the line segments which are representing the distance from the vertex and the circumcenter are [tex]\overline{UV},\ \overline{UZ},\ \overline{UX}[/tex]

Also, The circumcenter is at the intersection of the perpendicular bisectors of the triangle's sides.

Then ,  [tex]\overline{WX}\cong \overline{WV},\ \overline{VA}\cong\overline{AZ}[/tex] and [tex]\overline{XY}\cong\overline{YZ}[/tex]

Hence, the segments which are congruent are [tex]\overline{UV}\cong \overline{UZ}\cong \overline{UX}[/tex]

 [tex]\overline{WX}\cong \overline{WV},\ \overline{VA}\cong\overline{AZ}[/tex]

[tex]\overline{XY}\cong\overline{YZ}[/tex]

Answer:  Simplified form is

[tex]1\frac{5}{6}[/tex]

Step-by-step explanation:

Since we have given that

[tex]5\frac{1}{3}-3\frac{9}{18}[/tex]

Now, we will simplify it with the following steps :

[tex]5\frac{1}{3}-3\frac{9}{18}\\\\=\frac{16}{3}-3\frac{1}{2}\\\\=\frac{16}{3}-\frac{7}{2}\\\\=\frac{32-21}{6}\\\\=\frac{11}{6}\\\\=1\frac{5}{6}[/tex]

Hence, simplified form is

[tex]1\frac{5}{6}[/tex]

Method 1

Applying the Pythagorean Theorem

we know that

[tex]10^{2}= 5^{2} +a^{2}[/tex]

Solve for a

[tex]100= 25 +a^{2}[/tex]

[tex]a^{2}=100-25[/tex]

[tex]a^{2}=75[/tex]

[tex]a=\sqrt{75}=5 \sqrt{3}\ units[/tex]

therefore

the answer is

the length of the altitude is [tex]5 \sqrt{3}\ units[/tex]

Method 2

we know that

[tex]sin(60\°)=\frac{\sqrt{3}}{2}[/tex] -------> equation A

and

in this problem

[tex]sin(60\°)=\frac{a}{10}[/tex] --------> equation B

equate equation A and equation B

[tex]\frac{\sqrt{3}}{2}=\frac{a}{10}\\\\a=\frac{10\sqrt{3}}{2}\\\\a=5 \sqrt{3}\ units[/tex]

therefore

the answer is

the length of the altitude is [tex]5 \sqrt{3}\ units[/tex]

Answer:

Step-by-step explanation:

The perimeter is the sum of all sides of the figure. In this case, the perimeter of the rectangle would be: [tex]P=W+L+W+L[/tex]; where [tex]W[/tex] is width, and [tex]L[/tex] is length.

According to the problem, the width is two times the length:

[tex]W=2L[/tex]

Replacing this relation in the perimeter equation, we have:

[tex]P=2W+2L\\P=2(2L)+2L\\P=4L+2L\\P=6L[/tex]

Therefore, the perimeter is six times the length of the rectangle. The correct answer is B.