Thank you very much for your help!

Thank You Very Much For Your Help!
Thank You Very Much For Your Help!

Answers

Answer 1
For a.
[tex]x^2+y^2=25[/tex]

For b.
[tex](x-4)^2+(y-3)^2=25[/tex]

For c.
[tex](x-5)^2+(y-4)^2=9[/tex]


Hope that helps

Related Questions

What is the simplified form of the quantity of x plus 9, all over the quantity of x plus 1 + the quantity of x minus 2, all over 5

the quantity of x squared plus 4x plus 43, all over 5 times the quantity of x plus 1
the quantity of x squared plus 7x minus 18, all over 5 times the quantity of x plus 1
the quantity of x squared plus 7x minus 18, all over the quantity of x plus 6
the quantity of x squared plus 4x plus 43, all over the quantity of x plus 6

Answers

x + 9      x - 2
------  +  ------
x + 1        5

LCD = 5(x + 1) so we have

5(x + 9) + (x - 2)(x + 1)
------------------------------
          5(x + 1)

=  5x + 45 + x^2 - x - 2
     --------------------------
            5(x + 1)

=    x^2 + 4x + 43
      ------------------
          5(x + 1)

That is  A

Answer:

=    x^2 + 4x + 43

     ------------------

         5(x + 1)

Step-by-step explanation:


In which quadrant is sin positive and tan positive?

Answers

That would be Quadrant 1, which is the quadrant in the top right corner.

Sin corresponds to the y-value, so sin would be positive at Quadrants 1 and 2.

Tan, which is y/x (sin/cos), is positive at Quadrants 1 and 3.

So at quadrant 1 is where both sin and tan are positive.

Micah takes a job with a starting salary of $78,000 for the first year. He earns a 4% increase each year. How much does Micah make over seven years? $567,840 $616,067 $718,710 $718,499

Answers

Use the formula of the future value of an annuity ordinary which is
Fv=pmt [((1+r)^(t)-1)÷r]
Fv how much he made ?
PMT yearly salary 78000
R rate of increases 0.04
T time 7 years

Fv=78,000×(((1+0.04)^(7)−1)÷(0.04))
Fv=616,066.96 round your answer to get 616067

Answer:

b

Step-by-step explanation:

Evaluate 9 y 1 − y 0 9y1−y0  if y=−8 y=−8 .

Answers

9y^1 - y^0....it is not necessary to put ^1
9y - y^0...when y = -8
9(-8) - 1......anything to the ^0 = 1
-72 - 1 =
-73 <==

Answer:


Step-by-step explanation:


Write the equation of the line that passes through the points (-2,3) and (-2,5)

Answers

Since both points have -2 as the x value, the equation is x=-2

what shows 23^2-17^2 being evaluated using the difference of perfect squares method

Answers

23^2 - 17^2
= (23-17)(23+17)
=  6 * 40
= 240
remember
a²-b²=(a-b)(a+b)

so
23²-17²=(23-17)(23+17)=(6)(40)=240


Which system of inequalities is represented by the graph?

y ≤ –1/2x
y > –1
y ≥ –1/2x
y < –1
y < –1/2x
y ≥ –1
y > –1/2x
y ≤ –1

Answers

one of the lines is a horizontal line that crosses the y axis at (0,-1)...it has a solid line...it is shaded above the line...so the equation for that line is : y > = -1.

ur other line has a y int of (0,0), it has a slope of -1/2 ....it has a dashed line...it is shaded below the line.....so the equation for this line is : y < -1/2x

so ur answer is : y > = -1 and y < -1/2x

the answer is D)y ≥ 2x  

y > 1

on ed

just took the test

The length of a rectangle is 2 yd longer than its width. if the perimeter of the rectangle is 24 yd , find its area.

Answers

Width = x
Length = x +2
Perimeter = 24
Area = Width • Length = ?

Perimeter = 24 = 2(x +2) + 2(x)
= 2x + 4 + 2x
= 4x + 4
= 20 = 4x
= 5 = x

Width = x = 5, therefore Length = (5) + 2 = 7

Area = Width • Length = 5 • 7 = 35

Area = 35 yards

Solve the inequality -2x is less than or equal to 3x + 1 is less than or equal to 10

Answers

-2x[tex] \leq [/tex]3x+1[tex] \leq [/tex]10
[tex] \frac{-2x-1}{3} \leq x \leq 3[/tex]
this is what i understood from what you typed...

HELP PLEASE THANKS:(

Answers

2(2)+3y=13
4+3y=13
3y=9
y=3
The answer is B

Jennifer is on a trip and travels a distance of 150 miles. she spends some of her time walking, and some of her time travelling by train. if she spends w hours walking and t hours travelling by train, what is the meaning of 3w in the equation below? 50t + 3w =150

Answers

Final answer:

In the equation 50t + 3w = 150, 3w represents the distance Jennifer travels by walking in 3 hours.

Explanation:

In the equation 50t + 3w = 150, the term 3w represents the distance Jennifer travels by walking. Since w represents the number of hours she spends walking, 3w represents the distance she walks in 3 hours. This is because the rate of walking is constant, so if Jennifer walks for 1 hour and covers a certain distance, she would walk 3 times that distance in 3 hours.

When factored, the trinomials x^2-2x-15 and x^2-9x+20 have one binomial factor in common. What is this factor?
1. x-7
2. x+7
3. x-5
4. x+5

Answers

x^2-2x-15
(x-5)(x+3)

Proof:
-5+3=-2
-5*3=-15

x^2-9x+20
(x-4)(x-5)

Proof:
-4-5=-9
-4*-5=20

Final answer: (x-5)

The area (A) of a circle with a radius of r is given by the formula A=pier^2 and its diameter (d) is given by d=2r. Arrange the equations in the correct sequence to rewrite the formula for diameter in terms of the area of the circle.

Answers

[tex]A= \pi r^2 \ \ \text{and} \ \ d=2r \ \ \to r= \frac{d}{2} \\ \\ A= \pi *( \frac{d}{2} )^2 \\ \\A= \frac{ \pi d^2}{4} \\ \\ 4A= \pi d^2 \\ \\ d^2= \frac{4A}{ \pi } \\ \\ d= \sqrt{ \frac{4A}{ \pi } } [/tex]

Final answer:

The diameter d of a circle can be expressed in terms of the area A by first solving the area formula A = πr^2 for r, giving r = √(A/π), and then substituting r into the diameter formula d = 2r, resulting in d = 2√(A/π).

Explanation:

To rewrite the formula for the diameter of a circle in terms of the area, we start with the given formula for area A = πr^2 and the equation for diameter d = 2r. Our aim is to express the diameter d solely in terms of the area A. To achieve this, we rearrange the area formula to solve for the radius r:

A = πr^2r^2 = A/πr = √(A/π)

Then, we substitute r into the diameter formula:

d = 2rd = 2√(A/π)

Thus, the diameter d can be expressed in terms of the area A as d = 2√(A/π).

05.02)
Two right triangles are graphed on a coordinate plane. One triangle has a vertical side of 2 and a horizontal side of 6. The other triangle has a vertical side of 10 and a horizontal side of 30.

Could the hypotenuses of these two triangles lie along the same line?

No, because they are not similar triangles
No, because one is larger than the other
Yes, because they are both right triangles
Yes, because they are similar triangles

Answers

Compare the vertical/horizontal ratios to the slope of a line.  In the first triangle the vertical/horizontal ratio (which can also be described as the rise over the run, which is the slope definition) is 2/6 or 1/3.  In the second triangle, the vertical/horizontal ratio is 10/30 or 1/3.  Both of the third sides have a slope of 1/3, so the answer is the last one. 

Answer:

Yes, because they are similar triangles

Step-by-step explanation:

I got the answer right on the test

Determine if the solution set for the system of equations shown is the empty set, contains one point or is infinite. 3x + 2y = 6 x - y = 2

Answers

It contains only one point that is x=6/4 y=-1/2
Hope it helps.

What is the lateral surface area of the prism below?

1200 in2
2400 in2
1392 in2
2592 in2


Answers

check the picture below

so, the lateral, sides, area, is just the area of the sides, well, the sides are just those three rectangles

now, the rectangle is the middle is length = 25 as well as the others, but we dunno the width, say width  = c

[tex]\bf c=\sqrt{16^2+12^2}\implies c=\sqrt{256+144}\implies c=\sqrt{400}\implies c=20\\\\ -------------------------------\\\\ \textit{lateral area}\implies (25\cdot 16)+(25\cdot 12)+(25\cdot 20) \\\\\\ 400+300+500[/tex]

a lab researcher wants to find out whether mice will run through a maze quicker during the day or at night, after training. He has 100 mice available. He randomly assigns 50 of them into ech group. He trains the first group to run the maze ar 9:00am and trains the sevond group to run the maze ar 9:00 pm. Each mouse is trained the same way, and the last 3 years run times are recored. Describe what is being measured in this experiment and what variable is being manipulated?

Answers

In this case, since the run times are the one being compared and recorded, therefore the data being measured in the experiment is the run times.

The difference of the two groups of mice is the time of the day that the mice run, day or night. Therefore the variable being manipulated is the time of the day.

In triangle def, FE = 13 and angle f equals 34. Find DF to the nearest tenth.

Answers

The answer is 15.7. Hope this helps.
The answer that you are looking for is 15.7. :)

If a wheel with a radius of 70 inches spins at a rate of 600 revolutions per minute, find the approximate linear velocity in miles per hour.

Answers

This is the concept of speed:
ω=600 rev/min=600*2π rad/min=1200 rad/min
v=rω=70*1200π =84,000 in/min
converting the above in miles per hour we get:
84000 in/min
=(84000*1.6*10^(-5)*60)
=80.64 mph

What are the amplitude, period, and midline of f(x) = 3 cos(4x − π) + 2?

Answers

Amplitude: 3; period: pi/2; midline: y = 2

Answer:

The amplitude of the function is 3, period of the function is [tex]\frac{\pi}{2}[/tex] and midline of the function is 2.

Step-by-step explanation:

The given function is

[tex]f(x)=3\cos(4x-\pi)+2[/tex]               .... (1)

The standard form of a Cosine function is

[tex]g(x)=a\cos(bx+c)+d[/tex]               ... (2)

where, a is amplitude, period is [tex]\frac{2\pi}{b}[/tex] and d is midline.

From (1) and (2), we get

[tex]a=3,b=4,d=2[/tex]

The amplitude of the function is

[tex]a=3[/tex]

The period of the function is

[tex]\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}[/tex]

The midline of the function is

[tex]d=2[/tex]

Therefore the amplitude of the function is 3, period of the function is [tex]\frac{\pi}{2}[/tex] and midline of the function is 2.

Jack is building a deck that is 8 ft by 27.63 ft. He has the base built; he just needs to cover the surface with wood. When he gets to the hardware store he finds sheets of wood that are four ft by eight ft. Use estimation to determine how many sheets of wood he should buy to cover the surface of the deck.

Answers

The area of the deck is :
A ( deck ) = 8 * 27.63 = 221.04 ft²
The area of the sheet of wood:
A ( sheet ) = 4 * 8 = 32 ft²
221.04 : 32 = 6.9 ≈ 7 ( we need a whole number )
Answer: He should buy 7 sheets of wood to cover the surface of the deck.

If BC = 4.5, CD = 7.7, and AD = 16.7, find AB to the nearest tenth.

A. 2.1

B. 28.6

C. 9.8

D. 2.2

Answers

I think the answer is B not sure
ANSWER

[tex]9.8[/tex]


EXPLANATION

Triangle ABC is similar to triangle ADC,
therefore the corresponding sides sides are in the same proportion.


[tex] \frac{AB}{AD} = \frac{BC}{CD} [/tex]



We substitute the values to obtain,


[tex] \frac{AB}{16.7} = \frac{4.5}{7.7} [/tex]


We multiply through by
[tex]16.7[/tex]

to get,

[tex] AB= \frac{4.5}{7.7} \times 16.7[/tex]

This simplifies to give us,

[tex] AB= 9.75940259402....[/tex]

To the nearest tenth,

[tex] AB= 9.8[/tex]

The correct answer is C

how much would $140 invested at 6% interest compounded monthly be worth after 15 years? round your answer to the nearest cent

Answers

$343.57 is your answer

The principle amount of $140 invested at a 6% rate of interest compounded monthly be worth after 15 years will be $340.

What is compound interest?

Compound interests are those interests where the principle amount always going to change.

For example, if you give $100 to anyone with 5% interest monthly then at the end of your month your value becomes $105 and this will become the principal amount.

Given that the principal amount is $140

P = $140

The rate of interest is 6%

r = 6%

Number of time period 15 years

t = 15

Now by compounding interest formula

A = [tex][1+r/100]^{t}[/tex]

By putting all value we get

A = [tex][1 + 6/100]^{15}[/tex]

A = $340 hence, $340 will be the total amount after 15 years.

For more information about compound interest.

https://brainly.com/question/14295570

#SPJ5

If s is a sequence of consecutive multiples of 3, how many multiples of 9 are there in s? (1) there are 15 terms in s. (2) the greatest term of s is 126.

Answers


[tex]\it a_{15} =126=3\cdot42 \\\;\\a_1=3n=? \\\;\\ 3, 6, 9, 12, ... , 3n, ..., 3\cdot42 [/tex]

[tex]\it 42-(n-1) =15 \Rightarrow n-1=42-15=27 \Rightarrow n=28 \Rightarrow \\\;\\ \Rightarrow a_1=3\cdot28= 84[/tex]

Now, we have the sequence :

[tex]\it a_1= 3\cdot28 = 84 \notin M_9 \\\;\\ a_2= 3\cdot29 = 87 \notin M_9 \\\;\\ a_3= 3\cdot30 = 90 \in M_9 \\\;\\ \vdots[/tex]

[tex]\it a_{15} =3\cdot42=126 \in M_9 \\\;\\ 90\leq9\cdot k\leq126 |:9 \Rightarrow 10\leq k\leq14 \Rightarrow k \in \{10, 11, 12, 13, 14\}[/tex]

It implies 5 multiples of 9

At a glance :  {90,  99,  108,  117,  126}


Convert 7.2 ⋅ 10–3 to standard form.

72,000
7,200
0.0072
0.00072

Answers

[tex]0.0072 [/tex]
................................

0.0072 hope that helped

can someone help me with this factoring problem? I forgot how to factor.

Factor completely −3x2 + 6x − 9.

−3(x2 − 2x + 3)
−1(x2 − 6x + 9)
−3x(x2 − 2x + 3)
−3(x2 + 2x − 3)

Answers

−3x^2 + 6x − 9
= -3(x^2 - 2x + 3)

answer
-3(x^2 - 2x + 3) first one
First factor out the GCF
-3(x^2-2x+3)

To check, multiply what you took out by each term in the trinomial and make sure it's the same

-3*x^2=-3x^2
-3*-2x=6x
-3*3=-9

If [tex] 300cm^{2} [/tex]300 cm of material is available to make a box with a square base and an open top, find the maximum volume of the box in cubic centimeters. Answer to the nearest cubic centimeter without commas. For example, if the answer is 2,000 write 2000.

Answers

check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

[tex]\bf \textit{volume of a rectangular prism}\\\\ V=lwh\quad \begin{cases} l = length\\ w=width\\ h=height\\ -----\\ w=l=x \end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\ -------------------------------\\\\ \textit{surface area}\\\\ S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h \\\\\\ \boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\ -------------------------------\\\\ V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3[/tex]

so.. that'd be the V(x) for such box, now, where is the maximum point at?

[tex]\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2 \\\\\\ \cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100 \\\\\\ x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}[/tex]

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   [tex]\bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3[/tex]

how much would an 185 astronaut weigh on the moon?

Answers

He or she would be 301 pounds.

The students in the fourth grade sold 684 erasers for a fund-raiser. They sold 4 times as many erasers as the students in fifth grade. How many erasers did the students in 5 grade sell?

Answers

4 graders sold 4 times as many erasers as the students in fifth grade
so
684 / 4 = 171

answer
students in 5 grade sold 171 erasers 

The students in fifth grade sold 171 erasers

How Many Erasers Did the Fifth Grade Students Sell?

The question asks us to find out how many erasers the students in fifth grade sold based on the sales of fourth graders. We are told that the fourth grade students sold 684 erasers and that this number is 4 times the amount sold by the fifth graders. To find the number of erasers sold by the fifth graders, we need to perform a division operation.

Setting up the equation, let x be the number of erasers the fifth-grade students sold. Thus, 4x = 684. To solve for x, we divide both sides of the equation by 4. Therefore, x = 684 / 4 = 171.

So, the students in fifth grade sold 171 erasers for the fund-raiser.

Evaluate the following algebraic expressions:1.) 40y-¹, y = 5 2.) 1/m-²(m + 4), m = -8 3.) (p² – 3)-², p = 14.) (x – 1)-² / (x + 1)-², x = 2 5.) y-³ – y-², y = 2

Answers

Perform the calculations as follows.

1. [tex]40y^{-1}, \, y=5.2[/tex]
 = 40*y = 40*5.2
 = 208

2. [tex] \frac{1}{m^{-2}} (m+4),\, m=-8[/tex]
 = m²(m+4)
 = (-8)²*(-8+4)
 = -256

3. (p² - 3)⁻², p=1
 = 1/(p² - 3)²
 = 1/(1 - 3)²
 = 0.25

4. [tex] \frac{(x-1)^{-2}}{(x+1)^{-2}}, \, x=2.5 [/tex]
 [tex]= \frac{(x+1)^{2}}{(x-1)^{2}} [/tex]
 = 3.5²/1.5²
 = 5.444

5. y⁻³ - y⁻², y=2
 = 1/y³ - 1/y²
 = 1/8 - 1/4
 = -1/8

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