The average annual salary for 35 of a company’s 1200 accountants is $57,000. This describes a parameter.

Answer:

[tex]N(L)=\frac{k}{L^2}[/tex]

Step-by-step explanation:

Here, N represents the number of animal species and L represents a certain body length,

According to the question,

[tex]N\propto \frac{1}{L^2}[/tex]

[tex]\implies N=\frac{k}{L^2}[/tex]

Where, k is the constant of proportionality,

Since, with increasing the value of L the value of N is decreasing,

So, we can say that, N is dependent on L, or we can write N(L) in the place of N,

Hence, the required function formula is,

[tex]N(L)=\frac{k}{L^2}[/tex]

Certainly! When we say that the number of animal species \( N \) is inversely proportional to the square of the body length \( L \), what we mean mathematically is that as the body length increases, the number of species decreases at a rate that is the square of the increase in length. This can be represented by the following formula:

\[ N = \frac{k}{L^2} \]

Here \( N \) is the number of species, \( L \) is the body length, and \( k \) is the constant of proportionality. This constant \( k \) represents the number of species at the unit body length (when \( L = 1 \)). The constant of proportionality is determined by the specific biological context, based on empirical data or theoretical considerations.

In this formula, \( L^2 \) denotes the body length squared, and the fraction represents the inverse relationship.

In summary, to find the number of species \( N \) for a given body length \( L \), we use the inverse square relationship with the constant of proportionality \( k \).

Check the picture below.

let's recall that a kite is a quadrilateral, and thus is a polygon with 4 sides

sum of all interior angles in a polygon

180(n - 2)      n = number of sides

so for a quadrilateral that'd be 180( 4 - 2 ) = 360, thus

[tex]\bf 3b+70+50+3b=360\implies 6b+120=360\implies 6b=240 \\\\\\ b=\cfrac{240}{6}\implies b=40 \\\\[-0.35em] ~\dotfill\\\\ \overline{XY}=\overline{YZ}\implies 3a-5=a+11\implies 2a-5=11 \\\\\\ 2a=16\implies a=\cfrac{16}{2}\implies a=8[/tex]

Answer:

D.)a = 8; b = 40

Step-by-step explanation:

it is on edgeinuity

The probability that you win exactly one game is:

                               0.37

The probability that you win exactly one game is:

Probability you win first but not second+Probability you win second but not first.

=  0.60×0.25+0.40×0.55

=  0.37

( since probability of losing second game when you win first  is: 1-0.75=0.25

and probability that you lose first game is: 1-0.60=0.40 )

Final answer:

The probability of winning exactly one game, rounded to two decimal places, is 0.37.

Explanation:

Probability of winning the first game = 0.60

Probability of winning the second game if the first game is won = 0.75
Probability of winning the second game if the first game is lost = 0.55

To find the probability of winning exactly one game, we calculate the probability of winning the first game and losing the second game, plus the probability of losing the first game and winning the second game:

Answer:

(a)  99%

(b)  50%

Step-by-step explanation:

(a) All factorials after 1! have 2 as a factor, so are even. Thus 99 of the 100 factorials are even, for a probability of 99%.

__

(b) The first two sums are odd; the next two sums are even. The pattern repeats every four sums. There are 25 repeats of that pattern in 100 sums, so 2/4 = 50% of sums are even.

We're given an inner product defined by

[tex]\langle p,q\rangle=p(-2)q(-2)+p(0)q(0)+p(2)q(2)[/tex]

That is, we multiply the values of [tex]p(x)[/tex] and [tex]q(x)[/tex] at [tex]x=-2,0,2[/tex] and add those products together.

[tex]p(x)=2x^2+6x+1[/tex]

[tex]q(x)=3x^2-5x-6[/tex]

The inner product is

[tex]\langle p,q\rangle=-3\cdot16+1\cdot(-6)+21\cdot(-4)=-138[/tex]

To find the norms [tex]\|p\|[/tex] and [tex]\|q\|[/tex], recall that the dot product of a vector with itself is equal to the square of that vector's norm:

[tex]\langle p,p\rangle=\|p\|^2[/tex]

So we have

[tex]\|p\|=\sqrt{\langle p,p\rangle}=\sqrt{(-3)^2+1^2+21^2}=\sqrt{451}[/tex]

[tex]\|q\|=\sqrt{\langle q,q\rangle}=\sqrt{16^2+(-6)^2+(-4)^2}=2\sqrt{77}[/tex]

Finally, the angle [tex]\theta[/tex] between [tex]p[/tex] and [tex]q[/tex] can be found using the relation

[tex]\langle p,q\rangle=\|p\|\|q\|\cos\theta[/tex]

[tex]\implies\cos\theta=\dfrac{-138}{22\sqrt{287}}\implies\theta\approx1.95\,\mathrm{rad}\approx111.73^\circ[/tex]

The question is about calculating an inner product, norms, and the angle between two polynomials in a two-dimensional space, represented by their coefficients. We use the provided polynomials and input values from the question to calculate these values.

The mathematics problem given refers to calculating the inner product and magnitude of two polynomials, as well as the angle between them, if they are represented in a two-dimensional space.

To find the values asked in this problem, we will use the given polynomials p(x) = 2x^2+6x+1 and q(x) = 3x^2-5x-6. The inner product < p,q > is calculated as follows: p(-2)q(-2) + p(0)q(0) + p(2)q(2).

To find the magnitudes, or norms, ||p|| and ||q||, we need to solve the expression for < p,p > and < q,q > respectively, and then take the square root of the result. The angle between the vectors, denoted as Theta (θ), can be computed using the formula cos θ = < p,q > / (||p||*||q||). Because cos θ is the cosine of the angle, θ = arccos(< p,q > / (||p||*||q||)).

Note that the exact value of the inner product, norms, and angle depends on the input values of -2, 0, and 2 for each polynomial.

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Answer:

True

Step-by-step explanation:

If two events X and Y are mutually exclusive,

Then,

P(X∪Y) = P(X) + P(Y)

Let A represents the event of a diamond card and B represent the event of a heart card,

We know that,

In a deck of 52 cards there are 4 suit ( 13 Club cards, 13 heart cards, 13 diamond cards and 13 Spade cards )

That is, those cards which are heart can not be diamond card,

⇒ A ∩ B = ∅

⇒ P(A∩B) = 0

Since, P(A∪B) = P(A) + P(B) - P(A∩B)

⇒ P(A∪B) = P(A) + P(B)

By the above statement,

Events A and B are mutually exclusive,

Hence, the probability of selecting a 4 of diamonds or a 4 of hearts is an example of a mutually exclusive event is a true statement.

Answer:

  [2, 15]

Step-by-step explanation:

The graph shows the n/4 algorithm to be better (smaller run time) for n in the range 2 to 15.

Answer:

  f(x) = f(-x) = x^2 -1 is an even function

Step-by-step explanation:

When f(x) = f(-x), the function is symmetrical about the y-axis. That is the definition of an even function.

___

An odd function is symmetrical about the origin: f(x) = -f(-x).

Answer:

True

Step-by-step explanation:

The sample space consists of any possible outcome

Answer:

f(-3)=5x^2+5x*3

-f*3=5x^2+5*3x

-3f=5x^2+15x

f=-5x(x+3)/3

f(-9)=5x^2+5x*3

-f*9=5x^2+5*3x

-9f=5x^2+15x

f=-5x(x+3)/9

Step-by-step explanation:

hope it helps you?

Answer:

[tex]\large\boxed{43^o}[/tex]

Step-by-step explanation:

[tex]\text{Faucets}\to12\%\\\\p\%=\dfrac{p}{100}\to12\%=\dfrac{12}{100}=0.12\\\\12\%\ \text{of}\ 360^o\to0.12\cdot360^o=43.2^o\approx43^o[/tex]

Answer: [tex]43^{\circ}[/tex]

Step-by-step explanation:

From the given pie-chart, the percentage for faucets = 12 %

We know that every circle has angle of [tex]360^{\circ}[/tex].

Now, the central angle for faucets is given by :-

[tex]\text{Central angle}=\dfrac{\text{Percent of Faucets}}{\text{100}}\times360^{\circ}\\\\\Rightarrow\ \text{Central angle}=\dfrac{12}{100}\times360^{\circ}=43.2^{\circ}\approx43^{\circ}[/tex]

Hence, the measure of the central angle for faucets [tex]\approx43^{\circ}[/tex]

Answer:

D. 4

Step-by-step explanation:

Percent of drivers who wear seat belts = 68

Percent of drivers who do not wear seat belts = 100 - 68 = 32

Now, we know that for every 100 pull overs, 32 drivers will not be wearing belt.

32 drivers without seat-belt = 100 pullovers

1 driver without seat-belt = 100/32 pullovers

1 driver without seat-belt = 3.125 pullovers (4 pullovers)

So, a police officer should expect 4 pullovers until she finds a driver not wearing a seat-belt.

The police officer should expect to pull over approximately 4 drivers until finding one not wearing a safety belt.

To determine how many people a police officer should expect to pull over until she finds a driver not wearing a safety belt, given that only 68% of drivers wear their safety belt, follow these steps:

Step 1:

Calculate the probability of a driver not wearing a safety belt.

Since 68% of drivers wear their safety belt, the probability of a driver not wearing a safety belt is [tex]\( 1 - 0.68 = 0.32 \).[/tex]

Step 2:

Calculate the expected number of people to pull over.

The expected number of people to pull over is the reciprocal of the probability of a driver not wearing a safety belt. So, it's  [tex]\( \frac{1}{0.32} \).[/tex]

Step 3:

Perform the calculation.

[tex]\[ \frac{1}{0.32} \approx 3.125 \][/tex]

Step 4:

Interpret the result.

Since we can't pull over a fraction of a person, rounding up to the nearest whole number, the police officer should expect to pull over 4 drivers until finding one not wearing a safety belt.

So, the correct answer is option C: 4.

Answer:

a) False. Because you can live in California AND watch American Idol at the same time

b) True. Because the number of patients is a whole number, like 1, 2 or 3. There is no 1.5 patient

c) False. The actual probability should become closer to the theoretical probablity

d) True

Answer:  0.1037

Step-by-step explanation:

Given : Mean : [tex]\mu=80\text{ miles per day}[/tex]

Standard deviation : [tex]\sigma = 30\text{ miles per day}[/tex]

The formula to calculate the z-score is given by :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x = 97 miles per day ,

[tex]z=\dfrac{97-80}{30}\approx0.57[/tex]

For x = 107 miles per day ,

[tex]z=\dfrac{97-80}{30}=0.9[/tex]

The P-value =[tex]P(0.57<z<0.9)=P(z<0.9)-P(z<0.57)[/tex]

[tex]=0.8159398-0.7122603=0.1036795\approx0.1037[/tex]

Hence, the probability that a truck drives between 97 and 107 miles in a day = 0.1037

The probability that a truck drives between 97 and 107 miles in a day is approximately 0.101. We calculated this using the Z-scores for 97 and 107 miles, the standard normal distribution, and the properties of the normal distribution.

To find the probability that a truck drives between 97 and 107 miles in a day, we'll use the normal distribution. This probability is the equivalent of finding the area under the curve of the normal distribution between 97 and 107 miles.

First, we calculate the Z-scores for 97 and 107, where Z = (X - μ)/σ. Here, μ is the mean (80 miles), and σ is the standard deviation (30 miles).

Now, we look up these Z-scores in the standard normal distribution table or use a calculator with this function. Suppose the table gives us P(Z < 0.567) = 0.715 and P(Z < 0.9) = 0.816.

Then, the probability that a truck drives between 97 to 107 miles is P(0.567 < Z < 0.9) = P(Z < 0.9) - P(Z < 0.567) = 0.816 - 0.715 = 0.101.

Please note that results can vary slightly depending on the Z-table or calculator you use. All of the numbers after the decimal point are rounded to 4 decimal places.

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Final answer:

To assess if the frame can support a 20 kN load given the factor of safety for buckling of member AB is 3, the critical buckling loads for both axes, considering the end conditions, should be calculated and compared after adjusting for the safety factor.

Explanation:

To determine if the frame can support a load of P = 20 kN with a factor of safety with respect to buckling of member AB being F.S. = 3, we need to calculate the critical buckling load for member AB. The member's critical buckling load depends on its end conditions, which are pinned for the x-x axis and fixed for the y-y axis buckling. The Euler Buckling Formula, which is Pcr = (π2EI) / (KL2), where E is the modulus of elasticity, I is the moment of inertia, K is the column effective length factor, and L is the actual length of the column, can be applied separately for each axis. For pin-ended columns, K=1, and for fixed-ended columns, K=0.5.

To ensure safety, the critical load calculated for both axes should be divided by the factor of safety, F.S. = 3. If the adjusted critical load for either axis is greater than the applied load (P = 20 kN), the frame can support the load. However, specific values for E, I, and L are required to perform these calculations, which are not provided in the question. Generally, for steel, E=200 GPa is a typical value, and the values for I and L need to be determined based on the cross-sectional and length dimensions of member AB. Without these specifics, an exact answer cannot be provided.

Answer:

(a) shortest ladder length ≈ 35.7 ft (rounded to tenth)

(b) L = (d/x +1)√(16+x²) . . . . where 16 is fence height squared

Step-by-step explanation:

It works well to solve the second part of the problem first, then put in the specific numbers.

We have not been asked anything about "b", so we can basically ignore it. Using the Pythagorean theorem, we find the length GH in the attached drawing to be ...

  GH = √(4²+x²) = √(16+x²)

Then using similar triangles, we can find the ladder length L to be that which satisfies ...

  L/(d+x) = GH/x

  L = (d +x)/x·√(16 +x²)

The derivative with respect to x, L', is ...

  L' = (d+x)/√(16+x²) +√(16+x²)/x - (d+x)√(16+x²)/x²

Simplifying gives ...

  L' = (x³ -16d)/(x²√(16+x²))

Our objective is to minimize L by making L' zero. (Of course, only the numerator needs to be considered.)

___

(a) For d=24, we want ...

  0 = x³ -24·16

  x = 4·cuberoot(6) ≈ 7.268 . . . . . feet

Then L is

  L = (24 +7.268)/7.268·√(16 +7.268²) ≈ 35.691 . . . feet

__

(b) The objective function is the length of the ladder, L. We want to minimize it.

  L = (d/x +1)√(16+x²)

The objective function for the length of the ladder in terms of x is L = sqrt((x+b)^2 + d^2).

To find the length of the shortest ladder that extends from the ground to the house without touching the fence, we can use the concepts of similar triangles. Let L be the length of the ladder, x be the distance from the base of the ladder to the fence, d be the distance from the fence to the house, and b be the distance from the ground to the point the ladder touches the house. In terms of x, the objective function for the length of the ladder is:

L = sqrt((x+b)^2 + d^2)

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For this case we have the following expression:

[tex]\frac {b ^ 7} {b ^ 6}[/tex]

By definition of division of powers of the same base, we have to place the same base and subtract the exponents, that is:

[tex]\frac {a ^ m} {a ^ n} = a ^ {n-m}[/tex]

So:

[tex]\frac {b ^ 7} {b ^ 6} = b ^ {7-6} = b ^ 1 = b[/tex]

Answer:

b

Answer: [tex]b[/tex]

Step-by-step explanation:

 You need to remember a property called "Quotient of powers property". This property states the following:

[tex]\frac{a^m}{a^n}=a^{(m-n)}[/tex]

You can observe that the bases of the expression [tex]\frac{b^7}{b^6}[/tex] are equal, then you can apply the property mentioned before.

Therefore, you can make the division indicated in the exercise.

Then you get this result:

[tex]\frac{b^7}{b^6}=b^{(7-6)}=b[/tex]

Answer:

owen

Step-by-step explanation:

Answer:

Shaquille

Step-by-step explanation:

To determine the unit rate for each, divide the number of words by the number of minutes typed.

Ella: 640÷16=40

Harper: 450÷15=30

Owen: 560÷14=40

Shaquille=540÷12=45

Since Shaquille's is the most, we can tell he typed fastest.

Hope this helps!

Answer:   [tex]\bold{\dfrac{h^9}{g^9}}[/tex]

Step-by-step explanation:

The power rule is "multiply the exponents".

You must understand that the exponent of both h and g is 1.

Multiply 1 times 9 for both variables.

[tex]\bigg(\dfrac{h}{g}\bigg)^9=\bigg(\dfrac{h^1}{g^1}\bigg)^9=\dfrac{h^{1\times 9}}{g^{1\times 9}}=\large\boxed{\dfrac{h^9}{g^9}}[/tex]

Answer:

30 cubic feet

Step-by-step explanation:

Here we are given the volume of rectangular pyramid as 90 cubic feet as we are required to find the volume of rectangular prism.

For that we need to use the theorem which says that

the volume prism is always one third of the volume of the pyramid . Whether it is rectangular of triangular base. Hence in this case also the volume of the rectangular prism will be one third of the volume of the rectangular pyramid.

Volume of Rectangular prism = [tex]\frac{1}{3}[/tex] * Volume of rectangular pyramid

=  [tex]\frac{1}{3}[/tex] * 90

= 30

Answer:

270 is the answer just took test.

Step-by-step explanation:

The particle has position function

[tex]\vec r(t)=\cos t\,\vec\imath+\sin t\,\vec\jmath+3t\,\vec k[/tex]

Taking the derivative gives its velocity at time [tex]t[/tex]:

[tex]\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k[/tex]

a. The particle never moves downward because its velocity in the [tex]z[/tex] direction is always positive, meaning it is always moving away from the origin in the upward direction. DNE

b. The particle is situated 15 units above the ground when the [tex]z[/tex] component of its posiiton is equal to 15:

[tex]3t=15\implies\boxed{t=5}[/tex]

c. At this time, its velocity is

[tex]\vec v(5)=-\sin 5\,\vec\imath+\cos5\,\vec\jmath+3\,\vec k\approx\boxed{0.959\,\vec\imath+0.284\,\vec\jmath+3\,\vec k}[/tex]

d. The tangent to [tex]\vec r(t)[/tex] at [tex]t=5[/tex] points in the same direction as [tex]\vec v(5)[/tex], so that the parametric equation for this new path is

[tex]\vec r(5)+\vec v(5)t\approx\boxed{(0.284+0.959t)\,\vec\imath+(-0.959+0.284t)\,\vec\jmath+(15+3t)\,\vec k}[/tex]

where [tex]0\le t<\infty[/tex].

Answer:

The mean  of a sampling distribution of sample means is 87

The standard deviation of a sampling distribution of sample = 4

Step-by-step explanation:

* Lets revise some definition to solve the problem  

- The mean of the distribution of sample means is called μx

- It is equal to the population mean μ

- The standard deviation of the distribution of sample means is

 called  σx

- The rule of σx = σ/√n , where σ is the standard  deviation and n

  is the size of the sample

* lets solve the problem  

- A population has a mean (μ) is 87

∴ μ = 87

- A standard deviation of 24

∴ σ = 24

- A sampling distribution of sample means with sample size n = 36

∴ n = 36

∵ The mean of the distribution of sample means μx = μ

∵ μ = 87

∴ μx = 87

* The mean  of a sampling distribution of sample means is 87

∵ The standard deviation of a sampling distribution of sample

   means σx  = σ/√n

∵ σ = 24 and n = 36

∴ σx = 24/√36 = 24/6 = 4

* The standard deviation of a sampling distribution of sample = 4

The mean of the sampling distribution of sample means is 87, identical to the population mean. The standard deviation of this sampling distribution is 4, which is the population standard deviation (24) divided by the square root of the sample size (36).

When working with populations and sampling distributions, the Central Limit Theorem is critical for understanding the behavior of sample means. Given a population with mean (μ) and standard deviation (σ), the mean of the sampling distribution of sample means will be the same as the population mean, and the standard deviation of the sampling distribution (σx) is equal to the population standard deviation divided by the square root of the sample size (n).

In this instance, the population has a mean (μ) of 87 and a standard deviation (σ) of 24. For a sample size (n) of 36, the mean of the sampling distribution of sample means (μx) is equal to the population mean:

μx = μ = 87

The standard deviation of the sampling distribution of sample means (σx) is calculated as follows:

σx = σ / √ n = 24 / √ 36 = 24 / 6 = 4

Therefore, the mean of the sampling distribution is 87, and standard deviation is 4.

Answer: There are 6045 millions world population during the period of 1950 to 2000.

Step-by-step explanation:

Since we have given that

The world population in the second half of the 20 the century by the equation:

[tex]P(t)=2560e^{0.017185t}[/tex]

We need to find the average world population during the period of 1950 to 2000.

So, there are 50 years between 1950 to 2000.

So, t = 50 years.

Therefore, the  average population would be

[tex]P(50)=2560e^{0.017185\times 50}\\\\P(50)=6045.15\\\\P(50)\approx 6045\ millions[/tex]

Hence, there are 6045 millions world population during the period of 1950 to 2000.

Answer:

  r ≈ 13.01

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Cos = Adjacent/Hypotenuse

  cos(67.4°) = 5.00/r . . . . . . filling in the given values

Solving for r gives ...

  r = 5.00/cos(67.4°) ≈ 13.01

_____

Check your requirements for rounding. We rounded to 2 decimal places because the x-coordinate, 5.00, was expressed using 2 decimal places.

Answer:

D

Step-by-step explanation:

It's a repeating pattern

Answer:

D

Reasoning:

the pattern keeps the previous color and alternates between blue and red.  The pattern is also increasing in number by 1.  Therefore there would be no reason for the fourth step to change previous color or numbers.  That eliminates A and B.  For C, since the pattern is adding a different color clockwise in each step, it is more likely that the pattern will continue to alternate, therefore D is most likely.

[tex]\bf 5y^4+11y^2+2\implies 5(y^2)^2+11y^2+2\implies (5y^2+1)(y^2+2)[/tex]

For this case we must factor the following polynomial:

[tex]5y ^ 4 + 11y ^ 2 + 2[/tex]

We rewrite [tex]y ^ 4[/tex]as [tex](y^ 2) ^ 2[/tex]:

[tex]5 (y ^ 2) ^ 2 + 11y ^ 2 + 2[/tex]

We make a change of variable:

[tex]u = y ^ 2[/tex]

We replace:

[tex]5u ^ + 11u + 2[/tex]

we rewrite the middle term as a sum of two terms whose product of 5 * 2 = 10 and the sum of 11.

So:

[tex]5u ^ 2 + (1 + 10) u + 2[/tex]

We apply distributive property:

[tex]5u ^ 2 + u + 10u + 2[/tex]

We factor the highest common denominator of each group.

[tex](5u ^ 2 + u) + (10u + 2)\\u (5u + 1) +2 (5u + 1)[/tex]

We factor again:

[tex](u + 2) (5u + 1)[/tex]

Returning the change:

[tex](y ^ 2 + 2) (5y ^ 2 + 1)[/tex]

ANswer:

[tex](y ^ 2 + 2) (5y ^ 2 + 1)[/tex]

Answer:

The probability is 0.20

Step-by-step explanation:

a) Lets revise how to find the z-score

- The rule the z-score is z = (x - μ)/σ , where

# x is the score

# μ is the mean

# σ is the standard deviation

* Lets solve the problem

- Bob's golf score at his local course follows the normal distribution

- The mean is 92.1

- The standard deviation is 3.8

- The score on his next round of golf will be between 82 and​ 89

- Lets find the z-score for each case

# First case

∵ z = (x - μ)/σ

∵ x = 82

∵ μ = 92.1

∵ σ = 3.8

∴ [tex]z=\frac{82-92.1}{3.8}=\frac{-10.1}{3.8}=-2.66[/tex]

# Second case

∵ z = (x - μ)/σ

∵ x = 89

∵ μ = 92.1

∵ σ = 3.8

∴ [tex]z=\frac{89-92.1}{3.8}=\frac{-3.1}{3.8}=-0.82[/tex]

- To find the probability that the score on his next round of golf will

  be between 82 and​ 89 use the table of the normal distribution

∵ P(82 < X < 89) = P(-2.66 < z < -0.82)

∵ A z-score of -2.66 the value is 0.00391

∵ A z-score of -0.82 the value is 0.20611

∴ P(-2.66 < z < -0.82) = 0.20611 - 0.00391 = 0.2022

* The probability is 0.20

Normal distribution and z-scores are applied in this context. The z-scores for the given range are calculated, followed by finding the correlating probabilities from the z-table, resulting in the probability of Bob's next score falling within the range of 82-89.

To answer this question, we will utilize the concept of z-scores in a normal distribution. A z-score basically explains how many standard deviations a data point (in this case, a golf score) is from the mean.

Firstly, we calculate the z-scores for the limits given. Here, 82 and 89. The formula we use is Z = (X - μ) / σ, where X is the golf score, μ is the mean, and σ is the standard deviation.

The calculated z-scores are then used as references, and we refer a z-table (also known as a standard normal table) to find the probabilities which correspond to these z-scores, and the result is a probability of Bob's next golf score being between 82 and 89.

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The total number of ways are:

                       462

When we are asked to select r items from a set of n items that the rule that is used to solve the problem is:

Method of combination.

Here the total number of bills of different values are: 7

i.e. n=7

(  $1, $2, $5, $10, $20, $50, and $100 )

and there are atleast five of each type of bill.

Also, we have to choose 5 bills i.e. r=5

The repetition is  allowed while choosing bills.

Hence, the formula is given by:

[tex]C(n+r-1,r)[/tex]

Hence, we get:

[tex]C(7+5-1,5)\\\\i.e.\\\\C(11,5)=\dfrac{11!}{5!\times (11-5)!}\\\\C(11,5)=\dfrac{11!}{5!\times 6!}\\\\\\C(11,5)=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{5!\times 6!}\\\\\\C(11,5)=\dfrac{11\times 10\times 9\times 8\times 7}{5!}\\\\\\C(11,5)=\dfrac{11\times 10\times 9\times 8\times 7}{5\times 4\times 3\times 2}\\\\\\C(11,5)=462[/tex]

           Hence, the answer is:

                  462

There are 462 different possible ways to choose five bills from a set of seven types with repetition allowed.

To determine the number of different ways to choose five bills from a set of bills with values $1, $2, $5, $10, $20, $50, and $100, we can use the combinatorial concept known as "combinations with repetition."

Given:

- Bill values:  [tex]\( \{1, 2, 5, 10, 20, 50, 100\} \)[/tex]

- Total number of types of bills: ( n = 7 )

- Number of bills to choose: ( r = 5 )

The formula for combinations with repetition (also known as "stars and bars") is:

\[

\binom{n + r - 1}{r}

\]

Substituting the values ( n = 7 ) and ( r = 5 ):

[tex]\[\binom{7 + 5 - 1}{5} = \binom{11}{5}\][/tex]

Now, calculate  [tex]\( \binom{11}{5} \):[/tex]

[tex]\[\binom{11}{5} = \frac{11!}{5!(11-5)!} = \frac{11!}{5! \cdot 6!}\][/tex]

First, compute the factorials:

[tex]\[11! = 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\]\[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\]\[6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720\][/tex]

Next, compute [tex]\( \frac{11!}{6!} \):[/tex]

[tex]\[\frac{11!}{6!} = 11 \times 10 \times 9 \times 8 \times 7\]\[= 11 \times 10 = 110\]\[110 \times 9 = 990\]\[990 \times 8 = 7920\]\[7920 \times 7 = 55440\][/tex]

Now, compute:

[tex]\[\frac{55440}{120} = 462\][/tex]

Therefore, the number of different possible ways to choose the five bills is:

[tex]\[\boxed{462}\][/tex]

Answer: Last option.

Step-by-step explanation:

Given the inequality [tex]|x| > 5[/tex] you need to set up two posibilities. These posibilities are the following:

- FIRST POSIBILITY :

[tex]x>5[/tex]

- SECOND POSIBILTY:

 [tex]x<-5[/tex]

Then you get that:

 [tex]x<-5\ or\ x>5 [/tex]  

Therefore, through this procedure, you get that the solution set of the inequality  [tex]|x| > 5[/tex]  is this:

{[tex]x|x<-5\ or\ x>5[/tex]}

Answer:

C. {x|x < -5 or x > 5}

Step-by-step explanation: