Mathematics College

The average winter snowfall in City A is 105 cm. City B usually gets 2.8 m of snow each winter. Compare the yearly snowfall in the two cities. Complete parts a and b. (A) the difference in one year is __ m. (B) the difference over two years is ___ cm

Answers

Answer 1
We see that city A gets 105 cm of snow while city B gets 2.8 m. The first thing we do is make both measurements equal to each other. This can be done by either converting city A's 105 centimeters to meters or city B's meters to centimeters. But the question specifically calls for both, so we get both measurements.

City A: 105 centimeters OR 1.05 meters
City B: 280 centimeters OR 2.8 meters

Now that we know the measurements, let's look at the first problem. (A) asks for the difference in one year in meters. The difference of course means subtraction. Now it's here where I personally am confused on what it asking for in terms of which city is it asking for us to subtract from, but using an educated guess, I'll say we're subtracting from city B because if we were to subtract from city A, we'd have a negative, and you can't have a negative amount of snow, only 0 snow.

So once again, for question (A), we subtract 1.05 from 2.8 (2.80 - 1.05) and we get 1.75 meters of snow.

Question (B) asks for the difference during two years in centimeters, so we multiply both measurements by 2 and use the centimeter measurements. (105 x 2 = 210) (280 x 2 = 560) Subtract 560 from 210 (560 - 210) and we get 350 centimeters.

So your answers are: (A) 1.75 meters (B) 350 centimeters

I hope this helps!

Related Questions

a soccar team spent $55 dollars on supplies for a car wash then earned $275 whats their total after paying for supplies

Answers

To find what profit they made, subtract what they earned from what they spent money on. 275-55=220. They made a total of $220 after paying for supplies. I hope this helps! :)

Find all solutions to the equation csc theta +sqrt2 = 0

Answers

Theta = 7pi/4+2pi*n
Theta = 5pi/4+2pi*n

The tables represent two linear functions in a system.

What is the solution to this system?

Answers

The solution to this system is (x, y) = (8, -22).

The y-values get closer together by 2 units for each 2-unit increase in x. The difference at x=2 is 6, so we expect the difference in y-values to be zero when we increase x by 6 (from 2 to 8).

You can extend each table after the same pattern.

In table 1, x-values increase by 2 and y-values decrease by 8.

In table 2, x-values increase by 2 and y-values decrease by 6.

The attachment shows the tables extended to x=10. We note that the y-values are the same (-22) for x=8 (as we predicted above). That means the solution is ...

... (x, y) = (8, -22)

Answer:

(8,-22)

Step-by-step explanation:

Table 1)

To form equation we will use two point slope form

[tex](x_1,y_1)=(-4,26)\\(x_2,y_2)=(-2,18)[/tex]

Formula :[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Substitute the values :

[tex]y-26=\frac{18-26}{-2+4}(x+4)[/tex]

[tex]y-26=-4(x+4)[/tex]

[tex]y-26=-4x-16[/tex]

[tex]y=-4x-16+26[/tex]

[tex]y=-4x+10[/tex] ---1

Table 2)

To form equation we will use two point slope form

[tex](x_1,y_1)=(-4,14)\\(x_2,y_2)=(-2,8)[/tex]

Formula :[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Substitute the values :

[tex]y-14=\frac{8-14}{-2+4}(x+4)[/tex]

[tex]y-14=-3(x+4)[/tex]

[tex]y-14=-3x-12[/tex]

[tex]y=-3x+2[/tex] ---2

Now we are supposed to solve 1 and 2

Substitute the value of y from 1 in 2

[tex]-4x+10=-3x+2[/tex]

[tex]8=x[/tex]

Substitute the value of x in 2

[tex]y=-3(8)+2[/tex]

[tex]y=-22[/tex]

Hence the solution to this system is (8,-22)


John has taken out a loan for college. He started paying off the loan with a first payment of $100. Each month he pays, he wants to pay back 1.1 times the amount he paid the month before. Explain to John how to represent his first 20 payments in sequence notation. Then explain how to find the sum of his first 20 payments, using complete sentences.

Answers

Let a_0 = 100, the first payment. Every subsequent payment is the prior payment, times 1.1. In order to represent that, let a_n be the term in question. The term before it is a_n-1. So a_n = 1.1 * a_n-1. This means that a_19 = 1.1*a_18, a_18 = 1.1*a_17, etc. To find the sum of your first 20 payments, this sum is equal to a_0+a_1+a_2+...+a_19. a_1 = 1.1*a_0, so a_2 = 1.1*(1.1*a_0) = (1.1)^2 * a_0, a_3 = 1.1*a_2 = (1.1)^3*a_3, and so on. So the sum can be reduced to S = a_0 * (1+ 1.1 + 1.1^2 + 1.1^3 + ... + 1.1^19) which is approximately $5727.50

A store is selling two mixtures of coffee beans in one-pound bags. The first mixture has 12 ounces of Sumatra combined with 44 ounces of Celebes Kalossi, and costs $42. The second mixture has 44 ounces of Sumatra and 12ounces of Celebes Kalossi, and costs $30. How much does one ounce of Sumatra and one ounce of Celebes Kalossi cost?

Answers

Create 2 equations for the given problem

12s + 44c = 42
44s + 12c = 30

Take either equation and solve for either s or c.
12s + 44c = 42
12s = 42 - 44c
s = (42 - 44c) / 12
s = (21 - 22c) / 6

Substitute into 2nd equation

44s + 12c = 30
22((21 - 22c) / 3) + 12c = 30
22(21 - 22c) + 36c = 90
-448c +462  = 90
-448c = -372
c = -372/-448
c = 93/112
c = 0.83

Substitute into the 2nd equation

44s + 12c = 30
44s = 30 - 12c
s = (30 - 12 (93/112)) / 44
s = (30 - 279 / 28) / 44)
s = (30 - 9 27/28) / 44
s = 0.46

Prove
12s + 44c = 42
12(0.46) + 44(0.83) = 42
5.52 + 36.52 = 42
42.04 = 42

44s + 12c = 30
44(0.46) + 12(0.83) = 30
20.24 + 9.96 = 30.16

Assuming minor rounding issues this looks accurate.

what is the area of a circle with a radius of 7 inches

Answers

Area formula is A=πr2 
A=3.1416(radius)2 (radius is 7)
A=3.1416(49) 
A=153.94 
The area is 153.94 inches.
Hope that was helpful :)

Answer is provided in the image attached.

486 is what percent of 900

Answers

486/900 = .54 = 54%. .......

Use rounding or compatible numbers to estimate sum 198+727

Answers

198 round to 200
727 round to 730
200+ 730 is 930

The answer is 930. Hope this helps!

It is desired to estimate the mean gpa of each undergraduate class at a large university. assume that the variance of the gpas is 1.44. how large a sample is necessary to estimate the mean gpa within 0.25 at the 99% confidence level

Answers

Final answer:

To estimate the mean GPA of each undergraduate class at a large university within a margin of error of 0.25 at a 99% confidence level, approximately 187 samples are needed.

Explanation:

To estimate the mean GPA of each undergraduate class at a large university within a margin of error of 0.25 at a 99% confidence level, we need to determine the required sample size. In this case, we can use the formula for sample size determination, which is:

n = (Z^2 * σ^2) / E^2

Where:

n is the required sample sizeZ is the Z-score associated with the desired confidence level (99% corresponds to a Z-score of approximately 2.58)σ^2 is the variance of the GPAs (given as 1.44)E is the desired margin of error (0.25)

Plugging in the values, we get:

n = (2.58^2 * 1.44) / 0.25^2

n ≈ 186.43

Therefore, we need a sample size of approximately 187 to estimate the mean GPA within a margin of error of 0.25 at a 99% confidence level.

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Help Please question in the file.

Answers

check the picture below.

you have 5 antiques and want to display 3 on a shelf. how many different 3 antique arrangements are possible

Answers

[tex]\bf _{n}P_{r}=\cfrac{n!}{(n-r)!}\qquad\qquad _{5}P_{3}=\cfrac{5!}{(5-3)!}[/tex]


Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 50 km/h. After six hours, the velocity of the car is 54 km/h.

Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points)

Part B: How can you graph the equation obtained in Part A for the first seven hours? (5 points)

Answers

part A)

[tex]\bf \begin{array}{ccllll} hours(x)&velocity(y)\\ -----&-----\\ 2&50\\ 6&54 \end{array}\\\\ -------------------------------\\\\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 2}}\quad ,&{{ 50}})\quad % (c,d) &({{ 6}}\quad ,&{{ 54}}) \end{array}[/tex]

[tex]\bf slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{54-50}{6-2}\implies \cfrac{4}{4}\implies 1 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-50=1(x-2)\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-50=x-2\implies \boxed{y-x=48}\impliedby \begin{array}{llll} standard\\ form \end{array}[/tex]

part B)

well, to graph a LINEar equation, since it's just a LINE, you simply need two points to graph a line, and since we know that y - x = 48.... if you want to know what's "y" when x = 7? or 7 hours, well

y - (7) = 48
y = 48 + 7
y = 55

so.. that's the point for the 7th hour, 7, 55, and you can pick any other point above, and graph it away.

A pizza parlor sold 38 1/8 pizzas during a dinner hour. If each pizza contained 8 slices, how many slices of pizza were sold?

Answers

38*8 = 304

304 + 1 =305 slices were sold

8(38 1/8)      

8(38)+8(1/8)

304+1

305 slices.

solve for y 6y-8=3y-2

Answers

6y-8 =3y-2

subtract 3y from both sides

3y-8 = -2

add 8 to both sides

3y=6

y=6/3 =2

 y = 2

The social studies teacher is giving a test worth 80 points, and containing 34 questions. There are 2 point and 4 point questions on the test. How many of each type of question are on the test? Show your work. A. List the two equations B. Find each type of question

Answers

x is 2 pt questions
y is 4 pt questions
x+y=34
2x+4y=80
Multiply the top equation by -2 to use elimination technique
-2x-2y=-68
Then combine the two equations (x is cancelled out)
2y=12
y=6
If there are 6 four point questions, there must be 28 two point questions to get a total of 34 questions.

How many positive integers not exceeding 1000 are not divisible by either 4 or 6?

Answers

Final answer:

There are 667 positive integers not exceeding 1000 that are not divisible by either 4 or 6.

Explanation:

This is a question about number theory and involves the comprehension of divisibility. To identify the positive integers that are not divisible by either 4 or 6 and not exceeding 1000 is an application of the principle of inclusion and exclusion.

First, we need to figure out how many numbers up to 1000 are divisible by 4, which is 1000/4 = 250. Then, we look at how many numbers are divisible by 6, which is 1000/6 = about 166 (we only consider the whole numbers).

However, some numbers are divisible by both 4 and 6, so we have over-counted and need to correct for this. These would be the numbers divisible by the least common multiple (LCM) of 4 and 6, which is 12. There are 1000/12 = about 83 such numbers.

Thus, according to the principle of inclusion and exclusion, the total number of numbers divisible by 4 or 6 would be 250 + 166 - 83 = 333. The last step is to subtract this from the total number of integers from 1 to 1000, so the answer would be 1000 - 333 = 667.

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today there are 3,659 thousand elementary and secondary teachers employed in a certain country. this number is expected to increase to 3,856 thousand by next decade. what is the percent increase?

Answers

percent increase = (new number - original number) / original number...* 100
                           = (3856 - 3659) / 3659...* 100
                          = 197 / 3659....* 100
                          = 0.0538 * 100
                          = 5.38% <==

py+7=6y+q
what is the answer for this question (linear equations with unknown coefficients)?

Answers

Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)

Answer:

The required equation is  [tex]y =\frac{(q-7)}{(p-6)}[/tex].

Step-by-step explanation:

Consider the provided equation.

[tex]py+7=6y+q[/tex]

We need to simplify the equation and convert it into a linear equation with unknown coefficients.

Subtract 6y from both sides.

[tex]py - 6y + 7 = q[/tex]

Subtract 7 from both sides.

[tex]py - 6y = q - 7[/tex]  

Take y common from left side.

[tex]y(p-6) = q-7[/tex]

 Divide both sides by p-6.

 [tex]y =\frac{(q-7)}{(p-6)}[/tex]

Hence, the required equation is  [tex]y =\frac{(q-7)}{(p-6)}[/tex].

To make the two triangles below similar, what would the values of x and y have to be?

Answers

i dont really remember how to solve this since i done this some time ago the angles must be the same i would say d since 5 the bigger triangle is five times bigger 

~ hope this helps ~
First, y and 40 degrees would have to be the same; thus, y = 40 degrees.

Second, form and solve the ratio (x/25) = (6/30).  30x=25(6)=150.  Thus, x=5.

A basket contains five apples and seven peaches. Four of the apples and two of the peaches are rotten. You randomly pick a piece of fruit. It is fresh or it is an apple. Find the probability of this occuring.

Answers

2/35possible outcomes:5*7=35fresh or apple = 22/35

Answer:[tex]\frac{5}{6}[/tex]

Step-by-step explanation:

Given

5 apples and 7 peaches out of which 4 apples and 2 peaches is rotten

i.e. 1 apple and 5 peaches is fresh

probability of fresh fruit is =[tex]\frac{6}{12}[/tex]

probability of apple =[tex]\frac{5}{12}[/tex]

Probability of both =[tex]\frac{1}{12}[/tex]

Probability of fresh or an apple is=[tex] \frac{6}{12}+\frac{5}{12}-\frac{1}{12}[/tex]

=[tex]\frac{5}{6}[/tex]

palace help me solve these two equations 14, 15

Answers

14)

check the picture below... so.. is just a semi-circle and a rectangle, nothing fancy, get their area, sum them up.

15)

so... the voter turnout, is referring to, what's the percentage that voted, which year has the highest percentage... well, we simply check the percentage of the value provided from the total eligible voters, keeping in mind that, all eligible voters are the 100%

so.. for 1944

[tex]\bf \begin{array}{ccllll} amount&\%\\ ------&----\\ 86,607,000&100\\ 47,976,670&x\\ \end{array}\implies \cfrac{86,607,000}{47,976,670}=\cfrac{100}{x} \\\\\\ x=\cfrac{100\cdot 47,976,670}{86,607,000}\implies x\approx 55.39583405498[/tex]

for 1984

[tex]\bf \begin{array}{ccllll} amount&\%\\ -----&-----\\ 167,727,000&100\\ 92,659,000&x \end{array}\implies \cfrac{167,727,000}{92,659,000}=\cfrac{100}{x} \\\\\\ x=\cfrac{100\cdot 92,659,000}{167,727,000}\implies x\approx 55.2439380660239[/tex]

If 5 workers can pave 10 driveways in 30 days, how many days would it take 20 workers to pave 38 driveways?

Answers

Given that 5 workers can pave 10 driveways in 30 days, then:
let x be the number of days that can take 20 workers to complete 38 drive ways;
therefore:
proportion of work completed by 5 workers will be:
5*30/10
=15
proportion of work completed by 20 workers will be:
20*x/38
The time taken for 20 workers to complete 38 driveways will be:
15=20/38x
x=15*38/20
x=28 1/2
The answer is 28.5 days

Samantha threw an apple out of a window. The equation -16t^(2)+120=y can be used to represent the apple's height above the ground, where t = time in seconds after she threw the apple. how long did it take for the apple to hit the ground. Round to nearest hundredth

Answers

check the picture below, y = 0 when that happens

[tex]\bf -16t^2+120=0\implies 120=16t^2\implies \cfrac{120}{16}=t^2\implies \cfrac{15}{2}=t^2 \\\\\\ \sqrt{\cfrac{15}{2}}=t[/tex]

bear in mind the square root would give us a +/- roots, however, since this is seconds, a negative unit would be unfeasible, thus we only used the positive root from it.

Question help a robotic rover on mars finds a spherical rock with a diameter of 1313 centimeters. the rover picks up the rock and lifts it 1515 centimeters straight up. the rock has a specific gravity of 5.255.25. the gravitational acceleration on mars is 3.73.7 meters per second squared. if the​ robot's lifting arm has an efficiency of 3535​% and required 1212 seconds to raise the rock 1515 ​centimeters, how much power​ (in watts) did the arm​ use?

Answers

Due to apparent doubling of numbers in the question, assume
diameter=13 cm/2=0.065m
h=15 cm=0.15m
rho=5.25*1000=5250 kg/m^3
eta=35%=0.35 [efficiency]
t=12 s
g=3.7 m/s^2

mass, m=rho*V=rho*(4pi/3)(r^3)
=5250 kg/m^3 * (4pi/3)(0.065)^3 m^3
=1.922 kg

Work done in lifting h=0.15m
W=mgh
=1.922pi kg * 3.7 m/s^2 * 0.15 m
=1.067pi kg (m/s)^2
=1.067pi J

Average power required, with efficiency eta=0.35
P=(W/t)/eta
=(1.067pi J )/ (12 s) /0.35
=0.254pi J/s
=0.798W (approx.)

You have been offered a project paying $300 at the beginning of each year for the next 20 years. what is the maximum amount of money you would invest in this project if you expect 9 percent rate of return to your investment?

Answers

This is a simple problem with some quick addition and subtraction, and a bit of multiplication.

First we figure out how much money you're spending in total, which is $300 each year, for 20 years, so 300 x 20 = 6,000. Now, since the problem is asking for a maximum amount for percentage rate, this means we find the 9% for all 20 years combined and not individually. 9% of 6,000 is of course 540, so if we subtract 540 from 6,000, we get 5,460.

This means your answer is $5,460

Determine whether the given differential equation is exact. if it is exact, solve it. (if it is not exact, enter not.) (3x + 6y) dx + (6x − 8y3) dy = 0

Answers

[tex]\underbrace{(3x+6y)}_{M(x,y)}\,\mathrm dx+\underbrace{(6x-8y^3)}_{N(x,y)}\,\mathrm dy=0[/tex]

The ODE is exact if [tex]\dfrac{\partial M}{\partial y}=\dfrac{\partial N}{\partial x}[/tex]. We have

[tex]\dfrac{\partial M}{\partial y}=6[/tex]
[tex]\dfrac{\partial N}{\partial x}=6[/tex]

so the equation is indeed exact.

We're looking for a solution of the form

[tex]\Psi(x,y)=C[/tex]

By the chain rule, we have

[tex]\dfrac{\partial\Psi}{\partial x}+\dfrac{\partial\Psi}{\partial y}\dfrac{\mathrm dy}{\mathrm dx}=0[/tex]
[tex]\iff\dfrac{\partial\Psi}{\partial x}\,\mathrm dx+\dfrac{\partial\Psi}{\partial y}\,\mathrm dy=0[/tex]

which means [tex]\dfrac{\partial\Psi}{\partial x}=M[/tex] and [tex]\dfrac{\partial\Psi}{\partial y}=N[/tex].

Now

[tex]\dfrac{\partial\Psi}{\partial x}=M\implies\displaystyle\int\frac{\partial\Psi}{\partial x}\,\mathrm dx=\int M\,\mathrm dx[/tex]
[tex]\implies\Psi(x,y)=\dfrac32x^2+6xy+f(y)[/tex]

Differentiating with respect to [tex]y[/tex] yields

[tex]\dfrac{\partial\Psi}{\partial y}=N\implies 6x+f'(y)=6x-8y^3[/tex]
[tex]\implies f'(y)=-8y^3\implies f(y)=\displaystyle\int(-8y^3)\,\mathrm dy=-2y^4+C[/tex]

and so the general solution is

[tex]\Psi(x,y)=\dfrac32x^2+6xy-2y^4+C=C[/tex]
[tex]\implies\Psi(x,y)=\dfrac32x^2+6xy-2y^4=C[/tex]
Final answer:

The given differential equation (3x + 6y) dx + (6x − 8y3) dy = 0 is exact because its mixed partial derivatives are equal. To solve it, first integrate M with respect to x to get a function involving an unknown function of y, then compare it with N to determine the unknown function.

Explanation:

To determine if the given differential equation is exact, we need to check if the partial derivative of M with respect to y is the same as the partial derivative of N with respect to x. In this given differential equation (3x + 6y) dx + (6x − 8y3) dy = 0, M = 3x + 6y and N = 6x - 8y3. First, compute the partial derivative of M with respect to y (∂M/∂y) which is 6, then the partial derivative of N with respect to x (∂N/∂x), which is 6 as well. Since ∂M/∂y=∂N/∂x, the given differential equation is exact.

To solve this exact differential equation, we integrate M dx, i.e., ∫M dx, to get ψ(x,y) =1.5x^2+6xy+h(y), where h(y) is an arbitrary function of y. Next, differentiate ψ(x,y) with respect to y, then compare the result with N: ψy=6x+dh/dy=6x-8y³. Solving for dh/dy gives dh/dy=-8y³, so integrating this gives h(y)=-2y⁴+C, where C is a constant. Therefore, the solution to the differential equation is ψ(x,y)=1.5x²+6xy-2y⁴=C.

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Three times a number added to seven is 22

Answers

3x+7=22

3x=15

x=5

 the number is 5

Write 11760825 in word form

Answers

11 million seventy six thousand eight hundred twenty five

How many squares with sides that are 6 inches long are needed to cover a square with a side length of 30 inches without overlapping

Answers

5 squares are needed
Final answer:

Twenty-five squares with a side length of 6 inches are required to cover a square with a side length of 30 inches.

Explanation:

To find out how many squares with sides that are 6 inches long are needed to cover a square with a length of 30 inches, you first need to find the area of each square.

The area of a square is found by multiplying the length of one side by itself.

So, the area of the smaller square is 6 * 6 = 36 square inches, and

the area of the larger square is 30 * 30 = 900 square inches.

Then, you divide the area of the larger square by the area of the smaller square:

          900/36 = 25.

Therefore, 25 squares with sides of 6 inches are needed to cover a square with a side length of 30 inches.

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What are the X intercepts of a parabola with vertex (6,27) and y intercept of (0,-81)?

Answers

so hmm let's see if we can get the parabola's equation

if we assume a vertical parabola, "y" in x-terms.... then

[tex]\bf \begin{array}{llll} \boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\ x=a(y-{{ k}})^2+{{ h}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -------------------------------\\\\[/tex]

[tex]\bf \textit{we know that } \begin{cases} h=6\\ k=27 \end{cases}\implies y=a(x-6)^2+27 \\\\\\ \textit{we also know the y-intercept } \begin{cases} x=-81\\ y=0 \end{cases}\implies 0=a(-81-6)^2+27 \\\\\\ -27=a(-87)^2\implies \cfrac{-27}{(-87)^2}=a\implies -\cfrac{3}{841}=a\\\\ -------------------------------\\\\ \boxed{y=-\cfrac{3}{841}(x-6)^2+27}[/tex]

now, to get the x-intercepts, we simply set y = 0

[tex]\bf 0=-\cfrac{3}{841}(x-6)^2+27\implies -27=-\cfrac{3}{841}(x-6)^2 \\\\\\ \cfrac{-27\cdot 841}{-3}=(x-6)^2\implies 7569=(x-6)^2\implies \pm\sqrt{7569}=x-6 \\\\\\ \pm 87=x-6\implies \pm 87+6=x\implies x= \begin{cases} 93\\ -81 \end{cases}[/tex]

and... since the y = 0, then (93, 0) and (-81, 0)
Other Questions
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