The circumference of a circle is 6.28. What is the area of the circle.

Answers

Answer 1
Hello there! Thank you for asking your question here at Brainly. I will be assisting you today with how to handle this problem, and will teach you how to handle it on your own in the future.

First, let's evaluate the question.
"The circumference of a circle is 6.28. What is the area of a circle?"

Now, let's remember the different formulas for area and circumference.
The circumference is "2•3.14•r", while the area is "3.14•r•r".

We have our circumference, 6.28.
However, we are looking for the area. Since we have the circumference, we need to narrow down to the radius (so we can solve for the area).
Let's set this up as an equation;
C = 2 • 3.14 • r
Plug in the value for our circumference.
6.28 = 2 • 3.14 • r
Multiply 2 by 3.14 and r to simplify the right side of the equation.
2 • 3.14 • r = 6.28 • r = 6.28r

We're now left with:
6.28 = 6.28r
Divide both sides by 6.28 to solve for r.
6.28 / 6.28 = 1
6.28r / 6.28 = r

We are now left with the radius:
R = 1.

Now, we can solve for the area.
Remember our formula for the area.
A = r • r • 3.14.
Plug in 1 for r.
A = 1 • 1 • 3.14
A = 3.14.

Your area is 3.14 units^2.

I hope this helps, and has prepared you for your future problems in relation to this topic!
Answer 2
Circumfrence= πd
6.28=3.14*d
6.28/3.14=d
D=2
Area= πr*r
=3.14*1*1
=3.14

Related Questions

What is the answer to this question?

Answers

9/12= 0.75

8.00 * 0.75 = 6.00

 the 9" costs $6.00

Making use of the fact hat eq. (6.20) is an exact differential expression, show that what is the result of application of this equation to an ideal gas

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Since there is no figure attached, I will describe the derivation of the ideal gas law. The combined gas law has no official founder; it is simply the incorporation of the three laws that was discovered. The combined gas law is a gas law that combines Gay-Lussac’s Law, Boyle’s Law and Charle’s Law.  Boyle’s law states that pressure is inversely proportional with volume at constant temperature. Charle’s law states that volume is directly proportional with temperature at constant pressure. And Gay-Lussac’s law shows that pressure is directly proportional with temperature at constant volume. The combination of these laws known now as combined gas law gives the ratio between the product of pressure-volume and the temperature of the system is constant. Which gives PV/T=k(constant). When comparing a substance under different conditions, the combined gas law becomes P1V1/T1 = P2V2/T2.

Write as a single power: 4​^20​ + 4​^20​ + 4^​20​ + 4^​20

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Sorry, I misinterpreted the question before.\\\\ 4^20+4^20+4^20+4^20 \\\\ 4(4^20)\\\\ 4^21\\\\

what does it mean to say that's data point has a residual of 0

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The point lies directly on the regression line (Apex)

Answer:

The correct answer is “the point lies directly on the regression line”

Step-by-step explanation:

When you do a regression analysis, then you get a line of regression that best fits it. The data points usually tend to fall in the regression line, but they do not precisely fall there but around it. A residual is the vertical distance between a data point and the regression line. Every single one of the data points had one residual. If one of this residual is equal to zero, then it means that the regression line truly passes through the point.  

Evaluate the integral below, where e lies between the spheres x2 + y2 + z2 = 9 and x2 + y2 + z2 = 25 in the first octant.

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The student's question involves integrating a function in a region bounded by two spheres in the first octant, implying the use of spherical coordinates and integration over a sphere with a constant radius.

The question pertains to evaluating an integral within the region bounded by two spheres in the first octant. When dealing with spheres and integrals, the use of spherical coordinates is often beneficial. The question suggests using spheres with a constant radius and spherical coordinates (r, θ, φ), where a typical point in space is represented as (r sin(θ) cos(φ), r sin(θ) sin(φ), r cos(θ)). To integrate over the sphere, we consider the bounds given by the radii of the inner and outer spheres, (r = 3 and r = 5, respectively, since the square roots of 9 and 25 are 3 and 5), and the fact that it is within the first octant which further restricts the limits of θ and φ. The rest of the provided excerpts seem to be unrelated specifically to this problem but are examples of standard integrals and applications of integration in physics and potential theory.

The final answer after evaluating the integral is: [tex]\[\frac{49\pi}{3}\][/tex]. This is the value of the integral over the region between the spheres [tex]\( x^2 + y^2 + z^2 = 9 \) and \( x^2 + y^2 + z^2 = 25 \)[/tex] in the first octant.

To evaluate the given integral over the region between the spheres [tex]\( x^2 + y^2 + z^2 = 9 \)[/tex]and [tex]\( x^2 + y^2 + z^2 = 25 \)[/tex]  in the first octant, we can use spherical coordinates. In spherical coordinates, the volume element is given by [tex]\( r^2 \sin(\phi) \, dr \, d\theta \, d\phi \),[/tex] where r is the radial distance, [tex]\( \theta \)[/tex] is the azimuthal angle, and [tex]\( \phi \)[/tex] is the polar angle.

The limits for the integral are as follows:

[tex]- \( 3 \leq r \leq 5 \) (limits of the radii for the spheres)\\- \( 0 \leq \theta \leq \frac{\pi}{2} \) (first octant)\\- \( 0 \leq \phi \leq \frac{\pi}{2} \) (first octant)[/tex]

The integral to evaluate is not specified, so let's assume it's a simple function like \( f(x, y, z) = 1 \) for the sake of demonstration. The integral would then be:

[tex]\[\iiint_E 1 \, dV = \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \int_{3}^{5} r^2 \sin(\phi) \, dr \, d\theta \, d\phi\][/tex]

Now, let's evaluate this integral step by step:

[tex]\[\int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \int_{3}^{5} r^2 \sin(\phi) \, dr \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \left[ \frac{1}{3} r^3 \sin(\phi) \right]_{3}^{5} \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \left( \frac{125}{3} - \frac{27}{3} \right) \sin(\phi) \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \frac{98}{3} \sin(\phi) \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \left[ \frac{98}{3} \theta \right]_{0}^{\frac{\pi}{2}} \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \frac{98}{3} \cdot \frac{\pi}{2} \, d\phi\][/tex]

[tex]\[= \frac{98\pi}{6}\][/tex]

[tex]\[= \frac{49\pi}{3}\][/tex]

So, the value of the integral over the specified region is[tex]\( \frac{49\pi}{3} \).[/tex]

Let f(x) = -20x2 + 14x + 12 and g(x) =5x-6 Find f/g and state its domain a. 5x - 6; all real numbers except x =6/5 b. 5x - 6; all real numbers c. –4x – 2; all real numbers except x =6/5 d. –4x – 2; all real numbers

Answers

Final answer:

To find f/g, divide each term in f(x) by g(x). Resulting in f(x)/g(x) = -4x - 2 with the domain being all real numbers except x = 6/5. Hence, the correct answer is c. -4x - 2; all real numbers except x = 6/5.

Explanation:

To find the function f/g, we divide the function f(x) by g(x). Given f(x) = -20x2 + 14x + 12 and g(x) = 5x - 6, we divide these to get:

f(x)/g(x) = (-20x2 + 14x + 12) / (5x - 6)

Dividing each term in f(x) by g(x):

f(x)/g(x) = -4x - 2

The domain of this function would be all real numbers except where g(x) = 0, since we cannot divide by zero. g(x) = 0 when x = 6/5. Thus, the domain is all real numbers except x = 6/5.

The correct answer to the student's question is therefore c. -4x - 2; all real numbers except x = 6/5.

Your science quiz had 17 questions and you answered 13 of the questions correctly. What is your present score?

Answers

dived 13 by 17

13/17 = 0.7647

  = 76.47%

 if you need to round the number it would be 76%, which is a 76 grade

what is the answer ?

Answers

The system of inequalities is the following:

i) y ≤ –0.75x
ii)y ≤ 3x – 2

since [tex]0.75= \frac{75}{100}= \frac{3}{4} [/tex], we can write the system again as 

[tex]i) y \leq - \frac{3}{4}x [/tex]
[tex]ii) y \leq 3x-2[/tex]

Whenever we are asked to sketch the solution of a system of linear  inequalities, we:

1. Draw the lines
2. Color the regions of the inequalities.
3. The solution is the region colored twice.


A.

to draw the line [tex] y =- \frac{3}{4}x[/tex]

consider the points: (-4, 1) and (0, 0), or any 2 other points (x,y) for which [tex] y =- \frac{3}{4}x[/tex] hold.

since we have an "smaller or equal to" inequality, the line is a solid line (not dashed, or dotted).

In order to find out which region of the line to color, consider a point not on the line, for example P(1, 1), which is clearly in the upper region of the line.

For (x, y)=(1, 1) the inequality [tex]y \leq - \frac{3}{4}x[/tex], does not hold because 

[tex]1 \leq - \frac{3}{4}*1= -\frac{3}{4} [/tex] is not true,

this means that the solution is the region of the line not containing (1, 1), as shown in picture 1.


B.
similarly, to draw the solution of inequality ii) y ≤ 3x – 2, 

we first draw the line y=3x-2, using the points (0, -2) and (2, 4), or any other 2 points (x,y) for which y=3x-2 holds.

after we draw the line, we can check the point P(1, 7) which clearly is above the line y=3x-2.

for (x, y) = (1, 7), the inequality y ≤ 3x – 2 does not hold

because 7 is not ≤ 3*1-2=1, so the region we color is the one not containing P(1, 7), as shown in picture 2.


The solution of the system is the region colored with both colors, the solid lines included. Check picture 3.

the lines intersect at (0.533, -0.4) because:

–0.75x=3x-2
-0.75x-3x=-2
-3.75x=-2, that is x= -2/(-3.75)=0.533

for x=0.533, y=3x-2=3(0.533)-2=-0.4

Answer: Picture 3, the half-lines included. So the graph is in the 3rd and 4th Quadrants

A certain recipe requires 458 cups of flour and 659 cups of sugar. a) If 3/8 of the recipe is to be made, how much sugar is needed?

If the above ingredients are required for one batch, find the amount of flour needed for a double batch.

Answers

a) To make 3/8 of the recipe calculate 3/8 of each ingredient.

This is how to do it:

Flour: 458 cups * 3/8 = 3* 458 / 8 cups = 3*229/4 cups = 687/4 cups = 171.75 cups = 171 and 3/4 cups

Sugar: 659 cups * 3/8 = 3*659 / 8 = 1977 / 8 cups = 247.125 cups = 247 and 1/8 cup.

For a double batch multiply all the ingredients by 2:

Flour: [687 /4] * 2 = 687/2 = 343.5 cups = 343 and 1/2 cups

Sugar: [1977/8]*2 = 1977/4 = 494.25 cups = 494 and 1/4 cups.

Is this statemate true or false?
All parallelograms are special kinds of squares.

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This is false.
By definition, all squares must have four right angles. Not all parallelograms meet this requirement,

Rewrite with only sin x and cos x. cos 3x

Answers

[tex]\cos (3x)=4\cos^3 x-3\cos x[/tex]

One custodian cleans a suite of offices in 3 hrs. When a second worker is asked to join the regular custodian, the job takes only 2 hours. How long does it take the second worker to do the same job alone?

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The regular custodian's cleaning rate is 1/3 suites per hour. The combined cleaning rate is 1/2 suites per hour. The combined cleaning rate is (rate 1) + (rate 2) = 1/2 rate 2 = 1/2 - 1/3 = 3/6 - 2/6 = 1/6 The second worker's rate is 1/6 suites per hour. Therefore, the second worker can do the same job alone in 6 hours.

Five individuals, including a and b, take seats around a circular table in a completely random fashion. suppose the seats are numbered 1, . . . , 5. let x = a's seat number and y = b's seat number. if a sends a written message around the table to b in the direction in which they are closest, how many individuals (including a and
b.would you expect to handle the message?

Answers

Will use A and B in place of a and b for clarity.
Let x=number of individuals away from A, including A & B

Without loss of generality, assume A is seated in seat #1.

Then B is seated at 2,3,4,5 with equal probability.
Half of the time B is seated at 2 or 5, each of which is next to A, therefore x=2
The other half of the time B is seated at 3 or 4, each of which is separated from A by one seat, then x=3.

The expected number of individuals
E[X]=sum (x*P(x))
=2*(1/2)+3(1/2)
=2.5

So the expected number of individuals to handle the message is 2.5.

The number of  individuals you would expect to handle the message is 2.5.

Joint probability distribution

Let Z represent the number of individuals that handle the message

Table for the possible joint value of X and Y

Z                       Y

                         1          2          3            4         5  

X         1             -          2           3            3         2

          2           2         -           2            3         3

          3           3         2           -             2         3

           4           3         3           2            -          2

           5            2         3           3           2          -

Each cell contain=1/4×1/5=1/20

Hence:

Number of individual=10×2×1/20+10×3×1/20

Number of individual=20×0.05+30×0.05

Number of individual=2.5

Therefore the number of  individuals you would expect to handle the message is 2.5.

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If (f + g)(x) = 3x2 + 2x – 1 and g(x) = 2x – 2, what is f(x)?

Answers

F(x)= 3x^2+1

I'm taking that 3x2 equals 3x^2

A jeep and BMW enter a highway running east-west at the same exit heading in opposite directions. The jeep entered the highway 30 minutes before the BMW did, and traveled 7 mph slower than the BMW. After 2 hours from the time the BMW entered the highway, the cars were 306.5 miles apart. Find the speed of each car, assuming they were driven on cruise control.

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recall you d = rt, distance = rate * time

when the BMW has been running for 2hrs, the Jeep has been running for 2.5hrs, because it started off the exit 30minutes(0.5hr) before the BMW.

if the rate of the BMW is say "r", then the rate of the Jeep is "r - 7", slower by 7mph.

now, we know after the Jeep was running for 2.5hrs and the BMW was running for 2hrs, they were both apart by 306.5miles, so, say if the Jeep travelled a distance of "d", then the BMW travelled the slack from the 306.5, or "306.5 - d".

[tex]\bf \begin{array}{lccclll} &distance&rate& \begin{array}{cllll} time\\ (hours)\\ \end{array}\\ &-----&-----&-----\\ Jeep&d&r-7&2.5\\ BMW&306.5-d&r&2 \end{array} \\\\\\ \begin{cases} \boxed{d}=(r-7)2.5\\ 306.5-d=2r\\ ----------\\ 306.5-\boxed{(r-7)2.5}=2r \end{cases}[/tex]

solve for "r" to get the rate of the BMW.

what about the Jeep's? well, the Jeep is just r - 7.

Answer:

3x+27+3.5x=397.5

6.5x=370.5

x=57 mph for jeep and travels 199.5 miles in 3.5 hours

x+9=66 mph for B and travels 198 miles in 3 hours

Step-by-step explanation:

speed of jeep=x, time is     >>>>>    t+0.5 in hours or 3.5 hours here

speed of B=x+9, time is  >>>>>>>>>>>> 3 hours

distance is >>>>>>>>>    speed time

Hope it Helps.

Answer on: june 11, 2021

Will someone please answer this??

Answers

7.2 Feet Should be the correct answer

Please, show me how to solve this. Find the limit as x approaches −8 for the function ​f(x)=5x+12.

Answers

ahemm... cheap answer is just   [tex]\bf \lim\limits_{x\to -8}~5x+12\implies 5(-8)+12\implies -28[/tex]

Help.. :)

Which equation is not equivalent to the formula e = mc?
m equals e over c
c equals e over m
e = cm
m equals c over e
Please help THANKS!

Answers

m equals c over e is not equal to e=mc


Answer with Step-by-step explanation:

we are given a equation:

e=mc

We have to find which equation is not equivalent to the above formula.

e=mc

Dividing both sides by c,we get

m=e/c

i.e. m equals e over c

e=mc

Dividing both sides by m,we get

c=e/m

i.e. c equals e over m

e=mc=cmBut m is not equal to c over e

Hence, The equation which is not equivalent to e=mc is:

m equals c over e

The scores on an exam are normally distributed, with a mean of 74 and a standard deviation of 7. What percent of the scores are less than 81?

Answers

Mean = 74
Standard deviation = 7

For 81%, the Z-score is
Z=(X-mean)/(standard deviation)
=(81-74)/7
=1

So look up table of normal distribution for
P(Z<1)=0.8413
=>
On average, 84% of scores are less than 81.

Simplify Negative 3 over 2 ÷ 9 over 6.

Answers

1 because you can simply switch the numerator and the denominator when dividing.
3/2 divided by 9/6 is 3/2 X 6/9 = 18/18 which simplifies to 1.

A potter use 4/5 of a pound of clay to make a bowl.How many bowls can the potter make from 12 pounds.

Answers

12/1 / 4/5=

12/1 * 5/4 =

60/4 = 15

 they can make 15 bowls

Zooey predicts the movie will be 90 minutes long. If the movie actually is 102 minutes long, what is Zooey's percent error? Round your answer to the nearest tenth of a percent.

Answers

102 - 90 = 12
12 / 102 = 0.1176 = 11.76 rounds to 11.8% <==
%error=100(prediction-actual)/actual

%error=100(90-102)/102

%error≈ -11.8%

Now the negative sign indicates that she underestimated the length of he movie by 11.8%, but technically the percent error is an absolute value so it is just 11.8% error.

Which number is a prime number? 21,22,23,24

Answers

23 is the prime number bc it isn't divisable by anything
A prime number is a number that has no factors, except for itself and one. 

21 is not a prime number, because in addition to having one and itself as factors, it has 7 and 3. ( 1 x 21 = 21.) ( 7 x 3 = 21.) 

22 is not a prime number. It's easy to tell because it is an even number. ( 1 x 22 = 22.) ( 2 x 11 = 22.)

24 is not a prime number. It's even, but also has more factors. ( 2 x 12 = 24.) ( 3 x 8 = 24.) (4 x 6 = 24.)

23, however, has no other factors but one and itself. ( 1 x 23 = 23.) So therefore, it is prime.

Find the taylor polynomial t3(x) for the function f centered at the number
a. f(x) = eâ4xsin(2x), a = 0

Answers

[tex]e^{-4x}=\displaystyle\sum_{n=0}^\infty\frac{(-4x)^n}{n!}=1+(-4x)+\dfrac{(-4x)^2}2+\dfrac{(-4x)^3}6+\cdots[/tex]
[tex]e^{-4x}=1-4x+8x^2-\dfrac{32x^3}3+\cdots[/tex]

[tex]\sin2x=\displaystyle\sum_{n=0}^{\infty}\frac{(-1)^k(2x)^{2k+1}}{(2k+1)!}=(2x)-\dfrac{(2x)^3}6+\cdots[/tex]
[tex]\sin2x=2x-\dfrac{4x^3}3+\cdots[/tex]

[tex]e^{-4x}\sin2x=\left(1-4x+8x^2-\dfrac{32x^3}3+\cdots\right)\left(2x-\dfrac{4x^3}3+\cdots\right)[/tex]
[tex]e^{-4x}\sin2x=2x-8x^2+\dfrac{44x^3}3+\cdots[/tex]

[tex]\implies T_3(x)=2x-8x^2+\dfrac{44x^3}3[/tex]

The Taylor polynomial [tex]T_3(x)[/tex] will be written as [tex]2x-8x^2+\dfrac{44x^3}{3}+......[/tex].

Given:

The given function is [tex]f(x) = e^{-4x}sin(2x)[/tex].

It is required to find the Tylor polynomial [tex]t_3(x)[/tex] centered at a=0.

Now, the expansion of the function [tex]e^{-4x}[/tex] can be written as,

[tex]e^{-4x}=\sum\dfrac{(-4x)^n}{n!}\\e^{-4x}=1+(-4x)^1+\dfrac{(-4x)^2}{2!}+\dfrac{(-4x)^3}{3!}+.....\\e^{-4x}=1-4x+\dfrac{16x^2}{2}-\dfrac{64x^3}{6}+.....\\e^{-4x}=1-4x+8x^2-\dfrac{32x^3}{3}+.....[/tex]

Similarly, the expansion of the function [tex]sin(2x)[/tex] will be,

[tex]sin(2x)=\sum\dfrac{(-1)^n(2x)^{2n+1}}{(2n+1)!}\\=\dfrac{2x}{1!}+\dfrac{-(2x)^3}{3!}+.....\\=2x-\dfrac{4x^3}{3}+......[/tex]

So, the function [tex]f(x) = e^{-4x}sin(2x)[/tex] will be written as,

[tex]f(x) = e^{-4x}sin(2x)\\f(x)=(1-4x+8x^2-\dfrac{32x^3}{3}+.....)(2x-\dfrac{4x^3}{3}+......)\\f(x)=2x-8x^2+16x^3-\dfrac{4x^3}{3}+.......\\f(x)=2x-8x^2+\dfrac{(48-4)x^3}{3}+......\\f(x)=2x-8x^2+\dfrac{44x^3}{3}+......[/tex]

Therefore, the Taylor polynomial [tex]T_3(x)[/tex] will be written as [tex]2x-8x^2+\dfrac{44x^3}{3}+......[/tex].

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Rs = 8y + 4 , ST = 4y + 8 , and RT = 36 , find the value of y

Answers

I assume that you meant RS and ST are segments of RT.  If that is true then:

RS+ST=RT, using the values for these given...

8y+4+4y+8=36  combine like terms on left side

12y+12=36  subtract 12 from both sides

12y=24  divide both sides by 12

y=2

is 5.21 a rational number

Answers

yes; since 9 over 10 is 0.9 as a decimal, 5 and then 21 over 100 is 5.21 as a decimal.

A local carpet company has been hired to carpet a planetarium which is in the shape of a circle. If the radius of the planetarium is six yards, and the cost of the carpet is $14 per square yard, find the total cost to carpet the planetarium.

Answers

The cost of the carpet will be given by:
cost=[area of the carpet]*[price per yard]
area of the carpet will be given by:
area=πr^2
=π*6^2
=113.1 square yards
thus the cost of the carpet will be:
113.1*14
=$1,583.4

Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute. There are 700 liters in the pond to start. Let W represent the total amount of water in the pond (in liters), and let T represent the total number of minutes that water has been added. Write an equation relating W to T . Then use this equation to find the total amount of water after 19 minutes.

Answers

W=700+35T. Then replace T with 19 which will be W=700+35(19) which equals to 1365 total amount of water in liters.

An equation relating W to T is,

W = 700 + 35T

And, Total amount of water after 19 minutes is, 1365 liters

We have to given that,

Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute.

There are 700 liters in the pond to start.

Now, Let W represent the total amount of water in the pond (in liters), and let T represent the total number of minutes that water has been added.

Hence, an equation relating W to T is,

W = 700 + 35T

So, For T = 19 minutes,

W = 700 + 35  x 19

W = 700 + 665

W = 1365

Therefore, Total amount of water after 19 minutes is, 1365 liters

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Write the equation in spherical coordinates. 3x + 2y + 3z = 1

Answers

[tex]\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\cos\varphi\end{cases}[/tex]

[tex]3x+2y+3z=1[/tex]
[tex]\implies3\rho\cos\theta\sin\varphi+2\rho\sin\theta\sin\varphi+3\rho\cos\varphi=1[/tex]
[tex]\implies\rho=\dfrac1{(3\cos\theta+2\sin\theta)\sin\varphi+3\cos\varphi}[/tex]

Triangle XYZ is reflected across the line x = 3. What is the reflection image of X?

Answers

The image of x is the point (7,5).
Draw the line x= 3 and treat it like a mirror.

When you reflect the points of the triangle just count how many units each point is from the mirror (x=3)
Count the same number of points in the opposite direction (away from the mirror) and you will arrive at the coordinates for the points

Answer:

It's (7,5)

Step-by-step explanation:

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How would the installation of the roles and features selected in this exercise differ if the server was running windows server 2008 r2? How does Shakespeare make certain lines within his plays seem more important then others ? greens theorem. find the max value of the line integral where f=(13x^2y+3y^3-y)i-12x^3j and C is any positively oriented closed curve. max=? If 3/4 =7 x/3,then x= Read the supporting text from "Disease Control" and the passage from When Birds Get Flu by John DiConsiglio.In 1958, scientists at the CDC made their first trip overseas. A team went to Southeast Asia to respond to an epidemic of smallpox and cholera.Since then, the CDC has been active throughout the world, following infectious [diseases] such as smallpox, polio, tuberculosis, AIDS, and SARS.***So where did this killer flu come from? In 2005, researchers at the CDC announced that it had probably started off as a bird flu and then jumped to humans.Does that sound familiar? The Spanish flu is very similar to the bird flu we see today. Some scientists believe its the same strain of influenza.What do these two passages have in common? You attend an amusement park with your family. Your parents buy you an all-ride pass for $20, shown as fx. Instead of getting a pass, your parents decide to pay $4 for each ride they take, shown as gx. What function shows the correct combination of these two functions to represent the total cost to them of attending the amusement park that day, shown as hx? A. fx = 20x, gx = 4, hx = 20x + 4 B. fx = 20, gx = 4, hx = 4 + 20 C. fx = 20, gx) = 4x, hx = 4x + 20 D. fx = 20x, gx = 4x, hx = 20x + 4x Match each term with its definition:DictionTransitionsUnityUsageSyntaxA.Staying on topic in an essay or paragraphB.Words that connect ideas and paragraphsC.Correctness of phrases and clausesD.The order of words in a sentenceE.Word choices made for tone or clarity Why is bangladesh internationally competitive in textile and clothing manufacturer? The famous leaning tower of pisa doesn't topple over because its center of gravity is Now emily is looking for a compressed file format that is suitable for most types of simple line art, but that has the capacity for some complicated colors. what is the most likely format for the file she will use? Read the passage. Domesticated dogs and cats that are not fenced present many problems for neighborhood communities. These animals run wild, ruin yards, and often frighten children and adults. Barking has also been a problem for people unlucky enough to live near the noise nuisance. All of this happens because leash laws are not enforced. What is the cause of the loose pets? Loose pets ruin yards and frighten children. Dogs and cats run wild. Barking has been a problem for people living nearby. Leash laws are not enforced. A distribution x is known to have a mean value of 5 and a standard deviation of 5. what is its mean square value (i.e., the expected value of x2)? Which of these statements best describes a similarity between photosynthesis and dissolving in the sea? A. Both store carbon in the ground. B. Both take up carbon from the ground. C. Both release carbon dioxide into the atmosphere. D. Both absorb carbon dioxide from the atmosphere. an angle measures 12 degrees less than 3 times its supplement Native american man who taught the pilgrims about their new environment Recall the first step in the process to determine theme. In three to four sentences, summarize at least three events that happened in the fable. lion and mouse Lee abrams which individual sold album-oriented-rock formats as prepackaged products If a 70 inch television's diagonal forms a 29 angle with the base of the screen, what is the vertical height (h) of the screen to the nearest inch? 34 in 39 in 51 in 61 in if your ability to search is blocked by a large vehicle, ___________ your vehicle so you have a clear, unobstructed view of the path ahead. Express the angular velocity of 60 rpm (revolutions per minute) in units of radians per second (rad/s). Steam Workshop Downloader