Suppose a membrane surrounded an oil droplet, as it does in the cells of plant seeds and in some animal cells. describe and explain the form it might take.
How do you change the thermos into an open energy system
Final answer:
To convert a thermos into an open energy system, allow for energy exchange by adding openings or using less insulating materials, thus modifying the thermos to gain or lose energy like other open systems.
Explanation:
To change a thermos into an open energy system, you must allow for the transfer of energy between the thermos and its surroundings. A thermos is designed to be an isolated system, minimizing energy exchange with the environment to keep its contents at a consistent temperature. However, to convert it into an open system, modifications can be implemented such as adding openings or using materials that facilitate heat exchange. It is through such alterations that the thermos can then gain or lose energy, behaving similarly to a pot of water on a stove, which is considered an open system because it loses heat to the air.
While a thermos typically serves to approximate an isolated system, where the coffee inside remains hot by limiting heat transfer, to convert it to an open system, one might drill holes in it or construct it from a less insulating material. Once converted, the thermos could then absorb energy from the environment or release energy to it, such as solar radiation warming the contents or ambient air cooling them down. This adherence to thermodynamics principles demonstrates how the laws of thermodynamics govern the energy dynamics of open systems. Ultimately, converting a thermos to an open system reflects the first law of thermodynamics, where the energy within the system changes through the work done on it or by it.
Which statement best describes the skier? The skier has potential and kinetic energy. The skier has only potential energy. The skier has only kinetic energy. The skier does not have potential or kinetic energy.
Option A: The skier has potential and kinetic energy
If 2 joules of work is done in raising an apple 8 meters, how much force was exerted?
The position function x (6.0 m) cos[(3p rad/s)t p/3 rad]gives the simple harmonic motionof a body. at t 2.0 s, what are the(a) displacement, (b) velocity, (c)acceleration, and (d) phase of the motion? also, what are the (e)frequency and (f) period of the motion?
The correct formula for this simple harmonic motion is:
x = (6.0) cos [ (3 pi) t + pi/3 ]
A. Calculating for displacement x at t = 2:
x =6.0 cos (19/3 pi)
x = 6 (0.5)
x = 3 m
B. Velocity is equivalent to the 1st derivative of the equation. v = dx / dt
Velocity v = dx/dt = -18 pi sin (3pi t + pi/3)
v = - 18 pi sin (6pi + pi/3)
v = 49.0 m/s
C. Acceleration is the 2nd
derivative or the 1st derivative of velocity dv / dt
Acceleration a = dv/dt = -54 pi^2 cos(3pi t + pi/3)
a = -54 pi^2 cos(3pi * 2 + pi/3)
a = 386.34 m/s^2
D. Phase = pi/3
E. frequency f= 3pi/2pi = 1.5Hz
F. period = 1/f = 1/1.5 = .6667sec
Final answer:
The position function x(t) = X cos(ωt + φ) represents the simple harmonic motion of a body. At t = 2.0 s, we can calculate the displacement, velocity, acceleration, and phase of the motion. The frequency and period of the motion can also be determined.
Explanation:
In simple harmonic motion, the displacement of a body at any given time t is given by the equation x(t) = X cos(ωt + φ), where X is the amplitude, ω is the angular frequency, and φ is the phase angle.
(a) At t = 2.0 s, plugging in the values, we have x(2.0) = 6.0 cos((3π rad/s) * 2.0 s + π/3 rad).
(b) Velocity can be obtained by taking the derivative of the displacement function, v(t) = -ωX sin(ωt + φ).
(c) Acceleration can be obtained by taking the derivative of the velocity function, a(t) = -ω²X cos(ωt + φ).
(d) The phase of the motion refers to the initial position of the body and is represented by the phase angle φ.
(e) The frequency of the motion is given by f = ω/(2π) = (3π rad/s)/(2π) = 3/2 Hz.
(f) The period of the motion is the reciprocal of the frequency, T = 1/f = (2/3) s.
For an object starting from rest and accelerating with constant acceleration, distance traveled is proportional to the square of the time. if an object travels 2.0 furlongs in the first 2.0 s, how far will it travel in the first 4.0 s?
For an object starting from rest and accelerating with a constant acceleration, the distance travelled is proportional to the square of the time. So, if an object travels 2.0 furlongs in the first 2.0 seconds, it will travel 8.0 furlongs in the first 4.0 seconds.
Explanation:In the problem, we have an object accelerating from rest and we know that distance covered is proportional to the square of the time. In the first 2.0s, the object has covered a distance of 2.0 furlongs. Hence, if we double the time from 2.0s to 4.0s, since distance covered is proportional to the square of time, the object will cover 2*(2.0s)^2 = 8.0 furlongs in the first 4.0s. This relationship is based on the physics principle of displacement which defines that in constant acceleration, distance travelled is proportional to square of time.
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Is it possible for one ray to be shorter in length than another?
Which is a chemical property of iron?
its tendency to react with oxygen
its melting point
its strength under compression
its hardness
A chemical property of iron is its tendency to react with oxygen to form iron oxide, otherwise known as rust, which is a process called corrosion.
Explanation:A chemical property of iron is its tendency to react with oxygen, which is an example of corrosion. This reaction forms iron oxide, commonly known as rust. Unlike physical properties like melting point, hardness, and strength under compression, chemical properties describe the potential for a substance to change its chemical structure. Corrosion is one such property that can only be observed as the substance is transformed into a different substance, in this case, iron becoming iron oxide.
An adult with a high waist circumference measurement is at increased risk for what chronic diseases
Two planets are 3 x 107 km apart. Planet A has a mass of 8 x 1024 kg. Planet B has a mass of 1 x 1025 kg.
What is the gravitational force that Planet A exerts on Planet B? (2pts)
What is the gravitational force that Planet B exerts on Planet A? (2pts)
If a sheet of aluminum foil (d = 2.70 g/cm3) weighs 5.31 lbs and is 0.0130 mm thick, the surface area of the foil is closest to�
An electric hair dryer is rated 350w 110v. the safety fuse in the circuit can withstand 12a of current. how many hair dryers can be safely operated in the circuit?
Express the angular velocity of 60 rpm (revolutions per minute) in units of radians per second (rad/s).
Suppose you adjust your garden hose nozzle for a hard stream of water. you point the nozzle vertically upward at a height of 1.5 m above the ground. when you quickly turn off the nozzle, you hear the water striking the ground next to you for another 1.8 s .
When a refrigerant trace gas is necessary in a 410a air conditioner, which of the available refrigerants should be mixed with nitrogen and used to identify a leak?
The answer is CFC – 22 or HCFC - 22. To locate leaks, it is easily accomplished using a pressure – regulated dry nitrogen charge with CFC – 22. But some technicians prefer to use Refrigerant – 22 (HCFC – 22) to pressurize the system without the use of nitrogen. CFC – 22 is also known as Chlorodifluoromethane. This is a hydrochlorofluorocarbon (HCFC). This is better recognized as HCFC-22, or R-22. It is usually used as a propellant and refrigerant. While HCFC – 22 is also known as class II hydrochlorofluorocarbon refrigerant that is less harmful to the ozone than R -12. If HCFC – 22 is used for leak testing, all refrigerant must be first detached from the system. After the leak test, HCFC – 22 should be remove before putting any other refrigerant. Do not mix refrigerants. Both HCFC – 22 and R -134a fall into the kind of refrigerants known as combustible. If exposed to oxygen, they will burn when under pressure or exposed to high temperatures.
The pollutants associated with eutrophication are _____.
Nitrates and phosphates is correct on gradpoint
A turtle crawls at a constant speed, moving 4.77 m in 19.5 s. What was the turtle's velocity?
A turtle crawls and covers a distance of 4.77 m in a time of 19.5 seconds, then the velocity of the turtle will be equal to 0.245 m/s.
What is velocity?Velocity is the rate of change of a traveling object's direction, as measured by a certain unit of time and as seen from a specific vantage point. Speed is a basic concept in kinematic, the branch of special relativity that studies how bodies move.
A scientific vector quantity called velocity must have both a magnitude and direction to be described.
As per the given data provided by the question,
The distance traveled by the turtle, d = 4.77 m
Time is taken by the turtle, t = 19.5 seconds.
[tex]Velocity(v) = Distance(d)/Time(t)[/tex]
v = 4.77/19.5
v = 0.245 m/s.
Therefore, the velocity of the turtle is 0.245 m/s.
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In a vehicle equipped with an airbag, how much space should there be between your chest and the center of the steering wheel?
In vehicles with airbags, maintain 12-15 inches of clearance from the steering wheel. Avoid collisions by driving safely: obeying laws, keeping distance, and using defensive driving strategies.
In a vehicle equipped with an airbag, it is crucial to ensure that there is a sufficient clearance of 12-15 inches between your chest and the center of the steering wheel. This safety precaution is just one of several essential tips to protect yourself while driving. Collisions on the road are frequently the result of negligent driving behaviors, including speeding, disregarding traffic signals and stop signs, and driving under the influence of alcohol or drugs. To minimize the risk of being involved in a collision, there are several fundamental steps you should follow.
Maintaining an appropriate following distance behind the vehicle in front of you is paramount. This allows you ample time to react to sudden stops or emergencies, reducing the likelihood of a rear-end collision. Choosing the correct lane is another critical aspect of safe driving. Stay in the right lane if you are moving slower than the flow of traffic and use the left lane for passing. Driving defensively means constantly being aware of your surroundings, anticipating the actions of other drivers, and being prepared to react swiftly and safely.
In summary, for your safety on the road, ensure proper clearance from the steering wheel in airbag-equipped vehicles and adhere to safe driving practices. Collisions often result from avoidable mistakes, so by obeying traffic laws, maintaining a safe following distance, choosing the appropriate lane, and adopting a defensive driving mindset, you can significantly reduce the risk of accidents and protect yourself and others on the road.
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how light used to study space
How to find initial velocity in projectile motion without angle?
To find initial velocity in projectile motion without the angle, use the vertical motion information to calculate time of flight, then use horizontal distance and time to find horizontal velocity, and combine it with initial vertical velocity using the Pythagorean theorem.
Explanation:To find the initial velocity in projectile motion without knowing the angle, one approach is to use the given vertical motion information. According to the provided discussion, if a projectile has an initial vertical velocity (Vy0) of 14.3 m/s and lands 20.0 m below its starting altitude, the time of flight is 3.96 seconds. This time is solely determined by the vertical motion, as the vertical acceleration is constant due to gravity.
Once the time of flight is known, you can calculate the horizontal component of the velocity (Vx) as follows: Vx = horizontal distance traveled / time of flight. It is important to note that Vx is constant throughout the motion if air resistance is negligible. The horizontal component can then be used in combination with the vertical component to calculate the total initial velocity (Vo). This can be done by using the Pythagorean theorem, Vo = √(Vx² + Vy0²).
Calculate the change in internal energy (δe) for a system that is giving off 25.0 kj of heat and is changing from 12.00 l to 6.00 l in volume at 1.50 atm pressure. (remember that 101.3 j = 1 l∙atm) 14) ______
a.+25.9 kj
b.-16.0 kj
c.-25.9 kj
d.-24.1 kj
e.937 kj
Since the system itself is giving off heat, this is a reduction in the internal energy.
heat = - 25,000 J
Since work is being done on the system, therefore it is an additional energy to the system. Work is given as:
work = - P dV
work = - 1.50 atm (6 L – 12 L)
work = 9 L atm
Since it is given that 1 L atm is equivalent to 101.3 J, therefore the total energy added is:
energy due to work = 9 L atm (101.3 J / 1 L atm)
energy due to work = 911.7 J
Therefore the total change in internal energy is the sum of heat and energy due to work:
Change in internal energy = - 25,000 J + 911.7 J
Change in internal energy = - 24,088.3 J
Therefore, approximately 24.1 kJ of energy is lost by the system in the total process.
Answer:
-24.1 kJ
The correct option is d. which is the change in internal energy is -24.9 kj.
Given to us:Heat system is giving off, [tex]Q_{out}= -25000[/tex]Initial volume, [tex]V_{i}=12\ l[/tex]Final volume, [tex]V_{i}=6\ l[/tex]Pressure, [tex]P= 1.50\ atm[/tex]Also, a piece of additional information is given to us, [tex]101.3\ j = 1\ l\cdot atm[/tex].As work is being done on the system, meaning additional energy is provided to the system. Therefore,
[tex]\begin{aligned}W&=- \int\limits {P} \, dv\\&=-P\ dv\\\\&=-P\ (V_f-V_i)\\&=- (1.50) (6-12)\\&= 9\ l\cdot atm\end{aligned}[/tex]
Also,
[tex]1\ l\cdot atm=101.3\ j\\9\ l\cdot atm=101.3\times 9\\9\ l\cdot atm=911.7\ j[/tex]
According to the First law of thermodynamics,[tex]\Delta U = Q - W\Delta\\\\where,\\ U = change\ in\ internal\ energy\\Q = heat\ added\\W = work\ done\ by\ the\ system[/tex]
Substituting the values,
[tex]\begin{aligned}\\\Delta U&= Q - W\Delta\\&= -25000+911.7\\&=-24,088.3\ j\\&= -24.0883\ kj\end{aligned}[/tex]
Hence, the change in internal energy is -24.0883 kj.
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Eq-36 when paddling a canoe at night, which piece of equipment should be carried to help avoid a collision?
Which statements describe the process of scientific inquiry? Check all that apply.
Answer:
a
Explanation:
A tall cylinder contains 30 cm of water. oil is carefully poured into the cylinder, where it floats on top of the water, until the total liquid depth is 40 cm. part a what is the gauge pressure at the bottom of the cylinder? suppose that the density of oil is 900 kg/m3.
The total gauge pressure at the bottom of the cylinder would simply be the sum of the pressure exerted by water and pressure exerted by the oil.
The formula for calculating pressure in a column is:
P = ρ g h
Where,
P = gauge pressure
ρ = density of the liquid
g = gravitational acceleration
h = height of liquid
Adding the two pressures will give the total:
P total = (ρ g h)_water + (ρ g h)_oil
P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg / m^3) (9.8 m / s^2) (0.4 - 0.30 m)
P total = 2940 Pa + 882 Pa
P total = 3,822 Pa
Answer:
The total gauge pressure at the bottom is 3,822 Pa.
The total gauge pressure at the bottom of cylinder due to the oil and the water is [tex]\boxed{3822\,{\text{Pa}}}[/tex].
Further Explanation:
Given:
The water in the cylinder is up to the height of 30 cm .
The total height of the liquid column in the cylinder is 40 cm .
The density of oil is [tex]900\,{{{\text{kg}}}\mathord{\left/{\vphantom {{{\text{kg}}} {{{\text{m}}^{\text{3}}}}}}\right.\kern-\nulldelimiterspace} {{{\text{m}}^{\text{3}}}}}[/tex].
Concept:
The gauge pressure is the amount of pressure exerted by the liquid column on the surface below it.
The gauge pressure due to the height of the liquid pressure is given by:
[tex]P =\rho gh[/tex]
Here, [tex]P[/tex] is the gauge pressure, [tex]\rho[/tex] is the density of the liquid, g is the acceleration due to gravity and [tex]h[/tex] is the height of the liquid column.
The height of the oil present in the cylinder is:
[tex]\begin{aligned}{h_{oil}}&={h_{total}} - {h_{water}}\\&= 40 - 30\,{\text{cm}}\\&=10\,{\text{cm}}\\&\approx {\text{0}}{\text{.1}}\,{\text{m}}\\\end{aligned}[/tex]
The total gauge pressure at the bottom of the cylinder will be:
[tex]{P_{total}} = {\left({\rho gh}\right)_{water}} + {\left( {\rho gh}\right)_{oil}}[/tex]
Substitute the values in the above expression.
[tex]\begin{aligned}{P_{total}}&=\left({1000 \times 9.8 \times 0.30} \right) + \left( {900 \times 9.\times 0.1}\right)\\&=2940 + 882\\&=3822\,{\text{Pa}}\\\end{aligned}[/tex]
Thus, the total gauge pressure at the bottom of cylinder due to the oil and the water is [tex]\boxed{3822\,{\text{Pa}}}[/tex]
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Answer details:
Grade: High School
Subject: Physics
Chapter: Pressure
Keywords: Gauge pressure, water, oil, bottom of cylinder, 30cm of water, density of oil, 900kg/m^3, poured, floats on top, total liquid depth.
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The spread of uniform construction technology can be traced to which of the following developments?
The best answer for this question would be:
The onset of World War II
It started during World War II because during the war, soldiers needed to upgrade their uniform. This is to enable them to adapt to the battlefield where the deconstruction happened and courses of history have changed.