inner transition metals is your answer
The elements that contain electrons in an F sublevel near the highest occupied energy level are referred to as inner transition elements. Thus option D is correct.
What are orbitals?Orbitals are energy levels or regions in an atom where, there is a possibility of finding electrons. Electrons are filled in various orbitals from lower energy levels to higher energy levels.
There are 4 different orbitals namely s, p , d and f. Based on the energy level they can 1s, 2s, 2p, 3p and so on. The elements in periodic table are classified into 4 different blocks based on the orbitals of valence electrons.
If the valence electrons are filled in s orbital they are s-block elements containing metals and if they are filled in p orbital are p-block elements containing non metals.
Elements whose valence electrons fall in d-orbital are called d-block elements or transition metals and those having valence electrons in f orbital are f-block elements and they are called as inner transition elements.
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Calculate the density of an object that has a mass of 43 g and a volume of 56.0 ml.
Scientist discover that stars in the universe are mostly composed of which elements?
What is the right answer for this. I really need help
a car is traveling 55.0 miles per hour . convert this to meters per second . one miles is equal to 1.61 km
Answer : The speed of car in meters per second is 24.597 m/s
Explanation :
The conversion used from miles to kilometer is:
1 mile = 1.61 km
The conversion used from kilometer to meter is:
1 km = 1000 m
So, [tex]1mile=\frac{1.61km}\times \frac{1000m}{1km}=1610m[/tex]
The conversion used from hour to second is:
1 hr = 3600 s
So, [tex]1mile/hr=\frac{1610}{3600}m/s[/tex]
As we are given the speed 55.0 miles per hour. Now we have to determine the speed in meter per second.
As, [tex]1mile/hr=\frac{1610}{3600}m/s[/tex]
So, [tex]55.0mile/hr=\frac{55.0mile/hr}{1mile/hr}\times \frac{1610}{3600}m/s=24.597m/s[/tex]
Therefore, the speed of car in meters per second is 24.597 m/s
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(only for correct answers)
For EACH of the following reactions, identify ALL OF THESE:
a. oxidized species b. reduced species c. oxidizing agent d. reducing agent
I) 2 Fe (s) + 3 Cl2 (g) --> 2 FeCl3(s)
II) Mg (s) +2 H2SO4 (aq) --> MgSO4 (aq) + SO2 (g) + 2 H2O (l)
III) 2 Mg (s) + O2 (g) --> 2 MgO (s)
Final answer:
In the given reactions, the oxidized species, reduced species, oxidizing agent, and reducing agent are identified for each reaction.
Explanation:
In the given reactions:
I) 2 Fe (s) + 3 Cl2 (g) → 2 FeCl3(s)
Oxidized species: Fe (s)
Reduced species: Cl2 (g)
Oxidizing agent: Cl2 (g)
Reducing agent: Fe (s)
II) Mg (s) +2 H2SO4 (aq) → MgSO4 (aq) + SO2 (g) + 2 H2O (l)
Oxidized species: Mg (s)
Reduced species: H2SO4 (aq)
Oxidizing agent: H2SO4 (aq)
Reducing agent: Mg (s)
III) 2 Mg (s) + O2 (g) → 2 MgO (s)
Oxidized species: Mg (s)
Reduced species: O2 (g)
Oxidizing agent: O2 (g)
Reducing agent: Mg (s)
Electrolysis breaks down water to form hydrogen and oxygen gas. The word equation that represents this reaction is
What occurs when water in a river or stream transports tiny rock particles or sediment downstream. it also happens when these transported particles grind away the rock and when water dissolves chemical elements in the rock?
Uranium -235 is used in nuclear fission. determine the number of protons and neutrons in uranium -235
Uranium-235 has an atomic number of 92, indicating it has 92 protons. The mass number of 235 means it has 143 neutrons (235 - 92 = 143). Thus, uranium-235 contains 92 protons and 143 neutrons.
Uranium-235 is a commonly known isotope used in nuclear fission. To determine the number of protons and neutrons in uranium-235, we use its atomic number and mass number.
The atomic number of uranium (U) is 92. This means uranium has 92 protons.The mass number of uranium-235 (U-235) is 235. The mass number is the sum of protons and neutrons in the nucleus.To find the number of neutrons, we subtract the atomic number from the mass number:
Number of neutrons = Mass number - atomic number
Number of neutrons = 235 - 92 = 143
In uranium-235, there are 92 protons and 143 neutrons.
8. The number of protons in the nucleus of an element is called its ____________________________ number.
9. If two or more compounds are composed of elements A and B, the ratio of the masses of B combined with 1 g of A is always a ratio of small whole numbers. This is a statement of the law of
____________________________.
What is the electron structure of an oxygen atom?
A.) 1s22s22p4
B.)1s12s22p4
C.)1s22s12p4
D.) 1s12s12p4
The electronic configuration structure of an oxygen atom is 1s² 2s²2p⁴ (Option A)
What is electronic configuration?This is the arrangement of electrons in the atomic orbitals of an element.
How to write the electronic configurationOxygen has an atomic number of 8. Thus , we can write the electronic configuration using the spdf orbital notation as follows
NOTE:
Sharp (s) = Maximum of 2 electronsPrincipal (p) = Maximum of 6 electronsDiffuse (d) = Maximum of 10 electrons Fundamental (f) = Maximum of 14 electronsThe electronic configuration of oxygen atom can be written as follow:
O (8) => 1s² 2s²2p⁴
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how do atoms form a new substance
create a table that describes the three common states of matter in terms of their shape, volume, and compressibility.
Check attached for the table.
The explanation behind the table:
Solid – has definite shape and volume because if you hold any solid and put in anywhere it will not change.
Liquid – has definite volume and indefinite shape because the liquid take the shape of its container but with the same volume.
Gas – has indefinite shape and volume because the gas takes the shape and volume at its container.
The three common states of matter - solid, liquid, and gas - can be described in terms of their shape, volume, and compressibility.
Explanation:The three common states of matter - solid, liquid, and gas - can be described in terms of their shape, volume, and compressibility.
Solid:Rigid and possesses a definite shape.Has a fixed volume.Not easily compressible.Liquid:
Takes the shape of its container.Has a fixed volume.Not easily compressible.Gas:
Takes both the shape and volume of its container.Can be easily compressed.Learn more about States of Matter here:
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Explain the difference between a physical property and a chemical property
Given 7.55 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?
Final answer:
To calculate the grams of ethyl butyrate synthesized, use the molar ratios from the balanced chemical equation. Given 7.55 g of butanoic acid, the number of moles of ethyl butyrate synthesized is 0.0857 mol. Therefore, the grams of ethyl butyrate synthesized would be 9.96 g.
Explanation:
To calculate the grams of ethyl butyrate synthesized, we need to use the molar ratios from the balanced chemical equation. The balanced equation is: C4H8O2 + C2H5OH → C6H12O2 + H2O. The molar mass of butanoic acid (C4H8O2) is 88.11 g/mol and the molar mass of ethyl butyrate (C6H12O2) is 116.16 g/mol.
First, calculate the number of moles of butanoic acid:
7.55 g C4H8O2 * (1 mol C4H8O2 / 88.11 g C4H8O2) = 0.0857 mol C4H8O2
From the balanced equation, we can see that the mole ratio between butanoic acid and ethyl butyrate is 1:1. Therefore, the number of moles of ethyl butyrate synthesized is also 0.0857 mol.
Finally, calculate the grams of ethyl butyrate:
0.0857 mol C6H12O2 * (116.16 g C6H12O2 / 1 mol C6H12O2) = 9.96 g C6H12O2
7.55 g of butanoic acid would produce 9.95 g of ethyl butyrate, assuming a 100% yield.
To determine how many grams of ethyl butyrate would be synthesized from 7.55 g of butanoic acid, follow these steps:
Write the balanced chemical equation:
C₃H₇COOH + C₂H₅OH → C₃H₇COOC₂H₅ + H₂O
Calculate the molar mass:
Molar mass of butanoic acid (C₃H₇COOH) = 4(12.01) + 8(1.01) + 2(16.00) = 88.12 g/molFind the moles of butanoic acid:
Moles of C₃H₇COOH = 7.55 g / 88.12 g/mol = 0.0857 molDetermine the moles of ethyl butyrate:
According to the equation, 1 mole of butanoic acid produces 1 mole of ethyl butyrate. Thus, moles of ethyl butyrate = 0.0857 molCalculate the mass of ethyl butyrate:
Molar mass of ethyl butyrate (C₃H₇COOC₂H₅) = 4(12.01) + 10(1.01) + 2(16.00) = 116.16 g/molMass of ethyl butyrate = 0.0857 mol x 116.16 g/mol = 9.95 gSilver nitrate, agno3, reacts with iron(iii) chloride, fecl3, to give silver chloride, agcl, and iron(iii) nitrate, fe(no3)3. a solution containing 18.00 g of agno3 was mixed with a solution containing 32.40 g of fecl3. how many excess grams of the excess reactant remain after the reaction is over?
To determine the excess reactant after a reaction between silver nitrate and iron(III) chloride, calculate the moles of each reactant, identify the limiting reactant, and then calculate the remaining mass of the excess reactant using stoichiometry.
Explanation:The subject of the question is stoichiometry, which is a section of chemistry that involves the calculation of the quantities of reactants and products in chemical reactions. Specifically, the question asks to determine the excess grams of reactant remaining after a reaction between silver nitrate (AgNO3) and iron(III) chloride (FeCl3) has taken place.
To find the answer, we would calculate the moles of both reactants using their given masses and molar masses. Then, using the balanced chemical equation, we could determine the limiting reactant and the amount of excess reactant. From there, we can calculate the mass of the excess reactant remaining.
Is gasoline a compound or a mixture? compound mixture
Answer:
It is a mixture.
Explanation:
A compound is a pure substance which cannot be separated into its constituent by physical methods.
A mixture is a substance which can be separated into its constituent by physical methods.
Gasoline consists of different organic liquids.
These organic liquids can be separated by physical means like fractional distillation.
Thus gasoline will be a mixture. More specifically it is a homogeneous mixture.
Which compound is an example of a network solid? 1. H2O(s) 2. CO2(s) 3. SiO2(s) 4. SO2(s)
Which baroque element does vivaldi use to embellish the melodies in "spring"? this element is easily heard in the birdsong theme in "spring."?
Nuclear waste from fission reactions stays radioactive for a very long time.
Select one:
True
False
What precautions must be taken when mixing reagents in a separatory funnel or a centrifuge tube?
When you are mixing reagents in a separatory funnel it is important to vent it normally and do so in a method so that is it is not venting towards anybody. Also be certain to take out the stopper when draining the lower layer. If you do not take out the stopper, the pressure will not be correct, and the liquid will not pour out.
Final answer:
Proper precautions when mixing reagents in a separatory funnel or centrifuge tube include cushioning and securing equipment, careful pouring, and using the centrifuge correctly.
Explanation:
Precautions to take when mixing reagents in a separatory funnel or a centrifuge tube: When using a separatory funnel, ensure it is cushioned and secured, always pour liquids carefully to prevent spills, and vent pressure if needed. When using a centrifuge tube, cap it tightly, gently mix contents, and centrifuge to bring liquids to the bottom before removing. Be cautious with handling hot liquids, ensure equipment is properly set up, and avoid contamination by following proper lab techniques.
Is a banana turning brown when it is left on the counter a physical change?
A 50-mL beaker only has a scale that measures 10, 20, 30, and 40 mL. What is the uncertainty associated with the 50 mL beaker.
How many atoms of iron are in one formula unit of iron (III) chloride
How do you write a college psychology APA format abstract?????? Please help me, I procrastinated this essay and I'm really stressed.
(Do not label as “Introduction.” Title of paper goes at the top of the page—not bold)
The introduction of an APA-style paper is the most difficult to write. A good introduction will summarize, integrate, and critically evaluate the empirical knowledge in the relevant area(s) in a way that sets the stage for your study and why you conducted it. The introduction starts out broad (but not too broad!) and gets more focused toward the end. Here are some guidelines for constructing a good introduction:
Don’t put your readers to sleep by beginning your paper with the time-worn sentence, Past research has shown....(blah blah blah) They’ll be snoring within a paragraph! Try to draw your reader in by saying something interesting or thought-provoking right off the bat. Take a look at articles you’ve read. Which ones captured your attention right away? How did the authors accomplish this task? Which ones didn’t? Why not? See if you can use articles you liked as a model. One way to begin (but not the only way) is to provide an example or anecdote illustrative of your topic area.Although you won’t go into the details of your study and hypotheses until the end of the intro, you should foreshadow your study a bit at the end of the first paragraph by stating your purpose briefly, to give your reader a schema for all the information you will present next.Your intro should be a logical flow of ideas that lead up to your hypothesis. Try to organize it in terms of the ideas rather than who did what when. In other words, your intro shouldn’t read like a story of “Shirley did such-and-such in 1991. Then Gangelhoff did something-or-other in 1993. Then....(etc.)” First, brainstorm all of the ideas you think are necessary to include in your paper. Next, decide which ideas make sense to present first, second, third, and so forth, and think about how you want to transition between ideas. When an idea is complex, don’t be afraid to use a real-life example to clarify it for your reader. The introduction will end with a brief overview of your study and, finally, your specific hypotheses. The hypotheses should flow logically out of everything that’s been presented, so that the reader has the sense of, “Of course. This hypothesis makes complete sense, given all the other research that was presented.”When incorporating references into your intro, you do not necessarily need to describe every single study in complete detail, particularly if different studies use similar methodologies. Certainly, you want to summarize briefly key articles, though, and point out differences in methods or findings of relevant studies when necessary. Don’t make one mistake typical of a novice APA-paper writer by stating overtly why you’re including a particular article (e.g., “This article is relevant to my study because…”). It should be obvious to the reader why you’re including a reference without your explicitly saying so. DO NOT quote from the articles, instead paraphrase by putting the information in your own words.Be careful about citing your sources (see APA manual). Make sure there is a one-to-one correspondence between the articles you’ve cited in your intro and the articles listed in your reference section.Remember that your audience is the broader scientific community, not the other students in your class or your professor. Therefore, you should assume they have a basic understanding of psychology, but you need to provide them with the complete information necessary for them to understand the research you are presenting.METHOD An APA-style paper includes the following sections: title page, abstract, introduction, method, results, discussion, and references. Your paper may also include one or more tables and/or figures.How many electrons are in the outermost shell of an atom of phosphorus (p)? consult the periodic table. 15 5 30.974 3?
The total number of electrons in the outermost principal energy level or shell of a phosphorous atom is 5.
We have Phosphorous.
We have to determine the number of electrons are in the outermost shell of an atom of phosphorus.
What is Phosphorous ?Phosphorus is a chemical element with the symbol P and atomic number 15. Elemental phosphorus exists in two major forms, white phosphorus and red phosphorus.
According to the question -
We have an atom of phosphorous. The atomic number of phosphorous is 15. Now, if we look at the electronic configuration of phosphorous -
1s² 2s² 2p⁶ 3s² 3p³
The principal energy level (n = 3) has 2 electrons is s - subshell and 3 in
p - subshell. Therefore the total number of electrons in the outermost principal energy level or shell is 5.
Hence, the total number of electrons in the outermost principal energy level or shell of a phosphorous atom is 5.
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1362205.2 in scientific notation
For their summer holiday, Jane and her family are visiting places surrounding the Mediterranean Sea. Which type of biome is Jane and her family visiting?
Answer:
answer is Shrubland
How does the surface metabolism model of chemical evolution differ from the prebiotic soup model? see section 2.4 ( page 70) ?
The surface metabolism model evokes mineral catalysts. Surface metabolism model dissolved gases in contact with minerals lining the walls of the deep-sea hydrothermal vents and formed more complex, organic molecules while Prebiotic soup model is molecules in atmosphere or from meteorites condensed in the ocean which led to the formation of more complex molecules.
When you have taken too much of a chemical you should?
A 15.0 kg iron weightlifting plate has a volume of 1910 cm3 . What is the density of the iron plate in g/cm3?
The density of the iron weightlifting plate is approximately 7.85 g/cm³, which aligns with the reference density of iron.
Explanation:The density of an object is defined as its mass per unit volume. The question asks for the density of the iron plate, which can be calculated using the formula density = mass/volume.
To find the density of the 15.0 kg iron weightlifting plate with a volume of 1910 cm³, first convert the mass from kilograms to grams since the volume is given in cubic centimeters and density is often expressed in g/cm³. There are 1000 grams in a kilogram, so the mass of the plate is 15.0 kg × 1000 g/kg = 15000 g.
Now, density can be calculated as follows:
density = mass/volume
= 15000 g / 1910 cm³
≈ 7.85 g/cm³
This value is very close to the standard reference density for iron, which is around 7.86 g/cm³ to 7.9 g/cm³ under standard conditions.