The lengths of a particular type of metal rod are modeled by the equation r = |–24x + 120|, where r represents the lengths of the rod in inches, and x represents the speed at which the rods are produced, in rods per minute. If the manufacturing process is too fast or too slow, the rods will not be long enough. At what speeds will the lengths of the rods be greater than 48 inches?



A. The length of the rods will be greater than 48 inches when x > 3 or x < 7 rods per minute.


B. The length of the rods will be greater than 48 inches when x < 3 or x > 7 rods per minute.


C. The length of the rods will be greater than 48 inches when x > –3 or x < –7 rods per minute.


D. The length of the rods will be greater than 48 inches when 3 < x < 7 rods per minute

Answers

Answer 1
| -24x + 120| > 48

-24x + 120 > 48
-24x > 48 - 120
-24x > - 72
x < -72/-24
x < 3

-24x + 120 < -48
-24x < -48 - 120
-24x < - 168
x > -168/-24
x > 7

solution is : x < 3 or x > 7...answer B

Related Questions

Car rental at Q.T. Rental is $22 per day plus an initial deposit of $36.Which expression shows how much it will cost to rent a car for d number of days?

Answers

22d + 36 <== ur expression

Answer:

The expression is Price = 36 +22*d where d is each day that pass.

Step-by-step explanation:

The inicial 36 are the independant term since it's not related to how many days the car is rented. 22 is the slope since it depends on the days the car is rented.

Shelley spent 17 minutes washing dishes. She spent 38 minutes cleaning her room. Explain how you can use mental math to find how long Shelley spent on the two tasks.

Answers

17 + 38 your add both numbers. and you get 55
All you need to do is round up 17 and 38 to 20 and 40 in your head. Solve for that in your head and then subtract 5 from the sum.

20+40=60
60-5+55

You roll a pair of fair dice until you roll “doubles” (i.e., both dice are the same). what is the expected number, e[n], of rolls?

Answers

Final answer:

The expected number of rolls, e[n], to get doubles on a pair of fair dice is 6. This is calculated by recognizing that getting doubles has a probability of 1/6, and the expectation for a geometric distribution is the inverse of the probability (1/p).

Explanation:

To solve the problem of finding the expected number of rolls, e[n], to get doubles on a pair of fair dice, we first need to calculate the probability of rolling doubles. Since there are 6 faces on each die, there are a total of 6 x 6 = 36 possible outcomes when rolling two dice.

Out of these 36 possible rolls, there are 6 outcomes that result in doubles: (1,1), (2,2), (3,3), (4,4), (5,5), and (6,6). This means the probability of getting doubles in one roll is 6/36, which simplifies to 1/6.

Because each roll is independent, we can model the scenario using a geometric distribution, where the expected value, or mean, is given by 1/p, where p is the success probability. Substituting p with 1/6, the expected number of rolls to get doubles would be 1/(1/6) = 6.

Therefore, the expected number of rolls needed to roll doubles is 6.

Assume that a procedure yields a binomial distribution with a trial repeated n times. use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial. round to three decimal places. n = 14, x = 6 , p = 0.5

Answers

The binomial probability formula is given by

ⁿCₓ (p)ˣ (q)ⁿ⁻ˣ

Where q = 1 - p

We have
n = 14
x = 6
p = 0.5
q = 1 - 0.5 = 0.5

Substitute these values into the formula, we have

¹⁴C₆ × 0.5⁶ × 0.5⁸ = 0.183 (rounded to three decimal places)

how do you write 20484163 in different forms

Answers

You mean 20,484,163?

If so..

Standard form would be: 20,484,163

Word form would be: twenty million, four hundred eighty-four thousand, one hundred sixty-three

Expanded form would be: 20,000,000 + 400,000 + 80,000 + 4,000 + 100 + 60 + 3

The sum of 7 consecutive odd numbers is 91. What is the sum of the two largest numbers in this set?

Answers

7 consecutive odd numbers...x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 + x + 12 = 91
7x + 42 = 91
7x = 91 - 42
7x = 49
x = 49/7
x = 7

x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13
x + 8 = 7 + 8 = 15
x + 10 = 7 + 10 = 17
x + 12 = 7 + 12 = 19

the sum of the 2 largest numbers is : 17 + 19 = 36 <==

A car uses 25L of petrol to travel 280km. What is the rate of petrol usage in kilometres per litre?

Answers

The rate of petrol per liter is 11.2 liter

What is unitary method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

In 25l car travels = 280km

For finding rate of petrol per liter we have to divide as

Rate of petrol = 280/25

Rate of petrol = 11.2 liter

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The rate of petrol usage for the car is 11.2 kilometers per litre, calculated by dividing the distance travelled, 280km, by the amount of petrol used, 25L.

The question asks to find the rate of petrol usage in kilometers per litre for a car that uses 25L of petrol to travel 280km. To calculate the fuel efficiency, you divide the distance travelled by the amount of petrol used.

Step-by-step calculation:

Distance travelled = 280 km

Amount of petrol used = 25L

Fuel efficiency (km/L) = Distance travelled / Amount of petrol used

Fuel efficiency = 280 km / 25L = 11.2 km/L

Therefore, the car's fuel efficiency is 11.2 kilometers per litre.

Find the area under the standard normal distribution curve to the left of z=-2.15 and to the right of z=1.62

Answers

The area under the standard normal distribution represents probability from 0 to 1.
So, what's being asked, in essence, is what is P(Z ≤ -2.15) and P(Z ≥ 1.62).
P(Z ≤ -2.15) = 1 - P(Z ≤ 2.15) = 1 - 0.9842 = 0.0158.
P(Z ≥ 1.62) = 1 - P(Z ≤ 1.62) = 1 - 0.9474 = 0.0526

Using the normal distribution table, which shows the percentage of the areas to the left a normal distribution, the area to the left z = - 2.15 and area to the right of z = 1.62 are 0.0158 and 0.0526 respectively.

1.)

The area under the normal distribution curve to the left of z = 2.15 can be expressed thus :

P(Z ≤ -2.15)

Using a normal distribution table ; the area to the left is

P(Z ≤ -2.15) = 0.0158

2.)

The area under the normal distribution curve to the right of z = 1.62 can be expressed thus :

P(Z ≥ 1.62) = 1 - P(Z ≤ 1.62)

Using a normal distribution table ; the area to the left is P(Z ≤ 1.62) = 0.94738

P(Z ≥ 1.62) = 1 - 0.94738 = 0.0526

Therefore, the area to the left z = - 2.15 and area to the right of z = 1.62 are 0.0158 and 0.0526 respectively.

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What is the midpoint of the line segment (-3,-2) and (1,4)

Answers

Answer:

  (-1, 1)

Step-by-step explanation:

The midpoint (M) is found by averaging the coordinates of the end points:

  M = ((-3, -2) +(1, 4))/2 = ((-3+1)/2, (-2+4)/2) = (-2/2, 2/2)

  M = (-1, 1)

The midpoint of the line segment is (-1, 1).

If the minimum value of the function y = cos θ + d is –5, the value of d is...

Answers

the minimum value of cosθ is -1
-1 + d = -5
d = -4

The value of d, when the function is at its minimum is -4.

What is a Function?

A function is a law that relates two variables namely, a dependent and an independent variable.

A function always has a defined range and domain, domain is all the value a function can have as an input and range is all the value that a function can have.

The function is of various types, logarithmic, exponential, quadratic, radical etc.

The function is y = cos [tex]\rm \theta[/tex] + d

The minimum value of the function, y = cos [tex]\rm \theta[/tex] + d is -5.

The minimum value is the lowest value of the function.

The minimum value of cos [tex]\rm \theta[/tex] is at 180 degree equals to  -1

Substituting the value in the equation.

-5 = - 1 + d

d = -5 +1

d = -4

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Suppose you have a normally distributed set of data pertaining to a standardized test. the mean score is 1000 and the standard deviation is 200. what is the z-score of 900 point score? 1.5 1 0.5 â0.5

Answers

The z-score is calculated by teh equation,
                       z-score  = (X - μ) / σ
where X is the given data, μ is the mean/average and σ is the standard deviation.

From the given above,
X = 900
μ = 1000
σ = 200

Substituting the known values from the given above to the equation,
                        z-score = (900 - 1000)/ 200
                        z-score = (-100)/200
                        z-score = -1/2 = -0.5

Hence, the value of z-score is equal to -0.5. 

Write five numbers that round to 360 When rounded to the nearest 10.

Answers

355, 356, 357, 358, 359

Omar's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Omar $4.85 per pound, and type B coffee costs $5.95 per pound. This month's blend used twice as many pounds of type B coffee as type A, for a total cost of $519.25 . How many pounds of type A coffee were used?

Answers

27 pounds of Type A coffee 

If the APR of a savings account is 3.6% and interest is compounded monthly, what is the approximate APY of the account?

Answers

The Answer is ''3.66%''

Answer:

3.66% ( approx )

Step-by-step explanation:

Since, the formula of annual percentage yield is,

[tex]APY = (1+\frac{r}{n})^n-1[/tex]

Where,

r = stated annual interest rate,

n = number of compounding periods,

Here, r = 3.6% = 0.036,

n = 12 ( ∵ 1 year = 12 months )

Hence, the annual percentage yield is,

[tex]APY=(1+\frac{0.036}{12})^{12}-1=1.03659 - 1 = 0.036599\approx 0.0366 = 3.66\%[/tex]

Given the following triangle, if a = 12 and ∠B = 48°, find b to the nearest whole number.

Answers

In the figure, the triangle ABC is a right triangle, a is the adjacent leg to the angle B, and b is the opposite side to the same angle.

So, you can use the tangent ratio which relates the angle, the opposite leg and the adjacent leg:

tangent (angle B) = b / a => b = a * tan(B)

=> b = 12 * tan(48°) = 13.33≈ 13

Answer: 13


Answer:

The value of b nearest whole number is, 13.

Step-by-step explanation:

We know an [tex]\angle B=48^{\circ}[/tex] and the side adjacent to it i.e, a=12.\

In a right triangle BCA ,

the tangent(tan) of an angle is the length of the opposite side divided by the length of the adjacent side.  

i.e, [tex]\tan B=\frac{opposite}{Adjacent}=\frac{b}{a}[/tex]

Substitute the value of a=12 and [tex]\angle B=48^{\circ}[/tex] to solve for b in above expression:

[tex]\tan 48^{\circ}=\frac{b}{12}[/tex]

we have the value of [tex]\tan 48^{\circ}=1.110613[/tex]

then, [tex]1.20012724=\frac{b}{12}[/tex]

On simplify we get,

[tex]b=1.110613 \times 12=13.327356[/tex]

Therefore, the value of b nearest whole is, 13


61702 67102 same or different?

Answers

The numbers differ by 5,400, with 67,102 being greater than 61,702.

Let me know if you need any more help!

The area of one triangle is 150 square centimeters when it's height is 20 centimeters and it's base length is 15 centimeters. What is the area of a triangle having a height of 30 centimeters and a base length of 18 centimeters.

Answers

Formula for finding the area of a triangle: [tex]A = \frac{1}{2}bh[/tex]
Where b is the base and h is the height.

Substitute the variables for the values.

[tex]A = \frac{1}{2}(30)(18)[/tex]
[tex]A = \frac{1}{2}540[/tex]
A = 270

So, the area is 270 square centimeters.


 Donna and Phyllis are reviewing for a math final. They have 150 pages to cover. Donna can review 37 pages an hour, but Phyllis can only go 2/3 as fast as Donna. About how long does it take each girl to finish?

Answers

Donna: 37 pages per hour.  There are 150 pages.
Time: 150 pages  / (37 pages/hour)
= 150/37 hours
= 4 hours 3 1/2 min. (approx.)

Phyllis: (2/3)*37 pages per hour.  There are 150 pages.
Time: 150 pages / ((2/3)*37 pages / hour )
= 150*3/(2*37) hours
= 225/37 hours
= 6 hours 5 minutes (approx.)

Donna will finish reviewing in about 4.05 hours, while Phyllis will take approximately 6.08 hours.

Donna and Phyllis are reviewing for a math final and have 150 pages to cover. Let's calculate how long it takes each girl to finish reviewing:

Donna can review 37 pages an hour. To find the time she needs, we use the formula:

Time = Total Pages / Pages per Hour
Time = 150 / 37
Time ≈ 4.05 hours

Phyllis reviews at 2/3 of Donna's speed. So, her rate is:

Phyllis' rate = (2/3) × 37 ≈ 24.67 pages per hour

To find the time Phyllis needs, we use the same formula:

Time = Total Pages / Pages per Hour
Time = 150 / 24.67
Time ≈ 6.08 hours

In summary, Donna will finish reviewing in about 4.05 hours, while Phyllis will take approximately 6.08 hours.

Explain why rationalizing the denominator does not change the value of the original expression

Answers

Rationalizing is just simpllifying, so the simplified value has the same value as the original expression.

Answer:

Because basically, you are multiplying by 1

Step-by-step explanation:

Let me explain this with an example. Rationalize the following expression:

[tex]\frac{5}{\sqrt{7} }[/tex]

In order to rationalize the denominator, the numerator and denominator of the fraction must be multiplied by the root of the denominator. So, what happen if you do that? Well first of all you aren't altering the expression because:

[tex]\frac{\sqrt{7} }{\sqrt{7} } =1[/tex]

Right? Because a certain quantity divided by itself is always equal to 1. So basically you are doing this because you want to rewrite the expression without altering its original value, it is the same when you do this:

[tex]9=3^2=3+3+3=\sqrt{81}[/tex]

Therefore, the only thing you do when you rationalize is remove radicals from the denominator of a fraction. Take a look:

[tex]\frac{5}{\sqrt{7} } *\frac{\sqrt{7} }{\sqrt{7} } =\frac{5*\sqrt{7} }{\sqrt{7}*\sqrt{7} } =\frac{5*\sqrt{7}}{(\sqrt{7} )^2} =\frac{5*\sqrt{7} }{7}[/tex]

You can check this new expression is equal to the original using a calculator:

[tex]\frac{5}{\sqrt{7} } \approx1.8898\\\\\frac{5*\sqrt{7} }{7} \approx1.8898[/tex]

The variable z is directly proportional to x and inversely proportional to y. When x is 12 and y is 18 z has the value 2 what is the value of z when x = 19 and y = 22

Answers

[tex]\bf \qquad \qquad \textit{double proportional variation}\\\\ \begin{array}{llll} \textit{\underline{y} varies directly with \underline{x}}\\ \textit{and inversely with \underline{z}} \end{array}\implies y=\cfrac{kx}{z}\impliedby \begin{array}{llll} k=constant\ of\\ variation \end{array}\\\\ -------------------------------\\\\[/tex]

[tex]\bf z=\cfrac{kx}{y}\impliedby \begin{array}{llll} \textit{directly proportional to "x"}\\ \textit{and inversely proportional to "y"} \end{array} \\\\\\ \textit{we also know that } \begin{cases} x=12\\ y=18\\ z=2 \end{cases}\implies 2=\cfrac{k12}{18}\implies \cfrac{2\cdot 18}{12}=k \\\\\\ \boxed{3=k}\qquad thus\qquad \boxed{z=\cfrac{3x}{y}}\\\\ -------------------------------\\\\ \textit{what's "z" when } \begin{cases} x=19\\ y=22 \end{cases}\implies z=\cfrac{3\cdot 19}{22}[/tex]

Solve cos x +sqr root of 2 = -cos x for x over the interval 0,2pi

Answers

[tex]\bf cos(x)+\sqrt{2}=-cos(x)\implies 2cos(x)+\sqrt{2}=0\implies 2cos(x)=-\sqrt{2} \\\\\\ cos(x)=-\cfrac{\sqrt{2}}{2}\implies \measuredangle x= \begin{cases} \frac{3\pi }{4}\\ \frac{5\pi }{4} \end{cases}[/tex]

Using the given zero, find all other zeros of f(x).
-2i is a zero of f(x) = x4 - 32x2 - 144


a) 2i, 12, -12

b) 2i, 6i, -6i

c) 2i, 6, -6

d) 2i, 12i, -12i

Answers

Using the given zero, find all other zeros of f(x). -2i is a zero of f(x) = x4 - 32x2 - 144 

Answer: C; 2i,6,-6

Answer:

c) 2i, 6, -6

Step-by-step explanation:

The given function is

[tex]f(x)=x^{4}-32x^{2} -144[/tex]

The given zero to this function is

[tex]x=-2i[/tex]

Remember that a function has so many roots as its grade dictates. So, in this case, the function grade is four, which means it has four solutions.

Now, the given function is an imaginary number, which happens in pairs, that means the second root must be [tex]x=2i[/tex], because a function can have complex roots as pairs, 2, 4, 6,... many solutions.

The other two solutions are 6 and -6, because if we replace them into the function, it will give zero.

[tex]f(6)=6^{4}-32(6)^{2} -144=0\\f(-6)=(-6)^{4}-32(-6)^{2} -144=0[/tex]

Therefore, the other three solutions missing are: c) 2, 6, -6.

(The image attached shows the real solutions).

how to simplify expression by distribution 3(2y-7)

Answers

6y-27
Multiply 3 by everything inside the parenthesis

Carlos is putting money into a savings account. He starts with $750 in the savings account, and each week he adds $40 . Let S represent the total amount of money in the savings account (in dollars), and let W represent the number of weeks Carlos has been adding money. Write an equation relating S to W . Then use this equation to find the total amount of money in the savings account after 11 weeks.

Equation:
Total amount of money after 11 weeks:

Answers

Final answer:

The equation relating the total amount of money S in Carlos's savings to the number of weeks W he adds money is S = 750 + 40W. By substituting W with 11, we find that after 11 weeks, Carlos will have $1,190 in his savings account.

Explanation:

The question involves creating a linear equation to represent the relationship between the total amount of money S in Carlos's savings account and the number of weeks W he has been adding money. The equation can be written as S = 750 + 40W, where 750 represents the initial amount and 40 is the amount added each week. To find the total amount of money after 11 weeks, substitute W with 11:

S = 750 + 40(11) = 750 + 440 = 1190

Therefore, after 11 weeks, the total amount of money in the savings account would be $1,190.

The brightness of a variable star adds a component to the simple harmonic motion we have studied in this lesson. Since the brightness is variable the vertical axis may no longer be equal to zero. Also included in the variance is a phase shift. In this case, the equation for this function would be: y = a cos w(t – c ) + b.

Suppose we have a variable star whose brightness alternately increases and decreases. For this star, the time between periods of maximum brightness is 6.5 days. The average brightness (or magnitude) of the star is 5.0 and its brightness varies by + 0.25 magnitude.


1. What is the amplitude of the function for this model?

2. What is the period?

3. What is w?

4. What is the vertical shift?

5. Is there a phase shift? If so, what is it?

6. What is the function

Answers

The given model is
y a cos w(t - c) + b

1. The brightness varies by  0.25. Therefore the amplitude is
   a = 0.25

2. The time between maximum brightness is 6.5 days.
    Therefore the period is T = 6.5 days

3. By definition,
    w = 2π/T. Therefore,
    w = 2π/6.25 = 0.967

4. The average brightness is 5, therefore the vertical shift is b = 5.

5. Assume that maximum brightness occurs at the time, t = 0.
    Therefore there is no phase shift so that c = 0.

6. The function is
     y = 0.25 cos(0.967t) + 5

A graph of the function is shown below.
   

13-36x^2=-12 which value of x is a solution to he equation

Answers

13-36x^2=-12

36x^2=-12-13
x^2=24/36

×1=-5/6 ×2=5/6

If we reject the null​ hypothesis, can we claim to have proved that the null hypothesis is​ false? why or why​ not?

Answers

Yes, you can claim that the null hypothesis. But you must pay attention the p-value. If the p-value is higher than the significant value the null hypothesis can't be rejected.

The daily mean temperature in a particular place is 83. how many cooling-degree days were accumulated?

Answers

Degree days are the difference between the daily temperature mean, (high temperature plus low temperature divided by two) and 65°F. 65°F because we assume that at this temperature we do not need cooling or heating. 
In our case the daily mean temperature is 83°F and X is the number of cooling-degree days.
X=83-65
X=18

The bookstore ordered 15 Sociology work books and 10 Economy 101 textbooks on August 1st to prepare for the fall semester. After realizing they miscounted, the bookstore order 1 more Sociology workbook and three more Economy 101 textbooks on August 15th. If August 1st the order was for $4300 and the August 15th order was $800 , find the cost of one Sociology workbook and one Economy 101 textbook?

Answers

e = number of books on Economy
s = number of books on Sociology

so the order on August 1st looks like 15s + 10e = 4300
and the order on August 15th looks like 1s + 3e = 800

[tex]\bf \begin{array}{lllll} 15s&+&10e&=&4300\\ s&+&3e&=&800 \end{array}\\\\ -------------------------------\\\\ \boxed{s}=800-3e\qquad thus \\\\\\ 15s+10e=4300\implies 15\left( \boxed{800-3e} \right)+10e=4300\qquad then \\\\\\ 12000-45e+10e=4300\implies 12000-4300=45e-10e \\\\\\ 7700=35e\implies \cfrac{7700}{35}=e\implies \boxed{220=e} \\\\\\ now \qquad s+3e=800\implies s+3(220)=800\implies s=800-660 \\\\\\ \boxed{s=140}[/tex]
Final answer:

The cost of one Sociology workbook is $140, and the cost of one Economy 101 textbook is $220, determined by solving two simultaneous equations based on the initial and additional orders placed by the bookstore.

Explanation:

To solve for the cost of one Sociology workbook and one Economy 101 textbook, let's label the cost of one Sociology workbook as S and the cost of one Economy 101 textbook as E. Initially, the bookstore ordered 15 Sociology workbooks and 10 Economy 101 textbooks, spending a total of $4300. This gives us the equation: 15S + 10E = 4300. Later, the store ordered an additional 1 Sociology workbook and 3 Economy 101 textbooks for $800, leading to the equation: 1S + 3E = 800.

To solve these equations simultaneously, we can multiply the second equation by 15 to get 15S + 45E = 12000 and subtract the first equation from it: (15S + 45E) - (15S + 10E) = 12000 - 4300, simplifying to 35E = 7700. Dividing both sides by 35 gives us E = 220. Substituting E = 220 back into the first equation 15S + 10(220) = 4300 gives us 15S + 2200 = 4300, thus 15S = 2100 and S = 140.

Therefore, the cost of one Sociology workbook is $140 and the cost of one Economy 101 textbook is $220.

A cone-shaped paper drinking cup is to be made to hold 36 cm3 of water. find the height and radius of the cup that will use the smallest amount of paper. (round your answers to two decimal places.)

Answers

The formula for volume of cone is:

V = π r^2 h / 3

or

π r^2 h / 3 = 36 cm^3

Simplfying in terms of r:

r^2 = 108 / π h

To find for the smallest amount of paper that can create this cone, we call for the formula for the surface area of cone:

S = π r sqrt (h^2 + r^2)

S = π sqrt(108 / π h) * sqrt(h^2 + 108 / π h) 

S = π sqrt(108 / π h) * sqrt[(π h^3 + 108) / π h] 

Surface area = sqrt (108) * sqrt[(π h + 108 / h^2)] 

Getting the 1st derivative dS / dh then equating to 0 to get the maxima value:

dS/dh = sqrt (108) ((π – 216 / h^3) * [(π h + 108/h^2)^-1/2] 

Let dS/dh = 0 so,

 π – 216 / h^3 = 0 

h^3 = 216 / π

h = 4.10 cm

Calculating for r:

r^2 = 108 / π (4.10)

r = 2.90 cm

 

Answers:

 h = 4.10 cm

r = 2.90 cm

The height of the cone is [tex]\boxed{4.10}[/tex] and the radius of the cone is [tex]\boxed{2.90}.[/tex]

Further explanation:

The volume of the cone is [tex]\boxed{V = \dfrac{1}{3}\left( {\pi {r^2}h} \right)}.[/tex]

The surface area of the cone is [tex]\boxed{S=\pi \times r\times l}[/tex]

Here l is the slant height of the cone.

The value of the slant height can be obtained as,

[tex]\boxed{l = \sqrt {{h^2} + {r^2}} }[/tex].

Given:

The volume of the cone shaped paper drinking cup is [tex]36{\text{ c}}{{\text{m}}^3}[/tex].

Explanation:

The volume of the cone shaped paper drinking cup  [tex]36{\text{ c}}{{\text{m}}^3}[/tex].

[tex]\begin{aligned}V&=36\\\frac{1}{3}\left({\pi {r^2}h}\right) &= 36\\{r^2}&= \frac{{108}}{{\pi h}}\\\end{aligned}[/tex]

The surface area of the cone is,

[tex]\begin{aligned}S &= \pi\times\sqrt {\frac{{108}}{{\pi h}}}\times\sqrt {{h^2} + \frac{{108}}{{\pi h}}}\\&= \sqrt{108}\times\sqrt{\frac{{\pi {h^3} + 108}}{{\pi h}}}\\&=\sqrt {108}\times\sqrt {\pi h + \frac{{108}}{{{h^2}}}}\\\end{aligned}[/tex]

Differentiate above equation with respect to h.

[tex]\dfrac{{dS}}{{dh}}=\sqrt {108}\times \left( {\pi  - \dfrac{{216}}{{{h^3}}}}\right)\times {\left( {\pi h + \dfrac{{108}}{{{h^2}}}}\right)^{ - \dfrac{1}{2}}}[/tex]

Substitute 0 for [tex]\dfrac{{dS}}{{dh}}[/tex].

[tex]\begin{aligned}\pi- \dfrac{{216}}{{{h^3}}}&= 0\\\dfrac{{216}}{{{h^3}}}&= \pi\\\dfrac{{216}}{{3.14}} &= {h^3}\\h &= 4.10\\\end{aligned}[/tex]

The radius of the cone can be obtained as,

[tex]\begin{aligned}{r^2}&=\frac{{108}}{{\pi \left({4.10} \right)}}\\{r^2}&= \frac{{108}}{{3.14 \times 4.10}}\\{r^2}&= 8.40\\r&= \sqrt {8.40}\\r &= 2.90\\\end{aligned}[/tex]

Hence, the height of the cone is  [tex]\boxed{4.10}[/tex]and the radius of the cone is [tex]\boxed{2.90}[/tex].

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Mensuration

Keywords: cone shaped paper, drinking cup, volume, [tex]36{\text{ c}}{{\text{m}}^3}[/tex], height of cone, cup, smallest amount of paper, water.

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