Final answer:
The loudness of a sound is primarily determined by the amplitude of the sound wave, where larger amplitudes result in louder sounds. This is measured in decibels (dB). The perceived loudness also depends on the force of vibration and the frequency sensitivity of the human ear.
Explanation:
The loudness of sound is determined by the amplitude of vibration. The amplitude, or height of the sound wave, dictates how much energy it carries, subsequently influencing its perceived loudness or volume.
A wave with a larger amplitude carries more energy, resulting in a louder sound, while a smaller amplitude corresponds to a softer sound. This is why sound C in a diagram with higher amplitude waves is louder than sound B with lower amplitude waves.
Loudness is often measured in decibels (dB), with larger waves and consequently greater amplitudes reflected in higher decibel levels. As an example, a typical conversation may measure around 60 decibels, considerably louder than a faint whisper at 30 decibels, illustrating the impact of amplitude on the loudness of sounds we encounter daily.
However, the strength of the sensation, or intensity, also plays a role, mainly governed by the force behind the vibrating body - more force results in a wider vibration and greater intensity.
Yet, the ear's sensitivity to different frequencies also affects perceived loudness; we may perceive sounds as louder if they are within the frequency range where the ear is most sensitive.
A light wave traveling through an unknown medium strikes the boundary with
water at a 45° angle and then refracts toward the boundary. What could the
If light refracts toward the normal when passing from water to an unknown medium, it indicates that the unknown medium has a higher index of refraction than water.
Explanation:When light waves travel through water and encounter a boundary with another medium at a non-normal angle, they undergo refraction. If the medium has an index of refraction higher than that of water, the light waves slow down, bending toward the normal due to the change in speed. According to Snell's law, the path of light is dependent on the indices of refraction of the two media and the angle of incidence. In this case, if the angle of refraction is closer to the normal compared to the angle of incidence, it indicates that the unknown medium has a higher index of refraction than water.
So I answered this question and I got it wrong. The correct answer is in red. Can someone explain me why the correct answer is 140s/the temperature starts to rise? I don't understand it.
i) The lowest temperature recorded is [tex]12^{\circ}C[/tex]
ii) All the liquid has evaporated after 140 seconds
Explanation:
i)
In this part of the problem, we have to find the lowest temperature recorded as the liquid evaporates.
In order to do that, we have to look at the graph, where we have:
- The time (in seconds) represented on the x-axis
- The temperature (in Celsius degrees) represented on the y-axis
The lowest temperature recorded corresponds to the minimum value of the variable on the y-axis. By looking at the graph, we see that the temperature starts from [tex]20^{\circ}[/tex] at time [tex]t=0[/tex], then it reaches a minimum of approximately [tex]12^{\circ}C[/tex] at about [tex]t=140 s[/tex], then it increases again. Therefore, the lowest temperature recorded is [tex]12^{\circ}C[/tex].
ii)
In this part, we have to determine how long it takes for all the liquid to evaporate.
The process of evaporation of a liquid takes place when the molecules located on the surface of the liquid, which have more kinetic energy than the other molecules, "escape" the liquid. When these molecules escape the liquid, they remove heat from the liquid (because they carry away energy): therefore, the temperature (which is a measure of the kinetic energy) at the surface of the liquid decreases. This effect is known as cooling effect of evaporation.
When this decrease in temperature stops, it means that the liquid has completely evaporated. From the graph, we see that this occurs when the time is approximately about 140 seconds.
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A girl is riding her bike at as speed of 12 m/s. She weighs 55 kg and her bike weighs 22kg. What is the kinetic energy of the girl and her bike?
Answer:
Kinetic energy of the girl and her bike is 5.544 kJ
Explanation:
Given that a girl is riding bike at speed of 12m/s
Also, mass of Girl is 55kg and mass of bike is 22kg
Let, Total mass of girl and bike be M=22+55=77kg
Now, Kinetic energy is given by K=[tex]\frac{1}{2} Mv^{2}[/tex]
Hence, Kinetic energy of the girl and her bike will be
K=[tex]\frac{1}{2} Mv^{2}[/tex]
K=[tex]\frac{1}{2} (77)(12)^{2}[/tex]
K=5544J
Thus, Kinetic energy of the girl and her bike is 5.544 kJ
what is the maximum weight a boat can hold if a boat can displace 60.5ml?
a. 60.5 kg
b. 30.25 grams
c. 60.5 grams
d. 30.25 kg
Answer:
a. 60.5 kg
Explanation:
Given data,
The maximum water a boat can displace is, 60.5 ml
According to the principle of buoyancy, the weight of the floating body is equal to the weight of the liquid displaced.
Under standard temperature and pressure, a unit mass of water equals one liter.
If a boat can displace a maximum of 60.5 ml of water, then it can hold a mass of a maximum of 60.5 kg of mass.
What station broadcasts waves with more energy? (WIL-92.3 OR KSHE-94.7)
Answer:
KSHE [tex]94.7[/tex]
Explanation:
Given stations WIL [tex]92.3[/tex] and KSHE [tex]94.7[/tex]
The station number represents the frequency that waves of radio emit. They are measured in megahertz (MHZ).
Using the formula
[tex]E=h\nu[/tex]
Where [tex]E[/tex] is energy.
[tex]h[/tex] is Planck's constant.
[tex]\nu[/tex] is frequency.
We can see energy is directly related to frequency. A higher frequency will give higher energy.
As channel KSHE [tex]94.7[/tex] has more frequency than channel WIL [tex]92.3[/tex].
So, channel KSHE [tex]94.7[/tex] will have more energy.
Susan goes out to exercise. She runs for one hour at a constant speed and velocity. What is the overall net force acting on
Susan?
Answer:
Overall net force is zero.
Explanation:
Given:
Susan exercise for 1 hour at constant velocity and constant speed.
So, there is no change in the velocity for 1 hour.
We know that, acceleration is the quantity that measures the change in velocity over a given time interval. If there is no change in velocity or if velocity remains constant for a given time interval, then the acceleration of the body is zero.
Now, from Newton's second law, we know that, the net force acting on a body is directly proportional to its acceleration. Therefore, for a body to experience zero acceleration means that the body will have zero net force.
Susan here exercises at constant velocity and so, her net acceleration is zero. Therefore, the overall net force acting on her will also be zero as net force is directly proportional to the acceleration.
Final answer:
In an ideal scenario ignoring external factors, the overall net force acting on Susan while she runs at a constant speed and velocity is zero, as per Newton's first law of motion.
Explanation:
The question is concerned with a scenario where Susan is running at a constant speed and velocity, implying that she is not accelerating. According to Newton's first law of motion, also known as the law of inertia, an object in motion at a constant velocity will remain in motion at that velocity unless acted upon by a net external force. Since Susan is running at a constant speed and velocity, this means there is no net external force acting on her because all forces are balanced.
Based on Newton's second law, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (Fnet = ma), and given that Susan is not accelerating (acceleration is zero), the net force acting on her is also zero. This assumes ideal conditions where external factors like air resistance and friction are negligible or perfectly balanced by Susan’s forward force.
The psychologist known for latent learning and cognitive maps is _________. A. Robert Rescorla B. Edward Tolman C. William James D. B. F. Skinner
Answer:
B
Explanation:
B. Edward Tolman
The psychologist known for latent learning and cognitive maps is B. Edward Tolman
Explanation:The psychologist known for latent learning and cognitive maps is Edward Tolman. Tolman's various experiments with rats demonstrated that organisms can learn even if they do not receive immediate reinforcement, suggesting a cognitive aspect to comprehensive learning.
In some specific experiments, hungry rats were placed in a maze with no reward for finding their way through it. As they explored the maze, they developed a cognitive map or a mental picture of the maze layout. This is known as latent learning, which is learning that occurs but is not observable in behavior until there is a reason to demonstrate it.
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1. A projectile is launched into the air with an initial speed of vi = 40 m/s at a launch
angle of 20° above the horizontal. The projectile lands on the ground 5.0 seconds
later.
Neglecting air resistance, calculate the projectile's range and draw projectile
path
Answer:
range = x = 188 [m]
Explanation:
First we must find the velocity component on the horizontal axis or x-axis
[tex](v_{x})_{0} = 40*cos(20) \\(v_{x})_{0} = 37.58[m/s]\\[/tex]
Then using the kinematic expression that relates velocity with time, we can find the range of the projectile or the distance x.
[tex]x=(v_{x} )_{0}*t\\ x=37.58*5\\x=188[m][/tex]
What is DC in electricity mean?
Answer:
Direct Current
Explanation:
The electricity only flows in one direction.
A weight of 20.0 N hangs motionless from a spring, with a spring constant of 65.0 N/m. How far is the spring stretched from its original length?
0.130 m
0.308 m
0.769 m
3.25 m
Answer:
0.308 m
Explanation:
Force = spring constant * change in length
F = k * Δx
F = 20 N
k = 65 N/m
Δx = ? m
20 = 65 * Δx
20/65 = Δx
Δx = 0.308 m
According to the question,
Spring constant, k = 65 N/mForce, F = 20 NThe force will be:
→ [tex]Force =Spring \ constant\times Change \ in \ length[/tex]
or,
→ [tex]F = k\times \Delta x[/tex]
then,
→ [tex]\Delta x = \frac{F}{k}[/tex]
By putting the values,
[tex]= \frac{20}{65}[/tex]
[tex]= 0.308 \ m[/tex]
Thus the above answer is right.
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Calculate the volume of 1280 kilograms of aluminium if the density of aluminium is 2700 kg/m³. Give your answer to 2 decimal places.
Answer:
volume = 0.47 [tex]m^{3}[/tex].
Explanation:
Density:
[tex]d = \frac{m}{v}[/tex]
We have that d = 2700 kg/[tex]m^{3}[/tex] and that we have 1280 kg of Al.
[tex]2700 = \frac{1280}{V}[/tex]
V = 0.47 [tex]m^{3}[/tex]
Answer:
The correct answer is 0.47 m³
Explanation:
The formula for density (d) is
Mass (m) ÷ volume (v)
Hence
d = m ÷ v
The density of aluminium (as provided in the question) is 2700 kg/m³ and the mass of aluminium is 1280 kg, the volume is however unknown.
Thus, from the formula earlier
2700 = 1280 ÷ v
v = 1280 ÷ 2700
v = 0.47 m³
The volume of aluminium when the density is 2700 kg/m³ and the mass is 1280 kg is 0.47 m³
How much heat does it take to raise the temperature of 0.10kg of gold by 25°C
322.5 joules
Explanation:Data given;
Mass of Gold is 0.10 kg Change in temperature as 25°CWe are supposed to determine the amount of heat required.
We know that quantity of heat is given by the product of mass of a substance by its specific heat and by the change in temperature.That is, Q = mcΔTIn this case, specific heat, c of gold is 0.129 J/g/°C
Mass of gold in grams is 100 g
Therefore;
Q = 100 g × 0.129 J/g/°C × 25°C
= 322.5 joules
Thus, the amount of heat required is 322.5 Joules
When light is reflected, the "outgoing" ray is also called the _____ ray.
A. incident
B. reflected
C. bouncing
D. electromagnetic
Answer:
When light is reflected, the "outgoing" ray is also called the reflected ray.
Explanation:
when an light ray is incident on a boundary of two mediums it an reflect or refract.
reflected ray is the part of the ray that gets back with same mediu that it was coming from. angle of reflection and incident are equal . angle of reflection and incident are the angle made by the reflected and incident ray with the normal.
total internal reflection occurs when the incident angle is greater than the critical angle of pair of given medium and when light travels from denser to rarer medium . in total internal reflection ray gets reflected with no loss at all.
in refracted ray the the light ray passes to the other medium angle of incidence and refraction are not same.
bubba approach billie and gives him a swift shove.timid little billie keeps his hands in his pocket during this interaction.subsequently, while bubba places a force upon billie,billie does not place a force upon bubba
Answer:
Bubba like Billie :)
Final answer:
Newton's Third Law of Motion dictates that a force exerted on Billie by Bubba results in an equal and opposite force exerted back on Bubba, regardless of Billie's actions.
Explanation:
The scenario described involves Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. Despite Billie keeping his hands in his pockets, when Bubba pushes Billie, there is a force exerted back on Bubba, even if Billie does not actively push back. This interaction is involuntary and happens naturally due to the laws of physics.
Is the relationship between velocity and centripetal force a direct, linear or nonlinear square relationship?
Answer:
non linear square relationship
Explanation:
formula for centripetal force is given as
a = mv^2/r
here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have
a = constant × v^2
a α v^2
hence non linear square relationship
The relationship between velocity and centripetal force is a nonlinear square relationship.
The centripetal force is given by;
F = mv^2/r
The centripetal force is the force required to keep an object moving in a circular path.
If we take the relationship between the centripetal force and velocity as we can see in the equation above, we realize that it is a nonlinear square relationship. Therefore, the relationship between velocity and centripetal force is a nonlinear square relationship.
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What do human beings get from forest?
Answer:
Oxygen. When trees "breathe" they release oxygen and take in the carbon dioxide. On the other hand, when humans breathe we take in that oxygen and release carbon dioxide. In this way, we have a relationship that is mutually beneficial.
A rubbit gets down from a rump which its /\x=0.85m in 0.5s, The rubbit's mass is 2kg, what is the net Force?
Answer: 13.6 N
Explanation:
The equation of motion for the rabbit is:
[tex]\Delta x=V_{ox}t+\frac{1}{2}a_{x}t^{2}[/tex] (1)
Where:
[tex]\Delta x=0.85 m[/tex] is the distance traveled by the rabbit
[tex]V_{ox}=0 m/s[/tex] is the rabbit's initial velocity, assuming it started from rest
[tex]t=0.5 s[/tex] is the time
[tex]a_{x}[/tex] is the acceleration
Isolating [tex]a_{x}[/tex]:
[tex]a_{x}=\frac{2 \Delta x}{t^{2}}[/tex] (2)
[tex]a_{x}=\frac{2 (0.85 m)}{(0.5)^{2}}[/tex] (3)
[tex]a_{x}=6.8 m/s^{2}[/tex] (4)
On the other hand, the force [tex]F_{x}[/tex] is given by:
[tex]F_{x}=m.a_{x}[/tex] (5)
Where [tex]m=2 kg[/tex] is the mass of the rabbit
Substituting (4) in (5):
[tex]F_{x}=(2 kg)(6.8 m/s^{2})[/tex] (6)
Finally:
[tex]F_{x}=13.6 N[/tex]
A 2 kg book sits in the same room as a 5 kg vase. If the force of gravity between them is 7.41 x 10^-11 N, how far apart are they
The distance between the two objects is 3.0 m
Explanation:
The magnitude of the gravitational force between two objects is given by the following equation:
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where :
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
[tex]m_1,m_2[/tex] are the masses of the two objects
r is the separation between the objects
In this problem, we have:
[tex]m_1 = 2 kg[/tex] is the mass of the book
[tex]m_2 = 5 kg[/tex] is the mass of the vase
[tex]F=7.41\cdot 10^{-11}N[/tex] is the force between the two objects
Re-arranging the equation and solving for r, we find the distance between the two objects:
[tex]r=\sqr{\frac{Gm_1 m_2}{F}}=\sqrt{\frac{(6.67\cdot 10^{-11})(2)(5)}{7.41\cdot 10^{-11}}}=3.0 m[/tex]
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Answer:
3.00 m
Explanation:
What is the kinetic energy of an object that has a mass of 50 kg in a velocity of 18 m/s
Answer:
8100 J
Explanation:
KE = ½ mv²
KE = ½ (50 kg) (18 m/s)²
KE = 8100 J
SECTION B
THEORY QUESTIONS
(1a) Define the following
(a) Work:
Work is the amount of energy transferred
Explanation:
In physics, work is a measure of the energy transfer occurring in a process. Typically, we talk about work when energy is converted from one form into another.
For instance, work is done when a force is applied on an object. The work done on the object is given by:
[tex]W=Fd cos \theta[/tex]
where
where
F is the magnitude of the force
d is the displacement
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
We notice the following:
No work is done when the force is perpendicular to the displacement ([tex]cos 90^{\circ}=0[/tex])The work is maximum when the force is parallel to the displacementWhenever work is done, there is also an energy transfer taking place. For instance, in the previous example, when the force is applied to the object, the object will accelerate (assume there is no friction), and will gain kinetic energy: therefore, there is a transfer of energy to the object.
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jessica stretches her arms out to 0.6m from the center of her body while holding a 2 kg mass in each hand She then spins around on an ice rink at 1.1m/s.
If she pulls her arms in to .15 m, what is her linear speed if the angular momentum remains constant?
Answer:
4.4 m/s
Explanation:
Angular momentum is:
L = Iω
For a point mass, this can also be written as:
L = mvr
Angular momentum is conserved, so:
L₁ = L₂
m₁ v₁ r₁ = m₂ v₂ r₂
(2 kg) (1.1 m/s) (0.6 m) = (2 kg) v (0.15 m)
v = 4.4 m/s
2 1100 kg cars drive east; the first moving at 30 m/s the 2nd at 15 m/s what is the magnitude of the total momentum of the system
The magnitude of the total momentum of the system of two cars, each with a mass of 1100 kg and moving east at 30 m/s and 15 m/s respectively, is 49500 kg·m/s east.
Explanation:To calculate the total momentum of the system consisting of two cars driving east, you need to use the formula for momentum, which is the product of mass and velocity (p = mv). The momentum of each car is calculated separately and then added together since they are moving in the same direction (east).
For the first car with a mass of 1100 kg moving at 30 m/s, its momentum is:
p1 = m1 * v1 = 1100 kg * 30 m/s = 33000 kg·m/s.
For the second car with the same mass of 1100 kg but moving at 15 m/s, its momentum is:
p2 = m2 * v2 = 1100 kg * 15 m/s = 16500 kg·m/s.
The total momentum of the system is the sum of the momenta of both cars:
total p = p1 + p2 = 33000 kg·m/s + 16500 kg·m/s = 49500 kg·m/s.
Therefore, the magnitude of the total momentum of the system is 49500 kg·m/s to the east.
A girl runs 20.9 m/s East for 13.7s. How far does she go?
Answer: 286.33
Explanation:
multiplay them
what object did you choose to put on the skateboard
The object that I did choose to put on the skateboard is a sticky ball.
Is skateboarding a form of a good exercise?A sports scientists is said to have confirmed that skateboarding is seen to be a very goof and complete workout.
Note that It not only functions along the cardiovascular system and it also helps to create muscular strength. The core of a skateboarder is seen as very crucial role.
The object that I did choose to put on the skateboard is a sticky ball and it is one where i can measure the velocity as well as the speed taken.
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Suppose you throw a rock off a cliff on Earth with an initial horizontal velocity of 3 m/s. Assuming minimal drag and no wind, the horizontal velocity of the rock A. increases as it falls. B. decreases as it falls. C. is 0 m/s just before it lands. D. remains constant throughout the fall.
The horizontal velocity D. remains constant throughout the fall.
Explanation:
The motion of the rock off the cliff is a projectile motion, which consists of two independent motions:
A horizontal uniform motion. Since there are no forces acting along the horizontal direction (we consider the air drag to be negligible), the acceleration along this direction is zero, so the horizontal component of the velocity is constantAn accelerated motion with constant acceleration. There is one force acting along the vertical direction, the force of gravity, which is constant so the rock experiences a constant acceleration (downward) of magnitude [tex]g=9.8 m/s^2[/tex] (acceleration of gravity). This means that the vertical component of the velocity keeps changing.Here in this problem, we are only interested in the horizontal velocity. We said that the horizontal acceleration of the rock is zero: therefore, the horizontal velocity of the rock remains constant during the fall. (if the air drag was not negligible, then it would affect the horizontal velocity, which would decrease as the rock falls).
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A boy standing on the top of a cliff projects an object upwards with a velocity of 60m/s.
After 10s he releases anothe object from the cliff so that the 2 obects meet at a specific point. Find the distance from the top of the cliff to the point these objects meet with the correct explanation .
(Ans. 31.25m)
please i need help in this
Explanation:
For projectile motion, use constant acceleration equation:
Δx = v₀ t + ½ at²
where Δx is the displacement,
v₀ is the initial velocity,
a is the acceleration,
and t is time.
For the first object:
Δx = 60 t + ½ (-10) t²
Δx = 60 t − 5 t²
For the second object:
Δx = 0 (t−10) + ½ (-10) (t−10)²
Δx = -5 (t−10)²
When they meet, they have the same displacement, so:
60 t − 5 t² = -5 (t−10)²
60 t − 5 t² = -5 (t² − 20t + 100)
60 t − 5 t² = -5 t² + 100 t − 500
60 t = 100 t − 500
40 t = 500
t = 12.5
Plug into either of the original equations to find the displacement.
Δx = -5 (t−10)²
Δx = -5 (12.5−10)²
Δx = -31.25
The distance from the top of the cliff to the point where the objects meet is 31.25 meters.
HELP ASAP! A certain wave has a frequency of 200 Hz and a wavelength of 2 meters. Calculate the wave speed. SHOW WORK! Question 13 options:
Answer:
400 m/s
Explanation:
From the question;
The frequency of the wave is 200 Hz Wavelength of the wave is 2 metersWe are required to calculate the speed of the wave;
We need to know that the speed of the wave is calculated by multiplying frequency by the wavelength of the wave.That is, speed = wavelength × frequency In this case;Speed of the wave = 200 Hz × 2 m
= 400 m/s
Thus, the speed of the wave is 400 m/sif an offspring inherits chromosome 1a,the protein for what color flower can be produce?
Answer:
Your mother can tell you that answer
Explanation:
Skateboard falls with force of weight pulling downwards with 53 Newton’s accelerating at a rate of 9.81m/s what’s the mass of the skateboard
Point of correction, acceleration is 9.81 m/s2
Answer:
5.4 Kg
Explanation:
We know that F=ma and making m the subject of the formula then
[tex]m=\frac {F}{a}[/tex] where m is the mass of the skateboard, F is the pulling force and a is the acceleration of the body
Substituting 53 N for F and 9.81 m/s2 for a then
[tex]m=\frac {53 N}{9.81 m/s2}=5.40265 Kg\approx 5.4 Kg[/tex]
A snowball accelerates at
23.4 m/s? when a 2.87 N
force is exerted on it. What is
the mass of the snowball?
(Unit = kg)
Answer:
0. 1226495726kg
Explanation:
Force is the product of mass and acceleration.
Mathematically,
Force(F) = mass (m)×acceleration(a)
Substituting the values into the equation
2. 87=m×23. 4
2. 87=m (23. 4)
2. 87/23. 4=m (23. 4)/23. 4
2. 87/23. 4=m
0. 1226495726=m
Answer:
Answer:
0. 1226495726kg
Explanation:
Force is the product of mass and acceleration.
Mathematically,
Force(F) = mass (m)×acceleration(a)
Substituting the values into the equation
2. 87=m×23. 4
2. 87=m (23. 4)
2. 87/23. 4=m (23. 4)/23. 4
2. 87/23. 4=m
0. 1226495726=m
Explanation: