The perimeter of a playing field for a certain sport is 320 ft. The field is a? rectangle, and the length is 48 ft longer than the width. Find the dimensions.

Answer:  [tex]266,407.057\ km[/tex]

Step-by-step explanation:

The formula used to calculate the circumference of a circle is:

[tex]C=2\pi r[/tex]

The radius of the circle is r.

In the diagram you can observe that the radius of the satellite's orbit (r2) is the sum of the radius of the Earth (r1) and the distance from the Earth's surface to the satellite's orbit:

[tex]r2=r1+36,000\ km\\r2=6,400\ km+36,000\ km\\r2=42,400\ km[/tex]

Then, the circumference of the satellite's orbit is:

[tex]C=2\pi (42,400\ km)\\C=266,407.057\ km[/tex]

The circumference of the satellite's orbit is calculated by adding Earth's radius to the satellite's distance from Earth's surface to determine the orbit radius. The circumference is then found by using the formula for the circumference of a circle, 2πr, giving approximately 266,433 kilometers.

To find the circumference of the satellite's orbit, we need to first calculate the total distance from the center of Earth to the satellite. This is the sum of the Earth's radius (6400 kilometers) and the satellite's distance from the Earth's surface (36000 kilometers), which totals 42400 kilometers.

Once we have the radius of the orbit, we can calculate the circumference using the formula for the circumference of a circle, which is 2πr (two times Pi times the radius). Using this formula, the circumference of the satellite's orbit is approximately 266,433 kilometers.

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Answer:

108π cm^3/min

Step-by-step explanation:

At a time of t min, let the height be h cm

The volume of a cylinder;

V = π r^2 h

   = 36π h

differentiating both sides with respect to t;

dV/dt = 36π dh/dt

but dh/dt = 3 cm/min

dV/dt = 36π(3) = 108π cm^3/min

Answer:

The rate of change of the volume of the cylinder when the height is 20 cm is [tex]\frac{dV}{dt}=108\pi \:{\frac{cm^3}{min} }[/tex]

Step-by-step explanation:

This is a related rates problem. In this problem, you need to find a relationship between the quantity whose rate of change you want to find, the volume in this case, and the quantity whose rates of change you know, the height of the cylinder.

We know that the volume of the cylinder is

[tex]V=\pi r^2h[/tex]

We also know that the radius is a constant, 6 cm and thus

[tex]V=\pi (6)^2h=36\pi h[/tex]

V and h both vary with time so you can differentiate both sides with respect to time, t, to get

[tex]\frac{dV}{dt}=36\pi \frac{dh}{dt}[/tex]

Now use the fact that [tex]\frac{dh}{dt}=3 \:{\frac{cm}{min}[/tex] to find [tex]\frac{dV}{dt}[/tex].

[tex]\frac{dV}{dt}=36\pi (3)=108\pi[/tex]

Answer:12 yards

Step-by-step explanation: 22-10=12

Hello!

The answer is:

B. [tex]9x^{2}-16y^{2}[/tex]

To find the equivalent expression we need to apply the distributive property, so:

[tex](3x-4y)(3x+4y)=9x^{2}+12xy-12yx-16y^{2}\\\\9x^{2}+12xy-12yx-16y^{2}=9x^{2}+12xy-12xy-16y^{2}=9x^{2}-16y^{2}[/tex]

So, the correct option will be B. [tex]9x^{2}-16y^{2}[/tex]

Have a nice day!

Answer:

2/3

Step-by-step explanation:

5 black

3 green (not black)

3 blue (not black)

4 yellow (not black)

there are 5 black and 10 not black out of a total of 15 marbles.

there are 10/15 that are not black.  Reduced 2/3.

The probability of not drawing a black marble is 2/3, calculated by subtracting the number of black marbles from the total number of marbles in the bag and dividing the result by the total number of marbles.

The question asks to find the probability of not drawing a black marble. To solve this, we first determine the total number of marbles and then subtract the number of black marbles to find the number of marbles that are not black. In this case:

Next, we calculate the probability using the formula:

Probability (not black) = Number of marbles that are not black / Total number of marbles

Plugging in the numbers:

Probability (not black) = 10 / 15 = 2/3

Therefore, the probability of not drawing a black marble is 2/3.

Final answer:

The range of Set A is 5 and Set B is 16. The mean of Set A is 15.2 and Set B is 12. Set B has a larger range but a smaller mean compared to Set A.

Explanation:

The range of a data set is calculated by subtracting the smallest value from the largest value. For Set A, the range is 18 - 13 = 5. For Set B, the range is 20 - 4 = 16.

The mean of a data set is calculated by summing all the values and dividing by the number of values. For Set A, the mean is (13 + 15 + 16 + 18 + 14) / 5 = 76 / 5 = 15.2. For Set B, the mean is (4 + 10 + 8 + 18 + 20) / 5 = 60 / 5 = 12.

Comparing the two data sets, we can see that Set B has a larger range than Set A, indicating greater variability in the data. However, Set B has a smaller mean than Set A, indicating that the values in Set B are generally lower than those in Set A.

Answer:

y = 1 for the line.

Step-by-step explanation:

All values under y = 1. Surprisingly 1^0 is still 1. So just fill the table in with 1s under y.

I've drawn the line in desmos for you. I'm not sure whether you can extend the question enough to graph a line segment containing these 5 points (which is what I have done) or if you should just submit a graph with 4 points on. If it does not cost you anything to submit it twice, I would try the line first and the points alone the second time.

Answer:

[tex]\large\boxed{1.\ f(1)=135}\\\boxed{2.\ f(6)=115}\\\boxed{3.\ f(26)=25}\\\boxed{4.\ f(n)=139-4n}[/tex]

Step-by-step explanation:

[tex]f(1)=135\\f(2)=135-4=131\\f(3)=131-4=127\\f(4)=127-4=123\\f(5)=123-4=119\\\vdots\\\\\text{It's an arithmetic sequence with firs term = 135 and the common}\\\text{difference d = -4.}\\\text{The formula of arithmetic sequence: }\\\\f(n)=f(1)+(n-1)d\\\\\text{We have}\ f(1)=135\ \text{and}\ =-4.\ \text{Substitute:}\\\\f(n)=135+(n-1)(-4)=135+(n)(-4)+(-1)(-4)\\=135-4n+4=139-4n\\\\\boxed{f(n)=139-4n}[/tex]

[tex]\text{Put n = 6, n=26 to the formula:}\\\\f(6)=139-4(6)=139-24=115\\\\f(26)=139-4(26)=139-104=25[/tex]

First, lets start with the formula for the volume of a cone

[tex] \frac{1}{3} (\pi \times {r}^{2})h [/tex]

Then lets find the diameter so we can get the radius...

Since we have circumference, all we need to do is use this formula-

[tex] c \div \pi[/tex]

C being circumference, the PI being the 3.14, we plug it in to the formula as the number we have to get the diameter...

[tex]{75.36} \div 3.14[/tex]

And it comes out to...

24.

Now we need to divide it by two to get the radius, and we come up with 12.

Now that we have our radius, we can finally plug in all of the numbers into our original formula...

[tex] \frac{1}{3} (3.14 \times \: {12}^{2} ) \times 18[/tex]

The answer of the entire problem turns out to be... Drum roll please...

2712.96 cubic centimeters.

Answer:

the answer is 5

Step-by-step explanation:

25/5=5 & 5*5=25

Answer:

The Answer Is 5 because every square number has to equal the number by multiplying by 2 to get your Answer 5 x 5 = 25 which 5 is multiplied 2 times 5 and 5 which gives you your answer 25.

Step-by-step explanation:

Plz Mark Brainliest

Answer:

Similarity means that two figures are the same shape, but not necessarily the same size, color or orientation, congruent means two figures are the same in every form.

Step-by-step explanation:

In my understanding, The Property of Rigid motion holds two points:

- The relative distance between two points stays the same,

- The relative position of the points stays the same

This includes, translations, reflections, and rotation but not to dilutions since it breaks these rules. The relative distance between points gets smaller after dilution.

Answer:

Step-by-step explanation:

[tex]3\sqrt2\cos\theta+2=-1\\\\\text{Method 1}\\\\\text{Put}\ \theta=\dfrac{\pi}{4}\ \text{to the equation and check the equality:}\\\\\cos\dfrac{\pi}{4}=\dfrac{\sqrt2}{2}\\\\L_s=3\sqrt2\cos\dfrac{\pi}{4}+2=3\sqrt2\left(\dfrac{\sqrt2}{2}\right)+2=\dfrac{(3\sqrt2)(\sqrt2)}{2}+2\\\\=\dfrac{(3)(2)}{2}+2=3+2=5\\\\R_s=-1\\\\L_s\neq R_s\\\\\boxed{FALSE}[/tex]

[tex]\text{Method 2}\\\\\text{Solve the equation:}\\\\3\sqrt2\cos\theta+2=-1\qquad\text{subtract 2 from both sides}\\\\3\sqrt2\cos\theta=-3\qquad\text{divide both sides by}\ 3\sqrt2\\\\\cos\theta=-\dfrac{3}{3\sqrt2}\\\\\cos\theta=-\dfrac{1}{\sqrt2}\cdot\dfrac{\sqrt2}{\sqrt2}\\\\\cos\theta=-\dfrac{\sqrt2}{2}\to\theta=\dfrac{3\pi}{4}+2k\pi\ \vee\ \theta=-\dfrac{3\pi}{4}+2k\pi\ \text{for}\ k\in\mathbb{Z}\\\\\text{It's not equal to}\ \dfrac{\pi}{4}\ \text{for any value of }\ k.[/tex]

since the numerator is x² + 5x - 3, and therefore has a degree of 2, whilst the denominator, 4x¹ - 1, has a degree of 1, therefore, there's no horizontal asymptote.

recall, we only get a horizontal asymptote if the denominator's expression degree is equals or greater than that of the numerator's.

The function [tex]f(x) = (x^2+5x-3)/(4x-1)[/tex] does not have a horizontal asymptote because the degree of the numerator is higher than the degree of the denominator.

To identify the horizontal asymptote of the function

[tex]f(x) = \frac{{x^2+5x-3}}{{4x-1}}[/tex], you can examine the degrees of the polynomial in the numerator and the polynomial in the denominator. Since the degree of the numerator (which is 2) is higher than the degree of the denominator (which is 1), this function does not have a horizontal asymptote. However, for functions like

[tex]f(x) = \frac{{x^2+3}}{{x^2+4}}[/tex], where the degrees of the numerator and denominator are the same, the horizontal asymptote is determined by the leading coefficients of the numerator and denominator. Specifically, the horizontal asymptote is

[tex]y = \frac{{1}}{{1}}[/tex] = 1,

since the coefficients of the x^2 terms are both 1.

2/3 is the answer because 6 in is the model and 4 ft is the actual

Answer:

The  ratio of the height of the actual table to the height of the model table is [tex]\frac{8}{1}[/tex] .

Step-by-step explanation:

As given

A table is 4 ft high. A model of the table is 6 in. high.

As

1 foot = 12 inch

Now convert 4 ft into inches .

4 ft = 4 × 12

     = 48 inches

Height of the actual table = 48 inches

Now the ratio of the height of the actual table to the height of the model

table .

[tex]Ratio\ of\ the\ height\ of\ the\ actual\ table\ to\ the\ height\ of\ the\ model\ table =\frac{48}{6}[/tex]

[tex]Ratio\ of\ the\ height\ of\ the\ actual\ table\ to\ the\ height\ of\ the\ model\ table =\frac{8}{1}[/tex]

Therefore the  ratio of the height of the actual table to the height of the model table is [tex]\frac{8}{1}[/tex] .

the answer is A, what they changed is the (x) with (a+h), so the right side equation should be changed the same way just like A.

Answer:

d. $43.00

Step-by-step explanation:

Karli's total cost is ...

total cost = material cost + labor cost

= ($8.00/10 gal)·(5 gal) + ($13.00/h)·(3 h)

= $4.00 + $39.00

= $43.00

Answer:

$14.21

Step-by-step explanation:

Hello, I think I can help yo with this

if the lamp is on sale for 25% it means you have to pay the 75% of the original cost, you can find that 75% or to find the 25 % and the subtract that value from the original cost, it is the same anyway

Step 1

if

$18.95 ⇔100%

x$?       ⇔75%

[tex]\frac{18.95}{100}=\frac{x}{75}[/tex]

Step 2

solve for x

[tex]\frac{75*18.95}{100}=x\\x=\frac{1421.51}{100}\\ x=14.21\\\\[/tex]

the new price is $14.21

have a great day.

Answer:

m = 15.

Step-by-step explanation:

∛(3375) =  15.

You can use a calculator to do this. Some calculators have a direct key giving you a cube root or  you can use the power key + 1/3 .

Note:   ∛(3375) = 3375^(1/3).

Answer:

-5

Step-by-step explanation:

Edge 2020

It would be 30.8 hope this helps

Answer:

10 servings

Step-by-step explanation:

Divide the total juice available, 2 quarts, by the serving size, (1/5) quart per serving:

 2 quarts                     2        5

--------------------------- = ----  ·  ------ servings = 10 servings

(1/5) quart/serving       1         1

angle GAL would be the same as MLA

➷ Pythagoras' theorem is only suitable for right triangles, which this isn't.

The Sine rule would not be applicable as there isn't any side and paired angle given

The best option for this would be the Law of Cosines as it is suitable for when you are given two sides and an angle between the.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Answer:  Third option is correct.

Step-by-step explanation:

Since we have given that

ABC is triangle with its dimensions:

AB = 11

AC = 13

∠A = 108°

BC = a

We need to find the length of 'a'.

So, we can use "Law of cosines" as we have given two sides and one angle.

So, it becomes,

[tex]\cos A=\dfrac{b^2+c^2-a^2}{2bc}\\\\\cos 108^\circ=\dfrac{11^2+13^2-a^2}{2\times 13\times 11}\\\\-0.3=\dfrac{121+169-a^2}{286}\\\\-0.3\times 286=290-a^2\\\\-85.8=290-a^2\\\\-85.8-290=-a^2\\\\375.8=a^2\\\\a=\sqrt{375.8}\\\\a=19.38[/tex]

Hence, Third option is correct.

Answer:

Step-by-step explanation:

10x10 squared

=10x100

=1000

Answer 10000

Step-by-step explanation:

10x10=100

100x100=10000

Assume the car starts at the origin, so that its initial position is [tex]x(0)=0[/tex]. The car's displacement at any time [tex]t[/tex] over the 20 second interval is

[tex]\displaystyle x(0)+\int_0^t(44+2.2u)\,\mathrm du=0+\left(44u+1.1u^2\right)\bigg|_{u=0}^{u=t}=44t+1.1t^2[/tex]

so that after 20 seconds the car has moved 1320 ft.

###

Without using calculus, recall that under constant acceleration, the average velocity of the car over the 20 second interval satisfies

[tex]v_{\rm avg}=\dfrac{v_f+v_i}2[/tex]

and that, by definition, we have

[tex]v_{\rm avg}=\dfrac{\Delta x}{\Delta t}[/tex]

where [tex]v_f[/tex] and [tex]v_i[/tex] are the final/initial speeds of the car and [tex]\Delta x[/tex] is the displacement it undergoes. It starts with a speed of 44 ft/s and ends with a speed of 88 ft/s, so we have

[tex]\dfrac{88\frac{\rm ft}{\rm s}+44\frac{\rm ft}{\rm s}}2=\dfrac{\Delta x}{20\,\rm s}\implies\Delta x=1320\,\mathrm{ft}[/tex]

same as before.

To find the distance traveled by the car during the 20 seconds, we integrate the velocity function and solve for the distance using the given values. The car travels a distance of 1320 feet.

To find the distance traveled by the car during the 20 seconds, we need to calculate the area under the velocity-time graph. The velocity function given is v(t)=44+2.2t. To find the distance, we integrate the velocity function from 0 to 20 seconds:

d = ∫(44+2.2t) dt

Applying integration, we get: d = 44t + 1.1t^2

Substituting the values t=0 and t=20 into the equation, we can find the distance traveled by the car:

d = 44(20) + 1.1(20)^2

Solving this equation, we get d = 880 + 440

So, the car has traveled a distance of 1320 feet during the 20 seconds.

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Answer:

[tex]y = 2 - \frac{1}{32}x\text{ or } y=2-0.03125x[/tex]

Step-by-step explanation:

Here x represents the number of student and y represents the amount of juice remain after x students are served,

Given,

The total number of cup = 32,

And, the amount of juice in 32 cups = 2 gallon,

⇒ The amount in 1 cup = [tex]\frac{2}{32}[/tex] = [tex]\frac{1}{16}[/tex] gallons,

Number of cups served to a student = [tex]\frac{1}{2}[/tex] cup.

⇒ The amount of juice served to a student = [tex]\frac{1}{32}[/tex] gallon.

⇒ The amount of juice served to x students = [tex]\frac{x}{32}[/tex] gallon

Thus, the remaining amount of juice = The amount of juice in 32 cups - served amount

⇒ [tex]y = 2 - \frac{1}{32}x\text{ or } y=2-0.03125x[/tex]

Which is the required equation.

To answer the student's question, we list each possible pair of marble colors drawn without replacement from a bag with a white, red, and blue marble: White-Red, White-Blue, Red-White, Red-Blue, Blue-White, and Blue-Red.

The question asks for the display of all possible outcomes when two marbles are drawn from a bag containing a white, a red, and a blue marble, without replacement. To show all possible outcomes, we can list them in an organized manner, considering each color once it is drawn, is not put back into the bag. The first marble drawn can be any one of the three colors. Once a marble is drawn, there are only two colors left for the second draw.

Answer:

  968π ≈ 3041 . . . cubic units

Step-by-step explanation:

The usual formula for the volume of a cylinder is ...

  V = πr²h

For your given dimensions, the volume is found by putting the values into the formula and doing the arithmetic.

  V = π(11²)(8) = 968π . . . . cubic units

 V ≈ 3041 cubic units

Answer:

[tex]\large\boxed{N-T=-a^2+a-11}[/tex]

Step-by-step explanation:

[tex]T=-2a^2+a+6\\N=-3a^2+2a-5\\\\N-T=?\\\\\text{Substitute:}\\\\N-T=(-3a^2+2a-5)-(-2a^2+a+6)\\\\N-T=-3a^2+2a-5-(-2a^2)-a-6\\\\N-T=-3a^2+2a-5+2a^2-a-6\qquad\text{combine like terms}\\\\N-T=(-3a^2+2a^2)+(2a-a)+(-5-6)\\\\N-T=-a^2+a-11[/tex]

The difference between the functions is [tex]-a^2+a-11[/tex]

Given the following expression:

[tex]T=-2a^2+a+6\\N=-3a^2+2a-5[/tex]

We are to take the difference between N and T and this is as shown:

[tex]N - T= -3a^2+2a-5-(-2a^2+a+6)\\Expand\\N - T= -3a^2+2a-5+2a^2-a-6\\\\Collect \ the \ like \ terms\\N-T=-3a^2+2a^2+2a-a-5-6\\N-T=-a^2+a-11[/tex]

Hence the difference between the functions is [tex]-a^2+a-11[/tex]

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False. That does not satify the equation

Answer:

False

Step-by-step explanation:

The given inequality  is [tex]-3 \:<\:x\:<\:14[/tex].

Since both boundaries of the inequalities are not inclusive , we use the parenthesis for open interval."()".

We write the given inequality in interval notation as;

[tex](-3,14)[/tex].

The correct choice is false