The photo printed has length of 6 imams width of 4. A smaller picture is printed the ratio of the new picture to the size of the first picture is 1.5 to 2. What's the length and width of the new picture?

Answers

Answer 1
we know the width of the first picture, is 4
we know the ratio from smaller to larger is 1.5:2

thus     [tex]\bf \cfrac{\textit{width of small}}{\textit{width of large}}\qquad 1.5:2\implies \cfrac{1.5}{2}=\cfrac{w}{4}[/tex]

solve for "w".

we know the length of the first picture, 6

[tex]\bf \cfrac{\textit{length of small}}{\textit{length of large}}\qquad 1.5:2\implies \cfrac{1.5}{2}=\cfrac{L}{6} [/tex]

solve for "L".
Answer 2

The new picture will have a length of 4.5 inches and a width of 3 inches.

There is asking about the size of a scaled-down photo in comparison to the original photo that has a length of 6 inches and a width of 4 inches. Given the ratio of the new picture to the size of the first picture is 1.5 to 2, we need to calculate the new dimensions.

The scale factor from the original to the new photo is 1.5 / 2, which simplifies to 0.75. Thus, we multiply the original dimensions by 0.75 to find the dimensions of the new picture:

Length of new picture = 6 inches * 0.75 = 4.5 inches

Width of new picture = 4 inches * 0.75 = 3 inches


Related Questions

Find the height of the figure below if the volume is 480.66^3 cm.

Answers

volume = PI x r^2 x H

you know the volume and the radius ( 12/2 = 6)

480.66 =3.14 x 6^2 x H

480.66 = 113.04 x h

h = 480.66/113.04 = 4.252

round off as needed.


There were n balloons at the beginning of the party. By the end of the party, 5 of them had popped. Using n, write an expression for the number of balloons that were left

Answers

Answer:

The expression for the number of balloons that were left is [tex]n-5[/tex].

Step-by-step explanation:

There were n balloons at the beginning of the party.

By the end of the party, 5 of them had popped.

Let the remaining balloons be represented by x

So, x = total balloons minus 5

This gives: [tex]x=n-5[/tex]

Therefore, the expression for the number of balloons that were left is [tex]n-5[/tex].

How do I find ac in this problem

Answers

7 / x+4 = 5/x+1 =


5x+20 = 7x+7 =

20=2x+7

13=2x

x=13/2 = 6.5

6.5+4 = 10.5

6.5+1 =7.5

10.5+7.5 = 18

length of AC = 18

An expression is shown below:

square root of 32 plus square root of 2

Which statement is true about the expression?

please help 25 points

A. It is rational and equal to 4

B. It is rational and equal to 5

C. It is rational and equal to 5√2

D. It is rational and equal to 4√2

Answers

C) sqrt(32) = sqrt(2^5)=4sqrt(2), then + sqrt(2) = 5 * sqrt(2)

√(2^5)+√2

4√2+√2

(4+1)√2

5√2

There is a problem however...5√2 is IRRATIONAL because √2 is irrational, ie, it cannot be expressed as a ration of two integers...

So the problems simplified is certainly 5√2, but it is irrational.

Maybe there is a typo and should read:

C. It is IRrational and equal to 5√2


The base of a triangle measures (3x − 6) units and the height measures (2x + 4) units. Part A: What is the expression that represents the area of the triangle? Show your work to receive full credit. (4 points) Hint: Area = 0.5bh Part B: What are the degree and classification of the expression obtained in Part A? (3 points) Part C: How does Part A demonstrate the closure property for polynomials? (3 points)

Answers

To answer this item, we use the equation given for the calculation of the area of the triangle.

                                A = 0.5bh

Substituting the known expressions,

                      A = (0.5)(3x – 6)(2x + 4)

 

Part A: Use distribution method to simplify the expression for the calculation of area.

 

                         A = 0.5(6x^2 + 12x – 12x – 24)

                           A = 0.5(6x^2 – 24)

                          A = 3x^2 – 12

 Part B: The equation for area of has a degree of two because the highest exponent is 2.

Part C: The closure property of polynomials is always closed for multiplication.

Answer With Step-by-step explanation:

Part A:

.5[ (3x – 6) (2x + 4) ]

.5(6x^2 - 24)

3x^2 - 12

Part B:

Second Degree Binomial

Part C:

For Part A, a polynomial was multiplied by another polynomial. The resulting product was a polynomial. This is a demonstration of the closure property for multiplying polynomials.

which is enough information to prove that s||t

Answers

The answer is: <2 = <8
It will be the second option

Find cos θ if sin θ = negative twelve divided by thirteen and tan θ > 0. negative five divided by twelve negative five divided by thirteen twelve divided by five negative thirteen divided by twelve

Answers

1.
Sin∅=opposite side / hypotenuse, in a right triangle, as shown in the figure.

In this triangle, the length of the hypotenuse is 13, the length of one side 12, and the other side can be found by the Pythagorean theorem to be:

[tex] \sqrt{13^{2} - 12^{2} }= \sqrt{169-144}= \sqrt{25}=5 [/tex]

2.
The value of the cosine is (adjacent side)/(hypotenuse)=5/13.

3.
The tangent is positive in the first and third quadrants.

Since Tan=Sine/Cosine, and Sine is negative, then cosine must be negative as well


Answer: -5/13


A hair-styling salon charges $11.00 for a haircut, and an average of 75 people stop in for haircuts each day. The owner is thinking of increasing the price, and he estimates that every time he raises the price of a haircut by $1.00, the number of people coming in for haircuts will decrease by 3 per day. Which of these functions represents the estimated revenue per day from haircuts as a function of the number of dollars the price of a haircut is raised?

Answers

Final answer:

The estimated daily revenue function, given the described price increase and corresponding customer decrease, can be represented as R(x) = (11 + x)(75 - 3x), where x is the number of dollars by which the price is raised.

Explanation:

The question asks us to find a function that represents the estimated revenue per day from haircuts as a function of the number of dollars the price of a haircut is raised. Initially, the salon charges $11.00 for a haircut with an average of 75 people per day. When the price increases by $1, the number of customers decreases by 3.

Let x represent the number of dollars by which the haircut price is raised. The new price will be $11.00 + x. The number of customers is initially 75, and for each $1 increase, we lose 3 customers, so the new number of customers will be 75 - 3x. The daily revenue, R(x), can be found by multiplying the new price by the new number of customers:

R(x) = (11 + x)(75 - 3x)

This function will give us the estimated daily revenue after increasing the haircut price by x dollars.

Solve 4r2 – 7 = 29.
a. +-6
b. +-3
c. +-4
d. +-5

Answers

4r^2-7=29
+7 both sides
4r^2=36
÷4 both sides
r^2=9
square root both sides
r=+/-3 B

If k pencils cost c cents what is the cost in cents of p pencils

Answers

the cost in cents of 1 pencil = c/k

the cost in cents of p pencils = (c/k) * p

If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

If k pencils cost c cents. Then the cost of each pencil is given as,

⇒ c / k

Then the cost in cents of p pencils is given as,

⇒ (c / k) x p

⇒ (cp) / k

If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ5

Work out problem in picture

Answers

for x multiply 6 by sin(45) = 3sqrt(2) = 4.2426

for y  since it is a right triangle with 45 degree angle both legs are equal

 so y = x

A local carpet company has been hired to carpet a planetarium which is in the shape of a circle. If the radius of the planetarium is six yards, and the cost of the carpet is $14 per square yard, find the total cost to carpet the planetarium. (use 3.14 for π )

Answers

This is the concept of application of geometry and financial mathematics; To calculate for the total cost of the carpet we proceed as follows;
Total cost=[area of the carpet]*[price per square yard]
area of carpet is given by:
Area=πr^2
where;
radius,r=6 yeards
=π*6^2
=113.1 square yards
therefore the price of the carpet will be:
113.1*14
=$1,583.4

1. Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,1) E (7,1) and F(1,5). Show your work.




2. What is the length of the 2nd base of a trapezoid if the length of one base is 24 and the length of the midsegment is 19? Show your work.




Answers

1. Draw an accurate drawing of the triangle in the coordinate axis, as shown in the picture.

FD and DE are perpendicular, because D and F have the same x coordinate, and D and E the same y coordinate.

Let A(4, 1) be the midpoint of DE and B(1, 3) be the midpoint of FD.

Draw the perpendiculars from A and B. They meet at O(4, 3), since AO is parallel to DF and BO is parallel to DE.

the point where the perpendicular bisectors of the sides meet is the circumcenter, so the circumcenter is O(4, 3)


2. 

Let the length of the second base be x. 

the length of the midsegment is the sum of the ases divided by 2.

[tex]19= \frac{x+24}{2} [/tex]

19*2=x+24

38=x+24

x=38-24=14


Answers:

1) O(4, 3)
2) length of second base = 14 units

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they doubled the sales of the second week for the third week to sell a total of 431 boxes of cookies, how many did they sell each week?

Answers

week1 = x

week2 = x+5

week3 = 2(x+5)

x + (x+5) + 2(x+5) = 431

x + x + 5 + 2x + 10 = 431

4x + 15 = 431

4x = 431 - 15

4x = 416

x = 104


week1 = x = 104  boxes

week2 = x+5 = 104+5 = 109  boxes

week3 = 2(x+5) = 2(104+5) = 2*109 = 218  boxes


The scale on a map indicates that 1 in = 2.5mi. How far apart are two cities that measure 2.5 ft apart on the map? A. 60 miles B. 6.25 miles C. 75 miles D. 90 miles

Answers

The answer is C. 75 miles

What is the probability of flipping a penny and a nickel and obtaining one head and one tail?

Answers

Final answer:

The probability of flipping a penny and a nickel and obtaining one head and one tail is 0.25, or 25%.

Explanation:

The probability of flipping a penny and a nickel and obtaining one head and one tail can be calculated by multiplying the probabilities of getting a head on one coin and a tail on the other coin. Since the chance of getting a head on a fair coin is 0.5 and the chance of getting a tail is also 0.5, the probability of getting one head and one tail is:

Probability = (Probability of getting a head on the penny) × (Probability of getting a tail on the nickel)

Probability = 0.5 × 0.5 = 0.25, or 25%.

I need help with geometry.

Answers

1.

In any trapezoid, the length of the midsegment is [tex] \frac{|base_1|+|base_2|}{2} [/tex]

substituting the known values:

[tex] \frac{24+|base_2|}{2}=19 [/tex]

[tex]24+|base_2|=38[/tex]

[tex]|base_2|=38-24=14[/tex]

2.

Notice that since D and have the same y-coordinate, then DE is horizontal, and since F and D have the same x-coordinate, FD is vertical.

Thus FD and DE are perpendicular, so the triangle FED is a right triangle.

The median drawn from the right angle, is equal to half the hypotenuse.

That is, |DO|=1/2 |FE|, thus |OE|=|OF|=|OD|, are all radii of the circle centered at O.

O is the midpoint of EF, and is found by the Midpoint formula:

[tex]O=( \frac{1+7}{2} , \frac{5+1}{2} )=(4, 3)[/tex]


Answer:

1. 14

2. (4, 3)

A scientist begins an experiment with a petri dish containing a culture of bacteria cells and records the cell growth every hour. At 1 hour, the bacteria had grown to 880 cells, and at 2 hours, had grown to 3,520 cells. Which function can be used to represent the relationship between the number of bacteria cells, y, and the time in hours, x?

y = 4 x
y = 220(4) x
y = 880(4) x
y = 880(0.25) x

Answers

880 = 220(4)^1
3520 = 220(4)2


B is correct choice.

Answer:

B

Step-by-step explanation:

Which of the following points is in the solution set of y>-x^2+5?

A. (0,5)

B. (1,3)

C. (2,4)

Answers

The only point which is a solution is C

If 300 cm^2 of material is available to make a box with a square base and an open top, find the maximum volume of the box in cubic centimeters. Answer to the nearest cubic centimeter without commas. For example, if the answer is 2,000 write 2000.

Answers

Hello,
Assume a the side of the base, b the height.

[tex]V=a^2*b\\ a^2+4ab=300==\ \textgreater \ b= \dfrac{300-a^2}{4a} \\ V=a^2*\dfrac{300-a^2}{4a}= \frac{1}{4} *(300a-a^3)\\ \dfrac{dV}{da} = \frac{1}{4} *(300-3*a^2)=0\\ ==\ \textgreater \ a=10 \ and\ b=5\\ V=10^2*5=500\\ [/tex]

The formula used to calculate simple interest is modeled by I=prt, where I=simple interest, p=principle, r=interest rate, and t=time, measured in years. Which of the following options represent(s) an alternative equivalent version of the simple interest formula? select all that apply....TY
I = trp
I = p + rt
I - rt = p
t= l/rp
p= l/rt

Answers

An alternative equivalent versions are:

I = trp
t= l/rp
p= l/rt

Step-by-step explanation:

The formula for simple interest is as follows.

                I = prt

where,  I = simple interest

            p = principle

            r = rate

            t = time

This formula can be alternatively written by shifting I, r, t, and p either on the right or left side of equals sign.

Therefore, the formula can be rewritten as follows.

I = trp[tex]t = \frac{I}{rp}[/tex] [tex]p = \frac{I}{rt}[/tex]

Select the inequality that corresponds to the given graph. graph of an inequality with a solid line through the points negative 8 comma 0 and 0 comma negative 4 and shading above the line A 4x − 3y > − 12 B x + 4y > 4 C 4x − 2y < − 8 D 2x + 4y ≥ − 16

Answers

well by looking at the graph I can see that the equation for the line is y=-0.5x-4
rearranging I can get the answer.
y>=-0.5x-4
y+0.5x>=-4
2y+x>=-8



the answer is
2x+4y>=-16
Answer: 2x+4y ≥ -16

Step-by-step explanation:  In the given graph x-intercept is -8 and y-intercept is -4.

Also the graph is shaded up of the line for greater values of y's.

On the option 2x+4y ≥ -16 has x-intercept at -8 and y-intercept at -4.

Also all other inequalities has only less than or greater than sign.

In the given graph we have a solid line.

So, there should be greater than or equal to inequality sign for the inequality.

Only option 4 has greater than with equal to sign.

Therefore, correct option is 2x+4y ≥ -16



Calvin and hobbes are making snowballs to throw at suzi calvin made 3/7 of the snowballs and hobbes made 8/14 of the snowballs who mae more snowballs in fractions

Answers

recalculate 3/7 to have the same denominator as 8/14 ( 14)

 so multiply both top and bottom by 2. 3/7 becomes 6/14

8/14 - 6/14 = 2/14 reduces to 1/7

 Hobbes made more snowballs by 1/7

recalculate 3/7 to have the same denominator as 8/14 ( 14)

so multiply both top and bottom by 2. 3/7 becomes 6/14

8/14 - 6/14 = 2/14 reduces to 1/7

Hobbes made more snowballs by 1/7

88 is the product of
8
and Jenny's score

Answers

product means multiplication

88 is the product of 8 multiplied by a number

 so 88/8 =11

 jenny's score is 11


What are the solutions of the equation 2x2=2 use a graph of the related function

Answers

The equation given is 
2x² = 2
x² = 1
x = √1
x = 1

The solution is both -1 and 1 and the graph is shown below

Answer:

[tex]x=-1\text{ or }x=1[/tex]

Step-by-step explanation:

We have been given an equation [tex]2x^2=2[/tex]. We are asked to find the solutions of our given equation.

First of all, let us divide both sides of our equation by 2.

[tex]\frac{2x^2}{2}=\frac{2}{2}[/tex]

[tex]x^2=1[/tex]

Upon taking square root of both sides of our equation we will get,

[tex]x=\sqrt{1}[/tex]

[tex]x=\pm 1[/tex]  

[tex]x=-1\text{ or }x=1[/tex]

Therefore, [tex]x=-1\text{ or }x=1[/tex] are two solutions for our given function.

The sum of three consecutive even integers is 288. find the three integers.

Answers

288/3 =96

96-2 = 94

96+2 = 98

94 +96 +98 = 288


Answer:

94, 96, 98

Step-by-step explanation:

Let the smallest integer is x,

So, second larger integer = x + 2 (Because integer are even and consecutive),

And, largest integer = x + 2 + 2 = x + 4,

So, the sum of these integers = x + x + 2 + x + 4 = 3x + 6

According to the question,

3x + 6 = 288

3x = 282

⇒ x = 94

Hence, the integers are,

94, 94+2, 94+4

= 94, 96, 98

You have a total of 21 coins, all nickles and dimes. The total value is $1.70 Which of the following is the system of linear equations that represent this scenario? Let n= the number of nickles and let d= the number of dimes.

Answers

You need one equation for the physical nickels and dimes, which total to 21:

n+d=21

Secondly, you need one equation for the numerical value of those nickels and dimes. We know nickels are worth $0.05 and dime are worth $0.10:

.05n+.1d=1.70

What are the solutions of 2x^2+3x=-8

Answers

The equation given above is written here below with all the terms transposed to only one side of the equation.
     2x² + 3x + 8 = 0
The quadratic formula used for the determination of the roots is,
            x = (-b +/- sqrt (b² - 4ac)) / 2a

In the quadratic equation above, we have the numerical coefficients. 
   a = 2
   b = 3
   c = 8

Substituting the known values,
     x = (-3 +/- sqrt (3² - 4(2)(8))/ (2)(2)
      x = -0.75 + 1.854i  and x = -0.75 - 1.854i

By the calculated roots above, it is known that the roots are imaginary. 

How do you solve all of these ?

Answers

5)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ -3}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -1 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-3)=-1(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+3=-x+5\implies y=-x+2[/tex]

6)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 2}}\quad ,&{{ 1}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 3 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=3(x-2) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-1=3x-6\implies y=3x-5[/tex]

7)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ 2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 0 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=0(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-2=0\implies y=2[/tex]

8)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]

9)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]

10)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{-2}}\quad ,&{{ -2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-2)=\cfrac{3}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+2=\cfrac{3}{2}(x+2)\implies y+2=\cfrac{3}{2}x+3\implies y=\cfrac{3}{2}x+1[/tex]

Please help me and show work so I can understand worth 20 points!!!

Answers

The steps and final answer is shown in the attached image. I wrote it there so I could write out complex algebraic formulas. Let me know if you have any questions about any of the steps. Thank you.
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