the picture shows a barn door what is the distance BC between two horizontal parallel bars?

The Picture Shows A Barn Door What Is The Distance BC Between Two Horizontal Parallel Bars?

Answers

Answer 1
We know the lenght of the side adjacent to angle A, AC, and we want to know the opposite side, BC. What trig ratio describes the relationship between opposite and adjacent? The Tangent! 

tan (x) = opp / adj
In this case, tan (45°) = BC / 4
To get BC by itself, multiply both sides by 4
4 * tan (45°) = BC

The answer is D

Related Questions

Solve the equation using the Zero-Product Property. –8n(10n – 1) = 0

Answers

The answer to your question is n=0 or n=1/10

Answer: The solution is,

[tex]n = 0\text{ or }n = \frac{1}{10}[/tex]

Step-by-step explanation:

Since, Zero product property states that if the product of two numbers or expression is equal to zero then either of the numbers or expressions must be equal to zero.

That is, If a.b = 0 ⇒ a = 0 or b = 0

Here, the given expression is,

[tex]-8n(10n-1)=0[/tex]

[tex]\implies (-8n)(10n-1)=0[/tex]

Thus, by the above property,

[tex]-8n = 0\text{ or }(10n-1)=0[/tex]

[tex]\implies n = \frac{0}{-8}\text{ or }10n= 1[/tex]

[tex]\implies n = 0\text{ or }n = \frac{1}{10}[/tex]

if tanx=-4/3 and x is in quadrant 2 then cos2x=?
A. 7/25
b. -3/5
c. -7/25
d. 3/5

Answers

Trigonometric Identities are equalities that utilize trigonometry functions and hold true for all variables in the equation. The correct option is C, -7/25.

What are Trigonometric Identities?

Trigonometric Identities are equalities that utilize trigonometry functions and hold true for all variables in the equation. There are several trigonometric identities relating to the side length and angle of a triangle.

Given that the value of tan(x) = -4/3 and x is in quadrant 2.

In order to find the value of cos(2x), we can use the trigonometric identity of cos(2x), therefore, for cos(2x) we can write,

[tex]\cos(2x) = \dfrac{1-\tan^2(x)}{1+\tan^2(x)}[/tex]

Since the value of tan(x) is known, substitute the value in the identity,

[tex]\cos(2x) = \dfrac{1-(-\frac{4}{3})^2}{1+(-\frac{4}{3})^2}\\\\\cos(2x) = \dfrac{1-(\frac{16}{9})}{1+(\frac{16}{9})}\\\\[/tex]

cos(2x) = (-7/9) × (9/25)

Cancelling 9 from the numerator and the denominator,

cos(2x) = -7/25

Hence, if tanx=-4/3 and x are in quadrant 2 then cos2x=-7/25.

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The correct answer is c. [tex]$\cos(2x) = -\frac{7}{25}$[/tex].

First, we find [tex]$\sin(x)$[/tex] and [tex]$\cos(x)$[/tex] using the given value of [tex]$\tan(x)$[/tex]:

[tex]$\tan(x) = \frac{\sin(x)}{\cos(x)} = -\frac{4}{3}$.[/tex]

We can use the Pythagorean identity [tex]$\sin^2(x) + \cos^2(x) = 1$[/tex] to find [tex]$\sin(x)$[/tex] and [tex]$\cos(x)$[/tex]. Let's assume [tex]$\sin(x) = \frac{4}{5}$[/tex] (since [tex]$\tan(x) = -\frac{4}{3}$[/tex], and we are looking for a positive value of [tex]$\sin(x)$[/tex] in quadrant 2). Using the Pythagorean identity:

[tex]$\left(\frac{4}{5}\right)^2 + \cos^2(x) = 1$ \\ $\frac{16}{25} + \cos^2(x) = 1$ \\ $\cos^2(x) = 1 - \frac{16}{25}$ \\ $\cos^2(x) = \frac{25}{25} - \frac{16}{25}$ \\ $\cos^2(x) = \frac{9}{25}$. \\[/tex]

Since [tex]$\cos(x)$[/tex] is negative in quadrant 2, we have [tex]$\cos(x) = -\frac{3}{5}$[/tex].

 Now, we can use the double-angle formula for cosine:

[tex]$\cos(2x) = 2\cos^2(x) - 1$ \\ $\cos(2x) = 2\left(-\frac{3}{5}\right)^2 - 1$ \\ $\cos(2x) = 2\left(\frac{9}{25}\right) - 1$ \\ $\cos(2x) = \frac{18}{25} - 1$ \\ $\cos(2x) = \frac{18}{25} - \frac{25}{25}$ \\ $\cos(2x) = -\frac{7}{25}$.[/tex]

Therefore, the value of [tex]$\cos(2x)$[/tex] = [tex]$ -\frac{7}{25}$[/tex].

what is the prime factorization for 37

Answers

The answer is 1x37 and there other way to times 37.

The prime factorization of 37 is 37

We have,

The prime factorization of a number involves expressing it as a product of prime numbers.

However, in the case of prime numbers themselves, their prime factorization is simply the number itself.

In this case,

The number 37 is a prime number because it is only divisible by 1 and itself.

Since it has no other factors, its prime factorization is simply 37.

Thus,

The prime factorization of 37 is 37.

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if y varies directly as x and y=6 when x =-7, find y when x is 4

Answers

Final answer:

When x is 4, y is approximately -3.43.

Explanation:

To find y when x is 4, we can use the given information that y varies directly as x. This means that the ratio of y to x remains constant. We can set up a proportion using the initial values of y and x and solve for the unknown value:

6 / -7 = y / 4

By cross-multiplying, we get y = -24 / 7. Therefore, when x is 4, y is approximately -3.43.

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In order to start a business, a student takes out a simple interest loan for $7000.00 for 6 months at a rate of 8.00 %

Answers

To find The interest owed the formula is
I=prt
I interest owed?
P principle 7000
R interest rate 0.08
T time 6/12
I=7,000×0.08×(6÷12)
I=280

To find the balance at the end of 6 months the formula
A=p+I
A=7,000+280
A=7,280

Hope it helps!

Kurt and Maria’s high school is having a newspaper drive.The goal is to collect 3,585 pounds of newspapers. So far, 21% of the goal has been reached. Kurt estimated the number of pounds of newspapers collected by finding 10% of 3,600 and then multiplying the result by 2. Maria estimated the number of pounds of newspapers collected by finding mc006-1.jpg of 3,600. Who is right, and why?

Answers

Both Kurt and Maria are right, because 3585 will be rounded up to 3600 durning intermediate calculations and 21% of this amount can be approximated by either finding 10% of 3600 and multiplying the result by 2 or by finding [tex]\frac{1}{5}[/tex] of 3600.
Kurt and Maria were both right

The relationship between the number of $4 lunches you buy with a $100 school lunch card and the money remaining on the card

Answers

To set up an equation for this you must know what needs to be on the other side of the equals sign or what the answer is supposed to be. In this case, we know the answer should be the money remaining on the card. Since there is no number value for this, you must pick a variable to represent it. I am going to use variable R. So, since we know that you start with 100 dollars, and lose 4 dollars for each lunch, we can tell that there will be subtraction taking place. We also do not know how many lunches have been bought so we need a variable for that too. I will use variable x. That will leave you with an equation of:
R = 100 - 4x

x= number of lunches bought
R= remaining money on the lunch card

Hope this helps!

The equation of a line is y=3x+7. Change the equation so that it is proportional.

Answers

Answer:

y=3x

Step-by-step explanation:

For a line to be proportional it must have the form y=mx where the y-intercept is (0,0) through the origin. To change y=3x+7 to be proportional, write it as y=3x.

If Mr. Khans buys 15 staplers, it would cost him $254.85. How would you write this using function notation?

Answers

f(x) = 15x.......with f(x) being the total cost and x being the number of staplers

254.85 = 15x
254.85/15 = x
16.99 = x.....so each stapler costs $ 16.99

Answer:

f(x) = don't spend more than 200 dollars on staplers

Step-by-step explanation:

1.Find the coordinates of the midpoint of __ given that H (-1,3) and X (7,1).
HX

A.(3,1)
B (0,4)
C(-3,1)
D(-4,0)

2. Find the distance between the points R(0,5) and S(12,3). round the answer to the nearest tenth.

A 10.4
B 16
C 12.2
D 11.8

3. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85) what is the shortest possible distance for the trip?

A. 165 units
B. 170 units
C. 97 units
D. 169 units

Answers

1. B. 2.C 3.C.    these answers are all correct.

Answer:

1. (3, 2)

2. Option C. 12.2

3. Option A. 165 units

Step-by-step explanation:

1. The midpoint of two coordinates (x₁, x₂) and (y₁, y₂) is calculate by,

[tex](x, y) = (\frac{x_{1} + x_{2}}{2},\frac{y_{1} + y_{2}}{2})[/tex]

⇒[tex](x, y) = (\frac{-1 + 7}{2},\frac{3 + 1}{2})[/tex]

Thus (x, y) = (3, 2)

Hence, none of given options are true.

2. The distance between two coordinates is calculate by,

[tex]Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2[/tex]

⇒ Distance = 12.16 ≈ 12.2 unit

Hence, option (C) is correct.

3. The distance between T(80, 20) and V(110, 85) is comparatively smaller than T(80, 20) and U(20, 60).

Using the Distance formula,

[tex]Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2[/tex]

Distance between T(80, 20) and V(110, 85) is 71.59 unit

and Distance between U(20, 60) and V(110, 85) is 93.41 unit

So, Airplane firstly go to point V from point T and then point U.

Total shortest distance = 71.60 + 93.40 = 165 unit.

Hence, option (A) is correct.

what is the value of the 7 equal to (7×1/100)

Answers

Hey there (again)

[tex]7 ( \frac{1}{100} )[/tex]

Solve the division/fraction

[tex] \frac{1}{100} = 0.01[/tex]

Problem becomes: [tex]7(0.01) = 0.07[/tex]

[tex]Answer: 0.07[/tex]

Good luck on your assignment and enjoy your day!

~[tex]MeIsKaitlyn:)[/tex]

Determine the effective rate for $1 for 1 year at 5.9% compounded quarterly.

Answers

keeping in mind that the effective rate, is in effect the APY or Annual Percentage Yield, 

[tex]\bf \qquad \qquad \textit{Annual Yield Formula} \\\\ ~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1 \\\\ \begin{cases} r=rate\to 5.9\%\to \frac{5.9}{100}\to &0.059\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four times} \end{array}\to &4 \end{cases} \\\\\\ \left(1+\frac{0.059}{4}\right)^{4}-1\implies (1.01475)^4-1 \approx 0.0603 \\\\\\ 0.0603\cdot 100\implies \stackrel{\%}{6.03}[/tex]

Order the fraction from least to greatest.
2/3, 4/9, 5/6, 7/12

Answers

Ok so the first thing we need to do is find the least common denominator. The LCD is 36.

Now we must make all the denominators 36.
(2/3)=(24/36)
(4/9)=(16/36)
(5/6)=(30/36)
(7/12)=(21/36)

So we have the numbers (24/36),(16/36),(30/36), and (21/36).

Since they all have the same denominator, we can compare all the numerators and order hem from least to greatest.

(16/36)<(21/36)<(24/36)<(30/36)

Now that we have the order, we must simplify the numbers back to their original forms.

(4/9)<(7/12)<(2/3)<(5/6)

And that is your answer
1. 4/9 
2. 7/12
3. 2/3
4. 5/6

Solve: 5x - 7x + 6 = -2(x - 3).

A)
0


B)
3
4


C)
2


D)
infinitely many solutions

Answers

Answer:

  D)  infinitely many solutions

Step-by-step explanation:

The equation reduces to ...

  -2x +6 = -2x +6

This is true for all possible values of x, so there are infinitely many solutions.

Joanne is depositing money into a bank account. After 3 months there is $150 in the account. After 6 months there is $300 in the account. Determine the constant rate of change of the account.

Answers

The constant rate is 50 dollars per month. I hope this helps!

Answer:

The constant rate of change of the account is $50 or Increasing by $50 per month.

Step-by-step explanation:

Consider the provided information.

Joanne is depositing money into a bank account. After 3 months there is $150 in the account. After 6 months there is $300 in the account.

Rate of change is known as how one quantity change in relation to other.

The rate of change can be calculated as:

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Now use the above formula to calculated the rate of change.

[tex]\frac{300-150}{6-3}[/tex]

[tex]\frac{150}{3}[/tex]

[tex]50[/tex]

Hence, the constant rate of change of the account is $50 or Increasing by $50 per month.

Ken watches a marching band. He sees 2 rows of flute players. Six people are in each row. He sees 8 trombone players. How many flute or trombone players does Ken see

Answers

Twelve flute players.

Eight trombone players.

20 total of flute and trombone players.

the 4th and 13th terms of an AP are 5 and -1, find the 8th term of an AP

Answers

now, we know the 4th term is 5.... ok... now, what's the common difference?  well, we dunno, but notice, from the 4th to the 13th term, you do have to use it 9 times to hop over to the 13th term, let's say is "d", then

[tex]\bf \begin{array}{llll} term&value\\ ------&------\\ a_4&5\\ a_5&5+d\\ a_6&(5+d)+d\\ a_7&(5+d+d)+d\\ a_8&(5+d+d+d)+d\\ a_9&(5+d+d+d+d)+d\\ a_{10}&(5+d+d+d+d+d)+d\\ a_{11}&(5+d+d+d+d+d+d)+d\\ a_{12}&(5+d+d+d+d+d+d+d)+d\\ a_{13}&(5+d+d+d+d+d+d+d+d)+d\\ &5+9d \end{array}[/tex]

we also know that the 13th term is -1

[tex]\bf \stackrel{a_{13}}{5+9d}=-1\implies 9d=-6\implies d=\cfrac{-6}{9}\implies \boxed{d=-\cfrac{2}{3}}[/tex]

now, recall above what the 8th term is 

[tex]\bf a_8=5+4d\implies a_8=5+4\left(-\frac{2}{3} \right)\implies a_8=5-\cfrac{8}{3}\implies a_8=\cfrac{7}{3}[/tex]

a few questions i need help with.

Answers

question 1:
The first step is getting rid of the denominators by multiplying all terms by 3. This is done using multiplicative property.
The second step is getting rid of the brackets using the distributive property.
The third and fourth steps are isolating the term containing the x on one side of the inequality using addition or subtraction property of order
The last step is getting rid of the coefficient of the x using the division property of order.

So, the correct order of choices is:
1- multiplicative property..
2- distributive property.
3- addition or subtraction property of order
4- addition or subtraction property of order
5- division property of order.

question 2:
The first step is getting rid of the brackets using the distributive property.
The second and third steps are isolating the term containing the x on one side of the inequality using addition or subtraction property of order
The last step is getting rid of the coefficient of the x using the division property of order.

So, the correct order of choices is:
1- distributive property.
2- addition or subtraction property of order
3- addition or subtraction property of order
4- division property of order.

Let f(x,y)=x2 −y2. find the gradient of f at the point (√2,1). sketch the level curve of f through this point, together with the gradient at that point. g

Answers

Answer:

[tex]\displaystyle \nabla f(\sqrt{2}, 1) = 2\sqrt{2} \hat{\i} - 2 \hat{\j}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

DerivativesDerivative Notation

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Multivariable Calculus

Differentiation

Partial DerivativesDerivative Notation

Gradient:                                                                                                               [tex]\displaystyle \nabla f(x, y, z) = \frac{\partial f}{\partial x} \hat{\i} + \frac{\partial f}{\partial y} \hat{\j} + \frac{\partial f}{\partial z} \hat{\text{k}}[/tex]

Gradient Property [Addition/Subtraction]:                                                           [tex]\displaystyle \nabla \big[ f(x) + g(x) \big] = \nabla f(x) + \nabla g(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle f(x, y) = x^2 - y^2[/tex]

[tex]\displaystyle P(\sqrt{2}, 1)[/tex]

Step 2: Find Gradient

[Function] Differentiate [Gradient]:                                                              [tex]\displaystyle \nabla f(x, y) = \frac{\partial f}{\partial x} \bigg[ x^2 - y^2 \bigg] \hat{\i} + \frac{\partial f}{\partial y} \bigg[ x^2 - y^2 \bigg] \hat{\j}[/tex][Gradient] Rewrite [Gradient Property - Addition/Subtraction]:                [tex]\displaystyle \nabla f(x, y) = \bigg[ \frac{\partial f}{\partial x}(x^2) - \frac{\partial f}{\partial x}(y^2) \bigg] \hat{\i} + \bigg[ \frac{\partial f}{\partial y}(x^2) - \frac{\partial f}{\partial y}(y^2) \bigg] \hat{\j}[/tex][Gradient] Differentiate [Derivative Rule - Basic Power Rule]:                  [tex]\displaystyle \nabla f(x, y) = 2x \hat{\i} - 2y \hat{\j}[/tex][Gradient] Substitute in point:                                                                     [tex]\displaystyle \nabla f(\sqrt{2}, 1) = 2\sqrt{2} \hat{\i} - 2(1) \hat{\j}[/tex][Gradient] Simplify:                                                                                       [tex]\displaystyle \nabla f(\sqrt{2}, 1) = 2\sqrt{2} \hat{\i} - 2 \hat{\j}[/tex]

∴ the gradient of the given f(x, y) function is equal to <2√2, -2>.

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Topic: Multivariable Calculus

Unit: Directional Derivatives

When mary began her trip from san jose to la, she filled her car's tank with gas and reset its trip meter to zero. after traveling 324 miles, she stopped at a gas station to refuel; the gas tank required 17 gallons. mary wants a program that calculates and displays her car's gas mileage at any time during the trip. the gas mileage is the number of miles her car was driven per gallon of gas?

Answers

Yes.  The average  gas mileage for the trip was 324 / 17  =   19.06 miles per gallon
Final answer:

To calculate Mary's car's gas mileage, divide the number of miles driven by the number of gallons of gas used. In this scenario, her car's gas mileage is approximately 19.06 miles per gallon.

Explanation:

To calculate Mary's car's gas mileage, we need to divide the number of miles driven by the number of gallons of gas used. In this scenario, Mary traveled 324 miles and used 17 gallons of gas. Therefore, her car's gas mileage can be calculated as:

Gas mileage = Miles driven / Gallons of gas used

Substituting the values:

Gas mileage = 324 miles / 17 gallons

Simplifying the equation:

Gas mileage = 19.06 miles per gallon (rounded to two decimal places)

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Find the distance between points M(6,16) and Z(-1,14) to the nearest tenth.

Answers

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) M&({{ 6}}\quad ,&{{ 16}})\quad % (c,d) Z&({{ -1}}\quad ,&{{ 14}}) \end{array}\quad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ MZ=\sqrt{(-1-6)^2+(14-16)^2}\implies MZ=\sqrt{(-7)^2+(-2)^2} \\\\\\ MZ=\sqrt{49+4}\implies MZ=\sqrt{53}\implies MZ\approx 7.3[/tex]

All of the following expressions represent the sum of n and itself, except _____.

n + n
2n

Answers

n^2 because 2n is the same as n+n, but n^2 is the same as the product of n and n

Answer: [tex]n^{2}[/tex]

Step-by-step explanation:

(n + n) represents the definition of the sum of n and itself.

(2n) means two times n, wich is the same as adding n + n.

[tex]n^{2}[/tex] actually represents the multiplication of n two times: [tex]n*n[/tex]

For example, if n=3:

[tex]n+n=3+3=6[/tex]

[tex]2n=2(3)=6[/tex]

[tex]n^{2}=3^{2} =9[/tex]

One tablet contains 575 grams of muscle relaxing medication. How many grams are in 3 1/2 tablets

Answers

3.5*575=2,012.5 grams
the answer is 2012.5 grams of medicine 

an equation is shown below. 3x-10x+5=5x+17 what is the value of x that makes the equation true?

Answers

collect like terms;

3x-10x=-7x

-7x+5=5x+17

move the variable to the left and change sign

-7x+5=5x+17

move the constant to the right and change sign

-7x-5x+17-5

collect the like terms

-12x=17-5

subtract the numbers

-12x=12

divide both sides by -12

your answer is: x= -1

a pump is running at 6.4 quarts per minute. how many gallons per hour is this?

Answers

60*6.4 quarts = 384 quarts = 96 Gallons/hr

Is the subset w = {(x, y, z) | z = 1} ⊂ r 3 a vector subspace of r 3 ? explain why or why not?

Answers

No, [tex]W[/tex] is not a subspace of [tex]\mathbb R^3[/tex] because it doesn't contain the zero vector.

3x + 5x = 10 Which problem requires the same strategy (combining like terms)?

Answers

3x + 5x = 10 Which problem requires the same strategy (combining like terms)?
3x - 2x = 10


The answer is D. 3x - 2x = 10

what fraction 2/3 is found between which pair of fraction on the number line?

Answers

one third and three thirds,

Graph the line y+3=2(x-1) first identify the slope of the line

Answers

First you need to simplify the equation.

y + 3 = 2(x - 1)
y + 3 = 2x - 2

Then you need to put that into slope-intercept form (y = (slope)x + (y intercept))

y + 3 = 2x - 2
    -3           -3
y = 2x - 5

The slope is the coefficient of x, so 2 is the slope of the line.

which number is greater 67.89 and 67.98

Answers

67.98 lol what king of question is that??

.98 is greater than .89
so 67.98 is greater than 67.89

answer
67.98 is greater
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