The pressure in a water line is 1500 kPa. What is the line pressure in (a) lb/ft2units and (b) lbf/in2(psi) units?

Answer:

Three operations possible in a quack is QUACKPUSH, QUACKPOP and QUACKPULL.

Explanation:

A quack is a data structure combining properties of both stacks and queues. It can be viewed as a list of elements written left to right such that three operations are possible, these include:

Elements in the quack are stored in stacks. The component stacks can be accessed only through the standard stack functions PUSH and POP.

Answer:

The Java code is given below with appropriate comments for better understanding

Explanation:

import java.util.Scanner;

public class ValidatePassword {

  public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

          System.out.print("Enter a password: ");

          String password = input.nextLine();

          int count = chkPswd(password);

          if (count >= 3)

              System.out.println("Secure");

          else

              System.out.println("Not Secure");

  }

  public static int chkPswd(String pwd) {

      int count = 0;

      if (checkForSpecial(pwd))

          count++;

      if (checkForUpperCasae(pwd))

          count++;

      if (checkForLowerCasae(pwd))

          count++;

      if (checkForDigit(pwd))

          count++;

      return count;

  }

  // checks if password has 8 characters

  public static boolean checkCharCount(String pwd) {

      return pwd.length() >= 7;

  }

  // checks if password has checkForUpperCasae

  public static boolean checkForUpperCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isUpperCase(pwd.charAt(i)))

              return true;

      return false;

  }

  public static boolean checkForLowerCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isLowerCase(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password contains digit

  public static boolean checkForDigit(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isDigit(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password has special char

  public static boolean checkForSpecial(String pwd) {

      String spl = "!@#$%^&*(";

      for (int i = 0; i < pwd.length(); i++)

          if (spl.contains(pwd.charAt(i) + ""))

              return true;

      return false;

  }

}

Answer:

The largest distance between corners in a 3-D cube = a root 3

Explanation : The detailed and step by step explanation is given in the attached file below.

Answer:

B. $5.18

Explanation:

Cost of electricity per kWh = $0.09

Power consumption of refrigerator = 320W = 320/1000 = 0.32kW

In a month (30 days) the refrigerator works 1/4 × 30 days = 7.5 days = 7.5 × 24 hours = 180 hours

Energy consumed in 180 hours = 0.32kW × 180h = 57.6kWh

Cost of electricity of 57.6kWh energy consumed by the refrigerator = 57.6 × $0.09 = $5.18

The electricity cost of the refrigerator per month is approximately $0.65. The correct answer is none of the given options.

To calculate the electricity cost of the refrigerator per month, we first need to find out how many kWh it consumes when it is running for one hour. We can do this by converting the power consumption of the refrigerator from watts to kilowatts:

320 W = 0.32 kW

Since the refrigerator runs only one quarter of the time, we can calculate the kWh consumed per month as follows:

0.32 kW * 1/4 * 24 hours/day * 30 days/month = 7.2 kWh/month

Now, we can calculate the cost of electricity using the unit cost of $0.09/kWh:

7.2 kWh/month * $0.09/kWh = $0.648/month

Therefore, the electricity cost of the refrigerator per month is approximately $0.65.

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Answer:p=ML^-1T^-2

b)PV=MT^-3

c)P/PV^2=T^2L^-2

Explanation:In dimensions,Mass in kg is represented by M

Length is represented by L in meters.

T represent Time in seconds,s.

Pressure=hpg,h=height or depth In m,a=density=kg/m^3

g=acceleration due to gravity,m/s^2

P=hag=mxkg/m^3 xm/s^2=m^2×kg/m^2×s^2=kgm^-1 s^-2=ML^-1T^-2

B)PV=pressure xvelocity

=ML^-1T^-2×distance/time

ML^-1T^-2×L/T=MT^-3

C)p/pv^2=1/V^2=(time/distance)^2=(T/L)^2=T^2L^-2

Answer:

1. the bulb of the thermometer must be in the center of the lower calorimeter, about one inch from the bottom.

2.thermometer must face you to read

Explanation:

During an actual run with the calorimeter, there are two important criteria which must be satisfied by a correctly positioned thermometer. These two criteria include;

1. the bulb of the thermometer must be in the center of the lower calorimeter, about one inch from the bottom.

2. thermometer must face you to read

The thermometer must be fully immersed without touching the calorimeter’s sides or bottom and positioned to minimize heat exchange with the external environment to ensure accurate temperature readings.

When using a calorimeter, it is crucial to ensure that the thermometer is correctly positioned to obtain accurate measurements. The two important criteria for correctly positioning the thermometer in a calorimeter are:

1. Thermal Equilibrium:

  - The thermometer must be fully immersed in the substance being measured (typically a liquid) without touching the sides or the bottom of the calorimeter. This ensures that the thermometer accurately reflects the temperature of the substance rather than the container.

  - The immersion should be deep enough so that the thermometer's bulb is surrounded by the substance, allowing it to reach thermal equilibrium with the substance. This helps in obtaining a consistent and accurate temperature reading.

2. Minimize Heat Exchange with the Environment:

  - The thermometer should be positioned in a way that minimizes heat exchange with the external environment. The calorimeter is designed to be an insulated system, so the thermometer should not introduce significant thermal disturbance.

  - The top of the calorimeter should be closed or covered as much as possible to prevent heat loss or gain from the surroundings, which could affect the temperature reading. The thermometer should pass through a small hole or a sealed opening to maintain the insulation integrity of the calorimeter.

By adhering to these criteria, the thermometer can provide precise and reliable temperature measurements, which are essential for accurate calorimetric calculations.

Answer:

The moist unit weight of compaction = 109.05 lb/ft3

Explanation:

In order to determine the moist unit weight, the dry unit weight has to be evaluated first. If Y is the moist unit weight, then:

Y = Yd (1 + m)

Where:

Yd = dry unit weight

m = moisture content of soil = 8% = 0.08

But the dry unit weight is unknown. In order to calculate the dry unit weight, we will make use of the formula for relative density R;

R = [(Yd — Ydmin) ÷ (Ydmax — Ydmin)] × [Ydmax ÷ Yd]

Where:

R = relative density = 60% = 0.6

Yd = dry unit weight

Ydmin = minimum dry weight = 92 lb/ft3

Ydmax = maximum dry weight = 108 lb/ft3

Therefore R = 0.6 = [(Yd — 92) ÷ (108 — 92)] × [108/Yd]

0.6 = [(Yd — 92)/16] × [108/Yd], or

0.6 = (0.0625Yd — 5.75) × [108/Yd]

0.6Yd = 6.75Yd — 621

6.75Yd — 0.6 Yd = 621

6.15Yd = 621

And Yd = 100.98 lb/ft3 = dry unit weight

But we are asked to find the moist unit weight = Y = Yd (1 + m)

where Yd = dry unit weight and m = moisture content of soil = 8% = 0.08

Therefore, Y = 100.98 (1 + 0.08) = 109.05 lb/ft3.

Answer:

The program is given below with appropriate comments for better understanding

Explanation:

#Program

# foot stride = 2.5 feet

# 1 mile = 5280 feet

no_stride_first_min = int(input('Enter the number strides made durng the first minute of jogging: '))

no_stride_last_min = int(input('Enter the number strides made durng the last minute of jogging: '))

avg_stride_one_min = (no_stride_first_min + no_stride_last_min)/2 # calculates the average stride per minute

jogging_duration = float(input('Enter the total time spent jogging in hours and minute: '))

jogging_duration_hours = int(jogging_duration) # gets the hour

jogging_duration_min = jogging_duration - int(jogging_duration) # gets the minute

tot_jogging_duration_min = jogging_duration_hours*60 + jogging_duration_min # calculates total time in minutes

dist_feet = (avg_stride_one_min*2.5)*tot_jogging_duration_min # calculates the total distance in feet

dist_miles = dist_feet/5280 # calculates the total distance in mile

print('Distance traveled in miles = {0:.2f} miles'.format(dist_miles))

The volume of a zirconium unit cell, using a theoretical density of 6.52 g/cm³ and an atomic weight of 91.22 g/mol, can be found to be approximately 2.3 x 10-29 m³.

To calculate the volume of the zirconium unit cell, we need to know the atomic weight, density, and Avogadro's number. Assuming a theoretical density of 6.52 g/cm³, an atomic weight of 91.22 g/mol, and using Avogadro's number (6.022 x 10²³ atoms/mol), we can use the formula: volume = atomic weight / (density * Avogadro's number).

First, convert the density from g/cm³ to kg/m³, 1 g/cm³ = 1000 kg/m³. So, 6.52 g/cm³ = 6520 kg/m³. Then substitute these values into the formula: volume = 91.22 g/mol / (6520 kg/ m³ * 6.022 x 10²³ atoms/mol) = approximately 2.3 x 10-29 m³.

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Answer:

558.1918 kilocalories = 558191.8 calories

Explanation:

Data provided in the question:

Atmospheric pressure = 84.6 KPa

Mass of water, m = 900 g = 0.90 kg

Temperature = 15°C

Now,

Temperature at 84.6 KPa = 94.77°C

Therefore,

Heat energy required = m(CΔT + L)

here,

C is the specific heat of the water = 4.2 KJ/kg.°C

L = Latent heat of water = 2260 KJ/kg

Thus,

Heat energy required = 0.90[ 4.2 × (94.77 - 15) + 2260 ]

= 2335.53 KJ

also,

1 KJ = 0.239  Kilocalories

Therefore,

2335.53 KJ = 0.239 × 2335.53 Kilocalories

= 558.1918 kilocalories = 558191.8 calories

Answer:

d) II and IV . See explanation below.

Explanation:

Assuming the following list of inputs:

I. The discount percentage

II. The total value of the purchase

III. The loyalty-discount amount

IV. The customer ID card number

V. The amount payable after discount  

Possible options for the answer:

a) I, II, and III

b) I and III

c) II, IV, and V

d) II and IV  

For this case we want to calculate the amount payable by the customer after the discounts.

And for this case is always necessary the value of the purchase so option II is true. The percent of discount is given so then option I is not true since we know this value.

The option III is not required since the discount is based on the info and if the customer have ID card so then this value is not necessary.

For option IV is necessary know the ID card in order to identify if the person have a permanent or non permanent card in order to apply discounts, this information is useful

And for the last option V that's not an input, since represent the output desired.

So then the correct options are II and IV

d) II and IV  

The level of service of a highway is determined by the volume-to-capacity ratio. Using the provided traffic information, we can calculate the highway's capacity and determine its level of service, which ranges from A to F.

The level of service of a highway is determined by the volume-to-capacity ratio (V/C ratio).

Given peak-hour directional traffic flow, vehicle types, peak-hour factor, and free-flow speed, we can calculate the capacity of the highway and determine the level of service.

In this case, we would need to calculate the volume of traffic compared to the highway's capacity to determine the level of service, which can range from A to F.

Answer:

The weakest link is the people of the organization

The employees should be oriented and educated on the need to be security and safety conscious

Explanation:

Security professional had shown that negligence among the employees for security practices is a serious threat to end point security.

Answer:

a) Etath = 48.2 %

b) P2 = 1.195 MPa

c) wnet = 1749.14 KJ/kg

Explanation:

Given:

T1 = T2 = 50 , TL = 50 + 273 = 323 K

T3 = T4 = 350 , TH = 350 + 273 = 623 K

x3 =0.891

x4 = 0.1

Part a

Thermal efficiency (Etath) of carnot cycle is:

Etath = 1 - (TL / TH )

Etath = 1 - (323) / (623) = 48.2 %

Part b

Note:

From A - 4 Table

T1 = 50 C @sat

sf = 0.7038 KJ/kg.K

sfg = 7.3710 KJ/Kg.K

s2 = s3 = sf + x3 * (sfg)

s2 = s3 = 0.7038 + 0.891*7.3710 = 7.271361 KJ/kg.K

Thus,

@ T2 = 350 C  ; sg = 5.2114 KJ/kg.K

s2 = 7.271361 KJ/kg.K

s2 > sg@T = 350 C, hence super-heated region.

Use Table A-6

T2 = 350 C

s2 = 7.271361 KJ/kg.K

P2 = 1.195 MPa (using interpolation)

part c

wnet can be calculated by finding the enclosed area on a T-s diagram:

s4= sf + x4*sfg =  0.7038 + 0.1*7.3710 = 1.4409 KJ/kg.K

wnet = (TH - TL)*(s3 - s4)

wnet = (623 - 223) * (7.271361 - 1.4409) = 1749.14 KJ/kg

Hi, you haven't provided the programing language in which you need the code, I'll just explain how to do it using Python, and you can apply the same method for any programming language, pseudocode or flowchart.  

Answer:

1 userInput = input("Please enter 'userInput':\n")

2 if "darn" in userInput.lower():

3      print("Censored")

4 else:

5      print(userInput\n)

Explanation line by line:

Answer:

Explanation:

Sample output:

BANK ACCOUT PROGRAM!

----------------------------------

Enter the old balance: 1234.50

Enter the transactions now.

Enter an F for the transaction type when you are finished.

Transaction Type (D=deposit, W=withdrawal, F=finished): D

Amount: 568.34

Transaction Type (D=deposit, W=withdrawal, F=finished): W

Amount: 25.68

Transaction Type (D=deposit, W=withdrawal, F=finished): W

Amount: 167.40

Transaction Type (D=deposit, W=withdrawal, F=finished): F

Your ending balance is $1609.76

Program is ending

Code to copy:

// include the necessary header files.

#include<stdio.h>

// Definition of the function

float withdraw(float account_balance, float withdraw_amount)

{

// Calculate the balace amount.

float balance_amount = account_balance - withdraw_amount;

// Check whether the withdraw amount

// is greater than 0 or not.

if (withdraw_amount > 0 && balance_amount >= 0)

{

// Assign value.

account_balance = balance_amount;

}

// return account_balance

return account_balance;

}

// Definition of the function deposit.

float deposit(float account_balance, float deposit_amount)

{

// Check whether the deposit amount is greater than zero

if (deposit_amount > 0)

{

// Update account balance.

account_balance = account_balance + deposit_amount;

}

// return account balance.

return account_balance;

}

int main()

{

// Declare the variables.

float account_balance;

float deposit_amount;

float withdrawl_amount;

char input;

// display the statement on console.

printf("BANK ACCOUT PROGRAM!\n");

printf("----------------------------------\n");

// prompt the user to enter the old balance.

printf("Enter the old balance: ");

// Input balance

scanf("%f", &account_balance);

// Display the statement on console.

printf("Enter the transactions now.\n");

printf("Enter an F for the transaction type when you are finished.\n");

// Start the do while loop

do

{

// prompt the user to enter transaction type.

printf("Transaction Type (D=deposit, W=withdrawal, F=finished): ");

// Input type.

scanf(" %c", &input);

// Check if the input is D

if (input == 'D')

{

// Prompt the user to input amount.

printf("Amount: ");

// input amount.

scanf("%f", &deposit_amount);

// Call to the function.

account_balance=deposit(account_balance,deposit_amount);

}

// Check if the input is W

if (input == 'W')

{

printf("Amount: ");

scanf("%f", &withdrawl_amount);

// Call to the function.

account_balance = withdraw(account_balance,withdrawl_amount);

}

// Check if the input is F

if (input == 'F')

{

// Dispplay the amount.

printf("Your ending balance is $%.2f\n", account_balance);

printf("Program is ending\n");

}

// End the while loop

} while(input != 'F');

return 0;

}

the picture uploaded below shows the program screenshot.

cheers, i hope this helps.

Answer:

2.14 ft

Explanation:

We will use the following equation:

[tex]L = \frac{R_{T} * A}{p_{20C}*(1+\alpha _{20C}*dt ) }[/tex]

Data obtained:

[tex]R_{15.3 F , -9.27 C} = 15.3 ohms\\A_{28-gauge} = 8.2*10^(-8) m^2\\p_{20 C} = 1.723*10^(-6)\\\alpha _{20C} = 0.00393\\ dt = 20 - (-9.27) = 29.28[/tex]

Using the above equation:

[tex]L = \frac{15.3 * 8.2*10^(-8)}{1.723*10^(-6)*(1+0.00393*29.28 ) }\\\\L =0.6530 m = 2.14 ft[/tex]

To form the string 'ant bat cod', you can concatenate the strings s1, s2, and s3 using the + operator or repeat each string based on the desired repetition using the * operator.

Python expressions using s1, s2, and s3 and operators and * that evaluate to: (a) 'ant bat cod'.

Answer:

41.87 grams of water content must be added to each 500 grams of Boston Blue Clay (in its natural state) in order to increase the water content to 21.2%

Explanation:

The natural water content in Boston Clay is 14.6%. Thus, in 500 grams of Boston clay, the amount of water, naturally present will be:

Natural Water Content = 14.6% of 500 grams

Natural Water Content = 0.146 x 500 grams

Natural Water Content = 73 grams

Thus, the amount of dry clay will be:

Dry Clay = 500 grams - 73 grams

Dry Clay = 427 grams

Now, the required water content is 21.2%, and thus, the remaining 78.8% will be the dry clay. The mass of dry clay is calculated to be 427 grams.

If, we let 'X' be the total mass of clay and water content after the water content is increased to 21.2%. Then;

427 grams = 78.8% of X

427 grams = (0.788)X

X = 427 grams/0.788

X = 541.87 grams

Now, the mass of water content added will be equal to the difference between the total mass of clay before addition of water content and total mass of clay after addition of water content.

Water content added = X - 500 grams

Water Content Added = 541.87 grams - 500 grams

Water Content Added = 41.87 grams

90 inches

Explanation:

According to OSHA requirement, the distance around safety showers and eyewash should be between 82-96 inches off the flow. This will allow for maximum diameter of spray.

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Answer:

Explanation:

Implementing strategic system requires extensive organizational change coupled with a period of changing from one stage of socio-technical level to another. This changes are known as strategic transitions and are not easily achieved.

It must be noted that not all strategic systems are rewarding and can be very expensive to put together. It is easier to copy most information systems from other firms because strategic advantage can be most times unsustainable.

The stress in the brass cylinder can be calculated using a thermal stress formula that considers the modulus of elasticity, coefficient of linear expansion, and temperature change of the brass. Specific material properties for brass are needed to plug into the formula.

The stress in the cylinder can be found by considering that an increase in temperature will cause the brass cylinder BD to expand, while the steel rod AC remains the same length. This will cause an extra stress in the brass cylinder due to the constraints. The stress can be calculated using the formula σ = EαΔT where:

In order to use this thermal stress formula, you will need to look up the specific properties for brass in a materials textbook or reliable online resource. Substitute these values into the formula to get the stress in the brass cylinder caused by the temperature change.

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Answer:

Input power of the geothermal power will be 686000 J

Explanation:

We have given density of brine [tex]\rho =1050kg/m^3[/tex]

Rate at which brine is pumped [tex]V=0.3m^3/sec[/tex]

So mass of the pumped per second

Mass = volume × density = [tex]1050\times 0.3=315[/tex] kg/sec

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Depth h = 200 m

So work done [tex]W=mgh=315\times 9.8\times 200=617400J[/tex]

Efficiency is given [tex]\eta =0.9[/tex]

We have to fond the input power

So input power [tex]=\frac{617400}{0.9}=686000J[/tex]

So input power of the geothermal power will be 686000 J

Answer:

Vb.Net

msgbox ("Press "q" twice to quit", msgboxstyle.information)

if char.q = keypress and keypress.count = 2 then

End

End if

Explanation:

Answer:PHYSICALLY- sand is spherical in shape with large particles up to 0.18g

Silt also contains more of spherical particles with weights around 0.0029g.

Clay contain plate like particles,which are flat or layered. It's particles are generally lower that silt and sand below 0.0029g.

BEHAVIORS Sand particles are coarse and very porous,water can easily penetrate with no particles cohesion,does not retain water, difficult to expand,it is IDEAL FOR BUILDINGS.

Silt particles are also porous with some coarseness and no particles cohesion. retains water and can expand. NOT IDEAL FOR BUILDINGS.

Clay contain particles that are not coarse,they have high cohesiveness,they are not porous as it is difficult for water to penetrate. NOT IDEAL FOR BUILDINGS.

Explanation: Sand particles are coarse,very porous,contains spherical particles with large particles sizes and IDEAL FOR BUILDINGS

Silt particles are also porous, with some coarseness and with little or no particles cohesion, NOT IDEAL FOR BUILDINGS.

Clay soils are not porous water can not easily flow thought it,it is hard when dry and soft when wet. IT IS NOT A GOOD OPTION FOR BUILDINGS.

Answer:

B.gabbro

Explanation:

Gabbro is a coarse-grained, dark-colored igneous

rock . It is usually black or dark green in color and composed mainly of the minerals plagioclase and augite. It is the most abundant rock in the deep oceanic crust. Gabbro is used in construction.

Answer:

FALSE: decision support system is an information system that supports business or organizational decision-making activities.

Explanation:

Decision support system is an information system that supports business or organizational decision-making activities. While, a computer program or tool that software developers use to create, debug, maintain, or otherwise support other programs and applications is known as software development tool.

Software development approach maybe Agile, Waterfall, Scrum, Extreme programming, Lean and Feature-Driven Development methodologies.

Answer:

A)The sketches for the required planes were drawn in the first attachment.

B)The sketches for the required directions were drawn in the second attachment.

To draw a plane in a simple cubic lattice, you have to follow these instructions:

1- the cube has 3 main directions called "a", "b" and "c" (as shown in the first attachment)

2- The coordinates of that plane are written as: π:(1/a₀ 1/b₀ 1/c₀) (if one of the coordinates is 0, for example (1 1 0), c₀ is ∞, therefore that plane never cross the direction c).

3- Identify the points a₀, b₀, and c₀ at the plane that crosses this main directions and point them in the cubic cell.

4- Join the points.

To draw a direction in a simple cubic lattice, you have to follow these instructions:

1- Identify the points a₀, b₀, and c₀ in the cubic cell.

2- Draw the direction as a vector-like (a₀ b₀ c₀).

Answer:

Apparent Specific Gravity = 2.88

bulk specific gravity = 2.76

Bulk Specific Gravity SSD  = 2.80

absorption = 1.44%

bulk volume  = 373.3

Explanation:

given data

oven dry weight A  = 1034.0 g

moisture content = 4.0 %

saturated surface dry weight B = 1048.9 g

weight of the aggregate in water C = 675.6 g

solution

we get here Apparent Specific Gravity that is express as

Apparent Specific Gravity = [tex]\frac{A}{A-C}[/tex]   ..........1

put here value

Apparent Specific Gravity = [tex]\frac{1034}{1034-675.6}[/tex]

Apparent Specific Gravity = 2.88

and

now we get bulk specific gravity that is

bulk specific gravity = [tex]\frac{A}{B-C}[/tex]   ...................2

put here value

bulk specific gravity = [tex]\frac{1034}{1048.9-675.6}[/tex]

bulk specific gravity = 2.76

and

now we get Bulk Specific Gravity SSD

Bulk Specific Gravity SSD = [tex]\frac{B}{B-C}[/tex]    ............3

Bulk Specific Gravity SSD = [tex]\frac{1048.9}{1048.9-675.6}[/tex]

Bulk Specific Gravity SSD  = 2.80

and

now absorption will be here as

absorption = [tex]\frac{B-A}{A}[/tex] × 100%    ................4

absorption = [tex]\frac{1048.9-1034}{1034}[/tex] × 100%

absorption = 1.44%

and

last we get bulk volume that is

bulk volume = [tex]\frac{weight\ displce\ water}{density\ water }[/tex]

bulk volume = [tex]\frac{1048.9-675.6}{1}[/tex]

bulk volume  = 373.3

To estimate the drag force on the prototype submarine, use the principle of dynamic similarity and scale up the measured drag force by a factor of 5.

To estimate the drag force on the prototype submarine, we can use the principle of dynamic similarity. The drag force is directly proportional to the density of the fluid, the velocity of the fluid flow, and the reference area of the object. Since the model submarine is one-fifth the size of the prototype, we need to scale up the measured drag force by a factor of 5. Additionally, we need to account for the difference in fluid density between air and water, as well as the viscosity of the fluid.

The drag force on the prototype submarine can be estimated using the equation:

Drag force (prototype) = Drag force (model) x (scale factor)^2 x (fluid density ratio) x (viscosity ratio)

By plugging in the given values and solving the equation, we can estimate the drag force on the prototype submarine.

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