how do you simplify -7 |7|
Which symbol correctly compares the two fractions? Use > , < , or =. Enter your answer in the box. 2/4 3/8
The greater than symbol, ">," accurately compares the two fractions because 2/4 > 3/8. They are 2/4 and 3/8, respectively.
what are symbols ?something that represents another item. especially: something tangible that denotes or implies something else that is not itself imaginable or demonstrable. The lion is a representation of bravery. an alternative to a word or combination of words, such as a letter, character, or sign.
given
= 2/4 = 0.5
= 3/8 = roughly 0.37
The greater than symbol, ">," accurately compares the two fractions because 2/4 > 3/8.
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Final answer:
To compare 2/4 and 3/8, simplify 2/4 to 1/2, then convert to eighths, resulting in 4/8. Since 4/8 is greater than 3/8, 2/4 is greater than 3/8.
Explanation:
To compare the fractions 2/4 and 3/8, we need to find a common denominator or convert them to a common form such as decimals.
The simplest way is to notice that 2/4 can be simplified to 1/2.
Now, if we convert 1/2 to eighths, we get 4/8 because we multiply both the numerator and denominator by 4 to get the common denominator of 8 (1 x 4)/(2 x 4) = 4/8.
Comparing 4/8 with 3/8, we can see that 4/8 is larger than 3/8, as 4 is greater than 3.
Hence, the correct inequality symbol to compare 2/4 and 3/8 is ">".
According to the transitive property of inequality which states that if a > b and b > c then a > c, if 4/8 > 3/8 and 2/4 is equal to 4/8, then 2/4 > 3/8.
It takes 37 pounds of seed to completely play a 4 acre field how many acres can be planted per pound of seed
find the sum of the first 13 terms in the series -5+1+7...+67
The length of a rectangle is twice the width. If the perimeter of the rectangle is 60 units, find the area of the garden.
Set the following: Length = L Width = W
The length is twice the width: L = 2*W or: W = L/2
Perimeter: P = 60ft = 2*L + 2*W
Substituting L for W in the perimeter equation gives:
P = 60ft = 2*L + 2*(L/2) = 2*L + L = 3L
L = 60ft/3 = 20ft W=L/2=20ft/2=10ft
Verify result: Perimeter= P = 60ft = 2L + 2W = 2*20ft +2*10ft = 40ft+20ft = 60ft
The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft)^2
Hopefully This Helps!!
Final answer:
To find the area of a rectangle when the perimeter is given, determine the dimensions using the relationship between length and width and then calculate the area. In this case, the area of the garden is 200 square units.
Explanation:
The length of a rectangle is twice the width. If the perimeter of the rectangle is 60 units, find the area of the garden.
Let the width of the rectangle be x. Therefore, the length is 2x.
The perimeter of a rectangle is given by 2(length + width), which in this case is 2(2x + x) = 60 units.
Solving for x, we get x = 10. Therefore, the width is 10 units and the length is 20 units. The area of the garden is length x width = 20 x 10 = 200 square units.
Circle the ordered pairs that are solutions to the inequality y - 2x < - 1.
(1, 0)
(0, 1)
(0, -1)
(-1, 0)
(3, 2)
(-2, -4)
(2, 4)
(-4, 2)
(0, 0)
Please help!
3(x+1)-2(3x+7) i need help with this question
Density practice
A gas tank hold 50L. If the density of gasoline is 0.7 g/ml how much mass will the tank of gas have
Pat has nine cards. Frank has two more cards than Steve. Steve has 3 cards how many more cards does Pat have than Frank?
Based on the information given, Pat has 4 more cards than Frank.
The number of cards that Pat has = 9 cards
Number of cards that Steve has = 3 cards
Since Frank has two more cards than Steve, the total number of cards that Frank has will be: = 3 + 2 = 5
In order to know the number of cards that Pat has more than Frank, we will have to calculate the difference between the cards that they've. This will be:
= Pat's card - Frank's card
= 9 - 5
= 4
Therefore, Pat has 4 more cards than Frank.
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The Leukemia and Lymphoma Society sponsors a 5k race to raise money. It receives $55 per race entry and $10,000 in donations, but it must spend $15 per race entry to cover the cost of the race.
Write and solve an inequality to determine the number of race entries the charity needs to raise at least $55,000
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Calvin Butterball is driving along the highway. He starts up a long, straight hill. 114 meters from the bottom of the hill Calvin's car runs out of gas. He doesn't put on the brakes, so the car keeps rolling for awhile, coasts to a stop, then start rolling backwards. He finds that his distances from the bottom of the hill 4 and 6 seconds after he runs out of gas are 198 and 234 meters, respectively. b.Write an equation expressing Calvin's distance from the bottom of the hill in terms of the number of seconds which have elapsed since he ran out of gas.
Final answer:
To determine Calvin's distance from the bottom of the hill in terms of the number of seconds since running out of gas, we can use the equation of motion for uniformly accelerated motion.
Explanation:
To write an equation expressing Calvin's distance from the bottom of the hill in terms of the number of seconds that have elapsed since he ran out of gas, we can use the equation of motion for uniformly accelerated motion.
Calvin's initial position at 0 seconds is 114 meters, and his final position at 4 seconds is 198 meters. Plugging these values into the equation:
d = vi x t + 0.5 x a x t²
we can solve for the acceleration, a:
a = (d - vi x t) / (0.5 x t²)
Substituting the values of d = 198m and t = 4s, we get:
a = (198m - 114m) / (0.5 x (4s)²)
After obtaining the acceleration, we can use the equation to find Calvin's distance from the bottom of the hill at any time after running out of gas.
Write using algebra.
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PLease help ME!!!!!!!!!!!!!!!!!!
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i hope this helps
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A ball always bounces to 3/5 of the height from which it falls. It falls from a height of 1meter how high will it rise after the second bounce?
After the second bounce, the ball will rise to a height of 0.36 meter.
Explanation:To find the height the ball will rise after the second bounce, we can use the given information that the ball always bounces to 3/5 of the height from which it falls. In this case, the ball falls from a height of 1 meter.
For the first bounce, the ball rises to 3/5 of 1 meter, which is 0.6 meter. For the second bounce, the ball will rise to 3/5 of 0.6 meter. To calculate this, we multiply 3/5 by 0.6 meter, which gives us 0.36 meter.
Therefore, after the second bounce, the ball will rise to a height of 0.36 meter.