The answer is inertia
Answer: INERTIA
Explanation:
From newton first law, A body will continue to be in a state of constant motion unless being acted upon by an external force. Example passengers in a moving vehicle will tend to resist motion during stoppage of the car due to a tendency to want to continue in motion.
Electrons in a photoelectric-effect experiment emerge from a copper surface with a maximum kinetic energy of 1.10 eV. What is the wavelength of the light?
The photoelectric effect consists of the emission of electrons (electric current) that occurs when light falls on a metal surface under certain conditions.
If the light is a stream of photons and each of them has energy, this energy is able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.
This is what Einstein proposed:
Light behaves like a stream of particles called photons with an energy
[tex]E=h.f[/tex] (1)
So, the energy [tex]E[/tex] of the incident photon must be equal to the sum of the Work function [tex]\Phi[/tex] of the metal and the kinetic energy [tex]K[/tex] of the photoelectron:
[tex]E=\Phi+K[/tex] (2)
Where [tex]\Phi[/tex] is the minimum amount of energy required to induce the photoemission of electrons from the surface of a metal, and its value depends on the metal.
In the case of Copper [tex]\Phi=4.7eV[/tex]
Now, applying equation (2) in this problem:
[tex]E=4.7eV+1.10eV[/tex] (3)
[tex]E=5.8eV[/tex] (4)
Now, substituting (1) in (4):
[tex]h.f=5.8eV[/tex] (5)
Where:
[tex]h=4.136(10)^{-15}eV.s[/tex] is the Planck constant
[tex]f[/tex] is the frequency
Now, the frequency has an inverse relation with the wavelength [tex]\lambda[/tex]:
[tex]f=\frac{c}{\lambda}[/tex] (6)
Where [tex]c=3(10)^{8}m/s[/tex] is the speed of light in vacuum
Substituting (6) in (5):
[tex]\frac{hc}{\lambda}=5.8eV[/tex] (7)
Then finding [tex]\lambda[/tex]:
[tex]\lambda=\frac{hc}{5.8eV } [/tex] (8)
[tex]\lambda=\frac{(4.136(10)^{-15} eV.s)(3(10)^{8}m/s)}{5.8eV }[/tex]
We finally obtain the wavelength:
[tex]\lambda=213^{-9}m=213nm[/tex]
Calculate the drops per minute “gtts/min” for the following questions. Be sure to write your answer in gtts /min. 1. 250 ml/hour using macro tubing 20 gtts/ml _____________________ 2. 167 ml/hour using macro tubing 10 gtts/ml _____________________ 3. 125 ml/hour using macro tubing 15 gtts/ml _____________________ 4. 75 ml/hour using micro tubing 60 gtts/ml _____________________ 5. 250 ml/hour using macro tubing 20 gtts/ml _____________________ 6. 167 ml/hour using macro tubing 15 gtts/ml _____________________ 7. 125 ml/hour using macro tubing 10 gtts/ml _____________________ 8. 75 ml/hour using macro tubing 10 gtts/ml ______________________ 9. 1000 ml/hour using macro tubing 10 gtts/ml _____________________ 10. 500 ml/hour using macro tubing 10 gtts/ml _____________________
Answer:
Explanation:
There are 12 gtts in 1 mL, and 60 minutes in 1 hr.
250 mL/hr * (12 gtts / mL) * (1 hr / 60 min) = 50 gtts/min
167 mL/hr * (12 gtts / mL) * (1 hr / 60 min) = 33.4 gtts/min
125 mL/hr * (12 gtts / mL) * (1 hr / 60 min) = 25 gtts/min
75 mL/hr * (12 gtts / mL) * (1 hr / 60 min) = 15 gtts/min
1000 mL/hr * (12 gtts / mL) * (1 hr / 60 min) = 200 gtts/min
500 mL/hr * (12 gtts / mL) * (1 hr / 60 min) = 100 gtts/min
The table represent the thickness, top density, and bottom density of the different layers of the Earth. In most of the layers, the deeper the layer, the thicker and denser the layer becomes. Thickness (km) Density (g/cm3) Types of Rock Found Top Bottom Crust 30 2.2 2.9 Silicic rocks Upper mantle 720 3.4 4.4 Peridotite Lower mantle 2,171 4.4 5.6 Magnesium and silicon oxides Outer core 2,259 9.9 12.2 Iron+oxygen Inner core 1,221 12.8 13.1 Iron+oxygen At which location in Earth’s interior exhibits a change in the trend? inner core outer core lower mantle upper mantle
Answer:inner core?
Explanation:
Answer: your answer would be inner core hope it helps
Explanation:
tell me i am wrong?
(please help me)
If a wave has a wavelength of 13 meters and a period of 0.005, what's the velocity of the wave?
A. 260 m/s
B. 1,300 m/s
C. 2,600 m/s
D. 1,560 m/s
(please dont type any wrong answer on porpuse)
Answer:2,600 m/s
Explanation:13/ 0.005=2,600.
ANSWER:
The velocity of the wavelength is [tex]2600 \mathrm{m} / \mathrm{s}[/tex]
Explanation:
Given:
The wavelength of the wave= 13 meters
Time period of the wave=0.005seconds
To find:
velocity of the wave=?
Solution:
The velocity of the wave is defined as the product of frequency and wavelength.
Mathematically,
[tex]v=f \lambda[/tex]
Where f is the frequency and λis the wavelength of the wave.
Finding the frequency using time period,
[tex]f=\frac{1}{T}[/tex]
Substituting the value of time period we have,
[tex]f=\frac{1}{0.005}[/tex]
[tex]f=200 \mathrm{Hz}[/tex]
Now,
[tex]v=f \lambda[/tex]
[tex]v=200 \times 13[/tex]
[tex]v=2600 \mathrm{m} / \mathrm{s}[/tex]
Result:
The velocity of the wave with wavelength 13 meters and time period 0.005seconds is [tex]2600 \mathrm{m} / \mathrm{s}[/tex].
Technician a says in a parallel circuit, the more branches that are added, the more current flow increases. technician b says a series-parallel circuit is made of parallel branches only. who is correct?
Technician-A is correct. His statement: "In a parallel circuit, the more branches that are added, the more current flow increases." is technically true.
Technician-B is incorrect. His statement: "A series-parallel circuit is made of parallel branches only." is technically false.
The more branches a parallel circuit has the more current flow in the circuit therefore ; Technician A is correct while Technician B is wrong
In a parallel circuit the increase in branches will lead a corresponding increase in the amount of current flow through the circuit because the Total amount of current flowing through a parallel circuit is a summation of the individual currents flowing through the branches
i.e. [tex]I_{T} = I_{1} + I_{2} + I_{3}[/tex]
But A series-parallel circuit is made up of both parallel and series branches as the name implies therefore Technician B is wrong
Hence we can conclude that the more branches a parallel circuit has the more current flow in the circuit hence Technician A is correct.
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The Kinetic Molecular Theory of Gases Learning Goal To understand some aspects of molecular motion in the gas phase The kinetic molecular theory of gases explains how gas molecules behave in terms of motion, speed, and energy One important aspect of this theory deals with the relationship between temperature and the average speed of the gas molecules. Increasing the temperature of a gas sample increases the average kinetic energy of the molecules. The kinetic energy of a molecule determines its speed It is important to realize that not all molecules in a sample will have the same kinetic energy, which is why we refer to the average kinetic energy and the average speed. The speed of a particle with average kinetic energy is called the root mean square (rms) speed, vrms The rms speed may be expressed by the following equation: vrms=√3RT/MWhere R is the ideal gas constant, T is the absolute temperature, and M is the molar mass of the substance in kilograms per mole The constant motion of gas molecules causes diffusion and effusion. Diffusion is the gradual mixing of two substances resulting from the movement of their particles. Effusion is the gradual escape of gas molecules through microscopic holes in their container. Part A Which of the following state ments are true? Check all that apply The average kinetic energy of gas molecules increases with increasing temperature There are gas molecules that move faster than the average The temperature of a gas sample is independent of the average kinetic energy The average speed of gas molecules decreases with decreasing temperature All the gas molecules in a sample cannot have the same kinetic energy
Answer:
The average kinetic energy of gas molecules increases with increasing temperature
There are gas molecules that move faster than the average
The average speed of gas molecules decreases with decreasing temperature
All the gas molecules in a sample cannot have the same kinetic energy
Explanation:
The average kinetic energy of the particles in an ideal monoatomic gas is given by:
[tex]E_k = \frac{3}{2}kT[/tex] (1)
where
k is the Boltzmann constant
T is the absolute temperature of the gas
While the rms speed of the particles in a gas is given by
[tex]v_{rms}= \sqrt{\frac{3RT}{M}}[/tex] (2)
where
R is the gas constant
T is the absolute temperature
M is the molar mass
Let's now analyze each statement:
- The average kinetic energy of gas molecules increases with increasing temperature --> TRUE. If we look at eq.(1), we see that the average kinetic energy is directly proportional to the temperature.
- There are gas molecules that move faster than the average --> TRUE. The distribution of the speed of the particles in a gas is spread around the rms speed, but of course not all the particles are moving at that speed: some particles are moving faster, while some are moving slower.
- The temperature of a gas sample is independent of the average kinetic energy --> FALSE. As we see from eq.(1), the two quantities are related to each other.
- The average speed of gas molecules decreases with decreasing temperature --> TRUE. As we see from eq.(2), the average speed is proportional to the square root of the temperature: so, when the temperature decreases, the average speed decreases as well.
- All the gas molecules in a sample cannot have the same kinetic energy --> TRUE. In fact, each particle will have a different kinetic energy, depending on its speed (different speed means also different kinetic energy).
The Kinetic Molecular Theory denotes that with an increase in temperature, the average kinetic energy and speed of gas molecules also increase. Gas molecules can move faster or slower than the average speed, hence all molecules will not have the same kinetic energy. The temperature of a gas is not independent of the average kinetic energy.
Explanation:The Kinetic Molecular Theory of gases explains some key aspects of molecular motion within gases. The theory denotes that molecules are constantly in motion and the average speed of these molecules is determined by their absolute temperatures. As the temperature increases, so too does the average kinetic energy of the molecules, which in turn increases their speed.
Not all molecules in a gas sample will have the same kinetic energy; some will move faster than the average speed and others slower, lending to what we refer to as the average kinetic energy and average speed. The typical or root mean square (rms) speed of a particle with average kinetic energy can be expressed using the equation: vrms=√3RT/M, where R is the ideal gas constant, T is the absolute temperature, and M is the molar mass.
Moving on towards the state comparisons, the following statements are true: The average kinetic energy of gas molecules increases with increasing temperature; gas molecules can indeed move faster than the average speed; with a decrease in temperature, the average speed of the gas molecules decreases; all the gas molecules in a sample do not possess the same kinetic energy. The statement that classifies temperature of a gas sample as independent of the average kinetic energy is false.
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Which of the following is the best paraphrasing of the Heisenberg uncertainty principle?
(a) Only if you know the exact position of a particle can you know the exact momentum of the particle.
(b) The larger the momentum of a particle, the smaller the position of the particle.
(c) The more precisely you know the position of a particle, the less well you can know the momentum of the particle.
(d) The better you know the position of a particle, the better you can know the momentum of the particle.
(e) How well you can determine the position and momentum of a particle depends on the particle’s quantum numbers.
The Heisenberg uncertainty principle was enunciated in 1927. It postulates that the fact that each particle has a wave associated with it, imposes restrictions on the ability to determine its position and speed at the same time.
In other words:
It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.
So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity.In fact, even with the most precise devices, the uncertainty in the measurement continues to exist. Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.
Therefore the correct option is C.
The circular but relatively flat portion of the galaxy is the
The circular but relatively flat portion of the galaxy is the Disk
A galaxy that resembles a circle is known as a ring galaxy. Art Hoag's 1950 discovery of Hoag's Object is an illustration of a ring galaxy. Many big, relatively young blue stars that are quite brilliant can be found in the ring.
What circular but relatively flat portion of the galaxy?Galactic disks are thin, essentially circular collections of stars, gas, and dust; this matter revolves around a common core in almost circular orbits. As a result of this rotation, many disks have lovely spiral patterns, and some have distinct bars crossing their centres.
Nearly all of our galaxy's gas, dust, hot young stars, and star-forming regions are present there. When viewed from above, the disk reveals spiral arms that contain the majority of the ISM's cool, dense regions.
Therefore, Our galaxy's disk is incredibly narrow, only around 100 times wider than its own height.
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This is a map that shows hot spots around the world.
Which phrases describe the formation of the Hawaiian Islands? Check all that apply.
formed due to subduction
formed in the middle of a plate
formed at a divergent boundary
formed at a convergent boundary.
formed where mantle erupts through crust
Answer:
formed in the middle of a plate
formed where mantle erupts through crust
Explanation:
The Hawaiian Islands are Volcanoes that formed right in the middle of the Pacific plate which is moving North-westward.
Lithospheric plates lies on the weak and plastic asthenosphere. Such is the Pacific plate too. The weak asthenosphere can erupt on the surface if it gets access through faulting or other geologic conduits. When these mantle magma reaches the surface, they form hotpots on the crust.
The Hawaiian island is a series of these hotspot as it forms when mantle materials upwells to the surface. The hotspot from which the magma is sourced is relatively fixed. The moving plate is what leads to the eruption of the magma at several other parts in the crust.
Two disks with the same rotational inertia i are spinning about the same frictionless shaft, with the same angular speed ω, but with opposite angular velocities ~ω and −~ω. what is the total rotational kinetic energy kr of this system of two disks? 1. 1 2 i ω 2 2. zero 3. none of these
The total rotational kinetic energy of this system is : ( C ) none of these
Ker = Iw²
Determine the Total rotational kinetic energy
Given that the two disks have the same rotational inertia and the same angular speed but opposite angular velocities
w and -w
Total rotational kinetic energy ( Kr )
K.Er = K₁ + K₂
= [tex]\frac{1}{2} * Iw^2 + \frac{1}{2} * I (-w)^2[/tex]
= [tex]Iw^2[/tex]
Hence the total rotational kinetic energy of the system is : Iw²
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The total rotational kinetic energy of the system of two disks spinning with the same angular speed but in opposite directions is Kr = Iω², since the kinetic energy for both disks will be the same positive value when squared.
Given that both disks have the same rotational inertia (I) and angular speed (ω), we can calculate the total kinetic energy using the formula for rotational kinetic energy K = ½Iω² for each disk individually and then combine the results.
For the first disk with angular velocity ω:
K1 = ½Iω²
For the second disk with angular velocity -ω:
K2 = ½I(-ω)²
Since squaring a negative number yields a positive result, the kinetic energy for both disks will be positive and the same value.
Therefore, the total rotational kinetic energy is:
Kr = K1 + K2 = ½Iω² + ½Iω² = Iω²
What type of galaxy is M82 based on its appearance in the visible-light view?
A) elliptical
B) spiral
C) irregular Part
According to Hubble galaxies are classified into elliptical, spiral and irregular.
It should be noted this classification is based only on the visual appearance of the galaxy, and does not take into account other aspects, such as the rate of star formation or the activity of the galactic nucleus.
The classification is as follows:
1. Elliptical galaxies: Their main characteristic is that the concentration of stars decreases from the nucleus, which is small and very bright, towards its edges. In addition, they contain a large population of old stars, usually little gas and dust, and some newly formed stars.
2. Spiral galaxies: They have the shape of flattened disks containing some old stars and also a large population of young stars, enough gas and dust, and molecular clouds that are the birthplace of the stars.
3. Irregular Galaxies: Galaxies that do not have well-defined structure and symmetry.
In this context, galaxy M82 does not match with the first two types of galaxies, because it has not a defined shape.
Therefore, M82 is an irregular galaxy.
Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals. Which term do scientist use to describe these orbits
Answer:
It is most likely the word elliptical.
Explanation:
Usually the term elliptical refers to the oval-like shape of a substance or path of an object. The question states, "Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals." Because the planets orbit around the sun in an oval-like path, those orbits can be described as elliptical. Scientists also normally use this word to describe the same thing; Therefore, your answer is elliptical.
Planets in our solar system do not revolve around the sun in perfect circles. They revolve in the elliptical orbits.
What is the solar system?The solar system consists of the planet's satellites, as well as numerous comets, asteroids, and meteoroids, as well as the interplanetary medium.
Planets in our solar system do not revolve around the sun in perfect circles. They revolve in the elliptical orbits.
Hence, option D is correct.
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An object is placed 50 cm from a concave mirror of radius 70 cm. (a)What is the distance of the image from the mirror? (b) What is the lateral magnification of the image? Show your work and provide units of measure for each answer.
See the attached picture:
Determine which type of property each statement describes by typing "physical" or "chemical" in the blank. Hydrogen is a colorless, tasteless, and odorless gas. Hydrogen is very combustible in the presence of oxygen. Hydrogen is very reactive with most elements. Hydrogen is the least dense of all elements.
physical:1.Hydrogen is a colorless,tasteless and odourless gas.2.Hydrogen is the least dense of all elements.
chemical:1.hydrogen is very combustible in the presence of oxygen.2.hydrogen is very reactive with most elements.
Answer: Hydrogen is a colorless, tasteless, and odorless gas : Physical property
Hydrogen is very combustible in the presence of oxygen: Chemical property
Hydrogen is very reactive with most elements : Chemical property
Hydrogen is the least dense of all elements: Physical property
Explanation:
Chemical property is defined as the property of a substance which is observed during a reaction where the chemical composition identity of the substance gets changed.
Physical property is defined as the property which can be measured and whose value describes the state of physical system. For Example: State, density etc.
Hydrogen is a colorless, tasteless, and odorless gas is a physical property.
Hydrogen is very combustible in the presence of oxygen is a chemical property.
Hydrogen is very reactive with most elements is a chemical property.
Hydrogen is the least dense of all elements is a physical property.
During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun. Answer all questions to 3 significant figures. (a) What force is exerted by the Sun on the Moon? WebAssign will check your answer for the correct number of significant figures. Incorrect: Your answer is incorrect. Enter a number. (b) What force is exerted by the Earth on the Moon? WebAssign will check your answer for the correct number of significant figures. (c) What force is exerted by the Sun on the Earth? WebAssign will check your answer for the correct number of significant figures.
(a) [tex]4.40\cdot 10^{20}N[/tex]
The distance between the Sun and the Earth is
[tex]d_{SE}=1.496 \cdot 10^11 m[/tex]
The distance between the Earth and the Moon is
[tex]d_{EM} = 3.84\cdot 10^8 m[/tex]
So, the distance between the Sun and the Moon, when the Moon is between the Earth and the Sun, is
[tex]d_SM = 1.496\cdot 10^{11}m -3.84\cdot 10^8 m=1.492\cdot 10^{11} m[/tex]
So the gravitational force between the Sun and the Moon is
[tex]F_{SM} = G \frac{M_S M_M}{d_{SM}^2}[/tex]
where
G is the gravitational constant
[tex]M_S = 1.988 \cdot 10^{30}kg[/tex] is the mass of the Sun
[tex]M_M = 7.384\cdot 10^{22}kg[/tex] is the mass of the Moon
[tex]d_{SM}=1.492\cdot 10^{11} m[/tex] is their distance
Substituting,
[tex]F_{SM} = (6.67\cdot 10^{-11}) \frac{(1.988\cdot 10^{30} kg)(7.384\cdot 10^{22}kg)}{(1.492\cdot 10^{11} m)^2}=4.40\cdot 10^{20}N[/tex]
(b) [tex]2.00\cdot 10^{20}N[/tex]
The gravitational force between the Earth and the Moon is
[tex]F_{EM} = G \frac{M_E M_M}{d_{EM}^2}[/tex]
where
G is the gravitational constant
[tex]M_E = 5.972 \cdot 10^{24}kg[/tex] is the mass of the Earth
[tex]M_M = 7.384\cdot 10^{22}kg[/tex] is the mass of the Moon
[tex]d_{EM}=3.84\cdot 10^{8} m[/tex] is their distance
Substituting,
[tex]F_{EM} = (6.67\cdot 10^{-11}) \frac{(5.972\cdot 10^{24} kg)(7.384\cdot 10^{22}kg)}{(3.84 \cdot 10^{8} m)^2}=2.00\cdot 10^{20}N[/tex]
(c) [tex]3.54\cdot 10^{22}N[/tex]
The gravitational force between the Earth and the Sun is
[tex]F_{ES} = G \frac{M_E M_S}{d_{ES}^2}[/tex]
where
G is the gravitational constant
[tex]M_E = 5.972 \cdot 10^{24}kg[/tex] is the mass of the Earth
[tex]M_S = 1.988 \cdot 10^{30}kg[/tex] is the mass of the Sun
[tex]d_{SE}=1.496 \cdot 10^{11} m[/tex] is their distance
Substituting,
[tex]F_{ES} = (6.67\cdot 10^{-11}) \frac{(5.972\cdot 10^{24} kg)(1.988\cdot 10^{30}kg)}{(1.496 \cdot 10^{11} m)^2}=3.54\cdot 10^{22}N[/tex]
To derive the force exerted by the Sun on the Moon the Earth on the Moon and the Sun on the Earth during a solar eclipse, you apply Newton's law of universal gravitation taking into account the respective masses of the Sun, Earth, and Moon as well as their distances from each other.
Explanation:Determining the force exerted between celestial bodies during a solar eclipse involves understanding the gravitational relationship between them; primarily the gravitational forces between the Earth, Moon, and the Sun, and the principles of celestial mechanics.
Firstly, we know that the force of gravity follows Newton's law of universal gravitation: F = G (m1m2/r^2),where F is the force of gravity, m1 and m2 are the masses of the two bodies involved, r is the distance between the centers of the two bodies, and G is the gravitational constant.
For any of the specific forces asked in the question (i.e., the force exerted by the Sun on the Moon force exerted by the Earth on the Moon, and the force exerted by the Sun on the Earth), we would need specific values for the masses of the Sun, Earth, and Moon as well as their respective distances. Once those values are known, you can substitute into the above equation to obtain the force.
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Calculate the energy of a photon having a wavelength in thefollowing ranges.
(a) microwave, with λ = 50.00 cm
eV
(b) visible, with λ = 500 nm
eV
(c) x-ray, with λ = 0.50 nm
eV
The energy [tex]E[/tex] of a photon is given by the following formula:
[tex]E=h.f[/tex] (1)
Where:
[tex]h=4.136(10)^{-15}eV.s[/tex] is the Planck constant
[tex]f[/tex] is the frequency
Now, the frequency has an inverse relation with the wavelength [tex]\lambda[/tex]:
[tex]f=\frac{c}{\lambda}[/tex] (2)
Where [tex]c=3(10)^{8}m/s[/tex] is the speed of light in vacuum
Substituting (2) in (1):
[tex]E=\frac{hc}{\lambda}[/tex] (3)
Knowing this, let's begin with the answers:
(a) Microwave: 50.00 cmFor [tex]\lambda=50cm=0.5m[/tex]
[tex]E=\frac{(4.136(10)^{-15} eV.s)(3(10)^{8}m/s)}{0.5m}[/tex]
[tex]E=\frac{1.24(10)^{-6}eV.m }{0.5m}[/tex]
[tex]E=2.48(10)^{-6}eV[/tex]
(b) Visible: 500 nmFor [tex]\lambda=500nm=500(10)^{-9}m[/tex]
[tex]E=\frac{(4.136(10)^{-15} eV.s)(3(10)^{8}m/s)}{500(10)^{-9}m}[/tex]
[tex]E=\frac{1.24(10)^{-6}eV.m }{500(10)^{-9}m}[/tex]
[tex]E=2.48 eV[/tex]
(c) X-ray: 0.5 nmFor [tex]\lambda=0.5nm=0.5(10)^{-9}m[/tex]
[tex]E=\frac{(4.136(10)^{-15} eV.s)(3(10)^{8}m/s)}{0.5(10)^{-9}m}[/tex]
[tex]E=\frac{1.24(10)^{-6}eV.m }{0.5(10)^{-9}m}[/tex]
[tex]E=2480 eV[/tex]
As we can see, as the wavelength decreases, the energy increases.
When humans look at the sky, it appears blue, but the Sun appears yellow. What causes this phenomenon?
Light behaves like a wave, and the different colors we perceive are the result of light hitting our eyes at different wavelengths. The air molecules in our atmosphere scatter this visible light, with a "preference" towards light of shorter wavelengths -- blue and violet light. Light of longer wavelengths (green, yellow, orange, red), doesn't pass through to us as visibly until later in the day, when the sun's light has more atmosphere to pass through before it reaches our eyes. The blue light becomes so scattered by the air molecules in its way at this point that we're finally able to see those yellows and reds coming through on our end.
What can engineers do to prevent structures from collapsing
Explanation:
that don't look bright
The electrical force between two objects 36N. If the distance between the two objects is doubled the force between them will be
Answer:
The electrical force is 9N
Explanation:
For point loads, charged bodies very small compared to the distance r that separates them, Coulomb discovered that the electric force is proportional to [tex]\frac{1}{r^{2}}[/tex]. So, if the distance is doubled, the force will decrease a [tex]\frac{1}{4}[/tex] of its initial value.
[tex]F=\frac{36N}{4}=9N[/tex]
When the distance between two charged objects is doubled, the electrostatic force between them becomes one-fourth of the original force. Thus, if the original force is 36 N, the new force would be 9 N.
Explanation:The force between two charges is governed by Coulomb's Law, which states that the electrostatic force (F) between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance (r) between them. The law is mathematically expressed as F = k * (|q1*q2|) / r², where k is Coulomb's constant. If the distance between two charges is doubled, since the force is inversely proportional to the square of the distance, the new force will be one-fourth of the original force.
Thus, if the initial force is 36 N and the distance is doubled, the new force is calculated as:
Initial force: 36 N
New distance: 2r
New force (F') = F / (22) = 36 N / 4 = 9 N
Therefore, the new electrostatic force between the two objects when the distance is doubled would be 9 N.
Positively-charged particles consisting of two protons and two neutrons emitted by radioactive materials are
A) beta particles.
Eliminate
B) gamma particles.
C) alpha particles.
D) positron particles
Answer:
The answer to your question is Alpha particles.
Explanation: An electron released by a radioactive nucleus that causes a neutron to change into a proton is called a beta particle.
Final answer:
The question refers to alpha particles, which consist of two protons and two neutrons and are symbolized by He or the Greek letter α. Alpha particles carry a positive charge and result in the atomic number decreasing by two and the mass number by four following emission.
Explanation:
The positively-charged particles emitted by radioactive materials that consist of two protons and two neutrons are known as alpha particles. These particles are the equivalent of a helium nucleus and carry a positive charge due to the protons. The atomic symbol for an alpha particle is either He or the Greek letter α, and this type of radioactive emission results in the reduction of the atomic number by two and the mass number by four. For example, when uranium-238 undergoes alpha decay, it emits an alpha particle and transforms into thorium-234.
In contrast, beta particles are electrons with a 1- charge and are represented as e or β. The emission of a beta particle results in the conversion of a neutron to a proton within the nucleus, increasing the atomic number by one without changing the mass number. Gamma rays, on the other hand, are high-energy electromagnetic radiation with no mass and hence are not particles. Lastly, positron particles are positively charged electrons (anti-electrons) and have negligible mass.
Vector A has a magnitude of 50 units and points in the positive x direction. A second vector, B , has a magnitude of 120 units and points at an angle of 70 degrees below the x axis.
Part A
Which vector has the greater x component.
Part B
Which vector has the greater y component?
Vector A has the greater x-component, while vector B has the greater y-component.
Explanation:The x-component of a vector can be calculated by multiplying its magnitude by the cosine of the angle it makes with the x-axis. For vector A, the x-component is 50 units (since it lies entirely on the x-axis). For vector B, the x-component equals 120 units * cos(70 degrees) = 40.96 units. So, vector A has the greater x-component.
The y-component of a vector can be calculated by multiplying its magnitude by the sine of the angle it makes with the x-axis. For vector A, the y-component is 0 (since it lies completely on the x-axis). For vector B, the y-component equals 120 units * sin(70 degrees) = 112.90 units. So, vector B has the greater y-component.
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A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. Calculate the specific heat capacity of iron.
Answer:
0.46 J/gC
Explanation:
The specific heat capacity of a material is given by:
[tex]C_s = \frac{Q}{m \Delta T}[/tex]
where
Q is the amount of heat absorbed
m is the mass
[tex]\Delta T[/tex] is the variation of temperature
For the piece of iron in the problem:
[tex]m = 15.75 g[/tex]
[tex]Q=1086.75 J[/tex]
[tex]\Delta T=175 C-25 C=150^{\circ}[/tex]
Substituting into the equation,
[tex]C_s = \frac{1086.75 J}{(15.75 g)(150^{\circ}C)}=0.46 J/gC[/tex]
Answer:
0.46 J/gC
Explanation:
The specific heat capacity of a material is given by:
where
Q is the amount of heat absorbed
m is the mass
is the variation of temperature
For the piece of iron in the problem:
Substituting into the equation,
Explanation:
Which type of tissue allows for cordination and control movement ?
The Nerve Tissue allows for coordination and control movement
Nervous tissue is used for coordination and control movement.
Explanation:
The group of organized cells that is in the nervous system, which is responsible in controlling the movements of the human body, sending and carrying signals to and from different body parts is called Nervous tissue. It is also responsible in controlling functions in the body like digestion.
This tissue is classified into categories such as neurons and neroglia. The electric impulses are transmitted by neurons and supporting and protecting neurons is done by neuroglia. The whole nervous system is comprised of neurons.
What do we mean by the event horizon of a black hole?
A) It is the place where X rays are emitted from black holes.B) It is the very center of the black hole.C) It is the point beyond which neither light nor anything else can escape.D) It is the distance from the black hole at which stable orbits are possible.
The correct answer is: C. It is the point beyond which neither light nor anything else can escape.
The event horizon of a black hole is the boundary where the escape velocity is equal to the speed of light, making it impossible for anything, including light, to escape. It's defined by the Schwarzschild radius and increases in size with additional mass. The center is thought to contain a singularity, which is infinitely dense and small.
Explanation:The event horizon of a black hole is the boundary beyond which nothing, including light, can escape its gravitational pull. It corresponds to the distance at which the escape velocity equals the speed of light. This boundary is known as the Schwarzschild radius, which is directly proportional to the mass of the black hole. The event horizon is not visible because it does not emit any light; however, it can be inferred by observing the effects of its powerful gravity on nearby matter and radiation.
The size of the Schwarzschild radius (and therefore the event horizon) depends only on the mass of the black hole. If our Sun were to collapse into a black hole, which is purely a theoretical scenario since it lacks sufficient mass, its Schwarzschild radius would be approximately 3 kilometers. Any additional mass added to the black hole would increase the size of its event horizon proportionally.
Inside the event horizon, the center of the black hole is thought to contain a singularity, a point of infinite density and zero volume, which is not directly observable. As matter crosses the event horizon, it seems to freeze in position to an outside observer due to the extreme gravitational effects on lt's travel, but would, in reality, continue to fall inward toward the singularity.
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What nuclear reaction is the energy source of a white dwarf?
Answer:
Multiple choice answer would be "None"
Explanation:
White dwarfs are radiating stored heat from earlier reactions.
Technically, it would be the last fusion stage the star went through
BEFORE it became a white dwarf, but that's nit-picking.
The energy source of a white dwarf is not a nuclear reaction in the traditional sense, but rather it is supported by a process called electron degeneracy pressure.
What is a white dwarfA white dwarf is the remnant of a low to medium-mass star (up to about 1.4 times the mass of the Sun) after it has exhausted its nuclear fuel. The core of the star collapses under gravity, and the electrons in the core become packed extremely closely together due to the Pauli exclusion principle, which states that no two electrons can occupy the same quantum state simultaneously.
This electron degeneracy pressure provides the counterforce to gravity, preventing further collapse. No nuclear reactions are occurring in a white dwarf as it no longer has the high temperatures and pressures required for nuclear fusion. Instead, it is a stellar remnant that is gradually cooling over time.
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Two identical metal bars are heated up until they are both glowing. One of them is "red hot" and the other is "blue hot." Which one is hotter, the one that glows red or the one that glows blue?A) the red oneB) the blue oneC) We cannot tell without knowing more about the two bars.
Answer:
B) the blue one
Explanation:
We can assimilate each metal bar to a black body. The peak wavelength of the radiation emitted by a blackbody is given by Wien's displacement law:
[tex]\lambda = \frac{b}{T}[/tex] (1)
where
b is the Wien's displacement constant
T is the absolute temperature of the object
In this case, we have one object hotter and the other one colder. We see from (1) that the peak wavelength is inversely proportional to the temperature: therefore, the hotter object will have shorter peak wavelength, while the colder object will have longer peak wavelength.
Since red light has longer wavelength than blue light, we can conclude that the object that glows blue is hotter than the one that glows red.
Which characteristic is common to microwave radar, waves ,and television waves? A they are different types of waves with frequencies higher than radio waves B they are all radio waves with frequencies lower than visible light C they are all radio waves with wavelength shorter than visible light
Answer:
B they are all radio waves with frequencies lower than visible light
Explanation:
The electromagnetic spectrum classifies all the electromagnetic waves according to their frequency. In order from highest to lowest frequency, we have:
Gamma rays
X-rays
Ultraviolet
Visible light
Infrared
Microwaves
Radio waves
In particular, radio waves are the electromagnetic waves with lowest frequency (and longest wavelength), usually less than 300 GHz ([tex]300\cdot 10^9 Hz[/tex]).
Microwaves radar, radio waves and television waves are all examples of radio waves, which have frequencies lower than visible light. Radio waves are generally used for long-range communications, because given their long wavelength they are able to "bypass" huge obstacles like mountains or building, without being absorbed.
Answer:
B they are all radio waves with frequencies lower than visible light
Explanation:
A metal sphere is neutral because it has an equal number of protons and electrons. Draw how the charges in the sphere are redistributed when a negatively charged rod is brought near it.
Answer:
The protons will shift towards the negatively charged rod and the electrons will shift away
Explanation:
When negatively charged rod is brought near it , in sphere protons ( positively charge ) get attracted on the surface and electron get away (negatively charge) due to induction
What is meant by charging by induction ?
Charging by induction is a process by which a neutral body can be charged electrostatically in the presence of a negatively or positively charged body.
Whenever a charged body is placed over a neutral conducting material that conducting material will induce an opposite charge to the charged body because of induction . Example : if charged body have positive charge than conducting material will induce a negative charge on it
hence , when negatively charged rod is brought near it , in sphere protons ( positively charge ) get attracted on the surface and electron get away (negatively charge) due to induction
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In an isobaric compression of an ideal gas
a. no heat flows into gas.
b. the internal energy of the gas remains constant
c. no work is done on the gas
d. work is done on the gas
e. work is done by the gas
Answer:
d. Work is done on the gas
Explanation:
We are considering an isobaric compression, which means:
- Isobaric: the pressure of the gas is constant
- Compression: the volume of the gas is decreasing
For an isobaric compression, the volume done BY the gas is
[tex]W=p \Delta V= p (V_f -V_i)[/tex]
where
p is the gas pressure
[tex]V_f[/tex] is the final volume of the gas
[tex]V_i[/tex] is the initial volume of the gas
If the sign of W is positive, it means that the gas is doing work on the surrounding; if the sign of W is negative, it means that the surrounding is doing worn ON the gas.
In this case, since it is a compression, we have that the final volume is smaller than the initial volume:
[tex]V_f < V_i[/tex]
Therefore, the sign of W is negative, and therefore work is done ON the gas by the surroundings.
Final answer:
In an isobaric compression, work is done on the gas by the force exerted on the movable piston.
Explanation:
In an isobaric compression of an ideal gas,(option d) work is done on the gas. This means that energy is transferred to the gas through mechanical work. To understand this, let's consider a piston-cylinder system.
During an isobaric compression, the gas is compressed while the pressure remains constant. The gas particles push against the piston, causing it to move, and thus work is done on the gas.
This work is done by the force exerted on the movable piston, which causes a displacement. As a result, the volume and temperature of the gas decrease, indicating that the gas's internal energy has been decreased by doing work.
Use the following half-life graph to answer the following question:
A graph titled half-life graph of a radioactive isotope is shown with mass remaining on the y axis from 0 to 60 grams and time on the x axis from o to 6 minutes. A curve connects the points 0, 50 and 1, 25 and 2, 12.5 and 3, 6.25 and 4, 3.125 and 5, 1.5625.
The graph is attached.
What is the half-life of the isotope? (5 points)
A. 1.0 min
B. 3.0 min
C. 5.0 min
D. 6.0 min
Answer:
A 1.0 min
Explanation:
The half-life of a radioisotope is defined as the time it takes for the mass of the isotope to halve compared to the initial value.
From the graph in the problem, we see that the initial mass of the isotope at time t=0 is
[tex]m_0 = 50.0 g[/tex]
The half-life of the isotope is the time it takes for half the mass of the sample to decay, so it is the time t at which the mass will be halved:
[tex]m'=\frac{50.0 g}{2}=25.0 g[/tex]
We see that this occurs at t = 1.0 min, so the half-life of the isotope is exactly 1.0 min.
Answer:a
Explanation:test