Answer:
the answer is a
Explanation:
just took the test
Scientific models A. help to predict future events B. Prove that an object exists C.determine the distance to far off stars D. Show that the scientific method works
what best describes the degree to which a material can transmit heat
- melting point
- boiling point
- thermal conductivity
- electrical conductivity
Answer:
thermal conductivity
NEED HELP ASAP IF I FAIL THIS ONE I GET A F
If you want to cause an object to move, what should you do?
a Apply balanced forces.
b Apply neutral forces.
c Apply potential forces.
d Apply unbalanced forces.
Which of the following has mechanical energy? Car battery Compressed spring Glowing incandescent lightbulb Nucleus of uranium atom
Answer:
the correct answer is the lightbulb
Explanation:
i took the assighnment and got it correct
what are two pieces of information that the sunscreen manufacturer might include on the label to help you decide if thhe sunscreen will be effective
The elements helium, neon, and xenon are all part of the same _____ on the periodic table.
A. Diagonal
B. Period
C. Row
D. Group
the answer is D.group
hope this helps
D. Group
Explanation:
Helium, Neon and Xenon are all located under the same column in the periodic table. Elements within the same column in the periodic table are said to be in the same group, because they share similar chemical property: this is due to the fact that they have the same number of valence electrons (number of electrons in the outest shell).
Helium, neon and xenon are said to be part of the 'noble gas group'. The main property of these elements is that they do not react with other elements, because they have the outest energy shell completely filled with electrons, so they do not give/accept electrons to other atoms to form chemical bonds.
A truck with 0.420 m radius tires travels at 32 m/s. What is the angular velocity of the rotating tires in radians per second? What is the angular velocity of the rotating tires in rev/min?
Answer : [tex]\omega=76.19\ radians/second[/tex] and [tex]\omega=727.55\ rev/min[/tex]
Explanation :
It is given that,
The radius of the truck, r = 0.420 m
Velocity of the truck, v = 32 m/s
We have to find the angular velocity of the rotating tires.
The relation between the angular velocity and the linear velocity is :
[tex]v=r\omega[/tex]
[tex]\omega[/tex] is the angular velocity
[tex]\omega=\dfrac{v}{r}[/tex]
[tex]\omega=\dfrac{32\ m/s}{0.420\ m}[/tex]
[tex]\omega=76.19\ radians/second[/tex]
We know that, 1 revolution = 2π radian
So, [tex]\omega=727.55\ rev/min[/tex]
Hence, this is the required solution.
As a wave travels through a medium, it displaces particles in a direction parallel to the motion of the wave. We can conclude this is a
Answer:longitudinal wave
Explanation:. A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves.
Our understanding of the Atom has changed over time. which idea that was once accepted is now considered scientifically inaccurate
Answer:
Explained
Explanation:
From Rutherford's alpha ray scattering experiment, we know that most of the spaces in an atom is empty. It is so because most of the alpha particles in that scattering experiment had gone Undeviated without any deflection from the positively charged nucleus.
Hence, atom can not be considered as a compact solid sphere, which was once considered by the J.J. Thomson.
How is sound detected by the brain? A.electromagnetic waves
B. Bones amplifying sound
C. Vibrations
D. Electrical impulses from the ear
8. How does inertia act on an object that is moving in a circle? A. It causes the object to speed up as it moves. B. It causes the object to move along a straight path. C. It directs the object toward the center of the curve.
Answer: its D
Explanation:
took on study island
you push a sled of mass 15 kg across the snow with a force of 180 N for a distance of 2.5 m. There is no friction. if the sled started at rest. what is the velocity of the sled after you push it?
The velocity of the sled after being pushed is determined through the application of the work-energy theorem, calculating the work done as the force times distance and equating this to the change in kinetic energy. This results in a velocity of approximately 7.9 m/s.
Explanation:The subject of this problem pertains to the area of physics known as kinematics, specifically the forces and acceleration involved when an object is set into motion. To solve this problem, we can utilize the work-energy theorem. The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy.
In this case, the work done is the force applied to the sled times the distance the sled is pushed or W = Fd. Substituting the given values into the equation, we get W = 180 N * 2.5 m = 450 Joules.
The work done on the sled results in a change in the sled's kinetic energy. The kinetic energy (KE) of an object is given by KE = 0.5*m*v^2, where m is the mass of the object and v is its velocity.
Setting the work equal to the change in kinetic energy (since the sled starts at rest, the change in kinetic energy is just its final kinetic energy), we get 450 J = 0.5*15 kg*v^2. Solving for v gives a velocity of approximately 7.9 m/s.
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3. After studying about recycling, members of John’s biology class investigated the effects of various recycled products on plant growth. John’s lab group compared the effect of different aged grass compost on bean plants. Because decomposition is necessary for the release of nutrients, the group hypothesized that older grass compost would produce taller bean plants. Three flats of bean plants (25 per flat) were grown for 5 days. The plants were then fertilized as follows: flat A = 450. g of 3 month old compost; flat B = 450. g of 6 month old compost; flat C = 0 g of compost. The plants received the same amount of sunlight and water each day. At the end of 30 days, the group recorded the height of the plants in cm.
Hypothesis:
Independent Variable:
Dependent Variable:
Constant (at least one):
Control:
Number of groups:
Number of trials per group:
A airplane travels 3260 kilometers in 4 hours. What is the airplane average speed?
Adding energy or increasing the speed of the particles at very low pressure in a solid would cause
A) boiling.
B) condensation.
C) melting.
D) sublimation.
What profession is most likely to make use of amphoras and candelas
Final answer:
The profession most likely to make use of amphoras and candelas is an archaeologist or historian.
Explanation:
The profession most likely to make use of amphoras and candelas is an archaeologist or historian.
Amphoras were large vessels used for shipping liquid goods in the Mediterranean world. They were essential for trade, transportation, and storage. Historians study past civilizations, including their economies and trade networks, and archaeologists excavate ancient sites, including tombs and graves, where they may find artifacts like amphoras.
Candelas, on the other hand, are units of luminous intensity used in lighting design and engineering. This profession may involve designing and using light fixtures, such as candelabras, which are candle holders that can provide both functional and aesthetic lighting.
What important attitudes do successful scientists possess?
Curiousity. - A scientist shows interest and pays particular attentions to objects or events.
Honesty. - A scientist gives a truthful report of observations.
Open-Mindedness. - A scientist listens to and respects the ideas of others
A(n) _____ is a mass of living protoplasm.
amoeba
paramecium
euglena
virus
Answer: The correct answer for the blank is-
amoeba.
Protoplasm is considered as the living part of cell, which includes cell membrane, cytoplasm, and the nucleus.
Amoeba ( it is a protozoan, which is a group of kingdom protista) is the simplest living form of unicellular eukaryotic organisms. It does not have any specified shape. All the cellular activities that are essential for its life, takes place in the protoplasm. As all the properties of protoplasm can be readily observed in this simple organic form ( Amoeba), therefore, it is considered as the mass of living protoplasm.
what is the total displacement of the car after five h?
0km
15km
20km
40km
The total displacement of the car after five hours - 0km.
Displacement -
Displacement is a vector quantity that refers to the object's overall change in position.change in final position from its initial positioncalculating the distance between an object's initial position and its final position.In physics terms, displacement is referred to as the variable s. The official displacement formula is as follows:s = sf – si.
where, s = displacement.
In the given graph there is a change in distance covered with the time that are:
after two hours it reaches 15 km away from the initial pointafter 4 hours car reaches 20 km away from the initial pointAfter 5 hours it returns back to the initial point.Thus, the displacement would be 0 km as the final point and initial point are the same.
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what creates an electric force field that moves electrons through a circuit ?
a. energy source
b. load
c. metal wires
d. resistance
Answer:
a. energy source
Explanation:
In a circuit, there is cell or battery. This is the energy source. The battery creates an electric force field which causes electrons to move through the circuit. The current moves from positive terminal to negative terminal of the battery.
Resistance opposes the current in the circuit. load is same as resistance. Metal wires are used to connect different components of a circuit.
Answer:
A is the correct answer!!
Explanation:
Have a great day :^)
Starting initially at rest at t=0, a subway car accelerates to 29 m/s over a period of 6 seconds, and then begins to brake. Forty-eight (total) seconds after starting, it is moving at 12 m/s . What is its average acceleration in this 48-s interval?
Can you help me with number 4 plz
How many places are there for electrons in the second shell of an atom?
Answer:
Eight electrons.Explanation:
An atom is composed by shells, each shell can contain a limited number of electrons. The first one can contain two electrons. The second shell contains up to eight electrons. The third shell contains up to 18.
There's a formula to calculate the number of electrons:
[tex]2(n^{2} )[/tex]
The x-coordinates of two objects moving along the x-axis are given as a function of time (t). x1= (4m/s)t x2= -(161m) + (48m/s)t - (4 m/s^2)t^2 Calculate the magnitude of the distance of closest approach of the two objects. x1 and x2 never have the same value.
To calculate the magnitude of the distance of closest approach of the two objects, we need to find the minimum distance between the x1 and x2 functions. The minimum distance occurs when the derivative of the difference between x1 and x2 is zero. We can find this point by equating the derivatives of x1 and x2 and solving for t.
Explanation:To calculate the magnitude of the distance of closest approach of the two objects, we need to find the minimum distance between the x1 and x2 functions. The minimum distance occurs when the derivative of the difference between x1 and x2 is zero. We can find this point by equating the derivatives of x1 and x2 and solving for t. Once we have the value of t, we can substitute it back into either x1 or x2 to find the minimum distance.
Take the derivative of x1 with respect to t: x1'(t) = 4 m/sTake the derivative of x2 with respect to t: x2'(t) = 48 m/s - 8 m/s^2 * tSet x1'(t) = x2'(t) and solve for t: 4 m/s = 48 m/s - 8 m/s^2 * tSolve the equation: t = 5 sSubstitute t=5s into x1 or x2 to find the minimum distance: x1(5s) = 20 mTherefore, the magnitude of the distance of closest approach of the two objects is 20 meters.
What is the value of -2 + 100 - (-50)?
What is one positive ecological impact of switching to biological farming?
Which value is equivalent to 178 centimeters?
1.78 millimeters
17.8 millimeters
1.78 meters
1.78 × 10-2 micrometers
1.78 × 10-5 kilometers
Answer:
1 centimetres = 10 millimetres
178 centimetres = 10 × 178 = 1780 millimetres
1 meters = 100 centimeters
178 centimeters = 178 ÷ 100 = 1.78 meters Plato answer
1 cm = 10 mm
1 mm = 1000 micrometers
1 cm = 10000 micrometers
178 cm = 178 × 10⁴ micrometers
1 kilometre = 1000 metres
1 metre = 100 cm178 cm = 178 ÷ 100 = 1.78 metres
1.78 metres = 1.78÷1000 = 1.78 × 10⁻³ kilometres
Explanation:
Exactly 3.0s after a projectile is fired into the air from the ground, it is observed to have a velocity v = (8.4 i^ + 4.9 j^)m/s, where the x axis is horizontal and the y axis is positive upward. Determine the horizontal range of the projectile. Determine its maximum height above the ground. Determine the speed of motion just before the projectile strikes the ground. Determine the angle of motion just before the projectile strikes the ground.
The problem requires understanding of projectile motion in Physics. One calculates multiple parameters of projectile's path by understanding vertical and horizontal motions independently. The given information can be used to calculate the horizontal range, maximum height, and angle of motion.
Explanation:The subject of this question involves understanding projectile motion. In physics, projectile motion is the motion of an object that is subject only to the acceleration of gravity. It involves two independent one-dimensional motions, one along the vertical axis and one along the horizontal axis.
To solve this problem, we observe the given initial vertical and horizontal velocities after a time 3.0s. Using the equations of motion, we can calculate different parameters asked in the question. The horizontal range of the projectile can be calculated by multiplying the horizontal velocity by the total time the projectile is in the air. The maximum height, speed of motion and the angle of motion just before the projectile strikes the ground can also be calculated using these principles.
Remember, the x and y motions in a projectile are independent, so we must handle them separately. The vertical motion will determine the total time spent in the air, and it will reach zero velocity at its highest point. The horizontal motion, under the absence of air resistance, remains constant.
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The horizontal range of the projectile is 25.2 m. The maximum height above the ground is 7.35 m. The speed of motion just before the projectile strikes the ground is 9.7 m/s. The angle of motion just before the projectile strikes the ground is 29.3 degrees.
Explanation:Using the given information, we can calculate the horizontal range, maximum height, speed of motion just before the projectile strikes the ground, and the angle of motion just before the projectile strikes the ground.
To determine the horizontal range, we need to find the time it takes for the projectile to reach the ground. Since the projectile is observed to have a velocity of (8.4 i^ + 4.9 j^) m/s after 3.0 seconds, we can assume that the time of flight is 3.0 seconds. The horizontal range is then given by multiplying the horizontal component of the velocity by the time of flight, which is R = vx * t = 8.4 m/s * 3.0 s = 25.2 m.
To determine the maximum height, we need to find the time it takes for the projectile to reach its peak. Since the projectile is at ground level initially and at its peak after 3.0 seconds, the time it takes to reach the peak is half of the total time of flight, which is t/2 = 3.0 s / 2 = 1.5 s. The maximum height above the ground is then given by multiplying the vertical component of the velocity at the peak by the time it takes to reach the peak, which is H = vy * t/2 = 4.9 m/s * 1.5 s = 7.35 m.
To determine the speed of motion just before the projectile strikes the ground, we can use the Pythagorean theorem to find the magnitude of the velocity vector. The speed of motion is given by the magnitude of the velocity vector, which is v = sqrt(vx^2 + vy^2) = sqrt((8.4 m/s)^2 + (4.9 m/s)^2) = 9.7 m/s.
To determine the angle of motion just before the projectile strikes the ground, we can use the inverse tangent function to find the angle. The angle of motion is given by the inverse tangent of the vertical component of the velocity divided by the horizontal component of the velocity, which is angle = tan^(-1)(vy / vx) = tan^(-1)(4.9 m/s / 8.4 m/s) = 29.3 degrees.
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Explain how the energy of a marble is transformed as it rolls down a ramp. Give evidence that energy of the marble remains the same at all points on the ramp.
Answer:
All the energy remains same actually.
Explanation: First, when it is dropped, it collects speed and kinetic energy, and also creates few amounts of sound and little thermal energy. For, example, you dropped the marble, and it rolled and bounced off towards the ramp. Take, it had 100 joules ( joule is the unit of energy, founded by scientist James Prescott Joule ). As it dropped, it created sound energy ( the clink sound ) and assume it had taken 50 joules. The rest are transformed to thermal and kinetic energy, assuming both energies took 25 joules. As it rolls down, it gains speed, gradually, and soon, it comes to halt in the ground by friction. Friction gives enough evidence as well as use of joules by sound, thermal and kinetic energies.
True or False? Facts and Figures are examples of variables? If it's false explain how you can fix it.