The vertex of the graph of a quadratic function is (–2, –9) and the y-intercept is (0, –5). Which of the following is the equation of the function? A. y = x2 +10x + 2 B. y = x2 +10x – 2 C. y = x2 – 2x – 5 D. y = x2 + 4x – 5
Answers
Related Questions
Find -8 ÷ 1/2 =
a.1/16
b.16
c.-1/4
d. -4
Answers
-8 / 1/2 =
B. -16
hope i helped
Question Down Below...
Answers
48÷12=4
5×4=20
First, you need to replace that empty space by a letter. As usual, we replace that empty space by x or y. I pick X :)
[tex] \frac{5}{12} = \frac{x}{48} Now, we do something called cross-multiply 12*x = 48 * 5 12x = 240 x = 240/12 x= 20 [/tex]
The missing number is 20
----------------------
We can check if we got the answer right. Replace the hole by 20
so it will be
5/12 = 20/48
when divided 5 by 12, it equals to 0.41
when we divided 20 by 48, it equals 0.41
So yes, 20 is the missing number.
I hope this helps you. Please let me know if you have more questions.
Best of luck!
A student has some 1 bills and $5 bills in his wallet. he has a total of 15 bills that are worth $47. how many of each type of bill does he have?
Answers
Total number of bills - 15
Total value of the bills - $47
Bills - $1 and $5
*Solution
Let:
x - number of $1 bills
y - number of $5 bills
1. The total number of bills comprising of $1 and $5 bills is 15. Thus,
x + y = 15 (EQUATION 1)
2. The total value of the bills is $47. Thus,
$1 (x) + $5 (y) = $47 (EQUATION 2)
3. There are 2 ways to solve this (system of linear equations) mathematically. You can use the elimination method or the substitution method. Using the elimination method to eliminate the variable x... (subtract Equation 1 from Equation 2)
1x + 5y = 47
_
x + y = 15
0 + 4y = 32
4. Thus, the value of y, which is the number of $5 bills is,
4y = 32
4 4
y = 8
5. The number of $1 bills (x) can then be solved using either Equations 1 or 2. Using Equation 1 to determine x,
x + y = 15
x = 15 - y
x = 15 - 8
x = 7
From the solution, we have determined that there are 8 pieces of $5 bills and 7 pieces of $1 bills.
Answer:
B. seven $1 bills and eight $5 bills.
Step-by-step explanation:
n = number of $1 bills
m = number of $5 bills
Given:
n + m = 15
n($1) + m($5) = $47
Just solve 2 equations in 2 unknowns n and m:
(i) n + m = 15
(ii) n + 5m = 47
Subtract (i) from (ii) and get
4m = 32
m = 32/4 = 8
Then from (i) get
n = 15 - m = 15 - 8 = 7
There are 7 $1 bills and 8 $5 bills.
Helpppppppppppppppppppppppppppppp
Answers
replace the numbers inside () for x
f(4) = -4(4)-3 = -16 -3 = -19
G(-4) = 2(-4)^2 -3(-4) = 44
Can you check if I did this right? (:
Answers
what is the answer to algebra with pizzazz page 100; what should you say if you see a tall, wrought-iron tower in paris, france?
there are 24 blanks
Answers
Given
[tex]3n^2-17n+24 \\ \\ \Rightarrow3n^2-9n-8n+24 \\ \\ \Rightarrow3n(n-3)-8(n-3) \\ \\ \Rightarrow(3n-8)(n-3)[/tex]
Part 2:
Given
[tex]4x^3y-49xy^3 \\ \\ \Rightarrow xy(4x^2-49y^2) \\ \\ \Rightarrow xy(2x-7y)(2x+7y)[/tex]
Part 3:
Given
[tex]5x^2+20xy-60y^2 \\ \\ \Rightarrow5x^2-10xy+30xy-60y^2 \\ \\
\Rightarrow5x(x-2y)+30y(x-2y) \\ \\ \Rightarrow(5x+30y)(x-2y) \\ \\ \Rightarrow5(x+6y)(x-2y)[/tex]
Part 4:
Given
[tex]3x^3-x^2y+12x-4y \\ \\ \Rightarrow3x^3+12x-x^2y-4y \\ \\ \Rightarrow3x(x^2+4)-y(x^2+4) \\ \\ \Rightarrow(3x-y)(x^2+4)[/tex]
Part 5:
Given
[tex]2x^4y-3x^3y-20x^2y \\ \\ \Rightarrow x^2y(2x^2-3x-20) \\ \\ \Rightarrow x^2y(2x^2-8x+5x-20) \\ \\ \Rightarrow x^2y[2x(x-4)+5(x-4)] \\ \\ \Rightarrow x^2y(2x+5)(x-4)[/tex]
Part 6:
Given
[tex]9x^3y+33x^2y^2+30xy^3 \\ \\ \Rightarrow3xy(3x^2+11xy+10y^2) \\ \\ \Rightarrow3xy(3x^2+6xy+5xy+10y^2) \\ \\ \Rightarrow3xy[3x(x+2y)+5y(x+2y)] \\ \\ \Rightarrow3xy(3x+5y)(x+2y)[/tex]
Part 7:
Given
[tex]16a^3b^4+40a^2b^5+8ab^3 \\ \\ \Rightarrow8ab^3(2a^2b+5ab^2+1)[/tex]
Part 8:
Given
[tex]t^4-37t^2+36 \\ \\ \Rightarrow(t-1)(t-36)[/tex]
Part 9:
Given
[tex]2a^7b^3-288ab \\ \\ \Rightarrow2ab(a^6b^2-144) \\ \\ \Rightarrow2ab(a^3b-12)(a^3b+12)[/tex]
Part 10
Given
[tex]35a^2b-5a-7ab^2+b \\ \\ \Rightarrow35a^2b-7ab^2-5a+b \\ \\ \Rightarrow7ab(5a-b)-(5a-b) \\ \\ \Rightarrow(7ab-1)(5a-b)[/tex]
Part 11:
[tex]6a^4b^2-11a^3b^3+4a^2b^4 \\ \\ \Rightarrow a^2b^2(6a^2-11ab+4b^2) \\ \\ \Rightarrow a^2b^2(6a^2-3ab-8ab+4b^2) \\ \\ \Rightarrow a^2b^2[3a(2a-b)-4b(2a-b)] \\ \\ \Rightarrow a^2b^2(3a-4b)(2a-b)[/tex]
Part 12:
Given
[tex]t^2(t+3)+6t(t+3)+9(t+3) \\ \\ \Rightarrow(t^2+6t+9)(t+3) \\ \\ \Rightarrow(t+3)(t+3)(t+3) \\ \\ \Rightarrow(t+3)^3[/tex]
Answer: That’s really quite an eyeful
Step-by-step explanation:
The bottom answer to all of it is
That’s really quite an eyeful.
The following temperatures were recorded in Pasadena for a week in April: 87, 85, 80, 78, 83, 86, 90. Determine the interquartile range
Answers
78,[80],83,(85),86,[87],90
Q1 = 80
Q2 (median) = 85
Q3 = 87
Interquartile range (IQR) = Q3 - Q1 = 87 - 80 = 7 <==
78,[80],83,(85),86,[87],90
Q1 = 80
Q2 (median) = 85
Q3 = 87
Interquartile range (IQR) = Q3 - Q1 = 87 - 80 = 7 <==
what are the angle measures of the triangle? a)30, 60, and 90 b)45, 45, and 90 c)60,60,and 60 d)they cannot be determined.
Answers
the right answer is actually 30,60,90, I got the answer right on the test
The measures of the angles are 30°, 60°, and 90° for the given right triangle. The correct answer would be option (A).
What is right triangle?A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.
The right triangle is given in the figure, as shown.
According to the figure,
perpendicular = 7√3
hypotenuse = 14√3
As per the question, we have
Since sin θ = perpendicular/hypotenuse
Substitute the values in the above formula, and we get
sin θ = 7√3/14√3
sin θ = 1/2
θ = 30°
This means the measures of the angles are 30°, 60°, and 90°.
Hence, the correct answer would be an option (A).
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The question seems to be incomplete, the missing part has been attached below.
Simplify the square root of 16x^6th power
Answers
Krista is planning to mow her grandparents lawn the rectangular yard is 10 yards by 12 yards but there is a square patio that has 12 foot sides in the middle of Krista kenmo 15 square feet per minute about how long will it take to finish the yard
Answers
Use lagrange multiplier techniques to find the local extreme values of f(x, y) = x2 − y2 − 2 subject to the constraint x2 + y2 = 16
Answers
The local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] are -18 at points (0, 4) and (0, -4).
To find the local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] using Lagrange multiplier techniques, we need to set up the Lagrangian function:
[tex]\[ L(x, y, \lambda) = f(x, y) - \lambda(g(x, y) - c) \][/tex]
where [tex]\( g(x, y) \)[/tex] is the constraint, c is a constant, and [tex]\( \lambda \)[/tex] is the Lagrange multiplier.
In this case, [tex]\( g(x, y) = x^2 + y^2 \)[/tex] is the constraint, and c = 16 .
So, the Lagrangian function is:
[tex]\[ L(x, y, \lambda) = x^2 - y^2 - 2 - \lambda(x^2 + y^2 - 16) \][/tex]
Now, find the partial derivatives of L with respect to ( x, y, ) and[tex]\( \lambda \)[/tex] and set them equal to zero to find critical points:
[tex]\[ \frac{\partial L}{\partial x} = 2x - 2\lambda x = 0 \]\[ \frac{\partial L}{\partial y} = -2y - 2\lambda y = 0 \]\[ \frac{\partial L}{\partial \lambda} = x^2 + y^2 - 16 = 0 \][/tex]
Solving the system of equations, we get two critical points:
1. When [tex]\( x = 0, y = 4, \lambda = -\frac{1}{4} \)[/tex]
2. When [tex]\( x = 0, y = -4, \lambda = -\frac{1}{4} \)[/tex]
Now, evaluate f(x, y) at these critical points:
1. f(0, 4) = 0 - 16 - 2 = -18
2. f(0, -4) = 0 - 16 - 2 = -18
Therefore, the local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] are -18 at points (0, 4) and (0, -4).
△FEB≅△CNB.
What is length of BN¯¯¯¯¯¯ ?
Answers
You simply match them up in corresponding order and use CPCTC
we know that
The CPCTC states that corresponding parts of congruent triangles are congruent
so
△FEB≅△CNB
that means
[tex]FE=CN\\FB=CB\\EB=NB[/tex]
we have
[tex]FE=6.1\ units\\FB=4.8\ units\\EB=3.8\ units[/tex]
therefore
[tex]BN=3.8\ units[/tex]
the answer is
the length of BN is [tex]3.8\ units[/tex]
I have another math question
Answers
#9 is $520
_------_--------_
How to prove system of nonlinear equations has finite solutions?
Answers
what is the slope of the line (2,5) and 7,25)
Answers
25-5 divided by 7-2.
20 divided by 5
=4
The slope of the line would be 4.
The gasoline prices in seven states are $1.96, $2.09, $1.79, $1.61, $1.75, 2.11, and $1.84 what is the median gas price and the difference of the first and third quartiles
Answers
1.61, [1.75], 1.79, (1.84), 1.96, [2.09], 2.11
the median (the middle number) = 1.84 <=
the difference of the first and 3rd quartiles (the IQR) =
2.09 - 1.75 = 0.34 <=
Answer:
Median = $1.84
The difference of the first and third quartiles = $0.34
Step-by-step explanation:
Median
How to calculate the median of a small data or ungrouped data;
1. Arrange the data in ascending or descending order.
2. Choose the middle value. The middle value can be a single value or two value. If the middle value is a single value, then, that value is the median but if the middle values are two, the mean of the two middle values is evaluated to get the median.
Arranging the gasoline prices given in ascending order;
$1.61, $1.75, $1.79, $1.84, $1.96, $2.09, $2.11
The middle value is a single number $1.84 in bold. Therefore, the median is $1.84.
Median = $1.84
First (Lower) Quartile
To calculate for the First (Lower) quartile,
1. Arrange the data give in ascending order.
2. The First (Lower) quartile, Q1 is then calculated using;
[tex]Q1 =\frac{1}{4} (n + 1)^{th}[/tex] term
where n is the total number of terms of the data. In the given question, the total number of terms, n = 7
[tex]Q1 =\frac{1}{4} (7 + 1)^{th}[/tex] term
[tex]Q1 =\frac{8}{4}^{th}[/tex] term
Q1 = 2nd term
3. Select the 2nd term of the given data already arranged in ascending order.
$1.61, $1.75, $1.79, $1.84, $1.96, $2.09, $2.11
The First Quartile, Q1 = $1.75
Third (Upper) Quartile
To calculate for the third (upper) quartile,
1. Arrange the data give in ascending order.
2. The third (upper) quartile (Q3) is then calculated using;
[tex]Q3 =\frac{3}{4} (n + 1)^{th}[/tex] term
where n is the total number of terms. In the given question, the total number of terms, n = 7
[tex]Q3 =\frac{3}{4} (7 + 1)^{th}[/tex] term
[tex]Q3 =\frac{24}{4}^{th}[/tex] term
[tex]Q3 = 6^{th} term[/tex]
3. Select the [tex]6^{th} term[/tex] of the given data already arranged in ascending order.
$1.61, $1.75, $1.79, $1.84, $1.96, $2.09, $2.11
The third (upper) quartile Q3 = $2.09
The difference between the first and third quartiles is called interquartile range.
Now, calculating the difference of the first and third quartiles
Interquartile Range = Q3 - Q1
$2.09 - $1.75 = $0.34
The difference of the first and third quartiles, Interquartile Range = $0.34
Assume that you pay $2,849.84 in state property taxes every year. If your property has an assessed value of $41,302, what is your state’s property tax rate? a. 0.077 b. 0.032 c. 0.014 d. 0.069
Answers
Answer:
Therefore, The correct option is D. 0.069
Step-by-step explanation:
Amount of the money paid in the state property taxes every year = $2849.84
The property owned has an assessed value.
Now, the assessed value of the property is $41302
We need to find the state's property tax rate.
[tex]\text{So, State's property tax rate = }\frac{\text{state's property tax}}{\text{assessed value}}\\\\\text{State's property tax rate = }\frac{2849.84}{41302}\approx 0.069[/tex]
Therefore, The correct option is D. 0.069
Write an equation of the circle with center , −45 and radius 6 .
Answers
How do we modify this equation to shift the circle and change its radius, then? Well, if we want to change the radius, we simply have to change the hypotenuse of the triangle that's sweeping out the circle in the first place. The default for a circle is 1, but we're looking for a radius of 6, so our equation, in line with Pythagorus's, would look like [tex]x^2+y^2=6^2[/tex], or [tex] x^{2} +y^2=36[/tex].
Shifting the center of the circle is a bit of a longer story, but - at first counterintuitively - you can move a circle's center to the point (a,b) by altering the x and y portions of the equation to read:
[tex](x-a)^2+(y-b)^2[/tex]
What is the equation of the line that is perpendicular
Answers
If cats prowl, mice will scatter. Mice are scattering
Answers
Please help me with 3 math questions!!! I will give 30 points and brainliest to whoever answers the best!
1. Write the inverse function for the function, ƒ(x) = 1/2x + 4. Then, find the value of ƒ -1(4). Type your answers in the box.
ƒ -1(x) = (answer) x (answer)(answer)
ƒ -1(4) = (answer)
2. Match each function with the expression representing its inverse function. Match one of the numbers with the correct letter.
1. y = x - 4
2. g(x) = -0.5x
3. k(x) = x
4. p(x) = x + 4
5. h(x) = 4x
6. ƒ(x) = x/2
a. 2x
b. x + 4
c. x - 4
d. -2x
e. 0.25x
f. x
3. The graph of a function g is shown below.
Find its inverse.
(picture below, my answer is NOT correct)
Answers
original function: f(x)=(1/2)x+4
switch: x=(1/2)f(x)+4
f(x)=2x-8, this is the answer for question 1
answer for question 2: 1-b, 2-d, 3-f, 4-c, 5-e, 6-a
question 3
From the given graph, we know the slope is 2/5, the y intercept is -2, so the original function is f(x)=(2/5)x-2
switch x and f(x): x=(2/5)f(x)-2
solve for f(x): (2/5)f(x)=x+2
multiply both side by 5/2: f(x)=(5/2)x+5,
so the second choice is the correct answer.
Take a look at the figure. What is the first step you should take to solve the formula?
A. Find the value of 6 squared. B. Cancel 6 into 6. C. Subtract 2 from 3. D. Multiply 3 by 6.
Answers
1) Parenthesis
2) Exponents
3) Multiply OR Divide from right to left
4) Add OR Subtract from right to left
Since there are no Parenthesis, you'd move to Exponents as we have one of those, so doing 6^2 is your first step, which is choice A.
So, A is your answer.
Hope this helps,
Brian
If r^n=a, then which of the following are true statements? Check all that apply.
a. a^1/n=r b. a^r=n c. n sq a =r d. n^1/r=a
Answers
b. This is incorrect, because this contradicts with choice a.
c. This is correct. When a number is raised to a "1/n" fraction, that is equivalent to the nth root of the number.
d. This is incorrect, because it is not equivalent to the given equation.
Thus, the answers are A and C.
There are 20 counters in a box. A counter is chosen and replaced 100 times, the results are 32 blue and 68 red. How many of each color do you think there are in each box ?
Answers
45x = 2160
x - 2160/45 = 48 people
2)
n = (n - 1) - 5
3)
7x - 11 = 19 - 3x
add 3x to both sides:
10x - 11 = 19
add 11 to both sides:
10x = 30
divide both sides by 10:
x = 30/10 = 3
4)
4(8)(11) - 64 = 288
5)
(5, 0)
6)
-4x -3 + 2x - 6 = -2x - 9
7)
1.8(-20) + 32 = -4F
8)
Exterior angle add to 360
360/6 = 60 degrees
10)
2x/9 = 12
2x = 108
x = 108/2 = 54
11)
x = 0
12)
8 + 3 + 1 = 12
240/12 = 20
8(20) = 160
3(20) = 60
1(20) = 20
160 pounds, 60 pounds, 20 pounds
SOMEONE PLEASE HELP ME ASAP!!!
1. In recent years, there has been considerable discussion about the appropriateness of the body shapes and proportions of the Ken and Barbie dolls. These dolls are very popular, and there is some concern that the dolls may be viewed as having the "ideal body shape," potentially leading young children to risk anorexia in pursuit of that ideal. Researchers investigating the dolls' body shapes scaled Ken and Barbie up to a common height of 170.18 cm (5'7") and compared them to body measurements of active adults. Common measures of body shape are the chest (bust), waist, and hip circumferences. These measurements for Ken and Barbie and their reference groups are presented in the table below.
Ken Barbie
Chest Waist Hips | Chest Waist Hips
Doll: 75.0 56.5 72.0 | 82.3 40.7 72.7
Human x-bar: 91.2 80.9 93.7 | 90.3 69.8 97.9
Human S: 4.8 9.8 6.8 | 5.5 4.7 5.4
Suppose that the researchers' scaled-up dolls suddenly found themselves in the human world of actual men and women.
Convert Ken's chest, waist, and hips measurements to z-scores. Which of those measures appears to be the most different from Ken's reference group (human males)? Justify your response with an appropriate statistical argument.
2. In recent years, there has been considerable discussion about the appropriateness of the body shapes and proportions of the Ken and Barbie dolls. These dolls are very popular, and there is some concern that the dolls may be viewed as having the "ideal body shape," potentially leading young children to risk anorexia in pursuit of that ideal. Researchers investigating the dolls' body shapes scaled Ken and Barbie up to a common height of 170.18 cm (5'7") and compared them to body measurements of active adults. Common measures of body shape are the chest (bust), waist, and hip circumferences. These measurements for Ken and Barbie and their reference groups are presented in the table below.
Ken Barbie
Chest Waist Hips | Chest Waist Hips
Doll: 75.0 56.5 72.0 | 82.3 40.7 72.7
Human x-bar: 91.2 80.9 93.7 | 90.3 69.8 97.9
Human S: 4.8 9.8 6.8 | 5.5 4.7 5.4
Suppose that the researchers' scaled-up dolls suddenly found themselves in the human world of actual men and women.
Convert Barbie's chest, waist, and hips measurements to z-scores. Do these z-scores provide evidence to justify the claim that the Barbie doll is too thin of a representation of adult women? Justify your response with an appropriate statistical argument.
3. Jill scores 680 on the mathematics part of the SAT. The distribution of SAT scores in a reference population is normally distributed with the mean 500 and standard deviation 100. Jack takes the ACT mathematics test and scores 27. ACT scores are normally distributed with mean 18 and standard deviation 6.
Find the standardized scores for both students.
4. Jill scores 680 on the mathematics part of the SAT. The distribution of SAT scores in a reference population is normally distributed with the mean 500 and standard deviation 100. Jack takes the ACT mathematics test and scores 27. ACT scores are normally distributed with mean 18 and standard deviation 6.
Assuming that both tests measure the same kind of ability, who has the higher score, and why?
5. A lunch stand in the business district has a mean daily gross income of $420 with a standard deviation of $50. Assume that the daily gross income is normally distributed.
If a randomly selected dat has a gross income of $520, then how many standard deviations away from the mean is that day's gross income?
Answers
zChest -> (91.2-75)/4.8=-3.4zWaist -> (80.9-56.5)/9.8≈-2.5zHips -> (93.7-72)/6.8≈-3.2It would be Ken's chest because the difference between the doll and an averaged human male is the greatest
2.)
zChest -> (82.3-90.3)/4.7≈-1.45zWaist -> (40.7-69.8)/4.7≈-6.19zHips -> (72.7-97.9)/5.4≈-4.7
Yes because the waist is far too thin compared to an averaged human woman
3.)
zJill -> (680-500)/100=1.8zJack -> (27-18)/6=1.5
4.)
It would be Jill because she has the higher z-score
5.)
$520-420=80$50=SDs$80(1 SD/50)=1.6 SD
The equation y=-5.131x^2 31.821x-3.333 approximates the number of people standing in line to catch commuter train x hours after 5am what is the best estimate for the number of people in line at 9am
Answers
41 is the best estimate for the number of people in line at 9am
What is Equation?Two or more expressions with an Equal sign is called as Equation.
y equal to minus five point one three one x square plus Thirty one point eight two one x minus three point three three three.
y=-5.131x²+ 31.821x-3.333 approximates the number of people standing in line to catch commuter train x hours after 5am.
There is 4 hours in between 9 am and 5 am. so x=4
Substitute x=4 into the equation
y=-5.131(4)²+ 31.821(4)-3.333
y=-5.131(16)+127.284-3.333
y=-82.096+127.284-3.333
y=41.855
Hence 41 is the best estimate for the number of people in line at 9am
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The range of f(x) = |-x| is _____.
y < 0 , y > 0 , y ≤ 0 , y ≥ 0
Answers
Y >= 0 ( your last choice)
Answer:
y ≥ 0
Step-by-step explanation:
The real absolute value function is defined on the set of all real numbers, assigning each real number its respective absolute value. Formally, the absolute value of any real number x, is defined by:
[tex]|x|=x,\hspace{3}if\hspace{3}x\geq0\\|x|=-x,\hspace{3}if\hspace{3}x<0[/tex]
The domain of the function is all real numbers, and by definition, the absolute value of x will always be greater than or equal to zero and never negative. Hence:
[tex]Domain:\\x\in R\\Range:\\y\in R : y\geq0[/tex]
I attached you a picture of the graph.
Cameron bought four begonias in 6-in pots and a $19 fern at a fundraiser. he spent a total of $63. how much is each begonia?
Answers
The cost of each begonia is $11 at a fundraiser.
What is the equation?The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.
Let's assume the cost of each begonia x.
Since Cameron bought four begonias, the total cost of the begonias was 4x.
The total cost of the plants was the cost of the begonias plus the cost of the fern, or 4x + 19.
As per the question, the total cost was $63, so we can set up the equation:
4x + 19 = 63
To solve for x, we need to get x by itself on one side of the equation. We can do this by subtracting 19 from both sides:
4x + 19 - 19 = 63 - 19
This simplifies to:
4x = 44
To solve for x, we need to divide both sides by 4:
4x / 4 = 44 / 4
This simplifies to:
x = 11
Therefore, each begonia cost $11.
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Which of the following points are on the line given by the equation y=1/2x?
Check all that apply
A. (2, 1)
B. (3, 15)
C. (4, 2)
D. (3, 6)
E. (-2, 1)
F. (-2, -1)
Answers
Answer: (2,1) (4,2) (-2,-1)
Step-by-step explanation:
thats apex, my dude
Answer:
Option A, C, F are the correct options.
Step-by-step explanation:
The given equation of line is [tex]y=\frac{1}{2}x[/tex]
Now we will plug in the values of points and validate the equation.
Option A. (2, 1)
[tex]y=\frac{1}{2}x[/tex]
[tex]1=\frac{2}{2}=1[/tex]
So this points lies on the given equation of line.
Option B. (3, 15)
[tex]15\neq \frac{3}{2}[/tex]
So the point is not on the line.
Option C. (4, 2)
[tex]2=\frac{4}{2}=2[/tex]
Point lies on the line.
Option D. (3, 6)
[tex]6\neq \frac{3}{2}[/tex]
Therefore point is not on the line.
Option E. (-2, 1)
[tex]1\neq \frac{-2}{2}[/tex]
Point does not lie on the line.
Option F. (-2, -1)
[tex]-1=\frac{-2}{2}=-1[/tex]
So this point lies on the line.
There are three points (2, 1), (4, 2) and (-2, -1) are on the line.
Anthony has 115 book in his room .He is storing them in boxes .Each box holds 17 book .How many boxes does Anthony need?
Answers
Anthony need 7 boxes to hold 115 books.
What is Division method?
Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications.
For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.
Given that;
Anthony has 115 books in his room.
And, He is storing them in boxes.
Each box holds 17 books.
Now,
Since, Total number of books = 115
And, Each box holds 17 books.
Hence, Number of boxes to cover 115 books = 115 ÷ 17
= 7
Since, We get the quotient after divide 115 by 17 is 13.
So, Anthony use 1 box extra to keep 13 remaining books.
Thus, Anthony need 7 boxes to hold 115 books.
Learn more about the divide visit:
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