the zeros of f(x) algebraically

Answer: Each cup has 4 blueberries and 5 raspberries.

Step-by-step explanation:

Since we have given that

Number of blueberries = 36

Number of raspberries = 45

We need to find the number of each type if she wants to put an equal number of blueberries and an equal number of raspberries into each cup.

So, H.C.F. of 36 and 45 = 9

So, Number of blueberries would be

[tex]\dfrac{36}{9}=4[/tex]

Number of raspberries would be

[tex]\dfrac{45}[9}=5[/tex]

Hence, each cup has 4 blueberries and 5 raspberries.

Answer:

Length of the envelope = 14

Width of the envelope = 5.6

Step-by-step explanation:

Let the width of the rectangle be  x

Then the length of the rectangle will be [tex]2\frac{1}{2} \times x[/tex]

Also the length of the plastic band to cover the  front and back of the envolpe =  [tex]39\frac{3}{8}[/tex]

To cover one side th band required is

=>[tex]\frac{39\frac{3}{8}}{2}[/tex]

=>[tex]\frac{\frac{315}{8}}{2}[/tex]

=>[tex]\frac{\frac{315}{8}}{2}[/tex]

=>[tex]{\frac{315}{16}[/tex]

=>39.4

We know that the perimeter of the rectangle is

=> 2( L + B) = [tex]{\frac{39.4}{2}[/tex]

=> 2( [tex]2\frac{1}{2} \times x + x[/tex]) = 19.7

=> 2( [tex]\frac{7}{2}x) = 19.7 [/tex]

=>  [tex]3.5x = 19.7 [/tex]

=> [tex] x = \frac{19.7}{3.5} [/tex]

=>  [tex]x = 5.6[/tex]

Now length of the envelope =

=>  [tex]2\frac{1}{2} \times x [/tex]

=>  [tex] 2.5 \times 5.6 [/tex]

=> 14

The problem involves setting up a relationship equation using the width and length of a rectangle and solving the equation to find the width and length. The length of the plastic band is given, which helps in creating the equation.

In this problem, the rectangular envelope has its length, which is 2 1/2 times the width. There is a plastic band that wraps around the envelope and it is given that the total length of this plastic band is 39 3/8 inches. Thus, the length of the plastic band is equal to twice the length of the envelope plus twice the width of the envelope.

Let us denote the width of the envelope by w. Therefore, the length of the envelope is 2.5w. Setting up an equation using this information, we have: 2*(2.5w) + 2w = 39 3/8. Simplifying this equation, we get: 5w + 2w = 39 3/8, 7w = 39 3/8. To find the width, we can divide both sides of the equation by 7, yielding w = 39 3/8 / 7.

Having calculated the width, the length is simply 2.5 times this value. Therefore, we have found both the width and length of the rectangle envelope.

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Answer:

To write 252 cards together Courtney and Victoria will take = 140 minutes or 2 hours and 20 minutes.

Step-by-step explanation:

Given:

Courtney writes 4 cards in 10 minutes

Victoria writes 14 cards in 10 minutes.

To find the time taken by them to  write 252 cards working together.

Solution:

Using unitary method to determine their 1 minute work.

In 10 minutes Courtney writes = 4 cards

So,in 1 minute Courtney will write = [tex]\frac{4}{10}[/tex] cards

In 10 minutes Victoria writes = 14 cards

So,in 1 minute Victoria will write = [tex]\frac{14}{10}[/tex] cards

Now, Courtney and Victoria are working together.

So, in 1 minute, number of cards they can write together will be given as:

⇒ [tex]\frac{4}{10}+\frac{14}{10}[/tex]

Since we have common denominators, so we can simply add the numerators.

⇒ [tex]\frac{18}{10}[/tex]

Again using unitary method to determine the time taken by them working together to write 252 cards.

They can write  [tex]\frac{18}{10}[/tex] cards in 1 minute.

To write 1 card they will take  = [tex]\frac{1}{\frac{18}{10}}=\frac{10}{18}[/tex] minutes

So, for 252 cards the will take = [tex]\frac{10}{18}\times252=\frac{2520}{18}=140[/tex] minutes

140 minutes = (60+60+20) minutes = 2 hours and 20 minutes [ As 60 minutes = 1 hour]

So, to write 252 cards together Courtney and Victoria will take = 140 minutes or 2 hours and 20 minutes.

Courtney and Victoria can write 252 Christmas cards in 140 minutes when working together.

To find out how long it will take Courtney and Victoria to write 252 Christmas cards when they work together, we need to first determine how many cards they can write in 10 minutes individually. Courtney can write 4 cards in 10 minutes, while Victoria can write 14 cards in the same time. Thus, Courtney can write 4/10 = 0.4 cards per minute, and Victoria can write 14/10 = 1.4 cards per minute. When they work together, their combined rate is 0.4 + 1.4 = 1.8 cards per minute.

To determine the total time it will take them to write 252 cards, we can divide the number of cards by their combined rate: 252 / 1.8 = 140 minutes. Therefore, it will take them 140 minutes to write out 252 Christmas cards when they work together.

Answer:

8 years

Step-by-step explanation:

Use formula

[tex]I=P\cdot r\cdot t,[/tex]

where

I = interest

P = principal

r = rate (as decimal)

t = time

In your case,

I = $175.84

P = $314

r = 0.07, then

[tex]175.84=314\cdot 0.07\cdot t\\ \\175.84=21.98t\\ \\t=\dfrac{175.84}{21.98}\\ \\t=8[/tex]

The question asks for the duration of an investment. We use the formula for simple interest to solve this. By plugging the known values into the rearranged formula for time, we can find the duration of the investment.

The question asks for how long the principle was invested if you received $175.84 on $314 invested at a rate of 7%. The calculation is based on the formula for simple interest, which is I = PRT (Interest = Principal x Rate x Time). From the question, we know that the Interest (I) is $175.84, the Principal (P) is $314, and the Rate (R) is 7% or 0.07 when expressed as a decimal.

We need to find the Time (T), which can be rearranged from the formula as T = I / (P x R). By plugging the values into this formula, we get T = 175.84 / (314 x 0.07). Solving for T will give the time period the money was invested for.

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                                   Question #15

Step-by-step explanation:

A notation such as [tex]T_{(-1, 1)}oR_{y-axis}[/tex] is read as:

"a translation of (x, y) → (x - 1, y + 1) after a reflection across y-axis.

The rule of reflection of point (x, y) across y-axis brings (x, y) → (-x, y), meaning that y-coordinate remains the same, but x-coordinate changes its sign.

As ΔABC with coordinates A(1, 3), B(4, 5) and C(5, 2). Here is the coordinates of ΔA'B'C' after the glide reflection described by [tex]T_{(-1, 1)}oR_{y-axis}[/tex].

                                            [tex]R_{y-axis}[/tex]                                   [tex]T_{(-1, 1)}[/tex]  

A(1, 3)              →                A'(-1, 3)               →                    A"'(-2, 4)

B(4, 5)             →                B'(-4, 5)               →                    B"'(-5, 6)

C(5, 2)             →                C'(-5, 2)               →                    C"'(-6, 3)

                                        Question #16

Step-by-step explanation:

A glide reflection is said to be a transformation that involves a  translation followed by a reflection in which every  point P is mapped to a point P ″ by the following steps.

As ΔABC with coordinates A(-4, -2), B(-2, 6) and C(4, 4).

Translation : (x, y)  → (x + 2, y + 4)

Reflection : in the x-axis

The rule of reflection of point (x, y) across x-axis brings (x, y) → (x, -y), meaning that x-coordinate remains the same, but y-coordinate changes its sign.

Hence,

ΔABC with coordinates A(-4, -2), B(-2, 6), C(4, 4) after (x, y)  → (x + 2, y + 4) and reflection in the x-axis.

A(-4, -2)         →     A'(-2, 2)     →     A''(-2, -2)    

B(-2, 6)          →    B'(0, 10)       →     B''(0, -10)

C(4, 4)            →    C(6, 8)         →      C''(6, -8)

Keywords: reflection, glide reflection, translation

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Answer:

1 / (1 + x²)

Step-by-step explanation:

Derivative of a function by first principle is:

[tex]f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]

Here, f(x) = tan⁻¹ x.

[tex]f'(x)= \lim_{h \to 0} \frac{tan^{-1}(x+h)-tan^{-1}x}{h}[/tex]

Use the difference of arctangents formula:

[tex]tan^{-1}a-tan^{-1}b=tan^{-1}(\frac{a-b}{1+ab})[/tex]

[tex]f'(x)= \lim_{h \to 0} \frac{tan^{-1}(\frac{x+h-x}{1+(x+h)x} )}{h}\\f'(x)= \lim_{h \to 0} \frac{tan^{-1}(\frac{h}{1+(x+h)x} )}{h}[/tex]

Next, we're going to use a trick by multiplying and dividing by 1+(x+h)x.

[tex]f'(x)= \lim_{h \to 0} \frac{tan^{-1}(\frac{h}{1+(x+h)x} )}{h}\frac{1+(x+h)x}{1+(x+h)x} \\f'(x)= \lim_{h \to 0} \frac{1}{1+(x+h)x} \frac{tan^{-1}(\frac{h}{1+(x+h)x} )}{\frac{h}{1+(x+h)x}}[/tex]

We can now evaluate the limit.  We'll need to use the identity:

[tex]\lim_{x \to 0} \frac{tan^{-1}x}{x} =1[/tex]

This can be shown using squeeze theorem.

The result is:

[tex]f'(x)= \lim_{h \to 0} \frac{1}{1+(x+h)x}\\\frac{1}{1+x^2}[/tex]

Answer:

The width of the Iphone 11 pro max is 3.36 in.

Step-by-step explanation:

since both iPhones are proportional, you will need to find the ratio of what their proportion is to one another. the length of one iphone is 5.2, and the length of the other iphone is 6.24. Therefore, the ratio of proportion to each other would be 5.2/ 6.24. to find the width of the iphone 11 pro max, you will need to use the following equation: 5.2/6.24 x 2.8/? (unknown side)      

this gives you the equation 6.24 x 2.8 = 5.2 x ?  (unknown side)

(the question mark is the unknown side of the iphone 11 pro max)

6.24 x 2.8 / 5.2 = ? (unknown side)

therefore the unknown side of the iphone 11 pro max is 3.36 in.

By using the concept of proportions, the width of the iPhone 11 Pro Max, when it's proportional to iPhone 11 Pro, is approximately 3.36 inches.

The given problem involves finding a proportional measurement. The iPhone 11 pro has dimensions 5.2 inches (length) and 2.8 inches (width). If the iPhone 11 Pro Max is proportional in size and has a length of 6.24 inches, we can find its width using the ratio between the length and the width of the iPhone 11 pro.

We will set up a proportion like this:

[tex]5.2/2.8 = 6.24/x[/tex]

Where x is the width of the iPhone 11 Pro Max. Solving for x will give us the width:

[tex]2.8 * 6.24 = 5.2 * x\\x = (2.8 * 6.24) / 5.2[/tex]

After solving this equation, we find that the width of the iPhone 11 Pro Max is approximately 3.36 inches.

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The question is incomplete and the figure is missing. Here is the complete question with the figure attached below.

In the figure, sin ∠MQP = ______.

A. Cos N and Sin R

B. Sin R and Sin N

C. Cos N and Sin M

D. Cos R and Sin N

Answer:

D. Cos R and Sin N

Step-by-step explanation:

Given:

∠MQP = 56°

sin (∠MQP) = sin (56°)

Consider the triangle NMR,

m ∠N = 56°, m ∠R = 34°

sin (∠N) = sin (56°)

So, sin (∠MQP) = sin (∠N) = sin (56°) ---------- (1)

Now, we know that, [tex]\sin x=\cos(90-x)[/tex]

Therefore, sin (∠N) = sin (56°) = cos (90°-56°) = cos (34°)

Now, from the same triangle NMR,

[tex]\cos (\angle R)=\cos (34\°)[/tex]

Therefore, sin (∠N) = cos (∠R)  ------------- (2)

Hence, from equations (1) and (2), we have

sin (∠MQP) = sin (∠N) = cos (∠R)

So, option D is correct.

Answer:

A) H + R + T = 109

B) R = 3T

C) T = H + 9 combining equation B) with equation A)

A) H + 4T = 109 combining C) with A)

A) T -9  + 4T = 109

A) 5T = 118

Tom has 23.60 dollars

We put this information into equation B)

R = 3*23.60

Rafeal has 70.80 dollars

Putting this into Rafael and Ton into equation A)

A) H + 70.80 + 23.60 = 109

Heather has 14.60 dollars

Step-by-step explanation:

The width of rectangle is 8 units.

Step-by-step explanation:

Given,

Area of rectangle = 40 units

Width = w

Length = w-3

Area = Length * Width

[tex]40=(w-3)*w\\40=w^2-3w\\w^2-3w=40\\w^2-3w-40=0[/tex]

Factorizing the equation

[tex]w^2-8w+5w-40=0\\w(w-8)+5(w-8)=0\\(w-8)(w+5)=0[/tex]

Either,

w-8=0         => w=8

Or,

w+5=0        =>w= -5

As width cannot be negative, therefore

Width of rectangle = 8 units

The width of rectangle is 8 units.

Keywords: area, rectangle

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Final answer:

To find the width of a rectangle with an area of 40 units and a length expressed as the width minus 3 units, we set up and solve a quadratic equation, yielding the width of the rectangle as 8 units.

Explanation:

The question asks to find the width of a rectangle when the length is the width minus 3 units and the area is 40 units. To solve this, let's denote the width as w, then the length will be w - 3. The area of a rectangle is calculated by multiplying the length by the width, so we will set up an equation: area = length × width, or 40 = w × (w - 3).

This is a quadratic equation: w² - 3w - 40 = 0. To solve it we can factor the quadratic or use the quadratic formula. Factoring gives us (w - 8)(w + 5) = 0, which means w could be 8 or -5. Since a width cannot be negative, the width of the rectangle is 8 units.

The cost of swimming lesson in winters is $60.

Step-by-step explanation:

Given,

Cost of lessons in summer = $50 per month

Raise in winter = 20%

Amount of raise = 20% of summer's cost

Amount of raise = [tex]\frac{20}{100}*50[/tex]

Amount of raise = [tex]\frac{1000}{100}=\$10[/tex]

Cost of lesson in winter = Cost in summer + Amount of raise

Cost of lesson in winter = 50+10 = $60

The cost of swimming lesson in winters is $60.

Keywords: percentage, addition

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Answer:

The greatest number of pairs of skis and snowboards the group can rent are 21 pairs of skis and 9 pairs of snowboards.

Step-by-step explanation:

Given:

A group can rent pairs of skis and snowboards by the week. They get a reduced rate if they rent 7 pairs of skis for every 3 snowboards rented. The reduced ski rate is $45.50 per pair of skis per week, and the reduced snowboard rate is $110 per snowboard per week.

The sales tax on each rental is 16%.

The group has $2,500 available to spend on ski and snowboard rentals.

If the ratio of pairs of skis to snowboards is 7:3.

Now, to find the greatest number of pairs of skis and snowboards rentals.

So, the rent of 7 pairs of skis = [tex]7\times 45.50=\$318.50.[/tex]

And the rent of 3 pairs of snowboards = [tex]3\times 110=\$330.[/tex]

So, total rental amount of 7 pairs of skis and 3 pairs of snowboards:

[tex]318.50 + 330 = 648.50.[/tex]

Now, to get the rental amount after sales tax:

648.50 + 16% of $648.50.

[tex]=648.50 +\frac{16}{100}\times 648.50.[/tex]

[tex]=648.50+103.76[/tex]

[tex]=\$752.26.[/tex]

The total rental amount after sales tax = $752.26.

As the group has available $2,500.

So, the sets according to the given ratio:

[tex]2500\div 752.26 = 3.32.[/tex]

[tex]=3\ sets.[/tex]

Thus, there are 3 sets of the ratio 7:3.

So, the rental price according to sets are:

The rent of Skis:

[tex]7\times 3 = 21[/tex] 

[tex]21\times 45.50= 955.50[/tex]

The rent of snowboards:

[tex]3\times 3 = 9[/tex]

[tex]9\times 110 = 990[/tex]

So. the total rental amount of skis and snowboards according to sets are:

[tex]955.50 + 990 = 1,945.50[/tex]

Now, the amount of rent after sales tax:

$1945.50 + 16% of $1945.50.

[tex]=1945.50+\frac{16}{100}\times 1945.50[/tex]

[tex]=1945.50+311.28=\$2256.78.[/tex]

Thus, the total cost = $2256.78.

Now, to get the greatest number of pairs of skis to snowboards that can be rent:

[tex]2,500 - 2,256.78 = 243.22[/tex]

The cost of 21 pair of skis and 9 pairs of snowboards is $2256.78 and the group has available only $2500 to spend.

Thus, they can rent only 21 pairs of skis and 9 pairs of snowboards.

Therefore, the greatest number of pairs of skis and snowboards the group can rent are 21 pairs of skis and 9 pairs of snowboards.

Answer:

1275

Step-by-step explanation:

This is an arithmetic series. The formula for this is Sₙ = (n/2)(a₁ +aₙ)d. a₁ is the first term, so here it is 1, and aₙ is the nth term, or the last term, which is 50 here, but we don't know n.

Now we have to use the equation for an arithmetic sequence to solve for n. A sequence would just be if there was not a last number and it went on forever. that equation looks like aₙ = a₁ + (n - 1)d. Now the only new variable is d, which is the common difference. You can find that by subtracting one term from the term before it, like 2-1 = 1, so d is 1.

We can now solve for n by plugging our numbers into the second equation, so 50 = 1 + (n - 1)1, we can distribute the 1 and to (n-1) and get 50 = 1 + n - 1. Now the ones will cancel and we are left with n = 50

Finally we can plug everything into our original equation and find Sₙ = (50/2)(1+50), which simplifies to Sₙ = 25(51), and Sₙ = 1275.

Jayden ran [tex]\frac{6}{25}[/tex] of a kilometers in one minute

Solution:

Given that Angel and Jayden were at track practice

The track is two-fifth kilometers around

[tex]\text{ track length } = \frac{2}{5} \text{ kilometers}[/tex]

Angel ran 1 lap in 2 minutes

Jayden ran 3 laps in 5 minutes

To find: distance ran by Jayden in 1 minute

3 laps were run by Jayden in 5 minutes

3 laps = 5 minutes

"x" laps = 1 minute

Therefore laps run by Jayden in one minute is:

On cross multiplication we get,

5x = 3

[tex]x = \frac{3}{5}[/tex]

Therefore Jayden ran [tex]\frac{3}{5}[/tex] laps in 1 minute

Distance covered is:

Total track length = [tex]\frac{2}{5} \text{ km}[/tex]

Distance ran in 1 minute = [tex]\frac{3}{5} \times \frac{2}{5} = \frac{6}{25}[/tex]

Thus Jayden ran [tex]\frac{6}{25}[/tex] of a kilometers in one minute

Answer:

Area of parallelogram is equal to the product of base and height, the area is the product of [tex]\pi r[/tex] and r, or [tex]\pi r^{2}[/tex].

Step-by-step explanation:

We are finding the area of a circle by an alternative method.

What we do is split the circle into multiple sectors and then arrange them in the form of a parallelogram and find the area of this parallelogram.

Area of parallelogram = base[tex]\times height[/tex]

Hence area is the product of base and height.

Base = [tex]\pi r[/tex]

Height = r

Area is the product of [tex]\pi r[/tex] and r = [tex]\pi r^{2}[/tex]

Answer:

A) [tex]y=\frac{1}{2}x+3[/tex] - Linear

B) [tex]y=4x+2[/tex] - Linear      

C) [tex]xy=12[/tex] - Nonlinear

Step-by-step explanation:

To determine whether a function is linear or nonlinear.

The function of a straight line is given as :

[tex]y=mx+b[/tex]

where [tex]m[/tex] represents slope of line and [tex]b[/tex] represents the y-intercept.

Any function that can be represented as a function of straight line is called a linear function otherwise it is nonlinear.

We will check the equations given for linear or nonlinear.

A) [tex]y=\frac{1}{2}x+3[/tex]

The function is in the form [tex]y=mx+b[/tex] and hence it is a linear function with slope [tex]m=\frac{1}{2}[/tex] and y-intercept [tex]b=3[/tex].

B) [tex]y=4x+2[/tex]

The function is in the form [tex]y=mx+b[/tex] and hence it is a linear function with slope [tex]m=4[/tex] and y-intercept [tex]b=2[/tex].

C) [tex]xy=12[/tex]

On solving for [tex]y[/tex]

Dividing both sides by  [tex]x[/tex]

[tex]\frac{xy}{x}=\frac{12}{x}[/tex]

[tex]y=\frac{12}{x}[/tex]

This function cannot be represented in the form [tex]y=mx+b[/tex], hence it is a nonlinear function.

Answer:

4/9.

Step-by-step explanation:

There are a total of 18 people.

Prob( A Sculptor is chosen) = 3/18 = 1/6.

Prob( a photographer) = 5/18

The required probability is the sum of these 2, so

it is 3/18 + 5/18

= 8/18

= 4/9.

Answer:

[tex]\frac{8}{17}[/tex]

Step-by-step explanation:

Answer:

The third option is the correct one.

Step-by-step explanation:

For similar triangles, the angles are the same, but the distances between corresponding vertices is only proportional

Answer: 3.82 miles

Step-by-step explanation:

According to the shown figure, we can imagine the scene as a right triangle, where the tower is located at the right angle, and the fireman and the forest fire located at each of the other two vertices.

So, since we are dealing with a right triangle we can use the Pithagorean Theorem, in order to find the distance from the fireman to the fire [tex]d[/tex], which is also the hypotenuse.

[tex]d^{2}= (2.1 miles)^{2} +(3.2 miles)^{2}[/tex]

[tex]d=\sqrt{(2.1 miles)^{2} +(3.2 miles)^{2}}[/tex]

Finally:

[tex]d=3.82 miles[/tex]

The distance from the fireman and the fire is 3.83 miles.

Using the values given, we can calculate the distance using pythagoras ;

Inputting the values into the formula ;

distance = √2.1² + 3.2²

distance = √14.65

distance = 3.8275318418

Therefore, the distance between the fireman and the fire is 3.83 miles.

Answer:

The answer is 305. Step 1 is wrong in the given answer.

Kevin's mistake is that his step 1 in the answer is  wrong.

Step-by-step explanation:

Given expression is [tex]\frac{2440}{8}[/tex]

Now to simplify the given expression:

Given expression can be written as below

Step 1: [tex]\frac{2440}{8}=\frac{2400+40}{8}[/tex]

Step 2:  [tex]\frac{2440}{8}=\frac{2400}{8}+\frac{40}{8}[/tex]

Step 3: [tex]\frac{2400}{8}+\frac{40}{8}=300+5[/tex]  (the sum of the numerators are dividing with their corresponding terms)

Step 4: [tex]\frac{2440}{8}=305[/tex]  (adding the terms)

Step 5: Therefore [tex]\frac{2440}{8}=305[/tex]

Therefore the answer is 305 and from the problem step 1 is wrong.

Kevin's mistake is that his answer is correct and the step 1 is  wrong.

The answer is 305. Step 1 is wrong in the given answer.

Answer:

about 11 years

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]A=P(1+rt)[/tex]

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=?\ years\\ P=\$4,000\\ A=\$8,000\\r=9\%=9/100=0.09[/tex]

substitute in the formula above

[tex]8,000=4,000(1+0.09t)[/tex]

solve for r

[tex]2=(1+0.09t)[/tex]

[tex]0.09t=2-1[/tex]

[tex]0.09t=1[/tex]

[tex]t=11.1\ years[/tex]

Answer:

maximum height reached = 35 feet

and [tex]f(t) = 48t-16.07t^{2}[/tex]

Step-by-step explanation:

writing linear motion equations

[tex]s = ut + \frac{1}{2}at^{2}[/tex]

where s is the total displacement, u the initial velocity, t the time travelled, and a is the acceleration.

given u = 48 ft/s, and a = acceleration due to gravity g = -9.8[tex]\frac{m}{s^{2}}[/tex]

1 m = 3.28 feet therefore g becomes -9.8×3.28[tex]\frac{ft}{s^{2}}[/tex]

here negative sigh comes as acceleration due to gravity is in opposite direction of initial velocity.

therefore f(t) becomes [tex]f(t) = 48t-16.07t^{2}[/tex]

to find max height we should find differentiation of f(t) and equate it to 0

therefore we get 48 = 32.144t

t = 1.49 s

therefore max height f(1.49) = 71.67-36.67 = 35 feet

Answer: 36!!!

Step-by-step explanation:

Answer:

Option C is true.

Step-by-step explanation:

See the attached diagram.

Since MN is a diameter of the circle at P, so it will always make a right angle at a point on the circumference of the circle.

Therefore, ∠ MLN = 90° as L is a point on the circumference.

Now, given that LM = 2x and LN = 3x, then we have to find MN.

So, applying Pythagoras Theorem, MN² = LM² + LN²

⇒ MN² = 4x² + 9x² = 13x²

⇒ MN = x√13

Therefore, option C is true. (Answer)

Answer:

The numbers are 23,27

Step-by-step explanation:

Let one number be x

Other number = 50 - x

50 - x - x = 4

50 - 2x = 4

-2x = 4 - 50

-2x = - 46

x = -46/-2

x = 23

Other number = 50 - x = 50 -23 = 27

Answer:

x = -2

y = 3

Step-by-step explanation:

Since y = 3x +9, substitute this value in the first eq.

4x + 5(3x+9) = 7 ===> 4x + 15x + 45 = 7 ===> 19x = 7-45 ==> 19x = -38 ===>

===> x -38/19 ===> x = -2

Replace this value in the second eq.

y = 3(-2) + 9 ===> y = -6 + 9 ===> y = 3

Answer:

The rate at which the value of house increases in 40 years is 1.03  

Step-by-step explanation:

The initial value of house = P = $30,000

The final value of house = F = $120,000

The period for which the value increase = 40 years

Let the rate at which the value increases in 40 years = r%

Now, According to question

The final value of house after n years = The initial value of house × [tex](rate)^{time}[/tex]

i.r F = P × [tex](r)^{n}[/tex]

Or, r = [tex](\frac{F}{P})^{\frac{1}{n}}[/tex]

Or, r = [tex](\frac{120,000}{30,000})^{\frac{1}{40}}[/tex]

Or, r = [tex]4^{\frac{1}{40}}[/tex]

∴  r = 1.03

The rate at which the value increases in 40 years = r = 1.03

Hence,The rate at which the value of house increases in 40 years is 1.03  Answer

Answer:

Therefore the required Equations are

[tex]y =2(x+3)\ \textrm{is the required expression for First condition.}\\y = 3x-2\ \textrm{is the required expression for Second condition.}[/tex]

Step-by-step explanation:

Given:

'y' represents the larger number and

'x' represents the smaller number

Then, a larger number is double the sum of 3 and a smaller number will be

Larger no = double of ( 3 and smaller number)

∴ [tex]y=2(x+3)\ \textrm{is the required expression for First condition.}[/tex]

Now,

The larger number is 2 less than 3 times the smaller number.

Larger number = 3 times smaller number and 2 less

∴ [tex]y=3x-2\ \textrm{is the required expression for Second condition.}[/tex]

Therefore the required Equations are

[tex]y =2(x+3)\ \textrm{is the required expression for First condition.}\\y = 3x-2\ \textrm{is the required expression for Second condition.}[/tex]

Final answer:

The correct equations that model the situation are y = 3x - 2 and y = 2(x + 3), as they reflect the two conditions given in the problem description.

Explanation:

To determine which equations model the situation described, we should translate the worded statements into algebraic equations. The first statement tells us that a larger number 'y' is double the sum of 3 and a smaller number 'x'. This can be written as y = 2(x + 3). The second statement tells us that the larger number is 2 less than 3 times the smaller number, which can be written as y = 3x - 2.

Now, we need to verify the provided choices against these two derived equations:

y = 3x - 2 (Correct, it matches the second statement we translated from the problem description.)

3x - y = 3 (Incorrect, because rearranging this gives y = 3x - 3, which does not match either of our derived equations.)

3x - y = -2 (Incorrect, because rearranging this gives y = 3x + 2, which does not match either of our derived equations.)

y = 2 - 3x (Incorrect, this does not match the format of either derived equation.)

y=2(x + 3) (Correct, it matches the first statement we translated from the problem description.)

Answer:

Area of the field is 540 m².

Step-by-step explanation:

ABCD is the given quadrilateral in which diagonal BD is 36 m.

Now, AL ⊥ BD and CM ⊥ BD. Also, AL = 19 m and CM = 11 m.

Now, we have to calculate the area of quadrilateral shaped field ABCD.

At first, we will find the area of ΔABD and ΔBCD and then we will add the area of both the triangles to get the area of the quadrilateral shaped field.

Now, ΔABD and ΔBCD are both right angled triangles.

So,

[tex]area\; of \; triangle \; ABD = \frac{1}{2} \times base\times height[/tex]

[tex]=\frac{1}{2}\times BD\times AL=\frac{1}{2}\times36\times19=342\; m^{2}[/tex]

[tex]area \; of \; triangle\; BCD = \frac{1}{2}\times BD\times CM=\frac{1}{2}\times36\times 11 = 198\; m^{2}[/tex]

So, area of field ABCD = area of ΔABD + area of ΔCBD

= 342 + 198

= 540 m²

So, the area of quadrilateral shaped field is 540 m².