A toy airplane costs $4.84.. It costs 4 times as much as a toy car. What is the cost of the toy car? Show your work.
Are perfect square roots whole?
You are going to the movie theater with your grandparents and your 5 year old brother. If you spent an additional $20 on soda and popcorn, what is the total cost of your trip to the moive theater? Reel to Reel CInema Adults $7.25 Seniors $6.00 and Children under 8 $4.25
Solution:
The total cost will be the sum of money spent on tickets and on soda and popcorn.
Ticket cost for:
5 year old brother = $4.25.
Grandparents = 2x($6.00)=$12.00
Myself=$7.25.
Total cost of tickets= $4.25+$12.00+$7.25=$23.50
Total money spent= Cost of ticket + cost of soda popcorn= $23.50+$20=$43.50
Total money spent=$43.50.
Solve the inequality. r + 4 – 2(r – 14) > 0
A cell phone service provider offers two plans. Plan A includes a fee of $25 per month and charges $0.25 for every call. Plan B includes a fee of $40 per month and offers unlimited calls. For what number of phone calls is the cost of plan B less than the cost of plan A?
more than 160 calls
more than 120 calls
more than 100 calls
more than 60 calls
PLEASE HELP!!
A small fair charges an admission fee for children and adults. The cost for admission is $3 per adult and $2 per child. On a certain day, total sales were $900, and 350 people attended the fair. How many children attended the fair that day? 80 children 150 children 200 children 320 children
Answer:
B. 150 children
Step-by-step explanation:
Let, number of children = x and number of adults = y.
Since, total number of people attended the fair are 350.
So, x + y = 350.
Moreover, charges per child is $2 and adult is $3.
As, total sales are given to be $900.
So, 2x + 3y = 900
Thus, we get the system of equations,
2x + 3y = 900
x + y = 350
We will now solve the equations,
x + y = 350 ⇒ y = 350 - x
So, 2x + 3y = 900 ⇒ 2x + 3(350 -x) = 900 ⇒ 2x + 1050 - 3x = 900 ⇒ -x = -150 ⇒ x = 150.
Then, y = 350 - x ⇒ y = 350 - 150 ⇒ y = 200.
Hence, number of children and adults that attended the fair are 150 and 200 respectively.
Justin is married with one child. He works 40 hours each week at a rate of $16 per hour. His wife began working part time after their daughter was born, but still contributes about $350 to the cash inflow each month. Their monthly cash outflow is generally about $3,000. They have a balance of $2,000 in their savings account. Justin has retirement contributions taken out of his paycheck at work. They have renter’s, car and life insurance coverage. Based on this information, what part of their financial plan should Justin and his wife work on? a. managing income b. managing liquidity c. protecting assets d. retirement
Justin and his wife should focus on ( b) managing liquidity, as their savings are not sufficient to cover emergencies or unexpected expenses.
Based on the information provided, the area Justin and his wife should work on is b. managing liquidity. Justin's family has a set income from both his and his wife's jobs, and they have basic insurance coverage and are contributing to retirement. However, the fact that they have a relatively low balance in savings compared to their monthly outflow suggests that they may face challenges if unexpected expenses arise or if there is a disruption in their income. It’s important for them to focus on building a larger emergency fund to cover at least three to six months of living expenses to ensure they have sufficient cash on hand to handle unforeseen situations without jeopardizing their financial stability.
Which best describes the effect on f (x) = 2x - 5 if the slope changes to 10?
A small theater had 9 rows of 23 chairs each. An extra 8 chairs have just been brought in. How many chairs are in the theater now?
Which of the following sets of angles are congruent by the Alternate Interior Angles Theorem?
1. Angle A is congruent to Angle C
2. Angle CDE is congruent to Angle ABE
3. Angle AED is congruent to Angle CEB
4. Angle BAC is congruent to Angle CDB
The Alternate Interior Angles Theorem states that if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.
Explanation:The Alternate Interior Angles Theorem states that if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.
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What are the x and y-intercepts of the line described by the equation?
2x + 4y = 12.4
Enter your answers, in decimal form, in the boxes.
x-intercept = ____
y-intercept = _____
The x and y intercept of the given line is required,
The x intercept is [tex](6.2,0)[/tex]
The y intercept is [tex](0,3.1)[/tex]
The given line is [tex]2x+4y=12.4[/tex]
x intercept [tex]y=0[/tex]
[tex]2x+4\times 0=12.4\\\Rightarrow x=\dfrac{12.4}{2}\\\Rightarrow x=6.2[/tex]
The x intercept is [tex](6.2,0)[/tex]
y intercept [tex]x=0[/tex]
[tex]2\times 0+4y=12.4\\\Rightarrow y=\dfrac{12.4}{4}\\\Rightarrow y=3.1[/tex]
The y intercept is [tex](0,3.1)[/tex]
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A fisherman yanks a fish vertically out of the water with an acceleration of 2.5! !! using very light fishing line that has a breaking strength of 22 n. the fisherman unfortunately loses the fish as the line snaps. what can you say about the mass of the fish?
Two forces act on the fish, and these are:
1) Its weight mg, downwards and
2) pressure in the string, T, upwards which is 22 N when the string breaks.
In the result of these two forces, the fish had an acceleration of 2.5 m/s^2 in
the upward way.
So, T - mg = m*2.5
=> m = T / (2.5 + g)
=> m > 22 / (2.5 + 9.8) ( when the string snaps )
=> m > 1.79 kg.
As a result, the mass of the fish is more than 1.79 kg as the line has been broken.
Considering Newton's second law of motion and the given parameters of force and acceleration, the fish that caused the fishing line to snap would have a mass of approximately 1.76 kg.
Explanation:In order to find out the mass of the fish in this scenario, we need to consider the principles of Newton's second law of motion, which states that the force exerting on an object is equal to the mass of the object multiplied by its acceleration (F=ma).
In this case, the force before the fishing line breaks is 22 N (Newtons), and acceleration due to gravity is 10 m/s² approximately. But as the fish is pulled out with an acceleration of 2.5 m/s², we consider total acceleration to be (10+2.5) m/s² = 12.5 m/s².
Making these substitutions into Newton's law, we will solve the equation to 22 N = m* 12.5 m/s², yielding the mass of the fish m = 22 N / 12.5 m/s² = 1.76 kg
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Explain how you can classify shapes, using the distance and slope formula. Provide an example
To classify shapes, one can use the distance formula to calculate the lengths of a shape's sides and the slope formula to determine angles between sides. Analyzing these measurements helps identify if a shape is a rectangle, square, etc., based on side length equality and perpendicular angles.
Classifying Shapes Using Distance and Slope Formulas
To classify shapes using the distance and slope formulas, you'll need to analyze the lengths of sides and the angles between them. The distance formula helps determine the length of sides by calculating the distance between two points. On the other hand, the slope formula is used to find the inclination of sides, which can indicate whether lines are parallel or perpendicular.
Here's an example. Suppose we have a quadrilateral with vertices at (1,1), (1,4), (5,4), and (5,1). We'd calculate the distance between consecutive vertices to determine if the sides are equal. If the distances are the same, our shape might be a square or a rectangle. Next, we calculate the slopes of adjacent sides using the formula (y2-y1)/(x2-x1) (rise over run). If the slopes of adjacent sides are negative reciprocals of each other, the lines are perpendicular, which is a characteristic of rectangles and squares.
Applying the slope formula to our example, the slope from (1,1) to (1,4) would be (4-1)/(1-1), which is undefined, suggesting a vertical line. Between (1,4) and (5,4), the slope is (4-4)/(5-1), which is 0, indicating a horizontal line. Therefore, the expected behavior for a square's or rectangle's sides is observed. By further calculating all side lengths and slopes, we could definitively classify our shape.
What do you get when you cross the Atlantic with the titanic
Titanic is no longer in existence, as it sank over a century ago and currently rests on the ocean floor.
If you are referring to combining the Atlantic Ocean with the Titanic, it would simply mean that the Titanic is traveling across the Atlantic Ocean.
The Titanic was a famous British passenger liner that sank in the North Atlantic Ocean on April 15, 1912, after hitting an iceberg during its maiden voyage from Southampton to New York City.
So, crossing the Atlantic with the Titanic would describe the journey of the Titanic as it sailed across the Atlantic Ocean.
However, it's important to note that the Titanic is no longer in existence, as it sank over a century ago and currently rests on the ocean floor.
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three times a number is three more than twice the number which equation can be used to find the value of X the unknown number
Answer:
3x = 2x + 3.
Step-by-step explanation:
In the question it has been given that three times a number is three more than twice the number.
Let the number is x.
Then by the given statement 3x = 2x + 3
So equation formed can be used to find the value of x
3x - 2x = 3
x = 3
Therefore, the number is 3 and equation to be solved for x is 3x = 2x + 3.
Calculate the mass of the prism give your answer in kilograms.
Which length is 10 6 times greater than a nanometer?
Find m < 4 and m < 3
Gregory has agreed to donate $250 to Spring Valley High School for its library. In addition, he will donate $5 for every book a student at Spring Valley School reads during the summer. The sequence shown represents the possible amounts that Gregory will be donating for the summer. 250, 255, 260, 265, 270, 275, … Write the above sequence as a function in the form f(x) = mx + b
Cameron is designing a calendar as a fund-raising project for math class. The cost of printing is $500, plus $2.50 per calendar. Write an equation in slope-intercept form that models the total cost of printing the calendars. Cameron estimates that the math class will sell 200 calendars. What will the total cost be?
What is the sum of the first five prime numbers?
Your friend says that the absolute value equation ∣3x + 8 ∣ − 9 = −5 has no solution because the constant on the right side of the equation is negative. Is your friend correct? Explain.
No, our friend is not correct because the absolute value equation has a solution.
Given that,
Friend says that the absolute value equation ∣3x + 8 ∣ − 9 = −5 has no solution because the constant on the right side of the equation is negative.
It is to justify whether our fried is correct or not.
Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.
Here,
|3x + 8 | - 9 = -5
| 3x + 8 | = -5 + 9
| 3x + 8 | = 4
3x + 8 = ± 4
x = (-8 ± 4) / 3
Here, it can be seen that the given aboslute value equation has the solution that implies our friend is wrong.
Thus, no, our friend is not correct.
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Line l contains points (11,-1) and (-3,-11). Point P has coordinates (-1,1). Find the distance from P to l
Distance from point (-1,1) to line l: [tex]\( \frac{60}{\sqrt{74}} \)[/tex] units.
To find the distance from point P to line l, we can use the formula for the distance between a point and a line in the coordinate plane.
The formula to find the distance from a point (x1, y1) to a line Ax + By + C = 0 is given by:
[tex]\[ \text{Distance} = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}} \][/tex]
Where A, B, and C are the coefficients of the equation of the line, and (x1, y1) are the coordinates of the point.
First, let's find the equation of the line passing through the points (11, -1) and (-3, -11).
The slope of the line, m, can be calculated using the formula:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
[tex]\[ m = \frac{-11 - (-1)}{-3 - 11} = \frac{-11 + 1}{-3 - 11} = \frac{-10}{-14} = \frac{5}{7} \][/tex]
Now, we have the slope of the line. We can use the point-slope form of the equation of a line:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
Using one of the given points, let's say (11, -1):
[tex]\[ y - (-1) = \frac{5}{7}(x - 11) \][/tex]
[tex]\[ y + 1 = \frac{5}{7}(x - 11) \][/tex]
Now, let's convert this equation into the standard form Ax + By + C = 0:
[tex]\[ \frac{5}{7}x - y - \frac{5}{7} \cdot 11 + 1 = 0 \][/tex]
[tex]\[ \frac{5}{7}x - y - \frac{55}{7} + 1 = 0 \][/tex]
[tex]\[ \frac{5}{7}x - y - \frac{55}{7} + \frac{7}{7} = 0 \][/tex]
[tex]\[ \frac{5}{7}x - y - \frac{48}{7} = 0 \][/tex]
Now, we have the equation of line l:[tex]\(\frac{5}{7}x - y - \frac{48}{7} = 0\)[/tex]
Now, we can plug in the coordinates of point P (-1, 1) into the formula for the distance:
[tex]\[ \text{Distance} = \frac{| \frac{5}{7}(-1) - 1 - \frac{48}{7} |}{\sqrt{(\frac{5}{7})^2 + (-1)^2}} \][/tex]
[tex]\[ = \frac{| -\frac{5}{7} - 1 - \frac{48}{7} |}{\sqrt{\frac{25}{49} + 1}} \][/tex]
[tex]\[ = \frac{| -\frac{5}{7} - \frac{7}{7} - \frac{48}{7} |}{\sqrt{\frac{25 + 49}{49}}} \][/tex]
[tex]\[ = \frac{| -\frac{60}{7} |}{\sqrt{\frac{74}{49}}} \][/tex]
[tex]\[ = \frac{\frac{60}{7}}{\frac{\sqrt{74}}{7}} \][/tex]
[tex]\[ = \frac{60}{\sqrt{74}} \][/tex]
So, the distance from point P to line l is [tex]\(\frac{60}{\sqrt{74}}\)[/tex] units.
8 people are about to board a plane. In how many ways can this be done?
The Graduate Record Examinations are widely used to help predict the performance of applicants to graduate schools. The range of possible scores on a GRE is 200 to 900. The psychology department at a university finds that the scores of its applicants on the quantitative GRE are approximately normal with mean = 544 and standard deviation = 103. Use your calculator or computer to find the relative frequency of applicants whose score X satisfies the following conditions: (As part of your answer, draw a standard normal curve and shade the area under the curve that represented the answer to the question; do this on scratch paper and provide a one-sentence description for the assignment).
X < 500
To find the relative frequency of applicants whose score X is less than 500 on the quantitative GRE, calculate the Z-score for 500 and find the corresponding area under the standard normal curve.
Explanation:To find the relative frequency of applicants whose score X is less than 500, we need to calculate the Z-score for 500. The formula for calculating the Z-score is: Z = (X - mean) / standard deviation. Plugging in the values, we get Z = (500 - 544) / 103 = -0.427.
Next, we need to find the corresponding area under the standard normal curve for the Z-score of -0.427. Using a calculator or a standard normal table, we find that the area to the left of -0.427 is approximately 0.3356.
Therefore, the relative frequency of applicants whose score is less than 500 is 0.3356, or 33.56%.
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WHAT IS 9.24 DIVIDE BY 15.4
Mika’s gym allows her to bring 3 guests for free. After the first three, she must pay $7 per guest. How many guests, g, can she bring to the gym if she pays $42? Three of these equations give the correct value of g. Which equation does NOT?
7g = 63
7(g – 3) = 42
7g – 3 = 42
g = 9
Answer:
[tex]7\cdot g-3 = 42[/tex]
Step-by-step explanation:
As the first three guest are three and each aditional guest costs $ 7 dollars. The formula is presented as follows:
[tex]7\cdot (g-3) = 42[/tex]
Or:
[tex]7\cdot g = 63[/tex]
Or:
[tex]g = 9[/tex]
The wrong equation is:
[tex]7\cdot g-3 = 42[/tex]
Use technology and the given confidence level and sample data to find the confidence interval for the population mean muμ. assume that the population does not exhibit a normal distribution. weight lost on a diet:weight lost on a diet: 99 % confidence 99% confidence n equals 61n=61 x overbar equals 2.0 kgx=2.0 kg s equals 4.8 kg
The given in this problem are:
99% confidence level
N = 61
Mean = 2.0 kg
Standard deviation = 4.8
Z value for a 9% confidence interval is 2.576
Confidence Interval = mean ± Z s/ sqrt n
= 2.0 ± 2.576(4.8/sqrt 61)
=2.0 ± 2.576 (0.6145770236779006736364371988794)
= 2.0 ± 1.5832
= 0.4168 < x < 3.5832
La dirección del colegio a efectuado compras de 2 tipos de tizas en iguales, cantidades, los profesores usan en la clase 5/6 de un tipo y los 3/4 de otro tipo ¿ Que fracción de la cantidad quedo sin usar?
A bag contains 6 red balls and blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.
Another way is to note that there are (104)(104) (“10 choose 4”) ways to select 4 balls from a collection of 10. If 4 of those 10 balls are “special” in some way (in this case, “special” = “red”), then the number of ways to choose 4 special balls is (44)(44). (The factor of (60)(60) is included to convey that, after choosing 4 special balls, we choose none of the 6 non-special balls.) This line of reasoning gives the second expression.