There are 150 marigold plants in a back yard. Each month, the number of marigold plants decreases by 15%. There are 125 sunflower plants in the back yard. Each month, 8 sunflower plants are removed. Part A: Write functions to represent the number of marigold plants and the number of sunflower plants in the back yard throughout the months. (4 points) Part B: How many marigold plants are in the back yard after 3 months? How many sunflower plants are in the back yard after the same number of months? (2 points) Part C: After approximately how many months is the number of marigold plants and the number of sunflower plants the same? Justify your answer mathematically. (4 points)

Answers

Answer 1

To solve this problem, let us first assign variables. Let us say that:

X = number of marigold plants

Y = number of sunflower plants

n = number of months

We can see that in the given problem, X is decreasing by a percentage, this means that we have to set-up a geometric equation while for Y the decrease is linear so we set-up an arithmetic equation.

 

Part A.

For marigold plants X, a geometric sequence has a general form of:

X = Xo * (1 + r)^n

where r = -15% = -0.15   (negative since it is decreasing)

Xo = the initial amount of marigold plants = 150

X = 150 * (1 – 0.15)^n

X = 150 (0.85)^n

 

For the sunflower plants Y, an arithmetic sequence has a general form of:

Y = Yo + d * n

where d = -8 and Yo = 125

Y = 125 – 8 n

 

Part B. For n = 3

 

X = 150 (0.85)^3 = 92.12 = 92

 

Y = 125 – 8 (3) = 101

 

Part C. From Part B we see that the two values are very far from each other when n = 3, therefore they must be similar when n < 3. So we try n = 2

 

X = 150 (0.85)^2 = 108.38 = 108

 

Y = 125 – 8 (2) = 109

 

Therefore the two plants have approximately similar amount after 2 months.


Related Questions

A quadratic function and an exponential function are graphed below. Which graph most likely represents the exponential function? graph of function t of x is a curve which joins the ordered pair 0, 1 and 1, 3 and 3, 27. Graph of function p of x is a curve which joins the ordered pair 0, 2 and 1, 3 and 3, 11 and 5, 27 and 6, 38

Answers

Using the given points, I was able to graph the functions t(x) and p(x) as shown in the picture. The difference between a quadratic function and an exponential is the degree of the equation. The quadratic equation has a degree of 2 while that of an exponential function is a degree raised to a variable. For better illustration, I would provide examples:

Quadratic equation: y = 2x²+5
Exponential equation: y = 2³ˣ

If you would test it quantitatively the rate of change, or the slope, between points is greater for exponential than quadratic equations. Because a slight increase in x, will cause an exponential rise, To you observe visually if the slope is greater if the curve is closer to a vertical line. From the picture, we can see that the blue curve has a greater slope. Therefore, the exponential function is t(x).

Final answer:

The function t(x) with ordered pairs (0, 1), (1, 3), and (3, 27) most likely represents the exponential function because it shows rapidly increasing growth rates, which is a defining feature of exponential behavior.

Explanation:

The function that most likely represents the exponential function is the one whose growth rate increases significantly for larger values of x. Examining the ordered pairs, the function t(x), which passes through the points (0, 1), (1, 3), and (3, 27), clearly demonstrates this behavior as the increase between the y-values gets dramatically larger as x increases.

This is a classic characteristic of exponential growth. In contrast, the function p(x) that passes through (0, 2), (1, 3), (3, 11), (5, 27), and (6, 38) shows a more consistent increase in y-values as x increases, indicative of a quadratic function.

The volumes of two similar figures 27mm^3 and 1331mm^3. If the surface area of the smaller figure is 18mm^2, what is the surface area of the larger figure

Answers

[tex]\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{ccccllll} &Sides&Area&Volume\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array} \\\\ -----------------------------\\\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{small}{large}\qquad \cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\qquad thus\qquad \cfrac{\sqrt[3]{27}}{\sqrt[3]{1331}}=\cfrac{\sqrt{18}}{\sqrt{a}} \\\\\\ \cfrac{3}{11}=\sqrt{\cfrac{18}{a}}\implies \left( \cfrac{3}{11} \right)^2=\cfrac{18}{a}\implies \cfrac{3^2}{11^2}=\cfrac{18}{a}\implies a=\cfrac{11^2\cdot 18}{3^2}[/tex]

and surely, you know how much that is.

Branliest and 30 points to who answers first
To make one dose chispa put 2 drops of a herbal remedy into a 30 ml bottle and adds spring water he has now used 54 drops of the 120 that the full bottle contained how many more times can chispa use his herbal remedy

Answers

Assuming that the bottle contained only herbal remedy, we have 120-54=66. 66/2=33 uses left

Generally, how would one work out the surface area of a frustum?

Answers

see the formula in the picture

R is larger diameter, r is smaller diameter

A number is chosen at random from the integers between 11 and 99, inclusive. what is the probability that the number contains the digit 2?

Answers

18 out of 88 or 20% chance

The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle?

Answers

multiply 4 by the cos(45)

4 x cos(45) = 2sqrt(2) approximately 2.828cm

so depending how you are supposed to answer, either 2 sqrt(2) or approximately 2.83 cm

A chi-square test involves a comparison between what is observed and what would be expected by _______.

Answers

I believe the correct word to fill in the blank would be "chance". A chi-square test involves a comparison between what is observed and what would be expected by chance. It tests the the observed values and the values that are expected theoretically. The chi-square test is a statistical tool where the distribution of sampling is considered as a chi squared distribution when the null hypothesis is found to be true. There are two types of this test namely the chi-square goodness of fit test  and chi-square test for independence. The former type tests a data whether it matches the population while the latter assess two variables using a contingency table testing if a relation is present.

write the square root of 23 in exponential form

Answers

[tex]\sqrt[n]{x^m}=x^\frac{m}{n}[/tex]
so
[tex]\sqrt{23}=\sqrt[2]{23^1}=23^\frac{1}{2}[/tex]
The answer is 23 to the power of 1/2.

Solve the problem by writing an inequality. A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T-shirt to make the T-shirts. Write and solve an equation to find how many T-shirts the club needs to make and sell in order to profit at least $100. Show your work.

Answers

An algebraic equation containing an inequality may contain symbols such as <, >, ≤ and ≥. You should know the concept of profit first. Profit is the net income you acquired by getting the total revenue, and subtracting from it all the fixed and variable costs. So, in equation, that would be

Profit = Revenue - (Fixed Cost + Variable Cost)

You should note that the limit for profit is at least $100. So that means it can be more than $100 but can't be less than. Therefore, the symbol to be used is greater than or equal to, symbolized by ≥. Then the equation is

12x - (20 + 8x) ≥ 100, where x represents the minimum number of t-shirts to reach a profit of at least $100. Solving the equation,

12x - 20 - 8x ≥ 100
12x - 8x ≥ 100 + 20
4x ≥ 120
x ≥30

Therefore, the club needs to sell at least 30 shirts.

It doesn't matter which of the two points on a line you choose to call (x1, y1) and which you choose to call (x2, y2) to calculate the slope of the line.

A. True
B. False

Answers

ANSWER

A. True

EXPLANATION

Let

[tex](x_1,y_1) = (1,2)[/tex]



and

[tex](x_2,y_2) = (2,3)[/tex]


be two points on the straight line.

Then the slope is given by

[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]


This implies that,

[tex]m = \frac{3 - 2}{2 - 1} = \frac{1}{1} = 1[/tex]

Let us now choose it the other way round,


[tex](x_1,y_1) = (2,3)[/tex]
[tex](x_2,y_2) = (1,2)[/tex]


Then the slope is,

[tex]m = \frac{2 - 3}{1 - 2} = \frac{ - 1}{ - 1} = 1[/tex]

We still had they same result. Hence it doesn't matter which one you choose to call

[tex](x_1,y_1)[/tex]
and which to call

[tex](x_2,y_2) [/tex]

Answer:

the answer is true

Step-by-step explanation:

it's what I got

17. Evaluate. Show your work.
a. 6!

b. 6P5


c. 12C3

Answers

[tex]6!=1\cdot2\cdot3\cdot4\cdot5\cdot6=720\\\\ 6P5=\dfrac{6!}{1!}=6!=720\\\\ 12C3=\dfrac{12!}{3!9!}=\dfrac{10\cdot11\cdot12}{2\cdot3}=220[/tex]

In a binomial experiment the probability of success is 0.06. What is the probability of two successes in seven trials? a. 0.0554

Answers

Final answer:

For two successes in seven binomial trials with a success probability of 0.06, use the binomial probability formula. Calculate (7 choose 2) * (0.06^2) * (0.94^5) to get the probability of 0.0554.

Explanation:

To calculate the probability of two successes in seven trials with a success probability of 0.06, you can use the binomial probability formula, which is P(X = k) = (n choose k) * p^k * q^(n-k), where 'n' is the number of trials (7), 'k' is the number of successes (2), 'p' is the probability of success (0.06), and 'q' is the probability of failure (q = 1 - p = 0.94).

First, calculate the binomial coefficient using 'n choose k', which is (7 choose 2). Then, raise the probability of success to the power of the number of successes (0.06^2) and the probability of failure to the power of the number of failures (0.94^5). Lastly, multiply these values together to get the probability.

The calculation is as follows:

(7 choose 2) * (0.06^2) * (0.94^5) = 21 * 0.0036 * 0.7339 = 0.0554

I am confused about this question in trigonometry:

Answers

use AE and CE to find the angle

AE = 20, CE = 6

 so the angle FOR CAE = tan^-1(6/20) = 16.7 degrees

 to Find DF

a^2 = b^2 +c^2-2abcos(A)

a^2 = 10^2 + 14^2 -2(14)(10)cos(16.7)

a^2 = 30

sqrt((30)=5.47 rounded to 5.5

EF =

a^2 = b^2 +c^2-2abcos(A)

a^2 = 20^2 + 14^2 -2(14)(20)cos(16.7)

a^2 = 64

sqrt(64)=8


A country population in 1991 was 231 million in 1999 it was 233 million . Estimate the population in 2003 using the exponential growth formula. Round you answer to the nearest million

Answers

p(y)=ir^t

233=231r^(1999-1991)

(233/231)^(1/8)=r

p(y)=231(233/231)^((y-1991)/8)  so in 2003

p(2003)=231(233/231)^((2003-1991)/8)

p(2003)=231(233/231)^(1.5)

p(2003)=234

So 234 million (to the nearest million people)


Answer:

population in 2003 is 234 million.

Step-by-step explanation:

A country's population in 1991 was 231 million

In 1999 it was 233 million.

We have to calculate the population in 2003.

Since population growth is always represented by exponential function.

It is represented by [tex]P(t)=P_{0}e^{kt}[/tex]

Here t is time in years, k is the growth constant, and  is initial population.

For year 1991 ⇒

233 = [tex]P_{0}e^{8k}[/tex] = 231 [tex]e^{8k}[/tex]

[tex]\frac{231}{233}= e^{8k}[/tex]

Taking ln on both the sides ⇒

[tex]ln(\frac{233}{231})=lne^{8k}[/tex]

ln 233 - ln 231 = 8k  [since ln e = 1 ]

5.451 - 5.4424 = 8k

k = [tex]\frac{0.0086}{8}=0.001075[/tex]

For year 2003 ⇒

[tex]P(t)=P_{0}e^{kt}[/tex]

P (t) = 231 × [tex]e^{(0.001075)(12)}[/tex]

     = 231 × [tex]e^{0.0129}[/tex]

     = 231 × 1.0129

     = 233.9 ≈ 234 million

Therefore, population in 2003 is 234 million.

parallel lines r and s are cut by two transversals, parallel lines t and u

Answers

its not c or d for sure 

i believe it is b
its a <5 and <13 that is the right answer

PLEASE HELP!!!! Solve the equation. Check for extraneous solutions. Type your answers in the blanks. Show your work.


x = _____ or _____

Answers

|4x+3|=9+2x  if we square both sides, we can eliminate the absolute values signs...

16x^2+24x+9=81+36x+4x^2  subtract the right side from both sides

12x^2-12x-72=0  now we can factor

12(x^2-x-6)=0

12(x^2+2x-3x-6)=0

12(x(x+2)-3(x+2)=0

12(x-3)(x+2)

So:

x= -2 or 3


Answer:  

-3

Step-by-step explanation:

Where does the normal line to the parabola, given below, at the given point, intersect the parabola a second time? illustrate with a sketch. (round the answers to three decimal places.) y = 4 x - 2 x^ 2 p = (2, 0)?

Answers

The graph of the parabola when sketched is shown in the picture illustrated as the blue curve. If you want to find the normal line to the parabola at point (2,0), you want to find the line perpendicular to the curve at that certain point. Note that two equations are perpendicular to each other when the product of their slopes is equal to -1. With that, let's find the slope of the parabola at point (2,0). The slope can be determined by finding the first derivative of the equation and substituting the x-coordinate of the point.

y' = 4 - 4x = 4-4(2) = -4
Thus, the slope of the normal line is 1/4 (negative reciprocal of -4). Its equation would be y = 1/4 x + b. To find b (y-intercept), substitute the coordinates of point (2,0):

0 = 1/4 (2) + b
b = -0.5

Therefore, the equation of the normal line is y = 1/4 x - 0.5. This is illustrated as the orange line in the picture.

Can someone please help me with math for college readiness

Answers

6.79,7.729,31/4,7+5/6
it is best to start by converting all to decimals. so 7 5/6= 7.8333 and 31/4=7.75
o in order of least to greatest it is 6.79, 7.729, 31/4, 7 5/6.

Has 320 yards of fencing to enclose a rectangular area. find the dimensions of the rectangle that maximize the enclosed area. what is the maximum​ area

Answers

The dimensions of the rectangle that maximize the enclosed area are L = 80 yards and W = 80 yards. The maximum area is A = 80 * 80 = 6400 square yards.

To find the dimensions of the rectangle that maximize the enclosed area using 320 yards of fencing, we'll use the concept of optimization. Let's solve it step by step:

Let's assume the length of the rectangle is L and the width is W.

Perimeter constraint:

The perimeter of the rectangle is given as 2L + 2W, which must equal 320 yards:

2L + 2W = 320

Simplify the perimeter equation:

Divide both sides by 2 to get:

L + W = 160

Express one variable in terms of the other:

Solve the equation for L:

L = 160 - W

Area equation:

The area of the rectangle is given by A = L * W.

Substitute the value of L from the previous step into the area equation:

A = (160 - W) * W

A = 160W - W^2

Maximize the area:

To find the maximum area, we need to maximize the function A = 160W - W^2. This is achieved when the derivative is zero.

Take the derivative of A with respect to W:

dA/dW = 160 - 2W

Set dA/dW = 0 and solve for W:

160 - 2W = 0

2W = 160

W = 80

Substitute the value of W back into the perimeter equation to find the corresponding value of L:

L = 160 - W = 160 - 80 = 80

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Final answer:

The optimization problem involves finding the dimensions of a rectangle to maximize its area using a fixed amount of fencing. The dimensions that maximize the area are both 80 yards, making the maximum area 6400 square yards.

Explanation:

The subject of this question is Mathematics, specifically a problem about optimization in the field of Calculus. In the given problem, we wish to find a rectangular area that can be enclosed by 320 yards of fencing that maximizes the area.

Let's designate the rectangular area's width and length as x and y respectively. The problem can now be rephrased. With the total length of fencing equal to 320 yards, you can express this as 2x + 2y = 320. Simplifying this equation, we get x + y = 160, or y = 160 - x.

The area of a rectangle is computed as width times length, or in this case, x(160 - x). This is a quadratic function, and its maximum value happens at the vertex of the parabola defined by this function. For a quadratic in standard form like y = ax^2 + bx + c, the x-coordinate of the vertex is at -b/2a. In this case, the maximum area happens when x = 160/2 = 80.

Substituting this value back into the equation for the rectangle's dimensions gives y = 160 - 80 = 80. So, the dimensions that maximize the area for a rectangle with a parameter of 320 yards are both 80 yards. Therefore, the maximum area possible is 80*80 = 6400 square yards.

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Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2



***PLEASE HELP**

Answers

Given that
[tex]a_{n+1}=-4a_{n+2}[/tex] and [tex]a_1=2[/tex]

For n = 0,
[tex]a_1=-4a_2 \\ \\ 2=-4a_2 \\ \\ \Rightarrow a_2=-\frac{1}{2}[/tex]

common ratio = [tex]\frac{a_2}{a_1}=\frac{-\frac{1}{2}}{2}=-\frac{1}{4}[/tex]

4th term = [tex]a_4=a_1r^{4-1}=2(-\frac{1}{4})^3=2(-\frac{1}{64})=-\frac{1}{32}[/tex]

What is the slope of the line shown below?

Answers

Answer:

correct option is B) 2

Step-by-step explanation:

Slope of line is calculated by formula :-

Suppose two points on line are [tex](x_1, y_1) and (x_2 ,y_2)[/tex] then slope 'm' is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex].

We can see two points on line of graph are :- (-1, -4) and (2,2)

then slope will be calculated as,

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

since [tex]x_1 = -1, x_2 =2, y_1=-4\;and\; y_2=2[/tex]

now, put in formula

[tex]m=\frac{2-(-4)}{2-(-1)}[/tex]

[tex]m=\frac{2+4}{2+1}[/tex]

[tex]m=\frac{6}{3}[/tex]

[tex]m=2[/tex]

Hence, slope is 2 of the provided graph.

Therefore, correct option is B) 2

A survey asked 30 people what their favorite genre of television broadcasting was, and the results were tabulated above. Find the probability that a person chosen at random was female, given that they like comedy. Round the answer to the nearest hundredth.

Answers

The probability that a person chosen at random is female, given they like comedy, is approximately 0.53 or 53% .

First, let's find the total number of females who like comedy. In the Venn diagram, there are 8 females who like comedy. There are also 7 males who like comedy. So, there are 15 people who like comedy in total.

Next, we need to determine the total number of females. There are 16 females who like drama, and 4 females who like sports. Adding these together, we get 20 females in total.

Now, we can calculate the conditional probability that a female likes comedy given that she was chosen at random. The formula for conditional probability is P(A|B) = P(AnB) / P(B). In this case, event A is "being female" and event B is "liking comedy."

P(A|B) = (Number of females who like comedy) / (Total number of people who like comedy)

P(A|B) = 8 / 15

To express this as a percentage, multiply by 100:

P(A|B) * 100 ≈ 0.5333

Rounded to the nearest hundredth, the probability is 0.53 or 53%.

The probability that a person chosen at random is female, given they like comedy, is approximately 0.53 or 53% .

First, let's find the total number of females who like comedy. In the Venn diagram, there are 8 females who like comedy. There are also 7 males who like comedy. So, there are 15 people who like comedy in total.

Next, we need to determine the total number of females. There are 16 females who like drama, and 4 females who like sports. Adding these together, we get 20 females in total.

Now, we can calculate the conditional probability that a female likes comedy given that she was chosen at random. The formula for conditional probability is P(A|B) = P(AnB) / P(B). In this case, event A is "being female" and event B is "liking comedy."

P(A|B) = (Number of females who like comedy) / (Total number of people who like comedy)

P(A|B) = 8 / 15

To express this as a percentage, multiply by 100:

P(A|B) * 100 ≈ 0.5333

Rounded to the nearest hundredth, the probability is 0.53 or 53%.

A researcher wishes to find out whether giving a student $1 million in cash will improve or ruin the student's grades in school. A high school class consists of the 8 students numbered in the following list. 0 Juanita 1 Tuan 2 Harry 3 Greta 4 William 5 Hiroshi 6 Betty 7 Jane Help the researcher by using the line from a table of random numbers (shown below) to assign 4 of these students to the treatment group. 39661 55832 02589 52612 25414 19879 60880 30641 55259 35324 Which students go in the treatment group?

Answers

Answer:

Greta, Betty, Tuan and Hiroshi

Step-by-step explanation:

Start from the beginning:

3 - Greta

Then, continue with the next numbers:

9 -  skip (there is no student numbered with a 9)

6 - Betty

6 - skip (Betty is already chosen)

1 - Tuan

5 - Hiroshi  

What is the area for this problem?

Answers

It's 324pi since the circumference is 2 pi r, you can divide 36 by 2 to find the radius, after finding the radius plug it into the area equation which is pi r^2

C = 2* pi *r = 36 pi

 r = 36pi/2pi = 18

We know that A= r^2 * pi

A = 18^2 * pi = 324 pi

the area would be 324PI square units



The area of a certain rectangle is 288 yd2. the perimeter is 68 yd. what are the dimensions of the rectangle?

Answers

P = 2(L + W)
P = 68
68 = 2(L + W)
68/2 = L + W
34 = L + W
34 - L = W

A = L * W
A = 288
W = 34 - L

288 = L(34 - L)
288 = 34L - L^2
L^2 - 34L + 288 = 0
(L - 16)(L - 18)

L - 16 = 0
L = 16

L - 18 = 0
L = 18

not exactly sure which (length or width) , but one is 16 yds and one is 18 yds

The dimensions of the rectangle are a length of 16 yds and a width of 18 yds.

What is the area of the rectangle?

The area of a rectangle is defined as the product of the length and width.

The area of a rectangle = L × W

Where W is the width of the rectangle and L is the length of the rectangle

Given that the perimeter is 68 yd

We know that the perimeter of a rectangle is:

P = 2(L + W)

∴ P = 68

68 = 2(L + W)

68/2 = L + W

34 = L + W

34 - L = W ....(i)

The area of a rectangle is:

A = L × W ....(ii)

∴ A = 288

Substitute the value W = 34 - L in equation (ii), and solve for L

288 = L(34 - L)

288 = 34L - L²

L² - 34L + 288 = 0

(L - 16)(L - 18)

L - 16 = 0 and L - 18 = 0

L = 16 and L = 18

Take L = 16 and substitute the value in the equation (i)

So, W = 34 - 16 = 18

Therefore, the rectangle's length is 16 yds and its width is 18 yds.

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Solve △ABC if B=120°, a=10, c=18

Answers

[tex]b= \sqrt{a^2+c^2-2ac*cosB} = \sqrt{10^2+18^2-2*10*18*(-0.5)} = \\ = \sqrt{100+324+180}= \sqrt{604} \approx 24.58 \ units \\ \\ \\ \frac{b}{sinB} =\frac{a}{sinA} \ \ \to sinA= \frac{a*sinB}{b}= \frac{10*0.866}{24.58} \approx 0.3523 \ \to \ \angle{A} \approx 20.63^o \\ \\ \\ \angle{C}=180-120-20.63=39.37^o \\ \\ \\ Area= \frac{1}{2}ch \\ \\ h=a*sinB=10*sin120^o=10* 0.866=8.66 \ units \\ \\ Area= \frac{1}{2}*18*8.66=77.94 \ units^2[/tex]

Write the total population of india and china.estimate the total population by rounding off each population to nearest 100000

Answers

As of Thursday, August 17, 2017, based from the data of the latest United Nations estimates, the current population of China is 1,388,979,446.


China’s population is equivalent to 18.47% of the total world population.


18.47% of the total world population is composed by China’s population.


China is ranked number 1 in the list of countries by population.


Rounding that number off to the nearest 100,000, it would be 1,388,980,000.

 

As of Thursday, August 17, 2017, based from the data of the latest United Nations estimates, the current population of India is 1,344,431,890.


17.86% of the total world population is composed by India’s population.


India is ranked number 2 in the list of countries by population.


Rounding that number off to the nearest 100,000, it would be 1,344,400,000.

Can you check my work please!! And don't joke about it! Thanks

Answers

1. 86
2. 44
3. 50
4. 86
5. 44
6. 50
7. 130
8. 50
9. 130
10. 50
11. 86
12. 94
13. 86
14. 94

Remember that the triangle's inner angles should equal 180 for angle 8 and that angles that form a straight line add to 180 as well.
If you would like an explanation for any of these, please comment down below.

1 oz of walnuts were mixed with 4 oz of peanuts which cost $4/oz to make mixed nuts which cost $5/oz. what is the price per oz of walnuts

Answers

Call w the unknwon price of the walnuts, then:

total cost of walnuts = 1oz *  w

Total cost of peanuts = 4 oz * $4/oz = $16

Total cost of nuts = 5oz * $5 /oz = $25

=> 1oz*w + $16 = $25 => w = ($25 - $16) /1oz = $9/oz

Verfify:

1oz * $9/oz + 4oz * $4/oz = $9 + $16 = $25, which is equal to 5oz * $5/oz.

Answer: $9 per oz.

What is the vertex of the graph of y + 2x + 3 = –(x + 2)2 + 1?

Answers

There are a lot of steps involved in this, so pay attention. First step is to expand the squared quantity and FOIL it out, like this:
[tex]y+2x+3=-(x+2)(x+2)+1[/tex] and
[tex]y+2x+3=- x^{2} -4x-4+1[/tex]
We are going to combine all the like terms now and get them all on one side of the equation:
[tex]- x^{2} -6x-6=y[/tex]
Now we are going to complete the square on the polynomial in order to find the vertex.  Do this by first setting the equation equal to 0 and then moving the constant over to the other side of the equals sign, like this:
[tex]- x^{2} -6x=6[/tex] and now factor out the negative sign (cuz negative signs are a pain):
[tex]-( x^{2} +6x)=6[/tex].  To complete the square, you take half the linear term, square it, and add it in to both sides.  Our linear term is 6x.  Half of 6 is 3, and 3 squared is 9.  That's easy to add in on the left side, but we cannot forget that fact that we factored out a negative 1, and that the negative 1 is still there and has to be taken into consideration when we "add" in a 9 to the other side.  We actually multiply the negative 1 times the 9 and that's what's added in to the right:
[tex]-( x^{2} +6x+9)=6-9[/tex]
What you do when you complete the square is create a perfect square binomial on the left, which we have and which looks like this:
[tex]-(x+3) ^{2} = -3[/tex]
When we move the 3 back over to be with its mates (the 3 is the y coordinate for the vertex), we have the actual sign of the y coordinate.  The number inside the parenthesis with the x is the x coordiante of the vertex in the form [tex](x-h) ^{2} [/tex].  So the vertex of your problem is (-3, 3).  The negative outside the parenthesis just indicates to us that the parabola is an upside down one, like a mountain instead of a valley.

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