The answer is False, not two factors there are many factors that affect our environment.
What are the factors affecting our environment?The surrounding where we live with all the needs, nature, food, air and our life needed things can be said to be environment. In this environment human were causing many unwanted and environment affecting things.
Factors affecting environment are as follows:
Through the natural factor, physically, chemically, mechanically and biologically the environment gets affected.Green space, clean water and clean air gets affected through human pollutants.Humans made pollutions by air, water, noise, soil , geothermal, etc...Also by the influence of humans, nature itself causes disasters because of the pollution.So, there are not only two factors that affect our environment.
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A nurse pushes a cart by exerting a force on the handle at a downward angle of 36 degrees below the horizontal. the loaded cart has a mass of 28kg, and the force of friction is 65 n. what is the magnitude of force the nurse must exert to move at a constant velocity in newtons?
The nurse's push must equate to the frictional force for the cart to move at a constant velocity. Since the push is at an angle, its horizontal component, which opposes friction, is calculated and set equal to the friction. Solving for the force exerted by the nurse yields the answer.
Explanation:This is a physics problem related to force, friction, and motion. To keep the cart at a constant velocity, the net force exerted on it must be zero, as per Newton's second law. This means that the frictional force, which opposes the direction of motion, should be equal to the applied force, which is the nurse's push.
The nurse's push is exerted at an angle, so we have to decompose it into horizontal and vertical components. The horizontal component is the one that actively works against the friction and it can be calculated using the formula: F_Horizontal = F_Nurse cos θ, where 'F_Nurse' is the force applied by the nurse and 'θ' is the angle of the push. Since this component must equal the frictional force, we can rearrange the equation and solve for 'F_Nurse': F_Nurse = Friction / cos θ. Plugging in the known values for friction (65 N) and angle (36 degrees), we can find the magnitude of force the nurse must exert to move the cart at a constant velocity in newtons.
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To move the cart at a constant velocity, the nurse must exert a force of approximately 79.3 Newtons at a downward angle of 35 degrees below the horizontal. The force of friction and the horizontal component of the nurse's force must be equal for the cart to move at a constant velocity.
Explanation:To calculate the force the nurse must exert to move the cart at a constant velocity, we need to consider the forces acting on the cart. In this case, the force of friction and the force exerted by the nurse are the main forces. The force exerted by the nurse can be broken down into horizontal and vertical components. The horizontal component of the force is responsible for overcoming the force of friction. Since the cart is moving at a constant velocity, the net force in the horizontal direction is zero. To find the magnitude of the force the nurse must exert, we can use trigonometry to find the horizontal component of the force.
The horizontal component of the force can be found using the equation:
F_h = F_n * cos(theta)
Where F_h is the horizontal component of the force, F_n is the total force exerted by the nurse, and theta is the angle of the force below the horizontal. Substituting the values into the equation, we get:
F_h = F_n * cos(35 degrees) = F_n * 0.819
Since the net force in the horizontal direction is zero, the horizontal component of the force must be equal to the force of friction. Therefore, we can write the equation:
F_h = F_f = 65 N
Substituting the value of the force of friction and the expression for the horizontal component of the force, we can solve for the magnitude of the force the nurse must exert:
F_n * 0.819 = 65 N
F_n = 65 N / 0.819 = 79.3 N
The nurse must exert a force of approximately 79.3 Newtons to move the cart at a constant velocity.
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What is the upward force of the floor on the toes of one foot?
The upward force exerted by the floor exists equivalent to the downward force that the toes apply to the floor.
What is ment by an upward force?
The overall force acting on an item vertically is measured by an upward force. Usually, this is calculated by deducting the total upward force from the total force caused by gravity.
The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force. A body submerged partially or completely in a fluid appears to shed weight or to be lighter, due to the buoyant force.
Every action contains a corresponding and opposite response, according to Newton's Third Law of Motion. The forces of action and response do not affect the same body. This law can be utilized to define if the floor exerts any force on a person's feet.
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Your tongue and nose do not affect the functions of each other.
True or False ?
Answer:true
Explanation:
As shocking as it might be your nose and tongue some what function the same but for a question like this the answer would be true.
An instrument that measures and detects vibrations in earth is known as a _______.
A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result? A) law of differential mass B) law of conservation of momentum C) law of unequal forces D) law of accelerated collision
Hello!
A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result? A) law of differential mass B) law of conservation of momentum C) law of unequal forces D) law of accelerated collision
We have the following data¹:
ΔP (momentum before impact) = ?
mA (mass) = 10 kg
vA (velocity) = 5 m/s
mB (mass) = 5 kg
vB (velocity) = 0 m/s
Solving:
ΔP = mA*vA + mB*vB
ΔP = 10 kg*5 m/s + 5 kg*0 m/s
ΔP = 50 kg*m/s + 0 kg*m/s
Δp = 50 kg*m/s ← (momentum before impact)
We have the following data²:
ΔP (momentum after impact) = ?
mA (mass) = 10 kg
vA (velocity) = 0 m/s
mB (mass) = 5 kg
vB (velocity) = 10 m/s
Solving:
Δp = mA*vA + mB*vB
Δp = 10 kg*0 m/s + 5 kg*10 m/s
Δp = 0 kg*m/s + 50 kg*m/s
Δp = 50 kg*m/s ← (momentum after impact)
*** Then, which principle explains the result ?
Law of conservation of momentum, since the total momentum of body A and B before impact is equal to the total momentum of body A and B after impact.
Note: Bodies of different masses and velocities may have the same kinetic energy, if proportionality between the units is maintained it can occur that they have the same kinetic energy.
Answer:
B) law of conservation of momentum
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Determine the total number of energy states in silicon between ev and ev-3kt
A toy balloon is initially at a temperature of t = 20o
c. its initial volume is 0.0042 m3 (it is a 10 cm radius sphere). assume that the pressure in the balloon always equals atmospheric pressure, 101.3 kpa. 1) the balloon is lying in the sun, which causes the volume to expand by 6%. what is the new temperature, t? t =
which best explains why the electromagnetic force can be used to demonstrate how like charges behave when they come together
The correct answer is option d. Electromagnetism can repel which is why the electromagnetic force can be used to demonstrate how like charges behave when they come together.
Electromagnetic force, one of the fundamental forces in nature, governs the interactions between electrically charged particles. Like charges (charges of the same sign) experience a repulsive force when they come together, according to Coulomb's law.
This repulsion is a characteristic behavior of electromagnetic interactions, where positively charged particles repel other positively charged particles, and similarly for negatively charged particles.
Why other options are not correct:
Option a is incorrect because electromagnetic force is actually known for having an infinite range, meaning it acts over any distance, although its strength decreases with distance according to the inverse-square law.
Option b is not entirely accurate because while the range is effectively infinite, it does not explain why like charges behave a certain way.
Option c is incorrect because like charges do not attract; they repel each other.
The complete question:
Which best explains why the electromagnetic force can be used to demonstrate how like charges behave when they come together?
a. Electromagnetism has a very small range.
b. Electromagnetism has a infinite range.
c. Electromagnetism can attract.
d. Electromagnetism can repel.
Wastes are poisonous to a cell and must be removed from the cytoplasm. Predict how cell size could affect the removal process and the survival of a cell
Cell size negatively affects the efficiency of waste elimination due to the surface area to volume ratio. Diffusion, which is vital for nutrient intake and waste removal, is less effective in larger cells, leading to potential accumulation of toxic waste and free radicals. Therefore, cell size and shape are crucial for effective waste elimination and overall cell health.
Explanation:The size of a cell can have a significant impact on its ability to remove wastes and therefore on its survival. Cells require a balance between their surface area and volume to efficiently exchange substances with their environment. The surface area to volume ratio decreases as a cell grows, making it more difficult for substances to diffuse across the cell membrane at a rate necessary to maintain cell function. Diffusion is the primary mechanism through which cells take in nutrients and expel waste products. However, diffusion is only effective over short distances, hence the size of a cell is limited as large cells can potentially accumulate toxins or fail to acquire enough nutrients. Smaller cells, or cells with elongated or flattened shapes, have a higher surface area relative to their volume, allowing for more efficient waste removal and nutrient uptake.
Additionally, the build-up of waste products can be lethal to a cell, as these can interfere with cellular metabolism and lead to the production of harmful substances such as free radicals. These reactive chemicals can damage important molecules like DNA and contribute to diseases. Overall, the efficiency of waste elimination is crucial for the health and viability of a cell, and thus cell size and shape are critical to these processes.
The removal of waste from cells is less efficient in larger cells due to the increased distance substances must travel. This can result in toxic waste accumulation and impact cell survival. Cells adapt by maintaining a small size or a flattened shape to facilitate a more effective exchange of substances.
Explanation:The process of waste removal in cells is closely related to the size and shape of the cell. Larger cells have a bigger problem with waste accumulation because the distance travelled by waste products to the cell membrane is greater, leading to an inefficient removal process. This inefficiency can cause the accumulation of waste products, including toxic substances like free radicals, which can interfere with normal cellular metabolism and even lead to cell death. These toxic substances may contribute to diseases such as cancer and cardiovascular disease if not efficiently removed from the cell.
In contrast, smaller cells or those with a flattened shape have a larger surface area relative to their volume, which allows for easier and quicker exchange of nutrients and waste with their environment. This is because substances have a shorter distance to travel to reach or leave any part of the cell. Diffusion is more effective in these cells, facilitating timely nutrient uptake and waste elimination, crucial for the cell's survival.
Ultimately, if a cell grows too large, its ability to intake nutrients and expel waste effectively is compromised. Cells have adapted to this limitation by remaining small, flattening, or developing structures like microvilli that increase surface area. Furthermore, multicellular organisms have evolved complex systems like the circulatory and lymphatic systems to help transport substances to and from individual cells, thereby overcoming the limitations of diffusion over larger distances.
A 50-kg box is placed in the bed of a truck. the coefficient of static friction between the box and the truck bed is 0.54. if the truck is traveling at 100 km/h then calculate the minimum distance the truck can stop in without the box sliding into the cab.
The minimum distance the truck can stop in without the box sliding into the cab is equal to 77m.
What is the equation of motion?The equations of motion can represent the relation between the initial and final velocity, acceleration, displacement, and time of a moving object.
The equations of motions are usually represented as shown below:
[tex]v = u +at\\S = ut +\frac{1}{2}at^2\\v^2 -u^2 = 2aS[/tex]
Given, the final velocity of the truck, v = 100 Km/h
The third equation of motion: v²- u² = 2ad
v² - 0 = 2 × a × d
a = v²/2d
The coefficient of static friction between the box and the truck = 0.54
We know that, F = ma = [tex]\mu_{s}m g[/tex]
[tex]a = \mu_{s} g[/tex]
[tex]{\displaystyle \frac{v^2}{2d} = \mu_s g[/tex]
(100)²/2d = 0.54 × 9.8
d = 73 m
Therefore, the minimum distance the truck can stop is equal to 73m.
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What is the wavelength of a radio photon from an "am" radio station that broadcasts at 1080 kilohertz?
The wavelength of a radio photon from an AM radio station that broadcasts at 1080 kilohertz is approximately 27.8 centimeters.
Explanation:The wavelength of a radio photon from an AM radio station can be calculated using the formula:
wavelength = speed of light/frequency
Given that the frequency is 1080 kilohertz (or 1080,000 hertz), we need to convert it to megahertz (MHz) by dividing it by 1000. So the frequency is 1080 MHz.
Now, we can substitute the values into the formula:
wavelength = 3 x 10^8 meters per second / 1080 x 10^6 hertz
Performing the calculation, we get:
wavelength = 0.278 meters, or approximately 27.8 centimeters.
a beaker has a mass of 125g. What is the mass of this beaker in decigrams
A man starts walking north at 2 ft/s from a point p. five minutes later a woman starts walking south at 4 ft/s from a point 500 ft due east of p. at what rate are the people moving apart 15 minutes after the woman starts walking? (round your answer to two decimal places.)
To find the rate at which the man and woman are moving apart, calculate the distance each has traveled and add their speeds since they are moving in opposite directions. The man traveled 2400 ft and the woman 3600 ft in their respective times, and the rate at which they are moving apart 15 minutes after the woman starts walking is 6 ft/s.
The student's question involves determining the rate at which two people are moving apart after a certain amount of time has passed, with one walking north and the other south from different starting points. To solve this, we can use the concept of relative velocity in one dimension, as the paths of the man and the woman are perpendicular to each other.
Firstly, we calculate the distance the man has walked in 20 minutes (since he started 5 minutes before the woman). At 2 ft/s, he would have walked 2 ft/s × 1200 s = 2400 ft north of point P. The woman, having started 5 minutes later, would have walked for 15 minutes at 4 ft/s, so she would have walked 4 ft/s × 900 s = 3600 ft south of her starting point.
When calculating the rate at which they are moving apart, we need to consider the sum of their speeds as they are moving in opposite directions. The man's speed is 2 ft/s and the woman's speed is 4 ft/s, so the rate at which they are moving apart is 2 ft/s + 4 ft/s = 6 ft/s.
On the ride "spindletop" at the amusement park six flags over texas, people stood against the inner wall of a hollow vertical cylinder with radius 2.5 m. the cylinder started to rotate, and when it reached a constant rotation rate of 0.60 rev/s, the floor on which people were standing dropped about 0.5 m. the people remained pinned against the wall.
a) In this case the forces are the centrifugal force Fcp, which is directed horizontally toward the wall; the force of static friction Ff with the wall, directed upward; the normal force Fn by the wall, which is directed away the wall; the force of gravity Fg, directed downwards. Then we have that the horizontal forces are all equal in magnitude; similarly the vertical forces are also all equal in magnitude.
b) The minimum coefficient s occurs when force of gravity is equals the max friction force, that is
Fg = Ff,max
m g = s Fn
Also, the normal force has equal magnitude to the centrifugal force:
m g = s Fcp
m g = s m w^2 r
g = s w^2 r
s = g / (r w^2)
With values: g = 9.81 m/s^2; r = 2.5 m; and w = 2pi * 0.60 = 3.77 rad/s; we find
s = 9.81 / (2.5 * 3.77^2) = 0.276
The minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].
Further Explanation:
As the cylinder start to rotate, the people standing against the wall remain stick to the wall. So if we draw the free body diagram of the person, then we can see the balanced forces acting on person's body.
Given:
The rate of rotation of the cylinder is [tex]0.60\text{ rev}/\text{s}[/tex].
The radius of the cylinder is [tex]2.50\text{ m}[/tex].
Concept:
The friction force between the person’s body and the inner surface is balanced by the gravitational firce acting on the person's body.
[tex]\boxed{f_\text{friction}=f_\tect{gravity}}[/tex] ...... (1)
The force of friction acting on the person's body is:
[tex]f_\text{friction}=\mu N[/tex]
Here, [tex]N[/tex] is the normal reaction, [tex]\mu[/tex] is coefficient of static friction.
The gravitational force acting on the person's body is:
[tex]f_\text{gravity}=mg[/tex]
Here, [tex]m[/tex] is mass of the body, and [tex]g[/tex] is the acceleration due to gravity.
Substitute [tex]\mu N[/tex] for [tex]f_\text{friction}[/tex] and [tex]mg[/tex] for [tex]f_\text{gravity}[/tex] in equation (1).
[tex]{\begin{aligned}\mu N&=mg\\\mu&=\dfrac{mg}{N}\end{aligned}[/tex]
The Normal force acting on the person's body is balanced by the centrifugal force acting on the persion due to the rotation of the cylinder.
[tex]\boxed{f_\text{normal}=f_\text{centrifugal}}[/tex] ...... (2)
The centrifugal force acting on the person's body is:
[tex]f_\text{centrifugal}=m\omega^2r[/tex]
Here, [tex]\omega[/tex] is the angular speed of the cylinder, [tex]r[/tex] is the radius of the cylinder.
Substitute [tex]m\omega^2r[/tex] for [tex]f_\text{centrifugal}[/tex] in equation (2).
[tex]N=m\omega^2r[/tex]
Substitute the value of [tex]N[/tex] in equation of static friction coefficient.
[tex]\begin{aligned}\mu&=\dfrac{mg}{m\omega^2r}\\&=\dfrac{g}{\omega^2r}\end{aligned}[/tex]
The acceleration due to gravity on the surface of Earth is [tex]9.81\text{ m}/\text{s}^2[/tex].
The angular speed of rotation of the cylinder is given as:
[tex]\begin{aligned}\omega&=2\pi\times\text{Revolutions per second}\\&=2\pi\times0.6\\&=3.77\text{ rad}/\text{s}\end{aligned}[/tex]
Substitute the values of [tex]\omega[/tex], [tex]g[/tex] and [tex]r[/tex] in above expression.
[tex]\begin{aligned}\mu&=\dfrac{9.81}{(3.77)^2\times2.5}\\&=\dfrac{9.81}{35.53}\\&=0.276\end{aligned}[/tex]
Thus, the minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].
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Answer Details:
Grade: Senior school
Subject: Physics
Chapter: Circular motion
Keywords:
Amusement park, ride, spindle top, six flags, texas, vertical cylinder, hollow, 2.5m, 0.60 rev/s, dropped about, minimum static friction coefficient, rotation rate 0.60.
What is the potential energy of the two-spring system after the point of connection has been moved to position (x, y)? keep in mind that the unstretched length of each spring ℓ is much less than l and can be ignored (i.e., ℓ≪l). express the potential in terms of k, x, y, and l?
Answer:
P.E=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)
Explanation:
What is the potential energy of the two-spring system after the point of connection has been moved to position (x, y)? keep in mind that the unstretched length of each spring ℓ is much less than l and can be ignored (i.e., ℓ≪l). express the potential in terms of k, x, y, and l?
potential energy is equal to the kinetic energy
potential energy is energy at rest while kinetic energy is energy due to motion
P=U
P=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)
k=elastic constant of the pring system
x,y are the position
A farm tractor tows a 3300-kg trailer up a 14" incline with a steady speed of 2.8 m/s. what force does the tractor exert on the trailer ( ignore friction.)
The force exerted by the tractor can be calculated with the equation F = mg sin(θ), where m is the mass of the trailer, g is the acceleration due to gravity and θ is the incline angle. Substituting given values, we can find the value of force.
Explanation:The force that the tractor exerts on the trailer can be determined by using the principle of the forces in equilibrium. We can consider the component of the weight of the trailer acting down the slope (i.e. 3300 kg * 9.8 m/s² * sin(14°)) equal to the force exerted by the tractor.
So, the force exerted by the tractor F = mass * g * sin(θ)
Applying values into the equation: F = 3300 kg * 9.8 m/s² * sin(14°), we get the value of the force.
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To move the 3300-kg trailer up a 14° incline with a steady speed, the tractor must exert a force of about 12784.76 Newtons.
Explanation:In this physics problem, the tractor is doing work on the 3300-kg trailer by moving it up along an incline. The force the tractor must exert can be calculated using the formula F = mg sin(θ), where m is the mass of the trailer, g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and θ is the angle of the incline. Using the given mass of 3300 kg and an angle of 14 degrees (which should be converted to radians for the formula: 14°=0.24 radians), we find that the force required to move the load with a constant speed on the incline (no acceleration) is about 12784.76 Newtons.
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A deli owner creates a lunch special display board by taking a uniform board which has a weight of 217 n, cutting it in half, hinging the halves together with a frictionless hinge, and setting it up as an inverted "v". determine the minimum coefficient of static friction needed between the board and the ground in order for her to set the display board up with an angle of 30° between the two sides
The minimum coefficient of static friction needed for the deli owner to set up her display board with an angle of 30° between the two sides is 0.577.
Explanation:The problem asks for the minimum coefficient of static friction needed for the board to remain stable in a 'V' position. The forces acting on the board in this scenario would be gravity, which acts downward, and the force of static friction, which acts to prevent the board from sliding. The weight of the board acts at the center of gravity, which is at the midpoint of the height of the 'V'.
We need to consider the forces acting horizontally and vertically. Vertically, the total force must be zero, so the gravitational force (weight of the board) equals twice the vertical component of the force of friction. Horizontally, the net force must be zero as well, so the two horizontal forces of friction (one on each board) must balance each other.
Using the formula for the force of friction (friction = normal force x coefficient of friction), and knowing that for each side the normal force equals half the weight of the board, we can establish an equation and solve for the coefficient of friction.
Setting up these relationships, solving for the coefficient of friction gives us a value of tan(30°), which is 0.577. Thus, the minimum coefficient of static friction needed would be 0.577 to keep the board stable at an angle of 30°.
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As the wavelength increases, the frequency (2 points) decreases and energy decreases. increases and energy increases. decreases and energy increases. increases and energy decreases
Answer:
I TOOK THE TEST! the answer is INCREASES AND ENERGY INCREASES!
The mass of 29000 N elevator is
In this case we are given a force of 29,000 N. We know that the equation we can use is:
Force = mass * acceleration
However this is not just any type of force, because this is the weight of the elevator. So when the force is equal to weight, the acceleration acting is simply gravity. Therefore:
weight = mass * gravity
Calculating for mass:
mass = 29,000 N / (9.8 m/s^2)
mass = 2,959.18 kg
Heat transfer involving direct contact of particles
A seagull flies at a velocity of 9.00 m/s straight into the wind. if it takes the bird 20.0 min to travel 6.00 km relative to the earth, what is the velocity of the wind?
Final answer:
The velocity of the wind against the seagull is found to be 4.0 m/s. When the seagull turns around, it will take approximately 7.7 minutes to return the same distance of 6.00 km with the wind. Wind affects the round-trip time as it reduces and increases ground speed during different legs of the trip.
Explanation:
Calculating Wind Velocity and Round-Trip Time for a Seagull
A seagull flies at a velocity of 9.00 m/s straight into the wind. To find the velocity of the wind, we need to understand that the ground speed of the seagull is the difference between its airspeed and the wind's velocity since it's flying into the wind. Since it traveled 6.00 km in 20.0 min, we convert this to meters per second to get the ground speed, which is 300.0 m/s. Now we can set up the equation:
Ground speed = Air speed - Wind speed
300.0 m/s = 9.00 m/s - Wind speed
After solving, the wind speed is -4.0 m/s, which means the wind is blowing at 4.0 m/s in the opposite direction the seagull is flying.
If the bird turns around and flies with the wind, its ground speed will be the sum of its airspeed and wind speed. To find the time to return 6.00 km, we calculate:
Time = Distance / (Airspeed + Wind speed)
Time = 6000 m / (9.00 m/s + 4.0 m/s) = 461.54 seconds, or approximately 7.7 minutes to fly back with the wind.
Discussing the wind effect on round-trip time, we see that the wind increases the total time taken for a round trip due to the reduced ground speed when the seagull flies into the wind and a slightly less increased ground speed when flying with the wind, compared to no wind where the ground speed would be constant.
What is the crankshaft's angular acceleration at t=1s?
Why is the weight of an object more on Earth than on the Moon?
a.)The Moon is a satellite of Earth.
b.)The gravitational pull of the Moon is greater than that of Earth.
c.)The gravitational pull of Earth is greater than that of the Moon.
d.)The object’s mass is different on Earth and on the Moon.
Answer:
C
Explanation:
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What is the wave characteristic of stage 1 sleep
Stage 1 sleep is characterized by the transition from alpha waves to theta waves, indicating a light sleep state from which individuals can be easily awakened.
The wave characteristic of stage 1 sleep is predominantly marked by the presence of theta waves. Initially, as a person transitions from wakefulness to sleep, alpha waves are prevalent, characterized by their lower frequency (8-13 Hz) and higher amplitude. As stage 1 sleep progresses, theta waves, which have an even lower frequency (4-7 Hz) and higher amplitude, become more dominant.
These brain waves indicate that the individual is in a light sleep state, as it is quite easy to wake someone during this stage.
If you put a straw into a glass of water, the straw looks to be bent, although nothing has really happened to the straw. The term that describes this property of light is A) absorption. B) diffraction. C) reflection. D) refraction
Refraction is when the light is changes speed and bends as it travels from medium to another. The water slows down the light, and the image appears to bend.
The term that describes this property of light is Refraction. The correct option is D.
What is refraction?When a light ray falls on the interface of two medium like air and water, then the portion of light is reflected and another portion of the light is refracted into the water medium. The angle of incidence is equal to the angle of reflection but the angle of incidence is larger then the angle of refraction.
So, If you put a straw into a glass of water, the straw looks to be bent because of refraction of light into the water medium.
Refraction is when the light is changes speed and bends as it travels from medium to another. The water slows down the light, and the image appears to bend.
Thus, the correct option is D.
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it is known that a shark can travel at a speed of 15 m/s.how far can a shark go in 10 seconds?
it is known that a shark can travel at a speed of 15 meters/second then the shark can go 150 meters in 10 seconds.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second.
average speed = total distance /Total time
As given in the problem it is known that a shark can travel at a speed of 15 meters/second,
speed of the shark = 15 meters/second
time taken by the shark = 10 seconds
The total distance covered by the shark in 10 seconds = speed ×time
The total distance covered by the shark in 10 seconds = 15×10
= 150 metes
Thus, the shark can go 150 meters in 10 seconds.
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Jack tries to place magnets on the door of his refrigerator. He observes that the magnets don’t stick. He guesses that the door of the refrigerator is made of a nonmagnetic substance. What stage of scientific investigation does his guess represent?
What does each letter stand for in the formula p=v x i?
A runner with a mass of 80kg accelerates from 0 to 9 m/s in 3 s find the net force
An experiment is done to compare the initial speed of bullets fired from different handguns: a 9.0 mm and
a.44 caliber. the guns are fired into a 10-kg pendulum bob of length l. assume that the 9.0-mm bullet has a mass of 6.0 g and the .44-caliber bullet has a mass of 12 g . if the 9.0-mm bullet causes the pendulum to swing to a maximum angular displacement of 4.3∘ and the .44-caliber bullet causes a displacement of 10.1∘ , find the ratio of the initial speed of the 9.0-mm bullet to the speed of the .44-caliber bullet, (v0)9.0/(v0)44.
Answer: v1o/v2o=0.8518777161
Explanation:
using the equation from an answer in part A (https://brainly.com/question/14482074)
cancel out L and g and input the other variables in the ratio
((10kg+0.006kg)/0.006kg)sqrt(2(1-cos(4.3))) = 125.1276088 m/s = v1o
((10kg+0.012kg)/0.012kg)sqrt(2(1-cos(10.1))) = 146.8844723 m/s = v2o
v1o/v2o=0.8518777161