For an increase of 5 chirps per minute, the predicted increase in temperature is approximately 41.7 degrees Fahrenheit.
What is the predicted increase in temperature for an increase of 5 chirps per minute?In the given linear relationship model, the equation is:
T = 25.2 + 3.3x
Where:
T represents the estimated temperature in degrees Fahrenheit.
x represents the number of chirps per minute.
To find the predicted increase in temperature for an increase of 5 chirps per minute, you can simply plug in the value of x as 5 into the equation:
T = 25.2 + 3.3(5)
Now, calculate the result:
T = 25.2 + 16.5
T = 41.7
So, for an increase of 5 chirps per minute, the predicted increase in temperature is approximately 41.7 degrees Fahrenheit.
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The potential due to a point charge q at the origin may be written as v=q4πϵ0r=q4πϵ0x2+y2+z2√ part a calculate ex using equation ex=−∂v∂x.
Eₓ = [(qx) / [(4πϵ₀r)√(x² + y² + z²)³]
Further explanation
In this problem, we will solve the derivatives of the composite function. The formula used is the chain rule as follows.
[tex]\boxed{ \ If \ f(x) = h(g(x)) \ then \ f'(x) = h'(g(x)) \times g'(x) \ }[/tex]
In words: differentiate the outer function, then multiply it by the derivative of the innermost function.
Given:
[tex]\boxed{ \ V = \frac{q}{4 \pi \epsilon_0 r} \rightarrow V = \frac{q}{4 \pi \epsilon_0 r \sqrt{x^2 + y^2 + z^2}} \ }[/tex]
Question:
Calculate the x-component of electric field by using [tex]\boxed{ \ E_x = - \frac{\delta V}{\delta x} \ }[/tex]
The Process:
This case is a derivative application for electrostatics in physics.
The potential due to a point charge q at the origin may be written as
[tex]\boxed{ \ V = \frac{q}{4 \pi \epsilon_0 r \sqrt{x^2 + y^2 + z^2}} \rightarrow V = \frac{q}{4 \pi \epsilon_0 r}(x^2 + y^2 + z^2)^{-\frac{1}{2}} \ }[/tex]
The outside function is [tex] \boxed{ \ h(x) = \frac{q}{4 \pi \epsilon_0 r}(g(x))^{-\frac{1}{2}} \ } [/tex]The inside function is [tex]\boxed{ \ g(x) = x^2 + y^2 + z^2 \ }[/tex]Let's determine the derivative and run the composite function rule.
The outside function: [tex] \boxed{ \ h'(x) = -\frac{1}{2} \frac{q}{4 \pi \epsilon_0 r}(g(x))^{-\frac{3}{2}} \ } [/tex]The inside function: [tex]\boxed{ \ g'(x) = 2x \ }[/tex]Let us calculate the x-component of electric field by using
[tex]\boxed{ \ E_x = - \frac{\delta V}{\delta x} \ }[/tex]
The composite function rule tells us that
[tex]\boxed{ \ V(x) = h(g(x)) \rightarrow V'(x) = h'(g(x)) \times g'(x) \ }[/tex]
Therefore, [tex]\boxed{ \ E_x = - V'(x) \rightarrow -[h'(g(x)) \times g'(x)] \ }[/tex]
[tex]\boxed{ \ E_x = -[-\frac{1}{2} \frac{q}{4 \pi \epsilon_0 r}(x^2 + y^2 + z^2)^{-\frac{3}{2}} \times 2x] \ }[/tex]
Thus, the result is [tex]\boxed{\boxed{ \ E_x = \frac{qx}{4 \pi \epsilon_0 r}(x^2 + y^2 + z^2)^{-\frac{3}{2}} \ }}[/tex]
[tex]\boxed{\boxed{ \ E_x = \frac{qx}{4 \pi \epsilon_0 r \sqrt{(x^2 + y^2 + z^2)^3} }} \ }}[/tex]
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The product of 1.3×10^-4 and a number n results in 2.6×10^12 , what is the value of n?
Answer:
2x10^16
Step-by-step explanation:
ik im late but in case anyone still needs it
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Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
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Find the slope of the line passing through the points , (−7,2) and , (9,6) .
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What is the area under the normal curve between z = 0.0 and z = 1.79?
The area under the normal curve between z = 0.0 and z = 1.79 is 0.4641.
Explanation:The area under the normal curve between z = 0.0 and z = 1.79 can be found by subtracting the area to the left of z = 0.0 from the area to the left of z = 1.79.
The area to the left of z = 0.0 is 0.5000, and the area to the left of z = 1.79 is 0.9641 according to the Z-table.
Subtracting the two values, we get an area of 0.4641 between z = 0.0 and z = 1.79.
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Answer:45
Step-by-step explanation:For Julie's situation, the percent equation becomes:
money saved = percent of markdown × current price
Since the markdown is 60% off $75,
money saved====percent of markdown × current price60%×$750.6×7545
So, Julie will save $45.
ok i have calculated this and i srill havent got the right answer
What is the expression in simplest form ?
(3x - 2) - (4x + 1)
a. x-3
b. -x - 3
c. -x + 1
d. x + 1
Answer:
b. -x - 3
Step-by-step explanation:
(3x -2) -(4x +1) . . . given
3x -2 -4x -1 . . . . . . distribute the minus sign; eliminate parentheses
(3x -4x) + (-2 -1) . . . group like terms
-x -3 . . . . . . . . . . . . simplify
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Step-by-step explanation:
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$117.60
$117.60
for
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$148.50
in
18
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hours. Kim earns
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$137.60
in
16
16
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Use a straight edge to draw a line through M and K.
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What is 3.659090909090909 as a fraction?
Since there are 16 digits in 659090909090909 , the very last digit is the "10000000000000000th" decimal place.
So we can just say that .659090909090909 is the same as 659090909090909 /10000000000000000.
The fraction fmtterm: Can't handle [-2147483648/-2147483648] 3? is not reduced to lowest terms. We can reduce this fraction to lowest
terms by dividing both the numerator and denominator by -2.14748e+09.
Why divide by -2.14748e+09? -2.14748e+09 is the Greatest Common Divisor (GCD)
or Greatest Common Factor (GCF) of the numbers 6.59091e+14 and 1e+16.
So, this fraction reduced to lowest terms is
So your final answer is: 3.659090909090909 can be written as the fraction