Tierra rode in a bike-a-thon. Her sponsors donated $7 for every 5 miles she biked. At the end of the bike-a-thon, Tierra had raised $147. How many miles did she ride?

Answer:

[tex]\sqrt{29}\ units[/tex]

Step-by-step explanation:

we know that

In a right triangle

Applying the Pythagorean Theorem

[tex]c^2=a^2+b^2[/tex]

where

c is the hypotenuse (the greater side)

a and b are the legs (perpendicular sides)

In this problem we have

[tex]a=2\ units\\b=5\ units[/tex]

substitute

[tex]c^2=2^2+5^2[/tex]

[tex]c^2=29[/tex]

[tex]c=\sqrt{29}\ units[/tex]

For this case we have that by definition, the volume of a cube is given by:

[tex]V = l ^ 3[/tex]

Where:

l: It's the side of the cube

According to the statement we have:

[tex]l = 18 \ m[/tex]

Substituting we have:

[tex]V = 18 ^ 3\\V = 5832 \ m ^ 3[/tex]

Thus, the volume of the cube is [tex]5832 \ m ^ 3[/tex]

ANswer:

The volume of the cube is [tex]5832 \ m ^ 3[/tex]

Question:

A certain vibrating system satisfies the equation u''+γu'+u=0. Find the value of the damping coefficientγfor which the quasi period of the damped motion is 50% greater than the period of the corresponding undamped motion.

Answer: y = √(20/9) = √20/3 = 1.49071

Step-by-step explanation:

u''+γu'+u=0

m =1, k =1, w• = √ (k/m) = 1

The period of undamped motion T, is given by T = 2π/w•, T = 2π/1 = 2π

The quasi period Tq = 2π/quasi frequency

Quasi frequency = ((4km - y^2)^1/2)/2m

Therefore the quasi period Tq = 4πm/((4km - y^2)^1/2)

From the question the quasi period is 50% greater than the period of undamped motion

Therefore Tq = T + (1/2)T = (3/2)T

Thus,

4πm/((4km - y^2)^1/2) = (3/2)(2π)

Where, k =1, m=1,

4π/((4 - y^2)^1/2) = 3π,

(4 - y^2)^1/2 = 4π/3π,

(4 - y^2) = (4/3)^2,

4 - y^2 = 16/9,

y^2 =4 - 16/9,

y^2 = 20/9,

y = √(20/9)

Answer:

Answer is 1.49071

Step-by-step explanation:

See the picture for the complete details

Answer:

Step-by-step explanation:

We would apply the formula for exponential growth which is expressed as

y = b(1 + r)^t

Where

y represents the population, t years after 2010.

t represents the number of years.

b represents the initial population.

r represents rate of growth.

From the information given,

b = 2.13 × 10^6

r = 2.4% = 2.4/100 = 0.024

Therefore, the equation that you can use to predict the population for the number of years after 2010 is

y = 2.13 × 10^6(1 + 0.024)^t

y = 2.13 × 10^6(1.024)^t

Answer:

[tex]t=\frac{2.64-2.5}{\frac{1.02}{\sqrt{15}}}=0.532[/tex]    

[tex]p_v =P(t_{(14)}>0.532)=0.302[/tex]  

If we compare the p value and the significance level assumed [tex]\alpha=0.05[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to fail reject the null hypothesis at 5% of significance

Step-by-step explanation:

Data given and notation  

[tex]\bar X=2.64[/tex] represent the sample mean

[tex]s=1.02[/tex] represent the sample standard deviation for the sample  

[tex]n=15[/tex] sample size  

[tex]\mu_o =2.5[/tex] represent the value that we want to test

[tex]\alpha[/tex] represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

[tex]p_v[/tex] represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is greater than 2.5, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 2.5[/tex]  

Alternative hypothesis:[tex]\mu > 2.5[/tex]  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

[tex]t=\frac{2.64-2.5}{\frac{1.02}{\sqrt{15}}}=0.532[/tex]    

P-value

The first step is calculate the degrees of freedom, on this case:  

[tex]df=n-1=15-1=14[/tex]  

Since is a one side right tailed test the p value would be:  

[tex]p_v =P(t_{(14)}>0.532)=0.302[/tex]  

Conclusion  

If we compare the p value and the significance level assumed [tex]\alpha=0.05[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to fail reject the null hypothesis at 5% of significance

Answer:

Step-by-step explanation:

We will find two equations for this system, one representing flour and the other representing cocoa.  For the flour, we start with $2.50, and the cost goes up .07 per month, x. The equation for that is

y = .07x + 2.50

For the cocoa, the equation is written in the exact same way, but the cost goes down.  Down is a negative thing while up is a positive thing.  The cost starts at $6.00 and goes down .03 per month, x. The equation for that is

y = -.03x + 6.00

Comparing the first equation to the second, the .07 is positive because the cost goes UP that amount per month and the .03 is negative because the cost goes DOWN that amount per month.  Get it?

If y is cost and we are tryong to find out where the cost is the same, we are looking for when y is the same.  If the first y is equal to .07x + 2.50 and the second y is equal to -.03x + 6.00, and y is equal to y, then

.07x + 2.50 = -.03x + 6.00 (this is setting the first y equal to the second y).  This is the system that describes how to find the number of months x when the cost y is the same. We'll solve it just for practice.

Combining like terms we get

.10x = 3.5 so

x = 35

Now back sub in what x equals to solve for y.  If x = 35, then in the first equation,

.07(35) + 2.50 = y and

y = 4.95 (you could have used the second equation and subbed in 35 for x and you will get the exact same y value.  Promise!)

What this answer tells us is that 35 months after the start of this pricing, the cost of flour will be the same as the cost of cocoa.  But immediately after 35 months, the costs will not be the same anymore.  It is only AT 35 months.  At 36 months, the costs will be different.

The requried system of equations used to find the number of months is
y = 2.50 + 0.07x  and y = 6 -0.03x.

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

Here,
Let the number of months, x, when the price, y.
The cost of flour is $2.50 per pound and increases at a rate of $0.07 per month.
Equation ⇒ y = 2.50 + 0.07x   - - - - - (1)

The cost of cocoa is $6.00 per pound and decreases at a rate of $0.03 per month.
Equation ⇒ y = 6 -0.03x  - - - - - (2)

Solution of the equation 1 and 2 gives the price which would be equal for both flour and cocoa.

Thus, the requried system of equations used to find the number of months is y = 2.50 + 0.07x  and y = 6 -0.03x.

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Answer:

decreases as the required rate of return increases.

Step-by-step explanation:

Net present value (NPV) is the difference between the present value of cash inflows and the present value of cash outflows over a period of time. This differences tend to reduce as the requires rate of return increases.

Answer:

13 Minutes

Step-by-step explanation:

If it took 28 minutes total to wait in line and be in the haunted house, then the equation would be 15+x=28

x=13

Answer:

13 Minutes

Step-by-step explanation:

The accumulator pattern for calculating the sum of numbers using variables number and total in programming is correctly represented by 'total = total + number'. This demonstrates the commutative property of addition, indicating that 'total += number' updates the running total with the new number.

The correct representation of an accumulator to calculate the sum of numbers in a programming context, when the current number is stored in a variable number and the total is stored in a variable total, would be to update the total by adding the number to it. This would look like total = total + number or in a more simplified form as total += number.

Addition in programming is similar to addition in mathematics; it's commutative and associative. This means that the order of adding numbers does not change the sum, as represented by A + B = B + A. Whether we are dealing with numbers, such as integers or real numbers, or other structures like vectors, the concept of addition remains fundamentally the same.

The accumulator pattern is commonly used to build a sum or total by updating a running total each time a new value is added, which is also illustrated by the expression total += number. This pattern is essential in various programming tasks, such as summing a series of numbers in a loop.

Answer:

Pamela = 30

Jiri = 40

Step-by-step explanation:

Two equations needed:

J-10 = P

P+J = 70

Plug and solve:

(J-10) + J = 70

2J - 10 =70

2J = 80

J = 40

40 - 10 = P

P=30

Answer:

30

Step-by-step explanation:

Let Jiri's age be x

Let Pamela's age be (x - 10)

The sum of their ages becomes

x + (x - 10) = 70

x + x - 10 = 70

2x - 10 = 70

2x =70+10

2x = 80

x = 40

Therefore, it means that Jiri's age is 40

Pamela's age is 40-10= 30

The calculated area of the semicircle is 584.20 square inches

How to determine the area

From the question, we have the following parameters that can be used in our computation:

Length A to D to B = 37 inches

Perimeter of the semicircle = 60.57 inches

The perimeter of the semicircle is calculated using

P = πr

So, we have

πr = 60.57

r = 60.57/π

r = 60.57/3.14

r = 19.29

The area is then calculated as

Area = πr²/2

This gives

Area = π * 19.29²/2

Using 3.14 for π, we have

Area = 3.14 * 19.29²/2

Evaluate

Area = 584.20

Hence, the area of the semicircle is 584.20 square inches

Answer:

2 workers

Step-by-step explanation:

Here is additional information for your question:

The questions below deal with the Gizmo Company, which has the following production function.

# Workers # Produce

0 0

1 10

2 19

3 26

4 31

5 34

If the real wage is equal to 8 widgets and only an integer number of workers can be hired the Gizmo company should hire?

My answer:

2 workers. (where MPL is less than real wage)

It would be C. isosceles triangle.

Answer:

Total length of the Nylon rope will be 5.8 feet.

Step-by-step explanation:

Given:

Height of the tent = 5 ft

ground Distance from stake to tent = 3 ft

We need to find the Total length of the nylon rope.

Solution:

Now we can say that the total length of the nylon rope, the height of the tent, the ground distance from the stake to the tent, forms a right angle triangle.

From above we can see that;

the height of the tent, the ground distance from the stake to the tent are the two legs of the right angled triangle.

While the Total length of the nylon rope is the hypotenuse.

Now using Pythagoras theorem we get;

[tex]h^2=l_1^2+l_2^2[/tex]

[tex]l_1[/tex] ⇒ the height of the tent

[tex]l_2[/tex] ⇒  the ground distance from the stake to the tent

[tex]h[/tex] ⇒ the Total length of the nylon rope

substituting the values we get;

[tex]h^2=5^2+3^2\\\\h^2=25+9\\\\h^2=34[/tex]

Taking square root on both side we get;

[tex]\sqrt{h^2} =\sqrt{34} \\\\h=5.8\ ft[/tex]

Hence Total length of the Nylon rope will be 5.8 feet.

Answer:

Just find the hypotenuse by doing a^2 + B^2 = C^2

Step-by-step explanation:

Answer:

(1) 3628800

(2) 0.00000028

Step-by-step explanation:

We are given that a puzzle in the newspaper presents a matching problem. The names of 10 U.S. presidents are listed in one column, and their vice presidents are listed in random order in the second column.

(1) If we make the matches randomly, number of possible matches are given by = 10!

Because after making each match the number will decrease so,

Number of possible matches = 10! = 10*9*8*7*6*5*4*3*2*1 = 3628800 .

(2) The probability all 10 of your matches are correct is given by;

      Number of outcomes in favor ÷ Total number of matches

So, there will be only 1 case when all 10 of the matches are correct.

Therefore, required probability = [tex]\frac{1}{10!}[/tex] = [tex]\frac{1}{3628800}[/tex] = 0.00000028 .

Answer:

5%

Step-by-step explanation:

According to fisher equation

Nominal rate = Real rate + Inflation

N = R + I

N is calculated when there is no inflation and for the current year = 8%

The Real rate is calculated from the base year

Real rate is consider "Inflation factor" and R is unknown

Inflation rate (I) = 3%

Hence, N = R + I

8 = R + 3

R = 8 - 3

R = 5%

Answer:

22 rows and 22 flags are needed

Step-by-step explanation:

Total number of vendors = 88

Existing number of rows and flags= 4

Number of rows and flags needed= 88/4 =22

Answer:

4rows and 16flags

Step-by-step explanation:

Since there were 88 vendors at the craft fair and 4flags on each rows. To set up equal number of vendors on each row, we will use the expression;

Number of vendors per row = Total number of vendors/total number of flags per row = 88/4 = 22 vendors

If there are 22 vendors in a rows and there are 88vendors in total, the total of rows will be;

Total number of vendors/number of vendors per row

= 88/22

= 4 rows

If there are four rows in total and 4flags in each row, the total of flags needed will be;

Total number of row × total flag per row

= 4×4

= 16flags

This shows that there are 4rows and 16flags were needed.

Answer:

Part 1) [tex]A=28.96^o[/tex]

Part 2) [tex]B=46.57^o[/tex]

Part 3) [tex]C=104.47^o[/tex]

Step-by-step explanation:

step 1

Find the measure of angle A

Applying the law of cosines

[tex]a^2=b^2+c^2-2(b)(c)cos(A)[/tex]

we have

[tex]a=10\ cm\\b=15\ cm\\c=20\ cm[/tex]

substitute

[tex]10^2=15^2+20^2-2(15)(20)cos(A)[/tex]

Solve for A

[tex]2(15)(20)cos(A)=15^2+20^2-10^2[/tex]

[tex]600cos(A)=525[/tex]

[tex]cos(A)=(525/600)[/tex]

using a calculator

[tex]A=cos^{-1}(525/600)=28.96^o[/tex]

step 2

Find the measure of angle B

Applying the law of cosines

[tex]b^2=a^2+c^2-2(a)(c)cos(B)[/tex]

we have

[tex]a=10\ cm\\b=15\ cm\\c=20\ cm[/tex]

substitute

[tex]15^2=10^2+20^2-2(10)(20)cos(B)[/tex]

Solve for A

[tex]2(10)(20)cos(B)=10^2+20^2-15^2[/tex]

[tex]400cos(B)=275[/tex]

[tex]cos(B)=(275/400)[/tex]

using a calculator

[tex]B=cos^{-1}(275/400)=46.57^o[/tex]

step 3

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

[tex]A+B+C=180^o[/tex]

we have

[tex]A=28.96^o[/tex]

[tex]B=46.57^o[/tex]

substitute

[tex]28.96^o+46.57^o+C=180^o[/tex]

[tex]C=180^o-75.53^o[/tex]

[tex]C=104.47^o[/tex]

The value of a is 12

Step-by-step explanation:

Here we have , Lake mead contains approximately 28,945,000 acre feet of water and there are about 326,099 gallons in 1 acre foot . We need to find that the approximate number of gallons of water in lake mead is [tex]9.4 \times 10^a[/tex] what is the value of a . Let's find out :

We have, 1 acre foot = 326,099 gallons

So , 28,945,000 acre feet =  326,099 gallons ( 28,945,00 )

⇒ [tex]326,099 (28,945,000 )[/tex]

⇒ [tex]9.4389356e+12[/tex]

⇒ [tex]9.4(10^{12})[/tex]

Therefore , comparing this [tex]9.4(10^{12})[/tex] with [tex]9.4 \times 10^a[/tex]  we see that value of a = 12 .So , Value of a is 12 in  number of gallons of water in lake mead [tex]9.4 \times 10^a[/tex].

Final answer:

The number of gallons of water in Lake Mead, calculated by its volume in acre-feet times the gallons per acre-foot, is approximately 9.4 × 10¹², making the value of 'a' in the scientific notation 12.

Explanation:

To find the approximate number of gallons of water in Lake Mead, we multiply the volume of the lake in acre-feet by the number of gallons in an acre-foot. Given that Lake Mead contains approximately 28,945,000 acre-feet of water and there are about 326,099 gallons in 1 acre-foot, the calculation is as follows:

28,945,000 acre-feet × 326,099 gallons/acre-foot = 9.430455145 × 10¹² gallons.

Therefore, the scientific notation for the total number of gallons of water in Lake Mead would be approximately 9.4 × 10¹², making the value of a in the scientific notation 12.

The time for the fastest 10 % is less than 89.4 seconds

Here's how to find the qualifying task times:

Calculate the z-score for the 10th percentile:

A z-score represents the number of standard deviations a specific point is away from the mean. In this case, we want the z-score for the lower 10th percentile, which can be found using a z-score table or online calculators. The approximate z-score for the 10th percentile is -1.28.

Translate the z-score to task time:

We know the z-score for the 10th percentile (-1.28) and the standard deviation (20 seconds). We can use the formula to find the corresponding task time (t):

t = mean + (z-score) * standard deviation

t = 115 seconds + (-1.28) * 20 seconds

t ≈ 89.4 seconds

Therefore, task times less than 89.4 seconds qualify individuals for advanced training, as they fall within the lower 10th percentile of the normal distribution.

Complete question:

The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 115 sec and a standard deviation of 20 sec. The fastest 10% are to be given advanced training. What task times qualify individuals for such training? (Round the answer to one decimal place.)

Answer: the speed of the current is 6 mph

Step-by-step explanation:

Let x represent the speed of the current.

Logan is driving a boat that has a speed of 18 mph in standing water.

Assuming the current slowed down the boat while she was going up(upstream), it means that his total speed was (18 - x) mph

Also, if the current helped the boat while she was going down(downstream), it means that his total speed was (18 + x) mph

Time = distance/speed

The boat travels 4 miles each way. The time taken to travel upstream is

4/(18 - x)

Time taken to travel downstream is

4/(18 + x)

The round trip took 0.5 hour. It means that

4/(18 - x) + 4/(18 + x) = 0.5

Multiplying through by (18 - x)(18 + x), it becomes

4/(18 - x) + 4/(18 + x) = 0.5(18 - x)(18 + x)

4(18 + x) + 4(18 - x) = 0.5(18 - x)(18 + x)

72 + 4x + 72 - 4x = 0.5(324 + 18x -

18x - x²)

144 = 0.5(324 - x²)

144 = 162 - 0.5x²

0.5x² = 162 - 144

0.5x² = 18

x² = 18/0.5 = 36

x = √36

x = 6

Answer:

Part 1) [tex]m\angle 1=39^o[/tex]

Part 2) [tex]m\angle 3=51^o[/tex]

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the measure of angle 1

we know that

The longer diagonal of a kite bisects the kite into two equal parts

That means

[tex]m\angle 1=39^o[/tex]

In this problem the longer diagonal is the segment AC

Part 2) Find the measure of angle 3

we know that

The intersection of the diagonals of a kite form 90 degrees.

That means ----> The triangle ADO (O is the intersection point both diagonals) is a right triangle

so

[tex]39^o+m\angle 3=90^o[/tex] ----> by complementary angles in a right triangle

[tex]m\angle 3=90^o-39^o=51^o[/tex]

The possible length of the third side of a triangle with sides of 9 units and 6 units must be more than 3 units and less than 15 units, according to the triangle inequality theorem.

To determine the possible length of the third side of a triangle when two sides are known, we can use the triangle inequality theorem. The theorem states that the length of any side of a triangle must be less than the sum of the other two sides and greater than their difference. In this case, Millie's triangle has sides of 9 units and 6 units.

The sum of these two sides is 9 units + 6 units = 15 units, and their difference is 9 units - 6 units = 3 units. Therefore, the third side of the triangle must be greater than 3 units but less than 15 units.

The third side must be greater than 3 units.

The third side must be less than 15 units.

To summarize, the third side could have any length that is more than 3 units but less than 15 units.

Answer:

[tex]\frac{9}{4}[/tex]

Step-by-step explanation:

Given

x² + 3x - 13 = 0 ( add 13 to both sides )

x² + 3x = 13

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2([tex]\frac{3}{2}[/tex] )x + ([tex]\frac{3}{2}[/tex] )² = 13 + ([tex]\frac{3}{2}[/tex] )², that is

x² + 2([tex]\frac{3}{2}[/tex] )x + [tex]\frac{9}{4}[/tex] = 13 + [tex]\frac{9}{4}[/tex]

(x + [tex]\frac{3}{2}[/tex] )² = [tex]\frac{61}{4}[/tex]

The required number to be added to complete the square is [tex]\frac{9}{4}[/tex]

Hence, required number to be added to complete the square is 9/4

A quadratic equation is any equation that can be rewritten in standard form as ax2+bx+c=0 in algebra. When x is an unknown and a, b, and c are known numbers, and an is less than 0. Because there is no ax2 term when a = 0, the equation is linear rather than quadratic.

Given equation =x² + 3x - 13 = 0 ( add 13 to both sides )

=x² + 3x = 13

using complete the square and add ( half the coefficient of the x- term )² to both sides

=x² + 2(3/2 )x + ( 3/2)² = 13 + (3/2 )², that is

=x² + 2(3/2 )x +  = 13 + 9/4

=(x + 3/2 )² = 61/4

The required number to be added to complete the square is 9/4

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Answer:

sampling error i think

Step-by-step explanation:

Answer:

5.0 ft - 5.6 ft

Step-by-step explanation:

Given that the structure is to be made using two 12 foot boards, then we expect the total perimeter to be equal to (2*12)= 24 ft.

Using the angle of elevation, 40° and the width of 8 ft then you can apply the formula for tangent of a triangle where ;

Tan α = opposite side length/adjacent length

Tan 40°= h/8

h= 8 tan 40° = 6.71 ft

Applying the cosine of an angle formula to find the length of the sliding side

Cosine β = adjacent length /hypotenuse

Cosine 40°= 8/ sliding side length

sliding side length = 8/cosine 40° =10.44 ft

Checking  the perimeter = 10.44 +8+6.71= 25.15 ft

This is more than the total lengths of the boards, so you need to adjust the height as;

24 - 18.44 = 5.56 ft ,thus the height should be less or equal to 5.56 ft

h≤ 5.6 ft

The height range for Alex's outdoor structure that ensures snow slides off with a minimum width of 8 feet is approximately 3.4 to 12 feet, calculated using the tangent function in trigonometry for the minimum height and considering the maximum height based on the board length.

To solve this, we employ trigonometry, specifically the tangent function because it relates the angle of elevation to the opposite side (height in this case) over the adjacent side (half the width here, since it's a symmetrical layout).

First, establish the minimum height using the minimum angle of elevation, 40 degrees:
tan(40 degrees) = h / (8/2)

Solving for h gives h = tan(40 degrees) × 4. Calculating this yields approximately 3.4 feet, which is the minimum height.

Next, considering the boards are 12 feet long, to find the maximum height, we can imagine them being placed vertically, thus:
h = 12 feet as the absolute maximum height since any angle of elevation would still allow snow to slide off.

Therefore, the range of heights for the structure is approximately 3.4 to 12 feet.

Answer:

A

Step-by-step explanation:

i took the test. make me branliest please

Answer:

49 ft; B: 30.5 ft

Step-by-step explanation:

Find nth terms and arithmetic means of arithmetic sequences and find sums of n terms of arithmetic series.

Option b: The solution to the system of equations is (2,0)

Explanation:

Given that the graph that contains the system of equations.

We need to determine the solution to the system of equations.

The solution to the system of equations is the points of intersection of these two lines.

The two lines intersect at x - axis at 2 and y - axis 0.

This can be written in coordinates as (2,0)

Thus, the point of intersection of the two lines is the point (2,0)

Hence, Option b is the correct answer.

Answer: 27.3 degrees

cos x = 16/18

x = arccos(16/18)

x = 27.3 degrees

Value of x is 30°

Step-by-step explanation:

cos x° = adjacent side/hypotenuse = 16/18 = 8/9

x° = cos inverse(8/9) = 27.12° = 30° (Rounded off to nearest ten)

Among the sets given, ∅ is not a power set while {∅,{a}}, {∅,{a},{∅,a}}, and {∅,{a},{b},{a,b}} can be considered power sets of the sets {a}, {a}, and {a,b} respectively according to the definition of power set.

In mathematics, a power set of any set S is the set of all subsets of S, including the empty set and S itself. We can use this definition to examine the four sets provided and determine if they qualify as power sets.

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