Transitive property: if 3x plus y equals 7 and 7 equals 5x minus 2y then

A) Variable = x ( miles Tim walked )

B)  Tim walked X miles, Molly walked 4+x miles ( 4 more than Tim)

 Equation:  x + x+4 = 10

C) x +x+4 = 10

2x+4 = 10

2x =6

x = 3

D)

 Tim walked 3 miles, Molly walked 7 miles

To get the secret blend, you should mix 18 pounds of the Rift Valley coffee with the 60 pounds of Mexican Shade Grown coffee.

To find out how many pounds of the Rift Valley blend you should mix with the 60 pounds of Mexican Shade Grown coffee, we need to set up a proportion based on the ratio of the two blends. The ratio of the Mexican Shade Grown blend to the Rift Valley blend is 80:24, which can be simplified to 10:3. We can then set up the proportion: 10/3 = 60/x. By cross-multiplying, we get 10x = 180. Dividing both sides by 10, we find that x = 18. Therefore, you should mix 18 pounds of the Rift Valley coffee with the 60 pounds of Mexican Shade Grown coffee to get your secret blend.

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The velocity of the car is represented by the equation y = 4x + 39, where 'x' is time and 'y' is the velocity. You can graph this for the first six hours by substituting x=6 to find: y=63 km/h. Thus, the car's velocity after six hours would be 63 km/h.

In order to solve this problem, we first find the equation representing the change in the car's velocity. The point (3, 51) represents the condition that after three hours, the car is moving at 51 km/h. Similarly, the point (5, 59) stands for the velocity being 59 km/h after five hours. We derive the slope of the line connecting these two points by subtracting the y-coordinates and dividing by the difference of the x-coordinates, (59-51)/(5-3) = 4.

This slope represents an increase of 4 km/h for every hour that passes. Our equation then becomes y - 51 = 4(x - 3) which simplifies to y = 4x + 39. In this equation, 'x' represents time in hours and 'y' is the car's velocity at any given time 'x'.

For Part B, we graph the equation over the first six hours by inputting x=6 into the equation, giving us y = 4*6 + 39 = 63 km/h. Therefore, after six hours, the car would be moving at a velocity of 63 km/h.

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Answer:

Step-by-step explanation:

Given,

James's present age be = A

So,

After seven years from now will be +7

Therefore,

James age, seven years after his present age is,

= (A) + (7)

= A + 7

Hence, the required expression is: A + 7 (Ans)

Hello there, I hope you are having a nice day.

We are given that James's present age is A years.

If James's present age is a years, then in 7 years his age will be

A+7

Which means that whatever A is, it will be 7 more in 7 years.

Hence, the expression is A+7 (Answer)

Hope it helps.

~An emotional teen who helps others and listens to her favourite song "How Far I'll Go"

-Grace ;-)

Good luck with your studies.

You can change a column heading by clicking it, then right-clicking to select 'Rename Column' and inputting 'Total Number of Sessions'.

To change the column heading for the row sum which represents the total of each type of session to 'Total Number of Sessions', you need to follow these steps:

This will effectively rename your column heading to represent the total number of sessions accurately.

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Answer:  The zeroes of the given polynomial f(x) are

[tex]x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]

Step-by-step explanation:  We are given to find the zeroes of the quadratic function below:

[tex]f(x)=8x^2-16x-15.[/tex]

To find the zeroes, we must find the roots of the following equation

[tex]f(x)=0\\\\\Rightarrow 8x^2-16x-15=0~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex].

We know that the roots of the quadratic equation of the form [tex]ax^2+bx+c=0,~a\neq 0[/tex] is given by

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}.[/tex]

In the given quadratic equation , a = 8, b = -16  and  c = - 15.

Therefore, the roots of the equation are

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\\Rightarrow x=\dfrac{-(-16)\pm\sqrt{(-16)^2-4\times 8\times (-15)}}{2\times 8}\\\\\\\Rightarrow x=\dfrac{16\pm\sqrt{256+480}}{16}\\\\\\\Rightarrow x=\dfrac{16\pm\sqrt{786}}{16}\\\\\\\Rightarrow x=\dfrac{16\pm4\sqrt{46}}{16}\\\\\\\Rightarrow x=\dfrac{4\pm\sqrt{46}}{4}\\\\\\\Rightarrow x=1\pm\sqrt{\dfrac{46}{16}}\\\\\\\Rightarrow x=1\pm\sqrt{\dfrac{23}{8}}\\\\\\\Rightarrow x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]

Thus, the zeroes of the given polynomial f(x) are

[tex]x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]

Option (C) is correct.

The zeroes of the given polynomial f(x) = 8x^2-16x-15 are x = 1 + [tex]\sqrt{23}[/tex] / 8 and x = 1 -[tex]\sqrt{23}[/tex] / 8 Thus, Option C is correct.

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

We are given to find the zeroes of the quadratic function f(x) = 8x^2 - 16x-15

f(x) = [tex]8x^2-16x-15[/tex] = 0

We know that the roots of the quadratic equation ax² + bx + c = 0 is

x = -b ± [tex]\sqrt{b^2 - 4ac}[/tex] / 2a

In the given quadratic equation , a = 8, b = -16  and  c = - 15.

So,

x = -b ± [tex]\sqrt{b^2 - 4ac}[/tex] / 2a

x = -(-16) ± [tex]\sqrt{(-16)^2 - 4(8)(-15)}[/tex] / 2(8)

x = 16  ± [tex]\sqrt{256+ 480}[/tex] / 16

x = 16  ± [tex]\sqrt{786}[/tex] / 16

x = 4  ± [tex]\sqrt{46}[/tex] / 4

x = 1 ± [tex]\sqrt{23}[/tex] / 8

Thus, the zeroes of the given polynomial f(x) are

x = 1 + [tex]\sqrt{23}[/tex] / 8 and x = 1 -[tex]\sqrt{23}[/tex] / 8. Option C is correct.

Learn more about quadratic equations;

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Answer:

[tex] x = 4x -30[/tex]

We can solve for x subtracting x on both sides:

[tex] x-x= 4x-x-30[/tex]

And then we can add 30 in both sides:

[tex] 30= 3x[/tex]

And dividing both sides by 3 we got:

[tex] x = 10[/tex]

Step-by-step explanation:

For this case we know the measure of two angles:

[tex]m <A = x[/tex]

[tex] m<B = 4x-30[/tex]

And we know that both angles are vertical and by definition vertical angles are the angles opposite each other when two lines cross.

For this case since both angles are vertical we have the property that:

[tex] m<A = m<B [/tex]

And replacing what we got we have:

[tex] x = 4x -30[/tex]

We can solve for x subtracting x on both sides:

[tex] x-x= 4x-x-30[/tex]

And then we can add 30 in both sides:

[tex] 30= 3x[/tex]

And dividing both sides by 3 we got:

[tex] x = 10[/tex]

Keywords

transformed function, translation, rule  

In this problem we have

[tex]f(x)=|x+3|[/tex]

we know that

If the translation is [tex]5[/tex] units down

then

the rule of the translation is equal to

[tex](x,y)-------> (x,y-5)[/tex]

therefore

the answer is

the equation of the transformed function is equal to

[tex]g(x)=|x+3|-5[/tex]

see the attached figure to better understand the problem  

For ΔJKL ≅ ΔUVW and ΔUVW ≅ ΔABC, we conclude congruence JKL ≅ ABC, LK corresponds to UV and AB, and JLK corresponds to UVW and ABC.

The given information implies that triangle JKL is congruent to triangle ABC, and side LK corresponds to sides UV and AB. Angle JLK corresponds to angles UVW and ABC.

Therefore, the statements can be completed as follows:

Triangle JKL is congruent to triangle ABC.

Side LK corresponds to sides UV and AB.

Angle JLK corresponds to angles UVW and ABC.

Therefore, these statements reflect the congruence relationships established through the given information.

learn more about congruence here

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Answer:

sorry guys that other question is absolutely no help at all. The answer is 1.266 m/s squared. I don't know what kind of IDIOT would try and take you to a completely other website.

Step-by-step explanation:

Answer:

Option C is the correct choice.

Step-by-step explanation:

We have been given that a grocery store sells crackers in three box sizes.

To find the best buy, we will find the cost of per ounce crackers for each box.

[tex]\text{The price per oz for option A}=\frac{\$2}{8\text{ oz}}[/tex]

[tex]\text{The price per oz for option A}=\frac{\$0.25}{\text{ oz}}[/tex]

Therefore, the option A offers $0.25 for per oz of crackers.

[tex]\text{The price per oz for option B}=\frac{\$2.64}{12\text{ oz}}[/tex]

[tex]\text{The price per oz for option B}=\frac{\$0.22}{\text{ oz}}[/tex]

Therefore, the option B offers $0.22 for per oz of crackers.

[tex]\text{The price per oz for option C}=\frac{\$3.20}{16\text{ oz}}[/tex]

[tex]\text{The price per oz for option C}=\frac{\$0.20}{\text{ oz}}[/tex]

Therefore, the option C offers $0.20 for per oz of crackers.

Since the price offered by option C is less than other two options, therefore, option C is the correct choice.