Two friends, barbara and neil, are out rollerblading. with respect to the ground, barbara is skating due south at a speed of 5.9 m/s. neil is in front of her. with respect to the ground, neil is skating due west at a speed of 1.4 m/s. find neil's velocity (a) magnitude and (b) direction relative to due west, as seen by barbara.

Answers

Answer 1
As seen by Barbara, Neil is traveling at a velocity of 6.1 m/s at and angle of 76.7 degrees north from due west. Let's assume that both Barbara and Neil start out at coordinate (0,0) and skate for exactly 1 second. Where do they end up? Barbara is going due south at 5.9 m/s, so she's at (0,-5.9) Neil is going due west at 1.4 m/s, so he's at (-1.4,0) Now to see Neil's relative motion to Barbara, compute a translation that will place Barbara back at (0,0) and apply that same translation to Neil. Adding (0,5.9) to their coordinates will do this. So the translated coordinates for Neil is now (-1.4, 5.9) and Barbara is at (0,0). The magnitude of Neil's velocity as seen by Barbara is sqrt((-1.4)^2 + 5.9^2) = sqrt(1.96 + 34.81) = sqrt(36.77) = 6.1 m/s The angle of his vector relative to due west will be atan(5.9/1.4) = atan(4.214285714) = 76.7 degrees So as seen by Barbara, Neil is traveling at a velocity of 6.1 m/s at and angle of 76.7 degrees north from due west.
Answer 2

It is given that,

Speed of Barbara w.r.t ground, [tex]v_b=-5.9\ m/s[/tex] ( in south)

Speed of neil w.r.t ground, [tex]v_n=-1.4\ m/s[/tex] ( in west)

So, Neil's velocity as seen by Barbara is :

[tex]v^2=\sqrt{(1.4\ m/s)^2+(5.9\ m/s)^2}[/tex]

[tex]v=6.06\ m/s[/tex]

Direction relative to due wet is :

[tex]tan\theta=\dfrac{5.9\ m}{1.4\ m}[/tex]

[tex]\theta=tan^{-1} (4.21)[/tex]

[tex]\theta=76.6\ ^0[/tex]

So, with respect to barbara, Neil is travelling with velocity of 6.06 m/s making an angle of [tex]76.6^0[/tex] due west.

Hence, this is the required solution.


Related Questions

What effect might the stitches on a baseball have on a path of a baseball

Answers

Those stitches are what "chews" into the wind when you like to throw a breaking ball. Additionally, a knuckleball that barely spins eats at the wind using the stitches on the ball and this enables it to drop, sail or rise.

 

In short, the stitches makes the ball air resistant or cut into air making it faster.

Answer with Explanation

The most ‘striking’ feature of the baseball is the stitches that interact with the air when the ball moves. Along with a slight effect on the air drag, there is a strong effect on the Magnus force. According to the stitch pattern, the Magnus force on a moving ball depends accordingly because the air interacts strongly with the raised stitches on the ball. Apart from this, the stitches provide a better grip for the pitcher and help in forcing the ball to move in different ways.

STI is an abbreviation that refers to a number of diseases. What does STI stand for?

Answers

Sexually Transmitted Infection

Hope this helped!
sexual transmitted infection 

What angle can you kick a football that will make the initial vertical component of the velocity equal to the initial horizontal component of the velocity?

Answers

If the vertical and horizontal components of velocity are equal, then the object is moving in the direction of 45 degrees above the horizon.

Trigonometry allows finding the result for the angle for which the components of the velocity are equal is:  

 The angle is: θ = 45º

Trigonometry allows you to find the component of the vectors with the relationships.

              [tex]cos \theta = \frac{v_x}{v} \\sin \theta = \frac{v_y}{v}[/tex]  

             vₓ = v cos θ

             [tex]v_y[/tex]  = v sin sin θ

Indicates that the values ​​of the two components are equal therefore.

           [tex]v_y = v_x[/tex]

          sin θ = cos θ

The only angle where the sine and cosine values ​​are equal is 45º

In conclusion using trigonometry we can find the result for the angle for which the components of the velocity are equal is:

The angle is:   θ = 45º

Learn more here: brainly.com/question/20261153

The density of pure silver is 10.5 g/cm3 at 20°c. if 5.25 g of pure silver pellets is added to a graduated cylinder containing 11.2 ml of water, to what volume level will the water in the cylinder rise?

Answers

11.7 ml

The critical thing to note here is the question "Will silver sink or float when places in water?" The reason for this question is that if it sinks, the volume increase will be exactly the volume of the silver. If it floats, then the volume increase will be that of the volume of water the silver displaces. So looking at the density of silver at 10.5 g/cm3, it's a lot denser than that of water which is close to 1 g/cm3. So the silver will sink. Now the question is "What's the volume of 5.35 g of silver?" That number is simply the mass of the silver divided by the density of the silver, giving

volume = 5.25 / 10.5 = 0.5 cm3.

So the volume of silver is 0.5 cubic centimeters. Since a ml is a cubic centimeter, you just need to add up the volume the water with the volume of the silver to get the final answer, giving:

11.2 + 0.5 = 11.7 ml



Note: The exact density of water isn't needed since the volume calculations would be the same regardless. However, if the silver had been less dense than the water, then the exact density of the water would have been needed to calculate how much water would have been displaced.

Final answer:

Using the density of pure silver (10.5 g/cm³), we calculate that 5.25 g of silver will have a volume of 0.5 cm³, raising the water level in the graduated cylinder from 11.2 mL to 11.7 mL.

Explanation:

The question asks to determine the volume level rise in a graduated cylinder when 5.25 g of pure silver is added to it. To find the rise in the volume of water within the cylinder, we utilize the concept of density, which relationship between mass and volume of a substance. The density of pure silver is given as 10.5 g/cm3. We can calculate the volume of the silver using the formula: Density = Mass / Volume, hence Volume = Mass / Density. Substituting the given values, we get Volume = 5.25 g / 10.5 g/cm3 = 0.5 cm3. Therefore, the volume level in the graduated cylinder will rise from 11.2 mL to 11.7 mL (since 1 cm3 = 1 mL).

What are the three pins that may be worn below your name on the ffa jacket?

Answers

Highest degree, highest office and highest award are the three pins that may be worn below your name on the ffa jacket.
FFA is the biggest of the profession and specialized student associations in U.S. schools.The National FFA Organization is an adolescent initiative association that has a constructive outcome in the lives of youngsters by building up their potential for head authority, self-awareness and profession accomplishment through education of agriculture.The Motto of FFA is;
"Learning to do, Doing to learn, Earning to live, Living to serve."

When Ilana moved her pencil from the location (2,4) cm on her paper to the location (6, 3) cm, the ______ she made was (+4, -1)

Answers

Answer: Translation

Explanation:
Original coordinate  = (2, 4) cm
Final coordinate = (6,3) cm

Change ix the x-coordinate = 6 - 2 = 4 cm
Change in the y-coordinate = 3 - 4 = -1 cm

Therefore, there was a translation of (4, -1) cm


Which of the following is maintained across the terminals of a battery? A. a potential difference B. a voltage drop C. an electric charge D. both A and B

Answers

I believe the answer is C. An electric charge

both a and b

ur answer is d

What's the momentum of a 3.5-kg boulder rolling down hill at 5 m/s

Answers

p = mv 
p = 3.5 × 5 
p = 17.5 kg .m/s

Hope this helps!

Two technicians are discussing magnetic coils. technician a says that the magnetic force can be increased by increasing the number of windings in the coil. technician b says that won't help because adding windings also increases the length of the wire, so current flow will go down and the magnetic strength will be the same. who is correct.

Answers

The magnetic field of a coil is given by
[tex]B=\mu N I/L [/tex]
where [tex]\mu[/tex] is the magnetic permeability, [tex]N[/tex] is the number of windings, [tex]I[/tex] is the current in the coil, [tex]L[/tex] is the length of the coil.
Thus if we increase the number of windings we increase the coil magnetic filed. Technician a) is right.
It is true that increasing the number of windings will increase the length of the wire but the equivalent decrease in the intensity of the current (given by this) is not significative when compared with the increase given by increasing the number of windings.  

A rocket ship travels 14,000 miles per hour. What is the rocket ship's velocity in m/s in correct scientific notation? (1 km = 0.62 mi) A. 6.3 × 10^3 m/s B. 0.627 × 10^3 m/s C. 630 × 10^6 m/s D. 6.3 × 10^5 m/s

Answers

Note that
1 km = 0.62 mi
Therefore
0.62 mi = 10³ m
1 mi = 1.6129 x 10³ m

Also,
 1 h = 3600 s

The given speed is
[tex](14,000 \, \frac{mi}{h} )*( \frac{1.6129 \times 10^{3} \, m}{mi} )*( \frac{h}{3600 \, s} ) = 6.27 \times 10^{3} \, \frac{m}{s} \approx 6.3 \times 10^{3} \, \frac{m}{s} [/tex]

Answer:  A. 6.3 x 10³ m/s

Why is declaring faith the first of the five pillars of Islam?

Answers

The philosophy is simple that no one can start the journey towards being a Muslim unless he professes the basic principles mentioned in the  "Declaration of Faith", which is "“There is none worthy of worship but Allah and Muhammad is His Messenger”.
The declaration consists of the two most fundamental elements of Islamic ideology:
1) Unity of Allah: Declaring that there is only One God and none else is mandatory to be a Muslim.
2) Faith in the prophet hood of Muhammad, the messenger of Islam.

How much heat is absorbed by a 29g iron skillet when its temperature rises from 9oC to 105oC?

Answers

We have:

Mass (m) of the iron skillet = 29 grams
Difference in temperature (Δt) = 105 - 9 = 96°C
Heat capacity of iron = 0.449 J/g °C

The energy (Q) is given by:

Q = m × Δt × specific heat
Q = 29 grams × 96 °C × 0.449 J/g°C
Q = 1250.016 Joules

Two arrows are shot vertically upward. the second arrow is shot after the first one, but while the first is still on its way up. the initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. suppose that the initial speed of the first arrow is 31.8 m/s and that the second arrow is fired 1.82 s after the first. determine the initial speed of the second arrow.

Answers

Final answer:

To determine the initial speed of the second arrow when both arrows reach their maximum height at the same time, kinematic equations are utilized, taking into account the initial velocity of the first arrow, delay time before the second arrow is fired, and gravity's acceleration.

Explanation:

The problem given is a classic example of two-body motion in which two arrows are launched vertically with different initial velocities, and the challenge is to find the initial speed of the second arrow when both arrows reach their peak heights simultaneously. To solve this problem, we need to use the equations of kinematics for each arrow.

First, we find the time it takes for the first arrow to reach its maximum height using the initial speed and the acceleration due to gravity. The equation for this is derived from the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity (31.8 m/s), a is the acceleration (-9.8 m/s² directed downwards), and t is the time. Thus, the time, t, for the first arrow to reach its maximum height can be calculated as follows:

t = (v - u) / a

Knowing the time it takes for the first arrow to reach the maximum height, we can then calculate the initial speed of the second arrow, which is fired 1.82 s later. This involves adding the delay time to the time it took the first arrow to reach the maximum height and then using that total time to determine the initial speed of the second arrow using the kinematic equation u = v - at, with v again being 0 m/s at maximum height.

By carefully evaluating these kinematic equations, we find the initial speed of the second arrow, ensuring that both arrows reach their peak heights at the same moment.

A cyclist travels for 30 min with an average speed of 10km/h. How far does she travel?

Answers

If she travels for 30 minutes, and goes at 10 kilometers per hour, she travels 5 kilometers.

An hour is 60 minutes. So, to get 30, divide by 2. Just halve it all, and you will get 10 / 2 = 5.

Answer:

5 km

Explanation:

Hello

speed is the relationship between a travel length and the time taken for it,and  the equation is given by

[tex]V=\frac{displacement(d)}{time\ used\ for\ do\ that\ displacement(t)}\\\\ V=\frac{d}{t}[/tex]

Step 1

the speed and the time are known data, so we have to isolate the displacement

[tex]v=\frac{d}{t}\\d=v*t[/tex]

Step 2

same units of time must be used, hence

using a rule of three let's convert 30 min into hours

[tex]1\ hour = 60\ minutes\\x? hours= 30\ min\\\frac{1\ hour}{60\ minutes}=\frac{x}{30\ minutes } \\ x=\frac{1\ hour*30\ minutes}{60\ minutes}\\x=0.5\ hours\\[/tex]

Step 3

Put the values into the equation

[tex]d=v*t\\d=10\frac{km}{h}* 0.5\ h\\\\ d=5 km[/tex]

he traveled 5 kilometers

Have a good day

A gauge of how exact a measurement is called

Answers

The answer A. Precision

An object has a mass of 15 kg and is accelerating to the right at 16.3 m/s2. The free-body diagram shows the horizontal forces acting on the object.



What is the frictional force, Ff, acting on the object?

5.5 N
15 N
244.5 N
494.5 N



Answer :
5.5 N

Answers

Refer to the free body diagram shown melow.

F =  applied force
R =  frictional force
m = 15 kg, the mass of the object

The acceleration (to the right) is 16.3 m/s², therefore
F - R = (15 kg)*(16.3 m/s²) = 244.5 N

The normal reaction is
N = mg = (15 kg)*(9.8 m/s²)  = 147 N
The frictional force is
R = μN = 147μ N,  where μ =  coefficient of kinetic friction.

Let us check possible answers:
If R = 5.5 N, then μ = 5.5/147 = 0.0374 (very likely)
If R = 15 N, then μ = 15/147 = 0.102 (possible)
If R = 244.5 N,   (Highly unlikely, exceed mg)
If R = 494.5 N, (highly unlikely, exceeds mg)

Answer:
The most reasonable answer is R = 5.5 N

Answer:

Ff = 5.5 N

Explanation:

Given:

M: 15kg

A: 16.3 m/s2

We use:

[tex]f=ma[/tex]

force=mass*acceleration

[tex](15kg)(16.3m/s^{2} )=244.5N[/tex]

This means that 244.5 N is the net force on the object, and the right vector is showing 250 N, so to find the left vector - which would be a negative number (left direction) - we do

[tex](-Ff)+250N= 244.5N (net force)[/tex]

Which would give us 5.5 N in the left direction (Ff)

Hope This Helps!

When the shuttle bus comes to a sudden stop to avoid hitting a dog, it decelerates uniformly at 4.6 m/s2 as it slows from 9.5 m/s to 0 m/s.
Find the time interval of acceleration for the bus.
Answer in units of s.

Answers

Final velocity = Vf=0 
Initial velocity = Vi = 9.5m/s 
Acceleration = a = -4.6m/s²
Time = t =? 

Now use the formula;

Vf=Vi+at 

0=9.5 - 4.6m/s²t

-9.5 = -4.6m/s²(t) 

9.5/4.6 = t
T= 2.01s

If the voltage is 120 v, and the desired current is 5 a, what resistance must be in the circuit?

Answers

Resistance = (voltage) / (current)

= 24 ohms.

Using Ohm's Law, the resistance required in a circuit with a voltage of 120 volts to achieve a current of 5 amps is calculated to be 24 ohms.

To determine the resistance that must be in the circuit when the voltage is 120 volts, and the current is 5 amps, you can use Ohm's Law.

Ohm's Law states that V = IR, where V is the voltage, I is the current, and R is the resistance. You can rearrange the equation to solve for resistance: R = V/I.

Plugging the given values into this formula:

Voltage (V) = 120 volts

Current (I) = 5 amps

Resistance (R) = V/I = 120V / 5A = 24 ohms.

Therefore, the circuit must have a resistance of 24 ohms to achieve a current of 5 amps with a voltage of 120 volts.

When water freezes, what happens to the temperature of the surrounding air?

Answers

it gets warmer because the forming ice gives heat up

in a historical movie, two knights on horseback start from rest at 88.0 m spartans ride directly toward each other to do battle. Sir George’s acceleration has a magnitude of 0.300 m/s^2, while Sir Alfred’s has a magnitude of 0.200 m/s^2. Relative to Sir George’s starting point, where do the knights collide?

Answers

The distance formula:d = v i · t + a · t² / 2Sir G.: ( v i = 0 )
d G = 0 + 0.3 · t² / 2Sir A. : d A = 0 + 0.2 t² / 288 m = 0.3 t² / 2   + 0.2 t² / 2    / · 2 ( multiple both sides by 2 )176 = 0.3 t² + 0.2 t²176 = 0.5 t²t² = 176 : 0.5t² = 352t = √352t = 18.76 sd G. = 0.3 · 18.76² / 2 = 0.3 · 352 / 2 = 52.8 mAnswer: The knights collide at 52.8 m relative to Sir George`s starting point.


A rocket blasts off and moves straight upward from the launch pad with constant acceleration. after 3.6 s the rocket is at a height of 70.0 m. (a) what are the magnitude and direction of the rocket's acceleration?

Answers

x=.5a(t^2), x=70m, t=3.6s, a=?. a=140/(3.6^2)=10.8m/s^2. 

A pair of electrically charged objects attract each other with a force of 4 n when they are a distance of 2 m apart. if their charges stay the same, then what will be the attractive force between them when they are 4 m apart?

Answers

1 n The force attracting electrical charged objects follows the inverse square law. So we calculate how much further apart the objects are by dividing the new distance by the original distance, giving 4 m / 2 m = 2 So the new distance is twice as far as the original distance. That means that the attractive force will be the inverse square, giving 1/(2^2) = 1/4 = 0.25 So the attractive force will be one fourth as strong. The original force was 4 n, so the new force will be 4/4 n = 1 n

This outlaw is executed by hanging "in the spring of '25" by

Answers

Final answer:

The question delves into historical instances of execution by hanging, touching on both real individuals like John Brown and Nat Turner, and fictional characters such as Peyton Farquhar. These figures were tied to pivotal societal and political issues, such as slavery and civil war, facing harsh penalties for their actions.

Explanation:

The question refers to various historical figures who were executed by hanging for their actions which often had considerable political or social impact. Peyton Farquhar, a fictional character from Ambrose Bierce’s short story, "An Occurrence at Owl Creek Bridge", symbolizes the concept of civilian interference in military matters and the grim consequences that follow during times of war. He is described as a genteel man, suggesting that civil status did not exempt one from capital punishment. A reference is made to John Brown, a historical figure who was hanged in 1859 after attempting to initiate a slave revolt at Harpers Ferry, effectively marking a critical moment that stirred greater national tension leading to the American Civil War.

Similarly, it mentions Nat Turner, leader of a slave rebellion in Virginia, which led to a swift and brutal response from the state authorities and white vigilantes, resulting in his death along with many other Black individuals, free and enslaved. Lastly, it hints at the Fugitive Slave Law and the repercussions for those who attempted to help enslaved individuals escape, as in the case of the unidentified 'young white man from Ohio.' This aligns with historical accounts of abolitionists and their often fatal attempts to combat slavery.

Temperature, Thermal Energy and Heat is what my questions are about, in picture

Answers

Thermal energy is a type of heat but their is two names for it heat energy and thermal energy for example ur oven is heat energy/thermal energy

The radius of a niobium atom is 131 pm. how many niobium atoms would have to be laid side by side to span a distance of 2.40 mm

Answers

The number of atoms required to span the given distance is [tex]9.1\times 10^8[/tex].

The SI unit of length is the meter. The unit conversion of the picometer and millimeter to the meter is:

[tex]1\ pm= 10^{-12}\ m\\1\ mm= 10^{-3}\ m[/tex]

Given:

The radius of the niobium atom, [tex]r=131\ pm[/tex]

The length to be covered is [tex](l) =2.40\ mm[/tex]

Convert both magnitudes into meters.

[tex]r=131\times10^{-12}\ m\\l=2.40\times10^{-3}\ m[/tex]

The number of atoms required to cover the length is calculated as:[tex]n=\frac{l}{2\times r}\\=\frac{2.40\times 10^{-3}}{2\times1.31\times10^{-12}}\\=9.6\times10^8[/tex]

Therefore, the number of atoms required to span the given distance is [tex]9.1\times 10^8[/tex].

To know more about unit conversions, click here:

https://brainly.com/question/28600662

#SPJ12

Final answer:

Approximately 9160 niobium atoms, each with a diameter of 262 pm, would need to be laid side by side to span a distance of 2.40 mm.

Explanation:

To determine how many niobium atoms would span a distance of 2.40 mm, we need to convert the length into picometers (pm) since the atomic radius of niobium is given in picometers. First, convert millimeters to picometers:

1 mm = 106 pm

Therefore, 2.40 mm equals 2.40 × 10⁶ pm:

2.40 mm = 2.40 × 10⁶ pm

Next, since the atomic radius of niobium is the distance from the center to the edge of one atom, the diameter of one niobium atom is twice the radius. Therefore, the diameter is 2 × 131 pm = 262 pm.

To find out how many niobium atoms fit into 2.40 mm, divide the total distance in picometers by the diameter of one niobium atom:

Number of Niobium atoms = Total distance (pm) / Diameter of one atom (pm)

Number of Niobium atoms = 2.40 × 10⁶ pm / 262 pm

Finally, calculate the number of niobium atoms:

Number of Niobium atoms = 9160.3

Since we cannot have a fraction of an atom, we round to the nearest whole number, which makes it roughly 9160 niobium atoms that would span 2.40 mm.

A group of 7 campers has 4 hours to hike to a lighthouse and back before sundown. the lighthouse is 28 meters high. it is located 12 kilometers from camp. how fast do they have to walk?

Answers

We must take note that the 28 meters high is simply a diversion. What we only need is the 4 hours and 12 kilometers distance. The formula for calculating the speed or velocity is :

velocity = distance / time

 

Therefore:

velocity = 12 km / 4 h

velocity = 3 km / h = 0.83 m / s 

Answer: So the campers must travel 12km two times (because they must go back after reached the lighthouse), and 28m two times.

If they keep the velocity constant (it means that they climb up and down the stairs at the same speed that they walk )

then you could add the whole distance as 12km*2 + 28m*2

a km is 1000m, so the distance will be 12000*2m+28*2m = 24046m

and they have 4 hours to do this, so the velocity is distance over time, they should do 24046m/4hours = 6011.5m/h or 6.0115km/h

Explain the difference between si base units and derived units. give an example of each

Answers

Base SI unit is the unit that used for simple quantity like time=second and length= meter. They only have one unit.
Derived unit is more complex because you multiply or divide at least two base SI, making it have more than 1 unit. The example could be velocity which was time/length = m/s

Final answer:

SI base units are the seven fundamental units in the SI system, such as kilograms for mass; derived units, such as grams per milliliter for density, are constructed by combining base units. Derived units are essential for expressing a wide range of physical quantities, demonstrating the SI system's adaptability.

Explanation:

The difference between SI base units and derived units lies in their definitions and applications. SI base units are the seven fundamental units of measurement in the International System of Units (SI) that are defined by specific physical phenomena and are independent of each other. These include the kilogram (kg) for mass and the meter (m) for length, among others. On the other hand, derived units are units that are constructed by combining the base units according to algebraic relationships. Examples of derived units include grams per milliliter (g/mL) for density and joules (J) for energy, which are obtained by combining base units in multiplicative ways.

Derived units can express a wide variety of physical quantities such as area, volume, density, and energy, showcasing the versatility of the SI system. Combining prefixes with base units can also create new units of larger or smaller sizes, enhancing the adaptability of the system to cover a broad range of measurements from the microscopic to the astronomical scale.

A roller coaster has a mass of 425 kg. It sits at the top of a hill with height 66 m. If it drops from this hill, how fast is it going when it reaches the bottom? (Assume there is no air resistance or friction.)

Answers

im pretty sure its 36.0 m/s

Two boxes are suspended from a rope over a pulley. each box has weight 50 n. what is the tension in the rope

Answers

We can draw a free body diagram for one of the boxes. There are two forces acting on the box. The downward force is the force of gravity which is 50 N. The upward force is the force from the tension in the rope. Since the box is suspended, it is not accelerating. Therefore, the net force must be zero. Therefore the tension in the rope must be 50 N.

When jogging outside you accidently bump into a curb. Your feet stop but your body continues to move forward and you end up on the ground. Which law of motion is being described in this scenario?

Answers

inertia I think because I've heard it around school and in science
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