two objects of different masses are sitting on a different balance scales. object A has a greater mass than object B how will the weights of the objects compare to each other?

Answers

Answer 1
A will be lower on the scale compared to b because it is heavier
 Two Objects Of Different Masses Are Sitting On A Different Balance Scales. Object A Has A Greater Mass
Answer 2

Explanation:

Since it is given that object A has greater mass this means that object A is heavier than object B.

Therefore, when both object A and object B is placed on a balance scale on either side then the balance scale will move downwards on the side where object of heavier mass is placed.

That is, balance scale will be in downward direction where object A is placed. Whereas balance scale will move upwards where object B is placed.


Related Questions

Water has a density of 1.0 g/cm3. Glycerin, a liquid used in some soaps, has a density of 1.26 g/cm3. If an object sinks in water but floats at a constant depth in glycerin, its density is _____.
A. between 1.0 g/cm3 and 1.26 cm3
B.exactly 1.26 g/cm3
C.greater than 1.26 cm3
D.less than 1.0 g/cm3

Answers

For an object to sink in something, it's density has to be higher than the object it is in, so if it sinks in water the number has be higher than 1

And to float, and objects density has to be lower than that of the substance it is put in, so it has to be lower than 1.26

So between 1 and 1.26

Hello! Since the object will sink in the water that has a density as 1.0, then it obviously cannot be D. If it floats at the Glycerin level at 1.26, then it cannot be C. An object or a substance can float on the exact level of density as water or liquids. The answer is B. Exactly 1.26 g/cm3. I hope I helped! Please mark me brainliest if you find suitable! Have a fantastic day! :)

Evidence of a chemical change would be a ___________________. Question options: spinning top. rusting car fender. spilled bucket of water. melting popsicle.

Answers

The answer is the second option "rusting car fender." Hope this helps.
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Which of these is an example of a chemical change? Fireworks exploding
grinding powder
melting cheese
ironing a shirt

Answers

fireworks exploding is the answer


Answer is B. Fireworks Exploding.

A certain ore is 29.9% nickel by mass. How many kilograms of this ore would you need to dig up to have 75.0 g of nickel?

Answers

75g ---- 29,9%
Xg ----- 100%
X = 7500/29,9
X = 250,836g :)
Final answer:

To obtain 75 g of nickel from an ore that is 29.9% nickel by mass, approximately 0.252 kilograms of the ore would be required.

Explanation:

This type of problem is a matter of conversion between the mass of the ore overall and the mass of the specific component, in this case, nickel. The ore is 29.9% nickel by mass, which means for every 100 g of ore, there are 29.9 g of nickel.

To find out how much ore is needed to yield 75 g of nickel, we can set up a proportion: (29.9 g nickel / 100 g ore) = (75 g nickel / x g ore).

Solving for x, we find x = (75 g nickel * 100 g ore) / 29.9 g nickel = approximately 251.67 g ore.

This is the mass of the ore required in grams. Since the question asks for the answer in kilograms, we will need to convert this to kg. Knowing that 1 kilogram = 1000 grams, we divide the answer by 1000 and find that approximately 0.252 kg of the ore would need to be dug up in order to have 75.0 g of nickel.

Learn more about Mass conversions in Chemistry here:

https://brainly.com/question/31389471

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carbon dioxide is a gas with the relative formula mass of 44. calculate the mass of the 36 dm3 of the CO2 at room temperature? ?? ANYONE WHO GET CHHEMISTY HELP

Answers

At STP 44g = 22.4 L Temp increases by 25 at room temp
Vol increases 298/273=1.09
New volume of 44g =24.45 L
36dm cubed=.036L
44g/24.45L=x/.036L
Should be 0.065g of CO2

Final answer:

The mass of 36 dm3 of CO2 at room temperature is 66.02 grams, calculated by first determining the number of moles and then multiplying by the molar mass of CO2.

Explanation:

To calculate the mass of 36 dm3 of CO2 at room temperature, we can use the molar volume of a gas at room temperature, which is approximately 24 dm3/mol. Given that the molar mass of CO2 is 44.01 g/mol, we can first find the number of moles of CO2 by dividing the volume by the molar volume.

Number of moles = Volume / Molar volume = 36 dm3 / 24 dm3/mol = 1.5 moles

Now, to find the mass, we multiply the number of moles by the molar mass of CO2.

Mass = Number of moles × Molar mass = 1.5 moles × 44.01 g/mol = 66.02 g CO2

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