Two objects of the same mass are in a room. At which of the following distances will the greatest gravitational force be exerted by one object on another?

2 m
4 m
6 m
8 m

The acceleration due to gravity, or g (exp), will decrease if the experiment is conducted 10 kilometers above sea level. This is because the force of gravity reduces as you move further from the Earth's surface.

The acceleration due to gravity, or g (exp), is expected to decrease if the experiment is repeated at a place 10 kilometers above the sea-level. This is because the force of gravity decreases as the distance from the center of the Earth increases.

Essentially, the further you move away from the Earth's surface, the weaker the gravitational force gets. This is due to the fact that gravity is dependent on distance. So, being 10 kilometers above sea level would result in a slightly lower acceleration due to gravity.

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Answer:

B.  

more than 150 meters

Explanation:

As we know that the range of projectile motion on the surface of earth is given by the formula

[tex]R = \frac{v^2sin(2\theta)}{g}[/tex]

so here on the surface of earth the gravity is given as g = 9.8 m/s/s

now if the golf ball is hit on the surface of earth then it range is given as R = 150 m

while if we hit the ball at surface of mercury then on the surface of mercury the gravity will be g = 3.7 m/s/s

so due to decrease in the magnitude of gravity the range on the surface of mercury will be more than 150 m

Answer:

B. More that 150 meters.

Explanation:

:)

The relationship between height and gravitational potential energy is directly proportional, following the equation G.P.E. = mgh. GPE increases as the height of an object increases, and it is measured in Joules, reflecting the energy due to the object's position above a reference level.

The relationship between height (h) and gravitational potential energy (GPE) is directly proportional. This means, as an object is raised to a higher elevation above the ground, its GPE increases. The formula for calculating GPE is G.P.E. = mgh, where m represents the mass of the object in kilograms, g is the acceleration due to gravity (approximately 10 m/s² on Earth's surface), and h is the height in meters. The unit of GPE is Joules, which quantifies the energy associated with the object's position in the gravitational field.

In physics, only the change in GPE (ΔGPE) is of significance, which is measured as the difference in energy when an object's height changes relative to a reference level. For instance, if a 0.500-kg mass from a cuckoo clock is lifted by 1.00 m, its GPE changes by mgh. The concept of GPE is vital in various applications, including understanding how energy is conserved within systems influenced by gravitational forces.

Answer:

80 ft/s

Explanation:

Use III equation of motion

V^2 = U^2 + 2g h

Here, U = 0, g = 32 ft/s^2, h = 100 ft

V^2 = 0 + 2 × 32 ×100

V^2 = 6400

V = 80 ft/s

The multiplication of (6.2 × 10^4) by (3.3 × 10^2) results in 2.046 × 10^7, when expressed in scientific notation.

The result of the multiplication (6.2 × 104) × (3.3 × 102), expressed in scientific notation, involves multiplying the coefficients (6.2 and 3.3) and then adding the exponents of 10 (4 and 2). It's important to recall that we must perform both steps to arrive at the correct answer in scientific notation.

The product of the coefficients is 20.46 and when we add the exponents the result is 106. So the multiplication gives us 20.46 × 106, but in correct scientific notation, we want the coefficient to be between 1 and 10. To achieve this we adjust the coefficient to 2.046 and increase the exponent by 1, giving us the result: 2.046 × 107.

Answer:

The water cycle will affect the climate by causing rain and snow.

Explanation:

if temperatures increase more rainfall will occur because more water evaporates in the air.

Final answer:

Inertia is the property of an object to maintain its state of motion or rest unless acted upon by a net external force, as described by Newton's first law of motion. This law, also known as the law of inertia, indicates that an object will continue in its state of constant velocity unless a force causes a change.

Explanation:

How is Inertia Related to Newton's First Law of Motion?:

Inertia is directly related to Newton's first law of motion, often referred to as the law of inertia. Newton's first law states that a body at rest remains at rest, and a body in motion remains in motion at a constant velocity unless acted upon by a net external force. This tendency of an object to resist changes in its state of motion or rest is known as inertia. Essentially, inertia is the reason why an object remains at rest or carries on moving at the same speed in a straight line unless a net force acts upon it.

Newton's laws are fundamental in the study of motion under the influence of forces, particularly in inertial frames of reference. Forces, which are described by Newton's laws, are always vectors with both magnitude and direction, and arise from interactions among objects. Newton's first law serves as a definition of an inertial frame of reference, and thus, any frame where the law is valid is considered inertial.

Two rocks hit against each other in a fast-flowing stream and break apart. Mosses grow on a rock and produce acids that wear away the rock over time. These statements describe physical weathering. Therefore, option A and D are correct.

Physical weathering, often known as mechanical weathering, is the process that fractures rocks without altering their chemical makeup. The following instances show physical weathering: water moving quickly. For brief periods of time, swiftly rushing water has the ability to raise rocks out of the streambed.

Rocks break down into tiny fragments due to abrasive weathering processes like wind and water. Exfoliation weathering rocks shatter and expand as pressure from unloading is relieved. As water freezes and expands, frost-wedging rocks crack.

When a rock is subjected to physical processes like temperature changes or exposure to the effects of wind, rain, and waves, physical weathering takes place.

Thus, option A and D are correct.

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Final answer:

Statements A and C describe physical weathering, which involves the purely physical breakdown of rocks, such as through collision in a stream or animal activity, without altering their chemical composition.

Explanation:

The question asks which statements describe physical weathering. Physical weathering, or mechanical weathering, involves the breakdown of rocks into smaller pieces without changing their chemical composition. Examples of physical weathering include the expansion and contraction of rocks due to temperature changes, the abrasive action of water or wind, and biological factors like plant roots breaking rocks apart.

A. Two rocks hit against each other in a fast-flowing stream and break apart.

C. Small rocks are pushed together when a mole digs an underground den.

Statement A is an example of physical weathering because it describes the physical action of rocks breaking apart due to collision in a stream. Statement C also illustrates physical weathering, showing how animal activity can physically move and potentially break rocks. In contrast, statements B and D describe chemical weathering, which involves the chemical alteration of rocks, such as mineral changes through oxidation or the action of acids.

the force is gravity holding them

The object fell a distance of 396.9 meters before hitting the ground.

To calculate the distance an object falls in a given time ignoring air resistance, we use the formula for the distance covered under constant acceleration: d =  rac{1}{2} g t^2, where d is the distance, g is the acceleration due to gravity (

9.8 m/s2), and t is the time in seconds. Substituting the given time of 9.0 seconds into the equation, the distance is calculated as d =  rac{1}{2}  imes 9.8  imes 9.0^2, which equals 396.9 meters. This equation is derived from basic kinematic principles that govern the motion of objects in free fall, assuming gravity is the only force acting on the object.

Answer:

B. C + O2 ------> CO2

Explanation:

i took the test

Answer:

g/cm^3

Explanation:

grams is the unit of mass and cm cubed is the unit of volume.

the equation for density is mass over volume (d=m/v)

The speed of the satellite is approximately [tex]\(3311 \, \text{m/s}\)[/tex] when the force acting on it is 87.4 N.

The gravitational force [tex](\(F_{\text{gravity}}\))[/tex] acting on the satellite is given by [tex]\(F_{\text{gravity}} = \frac{GMm}{r^2}\)[/tex], where [tex]\(G\)[/tex] is the gravitational constant, [tex]\(M\)[/tex] is the mass of the Earth, [tex]\(m\)[/tex] is the mass of the satellite, and [tex]\(r\)[/tex] is the distance from the center of the Earth to the satellite.

The centripetal force [tex](\(F_{\text{centripetal}}\))[/tex] required for circular motion is [tex]\(F_{\text{centripetal}} = \frac{m v^2}{r}\)[/tex], where [tex]\(v\)[/tex] is the speed of the satellite.

In a circular orbit, the gravitational force provides the centripetal force, so [tex]\(F_{\text{gravity}} = F_{\text{centripetal}}\)[/tex]:

[tex]\[\frac{GMm}{r^2} = \frac{m v^2}{r}\][/tex]

Solve for \(v\):

[tex]\[v = \sqrt{\frac{GM}{r}}\][/tex]

Now, substitute the given values:

[tex]\[v = \sqrt{\frac{(6.67 \times 10^{-11} \, \text{m}^3/\text{kg}\cdot\text{s}^2) \times (5.97 \times 10^{24} \, \text{kg})}{(3.00 \times 10^7 \, \text{m} + 6.37 \times 10^6 \, \text{m})}}\][/tex]

Calculating the expression to find the speed of the satellite. I'll do the math for you.

[tex]\[v = \sqrt{\frac{(6.67 \times 10^{-11} \, \text{m}^3/\text{kg}\cdot\text{s}^2) \times (5.97 \times 10^{24} \, \text{kg})}{(3.00 \times 10^7 \, \text{m} + 6.37 \times 10^6 \, \text{m})}}\][/tex]

[tex]\[v = \sqrt{\frac{(6.67 \times 10^{-11} \times 5.97 \times 10^{24})}{(3.00 \times 10^7 + 6.37 \times 10^6)}}\][/tex]

[tex]\[v = \sqrt{\frac{3.9879 \times 10^{14}}{3.637 \times 10^7}}\][/tex]

[tex]\[v \approx \sqrt{1.097 \times 10^7}\][/tex]

[tex]\[v \approx 3311 \, \text{m/s}\][/tex]

Therefore, the speed of the satellite is approximately [tex]\(3311 \, \text{m/s}\)[/tex] when the force acting on it is 87.4 N.

The right option is; C) the abyssal zone of the ocean

The anglerfish are likely to be found in the abyssal zone of the ocean.  

The abyssal zone is the bottomless layer of the pelagic zone of the ocean that has the bathyal zone located on it.  The abyssal zone is at depths of 4,000 to 6,000 metres, and it remains permanently in darkness. This zone is a food limited environment because it lacks nutrients. The temperature of the zone is around 2 to 3 °C and has continuous cold.

Answer:

The Atmosphere

Explanation:

Answer: Cricket chirping increases with an increase in temperature.

Explanation:

The independent variable in the experiment is the variable which can be altered, manipulated and changed so as to determine it's influence over the dependent variable, which is the outcome of the experiment.

Here in the given experiment, the number of chirps is the dependent variable which is increasing due to the increase in the temperature which is the independent variable.

If you opened the valve on a bicycle tire, the air inside of the tire will come out and the pressure it exert will be less.

When air is pumped into a bicycle tube, the tube gets inflated due to the air pressure exerted by the collisions of gas molecules in air with the inner walls of the rubber tube. This air pressure makes the tyres feel hard.

When the temperature cools down, the air within the tire shrinks. In the same way, when the temperature rises, the air within the tire expands.

Due to the air being compressed in a small space, the air is pressurized and when the valve is open it causes a loss in pressure making the air gush out.

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