Two train whistles have identical frequencies of 1.54 102 Hz. When one train is at rest in the station and the other is moving nearby, a commuter standing on the station platform hears beats with a frequency of 8.00 beats/s when the whistles operate together. What are the two possible speeds that the moving train can have? moving away from the station m/s moving towards the station m/s

Answer:

the change in potential energy when it reaches the highest height = 634.8 J

Explanation:

Potential Energy: This is the energy a body posses due to position.

From the law of conservation of energy,

At the highest point and lowest points, potential energy is converted to kinetic energy

I.e

Ek = Ek

Where Ek = potential energy, Ep = potential energy

Ep₁ = 1/2mu²  (potential energy at the lowest point)................ Equation 1

Ep₂ = 1/2mv² (potential energy at the highest point)............. Equation 2

ΔEp = Ep₂ - Ep₁ = 1/2mu² - 1/2mv²........................ Equation 3

Where ΔEp = change in potential energy, m = mass of the ball of clay, v = final velocity of the ball of clay, u = initial velocity of the ball of clay

Given: m= 60 kg, u = 4.6 m/s v = 0 ( velocity at the maximum height)

Substituting these values into equation 3

ΔEp = 1/2×60×4.6 - 1/2×60×0²

ΔEp = 30×21.16 - 0

ΔEp = 634.8 J.

Therefore the change in potential energy when it reaches the highest height = 634.8 J

Final answer:

The change in potential energy of the 60.0-kg ball of clay when it reaches its highest point, ignoring air resistance, is 636.0 J.

Explanation:

To calculate the change in potential energy of the 60.0-kg ball of clay at its highest point, we use the formula for gravitational potential energy ([tex]PE_{g}[/tex]):

[tex]PE_{g}[/tex] = m × g × h

where m is the mass of the object, g is the acceleration due to gravity (9.81 m/s² on Earth), and h is the height reached.

First, determine the maximum height h the ball reaches using the conservation of energy principle, where the initial kinetic energy (KE) is fully converted to potential energy (PE) at the highest point:

[tex]KE_{initial}[/tex] = [tex]PE_{g,max}[/tex]

To find [tex]KE_{initial}[/tex], we use the kinetic energy formula:

KE =  1/2 × m × v²

[tex]KE_{initial}[/tex] =  1/2 × 60.0 kg × (4.60 m/s)²

[tex]KE_{initial}[/tex] = 1/2 × 60 kg × 21.16 m²/s²

[tex]KE_{initial}[/tex] = 636.0 J

Since [tex]KE_{initial}[/tex] = [tex]PE_{g,max}[/tex], the ball's change in potential energy is also 636.0 J.

Answer:

0.0031792338 rad/s

Explanation:

[tex]\theta[/tex] = Angle of elevation

y = Height of balloon

Using trigonometry

[tex]tan\theta=y\dfrac{y}{200}\\\Rightarrow y=200tan\theta[/tex]

Differentiating with respect to t we get

[tex]\dfrac{dy}{dt}=\dfrac{d}{dt}200tan\theta\\\Rightarrow \dfrac{dy}{dt}=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow 100=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{100}{200sec^2\theta}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{1}{2}cos^2\theta[/tex]

Now, with the base at 200 ft and height at 2500 ft

The hypotenuse is

[tex]h=\sqrt{200^2+2500^2}\\\Rightarrow h=2507.98\ ft[/tex]

Now y = 2500 ft

[tex]cos\theta=\dfrac{200}{h}\\\Rightarrow cos\theta=\dfrac{200}{2507.98}=0.07974[/tex]

[tex]\dfrac{d\theta}{dt}=\dfrac{1}{2}\times 0.07974^2\\\Rightarrow \dfrac{d\theta}{dt}=0.0031792338\ rad/s[/tex]

The angle is changing at 0.0031792338 rad/s

The rate of change of the angle of elevation in this problem would be calculated using the principles of related rates problems in calculus. This involves setting up an equation relating the quantities of interest (here, the altitude of the balloon and the angle of elevation seen by the observer), and differentiating this equation with respect to time. The precise calculation could not be completed as the question lacked certain specific data.

Rate of change of the angle of elevation is being calculated in this question. This question falls into the category of related rates problems in calculus, where the rate of change of one quantity (here, the altitude or the height to which the balloon has ascended) affects the rate of change of another quantity (the angle of elevation seen by the observer on the ground). However, the provided reference information does not appear to give specific details needed to answer this question.

Generally, you would use the properties of a right angled triangle and the concept of derivatives to set up an equation relating the quantities and find the value. For example, if we consider a right triangle where the observer and the balloon at a particular moment form the ends of a line representing the hypotenuse, and the angle of elevation to the balloon as θ, then tan(θ) = (altitude of the balloon) / (distance of observer from the launch point). And you'd differentiate this equation with respect to time to find the rate of change of the angle θ. However, again, the specific calculation may require more detailed information not provided here.

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Answer:

P = 462.62 watts

Explanation:

The power needed to accomplish this can be calculated how

P = Fv

    Where F:  The force exerted by the horse

                v:  velocity

The force exerted by the horse is against friction force; how the movement is with constant velocity these forces must be equals, then

Fr = μN

    =μmg

    = (0.135)(195.9)(9.8)

    = 259.17 N

And the power is

P = (259.17)(1.785)

P = 462.62 watts

The power needed to accomplish this is 462.62 watts.

It is defined as the numerical value that indicates the amount of friction present between the surfaces of two bodies. The lower the coefficient of friction the lower the friction between the surfaces and the higher coefficient of friction the higher the friction force between them.

We know the:

P = F×v

Where P is the power needed to accomplish this.

F = force exerted by the horse

v = velocity of the horse.

For F = [tex]\rm \mu N[/tex]

[tex]\mu = 0.135[/tex]

N = mg ⇒ 195.9×9.8   ( m= 195.9 kg and g = 9.8 [tex]\rm m/sec^2[/tex])

N = 1919.82 Newtons

F = 0.135×1919.82 ⇒ 259.1757 Newtons

Now P = F×v ⇒259.1757×1.785

P = 462.62  Watts

Thus, the power needed to accomplish this is 462.62 watts.

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Answer:True

Explanation:

The above statement is true as an anti-lock braking system (ABS) is a vehicle protection system that helps the wheels on a  vehicle to keep up tractive force with the road. ABS does not allow the brake to lock during braking and thus avoiding skidding which is necessary to avoid in wet roads otherwise it could be fatal for drivers.

It is widely used in vehicles to improve the safety measures and reduce road accidents.

Answer:

[tex]W_{AB} = EqL[/tex]

Explanation:

The work done by the electrostatic force is

[tex]W_{AB} = \int\limits^A_B {\vec{F}(x)} \, d\vec{x}[/tex]

where F can be calculated by Coulomb's Law:

[tex]\vec{F} = \frac{1}{4\pi \epsilon_0}\frac{q_0q_1}{x^2}[/tex]

We can express this equation by the variables given in the question.

Electric field is denoted as E.

[tex]\vec{F} = \vec{E}q = Eq~(+\^i)[/tex]

The distance, x, is given as L. If B is greater than A, the work done is positive. Else, work is negative.

[tex]W_{AB} = \int\limits^A_B {\vec{E}q} \, d\vec{x} = Eq(B-A) = EqL[/tex]

The work done on a charge q moving from point A to B in an electrostatic field E can be calculated using the formula: WAB = - q * E * L * cos(α). The maximum work is done when the charge is moving parallel to the electric field.

The work done on a charge, q, moving under an electrostatic field, E, from point A to B - referred to as WAB - can be calculated using the formula: WAB = - q * E * L * cos(α), where E is the electric field intensity, q is the charge, L is the displacement, and α is the angle between the electric field vector and the displacement.

This equation dictates that the work done is inversely proportional to the cosine of the angle between the electric field and the displacement direction - implying that the maximum work is done when the charge is moving parallel to the electric field direction(alpha=0).

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Answer:

4 times

Explanation:

[tex]M[/tex] = mass of the earth

[tex]R[/tex] = radius of the earth

[tex]g_{e}[/tex] = acceleration due to gravity on earth

acceleration due to gravity on the earth is given as

[tex]g_{e} =\frac{GM}{R^{2}}[/tex]

[tex]w_{e}[/tex] = weight of the astronaut on earth

weight of the astronaut on earth is given as

[tex]w_{e} = m g_{e} = \frac{GMm}{R^{2}}[/tex]

[tex]M_{p}[/tex] = mass of the planet = [tex]4 M[/tex]

[tex]R_{p}[/tex] = radius of the planet = R

[tex]g_{p}[/tex] = acceleration due to gravity on earth

acceleration due to gravity on the planet is given as

[tex]g_{p} =\frac{GM_{p}}{R_{p}^{2}}\\g_{p} = \frac{4GM}{R^{2}}\\g_{p} = 4 g_{e}[/tex]

[tex]w_{p}[/tex] = weight of the astronaut on planet

weight of the astronaut on planet is given as

[tex]w_{p} = m g_{p}\\w_{p} = m (4) g_{e}\\w_{p} = 4 w_{e}[/tex]

hence the weight of the astronaut on the planet is four times.

Final answer:

An astronaut would weigh 4 times more on a planet with the same radius as Earth but 4 times its mass, due to the direct relationship between mass and gravitational force.

Explanation:

To understand how an astronaut's weight would change on a planet with the same radius as Earth but 4 times its mass, we need to consider the universal law of gravitation. The formula to calculate gravitational force (which determines weight) is F = G (m1m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two masses (the radius of the planet, in this case).

Since the planet has 4 times the mass of Earth but the same radius, applying these values to the formula shows that the astronaut's weight would be 4 times greater on this new planet compared to Earth. The increase in mass directly increases the gravitational force, while the radius remains constant, leading to an increase in weight.

Answer:

The right sphere is negatively charged, the left sphere is charged positively.

Explanation:

When a negatively charged rod is held above the top of left sphere, the rod will attract positive charges and repel negative charges. As the sphere are initially touching each other so positive charges from the both spheres will moves toward the rod. When we separate the spheres positive charges from right sphere have already moved toward the rod i.e. left sphere, creating a deficiency of positive charges in the right sphere and excessiveness of positive charges in left sphere , hence the right sphere will remain negatively charged and left sphere will remain positively charged.

Answer:

A. The object falls a distance of 250 m

Explanation:

Hi there!

In the question, you have forgotten the acceleration due to gravity. However, looking on the web I´ve found a very similar problem in which the acceleration due to gravity was as twice as much as it is on Earth.

The equation of height of a falling object is the following:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the object after a time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (on Earth: ≅ -10 m/s² considering the upward direction as positive).

Let´s place the origin of the system of reference at the point where the object is released so that y0 = 0. Since the object falls from rest, v0 = 0.

Then, the height of the object after 5 s will be :

y = 1/2 · 2 · g · t²    (notice that the acceleration due to gravity is 2 · g)

y = g · t²

y = -10 m/s² · (5 s)²

y = -250 m

The object falls a distance of 250 m.

The object falling on this other planet with the same gravity as Earth falls a distance closest to 250m in 5 seconds, according to the standard formula and doubling the Earth result.

Given the planet where the object is falling has the same acceleration due to gravity as Earth, we can use the formula for the distance fallen, d (in meters), over a certain time, t (in seconds), assuming the object falls from rest. This formula is d = 0.5 * g * t^2, where g is the acceleration due to gravity. For Earth, g is approximately 9.8 m/s^2.

When t=5 seconds on Earth, using the given formula, d = 0.5 * 9.8 * (5^2) = 122.5 meters. Since the object on the other planet falls twice the distance in the same time, the object falls 2 * 122.5 = 245 meters. Thus, Choice A) 250 m is the closest to the calculated value.

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Answer:

The Kepler Space Telescope is searching for extrasolar planets by the transit method. It is necessary for Kepler to photometrically monitor a large number of stars because increase the probability to see a transit.

Explanation:

Photometry is the study of the intensivity of light radiated from a particular object.

In the other hand, the transit method consists in the measured of the dimming on the brightness of a star when a planet is passing in front of it, as long as the star, the planet and the detector (in this case the Kepler Telescope) are in the same line of sign.  

However, that transit has a short duration. So it is necessary that the Kepler Telescope monitorates the brightness of several stars each thirty minutes in order to increase the probability of detection of a transit.

Answer:

Model reasoning vs Moral behavior,cultural differences, bias

Explanation:

The answer for this case: Model reasoning vs Moral behavior,cultural differences, bias

Model reasoning

In particular usually we have a positive correlation between higher stages of reasoning and higher levels of moral behavior. But in some cases, some found we have situational factors are better predictors of moral behavior.

One example is when people prefer to help people with some disease because an institute with most prestigy says this condition is given by a problem of the society when the reality is not true.

Cultural differences

This item can create some problem since we can create problems when we need to establish if one statement is true or not.

Bias

This is one of the most common problems since we don't have a criteria to decide if we have bias or no.

Answer:

12544 N.m

Explanation:

given,

length of beam = 4 m

mass of steel = 500 Kg

mass of worker = 70 Kg

torque at hinge = ?

weight of the beam will at the center of mass which is at 4/2 = 2 m distance form the hinge.

distance of worker = 4 m

torque acting at hinge=

 = Mg x 2 + mg x 4

 = 500 x 9.8 x 2 + 70 x 9.8 x 4

 = 12544 N.m

hence, torque experience at the hinge is equal to 12544 N.m

This question is incorrect.The correct question is here

You have purchased a new 24-pin power supply to replace one that failed. However, the motherboard only has a 20-pin connector. What should you do?

Answer:

To solve this problem you should plug the 24-pin power supply into the motherboard, as your mother board has 20 pin you leave pins 11, 12, 23, and 24 on the motherboard unconnected.

I have attached a picture from which you can see that there are pins for same working

Answer:

Cycles per second is dependent on the construction of the alternator and the 120 volts is dependent upon the current and resistance in the circuit according to the ohms law.

Explanation:

We are given with AC of 120 volts, 20 amperes and 60 hertz frequency.

According to the Ohm's law, we find its resistance:

[tex]R=\frac{V}{I}[/tex]

[tex]R=\frac{120}{20}[/tex]

[tex]R=6\ \Omega[/tex]

So, this 6 ohm resistance controls the current controls the magnitude of the AC current, while the frequency of the current remains constant and depends upon the construction and rotational speed of the armature of the alternator producing the current.

Here the value of frequency is the number of times the current changes its direction or the polarity in one second.

The control of the AC power frequency is managed by power plant generators, which use turbine controls to ensure electricity alternates at a specific frequency, such as the standard 60 Hz in North America. Voltage and current in AC power cross zero 120 times a second due to this oscillation.

Alternating Current (AC) electric power is characterized by a voltage that alternates in polarity from positive to negative, resulting in a sinusoidal waveform. The frequency of this oscillation in North America is 60 times per second (60 Hz). This oscillation means that the voltage swings from a peak value to the opposite peak value, crossing zero in the process, twice every cycle. Therefore, for a 60 Hz AC supply, voltage and current cross zero 120 times a second.

The control of the frequency at which this oscillation occurs is managed by the generator at the power plant. In the case of a hydro-electric dam, turbine controls adjust the rotational frequency to produce the desired AC frequency. For example, in North America, these turbines are regulated to rotate in such a way that the electricity they generate alternates at 60 Hz. This regulated rotation is what ensures the consistency of the 120 volts at 60 cycles per second.

The power consumption of an electrical device such as a light bulb in an AC circuit also swings. Peak power is calculated by multiplying peak current by peak voltage. Given that the root mean square (RMS) voltage is 120 volts for a standard AC outlet, the peak voltage is actually higher, around 170 volts. Thus, for a 60-watt light bulb, the power consumption will pulse from zero up to its peak value 120 times per second, averaging out to the rated 60 watts.

Answer:

same

Explanation:

Acc. to Einstien's postulate of special theory of

Relativity , Velocity of the light beam is same in all frames of references

(a) If the freight car is at rest

The frame we can assumed as Non - inertial frame  of reference s

In the inertial frame of reference , velocity  of the light beam  has its own value as : 3 x 10^8 m/s

(b) If the freight car is moving , the frame we can assumed as  Non -inertial frame of reference    

In thus case also , The velocity of the light beam  will also have  the same value as ; 3 x 108 m/s

Answer: The cell potential is 0.712 V

Explanation:

The substance having highest positive [tex]E^o[/tex] potential will always get reduced and will undergo reduction reaction. Here, silver will undergo reduction reaction will get reduced. Hydrogen will undergo oxidation reaction and will get oxidized

Half reactions for the given cell follows:

Oxidation half reaction: [tex]H_2(1.00atm)\rightarrow 2H^{+}(0.355M)+2e^-;E^o_{H^{+}/H_2}=0.00V[/tex]

Reduction half reaction: [tex]Ag^{+}(0.0115M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V[/tex]   ( × 2 )

Net reaction: [tex]H_2(1.00atm)+2Ag^{+}(0.0115M)\rightarrow 2H^{+}(0.355M)+2Ag(s)[/tex]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the [tex]E^o_{cell}[/tex] of the reaction, we use the equation:

[tex]E^o_{cell}=E^o_{cathode}-E^o_{anode}[/tex]

Putting values in above equation, we get:

[tex]E^o_{cell}=0.80-(0.00)=0.80V[/tex]

To calculate the EMF of the cell, we use the Nernst equation, which is:

[tex]E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^2}{[Ag^{+}]^2}[/tex]

where,

[tex]E_{cell}[/tex] = electrode potential of the cell = ?V

[tex]E^o_{cell}[/tex] = standard electrode potential of the cell = +0.80 V

n = number of electrons exchanged = 2

[tex][Ag^{+}]=0.0115M[/tex]

[tex][H^{+}]=0.355M[/tex]

Putting values in above equation, we get:

[tex]E_{cell}=0.80-\frac{0.059}{2}\times \log(\frac{(0.355)^2}{(0.0115)^2})\\\\E_{cell}=0.712V[/tex]

Hence, the cell potential is 0.712 V

The cell potential of the cell is  0.71 V.

The overall equation of the redox reaction is;

2Ag^+(aq) + H2(g)  ----> 2H^+(aq) + Ag(s)

The E°cell =  E°cathode -  E°anode

E°cell =  0.80 V -  0.00 V = 0.80 V

Using the Nernst equation;

Ecell =  E°cell - 0.0592/n logQ

Where n = 2

Q = [H^+]^2/[Ag^+]^2 = (0.355 M)^2/(0.0115 M)^2

Q = 952.7

Substituting values;

Ecell = 0.80 V -  0.0592/2 log ( 952.7)

Ecell = 0.71 V

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Answer:

Assessment zone

Explanation:

It is the assessment zone in various security zones where active and passive security measures are employed to identify, detect, classify and analyze possible threats inside the assessment zones.

Answer:

125.04181 W

Explanation:

[tex]\sigma[/tex] = Stefan-Boltzmann constant = [tex]5.67\times 10^{-8}\ W/m^2K^4[/tex]

A = Surface area = 1.9 m²

[tex]T_b[/tex] = Skin surface temperature = 19°C

[tex]T_s[/tex] = Room temperature = 30°C

[tex]\epsilon[/tex] = Emissivity = 1

Radiated thermal energy is given by

[tex]P=\epsilon A\sigma (T_b^4-T_s^4)\\\Rightarrow P=1\times 1.9\times 5.67\times 10^{-8}((273.15+30)^4-(273.15+19)^4)\\\Rightarrow P=125.04181\ W[/tex]

The net amount of heat this person could radiate per second into the room is 125.04181 W

Answer:36 cm

Explanation:

Given

At Equilibrium extension a is 18 cm

suppose m is the mass of block

thus

[tex]ka=mg[/tex]

[tex]k=\frac{mg}{a}[/tex]

[tex]k=\frac{mg}{0.18}[/tex]

Now if the block is released from un-stretched position

conserving Energy and supposing block moves x units down

[tex]\frac{1}{2}kx^2=mgx[/tex]

[tex]x=\frac{2mg}{k}[/tex]

[tex]x=2mg\times \frac{0.18}{mg}[/tex]

[tex]x=0.36 \approx 36 cm[/tex]

Answer:

3. [tex]h^2[/tex]

Explanation:

Energy of volume contained in a dam is given by

[tex]E=\dfrac{1}{2}A\rho gh^2[/tex]

where,

A = Horizontal surface area of the barrage

[tex]\rho[/tex] = Density of water

g = Acceleration due to gravity = 9.81 m/s²

h =  Vertical tidal range,

It can be seen that

[tex]E\propto h^2[/tex]

Hence, the energy is proportional to [tex]h^2[/tex]

Final answer:

The gravitational potential energy of water behind a dam is directly proportional to the height of the water column, using the formula PE = mgh. For a tidal basin, the GPE is proportional to the average height (h/2), therefore, the correct relationship is proportional to the height h. So the correct option is 2.

Explanation:

The relationship between the height and gravitational potential energy (GPE) of water behind a dam is that GPE is directly proportional to the height of the water column. The formula to calculate the GPE is PE = mgh, where PE is the potential energy, m is the mass of the water, g is the acceleration due to gravity, and h is the height above the reference point.

When we consider a tidal basin with water depth h at high tide transitioning to zero at low tide, the average height of water behind the wall is h/2. Since mass (m) is the product of the water's density (assumed to be 1,000 kg/m³ for water) and volume—which, in turn, is the area of the water surface (A) multiplied by its height (h)—the GPE of water stored between a high tide and low tide is proportional to the average height, thus proportional to h. Therefore, the correct answer is option 2, which states that the gravitational potential energy of the water stored in the basin between high tide and low tide is proportional to h.

Answer:

A force of 83 N is needed to pull the sled with constant speed.

Explanation:

Hi there!

Please, see the attached figure for a graphical description of the problem.

We have the following horizontal forces applied on the sled:

F = applied force.

Fr = friction force.

And the following vertical forces:

N = normal force.

W = weight of the sled + weight of the person

According to the Newton´s second law:

∑F = m · a

Where "m" is the mass of the object and "a" is its acceleration

So, in the horizontal direction:

F - Fr = m · a

We have to find what force, F, is needed so that the sled moves with constant speed (acceleration = 0). Then:

F - Fr = 0

F = Fr

The applied force has to be equal in magnitude to the friction force.

The friction force is calculated as follows:

Fr = μ · N

Where μ is the coefficient of friction and N is the normal force.

To find the normal force, let´s apply Newton´s second law in the vertical direction:

∑F = N - W = m · a

Notice that the sled is not accelerated in the vertical direction so that a = 0:

N - W = 0

N = W

The normal force is equal to the weight and the weight is the sum of the weight of the sled plus the weight of the person:

W = 52 N + 700 N = 752 N

Then:

N = 752 N

Fr = 0.11 · 752 N

Fr = 83 N

Then

F = 83 N

A force of 83 N is needed to pull the sled with constant speed.

A force of 83 N is needed to pull the sled with constant speed.

We have the following horizontal forces applied on the sled:

F = applied force.

Fr = friction force.

And the following vertical forces:

N = normal force.

W = weight of the sled + weight of the person

According to the Newton´s second law:  

F = m * a

Where "m" is the mass of the object and "a" is its acceleration

So, in the horizontal direction:

F - Fr = m *a

To find what force, F, is needed so that the sled moves with constant speed (acceleration = 0). Then,

F - Fr = 0

F = Fr

The applied force has to be equal in magnitude to the friction force.

The friction force is calculated as follows:

Fr = μ · N

Where μ is the coefficient of friction and N is the normal force.

To find the normal force, let´s apply Newton´s second law in the vertical direction:

F = N - W = m · a

Notice that the sled is not accelerated in the vertical direction so that a = 0:

N - W = 0

N = W

The normal force is equal to the weight and the weight is the sum of the weight of the sled plus the weight of the person:

W = 52 N + 700 N = 752 N

Then:

N = 752 N

Fr = 0.11 · 752 N

Fr = 83 N

Then

F = 83 N

A force of 83 N is needed to pull the sled with constant speed.

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Answer:

[tex]F_{piston} = 600 N[/tex]

Explanation:

[tex]F_{car}[/tex] = weight of the car  = Force on the larger piston = 15000 N

[tex]r_{1}[/tex] = radius of the larger piston = 0.20 m

[tex]F_{piston}[/tex] = force on the smaller piston

[tex]r_{2}[/tex] = radius of the smaller piston = 0.040 m

Using pascal's law, Pressure must be equal on each piston, hence

[tex]\frac{F_{car}}{\pi r_{1}^{2} } = \frac{F_{piston}}{\pi r_{2}^{2} } \\\\\frac{15000}{0.20^{2} } = \frac{F_{piston}}{0.040^{2} }\\\\F_{piston} = 600 N[/tex]

600 N force must be applied to this smaller piston in order to lift the car.

Let's solve the question:

It states that if some pressure is applied at any point of incompressible liquid then the same pressure is transmitted to all the points of liquid and on the walls of the container.

Given:

Force on car, F= 15,000 N

Radius of larger piston, r₁ = 0.20m

Radius of larger piston, r₂ = 0.040m

To find:

Force on piston, F=?

Using Pascal's law:

[tex]\frac{F_{car}}{\pi r_1^2} =\frac{F_{piston}}{\pir_2^2}\\\\ \frac{15000}{0.20^2}=\frac{F_{piston}}{0.40^2}\\\\F_{piston}=600N[/tex]

600 N force must be applied to this smaller piston in order to lift the car.

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Answer:

Explanation:

Given

height [tex]h=6.2 km[/tex]

Initial temperature [tex]T_1=30^{\circ}C[/tex]

Specific heat of lead [tex]c=126 J/kg-^{\circ}C[/tex]

Melting Point of Lead [tex]T_m=130^{\circ}C[/tex]

Here Potential Energy is converted to heat energy to melt the lead ball

Sphere ball will first will be heated to [tex]130^{\circ}C[/tex] then it starts melting

thus

[tex]mgh=mc\Delta T+mL[/tex]

where [tex]L=latent\ heat\ of\ fusion[/tex]

[tex]\Delta T=[/tex]change in Temperature

[tex]gh=c\Delta T+L[/tex]

[tex]9.8\times 6.2\times 1000=126\times (130-30)+L[/tex]

[tex]L=48,160\ J/kg [/tex]

[tex]L=48.16\ kJ/kg[/tex]

Answer:

 "Same"  

"Ben Pumpiniron"

Explanation:

Given that

Will lifts 100 pound ,10 times in 1 minute

Ben lifts 100 pound ,10 times in 10 sec

As we know that work done given as

W= m g h

The height and mass are same for both therefore there will do the same work.

But we know that rate of work is known as power.Therefore Ben is more power .

Power

[tex]P=\dfrac{W}{t}[/tex]

t is less for Ben that is why power is more in Ben.

The answer will be "Same"  and "Ben Pumpiniron".

Explanation:

Both Ben and Will are doing same amount of work. that is lifting 100 pounds of barbell 10 times.

They apply the same force to lift the same barbell up to same distance hence, they do equal work.

Yet Ben is more powerful than Will because rate of work done (Power) by Ben is higher than the that of Will.

Answer:what is the role of of geologist in the petroleum industry

A. Stay with the drillers to examine rocks and fossils brought to the surface.

B. Chart information on a well log

C. Calculate the distance and direction of movement of the lost vein of ore

D. locate environment in which the petroleum forms

Correct option. Is D locate environment in which petroleum forms

Explanation:

Petroleum geologists are usually linked to the actual discovery of oil and the identification of possible oil deposits or leads. It can be a very labor-intensive task involving several different fields of science and elaborate equipment. Petroleum

geologists look at the structural and

sedimentary aspects of the stratum/strata to identify possible oil traps

Answer: D locate environment in which the petroleum forms

Explanation:

Answer:

Elastic deformation

Explanation:

When rock retains its new shape (without fracturing) after stress has been removed, it has undergone elastic deformation.

Elastic deformation is the process in which the object under temporary stress regains its original shape after the stress is removed. The stress must be low and not strong enough that it can create fracture and permanent damage to the object. for example, we can stretch a rubber band by applying some force and when we remove the force, the rubber band comes back to its original length and shape.

Answer:

Carbon, nitrogen and sulphur.

Explanation:

In carbon cycle, carbon dioxide is in the gaseous form in atmosphere. This gaseous carbon dioxide is emitted in the atmosphere through combustion of fossils, respiration, decomposition. In nitrogen cycle, atmospheric nitrogen is in the gaseous form which is emitted through denitrification. In sulphur cycle, sulphur is in the form of gaseous sulphur dioxide in the atmosphere. This sulphur is emitted in the atmosphere by the volatilization of hydrogen sulphide.

Elements such as carbon, nitrogen, and oxygen go through a gaseous phase in their respective nutrient cycles (the Carbon Cycle and Nitrogen Cycle for instance), moving through the environment in a regular pattern.

Certain elements move through our planet's systems, such as the water, atmosphere, and soils, in cycles known as nutrient cycles or biogeochemical cycles. These elements often go through a gaseous phase. Carbon, nitrogen, and oxygen are examples of elements that have a gaseous phase in their cycle. For instance, Nitrogen Cycle involves nitrogen gas in the atmosphere being converted into usable forms by bacteria in a process known as nitrogen fixation. Similarly, in the Carbon Cycle, carbon dioxide gas is absorbed by plants and converted into organic carbon through photosynthesis.

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Answer:

Power, P=1.57×[tex]10^{-6}[/tex] Watt

Explanation:

Given

Intensity, I=1×[tex]10^{-8}[/tex] W/m²

Distance, r=5 meter

Considering the hemispherical space with radius 5 meter centered on the speaker. Speaker emits sound wave continuously with Power P. Intensity I is constant throughout the space and defined as power per unit area.

I=[tex]\frac{P}{A}[/tex]

so, P=I×A

where A is the area of shape of propagation.

since ,shape of propagation is hemispherical

so, A=2×p×r²=2×3.14×5×5=157 m²

P=1×[tex]10^{-8}[/tex]×157

P=1.57×[tex]10^{-6}[/tex] Watt

Answer:

The Earth would increase in volume

Explanation:

What would happen to Earth if ocean floor were created at divergent boundaries at a faster rate than it is destroyed at convergent boundaries?

Divergent boundaries are boundaries where plates pull away from each other, forming mild earthquakes and volcanoes as magma comes to the surface. Earthquakes are as a result of vibrations travelling within the earth or ocean floors . Volcanoes occur as a result of the eruption of  molten magma from the ocean floor

In divergent boundaries, the plates pull away and and the weakened crust in between collapse leaving more space thereby increasing in volume.

Convergent boundaries are boundaries that pull into each other. mountain chains are formed as the two plates push into each other if they are of the same density.

Answer:  B.) To nearly its original height

Explanation:

Because if you have a ball than the inclined plane is heading up you would get almost the same height as it started.

Galileo found that a ball rolling down one inclined plane then, the ball will reach about the original height. Hence, option B is correct.

The momentum is the result of a particle's velocity and its mass. Force and motion, meaning it has both magnitude and the direction.

According to Isaac Newton's second equation of motion, the force acting on a particle equals the time rate of increase of momentum.

The impulse, which is the product of the force and the intervals (the impulse), is equal to the difference in momentum, according to Newton's 2nd law, if a steady force operates on a particle for a specific amount of time.

On the other hand, a particle's momentum is the amount of time needed for a consistent action to fight it to rest.

Because if you were to throw a ball while the inclined plane was moving upward, you would nearly reach its starting height.

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Answer:

There are 2 number of significant figures.

Explanation:

Significant figures include a zero at the start or between the digits after the decimal. But do not include a zero at the end. There are two zeros . It is 6400 but these zeros are at the end so they will not be counted in the significant figures. If they were present at the start or between any two non zero digits they would be included in significant figured