What are advantages of lookup fields?

Options:

a) The client wants to develop internal resources and capabilities

b) The client is looking for the lowest possible costs

c) The client has unique business requirement that must be satisfied by this software application

d) The client has some existing technology in place whose requirements must be met by the new software

Answer:

d) The client has some existing technology in place whose requirements must be met by the new software

Explanation:

For a client to purchase a software, the client has an already existing technology that requires that software for adequate functioning. The analyst will recommend the new software to the client based on the technology he/she previously has and the requirements he wants to meet.

The other options are not impossible, but they are not the primary reason why the software will be purchased, the overall aim for all the company's activities may be to develop internal resources and capabilities or to meet some unique business requirements, but these are secondary. The primary purpose is that the client has a technology that cannot function properly without the recommended software.

Answer:

See explaination

Explanation:

function thanos(lst) {

var result = [];

for (var i = 0; i < lst.length; i += 2) {

result.push(lst[i]);

}

return result;

}

// Testing the function here. ignore/remove the code below if not required

console.log(thanos([]));

console.log(thanos(['0', 2, 4]));

Answer:

See explaination

Explanation:

Given a set U which is the set of magnets where each magnet representing a symbol, but are accepted more copies of the same symbol which we number arbitrarily 1,2,3,. ... For example if we had two copies of the symbol A, we would have elements A 1 ,A 2 ) and subsets S 1 ,...S n which represent words formed from the magnets that Madison knows how to spell. Note that if ‘’CAT” was a word in Madison’s vocabulary, then both of the sets C,A 1 ,T and C,A 2 ,T would appear among the S i . We are interested in the maximum number of disjoint sets (which correspond to words in Madison’s vocabulary that can be simultaneously spelled out by the magnet pieces).

We reduce Independent Set (IS) to Set Packing. Given an instance of IS ( G,k ), we set U to be the set of edges of G . For each vertex v i , we introduce a set S i = { e : e = ( v i ,x ) } which has one element for each edge incident to v i . We claim that G has an independent set of size k iff there are k disjoint sets among the S i . Indeed, if I is an independent set of size k then the k sets S v for v ∈ I have no common elements. Also, if { S i 1 ,...,S i k } are k disjoint sets then the vertices v i 1 ,...,v i k have no edges between them thus they form an independent set of size.

Answer:

The answer to this question can be described as follows:

Explanation:

The mission-critical System-

A vital mission program is necessary for an organization's life. If a critical task program disrupted, industrial control should be severely affected.  The essential support device is often referred to as critical task equipment.

Safety system for nuclear reactors-

The nuclear power plant is used to control the system, and it also contains and continues reactions.  It's also usually used only for energy production, and also used experiments and clinical isotope manufacture.  

If another system of nuclear power fails, this could result in a continuous nuclear reaction in a range of aspects like irradiated leaks. These same persons across the area may experience serious radioactivity symptoms.

The main task in their personal life-  

They realize, that without power, they turn down your entire life when you've never encountered a dark off with more than 30 minutes. Essentially, people wouldn't have been allowed to do what you'll do, entirely frozen.  

Consumer survey: big financial transfer controlling business-

That company is the infrastructure and software supplier for banks, traders, distributors, and institutional investors to take out money transfers. With all the money transfers they depend on, you must establish a successful company to become the 'guy behind the button', etc.

Answer:

If there is a majority element in the array it will be the median. Thus,

just run the linear time median finding algorithm, and compare the result with all the  elements of the array (also linear time). If [tex]\frac{n}{2}[/tex]elements are the same as the median, the  median is a ma majority element. If not, there is none.

Suppose now that the elements of the array are not from some ordered domain like the  integers, and so there can be no comparisons of the form "is the ith element of the array  greater than the jth element of the array?" However you can answer questions of the  form:

"Are the ith and jth elements of the array the same?" in constant time. Such

queries constitute the only way whereby you can access the array. (Think of the elements  of the array as GIF files, say.) Notice that your solution above cannot be used now.

Answer:

D. All of the above are correct.

Explanation:

Asynchronous Transfer Mode is a fixed-length cell structure which allows cells to support voice, video  and data. Voice data can be converted to packets and shared with large packet data. Because voice packets, encounter queuing delays, they ought to be of the same size or length.

ATM provides a route between two end points and that is why it can be said to be connection oriented. There is an ease of switching in hardware because of the fixed structure of the ATM. It also offers predictability regarding latency which could be either high or low. So, all of the above satisfy the mode of operation of the Asynchronous Transfer Mode.

Answer:

The answer is "loss of 1,260,000"

Explanation:

Following are the important points of the question:

The cost of research and development is = $3840000

net income of the company is=  $2580000

Find: loss or profit .

According to the rate of the cost, the company cost is higher than the company rate. So, the company goes in loss stage, then  

Loss = total cost - net income

Loss = $3840000 - $2580000

Loss= $ 1,260,000

The computer company would face a net loss of $1,260,000.

The question is asking about the calculation of net income or loss for a computer company after accounting for research and development costs. To determine the net income or loss, we subtract the research and development (R&D) costs from the company's income before these costs are accounted for.

So, if the net income before R&D costs is $2,580,000 and the R&D costs are $3,840,000, we perform the following calculation:

Net Income after R&D = Net Income before R&D - R&D costs

Net Income after R&D = $2,580,000 - $3,840,000

Net Income after R&D = -$1,260,000

This result is a net loss of $1,260,000 after accounting for R&D costs.

Answer:

Because reusing the old passwords possess security threats.

Explanation:

A password can be defined as a string of characters or words or phrases that are used to authenticate the identity of the user. It is also known as passcode and should be kept confidential. A password is used to access constricted systems, applications, etc.

A password or passcode is usually composed of alphabets, numbers, symbols, characters, alphanumeric, or a combination of these.

In the given case, Judy was not able to change her passcode to the previous one because reusing old passwords is prohibited in any sites or systems. A system denies the user to reuse the old passwords for various reasons but most importantly due to security reasons. Though it is said that old passwords can be used after 100 times but seldom someone changes a password that much. All systems care for the security of their users thus they deny reusing old passcodes.

Answer:

The flowchart to this question can be given in attachment.

Explanation:

In the given statement, a flowchart is defined, in which we use an oval shape to start the, in the next step square shape is used, that initializes the value 0 in z variable, and an input box is used for user input in x variable.

Answer:

A

To ensure that Susan no longer has access without erasing her files I'll take the following steps:

B

The benefits that accrue to retaining her information will depend on the value of information that her account possesses. As the former executive IT personnel, this is most likely the case.

In the long run, the safest thing to do might be to just back up all information she created and had access to to a remote storage or data warehouse.

Cheers!

Answer:

def print_shampoo_instructions(num_cycles):

   if num_cycles < 1:

       print("Too few.")

   elif num_cycles >4:

       print("Too many.")

   else:

       N = 1

       for N in range (N,num_cycles+1):

           print(N,": Lather and rinse.")

       print("Done.")

Explanation:

Final answer:

The function shampoo_instructions() controls repetitions based on input, preventing infinite loops, akin to the shampoo instructions' issue. It emphasizes the importance of iteration control in programming loops to avoid endless execution. Understanding how to manage loop cycles prevents program malfunction due to infinite loops.

Explanation:

shampoo_instructions() is a function that takes a parameter num_cycles and prints instructions based on the input. If num_cycles is less than 1, it prints 'Too few.'; if more than 4, it prints 'Too many.'; otherwise, it prints the cycle number followed by 'Lather and rinse.' num_cycles times.The directions on shampoo create an infinite loop since they lack an iteration variable to specify the number of repetitions. In programming, developers must include a mechanism to control loops' execution, preventing infinite iterations.

In a loop, each iteration represents a cycle, akin to the instructions in shampoo; therefore, the concept of controlling the number of repetitions is fundamental to avoid infinite loops and ensure proper program execution.

Answer:

Linux is Unix-based and Unix was originally designed to provide an environment that's powerful, stable and reliable yet easy to use. Linux systems are widely known for their stability and reliability, many Linux servers on the Internet have been running for years without failure or even being restarted

Explanation:

Linux is used for commercial networking

Answer:

See attachment please

Answer:

The Power supply has been damaged.

Explanation:

There is no video on the monitor, but the monitor is tamed on. Also, there is no fan spinning sound. What this means is that the Power supply is not working, because fan is unable to work. The light of monitor is on because the direct power supply from the building is fate.

Note: In case of CMOS RAM is damaged, or processor is damaged, CPU fan will run properly until and unless the power supply is not enough.

Answer:

See explaination

Explanation:

public class InsertionSorter {

/* Function to sort array using insertion sort */

int sort(Comparable arr[]) {

int count = 0;

if (arr == null || arr.length == 0)

return 0;

int n = arr.length;

for (int i = 1; i < n; ++i) {

Comparable key = arr[i];

int j = i - 1;

while (j >= 0 && arr[j].compareTo(key) > 0) {

count++;

arr[j + 1] = arr[j];

j = j - 1;

}

arr[j + 1] = key;

}

return count;

}

// Driver method

public static void main(String args[]) {

Integer arr[] = { 50,21,34,26, 18, 31, 37, 54 };

InsertionSorter ob = new InsertionSorter();

int comp = ob.sort(arr);

System.out.println("Comparisons required : "+comp);

for(int i:arr)

System.out.print(i+" ");

}

}

Answer:

systems engineering

Explanation:

In systems engineering, information systems and software engineering, the systems development life cycle, also referred to as the application development life-cycle, is a process for planning, creating, testing, and deploying an information system.

Answer:

Live Preview.

Explanation:

This is a feature specifically found in the microsoft power point in detailing or slides showing in a preliminary stage of its previews.

By default, when you select the composing email content and change its text format, such as text font, size, color and so on, the live preview will be displayed when you put your cursor on different text format.

Actually the live preview function can be enabled or disabled manually in Outlook. In this tutorial, we will show you how to enable or disable live preview in Outlook in details.

Answer:

Kindly go to the explanation part for the code you seek.

Explanation:

This is the Code to Copy:

package file;

import java.io.BufferedReader;

import java.io.BufferedWriter;

import java.io.DataInputStream;

import java.io.FileInputStream;

import java.io.FileWriter;

import java.io.InputStreamReader;

import java.util.Scanner;

public class file

{

public static void main(String []args)

{

try

{

System.out.print("Type a file name: ");

//declare scanner for keyboard input

Scanner reader = new Scanner(System.in);

//scan the input file name

String infilename=reader.nextLine();

//define file stream

FileInputStream fstream = new FileInputStream(infilename);

DataInputStream in = new DataInputStream(fstream);

//define the buffer reader

BufferedReader br = new BufferedReader(new InputStreamReader(in));

String outfilename = "output.txt";

FileWriter fileWriter = new FileWriter(outfilename);

//declare buffer writer for file write

BufferedWriter bufferedWriter = new BufferedWriter(fileWriter);

String strLine,filename;

int status = 0;

int i=0;

//read lines one by one from input file

while ((strLine = br.readLine()) != null)

{

String temp="";

//for each character in a line

for(int k=0;k<strLine.length();k++)

{

char c;

c=strLine.charAt(k);

//if the character is uppercase

if(Character.isUpperCase(c))

//make the character lowercase and append it to the output line

temp +=Character.toLowerCase(c);

else

//character is not lowercase. append to the output line without changing it

temp += c;

}

//write the line to the file

bufferedWriter.write(temp+"\n");

}

//close the input file

in.close();

//close the output file

bufferedWriter.close();

}

catch (Exception e)

{

//System.err.println("Error: " + e.getMessage());

}

}

}

Answer:

See explaination

Explanation:

PhoneLookup.java

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class PhoneLookup

{

public static void main(String[] args) throws IOException

{

Scanner in = new Scanner(System.in);

System.out.println("Enter the name of the phonebook file: ");

String fileName = in.nextLine();

LookupTable table = new LookupTable();

FileReader reader = new FileReader(fileName);

table.read(new Scanner(reader));

boolean more = true;

while (more)

{

System.out.println("Lookup N)ame, P)hone number, Q)uit?");

String cmd = in.nextLine();

if (cmd.equalsIgnoreCase("Q"))

more = false;

else if (cmd.equalsIgnoreCase("N"))

{

System.out.println("Enter name:");

String n = in.nextLine();

System.out.println("Phone number: " + table.lookup(n));

}

else if (cmd.equalsIgnoreCase("P"))

{

System.out.println("Enter phone number:");

String n = in.nextLine();

System.out.println("Name: " + table.reverseLookup(n));

}

}

}

}

LookupTable.java

import java.util.ArrayList;

import java.util.Collections;

import java.util.Scanner;

/**

A table for lookups and reverse lookups

*/

public class LookupTable

{

private ArrayList<Item> people;

/**

Constructs a LookupTable object.

*/

public LookupTable()

{

people = new ArrayList<Item>();

}

/**

Reads key/value pairs.

atparam in the scanner for reading the input

*/

public void read(Scanner in)

{

while(in.hasNext()){

String name = in.nextLine();

String number = in.nextLine();

people.add(new Item(name, number));

}

}

/**

Looks up an item in the table.

atparam k the key to find

atreturn the value with the given key, or null if no

such item was found.

*/

public String lookup(String k)

{

String output = null;

for(Item item: people){

if(k.equals(item.getName())){

output = item.getNumber();

}

}

return output;

}

/**

Looks up an item in the table.

atparam v the value to find

atreturn the key with the given value, or null if no

such item was found.

*/

public String reverseLookup(String v)

{

String output = null;

for(Item item: people){

if(v.equals(item.getNumber())){

output = item.getName();

}

}

return output;

}

}

Item.java

public class Item {

private String name, number;

public Item(String aName, String aNumber){

name = aName;

number = aNumber;

}

public String getName(){

return name;

}

public String getNumber(){

return number;

}

}

input.txt

Abbott, Amy

408-924-1669

Abeyta, Ric

408-924-2185

Abrams, Arthur

408-924-6120

Abriam-Yago, Kathy

408-924-3159

Accardo, Dan

408-924-2236

Acevedo, Elvira

408-924-5200

Acevedo, Gloria

408-924-6556

Achtenhagen, Stephen

408-924-3522

Note: Replace all the "at" with at symbol

Answer:

public class Pyramid {

   public static void main(String[] args) {

             int h = 7;

       System.out.println("Pattern A");

               for(int i = 1; i <= h; ++i)

               {

                   for(int j = 1; j <= i; ++j) {

                       System.out.print("+");

                   }

                   System.out.println();

               }

       System.out.println();

       System.out.println("Pattern B");

               for (int i = 1; i<=h; ++i)

               {

                 for(int j = h; j >=i; --j){

                     System.out.print("+");

                 }

                   System.out.println();

               }

           }

       }

Explanation:

Answer:

Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".

Explanation:

The main issue with the first code segment is the way how the if else if condition are arranged. The "pea" is checked at the earliest time in the first code segment and therefore so long as there is the "pea" exist in the string (regardless there is pear or pearl exist in the string as well), the if condition will become true and display "pea" to terminal. This is the reason why the code segment 1 only work for the values of str that contain "pea".

Answer:

a) Time to live field

b) Destination

c) Yes, they have two ip addresses.

d) 128 bits

e) 32 hexadecimal digits

Explanation:

a) the time to live field (TTL) indicates how long a packet can survive in a network and whether the packet should be discarded. The TTL is filled to limit the number of packets passing through N routers.

b) When a large datagram is fragmented into multiple smaller datagrams, they are reassembled at the destination into a single large datagram before beung passed to the next layer.

c) Yes, each router has a unique IP address that can be used to identify it. Each router has two IP addresses, each assigned to the wide area network interface and the local area network interface.

d) IPv6 addresses are represented by eight our characters hexadecimal numbers. Each hexadecimal number have 16 bits making a total of 128 bits (8 × 16)  

e) IPv6 address has 32 hexadecimal digits with 4 bits/hex digit

The TCP/IP concepts of packet forwarding, fragmentation, and reassembly along with IPv4 and IPv6 addressing schemes are explained.

TTL (Time To Live) field in the IPv4 datagram header can be used to ensure that a packet is forwarded through no more than N routers. When a large datagram is fragmented into multiple smaller datagrams, these smaller datagrams are reassembled into a single larger datagram at the destination host. Routers do have IP addresses, typically one per interface, so the number varies. IPv6 addresses consist of 128 bits; represented using hexadecimal digits (each 4 bits), hence we need 32 hexadecimal digits to represent an IPv6 address.

Answer:

See explaination

Explanation:

//namespace

using System;

using System.Windows.Forms;

//application namespace

namespace TemperatureConversionApp

{

public partial class Form1 : Form

{

public Form1()

{

InitializeComponent();

}

//calculate button click

private void btnCalculate_Click(object sender, EventArgs e)

{

//taking temperature type

string temperatureType = cmbTemperatureType.SelectedItem.ToString();

//taking temperature entered by user

double temperature = double.Parse(txtTemperature.Text);

//taking conversion temperature type

string conversionType = cmbConversionType.SelectedItem.ToString();

//checking temperature type and conversion type

if(temperatureType == "Farenheit" && conversionType == "Celsius")

{

//if Farenheit to Celsius temperature then

double temp = (temperature - 32) * 5 / 9;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Farenheit is " + temp.ToString("0.00") + " Celsius";

}

else if (temperatureType == "Farenheit" && conversionType == "Kelvin")

{

//if Farenheit to Kelvin temperature then

double temp = (temperature - 32) * 5 / 9+273.15;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Farenheit is " + temp.ToString("0.00") + " Kelvin";

}

else if (temperatureType == "Celsius" && conversionType == "Kelvin")

{

//if Celsius to Kelvin temperature then

double temp = temperature + 273.15;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Celsius is " + temp.ToString("0.00") + " Kelvin";

}

else if (temperatureType == "Celsius" && conversionType == "Farenheit")

{

//if Celsius to Farenheit temperature then

double temp = (temperature*9/5) +32;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Celsius is " + temp.ToString("0.00") + " Farenheit";

}

else if (temperatureType == "Kelvin" && conversionType == "Farenheit")

{

//if Kelvin to Farenheit temperature then

double temp = (temperature-273.15) * 9 / 5 + 32;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Kelvin is " + temp.ToString("0.00") + " Farenheit";

}

else if (temperatureType == "Kelvin" && conversionType == "Celsius")

{

//if Kelvin to Celsius temperature then

double temp = temperature - 273.15;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Kelvin is " + temp.ToString("0.00") + " Celsius";

}

else

{

lblDetails.Text = "Select valid temperature conversion unit";

}

}

//Exit button click

private void btnExit_Click(object sender, EventArgs e)

{

this.Close();//close application

}

}

}

check attachment for the windows application

Answer:

see explaination

Explanation:

# importing "collections" for namedtuple()

from collections import namedtuple

# function creates student records and return the named tuple

def create_student():

Student = namedtuple('Student',['name','exam1','exam2']) # creating the object Student

# taking input the name and scores of the students

name = input()

exam1 = float(input())

exam2 = float(input())

return Student(name, exam1, exam2) # return the named tuple

# function creates list of student records and return it

def create_class(n):

student_list = []

# creating student data for n students

for i in range(n):

student_list.append(create_student()) # storing data in the student_list

return student_list # return the student data i.e. student_list

# function calculates the final score of each student and returns it

def calculate_score(S):

final_score = 0

if S[1] > S[2]: # if exam1 score is greater than exam2

final_score = S[1] * 0.3 + S[2] * 0.7 # final score is sum of 30% of exam1 and 70% exam2

elif S[1] < S[2]: # if exam2 score is greater than exam1

final_score = S[1] * 0.7 + S[2] * 0.3 # final score is sum of 30% of exam2 and 70% exam1

elif S[1] == S[2]: # if both scores are equal

final_score = S[1] # final score is sum if 30% of exam1 and 70% exam2, but here both scores are equal so final score is equal to any one of the score

else: # if scores are invalid

print('Invalid entries')

return final_score # return final score

# driver function

def main():

n = int(input()) # enter the no. of students in class

if n < 1: # if n is less than 1 return nothing and stop execution

return

student_list = create_class(n) # call create_class to create class of n students

for i in student_list:

print(round(calculate_score(i), 2)) # calculate the final score for each student and print it

if __name__ == "__main__": main()

Answer: Jim left the computer unattended while shopping for supplies to be used at the next crime scene.

Explanation: While transporting the evidence to a secure location (lab), he left the computer unattended in his car and goes shopping for supplies that will be used in his next crime scenes. This act will give the criminals or their accomplice the opportunity to break into his car and tamper with what ever evidence he might have left behind in his car.

Answer:

Check the explanation

Explanation:

#Define the class Employee.

class Employee:

   #Declare and initialize the required member variables.

   emp_name = ''

   Id_num = ''

   emp_dept = ''

   emp_job_title = ''

#Create an object of the class Employee.

emp_obj1 = Employee()

#Assign required values to the members of the class for a

#particular object.

emp_obj1.emp_name = 'Susan Meyers'

emp_obj1.Id_num = '47899'

emp_obj1.emp_dept = 'Accounting'

emp_obj1.emp_job_title = 'Vice President'

#Create another object of the class Employee.

emp_obj2 = Employee()

#Assign required values to the members of the class for the

#current object.

emp_obj2.emp_name = 'Marke Jones'

emp_obj2.Id_num = '39119'

emp_obj2.emp_dept = 'IT'

emp_obj2.emp_job_title = 'programming'

#Create another object of the class Employee.

emp_obj3 = Employee()

#Assign required values to the members of the class for the

#current object.

emp_obj3.emp_name = 'Joy Rogers'

emp_obj3.Id_num = '81774'

emp_obj3.emp_dept = 'Manufacturing'

emp_obj3.emp_job_title = 'Engineering'

#Display the details of each employee objects.

print('Employee 1 details:')

print('Employee Name:', emp_obj1.emp_name)

print('Employee ID Number:', emp_obj1.Id_num)

print('Employee Department:', emp_obj1.emp_dept)

print('Employee Job Title:', emp_obj1.emp_job_title)

print()

print('Employee 2 details:')

print('Employee Name:', emp_obj2.emp_name)

print('Employee ID Number:', emp_obj2.Id_num)

print('Employee Department:', emp_obj2.emp_dept)

print('Employee Job Title:', emp_obj2.emp_job_title)

print()

print('Employee 3 details:')

print('Employee Name:', emp_obj3.emp_name)

print('Employee ID Number:', emp_obj3.Id_num)

print('Employee Department:', emp_obj3.emp_dept)

print('Employee Job Title:', emp_obj3.emp_job_title)

Kindly check the attached image below for the code output.

Answer:

The previous andwers needed a few tweaks to be correct.

Explanation:

class Employee:

  #Declare and initialize the required member variables.

  emp_name = ''

  Id_num = ''

  emp_dept = ''

  emp_job_title = ''

#Create an object of the class Employee.

emp_obj1 = Employee()

#Assign required values to the members of the class for a

#particular object.

emp_obj1.emp_name = 'Susan Meyers'

emp_obj1.Id_num = '47899'

emp_obj1.emp_dept = 'Accounting'

emp_obj1.emp_job_title = 'Vice President'

#Create another object of the class Employee.

emp_obj2 = Employee()

#Assign required values to the members of the class for the

#current object.

emp_obj2.emp_name = 'Mark Jones'

emp_obj2.Id_num = '39119'

emp_obj2.emp_dept = 'IT'

emp_obj2.emp_job_title = 'Programmer'

#Create another object of the class Employee.

emp_obj3 = Employee()

#Assign required values to the members of the class for the

#current object.

emp_obj3.emp_name = 'Joy Rogers'

emp_obj3.Id_num = '81774'

emp_obj3.emp_dept = 'Manufacturing'

emp_obj3.emp_job_title = 'Engineer'

#Display the details of each employee objects.

print('Name:', emp_obj1.emp_name)

print('ID Number:', emp_obj1.Id_num)

print('Department:', emp_obj1.emp_dept)

print('Job Title:', emp_obj1.emp_job_title)

print()

print('Name:', emp_obj2.emp_name)

print('ID Number:', emp_obj2.Id_num)

print('Department:', emp_obj2.emp_dept)

print('Job Title:', emp_obj2.emp_job_title)

print()

print('Name:', emp_obj3.emp_name)

print('ID Number:', emp_obj3.Id_num)

print('Department:', emp_obj3.emp_dept)

print('Job Title:', emp_obj3.emp_job_title)

Answer:

See attached image for the source code and output

Answer:

following are the code to this question:

#include <iostream> //defining header file  

using namespace std;  

void me(int n) //defining a method me, that accept an integer value  

{  

int a,b,t1,t2; //defining integer variable  

for(a = 1; a<n; a++) //defining loop to calculates a variable value  

{

for(b=a+1; b<n; b++) //defining loop to calculates a variable value  

{

t1=(a*a)+(b*b)+1; //hold value in t1 value

t2=a*b; // calculates multiplication value and hold in t2 variable          

if(t1%t2==0) //defining condition that check calculated value is equal to 0

{

cout<<"("<<a<<","<<b<<")"; //print a and b value.

}

}

}

}

int main() //defining main method

{

int n; // defining integer variable

cout<< "Enter a number: "; //print message

cin>> n; // input value  

if(n>1) //defining condition that check value is greater then 1

{

me(n); //call method and pass the value

}

else

{

cout<<"Enter a number, which is greater then 1";  //print message  

}

   return 0;

}

Output:

Enter a number: 3

(1,2)

Explanation:

In the given C++ language code, a method "me" is defined, that accepts an integer value "n" as its parameter and this method does not return any value because its return type is void, inside the method two for loop is declared, that calculates a and b value and hold in t1 and t2 variable.

Answer:

See explaination

Explanation:

// File: TelephoneNumber.java

import java.util.Scanner;

public class TelephoneNumber

{

public static void main(String[] args)

{

Scanner input = new Scanner(System.in);

String inputNumber;

String tokens1[];

String tokens2[];

String areaCode;

String firstThree;

String lastFour;

String allSeven;

String fullNumber;

/* input a telephone number as a string in the form (555) 555-5555BsAt4ube4GblQIAAAAASUVORK5CYII= */

System.out.print("Enter a telephone number as '(XXX) XXX-XXXX': ");

inputNumber = input.nextLine();

System.out.println();

/* use String method split */

tokens1 = inputNumber.split(" ");

/* extract the area code as a token */

areaCode = tokens1[0].substring(1, 4);

/* use String method split */

tokens2 = tokens1[1].split("-");

/* extract the first three digits of the phone number as a token */

firstThree = tokens2[0];

/* extract the last four digits of the phone number as a token */

lastFour = tokens2[1];

/* concatenate the seven digits of the phone number into one string */

allSeven = firstThree + lastFour;

/* concatenate both the area code and the seven digits of the phone number into one full string separated by one space */

fullNumber = areaCode + " " + allSeven;

/* print both the area code and the phone number */

System.out.println("Area code: " + areaCode);

System.out.println("Phone number: " + allSeven);

System.out.println("Full Phone number: " + fullNumber);

}

}

Final answer:

System users at URP feeding data into a new information system to test its capability represents beta testing, where real users assess the software in real-world conditions.

Explanation:

The scenario that can be considered beta testing is when system users at URP feed data into a new information system to test its capability. Beta testing involves real users testing the software in a production environment to identify any unresolved bugs or issues before the official release. It is typically the last type of testing done after in-house tests such as unit testing and integration testing have been completed.

In beta testing, the goal is to assess how well the software performs under real-world conditions and to gather feedback from users that can be used to further improve the product's design. This is consistent with the cycle of prototyping, testing, and refinement discussed in the provided references, where testing and evaluation reveal weaknesses or potential improvements, and the design may be adjusted accordingly.

Other scenarios described may represent different levels and types of testing such as integration testing, system testing, or validation testing, which occur before beta testing in the software development lifecycle.