What are the most bags Mrs. Dupree can make? Will choose brainliest and will report absurd answers

Answer:

Part I: C. statistic

Part II: 95% confidence interval = (0.130, 0.270)

Step-by-step explanation:

Part I: The proportion of the 125 people who are living below the poverty line, 25/125, is which of the following: statistic, as it is a measure taken from the sample.

Part II:

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.2.

[tex]p=X/n=25/125=0.2[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{125}}\\\\\\ \sigma_p=\sqrt{0.00128}=0.035777[/tex]

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

[tex]MOE=z\cdot \sigma_p=1.96 \cdot 0.035777=0.070122[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=p-z \cdot \sisgma_p = 0.2-0.070122=0.129878\\\\UL=p+z \cdot \sisgma_p = 0.2+0.070122=0.270122[/tex]

The 95% confidence interval for the population proportion is (0.130, 0.270).

Answer:

[tex]14.2-2.03\frac{6.4}{\sqrt{35}}=12.004[/tex]    

[tex]14.2+2.03\frac{6.4}{\sqrt{35}}=16.396[/tex]    

We are 95% confidence that the true mean for the delay time is between (12.004 and 16.396)

Step-by-step explanation:

Information given

[tex]\bar X=14.2[/tex] represent the sample mean for the delay time

[tex]\mu[/tex] population mean

s=6.4 represent the sample standard deviation

n=35 represent the sample size  

Confidence interval

The confidence interval for the true parameter of interest is given by:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

The degrees of freedom, given by:

[tex]df=n-1=35-1=34[/tex]

The Confidence level is 0.95 or 95%,and the significance is [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value for this case is [tex]t_{\alpha/2}=2.03[/tex]

And replacing we got:

[tex]14.2-2.03\frac{6.4}{\sqrt{35}}=12.004[/tex]    

[tex]14.2+2.03\frac{6.4}{\sqrt{35}}=16.396[/tex]    

We are 95% confidence that the true mean for the delay time is between (12.004 and 16.396)

The traveler is disputing the claim about the variance. The hypothesis test is a right-tailed test. The result of the test does not provide enough evidence to dispute the airline's claim.

109. The traveller is disputing the claim about the variance.

110. A sample standard deviation of 15 minutes is the same as a sample variance of 225 minutes.

112. H-o: The variance is 150 minutes or less.

113. d-f = 24

114. chi-square test statistic = 35.172

115. p-value = 0.082

116. Graph the situation:

117. Let a = 0.05

Decision: Fail to reject the null hypothesis

Conclusion: There is not enough evidence to dispute the airline's claim about the variance being 150 minutes or less.

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Answer:

The area of the car tire = 254.57 in²

el área de la goma en pulgadas cuadradas = 254.57 in²

Step-by-step explanation:

English Translation

A car tire has a diameter of 18 inches which is the area of ​​the tire in square inches?

A car tire is circular in nature, the area of a circle (car tire) is given as

A = πr²

where

π = pi (a constant) = (22/7)

r = radius of the circle = (diameter/2) = (18/2) = 9 inches

Area of the car tire = π×9² = 254.57 in²

Hence, the area of the car tire = 254.57 in²

Hope this Helps!!!

Answer:

Move all the terms to the left and set equal to zero.

Then set each factor equal to zero.

Step-by-step explanation:

I hope this helps

The correct answer is that the expression [tex]\(a^2 + 2ab + b^2\)[/tex]  equals 44.

To solve the given mathematical expression [tex]\(a^2 + 2ab + b^2\),[/tex] we recognize that it is a perfect square trinomial. The perfect square trinomial can be factored into the square of a binomial:

[tex]\[ (a + b)^2 = a^2 + 2ab + b^2 \][/tex]

Given that this expression equals 44, we can set the factored form equal to 44:

[tex]\[ (a + b)^2 = 44 \][/tex]

To find the values of [tex]\(a\)[/tex] and [tex]\(b\)[/tex], we take the square root of both sides of the equation. Remembering that the square root of 44 is not a whole number, we can express it as the product of prime factors:

[tex]\[ \sqrt{44} = \sqrt{4 \cdot 11} = \sqrt{2^2 \cdot 11} = 2\sqrt{11} \][/tex]

 Therefore, we have:

[tex]\[ a + b = \pm 2\sqrt{11} \][/tex]

This equation tells us that the sum of [tex]\(a\)[/tex] and [tex]\(b\)[/tex] is either [tex]\(2\sqrt{11}\) or \(-2\sqrt{11}\).[/tex] Without additional information about [tex]\(a\)[/tex] and [tex]\(b\)[/tex], we cannot determine unique values for [tex]\(a\)[/tex] and [tex]\(b\)[/tex], but we know that their sum must equal one of these two values.

The expression [tex]\(a^2 + 2ab + b^2\)[/tex] is indeed equal to 44, and the relationship between [tex]\(a\)[/tex]  and [tex]\(b\)[/tex] is given by [tex]\(a + b = \pm 2\sqrt{11}\).[/tex]

Answer:

We can deduce that the elasticity of the labor supply is greater than 1 the labor supply is considered elastic

Step-by-step explanation:

The formula to use is the following:

Elasticity = (Change in working hours / Average working hours) / (Change in wage rate / Average wage rate)

we replace the data

Elasticity = [(7 - 3) / (7 + 3) / 2] / [(50 - 30) / (50 + 30) / 2]

Elasticity = [4 / (10/2)] / [20 / (80/2)]

Elasticity = (4/5) / (20/40)

Elasticity = 0.8 / 0.5

OUTCOME

Elasticity = 1.6

We can deduce that the elasticity of the labor supply is greater than 1 the labor supply is considered elastic

The elasticity of Poornima's labor supply between the wages of $30 and $50 per hour is approximately 1.5. This shows that Poornima's supply of labor in this wage range is elastic, indicating responsiveness to wage changes.

The elasticity of labor supply can be calculated using the midpoint method. This method measures elasticity as the percent change in quantity supplied divided by the percent change in wage. The percent change in quantity supplied is calculated as (Q2-Q1)/[(Q1+Q2)/2], where Q1 = 3 and Q2 = 7. That gives us (7-3)/[(3+7)/2] = 1. The percent change in wage is calculated similarly as (P2-P1)/[(P1+P2)/2], where P1 = $30 and P2 = $50, giving us (50-30)/[(30+50)/2] = 0.67. By dividing the percent change in quantity supplied by the percent change in wage, we get the elasticity of labor supply: 1/0.67 = 1.5 (rounded).

Therefore, the elasticity of Poornima's labor supply between wages of $30 and $50 per hour is approximately 1.5. Because the elasticity is greater than 1, Poornima's supply of labor over this wage range is elastic, meaning she is responsive to wage changes.

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Answer:

System utilization = 0.7 or 70%

Step-by-step explanation:

Given arrival rate of customer = 15 customer/Hour

Servie rate = [tex] \dfrac{60}{2.8} customer/Hour [/tex]

Now, use the below formula to find the system utilization.

System utilization = [tex] \dfrac{\text{ Arrival rate of customer }}{\text{ Servie rate}}[/tex]

System utilization = [tex] \dfrac{15}{ \dfrac{60}{2.8}}[/tex]

System utilization = [tex] \dfrac{15}{ \dfrac{60}{2.8}}[/tex]

System utilization = 0.7 or 70%

Answer:

[tex]t=\frac{70.5-68.7}{\sqrt{\frac{5.3^2}{360}+\frac{4.3^2}{329}}}}=4.913[/tex]  

Since we conduct a bilateral test we have the p value given by:

[tex]p_v =2*P(z>4.913)=8.97x10^{-7}[/tex]

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true means for girls and boys are different at 1% of significance

Step-by-step explanation:

Information given

[tex]\bar X_{boys}=70.5[/tex] represent the mean weigth for ten year boys

[tex]\bar X_{girls}=68.7[/tex] represent the mean weigth for ten year girls

[tex]s_{boys}=5.3[/tex] represent the sample deviation for 10 year boys

[tex]s_{girls}=4.3[/tex] represent the sample standard deviation for 10 year girls

[tex]n_{boys}=360[/tex] sample size for boys

[tex]n_{girls}=329[/tex] sample size for girls

t would represent the statistic

[tex]\alpha=0.01[/tex] significance level assumed

System of hypothesis to check

We need to conduct a hypothesis in order to check if the true means are different for boys and girls, the system of hypothesis would be:

Null hypothesis:[tex]\mu_{boys}=\mu_{girls}[/tex]

Alternative hypothesis:[tex]\mu_{boys} \neq \mu_{girls}[/tex]

The statistic for this case would be given by:

[tex]t=\frac{\bar X_{boys}-\bar X_{girls}}{\sqrt{\frac{s^2_{boys}}{n_{boys}}+\frac{s^2_{girls}}{n_{girsl}}}}[/tex] (1)

Replacing we got:

[tex]t=\frac{70.5-68.7}{\sqrt{\frac{5.3^2}{360}+\frac{4.3^2}{329}}}}=4.913[/tex]  

P value

We can assume that the degrees of freedom for this case are large enough to assume that the t distribution is approximately the normal distribution.

Since we conduct a bilateral test we have the p value given by:

[tex]p_v =2*P(z>4.913)=8.97x10^{-7}[/tex]

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true means for girls and boys are different at 1% of significance

Answer:

a) The function, f(x) is increasing at the intervals (x < -1.45) and (x > 3.45)

Written in interval form

(-∞, -1.45) and (3.45, ∞)

- The function, f(x) is decreasing at the interval (-1.45 < x < 3.45)

(-1.45, 3.45)

b) Local minimum value of f(x) = -78.1, occurring at x = 3.45

Local maximum value of f(x) = 10.1, occurring at x = -1.45

c) Inflection point = (x, y) = (1, -16)

Interval where the function is concave up

= (x > 1), written in interval form, (1, ∞)

Interval where the function is concave down

= (x < 1), written in interval form, (-∞, 1)

Step-by-step explanation:

f(x) = x³ - 6x² - 15x + 4

a) Find the interval on which f is increasing.

A function is said to be increasing in any interval where f'(x) > 0

f(x) = x³ - 6x² - 15x + 4

f'(x) = 3x² - 6x - 15

the function is increasing at the points where

f'(x) = 3x² - 6x - 15 > 0

x² - 2x - 5 > 0

(x - 3.45)(x + 1.45) > 0

we then do the inequality check to see which intervals where f'(x) is greater than 0

Function | x < -1.45 | -1.45 < x < 3.45 | x > 3.45

(x - 3.45) | negative | negative | positive

(x + 1.45) | negative | positive | positive

(x - 3.45)(x + 1.45) | +ve | -ve | +ve

So, the function (x - 3.45)(x + 1.45) is positive (+ve) at the intervals (x < -1.45) and (x > 3.45).

Hence, the function, f(x) is increasing at the intervals (x < -1.45) and (x > 3.45)

Find the interval on which f is decreasing.

At the interval where f(x) is decreasing, f'(x) < 0

from above,

f'(x) = 3x² - 6x - 15

the function is decreasing at the points where

f'(x) = 3x² - 6x - 15 < 0

x² - 2x - 5 < 0

(x - 3.45)(x + 1.45) < 0

With the similar inequality check for where f'(x) is less than 0

Function | x < -1.45 | -1.45 < x < 3.45 | x > 3.45

(x - 3.45) | negative | negative | positive

(x + 1.45) | negative | positive | positive

(x - 3.45)(x + 1.45) | +ve | -ve | +ve

Hence, the function, f(x) is decreasing at the intervals (-1.45 < x < 3.45)

b) Find the local minimum and maximum values of f.

For the local maximum and minimum points,

f'(x) = 0

but f"(x) < 0 for a local maximum

And f"(x) > 0 for a local minimum

From (a) above

f'(x) = 3x² - 6x - 15

f'(x) = 3x² - 6x - 15 = 0

(x - 3.45)(x + 1.45) = 0

x = 3.45 or x = -1.45

To now investigate the points that corresponds to a minimum and a maximum point, we need f"(x)

f"(x) = 6x - 6

At x = -1.45,

f"(x) = (6×-1.45) - 6 = -14.7 < 0

Hence, x = -1.45 corresponds to a maximum point

At x = 3.45

f"(x) = (6×3.45) - 6 = 14.7 > 0

Hence, x = 3.45 corresponds to a minimum point.

So, at minimum point, x = 3.45

f(x) = x³ - 6x² - 15x + 4

f(3.45) = 3.45³ - 6(3.45²) - 15(3.45) + 4

= -78.101375 = -78.1

At maximum point, x = -1.45

f(x) = x³ - 6x² - 15x + 4

f(-1.45) = (-1.45)³ - 6(-1.45)² - 15(-1.45) + 4

= 10.086375 = 10.1

c) Find the inflection point.

The inflection point is the point where the curve changes from concave up to concave down and vice versa.

This occurs at the point f"(x) = 0

f(x) = x³ - 6x² - 15x + 4

f'(x) = 3x² - 6x - 15

f"(x) = 6x - 6

At inflection point, f"(x) = 0

f"(x) = 6x - 6 = 0

6x = 6

x = 1

At this point where x = 1, f(x) will be

f(x) = x³ - 6x² - 15x + 4

f(1) = 1³ - 6(1²) - 15(1) + 4 = -16

Hence, the inflection point is at (x, y) = (1, -16)

- Find the interval on which f is concave up.

The curve is said to be concave up when on a given interval, the graph of the function always lies above its tangent lines on that interval. In other words, if you draw a tangent line at any given point, then the graph seems to curve upwards, away from the line.

At the interval where the curve is concave up, f"(x) > 0

f"(x) = 6x - 6 > 0

6x > 6

x > 1

- Find the interval on which f is concave down.

A curve/function is said to be concave down on an interval if, on that interval, the graph of the function always lies below its tangent lines on that interval. That is the graph seems to curve downwards, away from its tangent line at any given point.

At the interval where the curve is concave down, f"(x) < 0

f"(x) = 6x - 6 < 0

6x < 6

x < 1

Hope this Helps!!!

This question involves finding the increasing and decreasing intervals, local maximum and minimum values, and concavity of a cubic function f(x) = x3 – 6x2 – 15x + 4. These are found by taking the first and second derivative and applying various tests.

The subject of this question is Calculus, more specifically, regarding the properties of the function f(x) = x3 – 6x2 – 15x + 4. To find the intervals where the function is increasing or decreasing, we need to find the derivative of f(x), set it to zero and solve for x to find critical points. Then we set up a number line with these critical numbers and analyze the sign of f'(x) in each interval.

The local maximum and minimum values can also be found from the critical numbers. To find where the function is concave up or down, we find the second derivative (f''(x)) and perform a similar process we did with the first derivative.

The inflection points, where the function changes its concavity, can also be found from evaluating the second derivative.

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Answer:

99% confidence interval for [tex]\mu = 73220 \pm 565.4[/tex]

Step-by-step explanation:

Sample mean = [tex]\bar{x} =73220[/tex]

Standard deviation = s = 4400

Z at 99%  confidence level = 2.57

Sample = n = 400

Formula of confidence interval :[tex]\bar{x} \pm Z \times \frac{s}{\sqrt{n}}[/tex]

Substitute the values in the formula :

So,99% confidence interval for [tex]\mu = 73220 \pm 2.57 (\frac{4400}{\sqrt{400}})[/tex]

99% confidence interval for [tex]\mu = 73220 \pm 565.4[/tex]

Answer:

can you please post the pyramid

Step-by-step explanation:

The statements that are true concerning the rectangular pyramids include the following:

What are the properties of a rectangular pyramid?

The properties of a rectangular pyramid include the following:

From the given rectangular pyramid, The area of the base is 24 cm² because, 6*4= 24cm²

There are four lateral faces which are triangular in shape.

Answer:

Explanation:

Answer:

Explanation:

Answer: Std = 6.0

Step-by-step explanation:

Let us take a step by step process to solve this problem.

We have from the question that;

Population 1:   76   77   66  71    55   63  83   58

Population 2:   78  71   71   65   61    71   77    62

where n is no of occurrence = 8

taking the difference of P1 - P2 we have;

Difference (d) :    -2    6    -5    6    -6   -8    6    -4

Total value of difference = -7

Difference squared (d₁ -d)² =  4    36  25   36   36   64    36   16  

Total value of difference squared (d₁ -d)² = 253

The mean Σ  = sum of values (d)/total value = -7/8 = -0.875

⇒ We are asked to find the value of the standard deviation of the paired difference.

Standard deviation is given as;

Std = √(Σ (Δd)² / n-1

Std = √[(253) / 8-1]

Std = √(253/7) = 6.0

Std = 6.0

cheers i hope this helped!!!!!!

The husband is correct; the probability of the first child being a girl is higher than the probability of the first two being girls.

Let's list the sample space of possible outcomes for the genders of three children:

1. BBB (all boys)

2. BBG (two boys, one girl)

3. BGB (one boy, one girl, one boy)

4. BGG (one boy, two girls)

5. GBB (one girl, two boys)

6. GBG (two girls, one boy)

7. GGB (two girls, one boy)

8. GGG (all girls)

Now, let's examine the probabilities the husband and wife are discussing:

1. Husband's claim: Probability of the first child being a girl is greater than the probability of the first two children being girls.

  Probability of the first child being a girl: [tex]\( \frac{4}{8} = \frac{1}{2} \)[/tex]

  Probability of the first two children being girls: [tex]\( \frac{2}{8} = \frac{1}{4} \)[/tex]

  The husband is correct.

2. Wife's claim: Probability of the first child being a girl is equal to the probability of the first two children being girls.

  Both probabilities are [tex]\( \frac{1}{2} \)[/tex].

  The wife is incorrect.

Therefore, the husband is correct in this scenario.

Final answer:

The circumference of the outer circle is approximately 18.86 feet greater than the circumference of the inner circle, which has a circumference of 88 feet.

Explanation:

The circumference (C) of a circle is calculated using the formula C = 2πr, where π is Pi and r is the radius of the circle. Given that the circumference of the inner circle is 88 ft and the distance between the inner and outer circle is 3 ft, we deduce that the radius of the outer circle is 3 ft greater than the radius of the inner circle. Using the given approximation of π as 22/7, we can find the new circumference.

First, let's find the radius of the inner circle. Rearrange the formula to r = C / (2π) and substitute π with 22/7:

r = 88 / ((2 × 22)/7) = 88 / (44/7) = 88 / (6.2857) ≈ 14 ft

Now, the radius of the outer circle is r + 3 ft, which equals 17 ft. The circumference of the outer circle is then:

C = 2πr = 2 × 22/7 × 17 = 2 × 22 × 17 / 7 = 34 × 22 / 7 = 748 / 7 ≈ 106.86 ft

To find by how many feet the circumference of the outer circle is greater than the inner circle, subtract the circumference of the inner circle from that of the outer circle:

106.86 ft - 88 ft = 18.86 ft

Therefore, the circumference of the outer circle is approximately 18.86 ft greater than the circumference of the inner circle.

Answer:

1. less likely

2. more likely

Step-by-step explanation:

test took

Answer:

1. less likely

2. more likely

Step-by-step explanation:

Answer:

the box can hold a volume of 1024 inches ^3

Step-by-step explanation:

The volume of the given box is 1024 in.3.

Suppose the base of the pyramid has length = l units, and width = w units.

Suppose that the height of the pyramid is of h units, then:

[tex]v = \dfrac{l \times w \times h}{3} \: \rm unit^3[/tex]

is the volume of that pyramid.

The base is a rectangle with length = L units, and width = W units, so its area is:

[tex]b = l \times w\: \rm unit^2[/tex]

We are given that;

Dimension= 16*8*8 inches

Now,

To find the area of the base, we need to use the formula:

B=lw

where l is the length and w is the width. Substituting the given values, we get:

B=16×8

B=128

So, the area of the base of the box is 128 in.2.

To find the volume of the box, we substitute the values of B and h into the formula:

V=Bh

V=128×8

V=1024

Therefore, by the given prism the answer will be 1024 in.3.

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Answer:

356

Step-by-step explanation:

3 hundreds = 3 * 100 = 300

4 tens = 4 * 10 = 40

16 ones = 16 * 1 = 16

Combine the terms: 300 + 40 + 16 = 356

356 is your answer.

~

Answer:

12+ 8.2n

Step-by-step explanation:

12 more than 8.2 times a number n is:

First, 12 more indicates that whatever we get has to add 12 on since it is 12 more.

Second, 8.2 times a number is multiplication and that number is filled in by a variable (n).

Therefore, the equation is 8.2n + 12

Answer:

Step-by-step explanation:

The null hypothesis is the statement or claim that is believed or assumed to be true. In this case, the null hypothesis is "They believe that 40% of first-time borrowers take out smaller loans than other borrowers". Since we are dealing with proportion, we will denote it with p. The null hypothesis would be

p = 0.4

The alternative hypothesis is what the researcher expects or predicts. It is the statement that is believed to be true if the null hypothesis is rejected. The alternative hypothesis is "They perform a hypothesis test to determine if the percentage is the same or different from 40%". It would be written as

p ≠ 0.4

Answer:

a

Step-by-step explanation:

good luck :)

Answer:

Step-by-step explanation:

Socratic had the answer on there I think

Answer: D-On a coordinate plane, a line with positive slope goes through points (0, negative 1) and (2, 0). plz mark me brainliest.

Step-by-step explanation:

Option D. is correct. On a coordinate plane, a line with positive slope goes through points (0, negative 1) and (2, 0).

Which graph represents a function with a rate of change of 0.5?

Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.

since
given rate of change = 0.5
slope of curve = rate of change
slope = [tex]\frac{Y_2-Y_1}{X_2-X_1}[/tex]
we have (0,-1) and (2, 0)
slope = 0+1/2-0
= 1/5
=0.5
=rate of change

Thus, On a coordinate plane, a line with positive slope goes through points (0, negative 1) and (2, 0).

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Answer:

Step-by-step explanation:

When m=6

(1) The difference of the product of 3 and m minus the quotient of m divided by 2

[tex]3m-\dfrac{m}{2}\\=3(6)- \dfrac{6}{2}\\=18-3\\=15[/tex]

(2)The sum of 3 times m and 4 times m

3m+4m

=3(6)+4(6)

=18+24

=42

(3)The quotient of 6 divided by the difference of m minus 3

[tex]\dfrac{6}{m-3} =\dfrac{6}{6-3} =\dfrac{6}{3} =2[/tex]

(4)The sum of m and 3 divided by the difference of m minus 3

[tex]\dfrac{m+3}{m-3}= \dfrac{6+3}{6-3}=\dfrac{9}{3}=3[/tex]

Answer:

It would take 15.3846 minutes to stock the shelf if the two clerks worked together

Step-by-step explanation:

The first grocery clerk can stock a shelf in 40 minutes, it means that he can do  1/40 shelf per minute. At the same way, the second clerk requires 25 minutes, it means that he can do 1/25 shelf per minute

Then, if they worked together, they can stock 13 shelfs in 200 minutes, and it is calculated as:

[tex]\frac{1}{40}+\frac{1}{25} = \frac{13}{200}[/tex]

Now, using the rule of three, we need to find the minutes required to stock 1 shelf if they work at a rate of 13 shelf in 200 minutes as:

13 shelfs --------------   200 minutes

1 shelf    ---------------    X minutes

Where X are the minutes required to stock 1 shelf.

So, solving for X, we have:

[tex]X=\frac{1*200}{13}=15.3846[/tex]

Finally, it would take 15.3846 minutes to stock the shelf if the two clerks worked together

Answer:

The larger the p value, the less evidence the data provide against the null hypothesis and in favour of the alternative hypothesis

Step-by-step explanation:

P Value is the probability of obtaining extreme observed results in a statistical hypothesis test, assuming that null hypothesis is correct.

High p value implies evidence in favour of null hypothesis, against alternate hypothesis.

Low p value implies evidence against null hypothesis, in favour of alternate hypothesis

The incorrect statement about hypothesis testing is that a smaller p-value indicates less evidence against the null hypothesis.

A small p-value actually provides strong evidence against the null hypothesis, prompting its rejection.

The p-value measures how unlikely the observed data is under the null hypothesis, but does not indicate the truth of the null hypothesis itself.

The statement in hypothesis testing that is not true is The smaller the p-value, the less evidence the data provides against the null hypothesis and in favor of the alternative hypothesis.

A small p-value indicates that the observed test statistic is very unlikely if the null hypothesis is true, which provides stronger evidence against the null hypothesis and in favor of the alternative hypothesis.

In fact, we generally use a significance level (commonly < 0.05) to determine if we should reject the null hypothesis. On the contrary, a larger p-value suggests less evidence against the null hypothesis, implying that we are less likely to reject it.

It's important to remember that the p-value is the probability of obtaining the observed data, or more extreme, given that the null hypothesis is true.

It does not, however, describe the probability that the null hypothesis itself is true, thus a small p-value means that the data is unlikely under the null hypothesis, leading to its potential rejection.

Answer:

Radius, r = 6 inches

Step-by-step explanation:

We have,

Volume of a cone is 565.2 cubic inches

Height of the cone is 15 inches

It is required to find the radius of the cone. Volume of a cone is given by :

[tex]V=\dfrac{1}{3}\pi r^2 h[/tex]

r is radius of cone

[tex]r=\sqrt{\dfrac{3V}{\pi h}} \\\\r=\sqrt{\dfrac{3\times 565.2}{3.14\times 15}} \\\\r=6\ \text{inch}[/tex]

So, the radius of the cone is 6 inches. The correct option is (b).

Answer:

[tex]\mu_{\hat p} = 0.25[/tex]

[tex]\sigma_{\hat p}= \sqrt{\frac{0.25*(1-0.25)}{40}}= 0.0685[/tex]

[tex] z = \frac{0.2-0.25}{0.0685}= -0.730[/tex]

And we can use the normal standard distribution or excel to find this probability and we got:

[tex] P(\hat p <0.2) = P(z<-0.730)= 0.233[/tex]

Step-by-step explanation:

We define the parameter as the proportion of students at a college who study abroad and this value is known [tex]p =0.25[/tex], we select a sample size of n =40 and we are interested in the probability associated to the sample proportion, but we know that the distirbution for the sample proportion is given by:

[tex]\hat p \sim N(p , \sqrt{\frac{p(1-p)}{n}}[/tex]

And the paramters for this case are:

[tex]\mu_{\hat p} = 0.25[/tex]

[tex]\sigma_{\hat p}= \sqrt{\frac{0.25*(1-0.25)}{40}}= 0.0685[/tex]

We want to find the following probability:

[tex]P(\hat p< 0.2)[/tex]

For this case since we know the distribution for the sample proportion we can use the z score formula given by:

[tex] z = \frac{\hat p -\mu_{\hat p}}{\sigma_{\hat p}}[/tex]

Replacing the info given we got:

[tex] z = \frac{0.2-0.25}{0.0685}= -0.730[/tex]

And we can use the normal standard distribution or excel to find this probability and we got:

[tex] P(\hat p <0.2) = P(z<-0.730)= 0.233[/tex]

To find the probability that the proportion of students in your sample who have studied abroad is less than 0.2, you can use the normal distribution approximation for sampling proportions.

To find the probability that the proportion of students in your sample who have studied abroad is less than 0.2, you can use the normal distribution approximation for sampling proportions. First, find the mean of the sampling distribution, which is equal to the true proportion (0.25) multiplied by the sample size (40), giving a mean of 10.

Next, find the standard deviation of the sampling distribution, which is calculated as the square root of (p(1-p)/n), where p is the true proportion (0.25) and n is the sample size (40). The standard deviation is approximately 0.071.

Finally, use the normal distribution to find the probability that the proportion is less than 0.2. Using the z-score formula, calculate the z-score as (sample proportion - mean)/(standard deviation). In this case, the z-score is approximately -1.41. Use a standard normal distribution table or calculator to find the corresponding probability, which is approximately 0.079.

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Answer:

  salary

Step-by-step explanation:

Salary is the term generally used to refer to the annual amount of wages.

_____

tuition is the amount paid to an educational institution for the classes they offer.

hourly wage refers to the amount earned in an hour, not a year.

expense is the name given to any expenditure, not an amount earned.

Answer:

C. Salary

Step-by-step explanation:

EDg

To ensure Anna has two matching pairs of socks, she will need to draw out five socks. This illustrates a principle in probability known as the Pigeonhole Principle.

In this mathematics question, we are dealing with an example of the Pigeonhole Principle. Anna has 3 different types of socks: yellow, red, and blue. In the worst-case scenario, she picks one of each color for the first three socks- this doesn't give her a pair. To ensure she gets a pair, she would need to take out a fourth sock. Since we only have three different types, this fourth sock will have to be either a yellow, red or blue one, thus ensuring at least one pair. However, the question asks for two pairs. This would involve picking out a fifth sock, in the worst-case scenario this fifth sock could match with the second pair. Hence, to guarantee that there are two matching pairs, she would need to draw out a total of five socks.

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Answer:

Yogurt: $0.50 Sandwich: $6

Step-by-step explanation:

Because if you make the combos equations it would be Y+Y+X=7 and X+X+Y=12.5 so you would solve with those and for it to work with both, 0.50 for yogurt, and 6 for sand which would work.