An obtuse triangle will have one and only one obtuse angle.
The other two angles are acute angles.
The sum of the two angles other than the obtuse angle is less than 90º.
The side opposite to the obtuse angle is the longest side of the triangle.
The points of concurrency, the Circumcenter and the Orthocenter lie outside of an obtuse triangle, while Centroid and Incenter lie inside the triangle.
Which amount is the best estimate for the cost of the vehicle to drive through the safari in 2009?
A rectangular prism has a length of 3/4 cubic inch and a width of 1/2 inch. The volume is 21/32 cubic inch. Find the height of the prism. Write your answer as a mixed number in simplest form.
Answer:
[tex]\texttt{Height of the prism}=1\frac{3}{4}[/tex]
Step-by-step explanation:
Volume of rectangular prism = Length x Width x Height
[tex]\texttt{Volume of rectangular prism =}\frac{21}{32}\\\\\texttt{Length =}\frac{3}{4}\\\\\texttt{Breadth =}\frac{1}{2}[/tex]
Substituting
[tex]\frac{21}{32}=\frac{3}{4}\times \frac{1}{2}\times h\\\\h=\frac{7}{4}=\frac{4+3}{4}=1\frac{3}{4}[/tex]
[tex]\texttt{Height of the prism}=1\frac{3}{4}[/tex]
Please help, this is due in 5 minutes
The greatest common factor of 4a(2) b and 6ab(3)
The greatest common factor of the expressions 4a^2b and 6ab^3 is 2ab.
The question seeks to determine the greatest common factor of the expressions 4a2b and 6ab3. To find this, one must look at the common factors of the numerical coefficients (4 and 6) and the variables raised to their respective powers (a2 and a, b and b3). The numerical common factor of 4 and 6 is 2. The lowest power of 'a' common to both terms is a1 and for 'b' is b1. On doing this we get 2ab.
The question that says " a school has 1200 pupils "
Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces. suppose carl bags his potatoes in randomly selected groups of 6. what percentage of these bags should have a mean potato weight between 7.5 and 8.5 ounces?
3m + 7/2 = −2m + 5/2 the / means there fractions
3m +7/2 = -2m +5/2
subtract 5/2 from each side
3m +2/2 = -2m
2/2 = 1
3m+1 =-2m
subtract 3m from each side
1=-5m
divide both sides by -5
m = 1/-5 = -1/5
m = -1/5
If 3^2x+1=81, what is the value of x?
x=1/4
x=1/2
x=3/2
x=2/3
Compute the mean, variance, and standard deviation for the following data set. Round all answers to the nearest tenth. {85,95,90,70,75,95,85,85,95,90,70,75}
Find the value of y for a given value of x, if y varies directly with x. If y = –96 when x = 32, what is y when x = 58?
Simplify 4x2(2x2− 8x + 6). 8x2− 32x + 24 6x2− 32x + 24 6 − 32x + 24x2 8x4− 32x3+ 24x2
If a parent function is y=2x which is the function of the graph
if the line is on the positive side then your answer is "y=2^x+1 +2"
if the line is on the negative side your answer is "y=2^x-1 +2"
Positive always goes with positive
How to write three times the difference of two times m and five is equal to eight times m to the second power increased by four in a problem?
A Chef buys 9 cucumbers, 18 peppers and 21 tomatos at the farmers market. Cucumbers ae 6 for $2, pEPPERS ARE 12 for $9 and tomatoes are 6 for $4
Can someone help me with this please? And can you explain why that answer is right
Two parallel lines are crossed by a transversal. What is the value of g? g = 75 g = 80 g = 100 g = 105
The angle measure of g is ∠g = 105°.
The correct option is D.
What is an angle measure?When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.
As per the information provided, it is given that the two parallel lines u and v are traversed by line g.
To find the angle measure of ∠g:
The angle measure of ∠g is equal to 105° by the alternate exterior angle theorem.
Therefore, ∠g = 105°.
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The complete question:
Two parallel lines are crossed by a transversal. What is the value of g? g = 75 g = 80 g = 100 g = 105
Write an equation of the line that passes through the points (−3,12) and (0,6)
An equation of the line is y=
True or False: Is the number 2 a solution to 7≥−3k
I'm not sure about this. Please explain
Anyone wanna help me please?!
Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of one-half ?
3 in by 4 in
6 in by 8 in
12 in by 16 in
1.5 in by 2 in
Solve for x. 5x−2(x+1)=1/4
Graph f(x)=−0.25x+4.
Answer:
Point, (0,4) and (-4,5), just took the test
PLEASE HELP QUICK!!!!!
WILL GIVE BRAINIEST TO FIRST ANSWER
Solve the inequality below for t.
9 - 7t > -9 - 4t
A. t is greater than or equal to 0
B. t is less than or equal to 0
C. t is grater than or equal to 6
D. t is less than or equal to 6
By graphing the system of constraints find the values of x and y that maximize the objective function, find the maximum value.
3x+y<=7
x+2y<=9
x>=0
y>=0
Maximum for P=2x+y
A. P=3
B. P=4
C. P=6
D. P=10
Answer:
x=1, y=4
P=6
Step-by-step explanation:
We are given that
[tex]3x+y\leq 7[/tex]
[tex]x+2y\leq 9[/tex]
[tex]x\geq 0[/tex]
[tex]y\geq 0[/tex]
Objective function
[tex]P=2x+y[/tex]
We have to values of x and y that maximize the P and maximum value of P .
First we change inequality equation into equality equation
[tex]3x+y=7[/tex] (I equation )
[tex]x+2y=9[/tex] (II equation)
Equation I multiply by 2 and then subtract from II equation
[tex]-5x=-5[/tex]
[tex]x=1[/tex]
Substitute x=1 in equation I
Then, we get
[tex]3(1)+y=7[/tex]
[tex]3+y=7[/tex]
[tex]y=7-3=4[/tex]
The two equation intersect at point (1,4).
Substitute x=0 in equation I
Then , we get y=7
Substitute y=0 then
[tex]3x=7[/tex]
[tex]x=\frac{7}{3}=2.3[/tex]
The equation I cut the x- axis at point (2.3,0)and y-axis at (0,7).
Substitute x=0 in equtaion II
[tex]2y=9[/tex]
[tex]y=\frac{9}{2}=4.5[/tex]
Substitute y=0
Then, we get
[tex]x=9[/tex]
Therefore, the equation II cut the x- axis at point (9,0) and y axis at point (0,4.5).
Substitute x=0 and y=0 in inequality Equation I
[tex]3(0)+0=0< 7[/tex]
It is true . Therefore, shaded region below the line.
Substitute x=0 and y=0 in inequality equation II
Then, [tex]0+2(0)=0 < 9[/tex]
It is true. Therefore, the shaded region below the line.
The feasible region is bounded.The feasible region bounded by (0,0),(0,4.5),(2.3,0) and (1,4).
At (0,4.5)
[tex]P=2(0)+4.5=4.5[/tex]
At (2.3,0)
[tex]P=2(2.3)+0=4.6[/tex]
At (1,4)
[tex]P=2(1)+4=6[/tex]
At (0,0)
[tex]P=2(0)+0=0[/tex]
Hence, maximum value of P is 6 at (1,4).
x=1 and y=4
Without graphing, find the slope of each line described below.
A) A line that goes through the points (4,1) and (2,5)
B) A line that goes through the origin and the point (10,5)
C) A vertical line that goes through the point (6,-5)
D) A line that goes through the points (1,6) and (10,6)
A) The slope of line that goes through the points (4, 1) and (2, 5) is -2.
B) The slope of line that goes through the origin and the point (10, 5) is
1 / 2.
C) Vertical lines has undefined slope.
D) The slope of line that goes through the points (1, 6) and (10, 6) is 0.
What is Slope?
Slope is defined as the steepness of the line.
Since, Slope of line passes through points (x₁ , x₂) and (y₁ , y₂) is;
m = (y₂ - y₁) / (x₂ - x₁)
Now,
A) The slope of line that goes through the points (4, 1) and (2, 5) is;
m = 5 - 1 / 2 - 4
m = 4 / -2
m = - 2
B) The slope of line that goes through the (0, 0) and the point (10, 5) is;
m = 5 - 0 / 10 - 0
m = 5 / 10
m = 1 / 2
C) A vertical line that goes through the point (6,-5) has undefined slope.
Because the horizontal change is 0 and we cannot divide a number by 0.
D) The slope of line that goes through the points (1, 6) and (10, 6) is;
m = 6 - 6 / 10 - 1
m = 0 / 9
m = 0
Thus,
A) The slope of line that goes through the points (4, 1) and (2, 5) is -2.
B) The slope of line that goes through the origin and the point (10, 5) is
1 / 2.
C) Vertical lines has undefined slope.
D) The slope of line that goes through the points (1, 6) and (10, 6) is 0.
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The slope of the line below is –. Write a point-slope equation of the line using the coordinates of the labeled point.
A. y + 4 = 8/7 –(x + 4)
B. y – 4 = 8/7–(x – 4)
C. y – 4 = 8/7(x – 4)
D. y + 4 = 8/7(x + 4)
How many 1/3 pound paperback books together weigh 25 pounds?
We can find the quantity of 1/3 pound paperback books that weigh a total of 25 pounds by performing the calculation, 25 ÷ 1/3 or equivalently, 25 x 3, which equals 75. Therefore, we would need 75 of these books to total 25 pounds.
Explanation:To find out how many 1/3
pound
paperback
books weigh a total of 25 pounds, we use division. Since each book weighs 1/3 of a pound, we divide the total weight we want (25 pounds) by the weight of each individual book (1/3 pound). So, our calculation would look like this:
25 ÷ 1/3
. In mathematics, dividing by a fraction is equivalent to multiplying by its reciprocal. The reciprocal of 1/3 is 3/1, or just 3. So, our calculation is now:
25 x 3
. Multiplying 25 by 3 gives us 75. So, we would need
75
of these paperback books to
weigh
a total of 25 pounds.
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At a point on the ground 24ft from the base of a tree, the distance to the top of the tree is 4ft more than 3times the height of the tree. find the height of the tree.
Leena knits 10 rows in 12 min. At this pace, how long will it take her to knit the next 25 rows? Enter your answer in the box. min
HELP PLZ!!
Solve for x: −3(x + 3) = −3(x + 1) − 5. (1 point)
6
−6
All real numbers
No solution
Arthur is treating his friends to a meal at Chez Rich. The meals added up to $152.30. If he tips the waiter 15%, what is the amount of the tip.
a. $20.80
b. $15.24
c. $22.85
d. $13.37
Answer:
Option C. $22.85
Step-by-step explanation:
Arthur is treating his friends to a meal at Chez Rich.
The meals added up to = $152.30
He tips the waiter = 15% of the bill
The amount of the tip = 15% × 152.30
= 0.15 × 152.30
= 22.845 ≈ $22.85
The amount of the tip would be $22.85.
Option C. $22.85