All atoms are _____.positively charged, with the number of protons exceeding the number of electrons negatively charged, with the number of electrons exceeding the number of protons neutral, with the number of protons equaling the number of electrons neutral, with the number of protons equaling the number of electrons, which is equal to the number of neutrons description
Answer: I think it’s: Neutral, with The number of protons equaling to the number of electrons
Explanation:
Draw two lewis structures for a compound with the formula c4h10. no atom bears a charge, and all carbon atoms have complete octets.
The two Lewis structure for a compound with the formula [tex]\rm C_4H_{10}[/tex] are shown below in the attached image.
In a Lewis structure, an element's chemical symbol shows its nucleus and inner electrons, while dots or lines represent valence electrons. Valence electrons are the atom's outermost electrons and are important in chemical bonding.
Shown below are the two Lewis structures of the compound with molecular formula [tex]\rm C_4H_{10}[/tex]. The two structures are the isomers of each other.The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound.Therefore, the two structure of [tex]\rm C_4H_{10}[/tex] are isomers of each other (refer to the attached image).
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Draw the structure of the 1 isomer of c7h16 that contains 3 methyl branches on the parent chain
Answer:
2,2,3-trimethyl-butane
Explanation:
Hello,
On the attached picture, you will find one isomer with chemical formula C₇H₁₆ which is 2,2,3-trimethyl-butane as it has the required three methyl brances on the parent chain, therefore, they must be arranged in the inner carbons otherwise, they will be considered as part of the parent chain.
Best regards.
Final answer:
The structure of the 1 isomer of C7H16 with three methyl branches on the parent chain can be represented as 2,2,3-trimethylbutane, which has a butane backbone with two methyl groups on the second carbon and one on the third.
Explanation:
The student asked to draw the structure of the 1 isomer of C7H16 that contains 3 methyl branches on the parent chain. For heptane (C7H16), one possible isomer with three methyl branches on the parent chain could be 2,2,3-trimethylbutane. In this structure, we have a four-carbon (butane) chain as the parent, with methyl groups attached to the second and third carbons (two on the second and one on the third).
Here's how you could write it out in steps:
Start with a straight chain of four carbons, which is your butane base.Attach two methyl groups to the second carbon on the chain.Attach one methyl group to the third carbon on the chain.Name the compound P4O10
You have a racemic mixture of (+)-2-butanol and (-)-2-butanol. the (+) isomer rotates polarized light by +13.5∘. what is the observed rotation of your mixture?
Answer:
The degree of rotation of racemic mixture will equal 0°
Explanation:
Hello,
(-) isomer is in other words the Enantiomer of (+) isomer and as long as the statement indicates that (+)-isomer optical rotation is + 13.5°, the optical rotation of (-)-isomer will be the same value and degree but with the inverse sign which is -13.5°.
In such a way, the degree of rotation of the taken into account racemic mixture will equal 0°
This is in this way due to the fact that the racemic mixture has equal amount of both enantiomers.
Best regards.
The number of molecules in 1.0 mole of H2O is _____ as in one mole of O2.
How many picograms are in 1 Megagram?
what is the density of an unknown if 7.82g of it occupies a volume of 3.63ml
Sodium hydroxide, NaOH; sodium phosphate, Na3PO4; and sodium nitrate, NaNO3, are all common chemicals used in cleanser formulation. Rank the compounds in order from largest mass percent of sodium to smallest mass percent of sodium.
A transmission electron microscope was used to examine a microscopic organism. No nucleus was foumnd. Which of the following correctly describes the organism
A dilute solution is prepared by transferring 40.00 ml of a 0.3433 m stock solution to a 750.0 ml volumetric flask and diluting to mark. what is the molarity of this dilute solution?
An atom has three full orbitals in its second energy level. How many electrons are present in the second energy level of the atom
Answer:
6 electrons are in the third level if the atom.
Without doing any calculations, determine which mass is closest to the atomic mass of carbon. without doing any calculations, determine which mass is closest to the atomic mass of carbon. 12.00 amu 12.50 amu 13.00 amu
Final answer:
The atomic mass closest to carbon without calculations is 12.00 amu since carbon's average atomic mass is listed as 12.011 amu on the periodic table, and it mostly consists of carbon-12.
Explanation:
The atomic mass of an element like carbon is the weighted average of the masses of its naturally occurring isotopes. Carbon is predominantly composed of carbon-12, which has an atomic mass of exactly 12 amu (atomic mass units), as this isotope makes up about 98.90% of naturally occurring carbon. Because of this, the average atomic mass of carbon is close to 12 amu, but slightly higher due to the presence of the carbon-13 isotope. The periodic table lists carbon's atomic mass as 12.011 amu, making 12.00 amu the mass closest to carbon's atomic mass without doing any calculations.
In a combustion experiment, it was found that 12.096 g of hydrogen molecules combined with 96.000 g of oxygen molecules to form water and released 1.715 × 103 kJ of heat. Calculate the corresponding mass change in this process. (1 J = 1 kg · m2/s2)
Given 8.50 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?
Answer:
Amount of ethyl butyrate formed = 11.3 g
Explanation:
The reaction between butanoic acid (C3H7COOH) and excess ethanol (C2H5OH) is:
[tex]C3H7COOH + C2H5OH \rightarrow C3H7COOC2H5 + H2O[/tex]
Since ethanol is the excess reagent, the formation of the product i.e. ethyl butyrate is influenced by the amount of butanoic acid present
Based on the reaction stoichiometry:
1 mole of butanoic acid produces 1 mole of ethyl butyrate
Mass of butanoic acid = 8.50 g
Molar mass of butanoic acid = 88 g/mol
[tex]Moles\ of \ butanoic\ acid = \frac{Mass}{Molar\ mass} =\frac{8.50g}{88g/mol}=0.097 moles[/tex]
Moles of ethyl butyrate = 0.097
Molar mass of ethyl butyrate= 116 g/mol
[tex]Mass\ of\ ethyl\ butyrate= 0.097*116 = 11.3 g[/tex]
Table salt contains 39.33 g of sodium per 100 g of salt. The U.S. Food and Drug Administration (FDA) recommends that adults consume less than 2.40 g of sodium per day. A particular snack mix contains 1.24 g of salt per 100 g of the mix.What mass of the snack mix can you consume and still be within the FDA limit?
The answer is: mass of the snack mix can you consume and still be within the FDA limit is 491 grams.
ω(Na) = m(Na) ÷ m(salt).
ω(Na) = 39.33 g ÷ 100 g.
ω(Na) = 0.3933; mass percentage of sodium in salt.
m(salt) = 2.4 g ÷ 0.3933.
m(salt) = 6.10 g; mass of salt recommended for consumation.
Make proportion: 1.24 g : 100 g = 6.10 g ÷ m(mix).
m(mix) = 491.93 g; mass of the snack mix.
Based upon the absorbance spectrum of red dye #40, what would be the ideal wavelength to carry out a spectrophotometric experiment on the dye?
When aqueous solutions of lead(ii) nitrate (pb(no3)2) and potassium phosphate (k3po4) are mixed, the products are solid lead(ii) phosphate and aqueous potassium nitrate. write the balanced chemical equation for this reaction. (include states-of-matter under the given conditions in your answer. use the lowest possible whole number coefficients.)?
Answer: The balanced chemical equation is written below.
Explanation:
Balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side will be equal to the total number of individual atoms on the product side. These equations follow law of conservation of mass.
The chemical equation for the reaction of lead (II) nitrate and potassium phosphate follows:
[tex]3Pb(NO_3)_2(aq.)+2K_3PO_4(aq.)\rightarrow Pb_3(PO_4)_2(s)+6KNO_3(aq.)[/tex]
By Stoichiometry of the reaction:
3 moles of aqueous lead (II) nitrate reacts with 2 moles of aqueous solution of potassium phosphate to produce 1 mole of solid lead (II) phosphate and 6 moles of aqueous solution of potassium nitrate.
Hence, the balanced chemical equation is written above.
Fission occurs when the nucleus of an atom captures a subatomic particle
You are on an alien planet where the names for substances and the units of measures are very unfamiliar.
Nonetheless, you obtain 29 quibs of a substance called skvarnick.
You can trade this skvarnick for gold coins, but the vendors all measure skvarnick in units of sleps; not quibs.
10 quibs is equal to 4 sleps.
If you have 29 quibs of skvarnick, how many sleps do you have?
Round your answer to the nearest tenth (one decimal place).
Answer:
If we have 29 quibs of skvarnick they will be equal to 11.6 sleps.
Explanation:
Mass of a substance called skvarnick = 29 quibs
10 quibs is equal to 4 sleps. This means that 1 quibs is equal to 0.4 sleps.
10 quibs = 4 sleps
1 quibs = [tex]\frac{4}{10} sleps = 0.4 sleps[/tex]
Then 29 quibs will be:
[tex]29 quibs=29\times 0.4 sleps =11.6 sleps[/tex]
If we have 29 quibs of skvarnick they will be equal to 11.6 sleps.
Why do gamma rays have no charge? they are not made of protons, neutrons, or electrons they have equal numbers of protons and neutrons charge is balanced out by their intense frequency they are constantly emitting all their protons and electrons
Because they haare not made up of protons nuetrons or electrons
88.5 mol of P4O10 contains how many moles of P?
Ryan hypothesizes that darker colors heat up faster. He places a thermometer inside a red wool sock, a green cotton glove, and a black nylon hat. What's wrong with his procedure?
If some unknown solid weighs 84.0 grams and occupies 30.0 cm3 of space, what is its density?
The density of some unknown solid whose weight is 84.0 grams and volume is 30.0 cm3 is 2.8 g/mL.
What is Density?Density may be defined as a type of physical property that significantly deals with the description of how much space an object or substance takes up with respect to the amount of matter in that object or substance.
In a more simple sense, it is characterized as the measurement of quantity or mass per unit of volume in a particular substance.
According to the question,
The mass of the unknown solid = 84.0 grams.
The volume of the unknown solid = 30.0 cm3.
Now, the formula for calculating the density is as follows:
Density = Mass/Volume.= 84.0 g / 30.0 mL (1 cubic centimeter = 1 mL).
= 2.8 g/mL.
Therefore, the density of some unknown solid whose weight is 84.0 grams and volume is 30.0 cm3 is 2.8 g/mL.
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Which has the greater density? (Refer to "Densities of Common Substances" table.) air at sea level
air at 20 km altitude
How many grams of hydrogen gas can be obtained from 0.373 grams of magnesium? Note that the equation is NOT balanced.
Mg(s) + HCl(aq) → MgCl2(aq) + H2(g)
The first step to answering this item, is to balance first the chemical reaction. This is shown below.
Mg(s) + 2HCl (aq) --> MgCl₂(aq) + H₂(g)
HCl is multiplied by 2 to equalize the number of the hydrogen and chlorine.
The molar masses of magnesium and hydrogen gas are 24.3 g and 2 g, respectively. Using dimensional analysis and conversions, mass of hydrogen is calculated through the equation,
Mass of H₂ = (0.373 g Mg)(1 mol Mg/24.3 g Mg)(1 mol H₂/ 1 mol Mg)(2 g H₂/1 mol H₂)
Mass of hydrogen = 0.031 g of hydrogen
ANSWER: 0.031 g H₂
Energy from wind and water create dunes. However, what happens if that energy from the wind and water is too strong? What natural disaster is an example of this?
A 5.23 g sample of a metal occupies 0.27 ml. identify the density of the metal.
The density of a metal given a mass of 5.23 g and a volume of 0.27 mL is calculated using the formula density = mass / volume, resulting in a density of 19.37 g/mL, with the final answer limited to four significant figures.
Explanation:To identify the density of a metal given its mass and volume, you can use the formula for density, which is density = mass / volume. Given a 5.23 g sample of metal that occupies 0.27 mL, you first ensure the units are correct for density in g/mL. You then simply divide the mass by the volume.
So, density = 5.23 g / 0.27 mL = 19.37 g/mL.
This calculation gives us the density of the metal. Remember, when calculating density, it's important to ensure that your units are consistent, and for density, g/mL is a common unit. Additionally, when expressing your final answer, it matches the number of significant figures from the given data, in this case, being limited to four significant figures due to the precision of the volume measurement.
How many grams of sodium sulfate react with 20.8 of barium chloride?
To determine the number of grams of sodium sulfate that can react with 20.8 g of barium chloride, we use the balanced chemical equation and molar masses of the compounds. The number of moles of Na2SO4 that can react with 20.8 g of BaCl2 is 15.44 g Na2SO4.
Explanation:
To determine the number of grams of sodium sulfate that can react with 20.8 g of barium chloride, we need to use the balanced chemical equation and the molar masses of the compounds involved.
The balanced chemical equation for the reaction is:
BaCl2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2NaCl (aq)
The molar mass of BaCl2 is 208.23 g/mol and the molar mass of Na2SO4 is 142.04 g/mol.
From the balanced equation, we can see that the ratio of BaCl2 to Na2SO4 is 1:1. Therefore, the number of moles of Na2SO4 that can react with 20.8 g of BaCl2 is:
20.8 g BaCl2 × (1 mol BaCl2 / 208.23 g BaCl2) × (1 mol Na2SO4 / 1 mol BaCl2) × (142.04 g Na2SO4 / 1 mol Na2SO4) = 15.44 g Na2SO4.
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In 1928, 47.5 g of a new element was isolated from 660 kg of the ore molybdenite. the percent by mass of this element in the ore was:
To take the percent by mass of this element, we use the formula:
% mass = (mass of element / mass of ore) * 100%
% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*
% mass = 7.20 x 10^-3 %
Answer: The mass percent of element in the ore is 0.0072 %
Explanation:
To calculate the mass percentage of element in ore, we use the equation:
[tex]\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of ore}}\times 100[/tex]
Mass of element = 47.5 g
Mass of ore = 660 kg = 660000 g (Conversion factor: 1 kg = 1000 g)
Putting values in above equation, we get:
[tex]\text{Mass percent of element}=\frac{47.5g}{660000g}\times 100=0.0072\%[/tex]
Hence, the mass percent of element in the ore is 0.0072 %