When water has a temperature greater than 100c?
Find the density of a 5 kg solid cylinder. the cylinder is 5 cm tall and has a radius of 2 cm.
What kind of front involves three air masses of different temperatures?
An occluded front involves three air masses of different temperatures: two cold air separated by a warm air .
What is occluded front?Due to different densities, when big amounts of warm and cold air collide, they do not mix. They instead create a front that is typically hundreds of miles long. When a warm air mass is sandwiched between two cold air masses, an occluded front forms. As the cool air masses collide in the centre, the warm air mass rises. As the warm air mass is "cut off" from the earth and forced upward, the temperature decreases. Such fronts have the potential to produce violent winds and copious rain.
Typically, mature low pressure zones are where occluded fronts form.
Early occlusion of an extratropical cyclone in the Northern Hemisphere
Occlusion comes in two flavours, warm and cold:
In a cold occlusion, the cool air mass in front of the warm front is pushed aside by the cold air mass that is overtaking it because it is colder.In a warm occlusion, the warm air is lifted by the warm front's overtaking cold air mass, which is warmer than the cool air ahead of the warm front.Learn more about occluded front here:
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A 4-kg ball has a momentum of 12 kg∙m/s. what is the ball's speed?
Use the equation in the sample problem on the previous page to find the area of a rectangle that is 48.5 cm long and 3.77 cm wide. Round your answer to the correct number of significant figures.
The area of a rectangle with dimensions 48.5 cm by 3.77 cm is 182.865 cm², which is rounded to 183 cm² to maintain three significant figures.
To find the area of a rectangle with the dimensions 48.5 cm in length and 3.77 cm in width, we use the formula for the area of a rectangle, which is length x width. Multiplying the length by the width, we get:
48.5 cm x 3.77 cm = 182.865 cm²
When rounding this to the correct number of significant figures, we have to consider that the length and width measurements were given to three and three significant figures, respectively. Therefore, the area should also be reported to three significant figures:
The area rounded to three significant figures is 183 cm².
A car in a movie moving at 20 m/s flies off a cliff that is 74.3m tall. How long is the car in the air for and how far does the car travel before it hits the ground below?
The time the car, moving at 20 m/s, is in the air after flying off a 74.3m cliff is approximately 3.88 seconds. Within that time, it travels about 77.6 meters horizontally before hitting the ground.
Explanation:Using the concepts of gravity and projectile motion, the time the car, moving at 20 m/s, is in the air after flying off a 74.3m cliff is approximately 3.88 seconds.
To find the time the car is in the air, we use the formula for time in free fall, t = sqrt(2h/g), where h is the height the car falls, and g is the acceleration due to gravity. So, t = sqrt((2 * 74.3m) / 9.8m/s²), roughly giving t = 3.88 seconds.
To find the horizontal distance the car travels before hitting the ground, we use the formula x = vt, where v is the initial horizontal velocity and t is the time of flight. So, x = 20 m/s * 3.88 s, roughly equals 77.6 meters.
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An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
What is the force applied to the scale by the car?
_____N
Answer:
Force, F = 9800 N
Explanation:
It is given that,
The spring constant for the industrial scale at the junkyard is, k = 39,200 N/m
The compression in the spring, x = 25 cm = 0.25 m
To find,
The force applied to the scale by the car.
Solution,
The Hooke's law gives the relation between the force and the compression in the spring. Its expression is given by :
[tex]F=-kx[/tex]
[tex]F=39200\times 0.25[/tex]
F = 9800 N
So, the force applied to the scale by the car is 9800 N.
Refer to Explorations in Literature for a complete version of this story. How does Lizabeth interact with Miss Lottie in "Marigolds"?
A) Lizabeth is intrigued by Miss Lottie and her marigolds, so she enjoys going by Miss Lottie's house to see her garden.
B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
C) Lizabeth knows that Miss Lottie doesn't like to be bothered, but she encourages the other children to tease the woman.
D) Lizabeth is afraid of Miss Lottie because she thinks the old woman is a witch, so she avoids her house.
The answer is: B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
Lizbeth was depicted as an immature character that hates her condiiton and the place where she lived in. When she saw Miss Lottie taking care of the marigold flower, she could not understand why these poor woman had enough passion to take care of the wild flowers despite the horrid situations that she had and not miserable like her. This led her to destroy the flowers.
Earth has an abundant amount of iron, but also has many elements heavier than iron. Form a hypothesis
The earth has many elements heavier than iron due to the hypothesis that the explosions of sun have become more massive to man kind over a period of time, thus creating heavier elements found on Earth.
Heavy elements found on earthHeavy elements such iron are formed by nuclear fusion reaction. Example include the heavy element of iron.
Source of these heavy elements are:
geogenic, industrial, agricultural, pharmaceutical,domestic effluents, and atmospheric sources.Many elements that are heavier than iron has been formed over the years due to the sun explosions.
The formation of these heavy elements occurs due to the process called neutron capture, where neutrons penetrate an atomic nucleus in explosions of the sun.
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What is the wavelength of light emitted when the electron in a hydrogen atom moves from the n=5 state to the n=2 state? give your answer in nm?
if a car decelerates at a rate of 5.1 m/s, and its initial speed was 24 m/s. how long will it take the car to stop?
Final answer:
The car will take approximately 4.71 seconds to stop.
Explanation:
To find out how long it will take for the car to stop, we can use the equation:
Final velocity = initial velocity + (acceleration × time)
In this case, the final velocity is 0 m/s (since the car stops), the initial velocity is 24 m/s, and the acceleration is -5.1 m/s² (since the car is decelerating).
Plugging in these values, we have:
0 m/s = 24 m/s + (-5.1 m/s² × time)
Simplifying this equation, we get:
-5.1 m/s² × time = -24 m/s
Dividing both sides by -5.1 m/s², we find that:
time = 4.71 seconds
So, it will take approximately 4.71 seconds for the car to stop.
A study showed that children who watch more than 5 or more hours of television a day have lower grades than children who watch less. Which of these could be a hidden variable
The answer is D
Children who watch more television may have parents who are home less often to help them with schoolwork
A train that travel 100 kilometer in 4hours is traveling at what speed?
What is the biggest source of air pollution? power plants agriculture motor vehicles industry
Answer:
Moto vehicles
Explanation:
If a ball is thrown vertically upward from the ground with a velocity of 96 ft/s, then its height after t seconds is s = 96t − 16t2. what is the maximum height reached by the ball?
The maximum height achieved by the ball thrown vertically upwards is 243.9 ft.
What is a time - varying function?
A time varying function is a function whose final value varies with time.
Example - f(t) = 2t + 5
Given is a ball which is thrown vertically upward from the ground with a velocity of 96 ft/s, then its height after [t] seconds is S = 96t − 16t².
We can write -
S = 96t − 16t²
Differentiating with respect to 't', we get -
dS/dt = 96 - 2 x 16 x t
dS/dt = 96 - 32t
Now, for maximum height -
dS/dt = 0
96 - 32t = 0
32t = 96
t = 96/32
t = 3 seconds
At t = 3 seconds, the height will be maximum. Now, it is given that -
[u] = 96 ft/sec
[v] = 0 (at maximum height)
[g] = - 9.8 m/s²
Using the second equation of motion, we get -
S = ut + 1/2 gt²
S [max] = 96 x 3 - 0.5 x 9.8 x 3 x 3
S [max] = 288 - 44.1
S [max] = 243.9 ft
Therefore, the maximum height achieved by the ball thrown vertically upwards is 243.9 ft.
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An endothermic reaction is one that uses which form of energy?
A) Electrical Energy
B) Sound Energy
C) Chemical Energy
D) Nuclear Fusion
An endothermic reaction is the one that makes use of chemical energy.
What is endothermic reaction?An endothermic reaction is defined as a chemical reaction which is a thermodynamic process accompanied by an increase in enthalpy of the system.In this process, a system absorbs energy from the surroundings which is mainly thermal energy.
Thus an endothermic reaction leads to an increase in the temperature of the system with a decrease in the temperature of the surroundings.Endothermic reactions usually involve the formation of bonds which requires input of energy.In endothermic reactions, entropy of the surrounding decreases.
Many endothermic processes involve the physical changes rather the chemical changes.In an endothermic reaction ,the potential energy of products is greater than that of reactants.
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The velocity of a car changes from 60. meters per second north to 45 meters per second north in 5.0 seconds. the magnitude of the car's acceleration is
Assume that on a physics diagram, you saw a croquet ball moving along the grass and above it was an arrow labeled "3.5 m/s" that indicated BOTH the speed and direction of the ball. This is an arrow is a(n) _____.
Force arrow
Acceleration arrow
Speed arrow
Vector
Answer:
a vector.
Explanation:
The arrow labeled '3.5 m/s' in the given scenario, which denotes both the speed and direction of a croquet ball, is called a vector. A vector, in physics, represents a quantity showcasing both magnitude (in this case, velocity measured as '3.5 m/s') and direction.
Explanation:In the context of the question, the arrow labeled '3.5 m/s' that is indicating both the speed and the direction of the croquet ball is known as a vector. In physics, a vector is a quantity that possesses both magnitude (size or quantity) and direction. In this case, the '3.5 m/s' is the magnitude of the vector (the speed of the ball), and the direction the arrow is pointing indicates the direction the ball is moving. This is as opposed to a scalar quantity, which only has magnitude.
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how can two tectonic plates move relative to each other
Which kelvin temperature is equivalent to â24°c?
As you move from left to right on the periodic table, what generally happens to the electronegativity? *
A swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across a river that has a downstream current of 3.75 m/s. 46.
a. what must the swimmer’s direction be?
b. what is his velocity relative to the bank?
(ii) a woman stands on a bathroom scale in a motionless elevator. when the elevator begins to move, the scale briefly reads only 0.75 of her regular weight. calculate the acceleration of the elevator, and find the direction of acceleration.
Final answer:
To calculate the acceleration of the elevator when a woman's weight reads 0.75 of her regular weight, we use Newton's second law, resulting in an acceleration of -2.45 m/s². This indicates that the elevator is accelerating downwards or decelerating while moving upwards.
Explanation:
If a woman standing on a bathroom scale in an elevator observes that the scale reads only 0.75 of her regular weight, it means that the net force acting on her is reduced because the elevator is accelerating.
To calculate the acceleration of the elevator, we can use Newton's second law of motion and some assumptions about gravitational acceleration (g = 9.8 m/s2).
Let's denote the woman's mass as m, her regular weight as W = mg (where g is the acceleration due to gravity), and the scale reading when the elevator accelerates as 0.75W. When the elevator is accelerating, the apparent weight (scale reading) is W' = 0.75mg.
The net force (Fnet) acting on the woman in the elevator is her apparent weight, W', minus her actual weight, W, leading to Fnet = ma. Therefore:
Fnet = W' - W
ma = 0.75mg - mg
a = 0.75g - g = -0.25g
This gives us a = -0.25(9.8 m/s2) = -2.45 m/s2. The negative sign indicates that the acceleration is directed downwards - meaning that the elevator is accelerating downward or decelerating while going up.
Metamorphic rocks may generally be distinguished from igneous rocks because
If earth were twice as far from the sun, the force of gravity attracing earth to the sun would be
What happens to static and kinetic friction as mass increases?
What is the input and output of a microwave?
A stubborn 130 kg pig sits down and refuses to move. to drag the pig to the barn, the exasperated farmer ties a rope around the pig and pulls with his maximum force of 800 n. the coefficients of friction between the pig and the ground are μs=0.80 and μk=0.50. part a calculate the force which farmer needs to apply to budge the pig.
To calculate the force needed to budge the stubborn pig, we need to consider the frictional forces acting on it. Given the given values of μs and the weight of the pig, the force required to budge the pig can be found by subtracting the force of friction from the maximum force the farmer can exert.
Explanation:To calculate the force needed to budge the stubborn pig, we need to consider the frictional forces acting on it. The friction force can be calculated using the formula F_friction = μs ×F_normal, where F_normal is the normal force acting on the pig. The normal force is equal to the weight of the pig, which is given by F_weight = m × g, where m is the mass of the pig and g is the acceleration due to gravity.
Using the given values of μs and the weight of the pig, we can calculate the force of friction. Given that the maximum force the farmer can exert is 800 N, the force required to budge the pig can be found by subtracting the force of friction from the maximum force.
Let's calculate the force:
Calculate the weight of the pig using the formula F_weight = m × g, where m is the mass of the pig (130 kg) and g is the acceleration due to gravity (9.8 m/s^2).Calculate the force of friction using the formula F_friction = μs × F_normal, where μs is the static coefficient of friction (0.80) and F_normal is the normal force (weight of the pig).Subtract the force of friction from the maximum force the farmer can exert to find the force required to budge the pig.The force required to budge the pig is approximately 520 N.
Bernoulli's principle describes the property of a(n) _________.
Final answer:
Bernoulli's principle describes the relationship between pressure and velocity in fluids and is applicable in various fluid flow situations.
Explanation:
Bernoulli's principle describes the property of a fluid where there is an inverse relationship between the pressure and velocity of the fluid. According to Bernoulli's equation, for an incompressible, frictionless fluid, the sum of pressure, kinetic energy, and potential energy per unit volume is constant. This principle is applicable in various situations involving fluid flow, such as in the analysis of fluid devices and systems.
Bernoulli's principle serves as a fundamental concept in fluid dynamics, providing insights into the interplay between pressure and velocity within a flowing fluid. Its application extends to understanding phenomena like lift in aviation, the operation of carburetors, and the behavior of blood flow in arteries. By recognizing the conservation of energy in fluid motion, Bernoulli's principle contributes to the analysis and design of fluid-based systems across diverse fields.
A horizontal force of 30 n pulls a block of mass 2.5 kg across a level floor. the coefficient of kinetic friction between the block and the floor is μk = 0.25. if the block begins with a speed of 7.0 m/s and is pulled for a distance of 14 m, what is the final speed of the block?
The final speed is approximately 17.79 m/s. The final speed of the block is determined by calculating the net force and resulting acceleration, then using kinematic equations.
Final Speed of the Block
To determine the final speed of the block, we first need to calculate the net force acting on the block. Given:
Horizontal force (F) = 30 NMass of the block (m) = 2.5 kgInitial speed [tex](v_0) = 7.0 m/s[/tex]Coefficient of kinetic friction [tex](\mu_k) = 0.25[/tex]Distance (d) = 14 mThe force of kinetic friction (Ffriction) is calculated as:
[tex]F_{friction} = \mu_k \times N[/tex]
Where N is the normal force, and on a level floor N = mg:
[tex]N = m \times g = 2.5 kg \times 9.8 m/s^2 = 24.5 N[/tex]
Thus, the force of friction:
[tex]F_{friction} = 0.25 \times 24.5 N = 6.125 N[/tex]
The net force (F_{net}) acting on the block is:
[tex]F_{net} = F - F_{friction} = 30 N - 6.125 N = 23.875 N[/tex]
Using Newton's second law (F = ma) to find acceleration (a):
[tex]a = F_{net} / m = 23.875 N / 2.5 kg = 9.55 m/s^2[/tex]
We use the kinematic equation to find the final speed (v):
[tex]v^2 = v_0^2 + 2ad\\v = \sqrt{((7.0 m/s)^2 + 2 \times 9.55 m/s^2 \times 14 m)} = \sqrt{(49 + 267.4)} = \sqrt{(316.4)} = 17.79 m/s[/tex]
Therefore, the final speed of the block is approximately 17.79 m/s.