What do you think might be the explanation they are trying to test with the colored ice cubes?

Answer:

The problems faced in designing a roadway based on a single design vary. The challenges are described in the explanation section below. The first part of the question "If you wanted to create a vehicle that requires a very low tractive effort in order to overcome resistance forces, what parameter would you change and how would you change it" is also answered in italics below

Explanation:

When you are designing the roadway geometry you commonly use a design vehicle that gives you the worst scenario viable in that road, which is translated in terms of speed, meaning that after all of the topography problems, localisation of essential regions that can´t be modified (urban regions or national parks for example), ambiental effect and economic issues are handled, the horizontal and vertical geometry goes to depend of the speed value that is going to regulate camber, radius of curvature, acceleration and deceleration longitudes and others.

Now, in terms of infrastructure or pavement engineering, after handling climate challenges, the worst scenario is about weight, that has to do with the total equivalent load that is going to resist that pavement till first failure.So you see, that the challenges of using a single design vehicle in the geometry and infrastructure design of a roadway has to do with the selection of the worst scenario possible.

On the other hand, knowing the LOS of the roadway, which is crucial for knowing how is going to be transit management, depends on evaluating the level of service in all kinds of scenarios, that means different types of vehicles speed and acceleration configurations. So using a single vehicle, in this case, is not going to give you the best real knowledge of the road.

For the first question, designing a vehicle with a low tractive effort means that, from the civil engineering point of view, in order to enhance that vehicle, vertical geometry is key for solving resistance forces, because you can design a road that brings much more speed and power to the vehicle. Friction is also a parameter that reduces speed in vehicles but is necessary for a safe travel so you have see if it is logic to reduce this parameter in order to enhance the design vehicle behavior.

If you want to bring more tractive effort to the vehicle; handling resistance forces caused by rolling resistance or air resistance, drawbar pull and other should be key for enhancing the vehicle behavior. If you want a more detailed answer in this topic you should ask a mechanical engineering expert

Answer:

Aggressive behavior

Explanation:

Alcohol consumption tends to cause more Aggressive behavior.

The consumption of alcohol plays a more role in our culture but drinking of too much alcohol can cause drowsiness, vomiting, Upset stomach, slurred speech, heart damage, infertile, numbness lung infections, and many more. Also too much alcohol can cause violence, anger and so on in the society.    

Answer:

Tractive force or traction

Explanation:

The main purpose of the tractive forces is to improve the ability to transform the engine's energy into the vehicle's movement. There are several systems that have different qualities and uses. Here we explain how they work and what they are for.

In a traction vehicle with one of its axles, its ability to transmit engine power to the ground is limited for two reasons:

-  At least one of the wheels must have adhesion, and this as long as it has a self-locking differential. Otherwise, simply with one lacking grip, we can no longer move forward.

- If there are two wheels that must distribute the power, it will always be easier to saturate the traction capacity of the tire than if we divide the force by four. The example is very simple: if we try to drag an object on the ground by pulling a rubber, it will stretch more than if we pull 4 identical tires, although the force we make is the same.

Contrary to what one might think, all-wheel drive vehicles are nothing recent. What happens is that it did take time to reduce the weight and size, as well as to increase the resistance of the homokinetic joints (they are articulations on the axles to allow the wheel to go up and down with the suspension or turn with the steering) to to adapt these systems to cars.

Answer:

The viscous shear stress is 968 Pa (or can be written as 968 [tex]N/m^2[/tex]) and the drag force is 968 N.

Explanation:

Viscous shear stress

For a parallel flow of a Newtonian fluid, the shear stress is proportional to the gradient of the velocity,

[tex]\tau_{yx}= \mu \cfrac{du}{dy}[/tex]

Considering a large square plate moving on a thin film of thickness h, the velocity profile is

[tex]u(y) = U\cfrac{y}{h}[/tex]

Thus its derivative will be just

[tex]\cfrac{du}{dy}= \cfrac U h[/tex]

So replacing on the viscous shear stress formula we get

[tex]\tau_{yx}= \mu \cfrac {U}h[/tex]

We can then replace the given information

[tex]\tau_{yx}= 0.968 \times \cfrac{kg}{m\times  s}\times \cfrac{0.1 \cfrac ms}{0.0001 \, m}[/tex]

Evaluating we get

[tex]\boxed{\tau_{yx}=968\, Pa}[/tex]

The viscous shear stress is 968 Pascals or [tex]N/m^2[/tex].

Drag force

Using the given equation for the drag force we have

[tex]D = \tau_{yx} A[/tex]

And since we have a large square plate of sides L we can write the area as

[tex]A = L^2[/tex]

So the drag force is

[tex]D = \tau_{yx} L^2[/tex]

Replacing values

[tex]D = 968\, Pa \times (1\, m)^2[/tex]

We get

[tex]\boxed{D= 968 \,N}[/tex]

The drag force is 968 N.

Elongation in a bar is

[tex]\epsilon = \frac{PL}{\pi r^2 E}[/tex]

Where,

P = Applied force

L = Lengthof the specified rod

A = Cross-sectional area [tex](\pi r^2)[/tex]

E = Modulus of Elasticity

Performing a quick analysis we can realize that the larger the radius, the lower the elongation percentage. The radius is inversely proportional to the percentage of elongation. For this reason in a 2in bar the change will be GREATER than that of an 8in bar.

Answer:

ratio of the average convection heat transfer = 2

Explanation:

local heat transfer expression can be written as

[tex]H_{x}=Cx^{0.5}[/tex]       (1)

C= Constant

x=measured from the leading edge of the plate

We need to find local heat transfer coefficient at

 x=5L

so for equation 1 it can be written as

[tex]H_{x=5L}=C5L^{0.5}[/tex]

we can find the average heat transfer over entire lenght of plate as

[tex]H=\frac{1}{5L}\int\limits^5_0 {h_{x} } \, dx[/tex]  (2)

subsitute [tex]H_{x=5L}=C5L^{0.5}[/tex] in equation 2

[tex]H=\frac{C}{5L}\int\limits^5_0 {x^{-0.5}  } \, dx[/tex]

[tex]H=\frac{10C}{L}L^{-0.5}[/tex]

[tex]h=10CL^{-0.5}[/tex]

for ratio of the average convection heat transfer coefficient over the entire plate of length L to the local convection heat transfer coefficient at the end of the plate is given as

[tex]ratio = \frac{H}{H_{x} }[/tex]

Now putting values for H ,Hx and 5L for x

[tex]r=\frac{10CL^{-0.5}}{5CL^{-0.5} }[/tex]

[tex]r=2[/tex]

Answer:FALSE

Explanation:

Answer:

Explanation:

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Answer:

Consider the following code.

Explanation:

Code:

Unix Terminal> cat loan_calc.py

#!/usr/local/bin/python3

import locale

from decimal import *

def main():

locale.setlocale(locale.LC_ALL, 'en_US')

print('Monthly Payment Calculator')

while True:

print('DATA ENTRY')

loan_amt = input('Loan amount: ')

loan_amt = float(loan_amt)

int_rate = input('Yearly interest rate: ')

int_rate = float(int_rate)

years = input('Years: ')

years = int(years)

mon_rate = int_rate / 12 / 100

months = years * 12

monthly_pay = loan_amt * mon_rate / ( 1 - 1/(1 + mon_rate) ** months)

monthly_pay = Decimal(monthly_pay).quantize(Decimal('.01'), rounding=ROUND_DOWN)

print()

print('FORMATTED RESULT')

print('Loan amount: %30s' %locale.currency(loan_amt))

print('Yearly interest rate: %20.2f' %int_rate + '%')

print('Number of years: %25d' %years)

print('Montly payment: %25s' %locale.currency(monthly_pay))

print()

print('Continue? (y/n): ')

choice = input().strip()

if choice.lower() == 'n':

break

if __name__=='__main__':

main()

Unix Terminal>

Code output screenshot:

Answer:

it is not possible to place the wires in the condui

Explanation:

given data

total area = 2.04 square inches

wires total area = 0.93 square inches

maximum fill conduit =  40%

to find out

Can it is possible place wire in conduit conduit

solution

we know maximum fill is 40%

so here first we get total area of conduit that will be

total area of conduit = 40% × 2.04

total area of conduit = 0.816 square inches

but this area is less than required area of wire that is 0.93 square inches

so we can say it is not possible to place the wires in the conduit

Conduit fill is a term used in electrical engineering to describe the maximum amount of space that can be occupied by wires in a conduit. In this case, the percentage of fill exceeds the allowed limit, indicating that the wires cannot be accommodated within the given conduit diameter.

Conduit fill is a term used in electrical engineering to describe the maximum amount of space that can be occupied by wires in a conduit. It is important to ensure that the conduit is not overfilled, as this can cause overheating and other safety issues.

In this case, the conduit has a total area of 2.04 square inches and the wires occupy 0.93 square inches. To determine if the maximum fill is exceeded, we can calculate the percentage of fill:

Percentage of fill = (occupied area / total area) * 100

Plugging in the values given:

Calculating the percentage of fill:

Percentage of fill = (0.93 / 2.04) * 100 = 45.59%

Since the calculated percentage of fill (45.59%) is greater than the maximum fill allowed (40%), the 1½" conduit cannot be filled with the given wires within the allowed limit.

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Answer:

Those products are generally called Work in Process WIP

Explanation:

Work in process (WIP), or work in progress (WIP), goods in process, or in-process inventory in a manufacturing industry/company refer to the company's partially finished goods waiting for completion and eventual sale or the value of these items.

These items are either just being produced or require further processing (like purification, separation, packaging or handling) in a queue or a buffer storage.

Answer:

24.87 mm

Explanation:

The area of the bolt is given by

[tex]A_b=\pi r^{2}[/tex]

Since diameter is 16mm, the radius is 16/2= 8 mm= 0.008 m

Area, [tex]A_b=\pi\times 0.008^{2}=0.000201062 m^{2}[/tex]

For safe design of the bolt, we use stress of 201 Mpa

[tex]\sigma_b=\frac {P}{A_b}[/tex] where P is the load and [tex]\sigma_b[/tex] is normal stress.

Making P the subject then

[tex]P=A_b \sigma_b[/tex]

Substituting the figures given and already calculated area of bolt

[tex]P=201\times 10^{6}\times 0.000201062 m^{2}=40413.4479 N[/tex]

The area of spacer is given by

[tex]\pi (r_o^{2}- r_i^{2})[/tex] where r is radius and the subscripts o and I denote inner and outer respectively

The value of 142 Mpa by default becomes the stress on spacer hence

[tex]\sigma_s=\frac {P}{A_s}[/tex] and making [tex]A_s[/tex] the subject then  

[tex]A_s=\frac {P}{\sigma_s}[/tex]

[tex]\pi (r_o^{2}- r_i^{2})=\frac {P}{\sigma_s}[/tex]

Since we already calculated the value of P as 40413.4479 N and inner radius is 8mm= 0.008 m then  

[tex]\pi (r_o^{2}- 0.008^{2})=\frac {40413.4479}{142\times 10^{6}}[/tex]

[tex]r_o^{2}=0.000154592[/tex]

[tex]r=\sqrt{0.000154592}=0.012433 m[/tex]

Therefore, [tex]d=2r=2*0.012433=0.024867 m=24.86697 mm\approx 24.87 mm[/tex]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

Answer:b

Explanation:

A beam is subjected to an upward load in the middle and supported in both ends. The upper fibers i.e. a topmost layer of the beam is in tension while bottom fiber i.e. fiber of bottom layer is in compression because they are under compressive force.

Fibers above the neutral axis are in tension and fibers below the neutral axis are in compression.    

So option b is correct              

Answer:

what r u on

Explanation:

Answer:

89.967°C

Explanation:

According to Stefan-Boltzmann's law,

E = μΩA(Ts⁴ - Ti⁴)

Where,

Emissitivity, μ = 0.6,

Stefan-boltzmann's constant, Ω = 5.67 x 10^-8 W/m²K⁴

Surface area, A = 1.5 x 2.5 x 10-⁴ = 3.75 x 10-⁴ m²

Satellite temperature, Ti = -100°C = 173K

Power dissipated, E = 0.42 W

Since we're evaluating the temperature for both the top and bottom surfaces,

E = 2 x μΩA(Ts⁴ - Ti⁴)

0.42 = 2 x 0.6 x 3.75 x 10-⁴ x 5.67 x 10^-8 x (Ts⁴ - 173⁴)

0.0165 x 10^-12 = Ts⁴ - 8.957 x 10^8

Ts⁴ = 173.57 x 10^8

Taking 4th root of both sides,

Ts = 362.97 K

Ts = (362.97 - 273)°C

Ts = 89.967°C

Larry is exhibiting the defense mechanism known as Identification

Identification is a defense mechanism where an individual unconsciously takes on the characteristics, feelings, or behaviors of another person or group that they admire or identify with. In this case, Larry, who did not participate in sports himself, identifies closely with his school's sports teams.

By wearing the school's colors, cheering for the team, and feeling exhilarated when they win, Larry is psychologically aligning himself with the team and deriving a sense of belonging and accomplishment from their success, as if it were his own. This behavior allows Larry to cope with any feelings of inadequacy or unfulfilled desires he may have regarding his own athletic abilities.

Answer:

appropriate tunnel pressure is 384.64 ATM

Even at this (high) pressure, exact dynamic similarity is not achieved because the specific heat ratio of helium is approximately 1.66 and is not equal to that of air which is approximately 1.40

Explanation:

It is too long to type here.

Kindly check the attached file for the calculation.

Explanation:

Althought she referenced the article at the end, is imposible to know which part of the article is hers and which part is the expert's so that would be plagiarism.

If she used quotation marks in the words of the expert it would be clear and no plagiarism could be accused.

The scenario describes plagiarism, which occurs when one uses someone else's work or ideas without proper citation. Even though the student referenced the source at the end, not using quotation marks for direct quotes is considered plagiarism.

The scenario mentioned describes plagiarism. Plagiarism is a serious academic offense that occurs when one represents someone else's ideas, words, or work as their own without acknowledging the original source. In this case, the student has used the expert's words and ideas without proper citation (because she did not use quotation marks to indicate the direct quotes).

Although she mentioned the source at the end of her work, failing to use quotation marks for direct quotes is still considered plagiarism. To avoid this, it is essential to use quotation marks when directly quoting from a source and to paraphrase correctly when you are conveying the same idea in your own words.

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