What is a artafart and a Earth quack?

Answer:

is b

Step-by-step explanation: i did the test

To find the sum of 5 consecutive integers, use the formula (n + n+1 + n+2 + n+3 + n+4), where n is the first integer. The consecutive integers are 99, 100, 101, 102, and 103.

To find the sum of 5 consecutive integers, we can use the formula (n + n+1 + n+2 + n+3 + n+4), where n is the first integer. In this case, the sum is 505, so we have the equation: n + (n+1) + (n+2) + (n+3) + (n+4) = 505. Simplifying this, we get: 5n + 10 = 505. Subtracting 10 from both sides gives 5n = 495. Dividing both sides by 5, we find that n = 99.

Therefore, the 5 consecutive integers are 99, 100, 101, 102, and 103.

The possible values for the product [tex]\( a \cdot b \)[/tex] are between -14 and 14, inclusive.

Here's the step-by-step calculation:

1. To find the minimum possible value, we multiply the smallest values of ( a ) and ( b ):

[tex]\( a = -5 \) and \( b = -7 \)[/tex]

[tex]\( a \cdot b = (-5) \cdot (-7) = 35 \)[/tex]

2. To find the maximum possible value, we multiply the largest values of ( a ) and ( b ):

[tex]\( a = 2 \) and \( b = 1 \)[/tex]

 [tex]\( a \cdot b = 2 \cdot 1 = 2 \)[/tex]

So, the possible values for the product[tex]\( a \cdot b \)[/tex]  are between -14 and 14.

The range of values for( a ) is from -5 to 2, and for ( b ) is from -7 to 1. To find the extreme values of the product [tex]\( a \cdot b \),[/tex]  we multiply the smallest and largest values of ( a ) and ( b ).

For the minimum value, we take ( a = -5 ) and ( b = -7 ), which gives us [tex]( a \cdot b = 35 \).[/tex]

For the maximum value, we take ( a = 2 ) and ( b = 1 ), which gives us [tex]\( a \cdot b = 2 \).[/tex]

Therefore, the product[tex]\( a \cdot b \)[/tex] ranges from -14 to 14, inclusively.

complete question

If the value of "a" lies between −5 and 2 and the value of "b" lies between −7 and 1, what are the possible values for the product a· b?

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathtt{(6^3)^2}\\\\\mathtt{= (6\times6\times6)^2}\\\\\mathtt{= (36\times6)^2}\\\\\mathtt{= (216)^2}\\\\\mathtt{= 216^2}\\\\\mathtt{= 216\times216}\\\\\mathtt{= 46,656}\\\\\mathtt{= 6^6}\\\\\mathtt{= 6\times6\times6\times6\times6\times6}\\\\\mathtt{= 36\times36\times36}\\\\\mathtt{= 1,296\times36}\\\\\mathtt{= 46,656}\\\\\\\huge\text{Therefore your answer should be:}\\\boxed{\mathtt{Option\ C.\ 6^6}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Final answer:

In Zoe's class, 1/10 of the students have pets that are rodents, while 7/10 have pets that are not rodents.

Explanation:

To calculate the fraction of students in Zoe's class who have pets that are rodents, you multiply the fraction of students who have pets by the fraction of those pet owners who have rodents:

4/5 × 1/8 = 4/40 or simplified, 1/10.

This means 1/10 of Zoe's class have rodents as pets.

Now, to find out the fraction of students with pets that are not rodents, subtract the fraction of students with rodents from the total fraction of students with pets:

4/5 - 1/10 = 32/40 - 4/40 = 28/40, which simplifies to 7/10.

So, 7/10 of Zoe's class have pets that are not rodents.

The coordinates of the image of triangle ABC are A''(4, -2), B''(2, 1) and C''(-2, -2).

Here are the rotation rules: 90° clockwise rotation: (x, y) becomes (y, -x) 90° counterclockwise rotation: (x, y) becomes (-y, x).

Given that, he vertices of a triangle are A(-2,4), B (1,2), and C(-2,-2).

Reflect the triangle in the y-axis

The rule for a reflection over the y -axis is (x,y)→(-x, y)

Here, A(-2, 4)→A'(2, 4)

B (1,2)→B'(-1, 2)

C(-2,-2)→C'(2, -2)

Then rotate the image 90 degrees counterclockwise about the origin.

A'(2, 4)→A''(4, -2)

B'(-1, 2)→B''(2, 1)

C'(2, -2)→C''(-2, -2)

Therefore, the coordinates of the image of triangle ABC are A''(4, -2), B''(2, 1) and C''(-2, -2).

Learn more about the rotation of 90° counterclockwise here:

brainly.com/question/1571997.

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Answer:  Each friend get 3.5 cookies.

Step-by-step explanation:  Given that two friends share 7 cookie equally.

We are to find the number of cookies that each friend get.

We will be using the UNITARY method to solve the given problem.

Number of cookies shared by 2 friends equally = 7.

Therefore, number of cookies that one friend get will be

[tex]\dfrac{7}{2}=3.5.[/tex]

Thus, each friend get 3.5 cookies.

Answer:

"6 times the  difference of 12 and 4"

Step-by-step explanation:

Given: [tex]6\times (12-4)[/tex]

To write the given expression in words.

"6 times the difference of 12 and 4"

Because difference of 12 and 4 is 12-4

6 times of a number(n) is 6n

Therefore,

[tex]6\times (12-4)[/tex] as phrase "6 times the  difference of 12 and 4"

Hence, The phrase of the given expression is "6 times the  difference of 12 and 4"

Answer:

23 is the required answer.

Step-by-step explanation:

We are given a fraction of the form [tex]2\frac{5}{9}[/tex].

It is a mixed fraction.

We convert it into improper fraction.

The improper fraction is of the form [tex]\frac{(9\times2)+5}{9} = \frac{23}{9}[/tex].

This fraction can also be written as 23 multiplied [tex]\frac{1}{9}[/tex] times.

It is clear that the above fraction have 23 parts of ninth.

After discarding the gold card, Carolee has a total of 10 cards left. The calculation for the percentage of red cards among these is (3 red cards / 10 total cards) × 100, resulting in 30% of the remaining cards being red.

The question asks about the percentage of the remaining cards that are red after Carolee discards the gold card. Initially, Carolee has 4 green cards, 3 red cards, 3 orange cards, and 1 gold card. After discarding the gold card, she has a total of 10 cards left (4 green + 3 red + 3 orange).

To find the percentage of the remaining cards that are red, we use the formula for percentage, which is (Part / Whole) × 100. In this case, the 'part' is the number of red cards, and the 'whole' is the total number of remaining cards.

Percentage of red cards = (Number of red cards / Total number of cards) × 100

= (3 / 10) × 100

= 30%

Therefore, 30% of Carolee's remaining cards are red.