what is an example of y-intercept?

84-29=55

84 is your credit and 29 is your debit

All integers in which real numbers are involved can be written as p/q such that p and q are integers so they will be a rational number.

Any real number that cannot be written as the quotient of two integers, p/q, where p and q are both integers, is referred to as an irrational number.

In another word, irrational numbers are those numbers that can not terminate.

For example, √2, and √3 are irrational numbers because they cannot be written as p/q where p and q both should be integers.

All integers are non-decimal numbers so they can be written as p/q such that p and q both will be integers so they will be a rational number.

The whole number is a positive integer so it will be in the category of integers only.

So,

In the given Venn diagram it is clear that in the real number all rational and irrational numbers are included in the rational number integer and in which the whole number is shown.

Hence "All integers in which real numbers are involved can be written as p/q such that p and q are integers so they will be a rational number".

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Answer:

The values of x must be 16 meters or less to satisfy the inequality. (x ≤ 16 m)

Step-by-step explanation:

The area of a triangle is given by the formula:

A=[tex]\frac{bh}{2}[/tex]

Where 'b' is the base of the triangle (in this case is equals to 14 meters)

'h' is the height of the triangle (in this case is x)

As the area of the triangle must be less or equal to 112 m², the inequality is given by:

112m²≥[tex]\frac{(14m)x}{2}[/tex]

[tex]\frac{112m^{2}*2 }{14m}[/tex]≥x

16m ≥ x

I just took the test and the answer is B. 12/5x - 4

In case anyone else has the same question

Answer: [tex]16\dfrac{1}{2}[/tex] pound rock is 1.571 times heavier than [tex]10\dfrac{1}{2}[/tex] pounds rock.

Step-by-step explanation:

Since we have given that

Quantity of rock = [tex]16\dfrac{1}{2}\ pounds=\dfrac{33}{2}\ pounds[/tex]

Quantity of another rock = [tex]10\dfrac{1}{2}=\dfrac{21}{2}\ pounds[/tex]

We need to find the number of times heavier is 16 1/2 pound rockthen a 10 1/2 pound rock.

so, number of times is given by

[tex]\dfrac{33}{2}\div \dfrac{21}{2}\\\\=\dfrac{33}{2}\times \dfrac{2}{21}\\\\=\dfrac{33}{21}\\\\=1.571[/tex]

Hence, [tex]16\dfrac{1}{2}[/tex] pound rock is 1.571 times heavier than [tex]10\dfrac{1}{2}[/tex] pounds rock.

To calculate the change Wallace receives, subtract the total cost of pizzas (12.25 times p) from the original $50.

To answer the question of how to write an expression for the change Wallace receives after buying p number of pizzas, we need to use a simple algebraic expression. Wallace has a $50 bill and each pizza cost $12.25. If p represents the number of pizzas, then the total cost of the pizzas would be 12.25 times p. To find the change he receives, we subtract this amount from the original $50.

The expression for the change Wallace receives is:

Change = 50 - (12.25 times p)

Kami sold 28 large figures, as their earnings equaled that of 42 small figures. (Option B)

Let's denote the number of large figures sold as [tex]\( L \)[/tex] and the number of small figures sold as [tex]\( S \).[/tex]

We know the following:

1. [tex]\( L + S = 70 \)[/tex] (Total figures sold)

2.[tex]\( 12L = 8S \)[/tex] (Amount earned from large figures equals the amount earned from small figures)

We can use these equations to solve for [tex]\( L \):[/tex]

From equation 2, we can express [tex]\( S \) in terms of \( L \):[/tex]

[tex]\[ S = \frac{12L}{8} = \frac{3L}{2} \][/tex]

Now, we can substitute this expression for [tex]\( S \)[/tex] into equation 1:

[tex]\[ L + \frac{3L}{2} = 70 \][/tex]

Multiplying both sides by 2 to clear the fraction:

[tex]\[ 2L + 3L = 140 \]\[ 5L = 140 \][/tex]

Now, divide both sides by 5:

[tex]\[ L = \frac{140}{5} = 28 \][/tex]

So, Kami sold [tex]\( 28 \)[/tex] large figures.

Therefore, the answer is option B - 28.

The number is positive when measured in absolute value. So |-3| = 3. since distance cannot be calculated in negative quantities.

A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.

It is given that:

Two numbers are given:

|-3| and -3

As we know, the mod function has positive range.

Let f(x) = |x|

The range of the function is [0, ∞)

The value of |-3| will be 3 after removing the mod which is also called the absolute value of the mod function.

A number's distance from zero, or its absolute value, is expressed as the number of spaces.

Since distance cannot be calculated in negative quantities, it cannot be negative. A number is positive when measured in absolute value. So |-3| = 3.

Thus, the number is positive when measured in absolute value. So |-3| = 3. since distance cannot be calculated in negative quantities.

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To find the total number of burgers sold, we use the ratio of burgers with cheese to those without (10:7), determine the number of sets in the 30 burgers with cheese sold, and calculate the number of burgers without cheese accordingly. The restaurant sold a total of 51 burgers.

To determine the total number of burgers sold, we can use the given ratio of burgers with cheese to burgers without cheese, which is 10:7. This means for every 10 burgers with cheese, there are 7 burgers without cheese. We're told that the restaurant sold 30 burgers with cheese. Since these represent the '10' part of the ratio, we can find out how many sets of '10' there are in 30 burgers to then calculate the '7' part of the ratio.

First, we divide the number of cheeseburgers by 10:

Next, we multiply the 7 parts of the ratio by 3 to find the number of burgers without cheese:

To find the total number of burgers sold, we add the number of burgers with cheese and the number without cheese: